A thin uniform bar has a moment of inertia II about an axis perpendicular to it through its center. If both the mass and length of this bar are doubled, its moment of inertia about the same axis will be:_____.
A. 2I.
B. 4I.
C. 8I.
D. 16I.
E. I/16.

Answers

Answer 1

Answer:

C. 8I.

Explanation:

As moment of inertia for a bar is proportional to the product of its mass and the square of its length, doubling the mass will double the moment of inertia. Doubling the length will quadruple the moment of inertia. Doing both will make the moment of inertia 2(4) = 8 times larger


Related Questions

3. Write "T" for true statements and "F" for false statements:
a. Protozoa are multi cellular animals.
b. Vacuoles are larger in plant cell.
c. Body of mammals is covered with feathers.
d. There is a pair of antenna on the head of a cockroach.
e. Birds have hollow and air filled bones.

Answers

Answer:

F

T

F

T

T

Explanation:

Thanks for this oppurtunity

Two boats start together and race across a 44 km wide lake and back. Boat A goes across at 44 km/h and returns at 44 km/h. Boat B goes across at 22 km/h, and its crew, realizing how far behind it is getting, returns at 66 km/h. Turnaround times are negligible, and the boat that completes the round-trip first wins.
Which boat wins and by how much? (Or is it a tie?)
(a) By how much? (Enter NONE if it was a tie.)
km
(b) What is the average velocity of the winning boat? (Enter NONE if it was a tie.)
km/h .... I put 44 for this answer and it was.

Answers

Answer:

a. 44 km

b. 0 km/h

Explanation:

For part a, the faster boat finishes when the second turns around to come back.

For part b, the average velocity is zero because he travels forward (+) and then back (-). 44km/h - 44 km/h = 0 km/h

An object accelerates uniformly from rest to a speed of
50 meters per second in 5.0 seconds. The average speed of
the object during the 5.0-second interval is
A 5.0 m/s
B 10 m/s
C 25 m/s
D 50 m/s

Answers

Answer:

25

Explanation:

v=u+at.

50=a(5)

a=10m/s^2.

distance= ut+ 1/2 at^2

=125

average speed = total distance/total time

=125/5

=25

The average speed of  the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.

Hence, Option C) 25 m/s is the correct answer.

Given the data in the question;

Since the object was initially at rest,

Initial velocity; [tex]u = 0[/tex]Final velocity; [tex]v = 50m/s[/tex]Time; [tex]t = 5.0s[/tex]

First we determine the acceleration "a", using the First equation of motion:

[tex]v = u + at[/tex]

Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

We substitute our values into the equation

[tex]50m/s = 0 + ( a \ * \ 5.0s)\\\\a = \frac{50m/s}{5.0s} \\\\a = 10m/s^2[/tex]

Next we Calculate the distance travelled by the object

From the Second Equation of Motion:

[tex]s = ut \ + \ \frac{1}{2}at^2[/tex]

Where, u is the initial velocity, a is the acceleration and t is the time and s is the distance travelled.

Wes substitute our values into the equation

[tex]s = (0\ * 5.0s) + ( \frac{1}{2} \ *\ 10m/s^2 \ * (5.0s)^2)\\\\s = \frac{1}{2} \ *\ 10m/s^2 \ * 25s^2\\\\s = 125m[/tex]

Now, we can get the Average speed of the object.

We know that, Speed is the distance travelled per unit time.

[tex]Speed = \frac{Distance}{Time}[/tex]

We substitute our values into the equation

[tex]Speed = \frac{125m}{5.0s}\\\\Speed = 25m/s[/tex]

The average speed of  the object during the 5.0-second interval as it accelerates uniformly from rest is 25m/s.

Hence, Option C) 25 m/s is the correct answer.

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Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.​

Answers

Answer:

distance = 3 + 4 = 7 mi

displacement is √(3² + 4²) = 5 mi

Explanation:

i though a=9.8 is in free fall?

Answers

9.8m/s^2, i’m not sure what you are asking
A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). ... It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity.

Calculate the speed of a wave that has a frequency of 20,100 Hz and a wavelength of 0.67 m.

Answers

Do you have a caculater? If so use it!

Answer: 13,467 m/s

Explanation: The speed of a wave equals the frequency of the wave multiplied by the wavelength. In this instance the speed = 20,100 Hz * 0.67 m.

Which of the following is the best order-of-magnitude estimate in meters
of the height of a mountain?
a. 1 m
b. 10 m
c. 100 m
d. 1000 m

Answers

Answer:2

Explanation:

Need answer

d. Hydrogen gas is filled in two
identical bottles, A and B, at the
same temperature. The mass of
hydrogen in the two bottles is 12
gm and 48 gm respectively. In
which bottle will sound travel
faster? How may times as fast as
the other?
(Ans: In A; Twice)​

Answers

Explanation:

B I think it is because it has 48 gm than A

A truck travels 40 m while slowing down from 15 m/s to 10 m/s. How long does it take to do this?

Answers

Answer:

4s

Explanation:

7) Somewhere you place a 7.5 kg pumpkin on a spring scale. If the scale reads 78.4 N,
what is the acceleration due to gravity at that location?

Answers

Answer:

10.45m/s^2

Explanation:

Cause acceleration is the force divided by the mass

What are the conditions for a flow to be irotational flow​

Answers

Answer:

Rotation of a fluid particle can be caused only by a torque applied by shear forces on the sides of the particle. Since shear forces are absent in an ideal fluid, the flow of ideal fluids is essentially irrotational. Generally when the flow is viscid, it also becomes rotational

a person can run 280m in 68s. at what speed are they running?

Answers

Answer:

Explanation: divide 280 by 68 which would = 4 I think

4.1m/s
hope this helps

A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial, the student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
A. The student does not have a dependent variable.
B. The student changed too many variables.
C. The student needs to perform more trials.
D. The student did not change enough variables.

Answers

B- the student changed too many variables

You were asked to make Kaleidoscope by your teacher for a school project. But no plane mirrors are available with you. How will you construct the Kaleidoscope without the plane mirror? Do you think it will work as good as a kaleidoscope with plane mirrors? Write a report in 4 to 6 sentences. Consider the following points- a. What alternate materials/ tools you will use instead of the plane mirror? b. How will you assemble those to construct the Kaleidoscope? c. How will these modifications affect the performance of the Kaleidoscope?​

Answers

Answer:

A. Plastic cover.

B. Plastic cover will be shinny and clear which will be   acting like a plane mirror, instead use the clear plastic cover.

C. This does not affect much performance.

Explanation:

a. Instead of plane mirror we will use clear plastic cover

b. The clear plastic cover will be shinny and clear which will be acting like a plane mirror. So, in place of plane mirror we will place the clear plastic cover.

c. This modification will not affect much in the performance of  kaleidoscope as the clear plastic paper will be exactly the same  as the plane mirror.

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13.1 An object has an excess of 50 electrons. What
is the charge on the object in picocoulomb?


Answers

Answer:

-50* 1.6*10^-19 = -80*10^-19 = -8*10^-18 C

A cynical block on an air table vibrates horizontally in SHM with an amplitude of 8.0cm and a frequency of 1.50Hz. If a smaller block sitting on it is not to slide, what is the minimum value that the coefficient of static friction between the two blocks can have?

Answers

Answer:

μ = 0.724

Explanation:

maximum acceleration for SHM

a = ω²A

ω = 2πf

a = 4π²f²A

a = 4π²(1.50)²(0.080) = 7.106... m/s²

μ = F/N = ma/mg = a/g = 7.106/9.81 = 0.7243...

I'm cynical that a block can be cynical. Wassa madder, doesn't trust anyone?

Balance the nuclear equation
43
19K −→ 43
20 Ca + ?
1. ? = 1
0n
2. ? = 1
1p
3. ? = 43
18Ar
4. ? = 0
−1
β
5. None of these
6. ? = 43
−1
e
7. ? = 0
1
e

Answers

Answer:

Balance the nuclear equation

43

19K −→ 43

20 Ca + ?

1. ? = 1

0n

2. ? = 1

1p

3. ? = 43

18Ar

4. ? = 0

−1

β

5. None of these

6. ? = 43

−1

e

7. ? = 0

1

e

8. ? = 1

0n

9. ? = 2

3He

10. ? = 4

−1

p + e- + α

11. ? = 40

24Mg + β+ → 20 22Ne + γ

12. ? = 0

13C(β-)13N(e-)13C* → 13N(β-)13C(γ)13O + γ

The previous article was about the first step of fission process. The second step of fission is called secondary nuclear reaction, which includes the alpha decay and beta-minus (negative electron), beta-plus (positive electron), and gamma (high energy X-ray) emissions. Secondary nuclear reactions produce more neutrons than those produced by primary nuclear reaction.

The combining of two nuclei with less mass number than the original is called alpha decay, whereas, taking off a beta particle from nucleus is called beta-minus (negative electron), if the nucleus takes off a beta particle and proton, it is called beta-plus (positive electron), and a gamma ray with extremely high energy is called gamma emission.

The secondary nuclear reactions produce more neutrons than those produced by primary nuclear reaction. There are 5 common secondary nuclear reactions that can be seen in the fission process, as follows:

Alpha decay: α

Beta-minus (negative electron): β−

Beta-plus (positive electron): β+

Gamma emission: γ

Positron emission: β+

Explanation:

Alpha decay is a process in which a radioactive isotope emits an alpha particle and transforms into the element with 2 less protons. For example:

"43 19K → 20 22Ne + α"

In the previous equation, K-19 transforms into Ne-22 through alpha decay. The mass number decreases by 4 and the atomic number increases by 2. For instance 17O-16 becomes 18F-19 when it decays to fluorine. In this process, the mass number decreases by 4 and the atomic number increases by 2.

Beta-minus (negative electron) is a process of emitting an electron with negative charge from the nucleus. The electron that moves out of the nucleus has less energy than beta particle emitted during beta decay, which means it can be stopped easily with just a piece of paper.

Beta-minus (negative electron): β−

For example: "14 7N → 14 7C* + β−"

In the previous equation, N-14 transforms into C-14 through beta minus. The mass number remains unchanged and the atomic number decreases by 1. For instance 8O-15 becomes 8F-14 when it decays into fluorine. As the beta particle emitted in this process is negative, so the mass number remains unchanged and the atomic number decreases by 1.

Beta-plus (positive electron) is a process of emitting an electron with positive charge from the nucleus. The electron that moves out of the nucleus has more energy than beta particle emitted during beta decay, so it can be stopped only by special means like aluminum foils or other very dense materials.

Beta-plus (positive electron): β+

For example: "8 7Be → 8 4He + β+"

In the previous equation, Be-8 transforms into He-4 through beta plus. The mass number remains unchanged and the atomic number decreases by 2. For instance 14N-15 becomes 14O-8 when it decays into oxygen gas. As the beta particle emitted in this process is positive, so the mass number remains unchanged and the atomic number decrease by 2.

Gamma emission is a process of emitting electromagnetic waves from nuclei with no change to nuclear structure. Gamma radiation has less frequency than X-rays but higher energy, so gamma rays are very powerful radiation means that can pass through human body easily, whereas X-ray has less power so cannot pass through human body easily. Gamma rays are also used for imaging purposes because they are high penetrating power source which allows scientists to see inside opaque objects like humans or rocks without harming people or things.

Gamma emission: γ

For example: 2 1H → 1 0n + γ"

In the previous equation, H-2 transforms into neutron through gamma emission. The mass number remains unchanged and the atomic number is decreased by 1. For instance 13N-14 becomes 14O-13 when it decays into oxygen gas with radiation of gamma ray. As this process does not change the mass number so the atomic number decreases by 1.

Positron emission is a process in which an electron with positive charge moves out of nucleus to form an atom of anti-matter (the anti-particle). If matter and anti-matter collide each other they destroy themselves, but positrons are used in medicine for imaging because they emit radiation.

Positron emission: β+

For example: 1 1H → 1 0n + γ + β+"

In the previous equation, H-1 transforms into neutron through gamma emission and beta plus emission. The mass number remains unchanged and the atomic number is decreased by 2. For instance 13N-14 becomes 14O-13 when it decays into oxygen gas with radiation of positrons and gamma rays. As this process decreases the atomic number by two, so the mass number remains unchanged during decay process.

Is the melting point of an object a physical or chemical property

Answers

Answer:

Physical property

Convert 27 Fahrenheit to Celsius

Answers

Answer:

27 degrees Fahrenheit is -2.78°c

-2.77778 celcius
I hope this helps

Determine the order of magnitude of the following small number by entering the appropriate exponent n below:

6,370 ≈ 10^n km

Answers

The complete question is;

Determine the order of magnitude of the following small number by entering the appropriate exponent n below: 6,370km≈10^n km .

Order of magnitude is 3.

Now, when dealing with order of magnitude, we first write the number in scientific notation. We will have; 6.37 × 10³ km

The second thing we now do is to approximate the numerical part to either 1 or 10 as the case may be.

        In this case, we have 6.37 and it is closer to 10 than 1.

Thus, rewriting our number, we now have; 10 × 10³ km

The order of magnitude is the exponent attached to the 10 on the right.

Thus, order of magnitude is 3.

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The order of magnitude of the given number will be "3.804".

According to the question, the number is:

→ [tex]6370 \ km = 10^n \ km[/tex]

By taking "[tex]log_{10}[/tex]" both sides, we get

→ [tex]log_{10}(6370) = log_{10} \ 10^n[/tex]

By putting the values accordingly, we get

→ [tex]log_{10} (6370) = n[/tex]

→                [tex]n = 3.804[/tex]

Thus the above answer is correct.

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Learning Check: Ranking Elements
Use the following five elements to answer the next three questions: Na, K, Ca, He, Fr
1. Rank these elements from largest atomic radius to smallest.
2. Rank these elements from most metallic to least metallic.
3. Rank these elements from least electromagnetic to most electromagnetic.
Resubmit Assignment
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Answers

yes
62748476182973838292

define the term work​

Answers

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force

Explanation:

at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

A car speeds up from 3 m/s to 10 m/s in 8 s. How far does the car travel while doing this? 2. A

Answers

Initial velocity=u=3m/s

Final velocity=v=10m/s

Time=t=8s

[tex]\boxed{\sf Acceleration=\dfrac{v-u}{t}}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{10-3}{8}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{7}{8}[/tex]

[tex]\\ \sf\longmapsto Acceleration=0.8m/s^2[/tex]

Distance =s

Using second equation of motion

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=3(8)+\dfrac{1}{2}(0.8)(8)^2[/tex]

[tex]\\ \sf\longmapsto s=24+0.4(64)[/tex]

[tex]\\ \sf\longmapsto s=24+25.6[/tex]

[tex]\\ \sf\longmapsto s=49.6m[/tex]

If vector A has components Az = -3.00 and Ay = -4.00, then the magnitude of A is

Answers

Answer:

√((-3.00)² + (-4.00)²) = 5.00

Explanation:

The formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem.

|v| =√(x2 + y2).

V = √((-3.00)² + (-4.00)²)

  = 5.00

What is vector ?

"A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. "Although a vector has magnitude and direction, it does not have position.

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Add these two velocity vectors to find the magnitude of their resultant vector.
5.8 meters/seconds + 1.2 meters/seconds

Answers

The  magnitude of their resultant vector is 4.6 meters/seconds

Since we are to add the  velocity vectors in order to  find the magnitude of their resultant vector.

Hence:

Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)

Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds

Resultant vector magnitude 4.6 meters/seconds

Inconclusion The  magnitude of their resultant vector is 4.6 meters/seconds

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I tried zooming it in more, please help-

Answers

Answer:

Explanation:

a) 6 mm or 0.6 cm or 0.06 dm or 0.006 m or 0.000006 km

b) 12 mm or 1.2 cm or 0.12 dm or 0.012 m or 0.000012 km

c) 22 mm or 2.2 cm or 0.22 dm or 0.022 m or 0.000022 km

d) 37 mm or 3.7 cm or 0.37 dm or 0.037 m or 0.000037 km

e) 56 mm or 5.6 cm or 0.56 dm or 0.056 m or 0.000056 km

f) 67 mm or 6.7 cm or 0.67 dm or 0.067 m or 0.000067 km

g) 75 mm or 7.5 cm or 0.75 dm or 0.075 m or 0.000075 km

1) The SI Unit for intensity is a ms! b. Nm? C. SI d. Wm​

Answers

Answer:

The SI unit for intensity is watts per square meter (W/m2)

1. What is true about elements

Answers

w is the noble gas having atomic number 10 and configuration (2,8)
x, y and z are the s block elements. They have 2,2 and 1 electrons in their outermost shell respectively.
Atomic size decreases across the period and increases down the group. Element z is having more atomic size.

Hope it helps you!!!!

Space explorers discover an 8.7 × 1017 kg asteroid that happens to have a positive charge of 4400 C. They would like to place their 3.3 × 105 kg spaceship in orbit around the asteroid. Interestingly, the solar wind has given their spaceship a charge of -1.2 C.
What speed must their spaceship have to achieve a 8300-km-diameter circular orbit?

Answers

We have that the speed of the spaceship must be

[tex]V=2.47m/s[/tex]

From the Question we are told that

Mass [tex]8.7*10^{17} kg[/tex]

Positive charge of 4400 C

Spaceship mass m_s=3.3* 10^5 kg

Solar wind has given their spaceship a charge of -1.2 C.

Diameter d=8300-km-diameter

Generally the equation for the force of attraction   is mathematically given as

[tex]v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}[/tex]

[tex]V=2.47m/s[/tex]

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The speed will be "6.98 m/s". A complete solution is provided below.

The given values are:

Mass of asteroid,

M = [tex]8.7\times 10^{17}[/tex] kg

Mass of spaceship,

m = [tex]3.3\times 10^{5}[/tex] kg

Charge,

[tex]q_1=4400 \ C[/tex][tex]q_2=1.2 \ C[/tex]

As we know,

→ [tex]F_G +F_E = \frac{mv^2}{R}[/tex]

or,

→ [tex]\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}[/tex]

By putting the given values, we get

→ [tex]\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2[/tex]

→                                                                   [tex]v=6.98 \ m/s[/tex]                                                                                                                                                      

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Which of the following statements is an example of a vector quantity. SP1.c.
A. acceleration
C. speed
B. distant
D. time

Answers

Answer: speed

Explanation:

Speed is the important key to the vector quantity

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