After you complete the Rumbleometer traverse in class, and the two graphs at home, answer these questions. Keep your answers short and succinct.
1. The temperature started rising rapidly at _______decimal hours. 2. The numbleometer first started moving upwards at ________ decimal hours.
3. The lava flow first reached the rumbleometer at _______decimal hours. 4. When the eruption was over, the rumbleometer returned to it's pre-eruption depth of 1529.9 meters at ______ decimal hours. 5. The eruption lasted for ____________ decimal hours. (Hint: review questions 3 \& 4.) 6. The water temperature started at _________the water temperature increased by _______degree C and increased to a peak of _______∘C. 7. At 15 hours, the Rumbleometer was at at depeh of_______ m. It reached a minimum depth of m. So the maximum thickness of the lava flow, before drainback, was________ m. 8. The lava erupted at a temperature of 1200∘ Celsius ( −2200∘ Fahrenheit). Why do you think the recorded temperature rose so little? (Be specifict Don't give vague or generic answers.) 9. Did temperatures return to normal (3∘3∘C) right away? ____________Think of a possible explanation for your observation. 10. What happened to the Rumbleometer instrument during the eruption? (Use the terms "lava flow inflation", "lava drainback", "collapse" and "solidification" in your answer - and it's OK to use the past tense version of these terms, so "solidify" becomes "solidified", ete.) 11. Why did the rumbleometer survive and not get completely buried in lava? (Review your answer to question 7, and remember that the entire Rumbleometer was only about a meter high.) Characteristics of deep-sea animal species (Refer to this table during the

Answers

Answer 1

The Rumbleometer was not entirely buried in lava.

1. The temperature started rising rapidly at 5.7 decimal hours.2. The numbleometer first started moving upwards at 4.4 decimal hours.3. The lava flow first reached the rumbleometer at 6.4 decimal hours.4. When the eruption was over, the rumble meter returned to its pre-eruption depth of 1529.9 meters at 15 decimal hours.5. The eruption lasted for 8.8 decimal hours.6. The water temperature started at 3∘C, the water temperature increased by 2∘C and increased to a peak of 5∘C.7. At 15 hours, the Rumbleometer was at a depth of 1529.9 m. It reached a minimum depth of 1353.3 m. So the maximum thickness of the lava flow, before drainback, was 176.6 m.8. The recorded temperature rose so little because of the following reasons: Because there was an increase in temperature. The temperature was increased by 200°C, which is a significant amount of heat. 9. No, temperatures did not return to normal (3°C) right away. A possible explanation for this observation is that the water temperature had increased as a result of the lava flow, so it would take some time for the water to cool down.10. During the eruption, the Rumbleometer instrument went through the following stages: lava flow inflation, lava drainback, collapse, and solidification.11. The Rumbleometer survived and did not get completely buried in lava because the instrument was only about a meter high, and the lava flow that covered it was only about 176.6 meters thick.

Therefore, the Rumbleometer was not entirely buried in lava.

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Related Questions

A sandstone composed entirely of sand can be considered
Group of answer choices
well rounded
well sorted
well weathered
well brecciated

Answers

A sandstone composed entirely of sand can be considered well sorted. So, the correct option is B.

In the context of geology, the term well-sorted refers to sediments or rocks whose grains are of similar size or whose particle size distribution has a low degree of variance. A sandstone is a sedimentary rock composed primarily of sand-sized grains of rock, mineral, or organic material.

Sandstone is formed by the accumulation of sand grains that have been compacted or cemented together by minerals such as silica, iron oxide, or calcium carbonate. If a sandstone is made entirely of sand, it implies that all the grains in the rock are of the same size and do not vary in shape or mineral composition. As a result, this type of sandstone is well sorted. Thus, the correct answer is option B - well sorted.

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There is a lot of debate in the Pacific Northwest whether or not to remove numerous dams that are on the Columbia and Snake Rivers in Oregon, Washington, and Idaho. These dams provide hydroelectricity for over a million people, and also a source of water for crop irrigation in the drier parts of these states. However, water behind the dams also significantly warms up during the summer, reaching temperatures of greater than 22 degrees Celsius (~72 Fahrenheit). Adult salmon species which use the Columbia and Snake rivers to reach their spawning grounds cannot survive for long in waters that have temperatures greater than 21-22 degrees Celsius.

Answers

According to research, the adult salmon species cannot survive for long in waters with temperatures greater than 21-22 degrees Celsius. Removing the dams may help reduce the water temperature behind the barricades to the salmon's suitable level.

The barriers play an essential role in the economy of the Pacific Northwest region. They are the primary source of hydroelectricity for the area, providing electricity to over a million people in the region. The dams are also a water source for crop irrigation in the drier parts of the states mentioned earlier. Removing the barriers will significantly impact the region's economy, including job loss and reduced power and food production. Removing the dams could also increase electricity costs and food prices, as crop irrigation is only possible with the barriers.

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The red line in a Hydrogen spectrum of a star is typically at 656.3 nm. We find that the star is moving away from us at a decently fast speed. Which of the following is most likely to be the wavelength of the red line in Hydrogen in nm?
656.3
700
0
600

Answers

The wavelength of the red line in Hydrogen in nm is 700 nm. When a star moves towards or away from us, its light waves are shifted to shorter or longer wavelengths, respectively. This is called the Doppler Effect.

If a star is moving away from us, its light waves are stretched and their wavelengths increase, leading to a redshift. Conversely, if the star is moving towards us, its light waves are compressed and their wavelengths decrease, leading to a blueshift. In this case, the fact that the star is moving away from us means that the light from the star is redshifted, which means that its wavelength is increased. Therefore, the wavelength of the red line in Hydrogen is longer than its rest wavelength of 656.3 nm.

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Answer ALL THREE parts of this question, giving examples in each:
a) Define paleoecology and its differences from ecology; b) Define the facies concept and Walther’s Law; c) Briefly explain how TROPICAL REEF HABITATS have changed in paleocommunity composition through the Phanerozoic Eon.

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a) Paleoecology studies ancient ecosystems, different from modern ecology. b) The facies concept describes distinct sedimentary characteristics, and Walther's Law states that adjacent facies represent lateral shifts in environments. c) Tropical reef habitats have changed paleocommunity composition throughout the Phanerozoic Eon, from stromatolites in the early Paleozoic to scleractinian corals in the Mesozoic and diverse coral communities in the Cenozoic.

a) Paleoecology is the study of prehistoric organisms and ecosystems in the past. It is different from ecology because ecology mainly studies present-day organisms and their interactions in the current environment. Paleoecology gives a better understanding of the evolution of life on Earth. Ecology is an extension of biology, which is the study of organisms. However, ecology is the study of the interactions of living organisms with each other and with their non-living physical environment.

b) The facies concept involves the recognition of a suite of sedimentary rock units based on their lithologic, paleontologic, and geochemical characteristics. Walther's Law is the principle that states that when lateral environments shift laterally, the sedimentary rock type and the sequence of fossils change correspondingly. Walther's Law helps in understanding the geological past by linking the environment of deposition in adjacent areas.

c) Paleocommunity composition of Tropical reef habitats through the Phanerozoic Eon has changed from time to time. During the early Paleozoic, microbialites were the primary reef builders. They were dominated by stromatolites and thrombolites that created reefs that lacked metazoan animals. In the Late Ordovician and Silurian, these microbialites were overtaken by calcimicrobes and bryozoans that formed reef mounds.

During the Devonian and Carboniferous, the coral-stromatoporoid reef complex came into existence. It was a community dominated by a combination of colonial rugose corals, tabulate corals, stromatoporoid, brachiopods, and bryozoans. The rugose corals and stromatoporoid formed mound structures and provided a habitat for other organisms.

The Mesozoic saw a rapid increase in reef-building organisms such as scleractinian corals, bryozoans, and calcareous sponges. These organisms were able to create large, extensive, and complex reef systems. The reef system was able to support diverse ecological communities consisting of organisms such as echinoids, bivalves, gastropods, and sponges.

The Cenozoic era is characterized by the domination of scleractinian corals. A change in the climate and increased tectonic activity led to the extinction of many reef-building organisms and the evolution of new species. There has been a significant decrease in coral diversity and an increase in the abundance of algae in recent years.

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Q 4. East of the Rocky Mountains in North America the development of Mid-Latitude Wave Cyelones is the result of two air masses interacting with each other. Which two air masses do you think these are and why. (You may wish to refer to Figure 1.) (3 pts) Continental Arctic (cA) forms in the Arctic basin and Greenland and has Stable atmospheric conditions. The temperature and humidity characteristics can be described as bitterly cold and dry. Continental Polar (cP) forms in Interior Canada and Alaska and has Stable conditions. The temperature and humidity characteristics can be described as cold to very cold and dry. Continental Tropical (cT) forms in northern interior Mexico and SW U.S. (Summer only) and usually exhibits Unstable conditions. The temperature and humidity characteristics can be described as hot and dry. Maritime Polar (mP) forms in the northern Pacific and northern Atlantic Ocean and is Unstable in winter and Stable in summer. The temperature and humidity characteristics can be deseribed as cool and humid. Maritime Tropical (mT) forms in the Gulf of Mexico, Caribbcan Sca, west-central Atlantic, and eastem Pacific and is usually Unstable. The temperature and humidity characteristics can be deseribed as warm and humid.

Answers

East of the Rocky Mountains in North America, the development of Mid-Latitude Wave Cyclones is the result of two air masses interacting with each other. These two air masses are Continental Polar (cP) and Maritime Tropical (mT).

Continental Polar (cP) air mass forms in Interior Canada and Alaska and has Stable conditions. The temperature and humidity characteristics can be described as cold to very cold and dry.

Maritime Tropical (mT) air mass forms in the Gulf of Mexico, Caribbean Sea, west-central Atlantic, and eastern Pacific and is usually Unstable.

The temperature and humidity characteristics can be described as warm and humid. When these two air masses interact with each other, the cold, dry air of cP, and the warm, moist air of mT collide and create an unstable environment that can lead to the development of Mid-Latitude Wave Cyclones. East of the Rocky Mountains, this interaction between cP and mT air masses often results in significant weather events such as snowstorms, rainstorms, and thunderstorms. Therefore, Continental Polar (cP) and Maritime Tropical (mT) are the two air masses that interact with each other in the east of the Rocky Mountains in North America to create Mid-Latitude Wave Cyclones.

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7. The greenhouse effect* (mcp)
increases Earth's average surface temperature by about 5 degrees Celsius (9 degrees F)
increases Earth's average surface temperature by about 10 degrees Celsius (18 degrees F)
increases Earth's average surface temperature by about 15 degrees Celsius (27 degrees F)
increases Earth's average surface temperature by about 20 degrees Celsius (36 degrees F)
increases Earth's average surface temperature by about 35 to 40 degrees Celsius (63 to 72 degrees F)

Answers

The greenhouse effect increases Earth's average surface temperature by about 15 degrees Celsius (27 degrees F).

You have been given a task to investigate how colour/paint can influence energy consumption in our laboratories and auditoriums. Although you did not get an opportunity to perform an experiment, but based on your knowledge, answer the following question. a. Do you think colour/paint of the laboratories and auditoriums can have significant energy saving effect? (1) b. If you are given the colours: red, black, and white, which colour do you think can have a significant energy? (2) c. Discuss and explain how the colour you have chosen can really save energy, in terms of temperature? (6) d. Give five benefits of changing colour/paint of the laboratories and auditoriums? (5) e. Explain in detail the types of energy/energies (specifically temperature) influenced by colour/paint and how this energy can be lost and the costs involved?

Answers

a. Color/paint of the laboratories and auditoriums can have significant energy saving effects. This is due to the fact that the use of light and heat inside the building would be directly influenced by the color of the walls. This would imply that more light would be needed to brighten the rooms, and more heat would be needed to keep the building warm.

b. White is the color that has the most significant energy savings impact when it comes to the laboratory and auditorium.

c. In terms of temperature, white paint will reflect the majority of the light that enters the room, keeping the room's temperature cooler. This implies that less heat is required to keep the building warm. When it comes to the auditorium, white paint would have the same impact, as it would reflect light rather than absorbing it. This will assist in keeping the room cooler.

d. Five benefits of changing the color/paint of the laboratories and auditoriums are:

1. Lower energy costs
2. Improved building comfort
3. Less use of artificial light
4. Reduced carbon footprint
5. Increased building longevity

e. The color of paint can have a significant impact on the amount of heat and light that enters and exits a room. Light reflects off of white paint and other lighter colors, while it absorbs into black paint and other darker colors. As a result, a building's use of energy is directly affected by the color of the paint on the walls. This implies that the building will consume more energy if it has darker paint than it would if it had lighter paint. This is due to the fact that the darker paint absorbs more heat, which raises the building's temperature. This, in turn, causes the building to require more cooling and ventilation, resulting in increased energy costs.

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Using the gnomonic projection. Draw the great circle route from Los Angeles to Istanbul, Turkey. (Hint: A straight line drawn between any two points on the surface of a gnomonic projection is the great circle route between the points.) Label all the latitude and longitude graticule lines in order to answer these questions correctly. What is the approximate latitude reached by an aircraft flying the great circle route, in the previous question, as it crosses the following meridians? a) 100 ∘
W b) 80 ∘
W c) 40 ∘
W d) 20 ∘
W e) 0 ∘
f) 20 ∘
E

Answers

Approximate latitudes reached by aircraft flying the great circle route from Los Angeles to Istanbul as it crosses specific meridians are:

a) 100° W: 35° N b) 80° W: 37° N c) 40° W: 40° N d) 20° W: 42° N

e) 0°: 44° N f) 20° E: 42° N

Here is a gnomonic projection of the Earth, with the great circle route from Los Angeles to Istanbul, Turkey, drawn in. The latitude and longitude graticule lines are also labeled.

The approximate latitude reached by aircraft flying the great circle route, in the previous question, as it crosses the following meridians is as follows:

a) 100 ∘ W: 35 ∘ N

b) 80 ∘ W: 37 ∘ N

c) 40 ∘ W: 40 ∘ N

d) 20 ∘ W: 42 ∘ N

e) 0 ∘: 44 ∘ N

f) 20 ∘ E: 42 ∘ N

It is important to note that these are just approximate latitudes. The actual latitude reached by the aircraft will vary depending on the exact path of the flight.

Here is a more detailed explanation of how to find the approximate latitude reached by aircraft flying the great circle route from Los Angeles to Istanbul, Turkey, as it crosses the following meridians:

Draw a line from Los Angeles to Istanbul, Turkey, on the gnomonic projection.Find the meridians that the line crosses.Look up the latitude of the line at the points where it crosses the meridians.

The latitude of the line at the point where it crosses a meridian is the approximate latitude reached by the aircraft as it crosses the meridian.

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Please search and watch a video at least one hour long about "Dust Bowl". (people may watch different videos) Show the video link and answer following questions: 1. List major factors contributed to the Dust Bowl from 1931 to 1939. 2. What farming practices have reduced the effects of drought and soil erosion? Are these practices sustainable? (list or a few sentences) 3. Any topic you want to expression your thinking regarding this event (you can also choose topic from the list on class pp file) This is a discussion assignment. People may have different answers and opinions. HW grading is effort based.

Answers

1. Major factors that contributed to the Dust Bowl included drought, high winds, overproduction of crops, and plowing techniques.

2. Farming practices that have reduced the effects of drought and soil erosion were crop rotation, conservation tillage, contour farming, terracing, and windbreaks which are sustainable.

3.Dust Bowl is a reminder of the importance of environment preservation.

1. List of major factors that contributed to the Dust Bowl from 1931 to 1939 are:

Drought - The Great Plains region of the United States suffered from an extreme and prolonged drought during the 1930s.High winds - High winds whipped up and carried dust across hundreds of miles of barren land.Overproduction of crops - Farmers had been growing wheat and other crops non-stop for decades without practicing good soil conservation techniques.Plowing techniques - Farmers were plowing their fields improperly, leaving the soil exposed to the elements, which led to soil erosion.

2. Farming practices that have reduced the effects of drought and soil erosion include:

Crop rotation - This is the practice of growing different crops on the same land in a specific order to reduce soil erosion.Conservation tillage - This practice involves leaving the previous year's crop residue on the soil surface and tilling the soil to a shallower depth to reduce soil erosion.Contour farming - This is the practice of planting crops perpendicular to the slope of the land to prevent soil erosion.Terracing - This involves building a series of terraces on a slope to slow down water runoff and reduce soil erosion.Windbreaks - This is the practice of planting rows of trees or other vegetation to reduce wind erosion.

These practices are sustainable and are still being used by farmers today to reduce the impact of drought and soil erosion.

3. This event, the Dust Bowl, was a dark period in American history. It serves as a reminder of the importance of taking care of the environment and the negative consequences that can occur when we don't. It's essential that we practice sustainable farming practices to avoid future disasters like the Dust Bowl. We need to take care of the land, not only for ourselves but also for future generations.

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5. If we owe unknown persons living elsewhere ethical
recognition, then why
don’t we owe future generations the same?

Answers

There are several factors that can influence how we think about and prioritize these ethical obligations: Temporal Considerations, Proximity and Connection and Scope of Impact

Why don’t we owe future generations the same?

1. Temporal Considerations: One key difference between unknown persons living elsewhere and future generations is the temporal aspect. Future generations have not yet come into existence, while unknown persons living elsewhere already exist in the present. Some ethical theories emphasize the importance of prioritizing the needs and rights of present individuals over those of future generations.

2. Proximity and Connection: Our sense of moral responsibility often extends more strongly towards those with whom we have a closer connection or relationship.

3. Scope of Impact: Future generations are likely to be significantly affected by the decisions we make today, particularly when it comes to issues such as climate change, resource depletion, and environmental degradation.

4. Intergenerational Justice: The concept of intergenerational justice emphasizes the need to consider fairness and equity between different generations. It suggests that we should not burden future generations with the negative consequences of our actions and should strive to create a sustainable and just world for them.

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Answer the following clearly and thoroughly, using your own words. You may draw figures or diagrams as you deem necessary
1. Describe the physical and chemical mechanisms of weathering rocks.
2. Give one example of a sedimentary deposit produced from physical weathering – describe its formation, composition, textures, features and what rock it will form when lithified.
3. Give one example of a sedimentary deposit produced from chemical weathering – describe its formation, composition, textures, features and what rock it will form when lithified.

Answers

1. Physical weathering of rocks occurs through processes like freeze-thaw cycles and abrasion, while chemical weathering involves reactions such as hydrolysis and oxidation.

2. Sandstone is a sedimentary deposit formed from physical weathering, consisting of compacted sand grains that lithify into a rock with a grainy texture.

3. Limestone is a sedimentary deposit formed from chemical weathering, composed of calcium carbonate precipitated from dissolved minerals, exhibiting features like bedding and fossils when lithified.

1. Weathering is the process of breaking down rocks into smaller fragments or altering their chemical composition. Physical weathering involves the mechanical disintegration of rocks without changing their chemical composition.

This can occur through processes such as frost wedging, where water freezes and expands in cracks, causing rocks to fracture. Another mechanism is exfoliation, where outer layers of rocks peel away due to pressure release. Chemical weathering involves the alteration of rock minerals through chemical reactions.

This can occur through processes such as hydrolysis, where water reacts with minerals to form new compounds, or oxidation, where minerals react with oxygen. These processes weaken the rock structure and contribute to its breakdown over time.

2. An example of a sedimentary deposit produced from physical weathering is sand dunes. Sand dunes form in desert environments where wind acts as the agent of erosion and transportation.

As wind blows over rocky surfaces, it carries sand particles and deposits them in dune formations. The composition of sand dunes primarily consists of sand-sized particles, which are predominantly composed of quartz.

The textures of sand dunes vary depending on factors such as wind direction and speed, resulting in different shapes and sizes. Features of sand dunes include cross-bedding, where layers of sand are deposited at an angle to the horizontal, and ripple marks formed by the wind's action.

When lithified, these sand deposits can form sandstone, a sedimentary rock composed of cemented sand grains.

3. An example of a sedimentary deposit produced from chemical weathering is limestone caves. Limestone caves form in regions with abundant limestone deposits and water containing carbon dioxide. Rainwater absorbs carbon dioxide from the atmosphere and the soil, forming a weak carbonic acid.

This acidic water reacts with limestone, dissolving the calcium carbonate minerals over time. The dissolved minerals are transported within the water, creating underground channels and caverns. These caves often exhibit unique formations like stalactites and stalagmites, which are formed by the deposition of dissolved minerals.

When lithified, the sedimentary deposit of limestone caves can form limestone, a rock composed mainly of calcite or aragonite minerals.

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Which of the following is NOT a geologic feature or hazard that would be found at a Mid-Oceanic Ridge? - rifts new crust forming from the mantle - vents - strong, deep earthquakes - transform boundaries running perpendicular to ridge

Answers

The transform boundaries running perpendicular to the ridge is NOT a geologic feature or hazard that would be found at a Mid-Oceanic Ridge. Therefore, the correct option is D.

A mid-oceanic ridge is a range of mountains that runs beneath the ocean. It is the longest mountain range in the world, extending for more than 70,000 km and covering roughly 23% of the Earth's surface.

The Mid-Atlantic Ridge is one of the most well-known mid-oceanic ridges. Iceland is a country that is almost entirely situated on the Mid-Atlantic Ridge, which divides the country's two tectonic plates.

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State a major difference between plant and animal cells. A cell organelle found only in plant cells: a. plastid b. Golgi body c. centriole d. mitochondrion The two structures that make up the cell skelcton (cytoskeleton). a. Endoplasmic reticulum b. Microtubules \& Microfilaments c. Ribosomes and cellulose d. None of the above

Answers

Plant cells and animal cells differ in many ways, ranging from cell size, shape, organelles, and several other properties. One of the significant differences between plant and animal cells is the presence of a cell organelle that is only found in plant cells.

The answer to the question is option a, Plastids are the cell organelles found only in plant cells. Plastids are a group of membrane-bound cell organelles that are found in plants and some algae. Plastids are essential for photosynthesis, storage of food, and pigmentation. They are divided into three types, chromoplasts, chloroplasts, and leucoplasts. Chloroplasts are one of the most critical types of plastids, and they contain the green pigment chlorophyll, which helps the plants to carry out photosynthesis.

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Choose all answers that apply: Which of the following environments could produce a measurable seismic event (earthquake)? Open pit and underground mines Divergent plate boundary Areas where fracking is taking place Areas that are impacted by a meteor Convergent plate boundary Areas that are subject to large rockslides and avalanches Nuclear testing facilities Active volcanoes Transform plate boundary

Answers

A measurable seismic event (earthquake) can be produced by the following environments, Convergent plate boundary Divergent plate boundary Active volcanoes Transform plate boundary Areas that are subject to large rockslides and avalanches.

The Earth's crust is broken into a number of pieces called plates that shift and collide, causing tremors. The vast majority of earthquakes occur at or near plate boundaries. Plate boundaries are locations where two or more plates come into contact with one another or diverge from one another.There are three types of plate boundaries: divergent, convergent, and transform. Volcanoes, earthquakes, and mountain ranges can all be found at these sites. Seismic activity can be produced by a variety of activities and events.

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Discuss about how incorporating nature into urban environments is important basically. More points on being more environmentally friendly as well. give reference to eco friendly urban greening in Melbourne.

Answers

Urban greening refers to the creation of green spaces within cities, which includes parks, green roofs, green walls, and street trees.

Urban greening provides numerous environmental, social, and economic benefits, including reducing the urban heat island effect, mitigating climate change, providing habitat for wildlife, reducing air and water pollution, improving public health and wellbeing, and creating economic opportunities for local communities. Melbourne is a city that has embraced urban greening in many ways. The city is home to many parks, gardens, and green spaces, including the Royal Botanic Gardens and the Carlton Gardens.

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Objective: This activity has the purpose of helping students relate mass and energy transport with pollutants spreading in the atmosphere, explain the partitioning mechanisms that take place in air pollution events, and model the migration of pollutants between environmental compartments. Student Instructions: This is a 10 points assignment. Read the article "What is Acid Rain?" (EPA, 2017). Next go to the forum named Acid Rain and Chemodynamics and start a thread. In that thread each participant should write its own analysis of acid rain using chemodynamic principles. You have to: - Define and list compartments and phases. (2 points) - Name and write the symbol for the partition coefficients between phases. (2 points) - Write chemical reactions that transform the pollutant. (2 points) - Give your comments and observations to the thread opened by your classmates. (4 points) The forum will be open during week 6 and 7 of the term.

Answers

Acid rain refers to the phenomenon of the increased acidity of rainwater due to atmospheric pollutants.

The partition coefficients between the phases can be represented by Kp, Kd, and Koc, which are the equilibrium constants for partitioning between gas, liquid, and solid phases, respectively.

Chemical reactions that transform the pollutant: SO2(g) + H2O(l) → H2SO3(aq)NO2(g) + H2O(l) → HNO3(aq)

Acid Rain:

The pollutants that cause acid rain include sulfur dioxide and nitrogen oxides, which are primarily released from the burning of fossil fuels in industrial and transportation activities.

Chemical reactions that transform the pollutant

Acid rain forms due to the following reactions: SO2(g) + H2O(l) → H2SO3(aq)NO2(g) + H2O(l) → HNO3(aq)

The sulfur dioxide and nitrogen oxides react with water in the atmosphere to form sulfuric acid and nitric acid, respectively. These acids then mix with rainwater to form acid rain. Pollutants can undergo chemical reactions that transform them into new substances that are either more or less harmful than the original pollutant. The reactions can take place in the atmosphere, soil, water, or living organisms. For example, sulfur dioxide can react with hydroxyl radicals in the atmosphere to form sulfur trioxide, which then reacts with water to form sulfuric acid. The migration of pollutants between environmental compartments.

Pollutants can move between different compartments in the environment through mass and energy transport mechanisms. The compartments and phases that are relevant for acid rain include the atmosphere, hydrosphere (water bodies), and lithosphere (soil). The partitioning of pollutants between these compartments and phases depends on their chemical and physical properties, such as solubility, volatility, and adsorption. For example, sulfur dioxide is highly soluble in water and can dissolve in rainwater to form sulfuric acid, which then flows into rivers and lakes. On the other hand, nitrogen oxides are less soluble in water and can be transported over long distances by atmospheric circulation.

The partition coefficients between the phases can be represented by Kp, Kd, and Koc, which are the equilibrium constants for partitioning between gas, liquid, and solid phases, respectively.

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The soil borrow material to be used to construct a highway embankment has a wet unit weight of 15.4 kN m3 ⁄ , a water content of 9%, and the specific gravity of the soil solids is 2.67. The specifications require that the soil be placed in the fill so that the dry unit weight is 17.9 kN m3 ⁄ and the water content be held to 20%. a. How many cubic meters of borrow are required to construct an embankment having a 612, 000-m3 net section volume? b. How many gallons of water must be added per cubic meter of borrow material assuming no loss by evaporation? c. If the compacted fill becomes saturated at constant volume, what will be the water content and unit weight?

Answers

a. The embankment requires approximately 527,374.3 cubic meters of borrow material.

b. Approximately 0.0417 gallons of water must be added per cubic meter of borrow material.

c. If the compacted fill becomes saturated at constant volume, the water content will be approximately 7%, and the unit weight will be approximately 26.17 kN/m³.

a. To calculate the volume of borrow material required to construct the embankment, we need to determine the dry unit weight and water content of the borrow material that satisfies the specifications.

Wet unit weight of borrow material = 15.4 kN/m³

Water content of borrow material = 9%

Specific gravity of soil solids = 2.67

Required dry unit weight = 17.9 kN/m³

Required water content = 20%

Net section volume = 612,000 m³

To find the volume of borrow material, we can use the equation:

V = (Vn × γn) / γd

where:

V = Volume of borrow material

Vn = Net section volume

γn = Wet unit weight of borrow material

γd = Dry unit weight of borrow material

Plugging in the values, we have:

V = (612,000 × 15.4) / 17.9

V ≈ 527,374.3 m³

Therefore, approximately 527,374.3 cubic meters of borrow material are required to construct the embankment.

b. To calculate the amount of water in gallons that needs to be added per cubic meter of borrow material, we need to consider the change in water content.

Initial water content = 9%

Required water content = 20%

The change in water content is given by:

ΔW = W2 - W1

where:

ΔW = Change in water content

W1 = Initial water content

W2 = Required water content

Plugging in the values, we have:

ΔW = 20% - 9%

ΔW = 11%

To convert the change in water content to gallons per cubic meter, we need to consider that 1 gallon is approximately equal to 0.00378541 cubic meters. Thus:

Change in water content (gallons/m³) = ΔW × 0.00378541

Change in water content (gallons/m³) ≈ 0.0417 gallons/m³

Therefore, approximately 0.0417 gallons of water must be added per cubic meter of borrow material.

c. If the compacted fill becomes saturated at constant volume, the water content and unit weight will change. However, the volume of the borrow material will remain the same.

The saturated water content can be found using the specific gravity of soil solids and the water content:

Saturated water content = (water content) / (1 + specific gravity)

Plugging in the values, we have:

Saturated water content = 0.20 / (1 + 2.67)

Saturated water content ≈ 0.07 or 7%

The saturated unit weight can be calculated using the specific gravity:

Saturated unit weight = (specific gravity) × (unit weight of water)

Plugging in the values, we have:

Saturated unit weight = 2.67 × 9.81 kN/m³

Saturated unit weight ≈ 26.17 kN/m³

Therefore, if the compacted fill becomes saturated at constant volume, the water content will be approximately 7% and the unit weight will be approximately 26.17 kN/m³.

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For every particular substance, there is a temperature below which it is impossible for a liquid to exist. (Hint: Look at a PvT phase diagram.) Select one: True False Most (but not all) substances when cooled at constant pressure from a liquid to a solid. a. change colour b. expand c. maintaina constant temperature d. have less energy e. contract

Answers

The given statement, "For every particular substance, there is a temperature below which it is impossible for a liquid to exist." is true because Below this temperature, the substance is in its solid form or has transformed into a gaseous state.

Phase diagrams (PvT) give an overview of the conditions under which a substance exists in the solid, liquid, or gaseous state. A phase diagram is a graph of the pressure vs. temperature of a substance. It exhibits the temperature and pressure at which a particular substance will change from solid to liquid and then to gas or from gas to liquid and then to solid.

Most substances, when cooled at constant pressure from a liquid to a solid, contract. This happens because the average distance between the atoms or molecules of the substance decreases as the temperature drops. The remaining answer choices are not accurate for most substances when cooled at a constant pressure from a liquid to a solid. Therefore, the correct answer is:True. Most substances when cooled at constant pressure from a liquid to a solid, contract.

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What is transpiration? A. It is the process by which water changes from liquid state to gaseous state B. It is the process by which water vapor condenses to form dew C. It is the biological process by which plants water is transferred to the atmosphere as water vapor. D. It is the process by which water moves through the soil due to Gravity and by capillary forces. 58) Identify an example of Epigean Karts Forms A Potholes B. Chasms C. Dunes D. Karren 59) How are felsic rocks? A. The felsic rocks are low in silica and with low viscosity B. The felsic rocks are low in silica, but with iron and magnesium C. The felsic rocks are rich in silica and with low density D. The felsic rocks are characterized by low density and dark-colored minerals 60) What are the main factors influencing metamorphism? A. Temperature, pH, pressure and state of stress B. Pressure, temperature, state of stress and nature of fluid phase C. State of stress, weathering, temperature and pressure D. Nature of fluid phase, pressure, pH and state of stress

Answers

Epigean karst forms is Karren. Felsic rocks are rich in silica and with low density. Factors influencing metamorphism are pressure, temperature, state of stress, and the nature of the fluid phase.

The correct option for question 58 is (d), question 59 is (c) and question 60 is (b).

Transpiration is the biological process in which plants transfer water from their roots to the atmosphere as water vapor. Epigean karst forms refer to potholes, which are examples of solution cavities that form on the surface of limestone or other soluble rocks. Felsic rocks are characterized by being rich in silica and having a low density. The main factors influencing metamorphism are pressure, temperature, state of stress, and the nature of the fluid phase. These factors determine the physical and chemical changes that occur in rocks during the metamorphic process.

The correct answer to question 58)  is (d) Karren, to question 59 is (c) the felsic rocks are rich in silica and with low density and question 60 is (b) pressure, temperature, state of stress, and nature of fluid phase.

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What are the Sustainable Development Goals (SDGs)? Which SDGs can you relate to deforestation in the Palm Oil article (Pacheco, 2015), and why? (250 Words) Tip: You can use bullet points to answer this question.

Answers

The Sustainable Development Goals (SDGs) are a set of 17 global goals that were adopted by the United Nations General Assembly in 2015, to end poverty, protect the planet, and ensure prosperity for all. These goals aim to address some of the most pressing challenges of our time, including poverty, inequality, climate change, environmental degradation, and social exclusion.

The following SDGs can be related to deforestation in the Palm Oil article (Pacheco, 2015), and the reasons why are:

1. SDG 1: No Poverty: Palm oil plantations cause displacement of indigenous people and smallholder farmers who depend on the forest for their livelihoods. This has led to impoverishment, as they no longer have access to resources for subsistence.

2. SDG 2: Zero Hunger: The loss of forests due to deforestation in the palm oil industry has led to a decline in food security, especially for indigenous people and smallholder farmers.

3. SDG 5: Gender Equality: Women are particularly affected by the negative impacts of deforestation, as they are often excluded from decision-making processes regarding the use of land.

4. SDG 12: Responsible Consumption and Production: The palm oil industry has been linked to environmental degradation, deforestation, and the destruction of habitats for endangered species. This is a result of unsustainable production and consumption patterns.

5. SDG 13: Climate Action: Deforestation accounts for a significant amount of greenhouse gas emissions, contributing to climate change.

6. SDG 15: Life on Land: Deforestation in the palm oil industry has led to the loss of biodiversity and habitats for endangered species, as well as increased soil erosion and water pollution.

In conclusion, the Sustainable Development Goals provide a framework for addressing the complex challenges associated with deforestation in the palm oil industry. These goals can help guide policy decisions, promote sustainable production and consumption patterns, and ensure that the needs of marginalized communities are taken into account.

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1. Using the three criteria, sketch or copy and paste a diagram (or three distinct diagrams) illustrating the layers of the environment (composition, temperature, function). Be sure to provide each sublayer, such as Composition: Homo and Heterosphere.
2. Create a diagram by hand-drawing (preferred) or using cut-and-paste that shows the main wind belts, such as the trade winds and hemispheric pressure zones (i.e., ITCZ or Equatorial Low, Trade Winds, etc.).

Answers

1. The three criteria are:

Composition: HomeSphere and Heter sphere.

Temperature: Thermosphere, Mesosphere, Stratosphere, and Troposphere.

Function: Ionosphere and Ozone Layer.

The atmosphere of the earth is divided into five layers based on temperature and composition. They are as follows: Troposphere, Stratosphere, Mesosphere, Thermosphere, and Exosphere. The layer closest to the earth's surface is the troposphere, which extends from the earth's surface to an altitude of roughly 8-15 kilometers.The stratosphere extends from the top of the troposphere to an altitude of roughly 50 kilometers. The mesosphere begins at an altitude of roughly 50 kilometers and extends to an altitude of roughly 85 kilometers.The thermosphere extends from the mesosphere to an altitude of approximately 600 kilometers. Finally, the exosphere is the outermost layer, extending from the thermosphere to an altitude of approximately 10,000 kilometers.2. Diagram of the main wind belts:The earth's atmospheric circulation is driven by the sun's heat energy, which warms the earth's surface unevenly. As a result, the earth's atmosphere is divided into distinct wind belts that circulate the earth. The most well-known of these are the trade winds, which circulate in both the northern and southern hemispheres at roughly 30 degrees north and south latitudes. The following are the main wind belts: Equatorial Low or ITCZ Trade Winds Subtropical High Westerlies Subpolar Low Polar Easterlies.

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How did Dr. Susan Solomon and her team use the scientific method
in Antarctica? Provide a brief summary showcasing each step.

Answers

Dr. Susan Solomon and her team used the scientific method in Antarctica to understand the cause of the ozone hole. The first step of the scientific method is to make an observation.

The team observed that the ozone layer was thinning over Antarctica. The second step is to ask a question. The team asked why the ozone layer was thinning. The third step is to form a hypothesis. The team hypothesized that the thinning was caused by chlorofluorocarbons (CFCs). The fourth step is to conduct experiments. The team conducted experiments to measure the amount of CFCs in the atmosphere. The fifth step is to analyze the data.

The team analyzed the data and found that CFCs were indeed the cause of the ozone hole. The sixth step is to draw a conclusion. The team concluded that CFCs were the cause of the ozone hole. Finally, the seventh step is to communicate the results. The team communicated their results to the public, which led to the Montreal Protocol, an international agreement to reduce CFC emissions.

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Which of the following fuels has the lowest chemical potential energy per gram.11 natural gas O wood O petroleum O coal O

Answers

Among the given options, wood has the lowest chemical potential energy per gram.

Wood is primarily composed of cellulose, hemicellulose, and lignin, which are organic compounds with relatively lower energy content compared to fossil fuels like natural gas, petroleum, and coal.

The chemical potential energy of a fuel is determined by the energy stored in its chemical bonds. Fossil fuels, such as natural gas, petroleum, and coal, are derived from ancient organic matter that has undergone significant heat and pressure over millions of years, resulting in the formation of energy-rich hydrocarbon compounds.

These fuels contain higher carbon-to-hydrogen ratios and have more complex chemical structures, making them more energy-dense compared to wood.

Wood, on the other hand, is primarily composed of cellulose, which is a complex carbohydrate. While it serves as a source of energy, the chemical potential energy stored in wood is relatively lower than fossil fuels due to its simpler chemical structure and lower carbon content.

It is worth noting that the energy content of a fuel can vary depending on factors such as moisture content and specific composition. However, in general, wood has a lower chemical potential energy per gram compared to natural gas, petroleum, and coal.

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1. What is the relationship between the ground surface and the width of the outcrop in the map view?

Answers

In the context of geological mapping, the relationship between the ground surface and the width of an outcrop in the map view can provide valuable information about the geological structure and subsurface characteristics of an area.

The width of an outcrop, also known as its map width, refers to the horizontal extent of a geological formation or rock exposure as observed on a map.

The ground surface and the width of an outcrop are related through the angle of dip of the geological strata or rock layers. The dip refers to the inclination or tilt of the rock layers from the horizontal plane.

The angle of dip can vary depending on the geological structure and can be steep, gentle, or even horizontal.

When the ground surface is relatively flat or gently sloping, and the rock layers have a shallow dip, the width of the outcrop in the map view tends to be wider. This means that a larger horizontal extent of the rock layers is exposed on the surface, resulting in a broader outcrop on the map.

Conversely, when the ground surface is steeply inclined or has significant topographic relief, and the rock layers have a steeper dip, the width of the outcrop in the map view tends to be narrower.

This indicates that the rock layers have a more vertical orientation, and less of their horizontal extent is visible on the surface, resulting in a narrower outcrop on the map.

By considering the relationship between the ground surface and the width of the outcrop in the map view, geologists can infer the subsurface geological structures, such as folds, faults, and inclined strata.

This information is crucial for understanding the geological history of an area, predicting the distribution of rock units, and identifying potential mineral resources or geological hazards.

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Telescopes Homework (Due 3/2)
1. List at least two ways Earth’s atmosphere can hinder astronomical observations. What problem can adaptive optics help with?
2. Discuss how well each portion of the electromagnetic spectrum penetrates Earth’s atmosphere. Based on your answer, explain why space-based telescopes are so important to our understanding of the universe.
3. Telescope Technology. Suppose you were building a space-based observatory consisting of five individual telescopes. Which would be the best way to use these telescopes: as five individual telescopes with adaptive optics, or as five telescopes linked together for interferometry but without adaptive optics? Explain your reasoning clearly.
4. When multiple radio telescopes are used for interferometry, resolving power is most improved by increasing (a) the electrical power supplied to each telescope; (b) the distance between telescopes; (c) the number of telescopes in a given area; (d) the diameter of each telescope.
5. How much greater is the light-collecting area of a 6-meter telescope than that of a 3-meter telescope? (a) two times (b) four times (c) six times (d) eight times (e) nine times
6. Give two reasons that radio telescopes have to be very large?
7. The Hubble Space Telescope obtains higher-resolution images than most ground-based telescopes because it is (a) closer to the stars. (b) above Earth’s atmosphere. (c) larger.

Answers

Enhanced observations across multiple wavelengths, unobstructed by Earth's atmosphere, enabling breakthrough discoveries and deeper understanding of the universe.

What is the significance of space-based telescopes for our understanding of the universe?

Earth's atmosphere can hinder astronomical observations in several ways:

- Atmospheric turbulence: The movement of air masses in the atmosphere causes turbulence, which leads to the blurring of starlight and reduces image clarity. This effect is known as atmospheric seeing and can distort astronomical observations.

- Atmospheric absorption: Different components of Earth's atmosphere, such as water vapor, oxygen, and other gases, absorb specific wavelengths of electromagnetic radiation. This absorption can prevent certain wavelengths of light from reaching the Earth's surface, limiting the observations that can be made from the ground.

2. Different portions of the electromagnetic spectrum have varying degrees of penetration through Earth's atmosphere:

- Radio waves: Radio waves have long wavelengths and can penetrate the atmosphere with minimal absorption. However, they can be affected by interference from human-made radio signals, which limits observations in certain frequency ranges.

- Infrared: Infrared radiation is partially absorbed by Earth's atmosphere, especially by water vapor and carbon dioxide. This absorption restricts some infrared observations from the ground, particularly in certain wavelength regions.

- Visible light: The visible light spectrum is relatively well transmitted through Earth's atmosphere, allowing ground-based telescopes to observe this range effectively. However, atmospheric conditions like light pollution and atmospheric turbulence can still affect observations.

- Ultraviolet (UV), X-rays, and gamma rays: These high-energy forms of electromagnetic radiation are strongly absorbed by Earth's atmosphere. They hardly reach the surface, making space-based telescopes essential for observing these regions of the spectrum.

Space-based telescopes are crucial for our understanding of the universe because they can observe the full range of the electromagnetic spectrum without the limitations imposed by Earth's atmosphere.

By operating above the atmosphere, these telescopes can capture high-energy radiation, such as X-rays and gamma rays, which are absorbed before reaching the ground. They also avoid the atmospheric distortion that affects ground-based observations, enabling higher resolution and clearer images.

3. The best way to utilize the five individual telescopes would be to link them together for interferometry but without adaptive optics. Interferometry combines the signals from multiple telescopes to create a larger effective telescope, enhancing the resolving power and image detail. Adaptive optics, on the other hand, corrects for atmospheric turbulence but is not necessary for interferometry.

4. The resolving power of radio telescopes used for interferometry is most improved by increasing the (b) distance between telescopes. Resolving power refers to the ability of a telescope to distinguish between two closely spaced objects. In interferometry, the distance between telescopes acts as a baseline, allowing for higher angular resolution.

By increasing the distance between telescopes in a given array, the baseline lengthens, resulting in finer resolution. This increase in baseline effectively enhances the resolving power of the interferometric system. Electrical power, the number of telescopes, or the diameter of each telescope do not directly impact the resolving power in interferometry.

5. The light-collecting area of a telescope is directly proportional to the square of its diameter. Therefore, a 6-meter telescope would have (b)

four times the light-collecting area of a 3-meter telescope.

The area of a circular telescope is given by the formula A = πr², where r is the radius of the telescope (half of its diameter). If we compare a 3-meter telescope (r = 1.5 m) to a 6-meter telescope (r = 3 m), we find that the ratio of their areas is (3²)/(1.5²) = 9/2.25 = 4. Thus, the 6-meter telescope has four times the light-collecting area of the 3-meter telescope.

6. Radio telescopes need to be very large due to two main reasons:

Radio waves have long wavelengths, and to achieve good angular resolution, larger apertures are necessary. The size of a radio telescope is directly related to the wavelength of the radio waves it aims to detect.

- Sensitivity: Radio waves from astronomical sources can be extremely faint. Larger radio telescopes have a larger collecting area, which allows them to gather more photons and increase the signal-to-noise ratio. Improved sensitivity enables the detection of weaker radio signals and enhances the overall capabilities of the telescope.

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1. How is climate change altering precipitation in the U.S.?
Group of answer choices
-Increasing length of droughts everywhere
-Increasing both wet and dry extremes
2. In the U.S., sea level rise is anticipated to be:
Group of answer choices
-Be minor because the U.S. has built barriers to minimize its effect
-More destructive on the east coast
3. Groundwater represents how much of the world's TOTAL water supply?
Group of answer choices
3.8%
69%
0.75%
4. In a typical groundwater system, there are typically 7 "major" ions that make up the vast majority of TDS. These solutes usually have the following concentration to be considered "major":
Group of answer choices
10 mg/L
0.1 mg/L

Answers

Climate change is altering precipitation in the U.S. by increasing both wet and dry extremes. Sea level rise is anticipated to be more destructive on the east coast of the U.S., while groundwater represents approximately 0.75% of the world's total water supply, and in a typical groundwater system, seven "major" ions make up the majority of Total Dissolved Solids (TDS) with concentrations exceeding 10 mg/L.

1. Climate change is altering precipitation patterns in the U.S. by increasing both wet and dry extremes. The warming of the Earth's atmosphere due to human activities is causing changes in atmospheric circulation patterns, leading to shifts in precipitation distribution.

While some regions may experience more frequent and intense rainfall events, resulting in increased flooding and the risk of landslides, other areas may face more prolonged periods of drought. These changes in precipitation patterns have significant implications for water resources, agriculture, ecosystems, and human populations.

2. Sea level rise in the U.S. is anticipated to be more destructive on the east coast. This is because the eastern coastline is characterized by low-lying areas, including barrier islands, coastal marshes, and densely populated urban areas.

Rising sea levels exacerbate the risks of coastal erosion, saltwater intrusion into freshwater sources, and storm surge impacts. Additionally, the eastern coast is prone to hurricanes and tropical storms, which can intensify the destructive effects of sea-level rise, leading to increased coastal flooding and damage to infrastructure, property, and ecosystems.

3. Groundwater represents approximately 0.75% of the world's total water supply. Despite its relatively small percentage, groundwater is a vital source of freshwater for various human activities, including drinking water supply, irrigation for agriculture, and industrial processes.

Groundwater is stored underground in aquifers, porous rock formations, or sediment layers that can hold and transmit water. However, overexploitation and improper management of groundwater resources can lead to depletion, reduced water availability, and the intrusion of saline water into freshwater aquifers.

4. In a typical groundwater system, there are typically seven "major" ions that make up the majority of Total Dissolved Solids (TDS). These ions, including calcium, magnesium, sodium, potassium, bicarbonate, sulfate, and chloride, contribute to the chemical composition of groundwater. The concentrations of these ions typically exceed 10 mg/L to be considered "major."

The presence of these ions influences the water's taste, hardness, pH, and suitability for various uses such as drinking, irrigation, and industrial processes.

Monitoring and managing the concentrations of these ions in groundwater are important for ensuring water quality and sustainable water resource management.

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1. Describe specific examples of the effects already experienced in at
least 2 of these regions and how did La Nina likely exacerbate
them?

Answers

La Nina is a weather pattern characterized by colder-than-average sea surface temperatures in the equatorial Pacific Ocean. It affects weather patterns globally, and its impact on different regions depends on the severity and duration of the event. Here are two specific examples of the effects already experienced in two regions and how

La Nina likely exacerbated them:

1. South America:

In South America, La Nina results in above-average rainfall in the western Amazon basin and the Andean highlands, while parts of southern Brazil and Argentina experience droughts. La Nina's impact on South America was particularly severe in 2010-2011, leading to significant floods in Brazil, Colombia, and Peru, as well as droughts in Argentina, Paraguay, and Uruguay. La Nina exacerbates these conditions by strengthening the polar jet stream, which brings cold, dry air from the south to southern Brazil and Argentina, leading to less rainfall and drier conditions.

2. Southeast Asian:

In Southeast Asia, La Nina typically causes wetter-than-normal conditions during the northern hemisphere winter, leading to flooding and landslides in some areas. The impact of La Nina in Southeast Asia was most severe in 2011, when floods in Thailand, Laos, Cambodia, and Vietnam affected over 14 million people, causing hundreds of deaths and widespread damage to infrastructure and crops. La Nina exacerbates these conditions by enhancing the monsoon circulation, which brings more moisture to the region, leading to heavier rainfall and flooding in some areas.

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Key Contact metamorphism Granite intrusion a) Which sedimentary layer in the rock profile was deposited most recently? b) Which layer in the rock profile is the oldest? Justify your answer

Answers

The sedimentary layer deposited most recently in the rock profile is at the top of the rock profile. It is because the deposition of the rocks follows the principle of superposition.

According to this principle, the younger rock layers are deposited on, the older ones. Hence, the rock layer deposited most recently is found at the top of the rock profile. The oldest layer in the rock profile is the bottom-most layer. It is because the rock layers deposited first will be found at the bottom of the rock profile. Hence, the bottom-most layer is the oldest in the rock profile. Granite intrusion is an igneous rock that occurs when molten (magma) is pushed up from the Earth's interior and solidifies underground. The stones above the granite intrusion are affected by contact metamorphism, the heat, and pressure generated by granite intrusion cause the stones to change. The sedimentary rocks are the ones that get affected by the metamorphism of the granite intrusion. The rock profile of the area can provide insights into the site's geological history. The rock profile is arranged according to the principle of superposition. It means that the younger rocks are deposited over older rocks. Hence, the top-most layer is the most recently deposited, and the bottom-most layer is the oldest in the rock profile.

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The change in the proportional size of features at high latitudes on a Mercator map (conformal projection) occurs because OA. meridians are stretched apart at high latitudes. B. all latitudes are parallel C. all longitudes merge to a point D. a conic projection is used to create the map E. all of them QUESTION 7 Earth's seasons are caused by A. the increasing and decreasing distance of Earth away from the Sun during the year B. the constant tilt of Earth's axis throughout its revolution C. the changed temperature D. shifts in Earth's magnetic field OE. None of the above QUESTION 8 If it is 9 PM Greenwich, UK (UTC) and it is 2 PM where you are; at what longitude must you be? A. 60 °E B. 120 °E C.90 °W D. 75 W E. 105 °W

Answers

On a Mercator map, the change in the proportional size of features at high latitudes occurs because meridians are stretched apart, Option A.

Earth's seasons are caused by the constant tilt of Earth's axis throughout its revolution, Option B.

If it is 9 PM Greenwich, UK (UTC) and it is 2 PM where you are, you must be at 75°W longitude, Option D.

On a Mercator map, the proportional size of features, such as land masses and objects, becomes distorted at high latitudes. This distortion occurs because the meridians (lines of longitude) are stretched apart as they approach the poles.

As a result, objects near the poles appear larger and more distorted compared to their actual size. This distortion is a limitation of the Mercator projection, which is conformal and preserves angles but distorts sizes.

So, option A is correct.

Earth's seasons are primarily caused by the constant tilt of Earth's axis throughout its revolution around the Sun. As Earth orbits the Sun, the tilt of its axis remains constant, causing different parts of the planet to receive varying amounts of sunlight throughout the year.

This variation in sunlight leads to changes in temperature and weather patterns, resulting in the distinct seasons we experience.

So, option B is correct.

If it is 9 PM Greenwich, UK (UTC) and it is 2 PM where you are, you can calculate the time difference by comparing the longitudes. Since the time difference is 7 hours ahead, you must be located at a longitude of approximately 105°W.

This calculation is based on the concept that each hour of time difference corresponds to approximately 15 degrees of longitude (360 degrees divided by 24 hours).

So, option D is correct.

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Common substances such as ice, rock, or metal have densities given in grams per cubic centimeter (or g/cm3 ). The density of a world needs to be calculated in grams per cubic centimeter for comparison to the densities of the samples measured in a laboratory. Earth's mass is 5.97×10 24
kilograms. Convert this mass to grams. NOTE: Canvas needs the number written like 5.97e24 for it to be accepted. You can also use 5.97e+24. The "e24" in this case means 10 to the 24th power.

Answers

Common substances such as ice, rock, or metal have densities given in grams per cubic centimeter (or g/cm3 ). The density of a world needs to be calculated in grams per cubic centimeter for comparison to the densities of the samples measured in a laboratory. Earth's mass is 5.97×10 24 kilograms.

To convert the mass of Earth to grams: 5.97 × 10²⁴ kg = 5.97 × 10²⁴ kg × 1000 g/1 kg= 5.97 × 10²⁷ g. Thus, the mass of the Earth in grams is 5.97 × 10²⁷ g.

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Eventually the sun will use up its core helium and cease nuclear [Select] red giant main sequence star white dwarf Select ] supernova planetary nebula neutron star black hole Question 57 4 pts The Sun is currently in its [Select] phase and its spectral type is [Select ] In about 5 billion years, the sun will become a [ Select] Eventually the sun will use up its core helium and cease nuclear fusion, leaving behind a remnant known a [ Select ] white dwarf black hole neutron star protostar For a convex mirror, when the object is 24.5 cm in front of the mirror the image is 14.6 cm behind the mirror. If the object is moved to a distance of 14.0 cm in from the mirror, determine the distance of the image behind the mirror. cm Supporting Materials Physical Constants Additional Materials Reading 14. [-/1 Points] DETAILS OSCOLPHYS1 25.P.056.WA. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A 3.58 cm tall object is placed 14.0 cm in front of a concave mirror whose focal length is 19.4 cm. Determine the location and height of the image. location cm height cm Supporting Materials Physical Constants Additional Materials Reading Irithe experimental design, neither the participarits nor the researchers are aware of each participarit's assignment fest or piacebo) or the outcome of the study until it is completed. Muliphe choice double-binded clinical trial case control animal model Q9 How long does $1,000 have to be deposited into a savings account at the end of each month to accumulate to $36,000 if interest is 6.4% compounded monthly? Discuss the legal issues involved in the use of initial assessment methods, and methods on how legal problems can be avoided. Your discussion should also involve potential legal issues involving final matches. Calculate the bandwidth for FSK (frequencyshift key)Communication System transmits a Carrier at 800M Hz. Calculate the Fsk bandwidth a 10 Mbits -1 binary signal using Exercise: Properties of the Fourier transform The Fourier transforms of the signals x(t) and y(t) are X(f)=F[x(t)]=rect( T 1f) and Y(f)=F[y(t)]=rect( T 2f) If the signal z(t) is defined as z(t)=2x(t5)+6y(3t), what is its Fourier transform Z(f)=F[z(t)] ? You can utilize the transform formulas introduced in section 5.3.2. ( 2 attempts allowed, max. 1 point) Imagine you wake up on Monday morning and none of the lights or the appliances in your house are working. What is a theory? Come up with and describe a specific theory that might explain why this is happening? What could you do to test this theory? How is this an example of the theory-data cycle in science? : How many different 6-letter words can be made a. if the first letter must be E, W, or Q and no letter may be repeated? b. if repeats are allowed (but the first letter is E, W, or Q)? c. How many of the 6-letter words (starting with E, W, or Q) with no repeats end in R? Find an article on the www that gives information about a corporate strategy decision an organization has made.How does this corporate strategy decision potentially create additional value (i.e. economies of scope, or "synergies") compared to what would happen had the organization not made the decision?What will be the evidence/measure(s) the organization, or analysts, or investors, will be looking at in a few years to see whether or not the synergies have actually been achieved?In your write-up, include a www link to the article/story you are writing about. (Population growth) Find the general solution of each of the two general forms of the logistic equation, and X' = r(t)X (1 - 1/1), K X'= X(1-XX) K(t) Answers should be in terms of indefinite integrals. Hint: Bernoulli. Evaluate the combination. \[ C(35,20) \] Factor completely: 3431x 9y 3+27 The volume of a cylinder can be modelled by the equation V(x)=9x 3+51x 2+88x+48. What are the possible dimensions of the cylinder in terms of x ? You are auditing the Cash balance of your client. The client informs you that it has not yet recorded the $300 bank fee expense associated with the operation of its Cash account with Chase Bank.You are provided with the following information from the clients pre-audited financials:Cash Chase Bank account balance is $400,000 (a debit)Determine what adjusting journal entry needs to be proposed to the client to address any deficiencies. The future value of $1,000 deposited each year for 7 years earning 13 percent would be approximately: $6,500 $5,250 $10,404 $5,000 $8,200 6) What would be problematic about including both male and female athletes in this chapter's example data? Use the four-step process to find \( f^{\prime}(x) \) and then find \( f^{\prime}(5), f^{\prime}(7) \), and \( f^{\prime}(9) \). \[ f(x)=10 \sqrt{x+1} \] \( f^{\prime}(x)= \) \( f^{\prime}(5)= \) (Typ