Alex : Hey Bob, I think this coin is biased; I flipped it a few times and it always lends Tail. I think p, the probability of landing Head, must be less than 5%. Can you take a look?
Bob: Seriously? I bet it's fair, that is I think p = 1/2. Let me flip it three times and count the number of Heads. If the number of Heads is smaller than some threshold t, then I will buy you dinner. Otherwise, you will buy me dinner.
Alex: Wow Bob, okay! I will go ahead and reserve a fancy restaurant.
Bob: One last thing, though, just to make things fair: pick any t you want, but let's keep the proba- bility that I buy you dinner even if I'm right (that is, even if the truth is p= 1/2) below 10% please.
Alex: Go away, Bob! Stop wasting my time!
Question: why did Alex get mad?

Answer:

Step-by-step explanation:

Hello!

You have to estimate the mean length of 4000 b.c. human skulls trough a 95% confidence interval.

You know that

n= 6 human skulls

[tex]\frac{}{X}[/tex]= 94.2mm

S= 4.9

Assuming that the variable X: length of a 4000b.c. human skull (mm) has a normal distribution, to construct the interval you have to use the t statistic:

[[tex]\frac{}{X}[/tex] ± [tex]t_{n_1;1-\alpha /2} * \frac{S}{\sqrt{n} }[/tex]]

[tex]t_{n-1;1-\alpha /2}= t_{5; 0.975}= 2.571[/tex]

[94.2 ± 2.571 * [tex]\frac{4.9}{\sqrt{6} }[/tex]]

[89.06; 99.34]mm

With a 95% confidence level you'd expect the interval [89.06; 99.34]mm to contain the value for the average skull length for humans 4000 b.c.

I hope this helps!

Answer:

(B)[tex]4\sqrt{37}[/tex]

Step-by-step explanation:

First, we determine the height of the triangle which we label as y.

Using Pythagoras Theorem.

[tex]25^2=7^2+y^2\\y^2=25^2-7^2\\y^2=576\\y=\sqrt{576}\\y=24[/tex]

In the smaller right triangle with hypotenuse, x

Base = 7-3 =4 Units

Height, y= 24 Units

Therefore, applying Pythagoras Theorem.:

[tex]x^2=24^2+4^2\\x^2=592\\x=\sqrt{592}\\ x=4\sqrt{37}[/tex]

Step-by-step explanation:

just substitute the value of g(X) and f(X)

Hey there! I'm happy to help!

Let's set this up as a system of equations, where x is equal to the number of 10 dollar bills and y is equal to the number of 50 dollar bills.

10x+50y=1080

x+y=28

We want to solve for x or y. We can rearrange the second equation to find the value of one of the variables.

x+y=28

Subtract x from both sides.

y=28-x

Now, we have a value for y. So, we could replace the y in the first equation with 28-x and the solve for x.

10x+50(28-x)=1080

We use distributive property to undo the parentheses.

10x+1400-50x=1080

We combine like terms.

-40x+1400=1080

We subtract 1400 from both sides.

-40x=-320

We divide both sides by -40.

x=8

Since there are 28 total bills, this means that there must be 20 50 dollar ones because there are 8 10 dollar bills.

Have a wonderful day! :D

Answer:

[tex]\boxed{7^{\frac{3}{2} } \times 4}[/tex]

Step-by-step explanation:

[tex]4 (\sqrt{7} )^3[/tex]

Square root can be written as a power.

[tex]4(7^{\frac{1}{2} })^3[/tex]

Multiply the exponents.

[tex]4(7^{\frac{3}{2} })[/tex]

Answer:

A (7^3/4)

Step-by-step explanation:

ed 2020

Answer:

2(6)(4)

Step-by-step explanation:

The commutative law of multiplication states that the order of the numbers does not affect the answer. To rewrite 2(4)(6) using the commutative law of multiplication, rearrange the order of the numbers.

Answer:

100yd²

Step-by-step explanation:

length=4x

width=x

perimeter=2(l+w)

50=2(4x+x)

50=2(5x)=10x

50=10x

x=5yd

width=5yd

length=20yd

area=length×width

=20×5

=100yd²

Answer:

[tex]\boxed{\red{100 \: \: {yd} ^{2}}} [/tex]

Step-by-step explanation:

width = x

length = 4x

so,

perimeter of a rectangle

[tex] p= 2(l + w) \\ 50yd = 2(4x + x) \\ 50yd= 2(5x) \\ 50yd= 10x \\ \frac{50yd}{10} = \frac{10x}{10} \\ x = 5 \: \: yd[/tex]

So, in this rectangle,

width = 5 yd

length = 4x

= 4*5

= 20yd

Now, let's find the area of this rectangle

[tex]area = l \times w \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 100 {yd}^{2} [/tex]

Answer:

g(2) =10x+6

Step-by-step explanation:

g(x) =5x+3

g(2)=5x+3

g(2)=10x+6

have a great day

x^3 - 3x^2 - 18x

Using the FOIL method, I arrived at my solution!

Answer:

x=5

Step-by-step explanation:

35 = 7x

Divide each side by 7

35/7 = 7x/7

5 = x

Answer:

See picture attached

Step-by-step explanation:

Answer:

The bottom left

Step-by-step explanation:

the -4 tells you the y intercept and the 1/3 tells you slope

hope this helps!

Answer:

1510 h, or 3:10 PM.

Step-by-step explanation:

The next time they meet at the bus terminal will be a multiple of 50, 80, and 100.

A common factor among the three numbers is 10. If we divide all three by 10, we will get 5, 8, and 10. 5 is a factor of 10, so as long as 5 is multiplied by an even number, 10 will be a multiple.

Since the number will have to be divisible by both 5 and 8, the smallest possible number would be 5 * 8 = 40. So, the next time they meet at the bus terminal will be 40 * 10 = 400 minutes after 8:30.

400 minutes in hours is 400 / 60 = 40 / 6 = 20 / 3 = 6 hours and 2/3.

2/3 of an hour in minutes is (2/3) * 60 = 2 * 20 = 40.

So, they will meet again in 6 hours and 40 minutes.

8:30 plus 6 hours and 40 minutes is 14:70. 70 minutes translates into an hour and 10 minutes. So, the time will be 15:10, or 3:10 PM.

Hope this helps!

Answer:

undefined! one cannot divide by 0

Step-by-step explanation:

Answer:

undefined!

Step-by-step explanation:

Answer:

Step-by-step explanation:

We assume you are not interested in five infinite sets of translations. Rather, we assume you want to pick 5 translations from the infinite set of possibilities.

The attached graph shows f(x), g(x), and 5 lines (dashed or dotted) that represent possible reflections and shifts of the function f(x).

The function f1 represents a reflection of f(x) about the x-axis, followed by a left-shift of 6 units. To make it match g(x), we need to shift it upward 4 units. Then the set if translations is ...

  g(x) = f(x) ... {reflected over the x-axis, shifted left 6, shifted up 4}

Along the same lines, other possibilities are ...

  g(x) = f(x) ... {reflected over the x-axis, shifted left 3, shifted up 3}

  g(x) = f(x) ... {reflected over the x-axis, shifted left 0, shifted up 2}

  g(x) = f(x) ... {reflected over the x-axis, shifted right 3, shifted up 1}

  g(x) = f(x) ... {reflected over the x-axis, shifted right 9, shifted down 1}

___

Additional comment

All of the transformations listed above use reflection in the x-axis. Reflection could use the y-axis, as well. Reflection of the basic function f(x) in the y-axis will have the identical effect as reflection in the x-axis. The listed translations would apply unchanged.

Answer:-95 1/7 feet

Step-by-step explanation:

-120 4/7+25 3/7=-95 1/7 feet

Answer:

(0,7) and (7,0)

Step-by-step explanation:

When x = 0, y = 7

When y = 0, x = 7

The solution to this equation is: (0,7) and (7,0) and can be graphed on a cartesian plane like the attached graph.

Answer:

r = 2

h = 4

vol for r = 2  and h = 4 has the greater volume

Step-by-step explanation:

vol for r = 2, h = 4

= pi * r ² * h

= 50

vol for r = 1, h= 8

= pi * r ² * h

= 25

therefore : vol for r = 2  and h = 4 has the greater volume

Answer:

Hello  your questions is incomplete attached below is the missing part of the question

answer : A )  0.647 ,  (B) 0.353,  (C) students are more likely to spend the money than to have kept it

Step-by-step explanation:

from the attached table below

Given data :

Total number of students = Number of students who spent money + number of students who kept money

Total number of students = (33+13 ) + (18 + 27 ) =  91

p(Number of students given four quarters) = (33 +18 ) / 91 = 51/91

p( number of students who spent money ) = ( 33 +13 ) / 91 = 46/91

p( number of students who saved money ) = (18 +27 ) / 91 = 45 /91

p( number of students who spent money and given four quarters ) = 33/91

p( number of students who saved money and given four quarters ) = 18/91

A) The probability of randomly selecting a student who spent the money and also given four quarters

= p ( 33/91 | 51/91 )

= 33/91 * 91/51

= 33/51 = 0.647

B ) The probability of randomly selecting a student who kept the money and given that the student was given four quarters

= p ( 18/91 | 51/91 )

= 18/91 * 91/51

= 18 /51 = 0.353

C) students are more likely to spend the money than to have kept it

Answer: Regression line equation:  [tex]\hat{y}=-1.008x+39.1704[/tex]

Step-by-step explanation:

Equation of least-squares regression line for predicting y :

[tex]\hat{y}=b_1x+b_o[/tex]

, where [tex]\text{Slope} (b_1)=r\dfrac{s_y}{s_x}[/tex] ,  [tex]\text{intercept}(b_0)=\bar{y}-b_1\bar{x}[/tex]

Given: [tex]\bar{x}=8.8,\ s_x=1.5,\ s_y=1.8,\ \bar{y}=30.3,\ r=-0.84[/tex]

Then,

[tex]b_1=(-0.84)\dfrac{ 1.8}{ 1.5}\\\\\Rightarrow\ b_1=-1.008[/tex]

Now,

[tex]b_0=30.3-(-1.008)(8.8)=30.3+8.8704\\\\\Rightarrow\ b_0=39.1704[/tex]

Then, Regression line equation:  [tex]\hat{y}=-1.008x+39.1704[/tex]

Answer:

x is approximately 53°

Answer:52.64°

Step-by-step explanation:

opp=31

hyp=39

sin x° =[tex]\frac{opp}{hyp}[/tex]

sin x°=31/39

sin x°=0.7949

x=[tex]sin^{-1} (0.7949)\\[/tex]

x=52.64

Answer:

H₀ is accepted, we don´t have evidence to claim valves produces more than 4,1 pounds/square inch

Step-by-step explanation:

Normal Distribution

Population mean   μ₀  = 4.1

Population standard deviation  σ = 0,9

Sample size   n  = 260

Sample mean     μ  =  4,2

Level of significance 0,02       α = 0,02 form z-table we find z score

z(c) = 2,05  (critical value)

Test hypothesis      

Null hypothesis                       H₀            μ  =  μ₀

Alternative hypothesis           Hₐ            μ   >  μ₀

Is a one tail-test ( to the right. Values have a mean over the population mean)

z(s) = (  μ  -  μ₀ )/ σ /√n

z(s) =  4,2 - 4,1 / 0,9/√260

z(s) = 0,1 *16,1245 / 0,9

z(s) =  1,7916

To compare  z(s)   and z(c)

z(s) < z(c)

Then  z(s) is in the acceptance region, we accept H₀

Answer:

a) The rate of change associated with the volume of the box is 54 cubic meters per second, b) The rate of change associated with the surface area of the box is 18 square meters per second, c) The rate of change of the length of the diagonal is -1 meters per second.

Step-by-step explanation:

a) Given that box is a parallelepiped, the volume of the parallelepiped, measured in cubic meters, is represented by this formula:

[tex]V = w \cdot h \cdot l[/tex]

Where:

[tex]w[/tex] - Width, measured in meters.

[tex]h[/tex] - Height, measured in meters.

[tex]l[/tex] - Length, measured in meters.

The rate of change in the volume of the box, measured in cubic meters per second, is deducted by deriving the volume function in terms of time:

[tex]\dot V = h\cdot l \cdot \dot w + w\cdot l \cdot \dot h + w\cdot h \cdot \dot l[/tex]

Where [tex]\dot w[/tex], [tex]\dot h[/tex] and [tex]\dot l[/tex] are the rates of change related to the width, height and length, measured in meters per second.

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the volume of the box is:

[tex]\dot V = (6\,m)\cdot (3\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot (3\,m)\cdot \left(-6\,\frac{m}{s} \right)+(6\,m)\cdot (6\,m)\cdot \left(3\,\frac{m}{s}\right)[/tex]

[tex]\dot V = 54\,\frac{m^{3}}{s}[/tex]

The rate of change associated with the volume of the box is 54 cubic meters per second.

b) The surface area of the parallelepiped, measured in square meters, is represented by this model:

[tex]A_{s} = 2\cdot (w\cdot l + l\cdot h + w\cdot h)[/tex]

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time:

[tex]\dot A_{s} = 2\cdot (l+h)\cdot \dot w + 2\cdot (w+h)\cdot \dot l + 2\cdot (w+l)\cdot \dot h[/tex]

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the surface area of the box is:

[tex]\dot A_{s} = 2\cdot (6\,m + 3\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m+6\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m + 3\,m)\cdot \left(-6\,\frac{m}{s} \right)[/tex]

[tex]\dot A_{s} = 18\,\frac{m^{2}}{s}[/tex]

The rate of change associated with the surface area of the box is 18 square meters per second.

c) The length of the diagonal, measured in meters, is represented by the following Pythagorean identity:

[tex]r^{2} = w^{2}+h^{2}+l^{2}[/tex]

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time before simplification:

[tex]2\cdot r \cdot \dot r = 2\cdot w \cdot \dot w + 2\cdot h \cdot \dot h + 2\cdot l \cdot \dot l[/tex]

[tex]r\cdot \dot r = w\cdot \dot w + h\cdot \dot h + l\cdot \dot l[/tex]

[tex]\dot r = \frac{w\cdot \dot w + h \cdot \dot h + l \cdot \dot l}{\sqrt{w^{2}+h^{2}+l^{2}}}[/tex]

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the length of the diagonal of the box is:

[tex]\dot r = \frac{(6\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot \left(-6\,\frac{m}{s} \right)+(3\,m)\cdot \left(3\,\frac{m}{s} \right)}{\sqrt{(6\,m)^{2}+(6\,m)^{2}+(3\,m)^{2}}}[/tex]

[tex]\dot r = -1\,\frac{m}{s}[/tex]

The rate of change of the length of the diagonal is -1 meters per second.

Answer:

Step-by-step explanation:

Total inches grown last year by matthew = 2.7inches

Total inches grown this year by Matthew = 4.4 inches

Total inches grown by Matthew over the last two years combined will be the sum of heights of matthew for both the previous year and the current year.

Total inches grown = 2.7 inches + 4.4 inches

Total inches grown over the last two years = 7.1 inches

Answer: :o I FINALLY MADE IT

(5, 2)

x = 5

y = 2

Step-by-step explanation:

First, I graphed both equations.  They meet at the points (5,2) and (2,5).  Because y < 5, the solution is (5, 2)

Hope it helps <3

Answer:

[tex]x=5\\y=2[/tex]

Step-by-step explanation:

[tex]x^2 +y^2 =29[/tex]

[tex]x+y=7[/tex]

Solve for x in the second equation.

[tex]x+y=7[/tex]

[tex]x+y-y=7-y[/tex]

[tex]x=7-y[/tex]

Plug in the value for x in the first equation and solve for y.

[tex](7-y)^2 +y^2 =29[/tex]

[tex]y^2-14y+49+y^2 =29[/tex]

[tex]2y^2-14y+20=0[/tex]

[tex]2(y-2)(y-5)=0[/tex]

[tex]2(y-2)=0\\y-2=0\\y=2[/tex]

[tex]y-5=0\\y=5[/tex]

[tex]y<4[/tex]

[tex]y=2[/tex]

[tex]y\neq 5[/tex]

Plug y as 2 in the second equation and solve for x.

[tex]x+y=7[/tex]

[tex]x=7-y[/tex]

[tex]x=7-2[/tex]

[tex]x=5[/tex]

Answer:

x =2

Step-by-step explanation:

3 = 1/2x + 1/2x + 1/2x

Combine like terms

3 = 3/2 x

Multiply each side by 2/3 to isolate x

3 * 2/3 = 2/3 * 3/2 x

2 =x

Answer:

C. -30

Step-by-step explanation:

We would have to do order of operations or P.E.M.D.A.S. So fist we would do 7 times -4 which is -28 than we would do the absolute value of -6 which is 6 so we would do -28-6 which is -34 and we would do the absolute value of 4 which is 4 and we would add it to -34 which is -30 so our final answer would be C. -30

Answer:

This is skewed torwards the right. Or in other words positively skewed distribution.

Step-by-step explanation:

All of the values are fairly close together torwards the lower range. While 50.20 is more of an outlier, so this graph would gradualy skew to the right.

Answer:

Excluded value = -7

Solution = [tex] x = \frac{5}{9} [/tex]

Step-by-step Explanation:

The excluded value is the value that will make the denominator 0.

Thus,

[tex] x + 7 = 0 [/tex]

Subtract 7 from both sides

[tex] x + 7- 7 = 0 - 7 [/tex]

[tex] x = -7 [/tex]

The excluded value is -7

Solution=>

[tex] \frac{2x}{x + 7} + \frac{3x + 1}{x + 7} = \frac{1}{2} [/tex]

[tex] \frac{2x + (3x + 1)}{x + 7} = \frac{1}{2} [/tex]

[tex] \frac{5x + 1}{x + 7} = \frac{1}{2} [/tex]

Cross multiply

[tex] 2(5x + 1) = 1(x + 7) [/tex]

[tex] 10x + 2 = x + 7 [/tex]

[tex] 10x - x = -2 + 7 [/tex]

[tex] 9x = 5 [/tex]

[tex] x = \frac{5}{9} [/tex]

Answer:

0

Step-by-step explanation:

the answer is 0

Have a great day