PLEASE ANSWER!! I don’t understand
Answer:
[tex]m\angle 2=122^{\circ},\\m\angle 1 = 58^{\circ}[/tex]
Step-by-step explanation:
By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.
In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since [tex]\angle 2[/tex] forms an arc labelled 244 degrees, the measure of angle 2 must be [tex]\frac{244}{2}=\boxed{122^{\circ}}[/tex].
Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:
[tex]\angle 1+\angle 2=180,\\\angle 1 + 122=180,\\\angle 1=180-122=\boxed{58^{\circ}}[/tex]
(100 points)
4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
5. If he difference is 589 and the subtrahend is 339,what is the minuend?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
6. If the quotient is 17 and the dividend 765, what is the divisor?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?
a. What are they asking for?
how big was the original group?
b. identify all the necessary numbers.
28,5
c. write the equation or problem in numeric form.
x=28*5
d. solve the math.
x=140
e.write the answer
. the original group contains 140 people.
5. If he difference is 589 and the subtrahend is 339,what is the minuend?
a. What are they asking for?
what is the minuend?
b. identify all the necessary numbers.
589,339
c. write the equation or problem in numeric form.
x=589-339
d. solve the math.
x=250
e.write the answer.
minuend=250
6. If the quotient is 17 and the dividend 765, what is the divisor?
a. What are they asking for?
what is the divisor?
b. identify all the necessary numbers.
17,765
c. write the equation or problem in numeric form.
x=765/17
d. solve the math.
x=45
e.write the answer.
divisor is 45.
4. Solution
a. How big was the original group?
b. 28 and 5
c. x = 28×5
d. x = 140
e. There are 140 people in original group.
5. Solution
a. What is the minuend?
b. 589 and 339
c. x = 589-339
d. x = 250
e. The minuend is 250.
6. Solution
a. What is the divisor?
b. 17 and 765
c. x = 765/17
d. x = 45
e. Hence, 45 is the divisor.
A Warming Liquid - A liquid is taken out of a refrigerator and placed in a warmer room, where its temperature, in F, increases over time. It can be modeled using the equation Tm 74 390.87m. (a) What temperature did the liquid start at? Show the work that leads to your answer. (b) What is the temperature of the room?
Answer:
The temperature at the start is 35F
The temperature of the room is 74F
Step-by-step explanation:
Given
[tex]T(m) = 74 - 39(0.87)^m[/tex]
Solving (a): The temperature at the start.
To do this, we set: [tex]m = 0[/tex]
So, we have:
[tex]T(0) = 74 - 39(0.87)^0[/tex]
[tex]T(0) = 74 - 39*1[/tex]
[tex]T(0) = 74 - 39[/tex]
[tex]T(0) = 35[/tex]
Hence, the temperature at the start is 35F
Solving (b): The room temperature
We have:
[tex]T(m) = 74 - 39(0.87)^m[/tex]
To get the temperature of the room, we simply remove the exponential function.
So, we have:
[tex]Initial = 74[/tex]
Hence, the temperature of the room is 74F
The initial temperature of the liquid is 35 F and the room temperature is 74 F.
What is Melting Point?The melting point is the temperature at which the solid starts converting into liquid.
Given here,
[tex]T_m = 74- 39(0.87)^m[/tex]
Leat the [tex]m = 0,[/tex]
So,
[tex]T_0 = 74- 39(0.87)^0\\\\T_0 = 35 \rm \ F[/tex]
Thus the initial temperature is 35 F.
Now remove the exponential to get the room temperature,
So,
[tex]T_{RT} = 74[/tex]
Therefore, the initial temperature of the liquid is 35 F and the room temperature is 74 F.
Learn more about the Melting point:
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Jac is reading this paragraph from The Code Book. Mathematicians have been studying factoring for centuries, and modern factoring techniques are not significantly better than ancient techniques. Indeed, it could be that the laws of mathematics forbid the existence of a significant shortcut for factoring. Which question will best help Jac apply the reading to his own life
Answer:
The answer is "What is important for me to understand?".
Step-by-step explanation:
It is because it is based also on the conclusion that the word in the text read the Jac can draw. Essentially, the particular excerpt read by Jac in his coding book explains that, whether old or new, all older techniques used in the past, compared with the new factorization methods, in truth all shortcuts in mathematics are not feasible and hence all steps have to occur. This implies Jac has to discover what really is important, what he must comprehend, and whether whatever tactics he is using are old and new. The same would be valid of life itself; irrespective of how he chooses to live his life, there are times where shortcuts cannot be used.
6. The coordinates of the vertices of triangle CDE are C(3, - 2), D(5, 2) , and E(7, 0) The figure is rotated 90about the origin . What are the vertices of the resulting image, Figure C'D'E?
Answer:
Step-by-step explanation:
if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)
if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)
Which property does each equation demonstrate?
x2 + 2x = 2x + x2
Amelia, Luis, Shauna, and Clarence used different approaches to solve the inequality
7.2b + 6.5 > 4.8b – 8.1.
Amelia started by subtracting 7.2b from both sides to get 6.5 > –2.4b – 8.1.
Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.
Shauna started by subtracting 6.5 from both sides to get 7.2b > 4.8b – 14.6.
Clarence started by adding 8.1 to both sides to get 7.2b + 14.6 > 4.8b.
Which student’s first step was incorrect, and why?
Amelia’s, because the variable term must be isolated on the left side
Luis’s, because he flipped the inequality sign when he subtracted
Shauna’s, because she did not apply the subtraction property of equality properly
Clarence’s, because the terms he added together were not like terms
Answer:
Luis’s, because he flipped the inequality sign when he subtracted
Step-by-step explanation:
7.2b + 6.5 > 4.8b – 8.1.
Amelia started by subtracting 7.2b from both sides to get
6.5 > –2.4b – 8.1
Correct
Luis started by subtracting 4.8b from both sides to get
2.4b + 6.5 < – 8.1
Incorrect
Shauna started by subtracting 6.5 from both sides to get
7.2b > 4.8b – 14.6
Correct
Clarence started by adding 8.1 to both sides to get
7.2b + 14.6 > 4.8b
Correct
Luis’s is incorrect because he flipped the inequality sign when he subtracted
[tex]\sqrt{x} 8xyx^{2}[/tex]
Answer:
nom nom
Step-by-step explanation:
nom nommy nom nom
Solve for 0 or x, round to the nearest tenth.
Answer:
theta = 44.4 degrees
Step-by-step explanation:
Since this is a right triangle, we can use trig formulas
cos theta = opposite/ hypotenuse
cos theta = 15/21
Take the inverse of each side
cos^ -1 (cos theta) = cos ^-1 (15/21)
theta =44.4153086
theta = 44.4 degrees
evaluate log25+log8 _log2
Step-by-step explanation:
log 25 + log 8 = log (25 × 8) = log 200
log 200 - log 2 = log (200 ÷ 2) = log 100
logarithm base 10 of 100 is 2.
which graph is that one of the inequality shown below?
Answer:
D
Step-by-step explanation:
Find the cosine of angle A to the nearest 100th.
Answer:
[tex]{ \tt{ \cos(A) = \frac{ \sqrt{700} }{40} }} \\ { \tt{ \cos(A) = 0.66 }}[/tex]
T is directly proportional to
[tex] \sqrt{x} [/tex]
T=400 when x = 625
(a) Find a formula for T in terms of x.
pls help i need it urgently Pls pls pls
Answer:
(a) T = 16√x
Step-by-step explanation:
T is directly proportional to √x, so we can say,
T=k√x (where k is a constant)
now, according to the question,
400=k×√625
400=k×25
k=16
so, putting the value of k in the equation, T=16√x
Answered by GAUTHMATH
Step-by-step explanation:
Given that ,
T is directly proportional to √x .Mathematically we can write it as ,
[tex]\implies T \propto \sqrt{x}[/tex]
Let k be the constant , therefore ,
[tex]\implies T = kx [/tex]
Now when T = 400 and x = 625 , lets find the value of k , as ,
[tex]\implies 400 = k\times 625 \\\\\implies k =\dfrac{400}{625}\\\\\implies k= 0.64 [/tex]
Therefore the required formula will be ,
[tex]\implies \underline{\underline{ T = 0.64x}} [/tex]
Express the polynomial −g + 3g + 2g2 in standard form and then classify it.
cubic binomial
quadratic binomial
cubic trinomial
quadratic trinomial
Answer:
quadratic binomial
[tex]{ \boxed{ \bf{a {x}^{2} + bx + c }}} \\ 2 {g}^{2} + 3g - g[/tex]
Write the equation of the line parallel to 4y - x = -20 that passes through the point (8,3).
Answer:
y= ¼x +1
Step-by-step explanation:
Rewriting the equation into the slope-intercept form (y= mx +c, where m is the gradient and c is the y- intercept):
4y -x= -20
4y= x -20 (+x on both sides)
y= ¼x -5 (÷4 throughout)
Thus, slope of given line is ¼.
Parallel lines have the same gradient.
Gradient of line= ¼
y= ¼x +c
To find the value of c, substitute a pair of coordinates into the equation.
When x= 8, y= 3,
3= ¼(8) +c
3= 2 +c
c= 3 -2
c= 1
Hence the equation of the line is y= ¼x +1.
Find the product. If the result is negative, enter "-". If the result is positive, enter "+".
-7(- a2 ) 2 ( -b3 )
Answer:
7 a⁴ b³
Step-by-step explanation:
-7 ( -a²)²( - b ³)
A negative base raised to an even power equals a positive= -7 ( a²)² ( - b³)
Multiplying an even number of negative terms make the product positive= - 7 ( a²)² × b³
simplify the expression by multiplying exponent= (-7)( a²*² )× b³
= 7 a⁴ b³
Answer:
Solution given:
(-a²)=-a*-a=a²
-b³=-b*-b*-b=-b³
now
-7(-a²)²(-b³)=-7*a⁴*-b³=-7*-1 *a⁴b³=7a⁴b³
the product is 7a⁴b³.
so
enter"+".
y=x+2 y=-x +8 What is the solution for this system of equations?
Answer:
x = 3 y = 5
Step-by-step explanation:
y=x+2
+ y=-x +8
2y = 10
y = 5
y = -x + 8
5 = -x + 8
x = 3
Help please guys if you don’t mind
Step-by-step explanation:
Step 2:
[tex] ({15x}^{2} - 9x) + (5x - 3)[/tex]
Stepc3:
[tex]3x(5x - 3)[/tex]
A cylinder has a volume of 245x cubic units and a helght of 5 units. The diameter of the cylinder is
7 units
14 units
49 units
Answer:
Diameter = 14 units
Step-by-step explanation:
Volume ofa cylinder = πr²h
Volume of the cylinder = 245π cubic units
Height = 5 units
Volume of a cylinder = πr²h
245π = π × r² × 5
245π = 5r²π
Divide both sides by π
245π / π = 5r²π / π
245 = 5r²
r² = 245/5
= 49
r² = 49
r = √49
r = 7 units
Diameter = 2 × radius
= 2 × 7 units
= 14 units
Diameter = 14 units
For a project in his Geometry class, Mamadou uses a mirror on the ground to measure the height of his school's football goalpost. He walks a distance of 13.75 meters from his school, then places a mirror on flat on the ground, marked with an X at the center. He then steps 2.6 meters to the other side of the mirror, until he can see the top of the goalpost clearly marked in the X. His partner measures the distance from his eyes to the ground to be 1.75 meters . How tall is the goalpost? Round your answer to the nearest hundredth of a meter .
Answer:
Height of the goalpost is 9.25 m.
Step-by-step explanation:
As per the rule of reflection in physics,
Angle of incidence = Angle of reflection
As we can see in the picture attached, both the angles (θ) are equal.
m∠ACB = m∠ECD = 90° - θ
m∠ABC = m∠ADC = 90°
Therefore, both the triangles ΔABC and ΔEDC will be similar.
And by the property of similar triangles, their corresponding sides will be proportional.
[tex]\frac{AB}{ED}= \frac{CB}{CD}[/tex]
[tex]\frac{1.75}{ED}=\frac{2.6}{13.75}[/tex]
ED = [tex]\frac{1.75\times 13.75}{2.6}[/tex]
ED = 9.25 m
Height of the goalpost is 9.25 m.
If the length of a is 6, the length of b is 4, and the length of c is 7, what is the measure of angle B
Answer:
B = 34.77°
Step-by-step explanation:
For this problem you are given all three side lengths and asked to find an angle. To do this you can use the law of cosines which is written:
[tex]b^{2} =a^{2} +c^{2} -2ac Cos(B)[/tex]
This can be rearranged to find the angle B:
[tex]b^{2} -a^{2} -c^{2} /-2ac = Cos(B)[/tex]
With lowercase letters being sides and uppercase being angles.
We simply plug in the sides and solve:
[tex]4^{2} -6^{2} -7^{2}/-2*6*7= Cos(B)[/tex]
0.8214 = Cos (B)
Then you use inverse cosine to get angle B alone.
B = 34.77°
Miguel is trying to find the height of a radio antenna on the roof of a local building. He stands at a horizontal distance of 22 meters from the building. The angle of elevation from his eyes to the roof (point A) is 26 degrees , and the angle of elevation from his eyes to the top of the antenna ( oint B) is 31 degrees If his eyes are 1.53 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.
Given the 22 m. horizontal distance and the angles of elevation of 26°
and 31° gives the height of the building as approximately 2.49 meters.
How can the height of the building be found?Horizontal distance from the building = 22 m
Angle of elevation to the top of the roof = 26°
Angle of elevation to the top of the antenna = 31°
Height of his eyes from the ground = 1.53 m
Required:
The height of the antenna.
Solution:
In a right triangle, we have relative to an angle of the triangle, we have;
Opposite side = Adjacent side
Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75
Which gives;
Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26
Height of antenna = Height of the building + Height of antenna - Height of the buildingTherefore;
Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49
Height of the antenna ≈ 2.49 mLearn more about trigonometric tangent ratio here:
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Which property of math is the young student learning with the following equation? 3 x (4 + 7) = (3 x 4) + (3 x 7)
The property of math they are learning is the distributive property
Which expression can be used to convert 22 Australian dollars to US dollars?
Assume 1.2 Australian dollars equals 1 US dollar.
O $22 AUD X
1.2 USD
1 AUD
O $22 AUD X
1 USD
1.2 AUD
O $1.20 AUD X
1 USD
1.2 AUD
O $1.20 AUD X
1.2 USD
1 AUD
Answer:
The answer is B
Step-by-step explanation:
B
The 22 Australian dollar in USD is 18.33.
What is currency?Currency is a medium of exchange for goods or services within an economy, usually issued by a government or central bank and generally accepted at its face value.
Given that, we need to determine that there are how many USD in 22 AUD,
So, 1.2 Australian dollars equals 1 US dollar.
Therefore,
22 AUD = 22 x 1 / 1.2 = 18.33
Hence, the 22 Australian dollar in USD is 18.33.
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the volume of a swimming pool is 4x^3 - 20x^2 + 3x - 15 . what is one of the dimensions of the pool
Answer:
[tex]Height = x - 5[/tex] --- one of the dimension
Step-by-step explanation:
Given
[tex]Volume = 4x^3 - 20x^2 + 3x - 15[/tex]
Required
The side dimension
Factorize the given expression
[tex]Volume = 4x^2 (x- 5) + 3(x - 5)[/tex]
Factor out x - 5
[tex]Volume = (4x^2 + 3)(x - 5)[/tex]
Volume is the product of base area and height'
Hence:
[tex]Area = 4x^2 + 3[/tex]
[tex]Height = x - 5[/tex]
maths questions on coordinate geomery
Answer:
:
Example Question #1:
Step-by-step explanation:
Which of the following is the equation of a line that is parallel to the line 4x – y = 22 and passes through the origin?
Possible Answers:
4x – y = 0
(1/4)x + y = 0
4x + 8y = 0
4x = 8y
y – 4x = 22
Correct answer:
4x – y = 0
Explanation:
We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4x – 22
Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.
In 4x – y = 0 we can rearrange to get y = 4x. This fulfills both requirements.
', .
Find the 66th term of the arithmetic sequence 25, 10, -5, ...
Answer:
1000
Step-by-step explanation:
Given data
we have the sequence
25, 10, -5, ...
we want to find the 66th term, let us apply the formula
an = a + (n – 1)d
a= 25
n= 66
d= 15
substitute
a66= 25+(66-1)15
a66= 25+(65)*15
a66= 25+975
a66= 1000
Hence the 66th term is 1000
The force of gravity on an object varies directly with its mass. The constant of variation due to gravity is 32.2 feet per second squared. Which equation represents F, the force on an object due to gravity according to m, the object’s mass?
Answer:
f=x−32
Step-by-step explanation:
Subtract 3232 from both sides.
Answer:
f=32.2m
Step-by-step explanation:
got it right on edge
A boy bought an article for £9. He spent £4
repairing it and sold it for £18. Calculate the gain
percent on his total costs. (to nearest %)
Help
Answer:
Profit % = 39%
Step-by-step explanation:
Cost price of the article = 9
Price for repairing = 4
Therefore, Total cost of the article = 9 + 4 = 13
Selling price of the article = 18
Profit = 18 - 13 = 5
Hence,
[tex]Profit \% = \frac{Profit}{Cost \ price} \times 100\\\\[/tex]
[tex]= \frac{5}{13} \times 100\\\\=38.46 \%\\\\=38.5 \%[/tex]
Profit percent (to the nearest %) = 39%
I have this math problem I can't solve.
"Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.
The rate of the water flowing in the channel was 2 miles per hour. The total time it took them to kayak up and back was 3 hours and 40 minutes. Assuming they were padding their double kayak at a fairly consistent rate, find the rate Evelyn and Meredith were paddling.
Step 2 - Draw a picture to model the problem.
Step 3 - Label variables and create a table.
Step 4 - Write an equation to model the problem.
Step 5 - Solve the equation. Provide supporting work and detail.
Step 6 - Explain the results."
If you can help please do.
Evelyn and Meredith were paddling at a rate of [tex]\frac{3+\sqrt{493}}{11}mph[/tex] which is equivalent to 2.29mph approximately.
Step 2: See attached picture
Step 3: In this case we only have different variables, there is the rate at which Evelyn and Meredith were paddling, the rate at which they moved when rowing upstream, the rate at which they moved when rowing downstream, the time it took them to paddle upstream and the time it took them to paddle downstream.
v = rate at which Evelyn and Meredith were paddling.
[tex]v_{up}[/tex]= velocity at which they were moving when paddling upstream.
[tex]v_{down}[/tex]= velocity at which they were moving when paddling downstreamstream.
[tex]t_{up}[/tex]= time it took them paddling upstream.
[tex]t_{down}[/tex]= time it took them paddling downstream
Se attached picture for the table.
Step 4: Building this equation will require us to combine different equations into a single one. Let's start with the equation for the final rate at which they paddled when rowing upstream.
[tex]v-2=v_{up}[/tex]
When rowing upstream, the current will drag the kayak, so we subtract it from the rate at which they were rowing.
Let's find the final rat at which they moved when rowing downstream.
[tex]v+2=v{down}[/tex]
next, the problem tells us it took them 3 hours and 40 minutes to row up and down the channel so we can convert it into just hours like this:
[tex]40min*\frac{1hr}{60min}=\frac{2}{3}hr[/tex]
[tex]3hr+\frac{2}{3}hr=\frac{11}{3}hr[/tex]
so now we can build our equation for time.
[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]
We also know that the rate is built by dividing the distance over the time it took them to travel the distance, so:
[tex]v_{up}=\frac{1}{t_{up}}[/tex]
[tex]v_{down}=\frac{1}{t_{down}}[/tex]
If we solved each of those equations for their respective times, we would end up with the following:
[tex]t_{up}=\frac{1}{v_{up}}[/tex]
[tex]t_{down}=\frac{1}{v_{down}}[/tex]
so we can now combine all the equations together so we get:
[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]
[tex]\frac{1}{v_{up}}+\frac{1}{v_{down}}=\frac{11}{3}[/tex]
[tex]\frac{1}{v-2}+\frac{1}{v+2}=\frac{11}{3}[/tex]
So this equation models the problem.
Step 5: We can solve this equation by multiplying everything by the LCD
In this case the LCD is:
3(v-2)(v+2)
so, when doing the respective multiplications we end up with:
[tex]\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}[/tex]
We can now simplify to get:
3(v+2)+3(v-2)=11(v+2)(v-2)
We can now do the respective multiplications to get:
[tex]3v+6+3v-6=11(v^{2}-4)[/tex]
and we can further simplify:
[tex]6v=11v^{2}-44[/tex]
Step 5: So we can now solve it by using the quadratic formula, first, we need to rewrite the equation in standard form:
[tex]11v^{2}-6v-44=0[/tex]
So we can now use the quadratic formula:
[tex]v=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]
we substitute:
[tex]v=\frac{-(-6) \pm \sqrt{(-6)^{2}-4(11)(-44)}}{2(11)}[/tex]
and simplify:
[tex]v=\frac{6 \pm \sqrt{36+1936}}{22}[/tex]
[tex]v=\frac{6 \pm \sqrt{1972}}{22}[/tex]
[tex]v=\frac{6 \pm \sqrt{4(493)}}{22}[/tex]
[tex]v=\frac{6 \pm 2\sqrt{493}}{22}[/tex]
[tex]v=\frac{3 \pm \sqrt{493}}{11}[/tex]
this gives us two possible results:
[tex]v=\frac{3 + \sqrt{493}}{11}[/tex] and [tex]v=\frac{3 - \sqrt{493}}{11}[/tex]
Step 6: We only pick the first result since it's the positive result. We don't take the second one because a negative result represents the kayak moving in the opposite direction which is not how the situation was modeled.
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