A thin uniform bar has a moment of inertia II about an axis perpendicular to it through its center. If both the mass and length of this bar are doubled, its moment of inertia about the same axis will be:_____.
A. 2I.
B. 4I.
C. 8I.
D. 16I.
E. I/16.

Answer:

-50* 1.6*10^-19 = -80*10^-19 = -8*10^-18 C

Answer:

A. Plastic cover.

B. Plastic cover will be shinny and clear which will be   acting like a plane mirror, instead use the clear plastic cover.

C. This does not affect much performance.

Explanation:

a. Instead of plane mirror we will use clear plastic cover

b. The clear plastic cover will be shinny and clear which will be acting like a plane mirror. So, in place of plane mirror we will place the clear plastic cover.

c. This modification will not affect much in the performance of  kaleidoscope as the clear plastic paper will be exactly the same  as the plane mirror.

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Answer:

Explanation: divide 280 by 68 which would = 4 I think

Answer:2

Explanation:

Need answer

Answer:

a. 44 km

b. 0 km/h

Explanation:

For part a, the faster boat finishes when the second turns around to come back.

For part b, the average velocity is zero because he travels forward (+) and then back (-). 44km/h - 44 km/h = 0 km/h

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

Answer:

distance = 3 + 4 = 7 mi

displacement is √(3² + 4²) = 5 mi

Explanation:

Answer:

4s

Explanation:

Answer:

10.45m/s^2

Explanation:

Cause acceleration is the force divided by the mass

Answer:

√((-3.00)² + (-4.00)²) = 5.00

Explanation:

The formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem.

|v| =√(x2 + y2).

V = √((-3.00)² + (-4.00)²)

  = 5.00

"A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. "Although a vector has magnitude and direction, it does not have position.

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#SPJ2

We have that the speed of the spaceship must be

[tex]V=2.47m/s[/tex]

From the Question we are told that

Mass [tex]8.7*10^{17} kg[/tex]

Positive charge of 4400 C

Spaceship mass m_s=3.3* 10^5 kg

Solar wind has given their spaceship a charge of -1.2 C.

Diameter d=8300-km-diameter

Generally the equation for the force of attraction   is mathematically given as

[tex]v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}[/tex]

[tex]V=2.47m/s[/tex]

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The speed will be "6.98 m/s". A complete solution is provided below.

The given values are:

Mass of asteroid,

Mass of spaceship,

Charge,

As we know,

→ [tex]F_G +F_E = \frac{mv^2}{R}[/tex]

or,

→ [tex]\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}[/tex]

By putting the given values, we get

→ [tex]\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2[/tex]

→                                                                   [tex]v=6.98 \ m/s[/tex]                                                                                                                                                      

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Explanation:

B I think it is because it has 48 gm than A

Initial velocity=u=3m/s

Final velocity=v=10m/s

Time=t=8s

[tex]\boxed{\sf Acceleration=\dfrac{v-u}{t}}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{7}{8}[/tex]

[tex]\\ \sf\longmapsto Acceleration=0.8m/s^2[/tex]

Using second equation of motion

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2[/tex]

[tex]\\ \sf\longmapsto s=24+0.4(64)[/tex]

[tex]\\ \sf\longmapsto s=24+25.6[/tex]

[tex]\\ \sf\longmapsto s=49.6m[/tex]

Answer:

F

T

F

T

T

Explanation:

Thanks for this oppurtunity

Answer: speed

Explanation:

Speed is the important key to the vector quantity

Answer:

The SI unit for intensity is watts per square meter (W/m2)

Answer:

μ = 0.724

Explanation:

maximum acceleration for SHM

a = ω²A

ω = 2πf

a = 4π²f²A

a = 4π²(1.50)²(0.080) = 7.106... m/s²

μ = F/N = ma/mg = a/g = 7.106/9.81 = 0.7243...

I'm cynical that a block can be cynical. Wassa madder, doesn't trust anyone?

Answer:

27 degrees Fahrenheit is -2.78°c

Answer:

Explanation:

a) 6 mm or 0.6 cm or 0.06 dm or 0.006 m or 0.000006 km

b) 12 mm or 1.2 cm or 0.12 dm or 0.012 m or 0.000012 km

c) 22 mm or 2.2 cm or 0.22 dm or 0.022 m or 0.000022 km

d) 37 mm or 3.7 cm or 0.37 dm or 0.037 m or 0.000037 km

e) 56 mm or 5.6 cm or 0.56 dm or 0.056 m or 0.000056 km

f) 67 mm or 6.7 cm or 0.67 dm or 0.067 m or 0.000067 km

g) 75 mm or 7.5 cm or 0.75 dm or 0.075 m or 0.000075 km

The complete question is;

Determine the order of magnitude of the following small number by entering the appropriate exponent n below: 6,370km≈10^n km .

Order of magnitude is 3.

        In this case, we have 6.37 and it is closer to 10 than 1.

The order of magnitude is the exponent attached to the 10 on the right.

Thus, order of magnitude is 3.

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The order of magnitude of the given number will be "3.804".

According to the question, the number is:

→ [tex]6370 \ km = 10^n \ km[/tex]

By taking "[tex]log_{10}[/tex]" both sides, we get

→ [tex]log_{10}(6370) = log_{10} \ 10^n[/tex]

By putting the values accordingly, we get

→ [tex]log_{10} (6370) = n[/tex]

→                [tex]n = 3.804[/tex]

Thus the above answer is correct.

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Answer:

Balance the nuclear equation

43

19K −→ 43

20 Ca + ?

1. ? = 1

0n

2. ? = 1

1p

3. ? = 43

18Ar

4. ? = 0

−1

β

5. None of these

6. ? = 43

−1

e

7. ? = 0

1

e

8. ? = 1

0n

9. ? = 2

3He

10. ? = 4

−1

p + e- + α

11. ? = 40

24Mg + β+ → 20 22Ne + γ

12. ? = 0

13C(β-)13N(e-)13C* → 13N(β-)13C(γ)13O + γ

The previous article was about the first step of fission process. The second step of fission is called secondary nuclear reaction, which includes the alpha decay and beta-minus (negative electron), beta-plus (positive electron), and gamma (high energy X-ray) emissions. Secondary nuclear reactions produce more neutrons than those produced by primary nuclear reaction.

The combining of two nuclei with less mass number than the original is called alpha decay, whereas, taking off a beta particle from nucleus is called beta-minus (negative electron), if the nucleus takes off a beta particle and proton, it is called beta-plus (positive electron), and a gamma ray with extremely high energy is called gamma emission.

The secondary nuclear reactions produce more neutrons than those produced by primary nuclear reaction. There are 5 common secondary nuclear reactions that can be seen in the fission process, as follows:

Alpha decay: α

Beta-minus (negative electron): β−

Beta-plus (positive electron): β+

Gamma emission: γ

Positron emission: β+

Explanation:

Alpha decay is a process in which a radioactive isotope emits an alpha particle and transforms into the element with 2 less protons. For example:

"43 19K → 20 22Ne + α"

In the previous equation, K-19 transforms into Ne-22 through alpha decay. The mass number decreases by 4 and the atomic number increases by 2. For instance 17O-16 becomes 18F-19 when it decays to fluorine. In this process, the mass number decreases by 4 and the atomic number increases by 2.

Beta-minus (negative electron) is a process of emitting an electron with negative charge from the nucleus. The electron that moves out of the nucleus has less energy than beta particle emitted during beta decay, which means it can be stopped easily with just a piece of paper.

Beta-minus (negative electron): β−

For example: "14 7N → 14 7C* + β−"

In the previous equation, N-14 transforms into C-14 through beta minus. The mass number remains unchanged and the atomic number decreases by 1. For instance 8O-15 becomes 8F-14 when it decays into fluorine. As the beta particle emitted in this process is negative, so the mass number remains unchanged and the atomic number decreases by 1.

Beta-plus (positive electron) is a process of emitting an electron with positive charge from the nucleus. The electron that moves out of the nucleus has more energy than beta particle emitted during beta decay, so it can be stopped only by special means like aluminum foils or other very dense materials.

Beta-plus (positive electron): β+

For example: "8 7Be → 8 4He + β+"

In the previous equation, Be-8 transforms into He-4 through beta plus. The mass number remains unchanged and the atomic number decreases by 2. For instance 14N-15 becomes 14O-8 when it decays into oxygen gas. As the beta particle emitted in this process is positive, so the mass number remains unchanged and the atomic number decrease by 2.

Gamma emission is a process of emitting electromagnetic waves from nuclei with no change to nuclear structure. Gamma radiation has less frequency than X-rays but higher energy, so gamma rays are very powerful radiation means that can pass through human body easily, whereas X-ray has less power so cannot pass through human body easily. Gamma rays are also used for imaging purposes because they are high penetrating power source which allows scientists to see inside opaque objects like humans or rocks without harming people or things.

Gamma emission: γ

For example: 2 1H → 1 0n + γ"

In the previous equation, H-2 transforms into neutron through gamma emission. The mass number remains unchanged and the atomic number is decreased by 1. For instance 13N-14 becomes 14O-13 when it decays into oxygen gas with radiation of gamma ray. As this process does not change the mass number so the atomic number decreases by 1.

Positron emission is a process in which an electron with positive charge moves out of nucleus to form an atom of anti-matter (the anti-particle). If matter and anti-matter collide each other they destroy themselves, but positrons are used in medicine for imaging because they emit radiation.

Positron emission: β+

For example: 1 1H → 1 0n + γ + β+"

In the previous equation, H-1 transforms into neutron through gamma emission and beta plus emission. The mass number remains unchanged and the atomic number is decreased by 2. For instance 13N-14 becomes 14O-13 when it decays into oxygen gas with radiation of positrons and gamma rays. As this process decreases the atomic number by two, so the mass number remains unchanged during decay process.

Answer:

Rotation of a fluid particle can be caused only by a torque applied by shear forces on the sides of the particle. Since shear forces are absent in an ideal fluid, the flow of ideal fluids is essentially irrotational. Generally when the flow is viscid, it also becomes rotational

The  magnitude of their resultant vector is 4.6 meters/seconds

Since we are to add the  velocity vectors in order to  find the magnitude of their resultant vector.

Hence:

Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)

Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds

Resultant vector magnitude 4.6 meters/seconds

Inconclusion The  magnitude of their resultant vector is 4.6 meters/seconds

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Answer:

25

Explanation:

v=u+at.

50=a(5)

a=10m/s^2.

distance= ut+ 1/2 at^2

=125

average speed = total distance/total time

=125/5

=25

The average speed of  the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.

Hence, Option C) 25 m/s is the correct answer.

Given the data in the question;

Since the object was initially at rest,

First we determine the acceleration "a", using the First equation of motion:

[tex]v = u + at[/tex]

Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

We substitute our values into the equation

[tex]50m/s = 0 + ( a \ * \ 5.0s)\\\\a = \frac{50m/s}{5.0s} \\\\a = 10m/s^2[/tex]

Next we Calculate the distance travelled by the object

From the Second Equation of Motion:

[tex]s = ut \ + \ \frac{1}{2}at^2[/tex]

Where, u is the initial velocity, a is the acceleration and t is the time and s is the distance travelled.

Wes substitute our values into the equation

[tex]s = (0\ * 5.0s) + ( \frac{1}{2} \ *\ 10m/s^2 \ * (5.0s)^2)\\\\s = \frac{1}{2} \ *\ 10m/s^2 \ * 25s^2\\\\s = 125m[/tex]

Now, we can get the Average speed of the object.

We know that, Speed is the distance travelled per unit time.

[tex]Speed = \frac{Distance}{Time}[/tex]

We substitute our values into the equation

[tex]Speed = \frac{125m}{5.0s}\\\\Speed = 25m/s[/tex]

The average speed of  the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.

Hence, Option C) 25 m/s is the correct answer.

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Answer: 13,467 m/s

Explanation: The speed of a wave equals the frequency of the wave multiplied by the wavelength. In this instance the speed = 20,100 Hz * 0.67 m.