A town uses positive numbers to track increases in population and negative numbers to track decreases in population...

The population has decreased by 300 residents over the past 5 years. The same number of residents left each year.What was the change in the town's population each year?

residents:

Answer:

W= -6

Step-by-step explanation:

-4w = -5 + 29

-4w = 24

Divide both sides by -4

=

W = -6

Answer:

you change w to the other side then proceed as you normally would

Answer:

A (0.5, 4)

B (-3, 0)

C (-1, 1)

Step-by-step explanation:

In a coordinate, the x-value comes first, then the y-value.

a) The geometric definition of the constant π is the ratio of a circle's circumference to its diameter.
b) The exact perimeter of the irregular pentagon is approximately 9.236 cm.
c) The exact area of the irregular hexagon cannot be determined with the given information.

a) The constant π is defined geometrically as the ratio of a circle's circumference to its diameter. In other words, it represents the relationship between the distance around a circle and the distance across it. It is an irrational number, approximately equal to 3.1416, but its exact value cannot be expressed as a finite decimal or fraction.
b) To find the exact perimeter of the irregular pentagon, we need additional information such as the lengths of its sides or the coordinates of its vertices. Without this information, it is not possible to calculate the exact perimeter.
c) Similarly, to find the exact area of the irregular hexagon, we need additional information such as the lengths of its sides or the coordinates of its vertices. Without this information, it is not possible to determine the exact area using the subtraction or addition method. Other methods such as dividing the hexagon into triangles or using trigonometric functions may be needed to calculate the area accurately.

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Using the same guideline, for a four-credit class, you would ideally spend:

4 credits * 2-3 hours/credit = 8-12 hours per week.

it is suggested that students allocate around 2-3 hours of study time per credit hour per week for a college-level course. However, the actual study time required may vary based on individual learning styles, prior knowledge, and the specific requirements set by professors or institutions.

Let's apply this general guideline to your scenario:

One three-credit class that is less demanding:

Assuming 2-3 hours of study per credit hour, for a three-credit class, you would ideally spend:

3 credits * 2-3 hours/credit = 6-9 hours per week.

Two three-credit classes that are typically demanding:

Similarly, for each of the two three-credit classes, you would spend:

3 credits * 2-3 hours/credit = 6-9 hours per week.

Since you have two such classes, the total time would be:

2 * (6-9) hours = 12-18 hours per week.

One four-credit class that is very challenging:

Using the same guideline, for a four-credit class, you would ideally spend:

4 credits * 2-3 hours/credit = 8-12 hours per week.

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Answer:

x= -47/3

Step-by-step explanation:

3x-6x=23-8-5+37

-3x=47

3x=-47

x= -47/3

Answer:

X= -47/3

that's the answer

Answer:

D

Step-by-step explanation:

Answer:

I think it is 50:1

Step-by-step explanation:

Answer:

f(-8) = 45

Step-by-step explanation:

Step 1: Define

f(x) = -6x - 3

x = -8

Step 2: Substitute and Evaluate

f(-8) = -6(-8) - 3

f(-8) = 48 - 3

f(-8) = 45

Answer:

b) frequency

The number of times a particular observation repeats in a data is defined as frequency

Answer:

24

Step-by-step explanation:

y= 24-4x

Answer:

1.2 yard i got it right!

Step-by-step explanation:

Answer:

-$74

Step-by-step explanation:

$20 * 3 = $60

$235 - $60 = $175

$175 + $130 = $305

$167 + $212 = $379

305 - 379 = -74

He is $74 in debt

Answer:

$-74

Step-by-step explanation:

$235 - $20 - $20 - $20 = $175

$175 + $130 = $305

$305 - $167 = $138

$138 - $212 = $-74

In this question, we are asked to perform various calculations and verify Green's theorem in the plane. The first section involves calculating the square root of a vector and finding the dot product of two vectors.

The second section requires finding the directional derivative of a function at a given point in a specific direction. Finally, the third section involves verifying Green's theorem for a given curve and region.

A. In the first part of the question, we are asked to calculate the square root of a vector (√x) and find the dot product of two vectors (V.R). To calculate √x (R² R), we take the square root of each component of the vector R (Xi+Yj+Zk) individually. For V.R, we perform the dot product operation, which involves multiplying corresponding components of the two vectors and summing them up.

B. In the second part, we need to find the directional derivative of the function p=x²yz + 4xz² at the point (1, -2, -1) in the direction of 2i-j-k. The directional derivative measures the rate of change of a function along a given direction. To find it, we calculate the gradient of the function and then take the dot product of the gradient with the direction vector.

C. The third part involves verifying Green's theorem for a given curve C and region bounded by y=x and y=x². Green's theorem relates a line integral around a simple closed curve C to a double integral over the plane region bounded by C. To verify the theorem, we calculate the line integral of the given differential form [(xy + y²)dx + x³dy over the curve C and compare it to the double integral of the divergence of the form over the region bounded by C.

In summary, this question requires performing vector calculations, finding directional derivatives, and verifying Green's theorem. Each section involves applying specific mathematical concepts and techniques to arrive at the final solutions.

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The domain and the range of the function are

From the question, we have the following parameters that can be used in our computation:

The graph (see attachment)

The above graph can be represented as a list of ordered pairs

The rule of a graph is that

Using the above as a guide, we have the following:

Domain = [-8, -3) U [-3, 6) U (6, ∝)

Range = (-4, ∝)

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Answer: ∠E = 109°

Step-by-step explanation:

The interior angles of a pentagon add up to 540°:

540 - 121 - 108 - 102 - 100 = 109

∠E = 109°

Hope this helps!

Answer:

Please can you repost the question the picture is not visible

Answer:

10 D + 1  P = 140

140 - 10(p) = 130

10 D = 130

130/10 = 13

13 = 13 dimes.

Answer:

r = 42

Step-by-step explanation:

Answer:

6÷ (-2) = (-3)

Step-by-step explanation:

i used a calculator

but good question

Answer: 24

Step-by-step explanation:

Answer:

[tex]\huge\boxed{4^{-2}}[/tex]

Step-by-step explanation:

If we have the expression [tex]4^6 \cdot 4^{-8}[/tex], our goal is to simplify it.

Using exponent rules, we know that [tex]a^b \cdot a^c = a^{b+c}[/tex].

Therefore, we can add our exponents (since we have the same base, 4) to get our simplified expression.

[tex]6 + -8[/tex]

Adding a negative is the same as subtracting a positive.

[tex]6 - 8 = -2[/tex]

Now we raise 4 to that power.

[tex]4^{-2}[/tex]

Hope this helped!

Answer:

1 1/9

Step-by-step explanation:

Its a mixed number

Responda:

GRÁFICO DE TEMPO DE VELOCIDADE

Explicação passo a passo:

Para a pergunta, encontre o gráfico de velocidade-tempo no anexo.

O gráfico que melhor representa a velocidade desse avião em função do tempo é o gráfico velocidade-tempo. O gráfico de velocidade e tempo é um gráfico que representa o movimento de um objeto esquematicamente usando linhas. Ele é plotado em um plano de coordenadas com o eixo xe o eixo y.

A função de velocidade é posicionada no eixo y, enquanto o tempo gasto ao longo da viagem está no eixo x.

Pelo anexo, pode-se ver que o avião acelera em OA, possui velocidade constante em AB e CD e tem aceleração (desaceleração) negativa em BC e DE.

Answer:

The expression "20a/4" can be simplified by dividing 20a by 4.

To do this, we can first simplify 20/4, which is equal to 5. Then we can multiply 5 by a to get the final answer:

20a/4 = (20/4) * a = 5 * a = 5a

Therefore, the expression "20a/4" simplifies to "5a".

Step-by-step explanation:

20a/4 is a mathematical expression that involves division. To find the value of this expression, we need to divide the value of 20a by 4.

We can simplify the expression by dividing the numerator (20a) by the denominator (4). When we divide 20a by 4, we get:

20a/4 = 5a

Therefore, 20a/4 is equivalent to 5a.

To summarize, the expression 20a/4 means dividing 20 times the value of variable "a" by 4. The result of this expression is equivalent to 5 times the value of variable "a".

A) The word IMPORTANCE has 10 letters, and all of them are unique. So, the number of ways to arrange the letters in a row is 10!, or 3,628,800.

B) If I and M must remain next to each other, we can treat them as a single letter. This gives us 9 letters to arrange, which can be done in 9! ways, or 362,880. We then need to divide by 2 to account for the fact that I and M can be arranged in two different ways (IM and MI). This gives us a final answer of 181,440.

C) If P, O, and R cannot be together in any order, we can treat them as three separate groups of letters. This gives us 6 groups of letters to arrange, which can be done in 6! ways, or 720 ways. We then need to divide by 3! to account for the fact that P, O, and R can be arranged in 3 different ways (POR, ORP, and RPO). This gives us a final answer of 240.

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The quartiles divide a dataset into four equal sections. The quartiles are used to measure the central tendency and variability of a dataset.

The quartiles divide the data into four parts, with each part containing an equal number of values. The quartiles are the first quartile (Q1), the second quartile (Q2), and the third quartile (Q3).

For second quartile:The stem-and-leaf plot for the test scores of 24 students is given below:5|2 4 5 5 7 8 9 6|4 5 6 6 7 7 1|1 2 2 4 8 3|4 6 7 7 7 9

The data must be ordered from least to greatest before calculating the quartiles.1.

Order the data:1 2 2 4 4 5 5 5 6 6 6 7 7 7 7 8 9 9 2.

The median is the middle value in the dataset. The median divides the data into two halves, with half the data on either side of the median. If there is an even number of values in the dataset, the median is the average of the two middle values.

In this case, there are 24 values, so the median is the average of the twelfth and thirteenth values:(6+7)/2=6.5

Therefore, Q2=6.53.

The first quartile (Q1) is the median of the lower half of the dataset. Q1 divides the lower half of the data into two quarters, with half the data on either side of Q1. 12 values are in the lower half of the dataset. Q1 is the median of these values.

Therefore, the values 1 2 2 4 4 5 5 5 6 6 6 7 are used to calculate Q1:(5+5)/2=5

Therefore, Q1=5.4.

The third quartile (Q3) is the median of the upper half of the dataset. Q3 divides the upper half of the data into two quarters, with half the data on either side of Q3.

12 values are in the upper half of the dataset. Q3 is the median of these values.

Therefore, the values 7 7 7 8 9 9 are used to calculate Q3:(7+8)/2=7.5

Therefore, Q3=7.5 .

The median (Q2) is 6.5. The interquartile range (IQR) is the difference between Q3 and Q1.

Therefore, the interquartile range (IQR) is 7.5-5=2.5.

The first quartile (Q1) of the given stem-and-leaf plot is 5, and the third quartile (Q3) is 7.5. The median (Q2) is 6.5. The interquartile range (IQR) is 2.5.

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