The wavelength of the wave is 1.16m and the velocity is 23.64m/s.
To find the answer, we have to know more about the Transverse waves.
How to find different parameters of a wave?The displacement of the string as a function of position and time, y(x,t), when the wave traveling along a string lying along the x-axis is given as,[tex]y(x,t)=0.048sin(5.40x-128t)[/tex]
Comparing this with the general form of wave equation, we get,[tex]amplitude, a=0.048m\\wave vector, k=5.40\\angular frequency,w=128Hz[/tex]
We have to find the wavelength of the wave, for this, we have the expression as,[tex]k=\frac{2\pi }{wavelength} \\\\wavelength=\frac{2\pi }{k} =\frac{2*3.14}{5.40} \\\\wavelength=1.16m[/tex]
We have to find the velocity of the wave,[tex]v=frequency*wavelength\\2\pi f=w, thus,\\f=\frac{w}{2\pi } =\frac{128}{2*3.14}=20.38s^{-1}\\\\v=1.16*20.38=23.64m/s[/tex]
Thus, we can conclude that, the wavelength of the wave is 1.16m and the velocity is 23.64m/s
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It is useful to use a _________ to demonstrate how an electric circuit works
It is useful to use a model in order to demonstrate how an electric circuit works.
What is a model?In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.
For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.
The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.
In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.
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why is the bulb of hydrometer is made heavier give two reasons
The reason behind the heavier hydrometer bulb is the sinking of hydrometer is inversely proportional to the density of hydrometer, hence hydrometers is made heavier.
We all know that hydrometers float in liquid hence to maintain the centre of gravity while floating the hydrometer is made heavier using lead shots.
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.02 nC.
(A) What is the magnitude (in N) of the electric force that one particle exerts on the other?
______N
(B) Is the force attractive or repulsive?
The magnitude of the electric force that one particle exerts on the other is 8.59 x [tex]10^{-8}[/tex] N and the force is attractive.
How is Coulomb's Law Stated ?Coulomb law states that the attractive or repulsive force between two point charges is proportional to the product of the charges and inversely proportional to square of the distance between them. That is,
F = KQq / r²
Given that two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.02 nC.
Where
K = constant of proportionality = 9 x [tex]10^{9}[/tex] Nm²/c²Q = 7.03 x [tex]10^{-9}[/tex] Cq = 4.02 x [tex]10^{-9}[/tex] Cr = 1.72 m(A) The magnitude of the electric force that one particle exerts on the other will be
F = (9 x [tex]10^{9}[/tex] x 7.03 x [tex]10^{-9}[/tex] x 4.02 x [tex]10^{-9}[/tex]) / 1.72²
F = 2.54 x [tex]10^{-7}[/tex] / 2.96
F = 8.59 x [tex]10^{-8}[/tex] N
(B) Since our answer is positive, the force is therefore attractive.
Therefore, the magnitude of the electric force that one particle exerts on the other is 8.59 x [tex]10^{-8}[/tex] N and the force is attractive.
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A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N
B. The force is repulsive
A. How to determine the magnitude of the electric forceFrom the question given above, the following data were obtained:
Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ CCharge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 1.72 mForce (F) =?The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²
F = 8.60×10⁻⁸ N
B. How to determine whether the force is attractive or repulsiveFrom the question given, we were told that:
Charge 1 (q₁) = 7.03 nC Charge 2 (q₂) = 4.02 nCSince both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts
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The cricket ball has a mass of 0.16kg and it hits the bat with a speed of 25 m/s. After being in contact with the bat for 0.0013 s, the ball rebounds with a speed of 22 m/s in the direction exactly opposite to its original direction.
A) state the difference between speed and velocity
B) calculate.
I) the change in velocity of the cricket ball
Ii) the average acceleration of the ball whilst it is in contact with tge bat
Iii) the average force exerted on the ball by the bat
change in velocity is 3m/s,the force exterted by bat on ball is 4.8N and the acceleration is 30m/s².
Give some difference between velocity and speed.1) Speed is scalar quantity but velocity is vector quantity.
2) Speed is distance followed by an individual with respect to time and velocity is displacement with respect to time .
1) final velocity- intial velocity
25-22= 3m/s
2) The force is
F= ma
. 0.16×30= 4.8N
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An old grindstone, used for sharpening tools, is a solid cylindrical wheel that can rotate about its central axle with negligible friction. The radius of the wheel is 0.330 m. A constant tangential force of 200 N applied to its edge causes the wheel to have an angular acceleration of 0.844 rad/s2.
What is the moment of inertia of the wheel (in kg · m2)?
________kg · m2
What is the mass (in kg) of the wheel?
_______kg
The wheel starts from rest and the tangential force remains constant over a time period of 4.00 s. What is the angular speed (in rad/s) of the wheel at the end of this time period?
_______rad/s
(a) The moment of inertia of the wheel is 78.2 kgm².
(b) The mass (in kg) of the wheel is 1,436.2 kg.
(c) The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.
Moment of inertia of the wheel
Apply principle of conservation of angular momentum;
Fr = Iα
where;
F is applied forcer is radius of the cylinderα is angular accelerationI is moment of inertiaI = Fr/α
I = (200 x 0.33) / (0.844)
I = 78.2 kgm²
Mass of the wheelI = ¹/₂MR²
where;
M is mass of the solid cylinderR is radius of the solid cylinderI is moment of inertia of the solid cylinder2I = MR²
M = 2I/R²
M = (2 x 78.2) / (0.33²)
M = 1,436.2 kg
Angular speed of the wheel after 4 secondsω = αt
ω = 0.844 x 4
ω = 3.376 rad/s
Thus, the moment of inertia of the wheel is 78.2 kgm².
The mass (in kg) of the wheel is 1,436.2 kg.
The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.
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A steel piano wire, of length 1.150 m and mass 4.80 g is stretched under a tension of 580.0 N. What is the speed of transverse waves on the wire?
The speed of transverse waves on the wire is 1.555.
Given: Length= 1.150 m
Mass= 4.80 g
Speed =mass/length
U=M/L formula
U=1.150 *10^(-3)/4.80
v=√t/u
v=√580*4.80/1.150*10^(-3)=1.555
1.555
The derivative of the displacement with respect to time gives the transverse velocity in the y direction, as velocity is the rate of change of position: Where k = 2/ is referred to as the wave number and = 2f as before, v(x,t) = y(x,t)/t = -A cos (k x - t + ).The linear density and tension v=FT can be used to determine the wave's speed. v = F T μ . According to the equation v=FT, v = F T, the tension would need to be increased by a factor of 20 if the linear density were to be doubled by almost as much.
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In the Roman soldier model for refraction, what happens to the distance between the rows of each soldier once they enter the stream?
A. Not enough info
B. They are closer together
C. They stay the same distance
D. They are further apart
They pick up speed and move away from the usual.
Using meter sticks, a group of pupils makes a straight line (shoulder to shoulder) and connects to their closest neighbor. Two media are separated in the room by a strip of masking tape. Students can be seen moving normally in one of the media (on one side of the tape). The kids in the other medium (or on the opposite side of the tape) move very slowly and in baby stages. The class moves in the union in a straight line in the direction of the diagonal piece of masking tape. As they get close to the masking tape, the pupils stay in line. Each pupil immediately changes the speed of her or his walk as she or he reaches the tape.
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A uniform linear charge of 3.0 nC/m is distributed along the y axis from y = -3 m to y=2m. Which of the following integrals is correct for the magnitude of the electric field at y = 4 m on the y axis?
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex] is the integrals for the magnitude of the electric field.
A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
The formula for the electric field due to a point charge is:
[tex]E = \frac{kq}{r^2}[/tex]
Here q is the charge, r is the distance from the charge, and k = 8.99 × [tex]10^9 Nm^2/ C^2[/tex]
Imagine an infinitely - tiny portion of this charge distribution that has a charge [tex]dq[/tex]. This charge produces an electric field dE with magnitude:
[tex]\int\limits^ {} \, dE = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
[tex]E = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
Here, λ = 3.0 nC/m dq
= λ.dy dE = ∫k.dq
From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.
The integrals for the magnitude of the electric field at y = 4 m on the y axis:
[tex]E = k \lambda \int\limits^2_{-3} {} \, \frac{dy}{( 4 - y)^2}[/tex]
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex]
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Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person wearing a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a) If a human centrifuge has a radius of 4.00 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?
_______rad/s
(b) What linear speed (in m/s) would a person in the centrifuge have at this acceleration?
________m/s
(a) The angular speed of the human centrifuge is 4.7 rad/s.
(b) The linear speed (in m/s) a person in the centrifuge would have at this is 18.8 m/s.
Angular speed of the human centrifuge
a = ω²r
where;
a is centripetal acceleration = 9gr is radius of human centrifugeω = √(a/r)
ω = √(9g/r)
ω = √(9 x 9.8 / 4)
ω = 4.7 rad/s
Linear speed of the centrifugev = ωr
where;
v is linear speedv = (4.7 rad/s) x 4 m
v = 18.8 m/s
Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s) a person in the centrifuge would have at this is 18.8 m/s.
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iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weight of iron ball in air?
Answer:
453 gm
Explanation:
Immersed objects are buoyed up by force equal to mass of displaced liquid
400 + 53 = 453 gm in air
If little herbert does something uncon
sciously he will probably
If little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Doing something unconscious may have some implications which may not be favourable.
What is unconscious?Unconscious simply means a state of someone being absent minded of what is happening to him or her at a particular period of time
So therefore, if little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Complete question:
What happens if little herbert does something unconsciously he will probably
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what is atmosphere ?????
Answer:
the envelope of gases surrounding the earth or another planet.
Answer:
An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases.
(Please help 25 points)
Asteroids X, Y, and Z have equal mass of 6.0 kg each. They orbit around a planet with M=6.20E^24 kg. The orbits are in the plane of the paper and are drawn to scale.
In the statements below, TE is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.
The PE of X at r is .... that at s
The TE of Y is .... the TE of X
The PE of Y at u is .... the PE of Z at c
The speed of Y at i is .... that at u
The KE of Z at u is .... that at m
The PE of Y at s is .... the PE of X at c
The TE of Z is .... the TE of X
The PE of X at c is .... the PE of Z at c
(Options are: greater than, less than, equal to)
The potential energy (P.E) of X at r is less than P.E at s.
The total energy (T.E) of Y is less than total energy (T.E) of X.
The PE of Y at v is greater than the PE of Z at c.
The speed of Y at i is .greater than that at v.
The kinetic energy (KE) of z at u is less than that at n.
The PE of Y at s is less than the PE of X at c.
The PE of X at c is less than the PE of Z at c.
The PE of X at c is less than the PE of Z at c.
PE of X at r and at sThe potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.
TE of Y is .... the TE of XThe total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.
PE of Y at v is .... the PE of Z at cThe PE of Y at v is greater than the PE of Z at c due to greater displacement at v.
Speed of Y at i is .... that at uThe speed of Y at i is .greater than that at v because i is closer to the planet than v.
KE of Z at u is .... that at nThe kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.
PE of Y at s is .... the PE of X at cThe PE of Y at s is less than the PE of X at c, because position c has greater displacement.
The TE of Z is .... the TE of XThe TE of Z is greater than the TE of X due to greater displacement of Z from the planet.
The PE of X at c is .... the PE of Z at cThe PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.
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Using the Left Hand Rule, if motion is down and the current is toward you, which way is the field?
In the left-hand rule, the field is represented by the forefinger and it is perpendicular to the motion.
Fleming’s Left-Hand Rule:A force perpendicular to the field's direction and the direction of the current flow is experienced by a current-carrying conductor when it is exposed to an external magnetic field. According to Fleming's Left Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the left hand, the thumb will point in the direction of the force experienced by the conductor, and the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the electric current. This rule is employed to determine the magnetic force's direction within an electric motor.
Fleming’s Left-Hand Rule are essential rules applicable in magnetism and electromagnetism. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor.
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what does personal mission statement?
Answer:
A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.
Explanation:
It explains how you aim to pursue that purpose, and why it matters so much to you.
How do "inner planets" such as: Mercury, Venus, Earth and Mars compare with the "outer planets" such as: Jupiter, Saturn, Uranus and Neptune? Identify three characteristics that differ between these groups of planets.
Answer:
The four inner planets have shorter orbits, slower spin, no rings, and they are made of rock and metal. The four outer planets have longer orbits and spins, a composition of gases and liquids, numerous moons, and rings. The outer planets are made of hydrogen and helium, so they are called gas giants.
What is a small portable device that counts every step taken throughout the day?
A.stethoscope
B.pedometer
C.otoscope
D.thermometer
Answer: B
Explanation: i learned it last year
Pedometer is a small portable device that counts every step taken throughout the day. The correct option is (B).
A pedometer is a small portable device that counts the number of steps taken by an individual throughout the day. It is typically worn on the waist or carried in a pocket and uses a mechanism to detect body motion and count each step.
Pedometers are commonly used for tracking physical activity and encouraging individuals to achieve daily step goals as part of their fitness routines.
Therefore, Pedometer is a small portable device that counts every step taken throughout the day. Choose the option (B).
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state whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16
state, whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16 Reconstruction was successful in that it allowed the United States to once again function as a single country by 1877. The states' rights vs. federalism controversy, which had been a point of contention since the 1790s, was also eventually resolved during reconstruction.
By most other standards, reconstruction was a failure: radical Republican legislation eventually failed to shield former slaves from white persecution and to bring about significant alterations to the South's socioeconomic structure. The federalism question, which had been a topic since the 1790s practically immediately, was at hand when President Rutherford B. Former Confederate officials and slaves returned to the South after Hayes withdrew federal soldiers from the region in 1877. These newly powerful white southern legislators established anti-progressive laws like voter ID requirements and black codes with the help of a conservative Supreme Court in an effort to roll back the rights that blacks had won during Radical Reconstruction. With its rulings in the Slaughterhouse Cases, the Civil Rights Cases, and United States v., the U.S. Supreme Court strengthened this anti-progressive movement federalism.
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At the top of a hill a roller coaster has gravitational potential energy due to its position. What happend to this potential energy as the roller coaster speeds up on the way down the hill?
As the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy is neither created nor destroy, they can only be transformed from one form to another. Energy of and object can transform from Potential energy to kinetic energy and vice versa
Given that at the top of a hill a roller coaster has gravitational potential energy due to its position. What will happen to this potential energy as the roller coaster speeds up on the way down the hill is that the potential energy to the roller coaster will start decreasing while the kinetic energy will start to increase.
The total energy of the roller coaster will be constant because of conservation of energy. As the roller coaster speeds up on the way down the hill, the potential energy will eventually reduce to zero where the total energy of the as the roller coaster will be equal to maximum kinetic energy.
Therefore, as the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
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figue 1 shows a piece of elastic being stretched between 2 pieces of wood
When a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
However, in physics, the type of stress applied when an elastic material is stretched is tensile stress.
Recall:
Stess is defined as force per unit area
Mathematically; Stress = F/A
What is elasticity?Elasticity can be defined as the ability of a deformed elastic material or body to return to its original size and shape when the forces causing the deformation are removed.
So therefore, when a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
Complete question:
What happens when a piece of elastic material between two pieces of wood is being stretched beyond its limit?
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a simle arrangement by means of which emf are compared is known as
A simple arrangement by means of which EMF are compared is known as a voltmeter.
Discussion about Voltmeter :
A voltmeter is a straightforward device used to compare electromagnetic fields.When there is no current flowing through a cell, its terminal voltage equals its electromotive force (emf). The difference in potential between a cell's electrodes is what determines its terminal voltage. Since voltmeters use the cell's current to draw voltage, they are unable to measure a cell's emf.Using a voltmeter, one may determine the voltage generated in an electric circuit. Volts are the emf's SI unit (V). Volts are the voltage's SI unit (V). Non-coulomb force, also known as non-electric force operation, defines emf.Learn more about voltmeter here:
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the highest theoretical efficiency of a certain engine is 30% if the engine uses the atmosphere which has a temperature of 300k as its cold reservoir what is temperature of its hot reservoir
The temperature of its hot reservoir would be = 210k
Calculation of reservoir temperatureThe highest theoretical engine efficiency (η)= 30% =0.3
The temperature of the engine cold reservoir (T1)= 300k
Therefore the temperature of the engine hot reservoir (T2) = ?
Using this formula:
η=1- T2/T1
Make T2 the subject formula:
T2= T1 (1 - η)
T2 = 300 ( 1-0.3)
T2 = 300 × 0.7
T2 = 210k
Therefore, the temperature of its hot reservoir would be = 210K.
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A 940-kg sports car collides into the rear end of a 2500-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.8 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
What was the speed sports car at impact?
Express your answer to two significant figures and include the appropriate units.
The speed of the sport car at the time of impact is 6.61 m/s.
What is the frictional force of the two cars?Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
What is the acceleration of the skidded cars?As per Newton's second law of motion, force = mass × accelerationAcceleration= force / mass= 26,970/3440
= 7.8 m/s²
What is the velocity of the sport car at the time of impact?As per Newton's equation of motion, V² - U² = 2aSHere, V = 0 m/s, a= -7.8 m/s², S= 2.8 mSo, 0²-U²= 2×(-7.8)×2.8=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
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Describe at least four techniques used by astronomers to determine distances to stars and galaxies. Make sure you include the scientific theory behind each method and the range over which each method is considered valid.
Radar - measuring distances in our solar system
Parallax - measuring distances to nearby stars
Cepheids - measuring distances in our Galaxy and to nearby galaxies
Supernovae - measuring distances to other galaxies
Different techniques which can be used by the astronomers to determine the distances to the stars and galaxies include Radar, Parallax, Cepheids, and Supernova.
What are the techniques to determine distance of stars?
The distances to the nearby stars are precisely and accurately determined using the different techniques such as parallax. When a celestial body is seen from a different, widely separated viewing point, its position with respect to the more distant background stars or galaxies varies. This angular difference is known as parallax.
Radar is the measuring of the distances in the solar system.
Parallax is the measuring of distances to the nearby stars.
Cepheids is the measuring of distances in Galaxy and to nearby galaxies.
Supernovae is the measuring of distances to the other galaxies.
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The figure illustrates flow through a pipe with diameters of 1.0 mm and 2.0 mm and with different elevations. Px is the pressure in the pipe, and Vx is the speed of a non-viscous incompressible fluid at locations x = Q,R,S,T, or U. Options are: Greater than, Less than, Equal to
PU is ... PQ
VU is ... 2VT
PR is ... PU.
VR is ... VS
VQ is ... VU
PR is ... PS
By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]To find the answer, we need to know about the Bernoulli's equation as well as the Equation of continuity.
How to find the solution?1) We have to find the relation between pressure at U and Q.
We have the Bernoulli's equation,[tex]P+\frac{1}{2}dV^2+dgh=constant.[/tex]
where, P is the pressure, V is the velocity, d is density, g is acceleration due to gravity and h is the height of the flow.
By using the equation, we can find the pressure at U and Q.[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_q+\frac{1}{2}dV_q^2+dgh\\where,\\V_u=V_q, \\since, D_p=D_q\\Thus,\\P_u=P_q+dgh[/tex]
[tex]P_u > P_q[/tex]
2) We have to find the relation between velocity at U and T.
For this, we have the equation of continuity as,[tex]AV=constant\\A_1V_1=A_2V_2[/tex]
From the diagram, we have,[tex]A_u=\pi r^2=\pi *(0.5)^2=0.25\pi *mm^2\\A_t=\pi *1=\pi mm^2\\V_u=V\\V_t=?[/tex]
Thus, the relation between velocity at U and T is,[tex]V_t=\frac{A_uV_u}{A_t}=\frac{V}{4}[/tex]
[tex]2V_t=2*\frac{V}{4} =\frac{V}{2}\\V_u=V\\[/tex]
[tex]V_u > 2V_t[/tex]
3) We have to find the relation between pressure at R and U
[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_r+\frac{1}{2}dV_r^2+dg*0\\\\V_u=V , then\\V_r=V_t=\frac{V}{4}=\frac{V_u}{4} \\\\P_u=P_r+\frac{1}{16}[/tex]
[tex]P_u > P_r[/tex]
4) We have to find the relation between velocity at R and S
Both points R and S, have same area, thus same velocity.[tex]V_r=V_s[/tex]
5) We have to find the relation between velocity at Q and U
Both points Q and U, have same area, thus same velocity.[tex]V_q=V_u[/tex]
6) We have to find the relation between pressure at R and S
Both points R and S, have same area and thus, same velocities.[tex]P_r=P_s+dgh[/tex]
[tex]P_r > P_s[/tex]
Thus, we can conclude that, By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]Learn more about the Bernoulli's equation here:
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I = 30A and R = 30; what is V?
A. 900v
B.90v
C.10v
D.0.1v
Answer:
[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].
Explanation:
By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].
Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].
Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:
[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].
What is the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean?
It is slightly less than 9.81 m/s2.
It is very large due to the high pressure.
It is zero.
It is significantly less than 9.81 m/s2.
The gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure. That is option B
What is gravitational acceleration?The gravitational acceleration is the acceleration of an object that is under free fall. The acceleration due to gravity is 9.81 m/s2. above the sea level.
One of the factors that affect gravitational acceleration is depth. This is because as the depth increases so will pressure increase.
Increase in pressure leads to increase in gravitational acceleration.
Therefore, the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure.
Learn more about acceleration here:
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Is India a rich country?
Explanation:
India. Total wealth: $8.9 trillion | Wealth per capita: $6,440 | India, which is the fifth-largest economy in the world, is home to 3,57,000 HNWIs and 128 billionaires.
Answer:
50505050128128128128
Explanation:
7. Four perpendicular forces, 2 N, 3 N, 9 N and 10 N act on object P as shown in Diagram 2. 10 N A B 9 N 3 N 2 N P Diagram 2 What is the magnitude of the resultant force? 10 N C 18 N 14 N D 20 N
Answer: R=
A
2
+B
2
+2ABcosθ
θ=90
o
cos90
o
=0
R=
A
2
+B
2
=
3N
2
+4N
2
=5N
Explanation:
2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across a smooth horizontal surface by a force F evaluated the magnitude of F and what force the blocks exert on each other.
Answer:
Total mass of combination = 2+3+5 = 10kg.
Acceleration produced = 2m/s^2
hence force =( total mass × acceleration)= (2×10)= 20 N.
Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N
applied force on 2 kg block = 20N
Force between 2 kg and 3 kg block = (20-4) = 16N. ans
Net force on 3 kg block = 3 × 2 =6N.
Applied force on 3 kg block due to 2 kg block = 16N.
hence, force between 3 kg and 5 kg block = (16-6) = 10N .
answers:-
(a) 20 N
(b) 16N
(c) 10 N