A summary of two stocks is shown.


Name of Stock Symbol Closing Price Day 1 Closing Price Day 2 Closing Price Day 3
Metroplis, Ltd MTP 17.95 18.28 18.25
Suburbia, Inc SBR 5.63 5.88 4.98


Suppose you purchase 30 shares of Metropolis stock and 55 shares of Suburbia stock on Day 1 at the closing price. Which day, during the following two days, would be the best to sell both stocks?
Day 2 is the best by $26.75.
Day 3 is the best by $26.75.
Day 2 is the best by $23.65.
Day 3 is the best by $23.65.

Answers

Answer 1

The solution is,  the unique price of the proportion is $10.37 even as within the promotion it is promoting at $18.25 consequently, The inventory is over-valued.

We have,

The following market and stock-specific statistics  10.37201

anticipated Return on company Y = Rf + Beta(Rm-Rf)

= zero.029+ 1.forty one*(zero.082)

= zero.14462

charge of the stock =Dividend/predicted to go back

= 1. 5/0.14462

= 10.37201

So the unique price of the proportion is $10.37 even as within the promotion it is promoting at $18.25 consequently, The inventory is over-valued.

A market is described as the sum overall of all the consumers and dealers in the region or place under attention. The vicinity may be the earth, nations, regions, states, or towns. The fee, fee, and fee of items traded are according to forces of delivery and demand in a marketplace.

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complete question:

use the following market and stock specific information to answer this question. assume you create your own portfolio made up of the four individual stocks shown below. the weighting of the porfolio is 30% stock w, 20% stock x, 20% stock y and 30% stock z. if a treasury bill currently sells for $970.05 and if firm y is expected to pay a constant annual dividend of $1.50 per share, and if the stock is currently selling for $18.25 per share, what is your opinion of the stock price?


Related Questions


Find the number of real solutions of each equation using the
discriminant.

Answers

The solutions for each one are:

1) Two real

2) Two complex

3) One real.

How to find the number of real solutions?

For a quadratic of the form:

ax² + bx + c = 0

The discriminant is:

D = b² - 4ac

if D > 0, there are two real solutions.

if D=  0 there is one real solution.

if D < 0 the solutions are complex.

The first quadratic equation is:

2x² + 4x + 3 = 0

The discriminant is:

D = 4² - 4*2*3

  = 16 - 24 = -8

So this equation has no real solutions.

The second is:

3x² - 5x + 1 = 0

The discriminant is:

D = (-5)² - 4*3*1

  = 25 - 12 = 13

Two real solutions.

The last one is:

x² + 4x + 4  =0

We have:

D = 4² - 4*4*1

  = 16 - 16  =0

One real solution.

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Please answer this question

Answers

The slope of the line, based on the information given in the table is: the cost of purchasing one pencil.

How to Interpret the Slope of a Line?

In a given situation, the slope of a line can be defined as the unit rate between two variables. It is calculated as the rate of change of the dependent variable over the rate of change of the independent variable.

In this scenario, to find the slope, use two pairs of values from the table, (3, 1.05) and (7, 2.45):

Slope in this case = cost of purchasing one pencil (unit rate) = 2.45 - 1.05 / 7 - 3

Slope = $0.35 per pencil.

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The p-value is _____ or less if the chi-square statistic is 6.63 or more.

Answers

The p-value is 0.01 or less if the chi-square statistic is 6.63 or more.

The p-value is 0.01 or less if the chi-square statistic is 6.63 or more.

An analytical statistical technique for categorical data is the chi-square test. A set of variables expected and observed frequencies can be compared to see if there is a significant difference.

The chi-square statistic, which gauges the difference between observed and anticipated frequencies, serves as the foundation for the chi-square test. The test looks at whether there is a substantial difference between the observed and expected data.

Numerous disciplines, including biology, psychology, sociology, and business, can benefit from the chi-square test. Frequently, it is used to test theories relating to the interactions between two or more category variables.

There are various chi-square tests, including the likelihood ratio chi-square test and Pearson's chi-square test. The chi-square test by Pearson

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grear tire company has produced a new tire with an estimated mean lifetime mileage of 33,500 miles. management also believes that the standard deviation is 3,500 miles and that tire mileage is normally distributed. to promote the new tire, grear has offered to refund some money if the tire fails to reach 30,000 miles before the tire needs to be replaced. specifically, for tires with a lifetime below 30,000 miles, grear will refund a customer $1 per 100 miles short of 30,000. (a) for each tire sold, what is the average cost of the promotion (in $)? (use at least 1,000 trials. round your answer to two decimal places.)

Answers

Answer:

C

Step-by-step explanation:

Twenty-five percent of the employees of a large company are minorities. A random sample of 7 employees is selected.
a. What is the probability that the sample contains exactly 4 minorities?
b. What is the probability that the sample contains fewer than 2 minorities?
c. What is the probability that the sample contains exactly 1 non-minority?
d. What is the expected number of minorities in the sample?

Answers

Answer: This problem involves sampling from a binomial distribution, where the probability of success (i.e., being a minority employee) is p = 0.25, and the sample size is n = 7.

a. The probability that the sample contains exactly 4 minorities can be calculated using the binomial probability formula:

P(X = 4) = (7 choose 4) * 0.25^4 * 0.75^3

where (7 choose 4) = 35 is the number of ways to choose 4 employees out of 7.

Evaluating this expression gives:

P(X = 4) = 35 * 0.25^4 * 0.75^3 = 0.1318

Therefore, the probability that the sample contains exactly 4 minorities is approximately 0.1318.

b. The probability that the sample contains fewer than 2 minorities can be calculated as the sum of the probabilities of getting 0 or 1 minority:

P(X < 2) = P(X = 0) + P(X = 1)

Using the binomial probability formula again, we get:

P(X = 0) = 0.75^7 = 0.1335

P(X = 1) = (7 choose 1) * 0.25^1 * 0.75^6 = 0.3232

where (7 choose 1) = 7 is the number of ways to choose 1 employee out of 7.

Therefore,

P(X < 2) = P(X = 0) + P(X = 1) = 0.1335 + 0.3232 = 0.4567

So the probability that the sample contains fewer than 2 minorities is approximately 0.4567.

c. The probability that the sample contains exactly 1 non-minority can be calculated using the complement rule:

P(X = 1) = 1 - P(X = 0) - P(X > 1)

where P(X > 1) is the probability of getting 2 or more minorities, which can be calculated as:

P(X > 1) = 1 - P(X = 0) - P(X = 1) = 1 - 0.1335 - 0.3232 = 0.5433

Therefore,

P(X = 1) = 1 - P(X = 0) - P(X > 1) = 1 - 0.1335 - 0.5433 = 0.3232

So the probability that the sample contains exactly 1 non-minority is approximately 0.3232.

d. The expected number of minorities in the sample can be calculated using the formula:

E(X) = n * p = 7 * 0.25 = 1.75

Therefore, the expected number of minorities in the sample is 1.75.

Based on the calculations:

a. The probability that the sample contains exactly 4 minorities is 0.00015625 or approximately 0.0156.

b. The probability that the sample contains fewer than 2 minorities is 0.01435 or approximately 0.0144.

c. The probability that the sample contains exactly 1 non-minority is 0.322102 or approximately 0.3221.

d. The expected number of minorities in the sample is 1.75.

Therefore, the correct options are:

a. The probability that the sample contains exactly 4 minorities is approximately 0.0156.

b. The probability that the sample contains fewer than 2 minorities is approximately 0.0144.

c. The probability that the sample contains exactly 1 non-minority is approximately 0.3221.

d. The expected number of minorities in the sample is 1.75.

Given points P(4,12), Q(8,-8), and R(-4,-2) what would be P’ if (1/2 x + 3, 1/2 y - 4)?

Answers

Answer:

P' (5, 2 )

Step-by-step explanation:

under a translation

([tex]\frac{1}{2}[/tex] x + 3, [tex]\frac{1}{2}[/tex] y - 4 )

means half the original x- coordinate and add 3

half the original y- coordinate and subtract 4

P (4, 12 ) → ([tex]\frac{1}{2}[/tex] (4) + 3, [tex]\frac{1}{2}[/tex] (12 - 4 ) → P' (2 + 3, 6 - 4 ) → P' (5, 2 )

A random sample was drawn from a specific population and divided into three groups, the first group was given the first vitamin, the second was the second vitamin, and the third was the third vitamin, and the increase in weight was recorded for each individual In the three groups, they were as follows: + 3 5 6 8 3 5 4. 9 10 8 7 First Vitamin Second Vitamin Third Vitamin 2 3 1 2 3 O a Required: Knowing which of them leads to weight gain, at a level of significance of 5%, using a SPSS?

Answers

To determine which vitamin leads to weight gain, a hypothesis test can be conducted using SPSS with a level of significance of 5%. The group with the significantly higher mean weight gain would indicate which vitamin leads to weight gain.

To determine which vitamin leads to weight gain at a level of significance of 5%, a hypothesis test needs to be conducted. The null hypothesis would be that there is no significant difference in weight gain between the three groups, and the alternative hypothesis would be that there is a significant difference.

To conduct the test in SPSS, the first step would be to input the data for each group and calculate the mean weight gain for each group. Then, a one-way ANOVA test can be conducted to determine if there is a significant difference between the means. The level of significance is set at 5%.

If the p-value is less than 0.05, the null hypothesis can be rejected, indicating that there is a significant difference between the means. Further post-hoc tests can then be conducted to determine which specific groups differ significantly.

In conclusion, to determine which vitamin leads to weight gain, a hypothesis test can be conducted using SPSS with a level of significance of 5%. The group with the significantly higher mean weight gain would indicate which vitamin leads to weight gain.


To determine which vitamin leads to weight gain in the specific population, you can perform an analysis using SPSS at a 5% level of significance. First, input the weight gain data for the three vitamin groups into SPSS. Then, conduct an ANOVA (Analysis of Variance) test to compare the means of the three groups. If the p-value obtained from the test is less than the level of significance (0.05), it indicates a significant difference between the groups. Further post-hoc tests (such as Tukey's HSD) can then be conducted to identify which vitamin group leads to a significant weight gain compared to the others.

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what are the coordinates of point q that partitions AB into the ratio 1:3 where (-3,6) and B (6,0)

Answers

The coordinates of point Q that partitions line segment AB into the ratio 1:3 is (-0.75, 4.5).

How to determine the coordinates of point Q?

In this scenario, line ratio would be used to determine the coordinates of the point Q on the directed line segment AB that partitions the segment into a ratio of 1 to 3.

In Mathematics, line ratio can be used to determine the coordinates of Q and this is modeled by the following mathematical expression:

Q(x, y) = [(mx₂ + nx₁)/(m + n)],  [(my₂ + ny₁)/(m + n)]

By substituting the given points into the formula for line ratio, we have;

Q(x, y) = [(1(6) + 3(-3))/(1 + 3)],  [(1(0) + 3(6))/(1 + 3)]

Q(x, y) = [(6 - 9)/(4)],  [(0 + 18)/4]

Q(x, y) = [-3/4],  [18/(4)]

Q(x, y) = [-0.75, 4.5]

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in a scalene triangle, one angle measures 50 degrees. what are the measures of the other two angles?

Answers

In a scalene triangle, all three angles have different measures. So if one angle measures 50 degrees, the other two angles must have different measures as well.

To find the measures of the other two angles, we can use the fact that the sum of the measures of the angles in any triangle is always 180 degrees. Let x be the measure of one of the other angles. Then the measure of the third angle can be found by subtracting 50 degrees and x from 180 degrees:

x + 50 + third angle = 180

Simplifying:

third angle = 180 - x - 50

third angle = 130 - x

Since we know that all three angles are different, we can assume that x is not equal to 50. Therefore, the measures of the other two angles are x degrees and 130 - x degrees.

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For the following exercises, set up and evaluate each optimization problem. Find two positive integers such that their sum is 10, and minimize and maximize the sum of their squares.

Answers

The two positive integers that maximize the sum of their squares while satisfying the constraint x + y = 10 are x = y = 5.

To set up the optimization problem, let x and y be the two positive integers we are trying to find. Then, we want to minimize and maximize the sum of their squares, which can be expressed as:

Minimize: [tex]f(x, y) = x^2 + y^2[/tex]

Subject to: x + y = 10 and x, y > 0

Maximize: [tex]g(x, y) = x^2 + y^2[/tex]

Subject to: x + y = 10 and x, y > 0

Note that the constraint x, y > 0 means that we are looking for positive integers, and the constraint x + y = 10 means that their sum must be 10.

To solve the minimization problem, we can use the method of Lagrange multipliers. The Lagrangian function is:

L(x, y, λ) = [tex]x^2 + y^2 + λ(10 - x - y)[/tex]

Taking the partial derivatives with respect to x, y, and λ, we get:

∂L/∂x = 2x - λ = 0

∂L/∂y = 2y - λ = 0

∂L/∂λ = 10 - x - y = 0

Solving these equations simultaneously, we get:

x = y = 5

λ = 10

Therefore, the two positive integers that minimize the sum of their squares while satisfying the constraint x + y = 10 are x = y = 5. The minimum value of the sum of their squares is:

[tex]f(5, 5) = 5^2 + 5^2 = 50[/tex]

To solve the maximization problem, note that the function x^2 + y^2 is a continuous and increasing function of x and y. Since x and y must sum to 10 and be positive integers, the maximum value of their sum of squares occurs when one of them is as large as possible, which is 5. Thus, the maximum value of the sum of their squares is:

[tex]g(5, 5) = 5^2 + 5^2 = 50[/tex]

Therefore, the two positive integers that maximize the sum of their squares while satisfying the constraint x + y = 10 are x = y = 5.

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Out of 520 randomly selected students, 104 of them dropped an online course. Construct a 90% confidence interval for the true proportion of students that will drop an online course. Find the standard error

Answers

The standard error is found to be 0.024, when constructing a 90% confidence interval for the true proportion of students.

The point estimate of the proportion of students (sample) who dropped an online course is:

p' = 104/520 = 0.2

The standard error of the sample proportion is:

SE = √[p'(1 - p') / n]

where n is the sample size.

SE = √[0.2(1 - 0.2) / 520] = 0.024

To construct a 90% confidence interval, we can use the formula:

CI = p' ± z × SE

where z is the desired confidence level's associated z-score. The z-score with a 90% degree of confidence is 1.645.

CI = 0.2 ± 1.645(0.024) = (0.155, 0.245)

Therefore, we can be 90% confident that the true proportion of students who will drop an online course is between 0.155 and 0.245.

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True or False: An argument in which the premises and the conclusion are all contingent statements must be an invalid argument.

Answers

Answer:

1).False 2). False if the premise and conclusion are all consistent state

Step-by-step explanation:

i did it

Lots of points + brainlyist. Pls.

Answers

The interpretation of the given compound interest expression is:

2400 is the amount of initial deposit

1.03 is the amount

12t is the number of times the account has compounded since it opened

How to Interpret Compound Interest Problems?

The formula for compound interest is:

A = P(1 + (r/t))^(nt)

Where:

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

We are given the equation as:

S = 2400(1.03)^(12t)

Thus:

2400 is the amount of initial deposit

1.03 is the amount

12t is the number of times the account has compounded since it opened

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2
If two triangles are congruent, which of the following statements must be
true? Check all that apply.
A. The corresponding sides of the triangles are congruent.
B. The corresponding angles of the triangles are congruent.
C. The triangles have the same shape and size.
D. The triangles have the same shape, but not the same size.
SUBMIT

Answers

Answer: A, B, C

Step-by-step explanation:

Congruence of any shape by definition means that the two shapes have the same shape and size. This applies even if the shapes are in different orientations, or if the two shapes are reflected versions of each other, as long as the points are named the same respective to their different orientations. If the two triangles are congruent, their corresponding sides and angles are also congruent, because they are the same shapes, they have the same corresponding sides and angles. If any of these are not true, this means that the shapes are not congruent.

Alma makes `5` cups of her favorite shade of purple paint by mixing `3` cups of blue paint, `1\frac{1}{2}` cups of red paint, and `\frac{1}{2}` a cup of white paint.



Alma has `2` cups of white paint.



How much blue paint and red paint will Alma need to use with the `2` cups of white paint?

Answers

Alma has to utilize 6/5 glasses of blue paint and 6/5 mugs of ruddy paint with the 2 mugs of white paint to create 2 glasses of her favorite shade of purple paint.

How to Solve the Problem?

To form 5 mugs of purple paint, Alma makes use of 3 mugs of blue paint, 1frac{1}{2} glasses of ruddy paint, and frac{1}{2} a container of white paint.

So, to form 1 container of purple paint, she has to utilize:

3/5 glasses of blue paint

1frac{1}{2}/5 cups of ruddy paint

frac{1}{2}/5 mugs of white paint

Presently, Alma needs to form 2 glasses of purple paint utilizing 2 glasses of white paint.

Since she already has frac{1}{2} a container of white paint, she as it were needs another 1frac{1}{2} mugs of white paint.

To form 2 glasses of purple paint, Alma must twofold the sum of each color utilized to create 1 glass of purple paint.

In this way, she will require:

2 * 3/5 = 6/5 glasses of blue paint

2 * 1frac{1}{2}/5 = 3/5 + 3/5 = 6/5 glasses of ruddy paint

2 * frac{1}{2}/5 = 1/5 cups of white paint

Since she as of now has 2 glasses of white paint, she will as it were ought to utilize 1/5 glasses of the white paint that she as of now has.

Subsequently, Alma has to utilize 6/5 glasses of blue paint and 6/5 mugs of ruddy paint with the 2 mugs of white paint to create 2 glasses of her favorite shade of purple paint.

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A right rectangular prism (with square base) is sliced such that the plane cuts in a direction parallel to the base, what is the resulting cross section?

Answers

When a right rectangular prism with a square base is sliced in a direction parallel to the base, the resulting cross section is a square.

The parallel plane will intersect all the edges of the square base at the same distance from the top face of the prism, creating a new square.

The size of the resulting square will depend on the distance between the plane and the top face of the prism. If the plane is closer to the top face, the resulting square will be larger. If the plane is further away, the resulting square will be smaller.

It is important to note that if the plane is not parallel to the base, the resulting cross section will be a rectangle. This is because the plane will intersect the edges of the base at different distances from the top face of the prism, creating a new rectangle.

Understanding the resulting cross section of a sliced right rectangular prism can be useful in real-world applications, such as in architecture and engineering, where precise measurements and cutting are necessary for construction projects.

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What’s the unit rate of 144 pages in 3 minutes ?

Answers

To find the unit rate, divide the total number of pages by the total amount of time:

Unit rate = Total number of pages / Total amount of time

In this case, the total number of pages is 144 and the total amount of time is 3 minutes:

Unit rate = 144 pages / 3 minutes

Simplifying this expression:

Unit rate = 48 pages per minute

Therefore, the unit rate of 144 pages in 3 minutes is 48 pages per minute.

Divide and simplify.


(24a^3)/(35b^2) divided by (16a)/(14b^3)


A. (12a)/(35b)

B. (5a^2b)/(3)

C. (4a^2)/(5b)

D. (3a^2b)/(5)

Answers

Answer:

took me a minute the answer is D. (3a^2b)/(5).

I got some things like when I simpley the equation

(15a^2)(4b)

A spinner has a 45% chance of landing on green. What is the probability of the spinner first not landing on green, spun again, and then landing on green?

Answers

The probability of the spinner first not landing on green, spun again, and then landing on green is P ( A ) = 0.2475

Given data ,

Let the probability of the spinner first not landing on green, spun again, and then landing on green is P ( A )

Now , Since the likelihood of the spinner landing on green on each spin is independent and constant, the chance that it will do so on the second spin is 0.45.

We add the probabilities together to determine the likelihood that the spinner won't land on green at first, then will spin again and land on green.

On the first spin, there is a 0.55 percent chance of not landing on green.

The second spin's probability of landing on green is 0.45.

Probability of landing on green after not landing on green is equal to 0.55 times 0.45.

P ( A ) = 0.2475

Hence , the probability that the spinner will first miss landing on green, spin again, and finally land on green is 0.2475, or 24.75%

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2. A Company manager wishes to test a union leader's claim that employee absences occur on the different week days with the same frequencies. Test this claim at the 0.05 level of significance if the following sample data have been compiled. Select the correct conclusion about the null hypothesis.
Day: Mon Tue Wed Thru Fri
Abs: 37 15 12 23 43
A. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection fo the claim that absences occur on the different week days with the same frequency.
B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that absences occur on different week days with the same frequency,
C. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that absences occur on the different week days with the same frequency.
D. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that absences occur on the different week days with the same frequency.

5. Perform the indicated goodness-of-fit test. Use a significance level of 0.01 to test the claim that workplace accidents are distributed on workdays as follows: Monday: 25% Tuesday: 15% Wednesday: 15% Thursday: 15% and Friday: 30% In a study of 100 workplace accidents, 29 occurred on a monday, 12 occurred on a tuesday, 16 occurred on a wednesday, 15 occurred on a thursday, and 28 occurred on a Friday. Select the correct critical value.
A. Critical value: x^2=9.488
B. Critical value: x^=11.071
C. Critical value: x^=56.214
D. Critical value: x^=13.277

6. Use a Z^2 test to test the claim that in the given contingency table, the row variable and the column variable are independent. Responses to a survey question are borken down according to employment status and the sample results are given below. At the 0.10 significance level, test the claim that response and employment status are independent.
Yes No Undecided
Employed: 30 15 5
Unemployed: 20 25 10
Select the correct conclusion

7. Use a Z^2 test to test the claim that in the given contingency table, the row variable and the column variable are independent. Responses to a survey question are borken down according to employment status and the sample results are given below. At the 0.10 significance level, test the claim that response and employment status are independent.
Yes No Undecided
Employed: 30 15 5
Unemployed: 20 25 10
Select the correct test statistic and critical value.
A. Test statistic: x^2=4.231. Critical Value X^2=7.779
B. Test statistic: x^2=5.942. Critical Value X^2=4.605
C. Test statistic: x^2=5.942. Critical Value X^2=2.706
D. Test statistic: x^2=4.605 Critical Value X^2=2.706

8. Use a Z^2 test to test the claim that in the given contingency table, the row variable and the column variable are independent. Responses to a survey question are broken down according to gender and the sample results are given below. At the 0.05 significance level, test the claim that response and gender are independent.
Yes No Undecided
Male: 25 50 15
Female: 20 30 10
Select the correct conclusion

9. Use a Z^2 test to test the claim that in the given contingency table, the row variable and the column variable are independent. A study of 160 students who were majoring in either math or english were asked a test question, and the researcher recorded whether they answered correctly. The sample results are given below. At the 0.10 significance level, test the claim that response and major are indepedent.
Correct Incorrect
Math 27 53
English 43 37
Select the correct degrees of freedom
A. df=2
B. df=3
C. df=4
D. df=1

10. A researcher wishes to test whether the proportion of college students who smoke is the same in four different colleges. She randomly selects 100 students from each college and records the number that smoke. The results are shown below.
College A College B college C College D
Smoke 17 26 11 34
Don't smoke 83 74 89 66
Use a 0.01 significance level to test the claim that the proportion of students smoking is the same at all four colleges.
Select the correct test statistic and conclusion.
A. Test statistic: x^2=17.832. Reject the null hypothesis.
B. Test statistic: x^2=11.345. Reject the null hypothesis.
C. Test statistic: x^2=17.832. Fail to reject the null hypothesis.
D. Test statistic: x^2=11.345. Fail to reject the null hypothesis.

Answers

The correct conclusion is:

Fail to reject the null hypothesis.

There is not sufficient evidence to warrant rejection of the claim that absences occur on different weekdays with the same frequency.

Option C is the correct answer.

We have,

To test the claim that employee absences occur on different weekdays with the same frequencies, we need to use the chi-squared goodness of fit test.

First, we calculate the expected frequencies for each weekday assuming they have the same frequency.

Since there are 5 weekdays, we divide the total number of absences (130) by 5 to get the expected frequency of 26 for each weekday.

Using the formula for the chi-squared goodness of fit test, we can calculate the test statistic as follows:

χ² = Σ (O - E)² / E

where O is the observed frequency and E is the expected frequency.

Using the sample data, we get:

χ² = [(37-26)^2/26] + [(15-26)^2/26] + [(12-26)^2/26] + [(23-26)^2/26] + [(43-26)^2/26]

χ² = 8.658

The degrees of freedom for this test is (5 - 1) = 4, since we have 5 weekdays and one parameter (the frequency) has been estimated.

Using a chi-squared distribution table with 4 degrees of freedom and a significance level of 0.05, we find the critical value to be 9.488.

Since the test statistic (8.658) is less than the critical value (9.488), we fail to reject the null hypothesis.

Thus,

The correct conclusion is:

Fail to reject the null hypothesis.

There is not sufficient evidence to warrant rejection of the claim that absences occur on different weekdays with the same frequency.

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The Seattle Real Estate Market: Data are available on a number of recent home sales in 3 different cities in the Seattle, WA area. A regression model has been developed to predict selling price (in thousands of USD) based on the number of bedrooms, the number of bathrooms, and the total living area (in sqft.) as well as the city within which the property resides (either Bellevue, Renton, or Seattle).
THE RAW DATA FOR THIS QUESTION ARE **NOT** AVAILABLE TO YOU. Use the output below to answer the following questions.
ANOVA
df SS MS F-Statistic p-value
Regression 5 21,243,625 4,248,725 Residual 180 7,325,363 40,696 Total 185 28,568,988 Coefficients Standard Error t-Statistic p-value Intercept 200.824 61.332 Bedrooms -53.473 20.074 Bathrooms 20.264 31.315 Bellevue 62.114 44.077 Renton -265.282 42.166 Living Area 0.280 0.027 The coefficient for BEDROOMS is negative, which seems counterintuitive. Choose the BEST explanation for this result.
This is most likely the result of a multicollinearity problem with the model.
[A] This is likely because bedrooms, bathrooms, and living area are all roughly measuring the same thing: The size of the property.
[B] This is most likely the result of a non-constant variance problem with the model. This is likely because the spread around the regression line is different for different regions of the x variable range.
[C]This is most likely the result of an extrapolation beyond the range of the data problem with the model. This is likely because the model is being used to make predictions outside of the range of the original sample data.
[D] This is most likely the result of non-normal error problem with the model. This is likely because the model residuals are skewed or multi-modal to some degree.

Answers

[A] This is likely because bedrooms, bathrooms, and the living area are all roughly measuring the same thing: the size of the property.

The most likely explanation for the negative coefficient for BEDROOMS is option A - a multicollinearity problem with the model. This means that the variables included in the model (bedrooms, bathrooms, and living area) are highly correlated with each other, making it difficult to distinguish their individual effects on the selling price. As a result, the coefficient for BEDROOMS may be affected and appear counterintuitive.


[A] This is likely because bedrooms, bathrooms, and living area are all roughly measuring the same thing: The size of the property.

The negative coefficient for bedrooms could be a result of multicollinearity, where the predictor variables (bedrooms, bathrooms, and living area) are highly correlated. In this case, they are all related to the property's size, making it difficult for the model to distinguish their individual effects on the selling price.

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Please help me with this homework only the answer

Answers

try (-18,-5)

my step by step explanation is you would distrubute the -5 and add it to the -13 and you would do the same thing for the orher side

hopefully this is correct

and may i have brainliest

the price of a ball should not be more than $2. which inequality can be used to represent this problem?

Answers

In summary, the inequality x ≤ 2 represents the problem "the price of a ball should not be more than $2" and means that the value of x (the price of the ball) must be less than or equal to 2.

An inequality is a mathematical expression that compares two values and indicates whether they are equal or not, or whether one is greater than or less than the other. In this case, we want to represent the problem "the price of a ball should not be more than $2" using an inequality.

Let x be the price of the ball. The expression "the price of a ball should not be more than $2" means that the price of the ball, represented by x, must be less than or equal to $2. We can write this inequality as:

x ≤ 2

The symbol "≤" means "less than or equal to," and it indicates that the value of x should be less than or equal to 2. For example, if the price of the ball is $1.50, then x is less than 2, and the inequality x ≤ 2 is true. However, if the price of the ball is $3, then x is greater than 2, and the inequality x ≤ 2 is false.

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a gym believes that by doing its 45-minute exercise workout each day for a month, a person can lose more than 5 pounds. which statistical method would be best to use in this situation?

Answers

In this situation, the best statistical method to use would be a hypothesis test, specifically a one-sample t-test. This test will help determine if the average weight loss after following the gym's 45-minute workout routine for a month is significantly greater than 5 pounds.

In this situation, the best statistical method to use would be a hypothesis test. The gym's belief that their workout can lead to weight loss greater than 5 pounds can be tested by setting up a null hypothesis (the workout does not lead to weight loss greater than 5 pounds) and an alternative hypothesis (the workout does lead to weight loss greater than 5 pounds). The gym can then collect data on weight loss from participants who complete the workout for a month and use statistical analysis to determine if there is enough evidence to reject the null hypothesis and support the alternative hypothesis.

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Which of the following are assumptions for the confidence interval for the different between two population means?
Data is Quantitative.
Data is from a Convenience Sample
Random Sample
Both sample sizes are greater than 30 or the data from a Normal Distribution
Data is Categorical.
There are at least 15 successes and 15 failures.

Answers

The valid assumptions for constructing a confidence interval for the difference between two population means are: Data is Quantitative, Random Sample and Both sample sizes are greater than 30 or the data is from a Normal Distribution.

To answer your question, when constructing a confidence interval for the difference between two population means, certain assumptions must be met. These assumptions include:

1. Data is Quantitative: Since we are dealing with population means, the data should be quantitative, meaning it consists of numerical values. This is a correct assumption.
2. Data is from a Convenience Sample: This is not a valid assumption. To ensure the reliability of the confidence interval, data should be collected through random sampling, which ensures that each individual in the population has an equal chance of being included in the sample.
3. Random Sample: This is a correct assumption. A random sample is necessary to ensure the sample's representativeness and accuracy in estimating the population means.
4. Both sample sizes are greater than 30 or the data is from a Normal Distribution: This is a valid assumption. If both sample sizes are greater than 30, the Central Limit Theorem can be applied, which states that the sampling distribution of the sample means will be approximately normal. If the data is already from a normal distribution, the normality assumption is met.
5. Data is Categorical: This assumption is incorrect. As previously mentioned, the data should be quantitative for this analysis.
6. There are at least 15 successes and 15 failures: This assumption is not relevant for confidence intervals for the difference between two population means. This criterion is related to proportions rather than means.

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Three softball players discussed their batting averages after a game.


Probability
Player 1 seven elevenths
Player 2 six ninths
Player 3 five sevenths


Compare the probabilities and interpret the likelihood. Which statement is true?
Player 1 is more likely to hit the ball than Player 2 because P(Player 1) > P(Player 2)
Player 2 is more likely to hit the ball than Player 3 because P(Player 2) > P(Player 3)
Player 1 is more likely to hit the ball than Player 3 because P(Player 1) > P(Player 3)
Player 3 is more likely to hit the ball than Player 2 because P(Player 3) > P(Player 2)

Answers

The "Player 1 is more likely to hit the ball than Player 2 because P(Player 1) > P(Player 2)" is true.

To solve this problem

We need to convert them to a common denominator. The least common multiple of 11, 9, and 7 is 693.

Player 1: 7/11 = 504/693

Player 2: 6/9 = 462/693

Player 3: 5/7 = 495/693

Comparing the probabilities, we can see that:

Player 1 has a probability of 504/693 of hitting the ball.

Player 2 has a probability of 462/693 of hitting the ball.

Player 3 has a probability of 495/693 of hitting the ball.

Since the denominator is the same for all three players, we can directly compare the numerators.

Comparing the numerators, we can see that:

504 > 462 > 495

Therefore, Player 1 is more likely to hit the ball than Player 2 and Player 3.

Therefore, "Player 1 is more likely to hit the ball than Player 2 because P(Player 1) > P(Player 2)" is true.

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helpppp fast i will give brainliest to best answer!!!
Explain why too!!

Answers

Answer:

Step-by-step explanation:

First get y byitself to oneside

[tex]2x-y\leq 5[/tex]

Subtract -2x to bothside

[tex]-y\leq 5-2x[/tex]

Divide -1 to make y positive. Dividing or Multiplying changes direction.

[tex]y\geq 2x-5[/tex]

y >= any value above the positive of the line.

write the equation of the line that
passes through (2,-6) and is perpendicular to y = 2/3x+4

Answers

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+4\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{2} }}[/tex]

so we're really looking for the equation of a line whose slope is -3/2 and it passes through (2 , -6)

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{-6})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{- \cfrac{3}{2}}(x-\stackrel{x_1}{2}) \implies y +6 = - \cfrac{3}{2} ( x -2) \\\\\\ y+6=- \cfrac{3}{2}x+3\implies {\Large \begin{array}{llll} y=- \cfrac{3}{2}x-3 \end{array}}[/tex]

What is the equation of a line perpendicular to this line x+4y=-2

Answers

Step-by-step explanation:

solve for y

x-4y =24

-4y = 24-x

 y = x/4 - 6    slope = 1/4, the coefficient of the x term

a perpendicular line has the negative inverse,  change the sign and flip the fraction upside down to get -4/1 or -4

y=-4x + b.  plug in the point x=-2, y=7 to calculate b the y intercept

7=-4(-2) + b

b = 7-8 =-1

y=-4x -1 is the perpendicular line through (-2,7)

general equation in slope intercept form is y=mx +b.  m=-4,  b=-1

I need help what’s the answer

Answers

The complex number can be represented as matrix as follow:

[tex]\left[\begin{array}{cc}2&-3\\3&2\end{array}\right][/tex] [tex]\left[\begin{array}{cc}1&-4\\4&1\end{array}\right][/tex] and the correct answer from the option is (B)

How to solve the matrix of complex numbers

A complex number can be represented as a 2x2 matrix in the form:

[tex]\left[\begin{array}{cc}2&-3\\3&2\end{array}\right][/tex]

Addition and subtraction of complex numbers can be done by adding or subtracting the corresponding matrices.

Multiplication of two complex numbers can be done by multiplying the corresponding matrices and simplifying the result.

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