Given that you have a two-resistor series circuit with an applied voltage of 100 V, we can use the principle of voltage distribution in a series circuit to determine the voltage across the second resistor.
In a series circuit, the total applied voltage is distributed across all the resistors. The voltage across each resistor is directly proportional to its resistance. In this case, we know the voltage across one resistor is 40 V.
Using the principle of voltage distribution, we can calculate the voltage across the other resistor as follows:
Total applied voltage = Voltage across resistor 1 + Voltage across resistor 2
100 V = 40 V + Voltage across resistor 2
Now, we can solve for the voltage across resistor 2:
Voltage across resistor 2 = Total applied voltage - Voltage across resistor 1
Voltage across resistor 2 = 100 V - 40 V
Voltage across resistor 2 = 60 V
So, the voltage across the other resistor in the series circuit is 60 V.
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Compare the scale (size) of a typical dusty disk around a forming star with the scale of our solar system.
The scale of a typical dusty disk around a forming star is much larger than the scale of our solar system.
Dusty disks around forming stars, known as protoplanetary disks, are vast structures that can extend several hundred astronomical units (AU) in size. An astronomical unit is the average distance between the Earth and the Sun, approximately 93 million miles or 150 million kilometers. In comparison, the scale of our solar system, which includes the Sun, planets, and other celestial bodies, is relatively small, with the outermost planet, Neptune, located about 30 AU from the Sun.
The size difference between a typical dusty disk and our solar system is significant. Protoplanetary disks are several times larger in radius compared to the extent of our solar system, highlighting the immense space available for the formation of planetary systems around young stars.
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List three ways in which the exoplanets we have detected have been found to be different from planets in our solar system.
Exoplanets differ from planets in our solar system in terms of size, composition, orbital characteristics, and the range of unusual environments they exist in.
How do exoplanets differ from planets in our solar system?Sure, here are three ways in which exoplanets have been found to be different from planets in our solar system:
Diversity in Size and Composition: Exoplanets come in a wide range of sizes and compositions. Some are much larger than Jupiter, while others are smaller than Earth. Some are made mostly of gas, while others are primarily composed of rock or water. In contrast, the planets in our solar system are relatively similar in size and composition.
Orbital Characteristics: Exoplanets have been found with a wide range of orbital characteristics. Some orbit their star in just a few days, while others take thousands of years to complete an orbit. Some exoplanets orbit very close to their star, while others are much further away. In our solar system, the planets have more regular orbits and are relatively evenly spaced.
Unusual Environments: Exoplanets have been discovered in a variety of unusual environments, including binary star systems, ultra-hot planets that have surface temperatures exceeding 2000°C, and planets with extreme gravity. In contrast, the planets in our solar system are located in a relatively stable and predictable environment.
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make a list of several intentional movements you can make using your hands on a daily basis. Reflect on what these movements all have in common.
All hand movements listed require fine motor skills, which involve precise movements of the hands and fingers.
What are the movements?The hand mocements that i make each day are;
"Brushing" - the act of holding the toothbrush and moving it back and forth to clean the teeth.
Using a pen or pencil - the act of holding the writing instrument while moving it to write or draw, as opposed to using your fingers to hit the keys on a keyboard to produce words and sentences.
Cutting up vegetables, stirring a pot, and flipping pancakes are all examples of cooking tasks.
Using the fingers to apply makeup, such as eyeliner or lipstick
When using a phone, you touch or swipe the screen with your fingers.
Playing an instrument refers to using fingers to create notes on a piano, guitar, or other musical instrument.
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When a bird alights upon a stretched power line wire, does the tension in the wire change? If so, is the increase more than, less than, or about equal to the bird's weight?
When a bird alights upon a stretched power line wire, the tension in the wire does change. The increase in tension is about equal to the bird's weight, as the wire needs to support the additional weight of the bird.
When a bird alights upon a stretched power line wire, the tension in the wire does change. The increase in tension depends on the weight of the bird and the elasticity of the wire. The increase in tension is generally about equal to the weight of the bird. However, if the wire is very elastic, the increase in tension may be less than the weight of the bird. Overall, the change in tension is relatively small and is unlikely to cause any significant issues with the power line.
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Suppose you stood atop a ladder that was
so tall that you were three Earth radii from
Earth's center. Show that your weight would
be one ninth its present value.
If you were standing on a ladder three Earth radii from Earth's center, your weight would be one-ninth of its present value.
The weight of an object is proportional to the mass of the object and the gravitational force acting on it. The gravitational force is inversely proportional to the square of the distance between the objects. As you move away from Earth's center, the gravitational force acting on you decreases.
If you were three Earth radii from Earth's center, the distance between you and Earth's center would be three times greater than it is at the surface of the Earth. Therefore, the gravitational force acting on you would be one-ninth of the force acting on you at the surface of the Earth.
Since your weight is the product of your mass and the gravitational force acting on you, your weight would also be one-ninth of its value at the surface of the Earth.
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which battery rating is tested at 0 deg f (-18 c)??1. cranking ampre (CA)2. cold cranking ampere (CCA)3. Marine cranking ampere4. reverse capacity
The battery rating that is tested at 0 degrees Fahrenheit (-18 degrees Celsius) is the (2) cold cranking ampere (CCA) rating.
CCA measures the number of amps a battery can deliver for 30 seconds at 0°F without dropping below 7.2 volts. This rating is important in colder climates because lower temperatures can cause batteries to lose power, making it more difficult for the battery to start the vehicle.
The higher the CCA rating, the more powerful the battery is in cold weather. The cranking ampere (CA) rating measures the same thing, but at 32°F instead of 0°F. Marine cranking ampere (MCA) is similar to CCA, but is tested at 32°F and for a longer period of time, as it is used in marine applications. Reverse capacity is not a battery rating.
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When the distance between positive and negative charges increases the electric potential?
Answer:
Increases
Explanation:
Opposite charges naturally want to go toward eachother (opposites attract) by moving them apart you are building that energy that will be used to pull them toward eachother, therefore increasing their potential.
A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 29.0 m/s. With what maximum speed can it go around a curve having a radius of 61.5 m
To answer this question, we need to use the formula for centripetal force:
F = mv^2/r
where F is the centripetal force, m is the mass of the truck, v is its speed, and r is the radius of the curve.
We can rearrange this formula to solve for v:
v = √(Fr/m)
We know that the mass of the truck is constant, so we can simplify this to:
v = √(F/r)
Now, we can compare the two curves. We know that the truck can go around the first curve with a maximum speed of 29.0 m/s, so we can use that to find the centripetal force:
F = mv^2/r = m(29.0 m/s)^2/150 m = 1340 mkg/s^2
Now, we can use this centripetal force to find the maximum speed for the second curve:
v = √(F/r) = √(1340 mkg/s^2 / 61.5 m) = 23.1 m/s
Therefore, the maximum speed that the truck can go around a curve with a radius of 61.5 m is 23.1 m/s.
In conclusion, the long answer is that we can use the formula for centripetal force and rearrange it to solve for the maximum speed of the truck. By knowing the maximum speed and radius of the first curve, we can find the centripetal force, which we can then use to find the maximum speed for the second curve.
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3.26 a football is kicked at an angle of 30 degrees with a speed of 20 m/s. To the nearest 5m, how far will the ball travel?
A 15m
b 25 m
C 35 m
D 45 m
The ball will travel 40 m, which is an option (D).
We can use the range formula to determine how far the football will travel:
[tex]R = (v^2 / g) * sin(2 \theta)[/tex]
where R is the range, v is the initial velocity, g is the acceleration due to gravity, and θ is the angle of launch.
Substituting the given values, we get:
[tex]R = (20 m/s)^2 / (2 * 9.81 m/s^2) * sin(2*30^o)[/tex]
R = 40 m / (2 * 0.5)
R = 40 m / 1
R = 40 m
Rounded to the nearest 5m, the ball will travel 40 m, which is an option (D).
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4) What are the different types of binary systems and how are they defined?
The different types of binary system include but not limited to Visual Binary, Spectroscopic Binary, and Eclipsing binary.
What are the type of binary system?Binary systems can be classified into different types based on their characteristics.
Visual binary: A visual binary system is one in which the two stars can be distinguished as separate objects through a telescope.
Spectroscopic binary: In a spectroscopic binary system, the two stars are too close together to be resolved by a telescope.
Eclipsing binary: An eclipsing binary system is one in which the two stars orbit each other in a plane that is aligned with our line of sight.
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In compression molding of a disk between two plates, the force required to squeeze plates together decreases as time increases
T/F
The given statement: In compression molding of a disk between two plates, the force required to squeeze plates together decreases as time increases is FALSE because as time increases, the material in the mold becomes denser and harder, increasing the force required to compress it.
The force required to squeeze plates together in compression molding actually increases as time increases. This is because the material being molded undergoes a reduction in volume as it is compressed, which increases the force required to continue compressing it.
The force required may also increase due to factors such as material flow resistance, cooling of the material, and friction between the material and the mold surfaces.
In order to properly mold a material, it is important to carefully monitor and control the compression force and time to ensure that the material is adequately compressed without being overcompressed and damaging the mold or the material itself.
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Explain why a dielectric increases the maximum operating voltage of a capacitor even though the physical size of the capacitor doesn't change.
Even though the physical size of the capacitor doesn't change, the addition of a dielectric material increases the maximum operating voltage by increasing the capacitance and by reducing the risk of breakdown due to the higher breakdown voltage of the dielectric material.
What are dielectric materials?A capacitor consists of two conductive plates separated by a dielectric material. When a voltage is applied to the capacitor, an electric field is established between the plates, causing charge to accumulate on the plates.
Dielectric materials are characterized by their ability to store electric charge within their structure. When a dielectric material is placed between the plates of a capacitor, it reduces the electric field strength between the plates, which in turn reduces the potential difference across the plates for a given amount of charge.
In addition to increasing the capacitance, a dielectric material also increases the maximum operating voltage of a capacitor by reducing the electric field strength at the surface of the conductive plates.
This is because dielectric materials have a higher breakdown voltage than air or a vacuum, meaning they can withstand higher electric field strengths before breaking down and becoming conductive.
This allows capacitors with dielectric materials to be operated at higher voltages without the risk of arcing or breakdown, which can damage or destroy the capacitor.
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A vertical wire of length 40cm and diameter of 0. 98mm and made of material of density 8000kg/m^3 is fixed at its upper end and supports a body of mass 5kg of volume 6cm^-3 at the other end. If the mass of the wire is negligible compared with the mass of the body. Calculate the frequency of the fundamental mode of transverse vibration of the wire before and after the body is totally immersed in water
Find the frequency of the fundamental mode of transverse vibration of a wire of length 40cm and diameter 0.98mm with a 5kg body at one end, before and after total immersion in water.
The frequency of the fundamental mode of transverse vibration of a vertical wire of length 40cm and diameter of 0.98mm can be calculated using the formula f = (1/2L) x sqrt(Tension/mu), where L is the length of the wire, mu is the linear density of the wire, and Tension is the tension in the wire. The frequency before the body is immersed in water can be calculated by assuming the tension is equal to the weight of the body, which is 5 x 9.8 = 49 N. After the body is immersed in water, the frequency can be calculated by adjusting the linear density of the wire, since the buoyant force reduces the effective weight of the body.
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Suppose you set up a standing wave of three segments. If you shake with twice as much freq, how many wave segments will occur in your new standing wave? How many wavelengths?
Doubling the frequency doubles the number of wave segments.
How does frequency affect standing waves?If the frequency of the shaking is doubled, the number of wave segments in the standing wave will also double. This is because the number of segments in a standing wave is directly proportional to the frequency of the wave. Therefore, a standing wave that originally had three segments would now have six segments when the frequency is doubled.
The wavelength of the new standing wave would be halved, as wavelength is inversely proportional to frequency. Therefore, if the frequency is doubled, the wavelength would be reduced to half of its original value. This means that the distance between two consecutive nodes (or antinodes) in the standing wave would also be halved. The amplitude of the standing wave would remain the same, as it is not affected by the frequency of the wave.
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If the moon "falls" 1.4 mm each second. Does
this mean that it gets 1.4 mm closer to Earth
each second? Would it get closer if its tangential
velocity were reduced? Explain.
The moon does get 1.4 mm closer to Earth each second as it "falls".
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What is the Doppler shift? (Explain in words and provide the formula)
The Doppler shift, also known as the Doppler effect, is a phenomenon where the frequency and wavelength of a wave (such as sound or light) change as the source of the wave and the observer move relative to each other.
When the source and the observer are moving closer together, the frequency increases and the wavelength decreases. Conversely, when they are moving away from each other, the frequency decreases and the wavelength increases.
The formula for the Doppler shift is: f' = f * (v + vo) / (v + vs)
where:
f' is the observed frequency,
f is the source frequency,
v is the speed of the wave in the medium,
vo is the speed of the observer (positive if moving toward the source, negative if moving away),
and vs is the speed of the source (positive if moving away from the observer, negative if moving toward).
This formula helps us calculate the change in frequency and wavelength experienced by the observer due to the relative motion between the source and the observer.
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When a fluid is subjected to a steady shear stress, it will reach a state of equilibrium in which no further motion occurs
T/F
The statement is false. When a fluid is subjected to a steady shear stress, it will continue to undergo deformation, and no equilibrium state will be reached.
When a fluid is subjected to a steady shear stress, it will continue to undergo deformation, and no equilibrium state will be reached. A shear stress is a force per unit area that causes one layer of fluid to move relative to another layer. In other words, it is a stress that causes deformation of the fluid.
When a fluid is subjected to a steady shear stress, it will exhibit a linear relationship between the shear stress and the rate of deformation, known as Newtonian behavior. The proportionality constant between the two is known as the viscosity of the fluid.
If the shear stress is removed, the fluid will return to its original shape and size, and no permanent deformation will occur. However, if the shear stress is maintained, the fluid will continue to deform, and the deformation will increase over time.
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A 0.75-kg sheet is centered on a clothesline. The clothesline on either side of the hanging sheet makes an angle of 3.5 degree with the horizontal. Calculate the tension in the clothesline on either side of the sheet. Why is the tension so much greater than the weight of the sheet?
The tension in the clothesline is about 60.06 N on either side of the sheet. It is greater because the clothesline is at a small angle.
The tension in the clothesline on either side of the 0.75-kg sheet can be calculated using the principles of static equilibrium and trigonometry. Since the sheet is in equilibrium, the vertical and horizontal components of the tension force must balance the gravitational force acting on the sheet.
Let T be the tension in the clothesline on either side of the sheet, and θ be the angle between the clothesline and the horizontal (3.5 degrees in this case). The weight of the sheet (W) can be calculated using the equation W = mg, where m is the mass (0.75 kg) and g is the acceleration due to gravity (approximately 9.81 m/s²).
The vertical component of the tension ([tex]T_v[/tex]) can be expressed as [tex]T_v[/tex] = Tsinθ. Since there are two identical tension forces acting vertically, the sum of these vertical components must equal the weight of the sheet: 2Tsinθ = W.
Now, we can plug in the values and solve for T:
2Tsin(3.5) = 0.75 × 9.81
Tsin(3.5) = 3.67875
T = 3.67875 / sin(3.5) ≈ 60.06 N
The tension in the clothesline is about 60.06 N on either side of the sheet. This tension is much greater than the weight of the sheet (about 7.36 N) because the clothesline is at a small angle (3.5 degrees) with the horizontal, causing the tension force to be distributed mainly in the horizontal direction. The tension must be significantly higher to provide enough vertical force to support the weight of the sheet.
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A boy jumps from rest straight upward from a flat, stationary concrete surface. The boy, of mass M, leaves the concrete surface with speed v and his center of mass rises a distance d to the highest point of the motion. How much physical work did the average normal force of contact (N) between the boy's feet and the concrete do on the boy
Work done by the average normal force of contact between the boy's feet and the concrete is zero.
What is the work done by the average normal force of contact between the boy's feet and the concrete on the boy as he jumps upward?The average normal force of contact (N) between the boy's feet and the concrete did positive work on the boy, equal to the increase in the boy's kinetic energy.
At the moment the boy leaves the surface, the only force acting on him is his weight (mg) pointing downwards. As he rises, the normal force exerted by the concrete on his feet reduces the net force acting on him and causes him to decelerate. At the highest point of the motion, the normal force reduces to zero, and the boy momentarily comes to rest before falling back down.
The work done by the normal force is given by the product of the force and the displacement in the direction of the force. Since the normal force is always perpendicular to the displacement, it does no work on the boy during the upward motion. Therefore, the work done by the average normal force of contact between the boy's feet and the concrete is zero.
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What is the ratio between the maximum and the minimum sound intensities that produce this particular loudness?
The ratio between the maximum and minimum sound intensities that produce a particular loudness varies depending on the individual's perception and the specific loudness level being discussed.
However, in general, the relationship between loudness and sound intensity is not linear but logarithmic. This means that as the sound intensity doubles, the perceived loudness increases by a constant amount. The ratio between the maximum and minimum sound intensities that produce a particular loudness is known as the loudness level or the decibel (dB) scale. For example, a sound with an intensity of [tex]10^{-12} W/m^2[/tex] is considered the threshold of human hearing and has a loudness level of 0 dB. A sound with an intensity of [tex]10^{-9} W/m^2[/tex] has a loudness level of 30 dB, which is 100 times louder than the threshold of human hearing.
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According to the moment magnitude scale (M w), the amplitude of ground shaking during a magnitude 8 earthquake would be 1,000 times greater than a magnitude ________ earthquake. a. 9 b. 4 c. 5 d. 7
According to the moment magnitude scale (M w), the amplitude of ground shaking during a magnitude 8 earthquake would be 1,000 times greater than a magnitude 5 earthquake.
The moment magnitude scale (M w) is a logarithmic scale used to measure the size of earthquakes in terms of the energy released. Each increase in magnitude represents a tenfold increase in amplitude of ground shaking, and a 32-fold increase in the energy released. Therefore, an earthquake with a magnitude of 8 would have an amplitude of ground shaking 1,000 times greater than an earthquake with a magnitude of 5.
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A long solenoid has windings and a circular cross section of radius . The solenoid goes through the center of a circular coil of wire with windings and radius . The current in the circular coil changes according to .
The interaction between the long solenoid and the circular coil is described by Faraday's law of electromagnetic induction. When the current in the circular coil changes according to a particular function,
it induces an electromotive force (EMF) in the solenoid. The magnitude of this EMF is proportional to the rate of change of current in the coil and the number of turns in the solenoid.
The radius of the solenoid and the circular coil are also important factors in determining the strength of the EMF induced in the solenoid. The closer the circular coil is to the solenoid, the stronger the EMF induced will be.
Overall, the relationship between the current change in the circular coil, the number of windings in the solenoid, and the radius of both components will determine the magnitude of the induced EMF in the solenoid.
This principle is utilized in many applications, such as transformers and electric motors.
Hi! Your question seems to be about the magnetic field generated by a solenoid and a circular coil. A long solenoid with windings and a circular cross-section of radius has a magnetic field inside it that is uniform and parallel to its axis. .
When the solenoid goes through the center of a circular coil of wire with windings and radius , the magnetic field generated by the solenoid can induce an electromotive force (EMF) in the circular coil.
The current in the circular coil changes according to , which influences the magnetic field and the induced EMF. Faraday's law of electromagnetic induction states that the induced EMF in a closed loop is proportional to the rate of change of the magnetic flux through the loop.
So, as the current in the circular coil changes, the magnetic field and the EMF induced in the solenoid will also change accordingly.
In summary, a long solenoid with a circular cross-section and windings generates a magnetic field that interacts with a circular coil of wire, causing an induced EMF in the coil.
The changing current in the circular coil affects the magnetic field and the induced EMF, as described by Faraday's law of electromagnetic induction.
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A pencil that is 15.7 cm long is released from a vertical position with the eraser end resting on a table. The eraser does not slip as it tips over. Treat the pencil like a uniform rod. What is the angular speed of the pencil just before it hits the table?
The angular speed of the pencil just before it hits the table is 2.19 rad/s.
When the pencil is released, it begins to rotate about the eraser end. The potential energy of the pencil is converted into kinetic energy of rotation as it falls. Because the pencil is treated as a uniform rod, we can use the formula for rotational kinetic energy:
K = (1/2) × I × w²where K is the kinetic energy of rotation, I is the moment of inertia, and w is the angular speed.
The moment of inertia of a uniform rod rotating about one end is given by:
I = (1/3) × m × L²where m is the mass of the rod and L is its length.
In this case, the length of the pencil is L = 15.7 cm = 0.157 m, and assuming a uniform density, the mass can be calculated from its length and diameter. Then, plugging in the values for I, K, and solving for w, we get:
w = √(2 × K / I) w = √(2 × m × g × h / (3 × m × L² / 12))w = √(8/3 × g × h / L²) w = √(8/3 × 9.81 m/s² × 0.157 m / (0.157 m)²)w = 2.19 rad/sTherefore, the angular speed of the pencil just before it hits the table is 2.19 rad/s.
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Calculate the heat released when 2000 grams of ethanol condenses to a liquid
To calculate the heat released when 2000 grams of ethanol condenses to a liquid, we need to use the heat of vaporization of ethanol. The heat of vaporization of ethanol is 38.56 kJ/mol.
First, we need to convert 2000 grams of ethanol to moles. The molar mass of ethanol is 46.07 g/mol, so:
2000 g / 46.07 g/mol = 43.41 mol
Next, we need to multiply the number of moles by the heat of vaporization:
43.41 mol x 38.56 kJ/mol = 1671.77 kJ
Therefore, the heat released when 2000 grams of ethanol condenses to a liquid is 1671.77 kJ.
The gas phase of ethanol can condense into the liquid phase when it is cooled. Ethanol may exist as a liquid or a solid at temperatures lower than its boiling point of 78.37°C (173.1°F), which causes this to occur. When ethanol is heated, its molecules absorb energy and gain energy, ultimately building up enough energy to force their way out of the liquid phase and transform into a gas. This is referred to as evaporation or vaporisation. On the other hand, when ethanol is cooled, its molecules begin to lose energy until finally they are unable to keep the gaseous condition they are in.
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Calculate the approximate force on a square meter of sail, given the horizontal velocity of the wind is 6.00 m/s parallel to its front surface and 3.50 m/s along its back surface. Take the density of air to be 1.29 kg/m2
The approximate force on a square meter of sail is 16.79 N.
To calculate the force on the sail, we first need to determine the pressure difference between the front and back surfaces of the sail. We can use Bernoulli's equation for this:
P1 + 0.5 * ρ * v1^2 = P2 + 0.5 * ρ * v2^2
Where P1 and P2 are the pressures at the front and back surfaces, ρ is the air density (1.29 kg/m³), and v1 and v2 are the wind velocities (6.00 m/s and 3.50 m/s) along the front and back surfaces.
We can rewrite the equation to find the pressure difference (ΔP):
ΔP = 0.5 * ρ * (v1^2 - v2^2)
Substituting the given values:
ΔP = 0.5 * 1.29 kg/m³ * (6.00 m/s^2 - 3.50 m/s^2)
ΔP = 13.035 Pa
Now, to find the force (F) on a square meter of sail, we can use the formula:
F = ΔP * A
Where A is the area of the sail (1 m²). Substituting the values:
F = 13.035 Pa * 1 m²
F = 16.79 N (approximately)
Summary: Given the wind velocities and air density, the approximate force on a square meter of sail is 16.79 N.
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low pressure atmosphere (but must have been denser in the past) The atmosphere is made of mostly carbon dioxide (95%) and nitrogen.
is called?
The low pressure atmosphere that was denser in the past and is currently made up of mostly carbon dioxide (95%) and nitrogen is known as the Martian atmosphere.
The atmosphere of Mars is considerably thinner than that of Earth due to its lower gravitational pull and lack of a strong magnetic field, which has allowed for the loss of lighter gases such as hydrogen and helium over time. However, the presence of carbon dioxide in the Martian atmosphere has played a significant role in the planet's climate history, as it is a potent greenhouse gas that can trap heat and warm the planet. This has led to periods of warming and cooling on Mars, with evidence of past ice ages and the possibility of liquid water on the surface. Understanding the Martian atmosphere and its composition is crucial for future exploration and potential colonization of the planet.
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7. Epiphytes in a rainforest use rainforest trees for
food
b. support
C. oxygen
d. pollination
What do you think will happen when the balloon is moved closer to the wall?
A. Some positive charges in the wall will move towards the balloon B. Some negative charges in the wall will move towards the balloon C. Some positive charges in the wall will go onto the balloon D. Some negative charges on the balloon will go to the wall Neutral wall Negatively charged balloon
When the balloon is moved closer to the wall, there will be an electrostatic interaction between them. The balloon, being negatively charged, will repel the negative charges in the wall. This will cause some of the negative charges in the wall to move toward the balloon, resulting in option B.
As for option A, it is not likely that positive charges in the wall will move toward the balloon. This is because like charges repel each other and positive charges in the wall would be repelled by the positively charged balloon, which is not the case in this scenario.
Option C is also unlikely because positive charges in the wall would be attracted to the negatively charged balloon. However, the balloon cannot accept these charges as it is already negatively charged.
Option D is also incorrect as negative charges on the balloon would be repelled by the negative charges in the wall and would not be attracted to it.
Therefore, when the negatively charged balloon is moved closer to the neutral wall, some of the negative charges in the wall will move toward the balloon resulting in option B.
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The hydrostatic force entered on one face of a sphere plate of side L that is held vertically in a liquid with on edge in the free surface is F. If the plate lowered vertically by a distance L, the force on one face will be 3F.
T/F
True, the hydrostatic force exerted on one face of a sphere plate of side L that is held vertically in a liquid with one edge in the free surface is F. If the plate is lowered vertically by a distance L, the force on one face will be 3F.
A force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.......
The acceleration rises proportionately when we raise the force of an item. Because the mass does not change with increasing acceleration, we can tell that strength is equal to acceleration. Force is related directly to acceleration (force ~ acceleration)
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Describe the interaction between two bottom (B) strips when they are brought near each other. Do the strips attract, repel, or not interact at all?
The interaction between two bottom strips when brought near each other is likely to be repulsive.
When two bottom (B) strips are brought near each other, they will likely repel each other. This is because the bottom strips are made of a material that has a negative charge, which means that they have an excess of electrons.
The excess of electrons causes a negative charge to build up on the surface of the strips. When two negatively charged surfaces are brought close together, they will repel each other due to the electrostatic force.
This repulsion can be observed as the strips push away from each other when brought near. It is important to note that this repulsion is not always consistent,
As factors such as the distance between the strips and the charge distribution on their surfaces can affect the strength of the interaction.
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