Given data
*A vector starts with a point is P = (-3, 4)
*A vector ends with a point is Q = (6, -3)
The formula for the magnitude of the vector PQ is given as
[tex]\lvert\vec{PQ}\rvert=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \lvert\vec{PQ}\rvert=\sqrt[]{(6-(-3))^2+(-3-4)^2} \\ =\sqrt[]{(9)^2+(-7)^2} \\ =\sqrt[]{81+49} \\ =\sqrt[]{130} \\ =11.40 \end{gathered}[/tex]Please help me
how law of motion applied in tug of war game need step by step explanation
Newtons law- For every action, there is a reaction
The first team to tug is the action force, causing the pull on the rope, as the reaction force, the other team's rope end feels the pull.
When two teams are pulling in opposite directions, the movement of the rope (as calculated by Newton's second law) will be determined by the net force on the rope.
6) Find the speed a spherical raindrop would attain by falling from 4.00 km. Do this:a) In the absence of air dragb) In the presence of air dragc) Assume that the diameter of the drop is 3 mm and the density of the water is 0.98x10^3 kg/m^3
We are asked to determine the velocity of a rain drop if it falls from 4 km.
To do that we will use the following formula:
[tex]2ah=v_f^2-v_0^2[/tex]Where:
[tex]\begin{gathered} a=\text{ acceleration} \\ h=\text{ height} \\ v_f,v_0=\text{ final and initial velocity} \end{gathered}[/tex]If we assume the initial velocity to be 0 we get:
[tex]2ah=v_f^2[/tex]The acceleration is the acceleration due to gravity:
[tex]2gh=v_f^2[/tex]Now, we take the square root to both sides:
[tex]\sqrt{2gh}=v_f[/tex]Now, we substitute the values:
[tex]\sqrt{2(9.8\frac{m}{s^2})(4000m)}=v_f[/tex]solving the operations:
[tex]280\frac{m}{s}=v[/tex]Therefore, the velocity without air drag is 280 m/s.
Part B. we are asked to determine the velocity if there is air drag. To do that we will use the following formula:
[tex]F_d=\frac{1}{2}C\rho_{air}Av^2[/tex]Where:
[tex]\begin{gathered} F_d=drag\text{ force} \\ C=\text{ constant} \\ \rho_{air}=\text{ density of air} \\ A=\text{ area} \\ v=\text{ velocity} \end{gathered}[/tex]We need to determine the drag force. To do that we will use the following free-body diagram:
Since the velocity that the raindrop reaches is the terminal velocity and its a constant velocity this means that the acceleration is zero and therefore the forces are balanced:
[tex]F_d=mg[/tex]Now, we determine the mass of the raindrop using the following formula:
[tex]m=\rho_{water}V[/tex]Where:
[tex]\begin{gathered} \rho_{water}=\text{ density of water} \\ V=\text{ volume} \end{gathered}[/tex]The volume is the volume of a sphere, therefore:
[tex]m=\rho_{water}(\frac{4}{3}\pi r^3)[/tex]Since the diameter of the raindrop is 3 millimeters, the radius is 1.5 mm or 0.0015 meters. Substituting we get:
[tex]m=(0.98\times10^3\frac{kg}{m^3})(\frac{4}{3}\pi(0.0015m)^3)[/tex]Solving the operations:
[tex]m=1.39\times10^{-5}kg[/tex]Now, we substitute the values in the formula for the drag force:
[tex]F_d=(1.39\times10^{-5}kg)(9.8\frac{m}{s^2})[/tex]Solving the operations:
[tex]F_d=1.36\times10^{-4}N[/tex]Now, we substitute in the formula:
[tex]1.36\times10^{-4}N=\frac{1}{2}C\rho_{air}Av^2[/tex]Now, we solve for the velocity:
[tex]\frac{1.36\times10^{-4}N}{\frac{1}{2}C\rho_{air}A}=v^2[/tex]Now, we substitute the values. We will use the area of a circle:
[tex]\frac{1.36\times10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^3})(\pi r^2)}=v^2[/tex]Substituting the radius:
[tex]\frac{1.36\cdot10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^{3}})(\pi(0.0015m)^2)}=v^2[/tex]Solving the operations:
[tex]70.67\frac{m^2}{s^2}=v^2[/tex]Now, we take the square root to both sides:
[tex]\begin{gathered} \sqrt{70.67\frac{m^2}{s^2}}=v \\ \\ 8.4\frac{m}{s}=v \\ \end{gathered}[/tex]Therefore, the velocity is 8.4 m/s
Which two forces will cause the same rate of change in the stick's angular momentum as each other.
Given:
The stick is attached to a pivot at the right end.
The four forces are,
[tex]40\text{ N, 60 N, 30 N, 150 N}[/tex]Any one of the forces can act on that stick at a time.
To find:
Which two forces will cause the same rate of change in the stick's angular momentum
Explanation:
Let the length of each space be x.
To produce the same rate of change in angular momentum, the forces should produce the same torque.
The torque produces by the force,
[tex]40\text{ N}[/tex]is,
[tex]\begin{gathered} 40\times4x\text{ \lparen the distance of this force from the right end is 4x\rparen} \\ =160x \end{gathered}[/tex]Similarly, the torque by 60 N force is,
[tex]\begin{gathered} 60\times3x \\ =180x \end{gathered}[/tex]by 30 N force is,
[tex]\begin{gathered} 30\times2x \\ =60x \end{gathered}[/tex]by 150 N force is,
[tex]150x[/tex]Here, we see all the torques are different from each other.
Hence, they all are different.
You have an unknown substance with a mass of
40 g and a volume of 100 cm³.
What is its density?
Will it sink or float in water?
The main characteristics used to classify stars include all of the following EXCEPT:A. shape.B. brightnessC. colorD. temperature
From the given list of choices, let's select the characteristic that cannot be used to classify stars.
Stars can be said to be self-luminous bodies of gas which shines by radiation gotten from its internal energy sources.
Stars can be classified using five properties:
0. Color
,1. Temperature
,2. Size
,3. Composition
,4. Nature of brightness
Therefore, the characteristic that cannot be used to classify a star is its shape.
All stars look spherical due to their gravitational properties.
ANSWER:
A. Shape
A voice that is audible cannot be easily heard. True or false
Given
A voice that is audible cannot be easily heard.
To find
Whether the given statement is true or false
Explanation
The sounds which a person can hear is known as audible. So the voice that is audible is easily heard.
Conclusion
The given statement is false
A motorcycle moving at 18 m/s decelerates at a rate of 3.6 m/s². What is the car's
velocity 4 seconds later?
Answer:
V = 3.6 m/s
Explanation:
Given:
V₀ = 18 m/s
a = - 3,6 m/s² (The motorcycle is slowing down!)
t = 4 s
____________
V - ?
Motorcycle speed:
V = V₀ + a·t
V = 18 + (-3.6)·4 = 3.6 m/s
You walk exactly 250 steps North, turn around, and then walk exactly 400 steps South. How far are you from your starting point?
150 steps
Explanation
to find the final position, we need to add the vectors of displacement
Step 1
Diagram:
Step 2
now, we need to add the vectors
a)let the vectors
U= vector from the start point to the place where he turns around
v= vector from point B to end point
[tex]\begin{gathered} U=\langle0i+250j\rangle \\ v=\langle0i-400j) \end{gathered}[/tex]so, to find the final position we need to add the vectors, component to component
so
[tex]\begin{gathered} U+v=(0i+0i,250j-400j) \\ U+v=\langle0,-150\rangle \end{gathered}[/tex]so, the final position is -150, the negative sign indicates the direction (south) and the magnitud indicates the distance
so, you are 150 steps from your starting point
I hope this helps you
When we ride a bike, do we actually move the earth, but not enough for the human eye to see?
Answer: Yes, we do move the earth
Explanation: When we ride a bike, we exert a force on the earth, and the earth in turn pushes us forward, which is what propels us. The force that we exert on the earth does move the earth by a very small amount. Newton's third law of motion states exactly this.
Which of the following statements are correct?A.gamma rays travel faster than x-rays B.red light has a higher frequency than violet light C.Ultraviolet light and infrared light have the same frequency D.radio waves travel at the same speed as gamma rays
(A). The gamma rays and x-rays are the electromagnetic rays. The speed of the electromagnetic rays is constant.
[tex]c=3\times10^8ms^{-1}[/tex]Thus, the gamma rays and x-rays have the same speed.
Hence, option A is incorrect.
(B). The wavelength of the red light is larger than the wavelength of the violet light.
The frequency of light in terms of the wavelength is,
[tex]f=\frac{c}{\lambda}[/tex]where f is the frequency, c is the speed of light and
[tex]\lambda\text{ is the wavelength}[/tex]As the frequency is inversely propotional to the wavelength of light.
For the larger value of wavelength, the value of frequency is smaller and for the smaller value of the wavelength, the value of frequency is larger.
Thus, the frequency of the red light is smaller than the frequency of the violet light.
Hence, option B is incorrect.
(C). The ultraviolet light and infrared light have different value of wavelength.
Thus, the value of the frequency is not same for both the l
In most electric generators, either the armature (the coil of wire) or the magneticfield is ____ generating a(n) __---a) interrupted; impulse changeOb) nonconducting; flux lineOc) turned off; temporary dipoled) rotated; induced current
Answer:
d) rotated; induced current
Explanation:
The force exerted by gravity on a whole brick is greater than the force exerted bygravity on half a brick. Why, then, doesn't a whole brick fall faster than half a brick?
The force exerted by gravity on a whole brick is greater than the force exerted by gravity on half a brick.
They hit the ground at the same time because they fall at -9.81m/s^2.
What is force ?The definition of force is: The push or pull on a mass object causes it to change velocity. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.The term "force" has a specific meaning. At this level, it is perfectly acceptable to refer to a force as a push or a pull. A force is not something that an object 'has in it.' Another object applies a force to another. The concept of a force is not limited to living or nonliving things.According to Newton's Law F = ma. where m is mass of the object, a is acceleration.
so,
The force exerted by gravity on a whole brick is greater than the force exerted by gravity on half a brick.
They hit the ground at the same time because they fall at -9.81m/s^2.
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A point charge of −3μC is locatedat the center of a sphere with a radius r=5cm. What is the net electric flux through the surface?short answer pls asap
Given:
The total charge enclosed by the surface of the sphere, q=-3 μC
The radius of the sphere, r=5 cm=5×10⁻² m
To find:
The net electric flux through the surface of the sphere.
Explanation:
From Gauss's law, the net electric flux through the surface of the sphere is given by,
[tex]\phi=\frac{Q}{\epsilon_0}[/tex]Where ε₀ is the permittivity of free space.
On substituting the known values,
[tex]\begin{gathered} \phi=-\frac{3\times10^{-6}}{8.85\times10^{-12}} \\ =339\times10^3\text{ Nm}^2\text{/C} \end{gathered}[/tex]Final answer:
The net flux through the surface of the sphere is 339×10³ Nm²/C
Equilibrium Attained Net Force = 0 NewtonsDraw a free body diagram with a 10 N force and a 25 Newton force acting on an object in the opposite directions. Describe the additional force needed to be applied to achieve equilibrium.
Explanation:
There are two forces acting on the object in opposite directions.
The sketch of the two forces is
since the force acting towards the left is greater than the force acting on the right, the object will accelerate towards the left.
Now, how much force is required to counter 25 N acting on the left?
The answer is, if we apply an additional 15 N towards the right, the total force acting in this direction is 10 + 15 = 25 N, which is enough to counter 25 N acting towards the left.
Therefore, we need to apply an additional 15 N in the direction of the 10 N force.
What is the kinetic energy of a 200 kg object that is moving at a velocity of 15 m/s?3000 Jb30,0000 Jc215 Jd2150 J
22500 Joules
Explanation
Kinetic energy is a form of energy that an object or a particle has by reason of its motion and mass ,
[tex]E_k=\frac{1}{2}mv^2[/tex]
where m is the mass of the object and v the velocity
Step 1
a)Let
[tex]\begin{gathered} m=200\text{ Kg} \\ v=15\frac{m}{s} \end{gathered}[/tex]now, replace
[tex]\begin{gathered} E_k=\frac{1}{2}mv^2 \\ E_k=\frac{1}{2}(200\text{ kg\rparen\lparen15}\frac{m}{s})^2 \\ E_k=\frac{1}{2}*45000\text{ Joules} \\ E_k=22500\text{ Joules} \end{gathered}[/tex]so, the answer is 22500 Joules
I hope this helps you
A solid cube is submerged in a container of water of density p,. The cube has mass M, volume Vc, and density ½pw. The water exerts an upward buoyant force on the cube of magnitude PwVcg. Which of the diagrams is the best representation of the forces exerted by the water on the cube?
ANSWER:
STEP-BY-STEP EXPLANATION:
We have that the density of the cube is less than the density of water.
Which means that naturally the cube will float, so if it is immersed in water, the upward force will be greater than the downward push.
The diagram that represents a greater force upwards than downwards is the diagram for option C, so the correct option is option C.
Note: Fig
The figure above shows the forces exerted on a block that is sliding on a rough horizontal surface: The weight of the block is 500 N, the normal force is 500 N, the frictional force is 100 N, and there is an unknown force F exerted to the right. The acceleration of the block is .4m/s^2. The value of F is most nearly
A) 20 N
B) 80 N
C) 110 N
D) 120 N
The force 'F' on the block is equal to 120 N. Therefore, option D is correct.
What is frictional force?The frictional force is described as the force formed by two surfaces that slide against each other. The frictional force is affected by the texture of the surface, the angle, as well as the position of the object.
Friction can be defined as the force that resists motion when one surface comes in contact with the other surface. The mechanical advantage will reduce by the force of friction therefore the ratio of output to input will be reduced because of friction.
The formula of the frictional force can be represented as:
F = μmg
Given, the weight of the block, W = 500 N
W = mg
500 = m × 9.8
m = 51 Kg
The acceleration of the block, a = 0.4 m/s²
The frictional force of the block, F = 100 N
F(net) = F (applied) - F (frictional)
ma = F - 100
51 ×0.4 = F - 100
F = 100 + 20.4
F = 120.4 N
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A position versus time graph is shown below.
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. A line connects points 0, 0 and 1, 4. A horizontal line connects points 1, 4 and 4, 4. A line connects points 4, 4 and 6, 10. A horizontal line connects points 6, 10 and 8, 10. A line connects 8, 10 and 9, 14, and then 10, 15.
Use the graph to determine the instantaneous velocity in m/s of the object at 7 seconds.
0 m/s north
1.4 m/s north
7 m/s north
10 m/s north
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. The instantaneous velocity in m/s of the object at 7 seconds is 0 m/s north.
What is instantaneous velocity?
Instantaneous velocity, often known as the time derivative of position, is the rate of change (slope) of the position function.
[tex]v=\dot{s}=\frac{ds}{dt}[/tex]
The limit of the average velocity as time approaches 0, or the derivative of x with respect to t, is the instantaneous velocity of an object.
A Position versus Time graph is shown with y-axis labeled position in meters north up to 20 and x-axis labeled time in seconds up to 10. A line connects points 0, 0 and 1, 4. A horizontal line connects points 1, 4 and 4, 4. A line connects points 4, 4 and 6, 10. A horizontal line connects points 6, 10 and 8, 10. A line connects 8, 10 and 9, 14, and then 10, 15.
Use the graph we determine the instantaneous velocity in m/s of the object at 7 seconds is 0 m/s .
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Answer:
the answer is 7m/s north
Explanation:
I took the quiz
A certain transformer doubles input voltage. If the primary coil has 10 A of current, then the current in the
secondary coil is
O 25 A.
O 5 A.
O none of the above
O 2A.
O 10 A.
According to the given statement then the current in the secondary coil is 5A.
The correct option is B.
What does secondary coil in transformer do?Transformers have at least two windings or coils, as seen in the experiment above. The primary is referred to as such, and the secondary as such. AC electricity enters the primary coil here. Where the current is induced to carry out any sort of energy transfer is in the secondary coil.
Briefing:According to the question,
Current in primary coil, I[tex]_i_n[/tex] = 10A
Power = V[tex]_i_n[/tex]I[tex]_i_n[/tex] = V[tex]_o_u_t[/tex]I[tex]_o_u_t[/tex]
Then
By substituting the values,
V[tex]_i_n[/tex]* 10 =V[tex]_i_n[/tex]I[tex]_o_u_t[/tex]
By applying cross-multiplication,
10 = 2I[tex]_o_u_t[/tex]
I[tex]_o_u_t[/tex] = 10/2
= 5A
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The complete question is -
A certain transformer doubles input voltage. If the primary coil has 10 A of current, then the current in the secondary coil is
A- 25 A.
B- 5 A.
C- none of the above
D- 2A.
E- 10 A.
An object moving with uniform acceleration has a velocity of 13.0 cm/s in the positive x-direction when its x-coordinate is 3.18 cm. If its x-coordinate 2.95 s later is −5.00 cm, what is its acceleration? cm/s2
Given:
The initial velocity of the object is: u = 13 cm/s
The time taken by an object to change the position coordinate is: t = 2.95 s
The change in the position (displacenent) is: Δx = -5 cm - 3.18 cm = - 1.82 cm
To find:
The acceleration of an object.
Explanation:
The acceleration of an object can be determined by using following kinematical equation,
[tex]\Delta x=ut+\frac{1}{2}at^2[/tex]Rearranging the above equation, we get:
[tex]a=\frac{2(\Delta x-ut)}{t^2}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} a=\frac{2\times(1.82\text{ cm}-13\text{ m/s}\times2.95\text{ s\rparen}}{(2.95\text{ s\rparen}^2} \\ \\ a=\frac{2\times(-36.53^\text{ cm})}{8.7025\text{ s}} \\ \\ a=-8.9351\text{ cm/s}^2 \end{gathered}[/tex]Final answer:
The acceleration of an object is -8.9351 cm/s^2.
Which THREE statements are TRUE about mechanical and electromagnetic waves? A In all mechanical waves, the amplitude is the distance from the medium to the crest of the wave. B Particles in mechanical waves can travel perpendicular or parallel to the medium they are traveling throughCSome mechanical waves lack a crest because the particles move parallel to the medium they are traveling through D In electromagnetic waves, a wavelength is determined by measuring the distance between two consecutive cresis EIn electromagnetic waves, a wavelength is determined by measuring the distance between two consecutive compressions
The statements that are true are, Statement B, statement C and statement D.
Not all mechanical waves have crests. Transverse waves have crests and troughs and longitudinal waves have compression and rarefactions. Thus statement A is not true.
Mechanical waves have two main types. In transverse waves, the particles of the wave travel perpendicularly and in longitudinal waves, they travel parallelly. Therefore, statement B is true.
A circus van moves 50 km [E] in the first hour, 40 km [W] in the second hour, and 30 km [N] in the next half hour. Calculate the average velocity of the travelling circus van?
The average velocity of the travelling circus van is 12.64km/h.
As we already know, the directions east[E] and west[W] are opposite to each other, north[N] perpendicular to both of them.
We know, average velocity V,
V = total displacement/total time taken
Let us assume the situation on a coordinate plane, and say that the van started from origin,
The circus van first goes to the east direction and travels 50Km. After that, it travels 40Km back,
So, he travels straight 50Km and then return back 40Km, so now, his current position is 10Km in the east direction,
Now, from the point in 10km east, he travels 30km north,
Now, his current and final position is 10km east and 30km north,
His initial position was 0km in east and 0km in north,
So, his total displacement D is,
D² = (10)²+(30)²
D² = 100+900
D² = 1000
D = 10√10 Km.
Total time T taken by him is,
T = 1+1+.05
T = 2.5 hours,
Putting the values, the average velocity V is,
V = D/T
V = 10√10/2.5
V= 12.64 km/h
So, the average velocity is 12.64km/h.
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A penny is dropped from a building and it takes 7.00 seconds to hit the ground.
What was the penny’s final velocity as it hit the ground?
The final velocity of the pen as it hits the ground is 68.6 meters per seconds.
What is the velocity of the pen as it hits the ground?Velocity is simply the speed at which an object moves in a particular direction.
From the first equation of motion
v = u + gt
Where v is final velocity, u is initial velocity, t is time elapsed and g is acceleration due to gravity ( g = 9.8m/s² )
Given the data in the question;
The pen was initially at rest before the drop, Initial velocity u = 0Elapsed time t = 7.00sFinal velocity v = ?To determine the velocity just before the pen hits the ground, plug the values into the formula and solve for v.
v = u + gt
v = 0 + ( 9.8m/s² × 7.00s )
v = 9.8m/s² × 7.00s
v = 68.6m/s
Therefore, the final velocity is 68.6 meters per seconds.
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order the colors of the darts to show the size of the acceleration each dart will have as it is being thrown
silver
green
red
gold
blue
Explanation:Relationship between force (F), mass (M), and acceleration (a) is:
F = ma
a = F/m
The larger the value of a, the smaller the value of m. The smaller the value of a, the larger the value of m.
Therefore, if the force applied is equal, to arrange the acceleration from the largest to the smallest, we will arrange the mass from the smallest to the largest
silver
green
red
gold
blue
Anyone, help me plss
The acceleration of the given car is 4 m/s² on the Right hand side.
What is meant by velocity?Velocity can be defined as the rate at which something moves in a specific direction.
As the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
Based on the information, one could use the following formula to compute the magnitude of acceleration in this case:
[tex]$a=\frac{V_f-V_i}{t}$$[/tex]
Given:
initial velocity (u): 2m/s
Final velocity (v): 12m/s
Time taken : 2.5 second
we know that,
V = u + at
after putting all the values, we get
a = 4 m/s²
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What acceleration is needed to bring a car that is initially going 65.0 mi/hr to a complete stop in a distance of 57.0 m?
7.41 m/s^2
ExplanationWhen an object is traveling in a straight line with an increase or decrease in velocity at equal intervals of time, then the object is said to be in uniform acceleration
to find the acceleration we can use the formulas
[tex]\begin{gathered} x=v_it+\frac{1}{2}at^2 \\ and \\ v_f=v_1+at \end{gathered}[/tex]so
Step 1
a)
let
[tex]\begin{gathered} initial\text{ velocity}=v_i=65\frac{mi}{h} \\ final\text{ velocity= 0 \lparen complete stop-rest\rparen} \\ distance=57\text{ m=0.0354182 miles} \end{gathered}[/tex]b) replace in equation (2)
[tex]\begin{gathered} v_{f}=v_{1}+at \\ 0=65+at \\ -65=at \\ a=-\frac{65}{t} \end{gathered}[/tex]replace in equation (1)
[tex]\begin{gathered} x=v_{i}t+\frac{1}{2}at^{2} \\ 0.0354182=65t+\frac{1}{2}(-\frac{65}{t})t^2 \\ 0.0354182=65t-\frac{1}{2}(\frac{65}{})t^ \\ 0.0354182=65t-\frac{65}{2}t \\ 0.0354182=t(65-\frac{65}{2}) \\ 0.0354182=t(32.5) \\ t=\frac{0.0354182}{32.5}=0.001089\text{ hours} \end{gathered}[/tex]now, replace in the previous equation to find a
[tex]\begin{gathered} a=-\frac{65}{t} \\ a=-\frac{65\frac{mi}{h}}{0.001089\text{ hours }} \\ a=-59687\text{ }\frac{miles}{hour^2} \end{gathered}[/tex]so, the answer is
[tex]a=-59687.78\frac{m\imaginaryI les}{hour^{2}}[/tex]finally, let's convert the acceleration from miles per squared hour into meters per square second
remember that:
[tex]\begin{gathered} 1\text{ hour = 3600 seconds } \\ 1\text{ miles=1609.34 meters} \end{gathered}[/tex]so
[tex]\begin{gathered} a=-59,687\frac{m\imaginaryI les}{hour^{2}}(\frac{1\text{ hour}}{3600\text{ s}})^2(\frac{1609.34\text{ m}}{1\text{ mile}}) \\ a=-59,687\frac{\text{m}\mathrm{i}\text{les}}{\text{hour\textasciicircum{\text{2}}}}*\frac{1\text{ hour}^2}{12960000\text{s}^2}*(\frac{1609.34\text{ m}}{1\text{ mile}}) \\ a=-7.41\text{ }\frac{m}{s^2} \end{gathered}[/tex]hence
the acceleration is -7.41 m/s^2
I hope this helps you
analyze the motion of an object that has an acceleration of 0 m/s2
If the size of an object is 5.0 cm, and the size of the image formed by a lens is 15.0 cm, what is the magnification of the system?
The magnification of the system is 3.
To calculate the magnification, use the following system: magnification = the height of the photograph ÷ via the peak of the object. Plug your records into the formula and remedy. if your solution is more than 1, that means the photo is magnified. in case our solution is between zero and 1, the image is smaller than the object.
magnification = height of imagect/height of objest
= 15 cm/5 cm
= 3.
A magnification of one (plus or minus) approach that the image is the equal size as the object. If m has a value extra than 1 the photograph is greater than the item, and if an m with significantly much less than 1 way the photo is smaller than the item.
A negative magnification shows that the photograph is inverted. If the object is positioned in the direction of a converging lens than the focal period, the rays on the far side of the lens diverge. by means of extrapolating those traces returned (the red traces) the location of the digital image can be observed.
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A 50.0-g Super Ball traveling at 28.5 m/s bounces off a brick wall and rebounds at 18.0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.00 m/s,what is the magnitude of the average acceleration of the ball during this time interval?m/s
Given data:
*The given mass of the Superball is m = 5.0 g
*The initial speed of the Superball is u = -28.5 m/s
*The ball rebounds at a final speed is v = +18.0 m/s
*The given time is
[tex]t=4.00ms=4.00\times10^{-3}\text{ s}[/tex]Considering the rebound direction is positive
The formula for the magnitude of the average acceleration of the ball during this time interval is given as
[tex]a_{avg}=\frac{v-u}{t}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a_{avg}=\frac{18.0-(-28.5)}{(4.0\times10^{-3})} \\ =11625m/s^2 \end{gathered}[/tex]When a ball is dropped from a rooftop, it might make sense to choose the ground or the release point as the origin of the frame of reference. How do these choices make relevant calculations easier?
A reference point is a location or object that is used for comparison to determine whether or not something is moving. If an object changes position relative to a reference point, it is in motion. Buildings, trees, and signs that are fixed relative to Earth serve as good reference points.
How do you determine a frame of reference?To fully define a reference frame in n dimensions, n + 1 reference points are sufficient. A reference frame can be defined using rectangular Cartesian coordinates, with a reference point at the origin and a reference point one unit distance along each of the n coordinate axes.The ball's motion is independent of the reference frame and is consistent across reference frames.A reference point is a location or object that is used for comparison to determine whether or not something is moving. If an object changes position relative to a reference point, it is in motion. Buildings, trees, and signs that are fixed relative to Earth serve as good reference points.To learn more about : Reference frame
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