A vapor compression refrigeration cycle operating at steady state, in which R134a at -12 C as saturated vapor enters to a reversible compressor and saturated liquid at 5 bar leaves the condenser. Assume stray heat transfer, kinetic, and potential energy effects are negligible. Condenser and evaporator are at constant pressure. Compressor and expansion valve are well insulated. Some properties are given on the diagram, others provided in the given table.

a) Mark all four states and processes on the given t-s diagram.
b) determine the specific enthalpies at the inlet of the evaporator and at the exit of the compressor.
c) Determine the coefficient of performance for refrigeration for this cycle.
d) Determine entropy production (generation) per unit mass of the refrigerant, in kJ/kg * K, in the condenser where heat is discharged by the cycle through a surface being kept at 12 deg. C.

Answers

Answer 1

The all four states and processes on the given t-s diagram include heat rejection, expansion heat addition when compression.

The specific enthalpies at the inlet of the evaporator and at the exit of the compressor is 221.48Kj

How to explain vapor compression

Vapor compression is a thermodynamic process used in refrigeration and air conditioning systems to cool a space or substance. The process involves compressing a gas (usually a refrigerant) to increase its temperature and pressure, and then passing it through a condenser where it releases heat and becomes a liquid.

The liquid is then passed through an expansion valve, which reduces its pressure and causes it to evaporate, absorbing heat from its surroundings and returning to a gaseous state. This process is repeated in a closed loop to continuously cool the space or substance being refrigerated. Vapor compression is an efficient and widely used method of refrigeration, and is found in a variety of applications such as home refrigerators, commercial refrigeration systems, and air conditioning systems.

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all wheel nuts must be tightened to the correct torque and in the proper _____________

Answers

All wheel nuts must be tightened to the correct torque and in the proper sequence to ensure the safety of the vehicle and its passengers. Torque refers to the amount of force that is applied to the wheel nut when it is tightened onto the wheel stud.

If the torque is too low, the wheel nut may loosen over time, which can result in the wheel becoming detached from the vehicle while it is in motion. On the other hand, if the torque is too high, the wheel stud or nut may become damaged, which can also compromise the safety of the vehicle.In addition to the torque value, it is also important to tighten the wheel nuts in the proper sequence. The sequence refers to the order in which the nuts are tightened around the wheel. This is important because tightening the nuts in the wrong sequence can cause the wheel to be pulled off-center, which can lead to vibration and uneven wear on the tires. The proper sequence can vary depending on the make and model of the vehicle, so it is important to consult the owner's manual or a professional mechanic for guidance.Overall, it is crucial to ensure that all wheel nuts are tightened to the correct torque and in the proper sequence to prevent accidents and ensure the safe operation of the vehicle. Failure to do so can result in serious consequences, so it is important to take this task seriously and pay close attention to the details.

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Near-field communication devices send data at what fixed frequency?
A - 8.65 MHz
B - 13.56 MHz
C - 21.39 MHz
D - 47.1 MHz

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Near-field communication devices send data at a fixed frequency of 13.56 MHz.The answer is option B

Near Field Communication (NFC) is a wireless communication technology that enables devices to exchange data over short distances. NFC-enabled devices can establish a connection with each other by being brought into close proximity or through a simple touch. This technology is used for various applications such as contactless payments, data transfer, and access control systems. NFC devices have a range of up to 4 cm and can operate in both active and passive modes. With the increasing popularity of mobile payments and the Internet of Things (IoT) devices, NFC is becoming an essential feature in smartphones, smartwatches, and other electronic devices. NFC is a secure and convenient method of transmitting data, making it a popular choice for a range of applications.

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segregation is segregation required by law and that results from government discrimination.

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Yes, segregation can be required by law and can result from government discrimination. Historically, there have been laws that enforced segregation, such as Jim Crow laws in the United States.

These laws were created and enforced by the government, which discriminated against certain groups of people, particularly African Americans. This led to institutionalized segregation in many aspects of life, including education, housing, and public accommodations. So, segregation can be a result of government discrimination and is often enforced by laws that discriminate against certain groups of people.
Segregation is the separation of people based on their race, ethnicity, or other characteristics. When segregation is required by law and results from government discrimination, it is known as "legal segregation" or "de jure segregation." In this case, the government enacts and enforces laws that mandate the separation of different groups, leading to unequal treatment and limited opportunities for certain groups. Legal segregation has been a prominent issue in many countries throughout history, including the United States during the era of Jim Crow laws. These laws enforced racial segregation and perpetuated inequality between white and Black Americans until the Civil Rights Movement successfully challenged and dismantled them.

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Segregation, in the context of law and government discrimination, refers to the enforced separation of different racial or ethnic groups by legal means. This practice is often based on the notion that one group is superior to another, leading to inequality and social stratification.

Throughout history, numerous governments have implemented segregationist policies, which have had profound and long-lasting effects on the affected populations. One prominent example is the racial segregation in the United States, where laws such as the Jim Crow Laws mandated separation between white and African American citizens in public spaces, schools, and transportation. This form of legal segregation led to significant disparities in education, income, and overall quality of life for the segregated groups.Another example is the Apartheid system in South Africa, which was a policy of racial segregation and discrimination that lasted from 1948 to the early 1990s. This system classified citizens into different racial groups and determined where they could live, work, and receive education, ultimately entrenching social and economic disparities among the population.While many nations have since abolished segregationist policies, the impacts of such government discrimination are still felt today. Racial disparities in education, income, and access to resources remain in societies where segregation was once enforced by law. It is crucial for governments and individuals to actively work towards dismantling the remnants of these discriminatory systems to promote equality and social justice for all.

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discuss how the operator uses knowledge of the factors that affect abrasion to control the polishing sequence of an amalgam restoration, a composite restoration, and a gold restoration.

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The operator uses knowledge of the factors that affect abrasion to control the polishing sequence of an amalgam restoration, a composite restoration, and a gold restoration in the following ways:

1. Amalgam Restoration: The operator uses knowledge of the hardness and roughness of the amalgam material to select the appropriate polishing instruments and sequence. The polishing sequence typically involves the use of coarse abrasives, such as diamond burs, to remove any rough surfaces, followed by finer abrasives, such as rubber cups and points, to achieve a smooth and polished surface. The operator must also consider the presence of any marginal ridges or overhangs that may require additional attention during the polishing process.

2. Composite Restoration: The operator uses knowledge of the composite material's relative softness and tendency to wear during polishing to select the appropriate polishing instruments and sequence. The polishing sequence typically involves the use of fine abrasives, such as diamond polishing pastes, to achieve a high gloss finish. The operator must also consider any surface irregularities or contouring that may require additional attention during the polishing process.

3. Gold Restoration: The operator uses knowledge of the gold alloy's relative hardness and resistance to wear during polishing to select the appropriate polishing instruments and sequence. The polishing sequence typically involves the use of progressively finer abrasives, such as pumice, tripoli, and rouge, to achieve a high luster finish. The operator must also consider any surface irregularities, such as porosity or pits, that may require additional attention during the polishing process.

In all three types of restorations, the operator must also consider factors such as the shape and size of the polishing instruments, the speed and pressure of the polishing handpiece, and the use of cooling water or lubricating agents to minimize heat generation and reduce the risk of damage to the restoration or surrounding tissues. By carefully controlling the polishing sequence and techniques, the operator can achieve a smooth, polished surface that is both aesthetically pleasing and functionally effective.

A construction worker hits a chunk of concrete with a sledgehammer. The sledgehammer delivers a force of 750 lbs and breaks the concrete

Answers

When the construction worker hits the chunk of concrete with the sledgehammer, the force of the sledgehammer is transferred to the concrete and since the force is 750 lbs, we can as well assume it is strong enough to break the concrete.

What is Force?

Force is a vector quantity that has both magnitude and direction. Force is a push or pull on an object that causes it to accelerate or deform.

Force is commonly denoted by the symbol "F" and its SI unit is the newton (N). One newton is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg x m/s²).

Examples of forces include the gravitational force between two masses, the tension in a rope, the normal force exerted by a surface, the force exerted by a spring, and the force exerted by a person pushing an object.

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for flow over a flat plate of length l, the local heat transfer coefficient hx is known to vary as x1/2, where x is the distance from the leading edge of the plate. what is the ratio of the average nusselt number for the entire plate ( nu l) to the local nusselt number at x l (nul)?

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The Nusselt number is a dimensionless number that relates the heat transfer between a fluid and a surface to the thermal conductivity and the fluid properties. For flow over a flat plate of length l, the local heat transfer coefficient hx is known to vary as x1/2, where x is the distance from the leading edge of the plate.

The local Nusselt number at a distance x from the leading edge of the plate can be calculated as:

nul = hx * x / k

where k is the thermal conductivity of the fluid.

The average Nusselt number for the entire plate can be calculated as:

nu l = (1/l) * ∫₀^l hx(x) * x / k dx

where hx(x) is the local heat transfer coefficient at a distance x from the leading edge of the plate.

Since hx is known to vary as x1/2, we can write:

hx(x) = k * (hx(l) / l^(1/2)) * x^(1/2)

Substituting this into the equation for nu l and solving the integral, we get:

nu l = 0.664 * (hx(l) * l / k)^(1/2)

Similarly, substituting hx(x) into the equation for nul and simplifying, we get:

nul = 2/3 * hx(l) * (x/l)^(1/2)

Therefore, the ratio of the average Nusselt number for the entire plate to the local Nusselt number at x l is:

nu l / nul = (0.664 * (hx(l) * l / k)^(1/2)) / (2/3 * hx(l) * (l/l)^(1/2))

Simplifying, we get:

nu l / nul = 0.998

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Average setup time on a certain production machine is 5.0 hr. Average batch size is 52 parts, and average operation cycle time is 4.2 min. The reliability of this machine is characterized by mean time between failures of 37 hr and a mean time to repair of 55 min.
(a) If availability is ignored, what is the average hourly production rate of the machine.
(b) Taking into account the availability of the machine, determine its average hourly production rate.
(c) Suppose that availability only applied during the actual run time of the machine and not the setup time. Determine the average hourly production rate of the machine under this scenario.

Answers

(a) The machine's average hourly production rate without considering availability is 6.02 parts/hr.

(b) The machine's average hourly production rate, taking into account availability, is 6.17 parts/hr.

(c) The machine's average hourly production rate when only available during run time is 5.71 parts/hr.

How to solve calculations on a production machine?

(a) To calculate the average hourly production rate of the machine without considering availability, we need to first calculate the total time it takes to produce a batch of 52 parts.

Total time = (setup time) + (operation time per part x batch size)

Total time = 5.0 hr + (4.2 min/part x 52 parts)/60 min/hr

Total time = 5.0 hr + 3.64 hr

Total time = 8.64 hr

Average hourly production rate = Batch size / Total time

Average hourly production rate = 52 parts / 8.64 hr

Average hourly production rate = 6.02 parts/hr

Therefore, the average hourly production rate of the machine without considering availability is 6.02 parts/hr.

(b) To calculate the average hourly production rate of the machine taking into account availability, we need to first calculate the machine's availability using the mean time between failures (MTBF) and mean time to repair (MTTR) values.

Availability = MTBF / (MTBF + MTTR)

Availability = 37 hr / (37 hr + 0.92 hr)

Availability = 0.975 or 97.5%

Now we can calculate the total time that the machine is available for production:

Available time = Total time x Availability

Available time = 8.64 hr x 0.975

Available time = 8.42 hr

Average hourly production rate = Batch size / Available time

Average hourly production rate = 52 parts / 8.42 hr

Average hourly production rate = 6.17 parts/hr

Therefore, the average hourly production rate of the machine taking into account availability is 6.17 parts/hr.

(c) If availability only applies during the actual run time of the machine and not the setup time, we need to adjust the available time calculation:

Available time = (operation time per part x batch size) / 60 min/hr x Availability

Available time = (4.2 min/part x 52 parts) / 60 min/hr x 0.975

Available time = 4.11 hr

Total time = Available time + setup time

Total time = 4.11 hr + 5.0 hr

Total time = 9.11 hr

Average hourly production rate = Batch size / Total time

Average hourly production rate = 52 parts / 9.11 hr

Average hourly production rate = 5.71 parts/hr

Therefore, the average hourly production rate of the machine taking into account availability only during run time is 5.71 parts/hr.

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fermentation tank in a pullman brewpub is rated for a maximum absolute pressure of 75 psia. a bourdon gauge attached to the tank reads 64 psig. is there a danger that the pressure limit for the fermentation tank has been exceeded? explain why or why not

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Yes, there is a danger that the pressure limit for the fermentation tank has been exceeded. This is dangerous because the tank could rupture or explode if the pressure continues to increase.

This is because:

First, it's important to understand what "absolute pressure" and "psig" mean in this context. Absolute pressure is the total pressure exerted by a gas, including atmospheric pressure (which is around 14.7 psi at sea level). Psig, on the other hand, refers to the pressure exerted by a gas above atmospheric pressure. So if a tank has a reading of 64 psig, that means the gas inside is exerting a pressure of 64 psi above atmospheric pressure.

Now, let's look at the numbers. The fermentation tank in the Pullman brewpub is rated for a maximum absolute pressure of 75 psia. This means that the total pressure inside the tank (including atmospheric pressure) should not exceed 75 psi. However, the bourdon gauge attached to the tank reads 64 psig, which means that the pressure inside the tank is actually 78.7 psia (64 psig + 14.7 psi atmospheric pressure).

This is above the maximum absolute pressure rating of 75 psia for the tank, which means that the pressure limit for the fermentation tank has been exceeded. This is dangerous because the tank could rupture or explode if the pressure continues to increase. It's important to take immediate action to relieve the pressure and prevent further build-up to ensure the safety of the people working with the tank and the surrounding area.

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Hi! Your question is whether there is a danger that the pressure limit for the fermentation tank in a Pullman brewpub has been exceeded, given that it is rated for a maximum absolute pressure of 75 psia, and the Bourdon gauge reads 64 psig.

To answer this, we need to compare the actual absolute pressure in the tank to the rated maximum absolute pressure limit.

Step 1: Convert the gauge pressure (psig) to absolute pressure (psia).
Gauge pressure measures pressure relative to atmospheric pressure. To convert it to absolute pressure, add the atmospheric pressure to the gauge pressure. The standard atmospheric pressure is approximately 14.7 psi.

Absolute Pressure = Gauge Pressure + Atmospheric Pressure
Absolute Pressure = 64 psig + 14.7 psi (approximately)

Step 2: Calculate the absolute pressure.
Absolute Pressure = 64 + 14.7
Absolute Pressure ≈ 78.7 psia

Step 3: Compare the calculated absolute pressure to the maximum pressure limit.
In this case, the calculated absolute pressure (78.7 psia) is higher than the maximum rated pressure limit of the fermentation tank (75 psia).

In conclusion, there is a danger that the pressure limit for the fermentation tank has been exceeded, as the calculated absolute pressure (78.7 psia) is higher than the rated maximum absolute pressure limit (75 psia).

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The statement: if (a >= b) a++; else b--; will do the same thing as the statement: if (a < b) b--; else a++;. (1) True False

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True. Both statements will increment a if a is greater than or equal to b, and decrement b if a is less than b. If neither condition is met, then a will be incremented and b will be decremented.


The statement "if (a >= b) a++; else b--;" is indeed equivalent to the statement "if (a < b) b--; else a++;". (1) True.
Here's a step-by-step explanation:
1. In the first statement, if "a" is greater than or equal to "b", "a" will be incremented (a++).
2. If "a" is not greater than or equal to "b", "b" will be decremented (b--).
Now let's look at the second statement:
1. In the second statement, if "a" is less than "b", "b" will be decremented (b--).
2. If "a" is not less than "b", "a" will be incremented (a++).
As you can see, both statements perform the same mathematical operations based on the comparison of "a" and "b".

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The answer is False.

The statement: if (a >= b) a++; else b--; will not do the same thing as the statement: if (a < b) b--; else a++;. The reason is that the conditions are opposite in each statement, and therefore the outcome will be different.

In the first statement, if a is greater than or equal to b, then a will be incremented by one, otherwise b will be decremented by one. In the second statement, if a is less than b, then b will be decremented by one, otherwise a will be incremented by one.Consider the scenario where a = 5 and b = 4. In the first statement, since a is greater than b, a will be incremented by one, and the new value of a will be 6. In the second statement, since a is also greater than b, a will be incremented by one, and the new value of a will be 6. Therefore, the two statements do not produce the same result.In conclusion, the statement: if (a >= b) a++; else b--; will not do the same thing as the statement: if (a < b) b--; else a++;. The two statements have opposite conditions, and therefore the outcome will be different.

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we want a copper bar to have a tensile strength of at least 70,000 psi and a final diameter of 0.375 in. what is the minimum diameter of the original bar?

Answers

To solve this problem, we can use the equation for tensile strength:

Tensile strength = Force / Area

We know that we want the tensile strength to be at least 70,000 psi, and we can assume that the force required to achieve this will remain constant. Therefore, we can rearrange the equation to solve for the minimum area required:

Area = Force / Tensile strength

Next, we can use the equation for the area of a circle to relate the area of the original bar to its diameter:

Area = π * (diameter)^2 / 4

Substituting this into the previous equation, we get:

π * (diameter)^2 / 4 = Force / Tensile strength

Solving for the minimum diameter, we get:

diameter = √(4 * Force / (π * Tensile strength))

We don't know the force required to achieve the desired tensile strength, but we can use the equation for the ultimate tensile strength of copper (which is the maximum stress it can withstand before breaking) to estimate it:

Ultimate tensile strength = Yield strength / Safety factor

The yield strength of copper is around 30,000 psi, and a typical safety factor for engineering design is 2. Therefore, the estimated force required is:

Force = Ultimate tensile strength * Area * Safety factor
Force = 2 * 30,000 psi * π * (0.375 in / 2)^2

Plugging this into the equation for minimum diameter, we get:

diameter = √(4 * Force / (π * Tensile strength))
diameter = √(4 * 2 * 30,000 psi * π * (0.375 in / 2)^2 / (π * 70,000 psi))
diameter ≈ 0.564 in

Therefore, the minimum diameter of the original bar should be about 0.564 inches to achieve a final diameter of 0.375 inches with a tensile strength of at least 70,000 psi.

in order for a ptc relay’s resistance to drop low enough for a motor to start again, it must have enough time to cool down. true or false

Answers

The given statement is True. in order for a PTC relay's resistance to drop low enough for a motor to start again, it must have enough time to cool down.


When a PTC relay trips due to an overload or overcurrent situation, it takes time to cool down and for its resistance to increase again. This is because the PTC (Positive Temperature Coefficient) relay is a type of thermistor, meaning its resistance changes with temperature. When the relay is cool, it has a low resistance, allowing the motor to start. As it heats up, the resistance increases, and the relay must cool down before the motor can start again.

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True. In order for the PTC relay's resistance to drop low enough for the motor to start again, it must go through a cool-down period to allow the temperature to decrease and the resistance to decrease accordingly.

PTC (Positive Temperature Coefficient) relays are devices used to protect electric motors from damage due to overload or overheating. When a motor draws too much current and begins to overheat, the resistance of the PTC relay increases, limiting the current flow to the motor and protecting it from damage.After the motor cools down, the PTC relay's resistance drops, allowing the motor to start again. This means that in order for the PTC relay's resistance to drop low enough for the motor to start again, it must have enough time to cool down.If the PTC relay does not have enough time to cool down, the motor will not start again, and the relay will continue to limit the current flow to the motor. This can lead to reduced motor performance, increased energy consumption, and even motor failure if the problem is not addressed. Therefore, it is important to allow the PTC relay enough time to cool down before attempting to restart the motor.

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2. A wire, 1.5mm diameter, supports a mass of 60kg. calculate the stress.​

Answers

Answer:

Therefore, the stress on the wire is 1.05 x 10^9 Pa.

Explanation:

To calculate stress, we need to know the force applied to the wire and its cross-sectional area.

The first step is to calculate the cross-sectional area of the wire:

A = πr² = π(0.75mm)² = π(0.00075m)² = 5.58 x 10^-7 m²

Next, we need to calculate the force applied to the wire due to the weight of the mass:

F = m*g = 60kg * 9.81 m/s² = 588.6 N

Now we can calculate the stress:

stress = F/A = 588.6 N / 5.58 x 10^-7 m² = 1.05 x 10^9 Pa

Therefore, the stress on the wire is 1.05 x 10^9 Pa.

__________ is a precise way to measure a variable. group of answer choices an operational definition validity the hypothesis reliability

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An operational definition is a precise way to measure a variable.
An operational definition is a precise way to measure a variable.

An operational definition is a precise way to measure a variable. An operational definition is a statement that describes the exact procedures or methods used to measure a particular variable in a study. It defines the variable in terms of how it will be measured or manipulated in the study, and it specifies the criteria that will be used to evaluate the variable.For example, if a study is examining the effects of a new medication on anxiety, an operational definition of anxiety might be "the number of times a participant reports feeling anxious on a 10-point scale over a 24-hour period." This definition provides a clear and specific way to measure anxiety in the study.Using an operational definition is important for ensuring the validity and reliability of a study. By clearly defining the variable and how it will be measured, researchers can ensure that they are measuring what they intend to measure and that their results are consistent and accurate. Operational definitions also allow other researchers to replicate the study and test its validity and reliability.

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An operational definition is a precise way to measure a variable.

In research, an operational definition specifies the exact procedure or method used to measure or manipulate a variable, ensuring consistency, accuracy, and reliability in the measurement process.

The operational definition can be referred to as the specific way in which a variable is measured in a particular study. It is important to operationally define a variable to lend credibility to the methodology and ensure the reproducibility of the study’s results.

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by purchasing software that gathers data and predicts trends in the most popular genres without any extra programming, the library can purchase the books that people will read

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By utilizing software that collects data and forecasts trends in popular genres, the library can make informed decisions on which books to purchase. This ensures that the library's collection stays up-to-date and aligns with the reading interests of the community, ultimately leading to increased patron satisfaction and engagement.

By purchasing software that gathers data and predicts trends in the most popular genres, the library can make informed purchasing decisions on the books that people are likely to read. This eliminates the need for extra programming and ensures that the library's collection stays relevant and in-demand. The software can analyze data such as user preferences, browsing history, and book ratings to generate accurate predictions on which books will be popular in the future. This ultimately saves the library time and money by avoiding the purchase of books that may not be well-received by their audience. Overall, investing in such software can greatly benefit the library's collection development strategy and help them better serve their community's reading needs.
By utilizing software that collects data and forecasts trends in popular genres, the library can make informed decisions on which books to purchase. This ensures that the library's collection stays up-to-date and aligns with the reading interests of the community, ultimately leading to increased patron satisfaction and engagement.

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By purchasing software that gathers data and predicts trends in the most popular genres, the library can make informed decisions when acquiring new books.

This approach ensures that the library's collection remains up-to-date and relevant to the interests of its patrons, ultimately increasing the likelihood that people will read the selected books. Furthermore, this software eliminates the need for extra programming, saving time and resources.Such data-driven decisions also allow the library to maximize its budget, as it can focus on purchasing titles that are more likely to be borrowed and enjoyed by the community. Additionally, understanding trends in popular genres can assist the library in creating targeted promotions and events, further engaging patrons and fostering a love for reading.In summary, utilizing software that gathers data and predicts trends in popular genres is an efficient and cost-effective way for a library to maintain a relevant and engaging collection. This approach benefits both the library and its patrons by ensuring a diverse and appealing selection of books that cater to the community's interests.

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a concentric tube heat exchanger having an area of 100 m2 is used to heat 5 kg/s of water that enters the heat exchanger at 50oc. the heating fluid is oil having a specific heat of 2.1 kj/kg and a flow rate of 8 kg/s. the oil enters the exchanger at 100oc and the overall heat transfer coefficient is 120 w/m2k. calculate the exit temperature of the oil and the heat transfer if the exchanger operates in a counterflow mode

Answers

In a concentric tube heat exchange with an area of 100 m2, 5 kg/s of water enters at 50°C and is heated by oil with a specific heat of 2.1 kJ/kg and a flow rate of 8 kg/s. The oil enters the exchanges at 100°C, and the overall heat transfer coefficient is 120 W/m2K. Given that the exchange operates in counter flow mode, we can calculate the exit temperature of the oil and the heat transfer.

First, let's determine the heat transfer rate (Q) using the formula Q = m_water * c_water * (T_out_water - T_in_water), where m_water is the mass flow rate of water, c_water is the specific heat of water (4.18 kJ/kgK), and T_out_water and T_in_water are the outlet and inlet temperatures of water, respectively.
Since Q = m_oil * c_oil * (T_in_oil - T_out_oil), we can solve for T_out_oil: T_out_oil = T_in_oil - (Q / (m_oil * c_oil)).
The overall heat transfer coefficient (U) can be used to calculate Q: Q = U * A * ΔT_lm, where A is the heat exchanger area and ΔT_lm is the log mean temperature difference. For counterflow, ΔT_lm = [(T_in_oil - T_out_water) - (T_out_oil - T_in_water)] / ln((T_in_oil - T_out_water) / (T_out_oil - T_in_water)).
By solving the above equations simultaneously, we can determine the exit temperature of the oil and the heat transfer rate (Q). The resulting values will provide insight into the efficiency and performance of the concentric tube heat exchanger operating in counterflow mode.

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a parallel rlc circuit contains a resistor r = 1 ω and an inductor l = 2 h. select the value of the capacitor so that the circuit is critically damped

Answers

To design a critically damped parallel RLC circuit with a resistor R = 1Ω and an inductor L = 2H, you need to select the value of the capacitor C according to the following formula: C = 1 / (4 * R * L) Plug in the values for R and L: C = 1 / (4 * 1 * 2) C = 1 / 8 So, you need to select a capacitor with a value of 1/8 F (0.125 F) for the circuit to be critically damped.

To calculate the value of the capacitor required to make the parallel RLC circuit critically damped, we need to use the formula for the damping ratio, which is given by: ζ = R / (2√(L/C)) where R is the resistance, L is the inductance, C is the capacitance, and ζ is the damping ratio. For critically damped behavior, ζ = 1, which means: 1 = R / (2√(L/C)) Substituting the given values of R = 1 Ω and L = 2 H, we get: 1 = 1 / (2√(2/C)) Squaring both sides and rearranging, we get: C = 8/9 F Therefore, the value of the capacitor required to make the parallel RLC circuit critically damped is 8/9 F.

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To make a parallel RLC circuit critically damped, the value of the capacitor should be chosen so that the damping factor is equal to 1. In a parallel RLC circuit, the damping factor can be calculated using the formula:

damping factor = R / (2 * √(L * C))

Given that R = 1 Ω and L = 2 H, we can rearrange the formula to find the value of the capacitor (C):

C = (R^2) / (4 * L)

Plugging in the values, we get:

C = (1^2) / (4 * 2) = 1 / 8

Therefore, the value of the capacitor needed for the circuit to be critically damped is C = 1/8 F (farads).

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During useful life period, the reliability at mean time to failure (MTTF) is 0. 368, during wear out part of the life studied using Weibull model, when would one observe same reliability?

Answers

Assuming a shape parameter of = 2, the dependability at the same MTTF during the wear-out phase would be noticed at a time of roughly 0.211 time units. The time at which the same reliability is seen will, however, differ if the form parameter is altered.

How to explain the information

We can leverage the correlation between the MTTF and the Weibull distribution's scale parameter as follows:

MTTF = η * Γ(1 + 1/β)

where gamma is the function.

We can use the following method to solve for the scale parameter given the MTTF of 0.368:

η = MTTF / Γ(1 + 1/β)

Assuming a shape parameter of = 2 (which translates to a constant failure rate), the following results are obtained:

η = 0.368 / Γ(1 + 1/2) = 0.368 / Γ(3/2) ≈ 0.211

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when ben increases the temperature difference between two junctions, the voltage also increases. what type of variable is voltage in the above situation?

Answers

Voltage is a dependent variable in the above situation.

In the given situation, the independent variable is the temperature difference between two junctions, and the dependent variable is the voltage produced. As Ben increases the temperature difference, the voltage also increases, which means the voltage is dependent on the temperature difference.

In this case, voltage is not being directly controlled or manipulated by Ben but instead, it is being measured and observed as a result of the changes in temperature.

Therefore, voltage is a dependent variable. It is important to identify and understand the dependent variable in an experiment or situation to make meaningful conclusions and analyze the relationship between the independent and dependent variables.

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the tensile strength for a certain steel wire is 3000 mn/m2. what is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this kind of steel?

Answers

The maximum load that can be applied to a 3.0 mm diameter steel wire with a tensile strength of 3,000 MN/m² is approximately 21.21 kN.

To determine the maximum load that can be applied to a 3.0 mm diameter steel wire with a tensile strength of 3,000 MN/m², follow these steps:

1. First, we need to find the cross-sectional area of the wire. The wire is circular, so the formula for the area (A) is A = π × (d/2)², where d is the diameter.

2. Plug in the diameter: A = π × (3.0 mm / 2)² ≈ 7.07 mm². This is the cross-sectional area of the wire.

3. Now, we'll use the tensile strength (σ) formula to find the maximum load (F): σ = F / A.

4. Rearrange the formula to solve for F: F = σ × A.

5. Plug in the tensile strength (σ = 3,000 MN/m²) and the cross-sectional area (A = 7.07 mm²) into the formula: F = 3,000 MN/m² × 7.07 mm².

6. Convert the area from mm² to m² by multiplying by 1 x 10⁻⁶: F = 3,000 MN/m² × 7.07 x 10⁻⁶ m².

7. Calculate the maximum load: F ≈ 21.21 kN.

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the inner edge of a drip should be at least ____ from the face of the wall.

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The inner edge of a drip should be at least 2 inches (50 mm) from the face of the wall.

The inner edge of a drip should be at least 40mm (1.5 inches) from the face of the wall.A drip is a small projection or groove in a horizontal surface, such as the underside of a windowsill or the top of a chimney, that is designed to prevent water from flowing back into the building. The inner edge of the drip should be positioned far enough away from the face of the wall to ensure that water does not penetrate the wall or cause damage to the building envelope.In many building codes and standards, a minimum distance of 40mm (1.5 inches) is specified for the placement of drips. However, the exact distance may vary depending on the specific design and construction of the building.

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lateral buckling is inhibited by the rigid frame action of the arches and the horizontal elements linking the two arches to each other. b. roll-thru buckling is partly inhibited by the combined effect of the angled suspenders and the deadweight of the roadbed. c. roll-thru buckling is partly inhibited by the road bed, which attaches to the arch at about the quarter points of the arch. d. tension elements in the roadbed are all the horizontal force required to achieve full arch action over the full length of the arches. e. roll-through buckling is inhibited by the rigid frame action of the arches and the horizontal elements linking the two arches to each other.

Answers

Lateral buckling is inhibited by the rigid frame action of the arches and the horizontal elements linking the two arches to each other. This provides stability and support for the structure.

Roll-thru buckling is partly inhibited by the combined effect of the angled suspenders and the deadweight of the roadbed, as well as by the roadbed attaching to the arch at about the quarter points of the arch. This attachment helps distribute the load and prevent buckling. Tension elements in the roadbed provide the horizontal force required to achieve full arch action over the full length of the arches, ensuring stability. Finally, roll-through buckling is also inhibited by the rigid frame action of the arches and the horizontal elements linking the two arches to each other, maintaining the overall structural integrity.

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The statement that best describes the buckling mechanisms of an arch bridge is e. roll-through buckling is inhibited by the rigid frame action of the arches and the horizontal elements linking the two arches to each other.

Arch bridges are designed to support loads primarily through axial compression forces. However, they are also susceptible to different types of buckling under certain loading conditions. Roll-through buckling is one of the most critical types of buckling in arch bridges, where the arch rolls or twists laterally due to insufficient lateral bracing, resulting in instability and possible collapse.To inhibit roll-through buckling, arch bridges typically incorporate horizontal elements that link the two arches, creating a rigid frame action that can resist lateral forces. The angled suspenders also provide additional bracing to reduce the lateral displacement of the arches. In contrast, tension elements in the roadbed primarily resist the vertical forces that act on the bridge, such as the weight of the traffic and the weight of the bridge itself.In summary, the rigid frame action of the arches and the horizontal elements linking the two arches together are critical factors that inhibit roll-through buckling in an arch bridge.

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Scrum masters help remove impediments, foster an environment for high-performing team dynamics and what else?
- Relentlessly improve
- Continuously deliver
- Form and re-form teams
- Estimate stories

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Scrum Masters not only help remove impediments and foster an environment for high-performing team dynamics, but they also facilitate the team's ability to relentlessly improve and continuously deliver.

In addition, Scrum Masters are responsible for forming and re-forming teams as needed, as well as facilitating the team's ability to estimate stories accurately.
Scrum Masters help remove impediments, foster an environment for high-performing team dynamics, relentlessly improve, and continuously deliver. They facilitate the team's progress by addressing obstacles, promoting an environment that encourages collaboration and growth, working to constantly enhance the team's performance, and ensuring the consistent delivery of high-quality products.

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Scrum Masters play a crucial role in Agile project management by ensuring that the Scrum framework is properly followed and that the team is continuously improving. Apart from helping remove impediments and fostering high-performing team dynamics, Scrum Masters also:


1. Facilitate key Scrum events: Scrum Masters ensure that daily stand-ups, sprint planning, sprint review, and sprint retrospective meetings run smoothly and effectively.

2. Collaborate with Product Owners: They work closely with Product Owners to create, maintain, and prioritize the product backlog, ensuring that the team has a clear understanding of the project's goals.

3. Coach and mentor team members: Scrum Masters provide guidance and support to the team, helping them develop Agile skills and adopt best practices.

4. Protect the team from external interruptions: They shield the team from outside distractions, allowing them to focus on the tasks at hand.

5. Promote continuous improvement: Scrum Masters facilitate the process of inspecting and adapting, ensuring that the team learns from their experiences and constantly improves their performance.

6. Track and communicate progress: They monitor the team's progress, using metrics such as burndown charts and velocity, and keep stakeholders informed about the project's status.

7. Ensure quality and value delivery: Scrum Masters help the team maintain high standards of quality and ensure that the product increments delivered are aligned with customer needs.

In summary, Scrum Masters are essential for guiding and supporting Agile teams, ensuring that they work effectively within the Scrum framework and deliver valuable, high-quality products.

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The plaintiff properly filed an action in federal district court for breach of a partnership agreement. At the conclusion of the presentation of the evidence to the jury by both parties, the defendant filed a motion for judgment as a matter of law, contending that the evidence was insufficient as a matter of law to establish the existence of a partnership. The judge denied this motion. After the jury rendered a verdict in favor of the defendant, the plaintiff filed a motion for judgment as a matter of law 25 days after the entry of the judgment.
Should the court grant the plaintiff's motion?
Answers:
A. No, because the plaintiff did not file a motion for judgment as a matter of law prior to the submission of the case to the jury.
B. No, because the motion was not filed within 10 days of the entry of the judgment.
C. Yes, because the defendant filed a motion for judgment as a matter of law at the conclusion of the presentation of the evidence to the jury by both parties.
D. Yes, because the court rejected the defendant's motion for judgment as a matter of law at the conclusion of the presentation of the evidence.

Answers

Yes, because the court rejected the defendant's motion for judgment as a matter of law at the conclusion of the presentation of the evidence.

The plaintiff properly filed an action in federal district court for breach of a partnership agreement. At the conclusion of the presentation of the evidence to the jury by both parties, the defendant filed a motion for judgment as a matter of law, contending that the evidence was insufficient as a matter of law to establish the existence of a partnership. The judge denied this motion. After the jury rendered a verdict in favor of the defendant, the plaintiff filed a motion for judgment as a matter of law 25 days after the entry of the judgment.

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True or false: a rock becomes permanently deformed when even a small amount of stress is applied to it.

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False. A rock does not become permanently deformed when a small amount of stress is applied to it. Rocks can undergo elastic deformation, which means they can deform under stress but return to their original shape once the stress is removed.

Only when the stress exceeds the rock's strength will it undergo plastic deformation, resulting in permanent deformation.
True or false: a rock becomes permanently deformed when even a small amount of stress is applied to it.
Your answer: False. A rock does not become permanently deformed when only a small amount of stress is applied to it. Rocks can often withstand small amounts of stress without undergoing permanent deformation. Permanent deformation usually occurs when a rock is subjected to significant stress over a long period of time or under extreme conditions.

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The given statement is False.

A rock does not become permanently deformed when a small amount of stress is applied to it. Rocks have varying degrees of strength and elasticity, which determine how they respond to stress. When stress is applied to a rock, it may deform elastically, meaning it temporarily changes shape but can return to its original shape once the stress is removed.

However, if the stress is applied beyond the rock's elastic limit, it may undergo plastic deformation, meaning it changes shape permanently.The amount of stress required to cause plastic deformation varies depending on the type of rock and its physical properties. For example, some rocks such as granite are strong and brittle, meaning they have a high elastic limit and are likely to undergo brittle failure when they reach their limit. Other rocks, such as shale, are weaker and more ductile, meaning they can undergo significant plastic deformation before breaking.In summary, the statement that a rock becomes permanently deformed when even a small amount of stress is applied to it is false. Rocks have different strengths and elasticities, and the amount of stress required to cause permanent deformation varies depending on the type of rock and its physical properties.

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most cpt procedures and services are classified as what kind of codes

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Most CPT (Current Procedural Terminology) procedures and services are classified as numeric codes. These codes are used to accurately document and report medical, surgical, and diagnostic procedures and services provided by healthcare professionals.

Most CPT® codes fall under Category I. These are examples of commonly utilised current services or practises that have, when necessary, received FDA approval. There are very few exceptions to the rule when it comes to Category I codes, which are normally represented by five numeric characters. Codes that have been resequenced cause one difference from the expected order. The AMA "clusters" relevant codes together so that medical coders can easily access them and make appropriate code selections. When a new code is added to a family of codes but a sequential number is not available, a resequenced code results.

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Hi!

Most CPT (Current Procedural Terminology) procedures and services are classified as Category I codes. These codes represent procedures, services, and medical practices commonly performed by healthcare providers for patient care.

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with common control wiring, the power source for the control circuit is separate from the power circuit wiring. true or false?

Answers

It is true that with common control wiring, the power source for the control circuit is separate from the power circuit wiring. The reason for this is to ensure that the control circuit and the power circuit are kept separate to prevent any interference or damage.

In common control wiring, the power source for the control circuit is separate from the power circuit wiring. This separation is important to maintain the safety and functionality of the system.  The control circuit, which manages the operation of devices like switches and relays, requires a lower voltage compared to the power circuit wiring that delivers the main electrical power to equipment or loads. It is used to send signals to various components to control their functions, while the power circuit is responsible for providing the necessary power to operate the equipment.

By keeping these two circuits separate, any potential issues with the control circuit will not affect the power circuit, ensuring that the equipment continues to function as intended. Additionally, separating the control circuit from the power circuit wiring also helps to ensure the safety of the operators and anyone else working with or around the equipment.

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True. With common control wiring, the power source for the control circuit is separate from the power circuit control wiring. This is important for safety and to ensure that the control circuit is not affected by any issues or fluctuations in the power circuit.

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why can the compliance and stiffness tensors for cubic and orthotropic materials be greatly simplified from the general case?

Answers

The compliance and stiffness tensors for cubic and orthotropic materials can be greatly simplified from the general case because these materials have specific symmetry properties that allow for certain components of the tensors to be equal to each other or even zero

For example, in cubic materials, all three axes have equal stiffness and compliance, so only one value needs to be specified for each. In orthotropic materials, there are three mutually perpendicular planes of symmetry, which greatly reduces the number of independent components in the tensors. This simplification makes it easier to model and analyze the mechanical behavior of these materials. The compliance and stiffness tensors for cubic and orthotropic materials can be greatly simplified from the general case because these materials exhibit symmetry in their properties. In both cubic and orthotropic materials, the mechanical properties are directionally dependent, but they follow specific patterns.For cubic materials, the properties are isotropic within the three mutually perpendicular planes, while in orthotropic materials, the properties are isotropic within each of the three orthogonal planes. This symmetry allows for a reduced number of independent constants, simplifying the tensors and making them easier to work with in engineering applications.

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The compliance and stiffness tensors for cubic and orthotropic materials can be greatly simplified from the general case due to the specific symmetries present in these materials.

Cubic and orthotropic materials have symmetry in their elastic properties, which allows for a reduction in the number of independent elastic constants. In the general case, anisotropic materials have 21 independent constants in their stiffness tensor. However, cubic materials have only 3 independent constants, while orthotropic materials have 9 independent constants.

This simplification arises because the symmetry of cubic and orthotropic materials leads to specific relationships between the elastic constants. These relationships reduce the complexity of the compliance and stiffness tensors, allowing for easier analysis and calculation of material properties.

In summary, the compliance and stiffness tensors for cubic and orthotropic materials can be greatly simplified from the general case due to the symmetry in their elastic properties, which reduces the number of independent elastic constants.

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the arc definition and chord definition are preferred for--------------- and-----------------work respectively.

Answers

The arc definition is preferred for surveying work, and the chord definition is preferred for engineering work.

The arc definition of an angle is based on the length of the arc on a circle intercepted by the angle, while the chord definition is based on the length of the chord connecting the two endpoints of the arc. In surveying, measurements are made over long distances, and the arc definition is more accurate due to the curvature of the Earth.

The arc definition is also preferred in geodesy, which deals with the measurement and representation of the Earth. In engineering, however, measurements are typically made over shorter distances, and the chord definition is preferred because it is simpler and easier to work with.

The chord definition is also useful in trigonometry, where the chord of an angle is used to define trigonometric functions such as sine and cosine.

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what is the basic equation that we need to solve to get the temperature out of heat flux loading conditions? provide any journal reference to any equations you type.

Answers

The basic equation used to determine temperature from heat flux under steady-state conditions is the Fourier's Law equation, which can be rearranged to solve for temperature at a certain point in a material when the heat flux and material properties are known.

What is the equation used to determine temperature from heat flux loading conditions and can you provide a journal reference to it?

The basic equation used to determine temperature from heat flux under steady-state conditions is the Fourier's Law equation:

q = -kA(dT/dx)

where:

q is the heat flux (W/m²)

k is the thermal conductivity (W/mK)

A is the cross-sectional area perpendicular to the direction of heat flow (m²)

dT/dx is the temperature gradient (K/m)

To solve for temperature, the equation can be rearranged to:

dT/dx = -(q / kA)

Integrating both sides of the equation with respect to x gives:

(T2 - T1) = -(q / kA) * L

where:

T1 and T2 are the temperatures at two points along the direction of heat flow (K)

L is the distance between those two points (m)

Solving for T2, we get:

T2 = T1 - (q / kA) * L

This equation can be used to calculate the temperature at a certain point in a material when the heat flux and material properties are known.

As for a journal reference, one example is the paper "Numerical Analysis of Heat Flux and Temperature Distribution on the Tool Surface in Friction Stir Welding" by M. Mazumder, S. Saigal, and S. Basu, published in the Journal of Manufacturing Processes (2017). The paper describes the use of Fourier's Law to analyze the heat flux and temperature distribution in friction stir welding.

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Which of the following distinguishes how geothermal power can be used as an alternative energy source? A family relies on a ground-source heat pump to stay warm during winter. A family relies on a ground-source heat pump to stay warm during winter. A riverside power plant employs turbines to create electricity. A riverside power plant employs turbines to create electricity. A botanist uses mirrored panels to absorb and reflect sunlight onto plants. A botanist uses mirrored panels to absorb and reflect sunlight onto plants. A man drives an electric car and recharges it when necessary. A man drives an electric car and recharges it when necessary.

Answers

Answer:    .

Explanation:      

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