Algae can be used to produce oxygen by the …………………. process.
2. Suspended particles of dust, smoke and sand are called ……………….. .
3. Two examples of greenhouse gases are …………………. and …………….. .
4. …………………. or ………………… can be used to kill the disease causing microorganisms present in water.

Answers

Answer 1

1. Algae can be used to produce oxygen by the photosynthesis process.

2. Suspended particles of dust, smoke and sand are called pollutant matter.

3. Two examples of greenhouse gases are carbon dioxide and methane.

4. Disinfectant and antibiotic can be used to kill the disease causing microorganisms present in water.

Water borne Diseases

Water borne Diseases are Illnesses caused by micro-organisms in untreated or contaminated water. Some of the diseases can be less severe like diarrhea and some can be life threatening like cholera.

Most people recover from waterborne diseases on their own and only require supportive care. Some people may require antibiotics or other treatment depending on the type of pathogen or contaminant in the water and their ability to fight infections.

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Related Questions

Concentrated HCl was added to a Ca(OH)2 suspension (in water) and the precipitate dissolved. Explain this observation on the basis of a Le Chatelier's shift in the equilibrium.

Answers

When concentrated hydrochloric acid is added to a calcium hydroxide suspension, it shifts the equilibrium of the reaction to the right, so that more of the reactants are converted to the products.

Ca(OH)2 + 2HCl --> CaCl2 + 2H2O

This causes the calcium hydroxide to dissolve, as the reactants are being removed from the solution as they are converted to the products.

Le Chatelier's principle states that when a system at equilibrium is subjected to a stress, the equilibrium will shift to alleviate the stress. In this case, when concentrated hydrochloric acid is added to the calcium hydroxide suspension, it acts as a stress on the equilibrium of the reaction Ca(OH)2 + 2HCl --> CaCl2 + 2H2O.

This causes the equilibrium to shift to the right, so that more of the reactants are converted to the products and the calcium hydroxide is dissolved.

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what is the ratio of benzaldehyde to acetone in the balanced equation?

Answers

The ratio of benzaldehyde to acetone in the balanced equation is 1 : 1.

In chemistry, a balanced equation is a condition in which mass is conserved and there is an equal number of atom of each involved element on both sides of the equation.

The balanced equation between benzaldehyde and acetone is as follows:

  C₆H₅CHO + CH₃COCH₃ → C₆H₅CH(OH)COCH₃

C₆H₅CHO is benzaldehyde and CH₃COCH₃ is acetone.

As you can see, in the balanced equation, the coefficients of benzaldehyde and acetone are both 1, which means that there is a 1:1 ratio between them. This ratio means that for every molecule of benzaldehyde, there is one molecule of acetone.

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What Is The Equilibrium Constant, K, Expression For The Following Reaction?2 H2O(l) + N2O(g)=NH4NO3(s)a. K = [N20] / [NH4NO3]b. K = 1 / [N20]c. K = [N20]d. K = [NH4NO3] / [N20][H20]^2e. K = [NH4NO3] / [N20]

Answers

The correct option is Option E. The equilibrium constant, K, expression for the given reaction is [tex]K = [NH4NO3] / [N20][/tex].

The equilibrium constant, K, is a ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. It is calculated by multiplying the concentrations of the products and dividing by the product of the concentrations of the reactants, each raised to the power of their coefficients in the balanced equation.

For the given reaction: [tex]2 H2O(l) + N2O(g)=NH4NO3(s)[/tex]

The equilibrium constant expression would be:

[tex]K = [NH4NO3] / ([N20] * [H20]^2)[/tex]

Since the coefficients of the reactants are 1 for N2O and 2 for H2O, they are raised to the power of 1 and 2, respectively. The product NH4NO3 has a coefficient of 1, so it is raised to the power of 1.

Therefore, the correct option is (e) K = [NH4NO3] / [N20].

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how many allylic halides (ignoring stereoisomers) can be formed when 3-methylcyclohexene undergoes allylic halogenation with one equivalent of nbs, peroxide, and light?a. 1b. 2c. 3d. 4

Answers

3 allylic halides can be formed when 3-methylcyclohexene undergoes allylic halogenation with one equivalent of NBS, peroxide, and light. The three possible products are 1-bromo-3-methylcyclohexene, 2-bromo-3-methylcyclohexene, and 4-bromo-3-methylcyclohexene. Option C is correct.

Allylic halides are halogenated compounds that have a halogen atom directly bonded to a carbon atom that is adjacent to a carbon-carbon double bond. In other words, allylic halides are compounds that have a halogen atom attached to an allylic carbon.

These compounds are important intermediates in organic synthesis and are commonly used in the preparation of various organic compounds.

Allylic halogenation is a type of organic reaction in which a halogen atom is added to an allylic carbon adjacent to a carbon-carbon double bond. The reaction is typically carried out using a halogenating reagent such as N-bromosuccinimide (NBS) or N-chlorosuccinimide (NCS) in the presence of a radical initiator such as a peroxide or light.

Hence, C. 3d is the correct option.

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5. Which property of carbon allows it to form complex organic molecules?
A. Carbon is the lightest element.
B. Carbon is the most common element on Earth.
C. Carbon can form four bonds.
D. Carbon is the largest element. ​

Answers

The answer is c carbon can form four bonds

Oxidation of Secondary Alcohol to Ketones Lab:In my organic chemistry lab, we performed the oxidation of 2-octanol to 2-octanone. In the lab we used Ca(OCl)2 as the oxidizing agent, and water. The reaction happens in a acidic solution aa CH3COOH and CH3CN was also in the mixture, before it got extracted away and washed with Dichloromethane, NaHCO3 and water. Then Dichloromethan was evaporated away from the solution and pure 2-octanone was obtained from a fractional-destillation.Starting mass of 2-octanol = 2.987 gEnding mass of 2-octanone (after distillation) = 2.785 ga.) Write a balanced equation for the reaction:2 octanol + Ca(OCl)2\rightarrow2 octanoneFind it by using oxidation numbers.b.) Find the theoretical yield by finding the limiting reagent in the balanced equation.c.) Find the percent yield.% yield = actual yield / theoretical yield

Answers

The balanced chemical equation for the reaction is [tex]2 \mathrm{C}_8 \mathrm{H}_{18} \mathrm{O}+\mathrm{Ca}(\mathrm{OCl})_2 \longrightarrow 2 \mathrm{C}_8 \mathrm{H}_{16} \mathrm{O}+\mathrm{CaCl}_2+2 \mathrm{H}_2 \mathrm{O}[/tex] and the percentage yield is 94.88%

The balanced chemical equation is

[tex]2 \mathrm{C}_8 \mathrm{H}_{18} \mathrm{O}+\mathrm{Ca}(\mathrm{OCl})_2 \longrightarrow 2 \mathrm{C}_8 \mathrm{H}_{16} \mathrm{O}+\mathrm{CaCl}_2+2 \mathrm{H}_2 \mathrm{O}[/tex]

According to the equation the limiting reagent is [tex]\mathrm{Ca}(\mathrm{OCl})_2[/tex]

Hence theoritical yield should depend on  the amount of [tex]\mathrm{Ca}(\mathrm{OCl})_2[/tex] participating.

If 2x130 gms of 2-octanol participates in the reaction it requires 143gms of Ca(OCl)2

so if only 2.987gms of 2-Octanol is involved then:

[tex]=\frac{2.987 X 143}{2 x 130}=1.64 \mathrm{gmsofCa}(\mathrm{OCl})_2[/tex]

Based on this mass the theoretical yield of 2-octanone is given by:

Here if 43 gms of [tex]\mathrm{Ca}(\mathrm{OCl})_2[/tex] produces 256gms of 2-Octonone then 1.64 gms produces:

[tex]=\frac{1.64 x 256}{143}=2.935 g[/tex]

Hence theoretical yield of 2-octanone = 2.935gms

The percentage yield is actual yield by theoretical yield multiplied by 100

[tex]\text { Percentageyield }=\frac{2.785 X 100}{2.935}=94.88[/tex]

Therefore, the required percentage yield is 94.88%

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A spherical cavity of radius a is within a large, grounded conductor. A charge q is placed within the cavity at a distance b from the center. A) Find the potential at all points within the cavity. Use spherical coordinates with origin at the center and z axis passing through q. B) Find the electric field, E vector at all points within the cavity. What is E vector at the center of the cavity

Answers

We can imagine that there is an image charge -q located at a distance [tex]b' = a^2/b[/tex] from the center of the cavity. The potential due to the charge q and its image -q will cancel each other at the surface of the conductor, since the conductor is grounded.

A) The potential at all points within the cavity due to the charge q can be found using the formula:

V = k*q/r

where r is the distance between the point and the charge q. In spherical coordinates, we have:

[tex]r = sqrt(a^2 + b^2 - 2ab*cos(theta)*cos(phi))[/tex]

where theta and phi are the spherical coordinates of the point with respect to the origin at the center of the cavity.

The potential due to the image charge -q can be found in a similar way:

V' = k*(-q)/r'

where r' is the distance between the point and the image charge -q. In spherical coordinates, we have:

[tex]r' = sqrt(a^2 + b'^2 - 2ab'*cos(theta)*cos(phi))[/tex]

Substituting b' = a^2/b, we get:

[tex]r' = sqrt(a^2 + b^2 - 2a^2*cos(theta)*cos(phi)/b)[/tex]

The total potential at any point within the cavity is given by the sum of V and V':

[tex]V_total = V + V'[/tex]

Substituting the expressions for V and V', we get:

[tex]V_total = kq(1/r - 1/r')\[/tex]

Substituting the expressions for r and r', we get:

[tex]V_total = kq(1/sqrt(a^2 + b^2 - 2ab*cos(theta)cos(phi)) - 1/sqrt(a^2 + b^2 - 2a^2cos(theta)*cos(phi)/b))[/tex]

B) The electric field E vector at any point within the cavity is given by:

[tex]E = -grad(V_total)[/tex]

where grad is the gradient operator. In spherical coordinates, the gradient operator can be expressed as:

[tex]grad = er*(1/r)d/dr + eθ(1/r)d/dθ + eφ(1/r*sin(θ))*d/dφ[/tex]

where er, eθ, and eφ are the unit vectors in the radial, polar, and azimuthal directions, respectively.

Taking the gradient of V_total with respect to the spherical coordinates, we get:

[tex]dV_total/dr = -kq(1/r^2 - 1/r'^2)dr/d(r')[/tex]

[tex]dV_total/dθ = -kq*(1/r^2 - 1/r'^2)d(r')/dθcos(φ)[/tex]

[tex]dV_total/dφ = -kq(1/r^2 - 1/r'^2)d(r')/dφ(-sin(θ))[/tex]

Substituting the expressions for r and r' and simplifying, we get:

[tex]dV_total/dr = kq(acos(θ)cos(φ)/r^3 - a^2cos(θ)cos(φ)/(br'^3))[/tex]

[tex]dV_total/dθ = -kq*(asin(θ)cos(φ)/r^3 - a^2sin(θ)cos(φ)/(br'^3))[/tex]

[tex]dV_total/dφ = -kq*(a*cos(θ)sin(φ)/r^3 - a^2cos(θ)sin(φ)/(br'^3))[/tex]

Substituting the expressions for r and r', we get:

[tex]dV_total/dr = kq(acos(θ)cos(φ)/r^3 - a^4cos(θ)[/tex]

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A typical fluorescent light bulb contains argon gas and mercury vapor. If the total gas pressure in a fluorescent light bulb is 307.1 Pa and the partial pressure of the argon gas is 306.0 Pa, what is the partial pressure of the mercury vapor?

Answers

If the total gas pressure in a fluorescent light bulb is 307.1 Pa and the partial pressure of the argon gas is 306.0 Pa, the partial pressure of the mercury vapor is 30.71 Pa.

What is partial pressure of a gas?

The thermodynamic activity of a gas's molecules is evaluated by its partial pressure. Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

In a mixture of gases, each constituent gas has a partial pressure which is the notional pressure of that constituent gas as if it alone occupied the entire volume of the original mixture at the same temperature. The total pressure of an ideal gas mixture is the sum of the partial pressures of the gases in the mixture (Dalton's Law).

According to Dalton's Law,

P = P₁ + P₂

where,

P is the total gas pressure

P₁ is the partial pressure of Argon gas

P₂ is the partial pressure of Mercury vapor

Partial pressure of a gas is the product of total pressure and the mole fraction of the gas in the mixture.

P₁ = P × n₁

where,

n₁ is the mole fraction of argon gas

So,

n₁ = P₁/P

Substituting the values;

n₁ = 0.9

Now,

n₂ = 1 - 0.9 = 0.1

According to the formula;

P₂ = P × n₂ = 307.1 × 0.1 = 30.71 Pa

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what are some visible differences between intergrown mineral grains and clastic

Answers

Some visible differences between intergrown mineral grains and clastic are:
1) Intergrown mineral grains are tightly bonded together and do not have any visible spaces between them, while clastic have visible spaces between the grains.
2) Intergrown mineral grains have a smooth and continuous texture, while clastic have a rough and discontinuous texture.
3) Intergrown mineral grains have a uniform and consistent color, while clastic have a varied and inconsistent color.
4) Intergrown mineral grains have a crystalline structure, while clastic have a non-crystalline structure.

Overall, intergrown mineral grains have a more cohesive and uniform appearance, while clastic have a more fragmented and varied appearance. These differences can be used to distinguish between the two types of rocks and understand their formation processes.

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What is the total charge of all the electrons in a 15 kg bar of gold? (Gold has 79 electrons per atom and an atomic mass of 197 u.)

Answers

The total charge of all the electrons in a 15 kg bar of gold can be calculated by using the number of atoms in the bar and the number of electrons per atom. The mass of gold is 197 u (atomic mass unit) and the number of electrons per atom is 79. So, we can calculate the number of atoms in the bar by dividing the mass of gold (15 kg) by the atomic mass (197 u):

15 kg / 197 u = 76,154 atoms


Now we can calculate the total charge of all the electrons in the bar by multiplying the number of electrons per atom by the number of atoms in the bar:

76,154 atoms x 79 electrons per atom = 6,022,866 total electrons

Since the charge of one electron is -1.6 x 10^-19 Coulombs, the total charge of all the electrons in the 15 kg bar of gold is:


6,022,866 total electrons x (-1.6 x 10^-19 Coulombs/electron) = -9.63 x 10^-10 Coulombs

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how many grams of hno3 are in 2.105×1022 molecules of hno3? show the conversions required to solve this problem and calculate the grams of hno3.

Answers

In 2.105×10²² molecules of HNO₃, there are 2.215 grams of HNO₃

Conversion factors

To solve this problem, we will need to use the following conversions:

1 mole of HNO₃ = 6.022×10²³ molecules of HNO₃1 mole of HNO₃ = 63.01 grams of HNO₃

First, we need to convert the given number of molecules of HNO₃ to moles of HNO₃ using the first conversion factor:

2.105×10²² molecules of HNO₃ × (1 mole of HNO₃ / 6.022×10²³ molecules of HNO₃) = 3.495×10⁻² moles of HNO₃

Next, we need to convert the moles of HNO₃ to grams of HNO₃ using the second conversion factor:

3.495×10⁻² moles of HNO₃ × (63.01 grams of HNO₃ / 1 mole of HNO₃) = 2.215 grams of HNO₃

Therefore, there are 2.215 grams of HNO₃.

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. a. you need to make 250 ml of a stock solution of 0.1 m na2 atp. its formula weight is 605.2 g mol21 . how much na2 atp should you weigh out?

Answers

You should weigh out 15.13 g of Na2 ATP to make 250 mL of a 0.1 M stock solution.

How to calculate the required amount of Na2 ATP

To make 250 mL of a stock solution of 0.1 M Na2 ATP, we need to calculate the amount of Na2 ATP required using the formula weight and molarity.

The formula for this calculation is:

amount of Na2 ATP (g) = molarity (M) × volume (L) × formula weight (g/mol)

Plugging in the given values:

amount of Na2 ATP (g) = 0.1 M × 0.250 L × 605.2 g/mol

amount of Na2 ATP (g) = 15.13 g

Therefore, you should weigh out 15.13 g of Na2 ATP to make 250 mL of a 0.1 M stock solution.

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what is the actual free energy change for the reaction a b at 37 °c when △go’ = – 15 kj/mol [a] = 10mm and [b] = 0.1 mm?

Answers

The actual free energy change for the reaction a b at 37 °C when △Go' = -15 kJ/mol, [a] = 10mm, and [b] = 0.1 mm is -26.522 kJ/mol

It can be calculated using the equation △G = △Go' + RTlnQ, where R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

First, we need to convert the temperature from Celsius to Kelvin: 37 °C + 273.15 = 310.15 K

Next, we need to calculate the reaction quotient Q: Q = [b]/[a] = 0.1/10 = 0.01

Now we can plug in the values into the equation:

△G = -15 kJ/mol + (8.314 J/mol·K)(310.15 K)ln(0.01)

△G = -15 kJ/mol + (2578.6 J/mol)ln(0.01)

△G = -15 kJ/mol + (-11.522 kJ/mol)

△G = -26.522 kJ/mol

Therefore, the actual free energy change for the reaction is -26.522 kJ/mol.

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Barium ions carry a 2+ charge, and nitrogen ions carry a 3- charge. What would be the chemical formula for the ionic compound barium nitride?
Select one:
a. Ba3N2
b. Ba2N3
c. Ba3N4
d. Ba2N2

Answers

The chemical formula for the ionic compound barium nitride is a. Ba₃N₂.

What is the chemical formula of barium nitride?

To find the chemical formula for the ionic compound barium nitride, we need to balance the charges of the barium ions and nitrogen ions. Barium ions carry a 2+ charge, and nitrogen ions carry a 3- charge.

In order to balance the charges, we need to have three barium ions (3 x 2+ = 6+) and two nitrogen ions (2 x 3- = 6-). This will give us a neutral compound with no overall charge.

Therefore, the chemical formula of barium nitride is Ba₃N₂.

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what is the hybridization of the central atom in the sulfur trifluoride anion?

Answers

The hybridization of the central atom in the sulfur trifluoride anion is sp3.

Explanation:
Sulfur trifluoride anion (SF3-) has a total of 28 valence electrons (6 from sulfur, 7 from each fluorine, and 1 from the negative charge). The Lewis structure of SF3- is:

   F      F
    \   /
     S
    /
   F

The central sulfur atom is bonded to three fluorine atoms and has one lone pair of electrons. This means that the sulfur atom has a total of four electron domains (three bonding and one lone pair). According to the VSEPR theory, four electron domains correspond to sp3 hybridization. Therefore, the hybridization of the central atom in the sulfur trifluoride anion is sp3.

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according to the following reaction, how many grams of hydrogen gas will be formed upon the complete reaction of 26.8 grams of water? water (l) hydrogen (g) oxygen (g) grams hydrogen gas

Answers

3.01 grams of hydrogen gas will be formed upon the complete reaction of 26.8 grams of water.

Balanced chemical equation

According to the balanced chemical equation for the reaction of water to form hydrogen gas and oxygen gas:
2H₂O(l) → 2H₂2(g) + O₂(g)

The molar mass of water is 18.02 grams per mole, and the molar mass of hydrogen gas is 2.02 grams per mole.

Stoichiometric calculation

First, we need to convert the given mass of water into moles:
26.8 grams H₂O × (1 mole H₂O / 18.02 grams H₂O) = 1.49 moles H₂O

Next, we use the mole ratio from the balanced equation to determine the moles of hydrogen gas produced:
1.49 moles H₂O × (2 moles H₂ / 2 moles H₂O) = 1.49 moles H₂

Finally, we convert the moles of hydrogen gas into grams:
1.49 moles H₂ × (2.02 grams H₂ / 1 mole H₂) = 3.01 grams H₂.

Therefore, the correct answer is 3.01 grams of hydrogen gas.

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Intermolecular Forces and Physical Properties of Pure Substances


Which has the highest normal freezing point?

a. O2

b. N2

c. H2

d. NH3

Which has the lowest enthalpy of fusion?

a. H2O

b. Li2O

c. HCl

d. HF

Which has the least heat of vaporization?

a. H2Te

b. Xe

c. H2Se

d. H2O

Which has the highest normal boiling point?

a. C2H6

b. NH3

c. Li2O

d. CH4

Which has the smallest vapour pressure at 25°C?

a. O3

b. SiO2

c. CO2

d. H2O

Answers

1. NH₃ has the highest normal freezing point. Option d is correct.

2. The substance with the lowest enthalpy of fusion is b. Li₂O.

3. The substance with the least heat of vaporization is b. Xe.

4. C₂H₆ is substance with the highest normal boiling point. Option a is correct.

5. CO₂ is the substance with the smallest vapor pressure at 25°C. Correct choice is c.

NH₃ has hydrogen bonding which is the strongest intermolecular force among the given options. Stronger intermolecular forces lead to higher melting and boiling points.

Li₂O is an ionic compound and has a very high melting point due to strong ionic bonds. The enthalpy of fusion is the energy required to melt a solid. Since Li2O has a high melting point, it will require more energy to melt compared to the other options.

Xe is a noble gas and has weak intermolecular forces due to its large atomic size. Weak intermolecular forces lead to low boiling points and low heats of vaporization.

C₂H₆ has stronger London dispersion forces than the other options due to its larger size and higher molecular weight. Stronger intermolecular forces lead to higher boiling points.

CO₂ is a small molecule with strong London dispersion forces. Strong intermolecular forces lead to low vapor pressure.

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What mass of HClO4 should be present in 0.600 L of solution to obtain a solution with each of the following pH values? pH = 2.70? pH = 1.70? pH = 0.60

Answers

The mass of HClO4 needed for each solution is 0.120552 g for pH = 2.70, 1.20552 g for pH = 1.70, and 15.167316 g for pH = 0.60.

To obtain a solution with a specific pH value, we need to calculate the molarity of the solution using the equation: pH = -log[H+]. Then, we can use the molarity and volume of the solution to calculate the mass of HClO4 needed. The molar mass of HClO4 is 100.46 g/mol.

For pH = 2.70:
- log[H+] = 2.70
[H+] = 10^-2.70 = 0.002
Molarity = 0.002 mol/L
Mass of HClO4 = 0.002 mol/L × 0.600 L × 100.46 g/mol = 0.120552 g

For pH = 1.70:
- log[H+] = 1.70
[H+] = 10^-1.70 = 0.020
Molarity = 0.020 mol/L
Mass of HClO4 = 0.020 mol/L × 0.600 L × 100.46 g/mol = 1.20552 g

For pH = 0.60:
- log[H+] = 0.60
[H+] = 10^-0.60 = 0.251
Molarity = 0.251 mol/L
Mass of HClO4 = 0.251 mol/L × 0.600 L × 100.46 g/mol = 15.167316 g

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how much is the energy of one mole of co2 increased when it absorbs infrared radiation with a wavenumber of 2400 cm-1?

Answers

The energy of one mole of CO₂ increased when it absorbs infrared radiation with a wavenumber of 2400 cm⁻¹ is 2.869 × 10³ J/mol.

The energy of one mole of CO₂ increased when it absorbs infrared radiation with a wavenumber of 2400 cm-1 can be calculated using the equation E = hcν.

Where,
E = energy
h = Planck's constant (6.626 × 10⁻³⁴ J s)
c = speed of light (2.998 × 10⁸ m/s)
ν = wavenumber (2400 cm⁻¹ or 2.4 × 10⁴ m⁻¹)

Plugging in the values, we get:
E = (6.626 × 10⁻³⁴ J s) × (2.998 × 10⁸ m/s) × (2.4 × 10⁴ m⁻¹)
E = 4.763 × 10⁻²¹ J

Since the question asks for the energy of one mole of CO2, we need to multiply the energy of one molecule by Avogadro's number (6.022 × 10²³ mol⁻¹):
E = (4.763 × 10⁻²¹ J) × (6.022 × 10²³ mol⁻¹)
E = 2.869 × 10³ J/mol

Therefore, the energy of one mole of CO₂ is 2.869 × 10³ J/mol.

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:-:> patulong po <:-:
TRUE or FALSE
1. Gravity is a contact force that acts between two seperate objects.
2. Gravity is the force exerted by the Earth which is equivalent to the mass of the object.
3. Gravity on the Moon is less than the gravity on the Earth.
4. Friction, unlike gravity, is a non-contact force.
5. Friction keeps objects from sliding off surfaces.
6. The principle of gravity was discovered by Sir Isaac Newton.
7. Friction is the force that opposes the push of gravity on objects.
8. The lesser the mass of an object, the greater the pull of gravity on it.
9. Gravity keeps anything from going up.
10. Gravitational pull between objects increases as the distance between them decreases.

Answers

Answer:

1. FALSE

2. FALSE

3. TRUE

4. FALSE

5. TRUE

6. TRUE

7. FALSE

8. FALSE

9. FALSE

10. FALSE

A student uses 554 Joules to raise the temperature of some copper 9°C. How much copper was used?

Answers

Explanation:

The amount of copper used can be calculated using the specific heat capacity of copper and the amount of energy used to raise its temperature:

Q = mcΔT

where Q is the amount of energy used, m is the mass of copper used, c is the specific heat capacity of copper, and ΔT is the change in temperature.

The specific heat capacity of copper is approximately 0.385 J/g°C.

Substituting the given values, we get:

554 = m * 0.385 * 9

Simplifying:

m = 554 / (0.385 * 9) ≈ 166.4 grams

Therefore, approximately 166.4 grams of copper were used.

What mass of AgNO
3 (169.9 g/mol) is needed to convert 2.33 g of
Na 2 CO 3 (106 g/mol) to Ag 2 CO 3

Answers

7.48 g of AgNO₃ is needed to convert 2.33 g of Na₂CO₃ to Ag₂CO₃.

The balanced chemical equation for the reaction between AgNO₃ and Na₂CO₃ is,

2AgNO₃ + Na₂CO₃ → Ag₂CO₃ + 2NaNO₃

From this equation, we can see that two moles of AgNO₃ react with one mole of Na₂CO₃ to produce one mole of Ag2CO3.

Calculate the number of moles of Na₂CO₃ using its molar mass,

n(Na₂CO₃) = m(Na₂CO₃) / M(Na₂CO₃)

n(Na₂CO₃) = 2.33 g / 106 g/mol

n(Na₂CO₃) = 0.022 moles

Use the stoichiometry of the balanced equation to calculate the number of moles of AgNO₃ needed,

n(AgNO₃) = n(Na₂CO₃) x (2 moles AgNO₃ / 1 mole Na₂CO₃)

n(AgNO₃) = 0.022 moles x (2/1)

n(AgNO₃) = 0.044 moles

Calculate the mass of AgNO₃ needed using its molar mass,

m(AgNO₃) = n(AgNO₃) x M(AgNO₃)

m(AgNO₃) = 0.044 moles x 169.9 g/mol

m(AgNO₃) = 7.48 g

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m-Toluic acid has a pKa of 4.27. 4-Iodophenol has a pKa of 9.33. 3-Cyanophenol has a pKa of 8.61). You will need the following information: The pKa of HCl is –7; pKa of carbonic acid (H2CO3) is 6.52 and the pKa of water is 15.
Mixture A is a mixture of 4-iodophenol and m-toluic acid.
Mixture B is a mixture of 3-cyanophenol and 4-iodophenol.
Mixture C is a mixture of m-toluic acid and 3-cyanophenol.
All mixtures are dissolved in methylene chloride.
Copyright 2021. Govindarajoo, G. Rutgers, The State University of New Jersey. All rights reserved.
a) Why would reacting Mixture A with an aqueous solution of NaOH (sodium hydroxide) NOT separate one substance from the other?
Answer: The acidity of _______________________ [ Select ] ["sodium hydroxide", "sodium bicarbonate", "carbonic acid", "water", "HCl"] is _____________________ [ Select ] ["Stronger", "Weaker"] than both components so __________________ [ Select ] ["Both", "Neither"]
will be extracted into the aqueous layer.
b) Why would reacting Mixture B with an aqueous solution of NaHCO3 (sodium bicarbonate) NOT separate one substance from the other?
Answer: The acidity of _______________________ [ Select ] ["sodium bicarbonate", "sodium hydroxide", "HCl", "water", "carbonic acid"] is _____________________ [ Select ] ["Weaker", "Stronger"] than both components so __________________ [ Select ] ["Neither", "Both"]
will be extracted into the aqueous layer.
Copyright 2021. Govindarajoo, G. Rutgers, The State University of New Jersey. All rights reserved.
c) What species (among HCl, sodium hydroxide and sodium bicarbonate) could you use to separate the components of Mixture C? [ Select ] ["sodium bicarbonate", "HCl", "sodium hydroxide"]
d) What species would exist in the aqueous layer AFTER the extraction? [ Select ] ["Sodium salt of m-toluic acid", "m-toluic acid", "3-cyanophenol", "Sodium salt of 3-cyanophenol"]

Answers

HCl can be used to separate the components of Mixture C, as its pKa of -7 is much lower than that of m-toluic acid (pKa of 4.27). After the extraction, the aqueous layer would contain the sodium salt of m-toluic acid and 3-cyanophenol.

What is Cynaphenol?

Cynaphenol is a dietary supplement derived from the medicinal herb Cynanchum wilfordii. It is a powerful antioxidant that has been used for centuries in traditional Chinese medicine to treat a variety of ailments, including diabetes, arthritis, and heart problems. Cynaphenol contains a compound called cynarine, which helps to boost the body’s natural production of enzymes that fight inflammation.

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HELPP ILL GIVE BRALIEST!!!! +15 (there are 2 pictures)

Answers

Answer: Freeze-thaw weathering and Chemical Weathering

Explanation: I can't see the options, but I'll give it a go.

Physical weathering occurs when rocks are broken down into smaller pieces without changing their composition. The alternating freeze-thaw cycles in Lansing during the winter season contribute to the physical weathering of the sandstone cliffs. Water seeps into cracks and crevices in the rocks and then freezes when temperatures drop below freezing point. When water freezes, it expands, causing the rocks to crack and break apart. This process is called freeze-thaw weathering. Evidence for physical weathering can be seen in the form of small cracks and fractures on the surface of the sandstone cliffs.

Chemical weathering occurs when rocks are broken down by chemical reactions. In Lansing, the water that seeps into the sandstone cliffs contains dissolved iron, copper, and manganese. Over time, these minerals react with the sandstone, causing it to break down and dissolve. The dissolved minerals then stain the surface of the sandstone cliffs, giving them their characteristic red, green, and black stripes. Evidence for chemical weathering can be seen in the staining on the surface of the sandstone cliffs and the presence of dissolved minerals in the water that flows from the cliffs.

show by means of an equation why carbon dioxide produces an acidic solution

Answers

Carbon dioxide produces an acidic solution by the reaction of CO2 with water, which forms carbonic acid.

The equation is as follows:
CO2(g) + H2O(l) ⇌ H2CO3(aq)
H2CO3 is a weak acid and it undergoes partial dissociation into H+ ions and HCO3- ions:
H2CO3(aq) ⇌ H+(aq) + HCO3-(aq)
Thus, the solution becomes acidic due to the presence of H+ ions.

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Your team must design an area in your school where students can relax between classes. You need to choose a material for a walkway. The materials you need to consider are in the table.



Which material should you use so that the area is cool in terms of temperature?

Answers

Red bricks should be use so that the area is cool in terms of temperature. Therefore, option B is correct.

What are red bricks good for?

Construction of buildings, foundations, arches, pavement, and bridges may all be done using red bricks. They can also be employed for decorative reasons in architecture, such as landscaping and facial work.

Structures built using traditional red bricks are said to be more durable than those made of hollow blocks.

Red brick can have warm undertones of terracotta or rust. They could also be cooler and burgundy in colour.

Thus, option B is correct.

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Your question is incomplete, most probably your question is

Your team must design an area in your school where students can relax between classes. You need to choose a material for a walkway. The materials you need to consider are in the table. Which material should you use so that the area is cool in terms of temperature? PLEASE HELP!!!!

asphalt

red bricks

concrete

soil

consider the decomposition reaction of n2o5. is the average rate of change of no2 positive or negative? 2 n2o5 (g) → 4 no2 (g) o2 (g)

Answers

Based on the decomposition reaction of N₂O₅, the average rate of change of NO₂ is positive.

Determining the Average Rate of Change of NO₂ in the Decomposition of N₂O₅ Reaction.

The decomposition reaction of N₂O₅ produces 4 molecules of NO₂ and 1 molecule of O₂. Therefore, the average rate of change of NO₂ can be determined by calculating the rate of production of NO₂ -since there are no other reactions consuming it.

From the balanced equation, we see that 2 moles of N₂O₅ decompose to produce 4 moles of NO₂. Therefore, the stoichiometry of the reaction tells us that the rate of production of NO₂ is twice the rate of disappearance of N₂O₅.

Since the rate of disappearance of N₂O₅ is always positive-as the reactant is being consumed, the rate of production of NO₂ is also positive, and therefore the average rate of change of NO₂is also positive.

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an unknown metal, m, is reacted with sulfur to produce a compound with the chemical formula m2s3. what is the charge on the metal in the compound m2s3 ?

Answers

The charge on the metal in the compound m2s3 is +3.

In the compound m2s3, there are two atoms of the unknown metal, m, and three atoms of sulfur. The charge on sulfur is -2, so the total charge of the sulfur atoms is -6. Since the compound is neutral, the total charge of the metal atoms must be +6 to balance out the charge of the sulfur atoms.

Since there are two metal atoms, each metal atom must have a charge of +3 in order for the total charge of the metal atoms to be +6. Therefore, the charge on the metal in the compound m2s3 is +3.

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The pH of a basic solution is 8.11. What is [H+]? The pH of an acidic solution is 2.11. What is [H+]?

Answers

The [H+] of a basic solution with pH 8.11 is 1.0 x 10^-8 M. The [H+] of an acidic solution with pH 2.11 is 1.0 x 10^-2 M.

What is pH?

pH is a measure of the acidity or basicity of a water-based solution. It is measured on a scale of 0 to 14, with 0 being the most acidic, 7 being neutral, and 14 being the most basic. Solutions with a pH below 7 are considered acidic and solutions with a pH above 7 are considered basic. pH is important to consider in many contexts, such as when measuring the acidity of soil or water to ensure a healthy environment for plants and animals.

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What is the Lewis dot structure for CL?

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The Lewis dot structure for Cl (chlorine) is represented by a symbol for the element surrounded by seven dots, representing the seven valence electrons that chlorine has.

In this structure, the dots are arranged around the symbol in such a way that each side (top, bottom, left, and right) has at least one dot, and no side has more than two dots. This arrangement reflects the fact that chlorine has seven valence electrons, and that these electrons are distributed in a way that minimizes repulsion between them. The Lewis dot structure is a simple way to represent the valence electrons of an atom and is used to predict how atoms will bond with other atoms to form molecules.

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