Here, the total momentum before and after the release of the projectile is same. From this concept the final velocity of the cannon after the release will be 0.00433 m/s.
What is conservation of momentum ?Momentum of an object is the product of its mass and velocity. During a collision, the momentum after and before the collision is constant. This can be applied in the case of a projectile from the cannon.
Here, the initial momentum of the cannon and the ball is zero, because they are at rest.
After, projectile the total momentum momentum is zero itself according to conservation of momentum.
momentum of the ball = 0.05 kg × 0.1 m/s cos 30 + 1 kg × v = 0
Here v is the velocity of the cannon.
then v = 0.05 kg × 0.1 m/s cos 30 / 1 kg
= 0.0043 m/s.
Therefore, the velocity of the cannon after the projectile is released is 0.0043 m/s.
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7. A skydiver has dropped out of the airplane and has just deployed their parachute. They notice that they are
moving at an acceleration of 2 ms. They also know that their mass is 80 kg. What is their force?
10N to the right, what is their force
can you please help me ASAP show your answer on paper please make it readable
Different elements' atoms can have different quantities of neutrons in their nuclei. For instance, stable helium atoms with one or two neutrons are known, although they both have two protons.
What is Atomic mass?Isotopes are the several varieties of helium atoms that have differing masses.
The total number of protons and neutrons in an isotope's nucleus is referred to as the mass number. This is due to the fact that each proton and neutron has a mass of one atomic mass unit (amu).
We may get the mass of the atom by multiplying the total number of protons and neutrons by 1 amu. Each element is made up of a variety of isotopes.
Therefore, Different elements' atoms can have different quantities of neutrons in their nuclei. For instance, stable helium atoms with one or two neutrons are known, although they both have two protons.
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After finishing her Physics homework, Julie pulls her 50.0kg body out of the living room chair and climbs the 5.0m high flight of stairs to her bedroom. How much work does Julie do in ascending the stairs?
Answer: 2452.5 Joules
Explanation: The equations we will be using in the problem are Weight=Mass*(Newton's Gravitational constant(9.81m/s^2)) and Work=Force*displacement*cos(the angle between the force and displacement vectors). We won't be needing the cosine part of the work equation because the work and force vectors are parallel so the angle is 0(cos(0)=1).
We are told Julie is 50 kg and she climbs 5 meters I.e. her displacement is 5 meters. We first have to calculate the force acting on Julie so that we can determine what force we will use in the work equation. Weight is a force so we can convert her 50 kg to a weight. We do this by plugging into Weight=Mass*9.81.
Weight=50kg*9.8m/s^2=490.5 Newtons.
Now we know the force that Julie is working against while climbing the stairs. She climbs 5.0m up so her total displacement is 5 meters.
Work=(490.5 N)(5 meters)= 2452.5 Joules
Hope this helps!
For extra practice, figure out how much work Julie was to do if she had been carrying her pet dog in her arms who weighed 32 Kg while climbing 5.0 meters up the stairs.
5. On Earth, where is hydrogen not found?
• A. Mine
• B. Natural gas well
• C. Water
O D. Atmosphere
Answer:
Atmosphere
Explanation:
Hydrogen,
H
2
, is one of the lightest gases that can be found on Earth. The other gas is helium, and these two gases are both lighter than air, because they have a high degree of buoyancy.
This means that the air below it is pushing up with a greater force than the air above it is forcing it down.
Can someone helping me!
For this activity create a kinship chart of a celebrity family or fictional family on television or in other media. Choose a person as “ego” and use the anthropological symbols to identify as many of their relatives as you can. Be sure to choose a family with at least three known generations.
Kinship charts, often known as kinship diagrams, show relationships. Similar to a family tree chart or a pedigree chart, you can use a kinship diagram to display your genealogy.
What do you meant by a kinship chart?
An illustration of relationships in a family, community, or culture is called a kinship diagram. Kinship charts resemble family trees in many ways. Therefore, kinship diagrams are used more broadly to comprehend how most families in a culture function rather than identifying individual names or modeling the diagram after one family.
Kinship diagrams enable cultural anthropologists to swiftly sketch out relationships between people throughout the interview process. Also, it offers a way to represent kinship patterns visually in cultures without the use of names, which can be confusing, and it protects people's privacy.
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A gardener pulles a mower with a force 500J, is done in moving the mower along the grassland through a distance of 20m. & Find the angle of application of the foce
The angle of application of the force is theta = arccos(500 J / (F * 20 m))
Force calculation.
We can use the work-energy principle to solve this problem. The work done by the gardener's force is equal to the change in kinetic energy of the mower. Since the mower starts from rest, the initial kinetic energy is zero. Therefore, the work done by the gardener's force is equal to the final kinetic energy of the mower:
Work = Change in kinetic energy
500 J = (1/2)mv^2
where m is the mass of the mower and v is its final velocity.
Since we don't know the mass of the mower or its final velocity, we cannot directly solve for the angle of application of the force. However, we can use the fact that the work done by a force is equal to the product of the magnitude of the force, the displacement, and the cosine of the angle between the force and the displacement:
Work = Fd cos(theta)
where F is the magnitude of the force, d is the displacement, and theta is the angle between the force and the displacement.
Substituting the given values, we have:
500 J = F(20 m) cos(theta)
Solving for the cosine of the angle:
cos(theta) = 500 J / (F * 20 m)
Since we don't know the magnitude of the force, we cannot directly solve for the angle. However, we can rearrange the equation to isolate the angle:
theta = arccos(500 J / (F * 20 m))
Therefore, we need to know the magnitude of the force to find the angle of application.
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M
Dopamine is key for
Functioning of autonomic system.
Release of glucose
✔Pleasure
Reinforcement
Blood pressure
Dopamine is key for : pleasure. Dopamine lets you feel pleasure, satisfaction and also motivation. When one feels good that they have achieved something, then it is because one has surge of dopamine in the brain.
What is the role of dopamine?Dopamine is key for pleasure, reinforcement, and motivation and is commonly known as the "reward molecule". It is responsible for the feelings of pleasure and satisfaction that we experience after completing rewarding activity, like eating food or engaging in social interaction.
Dopamine is also involved in reinforcement, which is the process by which brains learn to associate specific actions or behaviors with rewards.
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(ii) Describe one use of optical fibres in medicine. You may draw a diagram
Answer:
One use of optical fibers in medicine is for endoscopy. Endoscopy is a medical procedure in which an instrument called an endoscope is used to visualize and examine the internal organs or structures of the body. Optical fibers are used in the endoscope to transmit light from a source to the end of the instrument, allowing doctors to see inside the body without making large incisions. The endoscope typically has a camera attached to its end, which captures images of the body's interior and sends them back through the optical fibers to a screen where they can be viewed by the doctor.
Here is a simple diagram of how optical fibers are used in endoscopy:
+-----------------+
| Light |
| Source |
+--------+--------+
|
|
|
+------+-------+
| Endoscope |
| |
+--------------+
|
|
|
+------+-------+
| Camera |
+--------------+
|
|
|
+------+-------+
| Display |
+--------------+
Explanation:
In the diagram, the light source generates light, which is transmitted through the optical fibers in the endoscope. The light is then emitted at the end of the endoscope, illuminating the internal organ or structure being examined. The camera attached to the endoscope captures images of the illuminated area, and sends the images back through the optical fibers to a display screen where they can be viewed by the doctor.
Remember that a measured value agrees with an established value if the established value is within a range of ±2Δx of the measured mean, where Δx is the standard uncertainty.
The table provides a range of modulus values for each material. Therefore, we cannot exclude a material as a possibility if the range in the table and the 95% confidence interval overlap.
Based on this, which of the materials shown above might the cylinder be? Select all that apply. (1 GPa = 1,000,000,000 Pa, and 1 Pa = 1 N/m2)
Butyl rubber is the measured value agrees with an established value if the established value is within a range of ±2Δx of the measured mean.
What is temperature ?
The movement of these particles likewise increases with rising temperature. A thermometer or a calorimeter are used to measure temperature.
What is reaction ?
The transformation of one or more reactants into one or more new products is referred to as a chemical reaction. Substances are made of chemical constituents or compounds. The transformation of one or more reactants into one or more new products is referred to as a chemical reaction. Substances are made of chemical constituents or compounds.
Therefore, Butyl rubber is the measured value agrees with an established value if the established value is within a range of ±2Δx of the measured mean.
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help pls need answers now
At wavelengths [tex]$644.44 \mathrm{~nm}$[/tex] and[tex]$483.33 \mathrm{~nm}$[/tex], the stars [tex]$\mathrm{A}$[/tex] and B have maximum intensities. temperature of most intense star is 6,502.242K
What is a wavelengths frequency?Temperature of star [tex]$\mathrm{A}$[/tex] is [tex]$\mathrm{TA}[/tex]=4,500 [tex]\mathrm{~K}$.[/tex]
Temperature of star $B$ is TB $=6,000 [tex]\mathrm{~K}$.[/tex]
Wavelength of most intense star is [tex]$\lambda_0=446[/tex]
We have to find wavelengths corresponding to maximum intensity of stars at temperatures [tex]$T \wedge$[/tex]and TB and wavelength of most intense star.
From Wein's law, we have
[tex]$\lambda_{\mathrm{nm}}=\frac{2.90 \times 106}{\mathrm{Tk}_{\mathrm{k}}}$[/tex]
Where [tex]$\lambda_{\mathrm{nm}}$[/tex] is in nanometers and [tex]$\mathrm{T} k$[/tex] is in Kelvin.
For Star A, equation (1) becomes
[tex]$\lambda_{\mathrm{A}}=\frac{2.90 \times 106}{\mathrm{TA}}$[/tex]
Using values in (2), we get
[tex]\lambda_{\mathrm{A}}[/tex] & =[tex]\frac{2.90 \times 106}{4,500 \mathrm{~K}} \\[/tex]& =644.44 [tex]\mathrm{~nm}[/tex]
For Star B equation (1) becomes
[tex]$$\lambda_{\mathrm{B}}=\frac{2.90 \times 106}{\mathrm{Tr}}$$[/tex]
Let the temperature of the most intense star is[tex]$\mathrm{T} 0$.[/tex] Now, equation (1) for most intense star becomes [tex]$\lambda_0=\frac{2.90 \times 106}{T_0}$[/tex]
From above equation, we have
[tex]$\mathrm{T}_0=\frac{2.90 \times 106}{\lambda_0}$[/tex]
Using values in (3), we get
[tex]$$\begin{aligned}\lambda_{\mathrm{B}} & =\frac{2.90 \times 106}{6,000 \mathrm{~K}} \\& =483.33 \mathrm{~nm}\end{aligned}$$[/tex]
Using vales in (4), we get
[tex]\begin{aligned}\mathrm{T}_0 & =\frac{2.90 \times 10_6}{446 \mathrm{~nm}} \\= & 6,502.242 \mathrm{~K}\end{aligned}[/tex]
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What’s the right answer for 2
The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound.
Dan was in a roller coaster cart at the top of a hill, which was the tallest point on the ride. As the cart rushed down the hill, Dan screamed and put his hands up. The cart gained speed until it reached the bottom of the hill, where it was moving the fastest. Dan saw that the cart was headed toward a loop. He held on tight while the cart zoomed up and around the loop.
When was the most gravitational potential energy stored between the cart and Earth? Assume that the cart's mass did not change.
smallest possible potential energy The potential energy of the cart began to rise once more as it advanced higher up the loop as it entered the loop, but it was never able to match its level at the top of the hill.
What does children's potential energy entail?Potential energy is the energy that is held in reserve by an object due to its position or condition. Potential energy exists in objects like a spring stretched out, a bicycle on a hilltop, and a book held above your head.
What is potential and kinetic energy?On the other hand, kinetic energy is the energy of an object or a system's particles in motion .The most gravitational potential energy between the cart and the Earth was stored at the top of the hill, which was the tallest point on the ride where the cart was stationary. When the cart was at the top of the hill, it had the highest potential energy due to its position above the ground. As the cart began to move downhill, some of this potential energy was converted into kinetic energy, which increased the cart's speed.
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Question in the photo
Answer:
Find his gravitational then divide it by your potential
The figure shows an arrangement of a very large, charged disk of radius R = 0.2 m and a dipole such that the net electric field at the point marked 'x', at a distance d=3.2 cm from the center of the dipole, is zero. The magnitude of the dipole moment of the dipole is 1.5e-12 C.m. (Figure provided in the photo)
A. Is the disk negatively charged or positively charged?
B. Calculate the charge density of the disk.
C. Calculate the charrge on the disk.
A. We must examine the direction of the electric field the disk produces in order to identify whether it is negatively or positively charged.
If a charged disk is positively charged, the electric field it produces is directed away from the disk, and if it is negatively charged, the electric field is directed toward the disk.
The electric field owing to the disk must be directed away from the disk since the electric field due to the dipole at point "x" is directed toward the positive charge, proving that the disk is positively charged.
B. The electric field at point 'x' due to the disk can be calculated using Gauss's law, which gives us:
E = σ/(2ε0),
σ/(2ε0) = 0
σ = 0
This indicates that the disk has zero charge density.
C. Since the disk has zero charge density, the charge on the disk is also zero. Therefore, there is no charge on the disk.
Describe the dipole moment using an example.The symmetry of the molecules is established using the dipole moment. The molecules would not be symmetrical and have some dipole moment if they contained two or more polar links.
For illustration, H2O = 1.84 D and CH 3Cl, or methyl chloride, = 1
Why does a dipole moment exist?When there is a separation of charge, dipole moments happen.
Dipole moments, which result from variations in electronegativity, can happen between atoms in a covalent link or between two ions in an ionic bond.
The dipole moment increases with the difference in electronegativity.
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A rifle shoots a 4.20 g bullet out of its barrel. The bullet has a muzzle velocity of just as it leaves the barrel. Assuming a constant horizontal acceleration over a distance of 45.0 cm starting from rest, with no friction between the bullet and the barrel, (a) what force does the rifle exert on the bullet while it is in the barrel? (b) Draw a free-body diagram of the bullet (i) while it is in the barrel and (ii) just after it has left the barrel. (c) How many g’s of acceleration does the rifle give this bullet? (d) For how long a time is the bullet in the barrel?
(a)The rifle exerts a force of 628 N on the bullet while it is in the barrel.
(b) (i) There is no friction between the bullet and the barrel, there is no force of friction to consider.
(ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.
(c) The rifle gives the bullet an acceleration of about 24885 g's.
(d) the bullet is in the barrel for 0.030 s.
What is Force?
Force is a physical quantity that describes the interaction between two objects, causing a change in motion. Specifically, it is an influence that can cause an object to accelerate, change direction, or deform. Force is defined as the product of mass and acceleration, according to Newton's second law of motion. Mathematically, force can be represented by the equation:
F = m*a
(a) To determine the force that the rifle exerts on the bullet while it is in the barrel, we need to use the equation for the work done by a constant force:
W = Fd
where W is the work done, F is the force, and d is the distance over which the force is applied. We can rearrange this equation to solve for the force:
F = W/d
We know that the work done on the bullet is equal to the change in kinetic energy:
W = ΔK = (1/2)mv^2
where m is the mass of the bullet and v is its velocity. Plugging in the given values, we get:
W = (1/2)(0.00420 kg)(370 m/s)^2 = 283 J
The distance over which the force is applied is given as 45.0 cm = 0.45 m. So the force exerted by the rifle on the bullet is:
F = W/d = 283 J / 0.45 m = 628 N
Therefore, the rifle exerts a force of 628 N on the bullet while it is in the barrel.
(b) (i) The free-body diagram of the bullet while it is in the barrel would show two forces acting on it: the force of the rifle pushing it forward, and the force of gravity pulling it downward. Since there is no friction between the bullet and the barrel, there is no force of friction to consider.
(ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.
(c) We can calculate the acceleration of the bullet using the formula:
a = Δv/t
where Δv is the change in velocity and t is the time for which the acceleration occurs. We know that the initial velocity of the bullet is 370 m/s and that it starts from rest, so the change in velocity is:
Δv = 370 m/s
The distance over which the acceleration occurs is given as 45.0 cm = 0.45 m. Using the formula for distance traveled with constant acceleration, we can find the time for which the acceleration occurs:
d = (1/2)at^2
0.45 m = (1/2)a(t^2)
Solving for t, we get:
t = sqrt(0.9/a)
Plugging this into the equation for acceleration, we get:
a = Δv/t = 370 m/s / sqrt(0.9/a)
Solving for a, we get:
a = 2.44 x 10^5 m/s^2
To express this acceleration in units of g's, we can divide by the acceleration due to gravity:
a/g = 2.44 x 10^5 m/s^2 / 9.81 m/s^2 = 24885
Therefore, the rifle gives the bullet an acceleration of about 24885 g's.
(d) Using the same formula as before for distance traveled with constant acceleration, we can solve for the time the bullet is in the barrel:
d = (1/2)at^2
0.45 m = (1/2)(2.44 x 10^5 m/s^2)t^2
Solving for t, we get:
t = [tex]\sqrt{(0.00092)}[/tex]s = 0.030 s
Therefore, the bullet is in the barrel for 0.030 s.
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The bullet is in the barrel for 7.05 x 10^-5 seconds. Acceleration can also be caused by changes in direction, such as when an object moves in a circular path.
What is Acceleration?
Acceleration is a fundamental concept in physics and plays an important role in understanding the motion of objects. It is used to describe the behavior of objects in a wide range of applications, from simple everyday situations such as cars accelerating and braking, to more complex phenomena such as the acceleration of particles in particle accelerators or the acceleration of celestial bodies in space.
(a) To find the force exerted by the rifle on the bullet, we can use the kinematic equation:
v^2 = u^2 + 2as
where v is the final velocity (muzzle velocity), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (45.0 cm = 0.45 m).
Rearranging this equation to solve for acceleration:
a = (v^2 - u^2) / 2s
Plugging in the given values:
a = (1200 m/s)^2 / (2 x 0.45 m) = 3.20 x 10^6 m/s^2
The force exerted by the rifle on the bullet can be found using Newton's second law:
F = ma
where F is the force, m is the mass of the bullet (4.20 g = 0.00420 kg), and a is the acceleration we just calculated:
F = 0.00420 kg x 3.20 x 10^6 m/s^2 = 13,440 N
Therefore, the rifle exerts a force of 13,440 N on the bullet while it is in the barrel.
(b)
(i) Free-body diagram of the bullet while it is in the barrel:
The only force acting on the bullet while it is in the barrel is the force exerted by the rifle, which is directed to the right.
|
|
-->| F
|
|
Once the bullet has left the barrel, it is subject to air resistance, which we will assume acts in the opposite direction to the velocity of the bullet. The force of gravity on the bullet is negligible for this problem.
|
|
<--| F_air
|
|
(c) The acceleration given to the bullet can be expressed in terms of g's by dividing by the acceleration due to gravity, g:
a_g = a / g = (3.20 x 10^6 m/s^2) / 9.81 m/s^2 = 326,000 g's
Therefore, the rifle gives the bullet an acceleration of 326,000 g's.
(d) The time the bullet is in the barrel can be found using the kinematic equation:
s = ut + (1/2)at^2
where s is the distance traveled (0.45 m), u is the initial velocity (0 m/s), a is the acceleration we calculated earlier (3.20 x 10^6 m/s^2), and t is the time the bullet is in the barrel (which we want to find).
Rearranging and solving for t:
t = sqrt(2s/a) = sqrt(2 x 0.45 m / 3.20 x 10^6 m/s^2) = 7.05 x 10^-5 s
Therefore, the bullet is in the barrel for 7.05 x 10^-5 seconds.
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a 0.1 kg tennis ball moving at 5m/s [W] is hit by a racquet. If the final velocity of the ball is 5 m/s [E], what is the change of momentum of the ball?
The change in momentum of the ball is 1.0 kg m/s [E].
Momentum calculations
The change in momentum of the ball can be calculated using the formula:
Δp = p₂ - p₁
where Δp is the change in momentum, p₂ is the final momentum, and p₁ is the initial momentum.
The momentum of an object is defined as the product of its mass and velocity, so we can calculate the initial and final momenta of the ball as follows:
p₁ = m₁v₁ = (0.1 kg)(5 m/s [W]) = -0.5 kg m/s
p₂ = m₁v₂ = (0.1 kg)(5 m/s [E]) = 0.5 kg m/s
Substituting these values into the formula for Δp, we get:
Δp = p₂ - p₁ = (0.5 kg m/s) - (-0.5 kg m/s) = 1.0 kg m/s [E]
Therefore, the change in momentum of the ball is 1.0 kg m/s [E] using Δp = p₂ - p₁.
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URGENT HELP NEEDED!!!
A gardener uses a shovel as a lever to lift a 200 N rock a distance of 0.20 meters. He does this by applying 50 N of force to the end of the shovel. a) Calculate the mechanical advantage of the lever. b) How far down does the gardener push the shovel?
a) 4 b) 0.8 m
a) 4 b) 0.4 m
a) 40 b) 1.2 m
a) 2 b) 0.8 m
The mechanical advantage of the lever will be 4.
The distance the gardener pushed the shovel will be 0.8 m.
Work done problema) The mechanical advantage of the lever can be calculated using the formula:
MA = output force/input force
In this case, the output force is the weight of the rock (200 N) and the input force is the force applied to the shovel (50 N). Therefore:
MA = 200 N / 50 N = 4
So the mechanical advantage of the lever is 4.
b) The distance that the gardener pushes the shovel can be calculated using the formula:
output distance / input distance = input force / output force
In this case, the output distance is the distance that the rock is lifted (0.20 m) and the input distance is the distance that the gardener pushes the shovel (unknown). We know the input force (50 N) and the output force (200 N), so we can set up the equation:
0.20 m / x = 50 N / 200 N
Simplifying and solving for x:
0.20 m * 200 N / 50 N = x
0.8 m = x
Therefore, the gardener pushes the shovel down 0.8 m.
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Explain how it is possible to hear sound waves, when there is no direct path to the source of the sound.
Sound waves can travel through a medium (such as air, water, or solid objects) and can reflect or diffract around obstacles, allowing them to be heard even when there is no direct path to the source of the sound.
When sound waves encounter an obstacle, they can either reflect or diffract. Reflection occurs when sound waves bounce off a surface and return in the direction they came from. Diffracton occurs when sound waves bend around an obstacle and continue in a different direction. This allows sound waves to travel around corners and through small openings.
For example, if someone is talking behind a wall, the sound waves they produce can diffract around the wall and reach your ears, allowing you to hear them. Similarly, when you hear an echo, it is because sound waves have reflected off a surface and reached your ears.
In some cases, sound waves can even travel through solid objects. This is known as vibration or bone conduction. For example, when you hear your own voice or a piece of music through a set of headphones, the sound waves are transmitted through the headphones and vibrate the bones in your ear, which sends signals to your brain that you perceive as sound.
In summary, sound waves can travel through a medium and reflect or diffract around obstacles, allowing them to be heard even when there is no direct path to the source of the sound.
Dantes peak 1997: the scientists know an eruption is immanent because the _____ are swarming and the ______ readings increase.
The scientists in the 1997 film "Dante's Peak" know an eruption is coming because of "rats" are congregating as well as the "sulfur dioxide" measurements are rising.
Is the mountain Dante's Peak real?Peak Dante | 1997 Wallace, located in Idaho's Western Rockies in the Bitteroot Alps, serves as the model for the fictional hamlet of "Dante's Peak". Digitally added elements include "Dante's Peak" and the surrounding alpine environment. The setting for Michael Cimino's novel Heaven's Gate was Wallace.
A failure, Dante's Peak?Dante's Peak may not have been warmly accepted at the time as it was treated seriously. It was a dreadful bomb that barely made $175 million just at movie office, like its rival Volcano.
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Select all that are true regarding natural resources (Hint: Pick 3)
There is a big difference between renewable and nonrenewable resources.
Tectonic plates are one reason why certain materials are found only at certain places.
Not every resource is found everywhere on earth
A person can find all resources everywhere
The distinction among renewable and nonrenewable is substantial. One explanation for why some materials are unique to specific locations is the movement of tectonic plates. On Earth, not every resource can be found.
Simply put, what do tectonic plates mean?Huge fragments of the Planet's crust and upper mantle make up tectonic plates. They are composed of both continental and oceanic crust. Along pre ridges and the significant faults that define the plate boundaries, earthquakes happen.
How do tectonic plates function? What are they?According to the idea of plate tectonics, Earth's crust is made up of enormous solid rock slabs called "plates" that move across the beneath, the rock inner layer above the planet's core. The crust is a part of the solid outer layer of the earth.
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URGENT HELP NEEDED!!!
Two spheres of molten rock, both moving in the positive y-direction, collide in space. One sphere has a mass of 660 kg and is moving at a velocity of 17 m/s. The other sphere has a mass of 970 kg, and is moving at a velocity of 24 m/s. When the two spheres collide, and become one unit, what will be their combined velocity?
21.2 m/s
24.0 m/s
41.0 m/s
20.5 m/s
Answer:
20.5 m/s
Explanation:
35. Motors When the plane of an armature in a motor is perpendicular to the magnetic field, the forces do not exert a torque on the coil. Does this mean that the coil does not rotate? Explain.
Answer:
The coil rotates due to its inertia.
Maximum torque occurs when the plane of the coil is parallel to the magnetic field - consider the directions involved in F = I L B - the resulting force is perpendicular to I and B
External forces can cause elastic materials to vibrate around their ?
Yes, External forces can cause elastic materials to vibrate around them
What drives the external forces?
External factors are those brought on by an outside the system agent. Regardless of the place of application, an external non-zero net force causes the system's center of mass to accelerate. Internal forces are the forces that the system's objects trade.
A system's momentum is altered by an external source that exerts force on it. This may appear as a shift in the system's position, velocity, or acceleration.
An elastic material deforms in response to an external force, and internal resistance develops as a result of molecular cohesion. Within elastic bounds, the internal resistance's effort is stored as strain energy. Resilience is the term for this stress force.
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A piece of clay flies off a pottery wheel and sticks to a potter walking by.
The initial momentum of the clay was 3.0 kg.
m
and the initial
m
momentum of the potter was -85 kg
kg.
FUSORE
ku
m
PREDME
S
-
What is the final momentum of the artist-clay system immediately after
the collision?
Your answer should have two significant figures.
S
The final momentum of the artist-clay system immediately after collision is -82 kgm/s.
How to calculate final momentum?Assuming that the initial momentum of the clay was 3.0 kgm/s and the initial momentum of the potter was -85 kgm/s, we can use the law of conservation of momentum to find the final momentum of the artist-clay system immediately after the collision:
Initial momentum = Final momentum
(3.0 kgm/s) + (-85 kgm/s) = Final momentum
-82 kg×m/s = Final momentum
Therefore, the final momentum of the artist-clay system immediately after the collision is -82 kgm/s.
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Rank the four cases below according to the magnitude of the net electric force on the + q charge. Explain how you determined your ranking.
The order of net coulombic measurement of the amount is (4) > (3) > (1) > (2) .
What kinds of electrostatic charge exist?The Many Kinds of Electric Forces Electromagnetic forces can be divided into two categories: attractive electromagnetic forces and repellent electrical forces. Related crimes repel each other whereas opposite charges attract one another.
(1) Net charge density force on charge q: magnitude = kQq / R2 + 2 kQq cos(theta) / R2
= k Q q ( 1 + 2 cos(theta) ) / R2
(2) Net charge density force on charge q: magnitude = kQq / R2 + 2 kQq cos(theta) / (R/cos(theta))^2
= k Q q ( 1 + 2 cos3(theta) ) / R2
(3) Net charge density force on charge q: magnitude = 3 kQq / R2
(4)Net charge density force on charge q: magnitude= kQq / (R/2)^2 = 4 kQq / R2
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Water at 100 is taken off the stove and allowed to cool for 10 minutes. In this 10 minutes, the temperature decreased to 65. Given that the room temperature is 21, find the temperature of the water in degrees Celsius after an additional 5 minutes waiting time and on condition that the Newton’s Law of cooling is not violated.
Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.
The rate of cooling of the water can be described as:dQ/dt = -k(T - Troom)
where Q is the amount of heat in the water, t is time, k is a constant, T is the temperature of the water, and Troom is the room temperature.
Using the given information, we can set up the following system of equations:
100 = k(100 - 21) (at t = 0) 65 = k(100 - 21) e⁽⁻¹⁰⁾k (at t = 10)
Solving for k in the first equation gives k = 1/79. Plugging this value into the second equation and solving for T gives T = 36.1 degrees Celsius.
Now, to find the temperature after an additional 5 minutes, we can use the same equation with a new time value:
T = (65 - Troom) e^(-k(10+5)) + Troom
Plugging in the values we know gives T = 30.4 degrees Celsius.
Therefore, the temperature of the water after an additional 5 minutes of cooling is approximately 30.4 degrees Celsius
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What is the total work wtot done on the block by all forces as the block moves a distance l up the incline? (include only the work done after the block has started moving, not the work needed to start the block moving from rest. ).
To calculate the total work done on the block by all forces as it moves a distance "l" up the incline, we need to consider the work done by each force separately.
What is the total work done on the block by all forces as the block moves a distance l up the incline?Assuming that the block is moving up the incline with a constant velocity, the net force on the block is zero. Therefore, the work done by the net force on the block is also zero.
However, there are two forces acting on the block: the force of gravity (Fg) and the force of friction (Ff). Since the block is moving up the incline, the direction of the frictional force is opposite to the direction of the displacement of the block, so the work done by the force of friction is negative.
The work done by the force of gravity is given by:
Wg = Fg * d
where Fg is the force of gravity acting on the block and d is the distance moved by the block in the direction of the force of gravity. Since the block is moving up the incline, the distance moved by the block in the direction of the force of gravity is l sinθ, where θ is the angle of inclination of the incline.
The work done by the force of friction is given by:
Wf = Ff * d
where Ff is the force of friction acting on the block and d is the distance moved by the block in the direction of the force of friction. Since the block is moving up the incline, the distance moved by the block in the direction of the force of friction is also l sinθ.
Since the force of friction is opposing the motion of the block, the work done by it is negative:
Wf = -μk * N * l sinθ
where μk is the coefficient of kinetic friction, N is the normal force exerted on the block by the incline and l sinθ is the distance moved by the block in the direction of the force of friction.
Therefore, the total work done on the block by all forces as it moves a distance "l" up the incline is:
Wtot = Wg + Wf
= Fg * l sinθ - μk * N * l sinθ
= (m * g * sinθ) * l sinθ - μk * (m * g * cosθ) * l sinθ
= (m * g * sinθ - μk * m * g * cosθ) * l sinθ
where m is the mass of the block, g is the acceleration due to gravity.
So, the total work done on the block by all forces as it moves a distance "l" up the incline is (m * g * sinθ - μk * m * g * cosθ) * l sinθ.
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The index of refraction of quartz is 1.46. What is the velocity of light in quartz?
Answer:
Approximately [tex]2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
The refractive index [tex]n[/tex] of a material is the ratio between the speed of light in vacuum [tex]c[/tex] and the speed of light [tex]v[/tex] in that material. In other words:
[tex]\begin{aligned}n &= \frac{c}{v}\end{aligned}[/tex].
The speed of light in vacuum is [tex]c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}[/tex].
It is given that the refractive index is [tex]n = 1.46[/tex]. Rearrange this equation to find [tex]v[/tex], the speed of light in this material:
[tex]\begin{aligned}v &= \frac{c}{n} \\ &\approx \frac{3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}}{1.46} \approx 2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
very important!!!
A drilling rig performs 5.15∗105 J of work at an average power output of 3940 W. How long does it take the drill to perform this work?
540 s
916 s
244 s
131 s
Answer:131s
Explanation:
time = 5.15*10^5 J / 3940
Before the coyote begins to fall, what can you tell about the potential and kinetic energy of the roadrunner vs the coyote?
Select all correct responses.
A. Ignoring air resistance and assuming they have the same mass, the kinetic energy of both is equal right before impact with the ground.
B. The potential energy of the one with the most mass is greater than the other.
C. Weight is the same for both, regardless of mass.
D. The potential energy of both are equal.
Before they begin to fall, the potential energy of the roadrunner and the coyote is the same regardless of their mass. Both the roadrunner and the coyote have zero kinetic energy just before they begin to fall.
What are some illustrations of kinetic and potential energy?The energy an individual or an object has as a result of motion—in this case, the motion of the falling apple—is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill.
What is the connection between potential difference and kinetic energy?By virtue of energy conservation, kinetic energy (KE) must be equal to the change in potential energy (qV), or vice versa. The voltage between the plates and the electron's energy are numerically equivalent in electron-volts. A 5000-V potential difference, for instance, results in 5000-eV electrons.
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