All of the following can be added to a circuit to reduce electromagnetic interference, except:

A)

a capacitor.

B)

a diode.

C)

a coil.

D)

ground wires.

Answers

Answer 1
All can be added to reduce electromagnetic interference except a diode because a diode is a semi-conductor

Related Questions

n order to adjust the mix to increase the compressive strength, the water-to-cement ratio is reduced to 0.45. will the quantity of coarse aggregate increase, decrease, or stay the same?

Answers

The strength reduces as the w/c ratio rises. The typical w/c ratio needed to completely hydrate cement is 0.42.

Beyond this point, additional water makes concrete easier to work with for compaction but is not required for hydration. A larger water-to-cement ratio results in wider gaps between the cement aggregates, which affects the compaction. Consequently, rising moisture levels result in decreased concrete durability and compressive strength. In a variety of applications, mortar or concrete's fresh and hardened qualities are enhanced by chemical admixtures. Their inclusion may enable the water to cement ratio (w/c) to be decreased without compromising the mixture's workability.

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technician a says that cj-4 diesel engine lubricating oil is backward compatible with all previous diesel engine lube oil classifications. technician b says that the digit 4, in cj-4 means that the oil is suitable for 4-stroke cycle use. who is right?

Answers

Answer: The both the a and b technician are correct about the lubricating oil.

Explanation:

A lubricant, also known as lube or lubricant, is a substance that aids in reducing friction between surfaces in contact, thereby lowering the heat produced when the surfaces move. Additionally, it might be used for force transmission, the transportation of foreign objects, or the heating or cooling of surfaces. Lubricity is the quality that lowers friction.In addition to industrial applications, lubricants are used for many other purposes. Other uses include cooking (oils and fats in use in frying pans, in baking to prevent food sticking), bioapplications on humans (e.g. lubricants for artificial joints), ultrasound examination, medical examination, and sexual intercourse. It is mainly used to reduce friction and to contribute to a better and efficient functioning of a mechanism

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air is compressed at 20 psi and 70 degrees f to 150 psia in a compressor. the compressor is operated sich that the air temperature remains constant. calculate the change in the specific volume of air as it passes through this compressor.

Answers

Change in the specific volume of air = -8.51 ft³/lbm

By using the ideal gas law:

n1 = 1 mole

p1 = 20psia

T1 = 70°F

n2 = 1 mole

T1 = T2 = 70°F

Δv = v2-v1

Change in the specific volume of air = -8.51 ft³/lbm

⇒ negative sign shows that gas was compressed during this process.

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technician a says that fuel pump modules are spring-loaded so that they can be compressed to fit into the opening. technician b says that they are spring-loaded to allow for expansion and contraction of plastic fuel tanks. who is right?

Answers

According to Technician A, fuel pump modules are spring-loaded so they can be compressed to fit the aperture.

Electric fuel pumps are often mounted in the fuel tank to utilize the fuel in the tank to cool the pump and ensure a steady supply of fuel. Each injector has a spring-loaded valve that is kept closed by the force of the spring. The valve doesn't open until fuel is squirted into it. The fuel pump driver module controls the voltage supplied to the fuel pump in a vehicle. By adjusting voltage, the module ensures ideal fuel pressure and flow to the engine throughout its entire operating range.

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refrigerant-134a enters a compressor at 200 kpa as a saturated vapor with a flow rate of 0.45 m3 /min and leaves at 800 kpa. the power supplied to the refrigerant during compression process is 3 kw. what is the enthalpy of r-134a at the exit of the compressor?

Answers

The fluid's state at the outlet resembles that of a superheated vapor. The specific enthalpy's corresponding temperature is T=49.641 C.

Enthalpy is the unit used to describe the total amount of heat in a thermodynamic system with constant pressure. It's depicted as. Where E is the internal energy, P is the pressure, and E is the energy, H is defined as E + P + V. The degree of disorder in a thermodynamic system is measured by entropy. The First Law of Thermodynamics is used to model the compressor:

W+ m (h in - h out) =0

The following expression can be used to determine the mass flow rate:

The refrigerant's characteristics at the inlet are: Saturated Vapor, State

P=180 pka

Tsat=12.73

It is calculated as follows: m=0.053 kg/s

284.409 kJ/kg is the specific enthalpy at the outflow.

The fluid's state at the outlet resembles that of a superheated vapor. The specific enthalpy's corresponding temperature is T=49.641 C.

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A building may be work of art if it reflects technological, environmental and societal considerations

Answers

It is false that a construction is considered a work of art because it has technological, environmental and social considerations.

Why can a construction be considered a work of art?

A construction can be considered a work of art when its appearance and visual factor is characterized by beauty and differs from other constructions in its internal and external part. For example, the Burj Khalifa building located in Dubai is a work of art because its infrastructure is scaled and has very striking shapes for the public.

On the other hand, a self-sustaining house is not considered a work of art despite including technology to have environmental and social consideration. According to the above, it can be inferred that it is false that when a construction has a technological implementation for social and environmental considerations it is a work of art.

Note: This question is incomplete because there is some information missing. Here is the complete information:

Options

True

False

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air is compressed at 20 psi and 70 degrees f to 150 psi in a compressor. the compressor is operated such that the air temperature remains constant. calculate the change in the specific volume of air as it passes through this compressor.

Answers

dH = V dp However, I am also aware that H = CpT. The air is compressed when a force is provided by pushing the plunger in. Consequently, the air now occupies less area (as seen below).

This demonstrates a reduction in the gas's volume (although the mass of the gas remains the same). It is accurate to say that as air temperature rises, so does air volume. As the gas volume decreases, the molecules hit the walls more frequently, raising the pressure; conversely, as the volume increases, the molecules must travel farther to strike the walls, reducing the frequency with which they do so and raising the pressure.

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N 40° 30' E
Achains 21 Links 4 chains 25 LINKS
Schains 21 LINKS
OLO
5 chains
N 40° 30'E
FARM
3 chains
N 49° 30' W
ROAD
1. Determine the area of the enclosed property in square feet and acres.
2. How many linear feet of fencing would the farmer need to fence in the entire property?
3. If the land is valued at $4500.00 per hectare, what price did the farmer pay for the parcel?
4. Determine the three unidentified internal angles of the polygon.
5. Determine the bearings of the unidentified sides of the parcel.

Answers

Answer:

Omg so long i will give later

Which of these parts serves as the front-end cross structure on most vehicles?

A. Front lower rail

B. Radiator core support

C. Front upper rail

D. Apron

Answers

'Radiator core support' part serves as the front-end cross structure on most vehicles. Hence, option B 'radiator core support' is the correct answer.

What is the 'Front-End Cross Structure' of Vehicles?

The front-end cross structure of automobiles is referred to the several frontal parts that are located at the front of vehicles and that define their appearance and their effective workability and running. The radiator core support is one of the front-end cross structures that acts as extra protection for the radiator of vehicles by holding it securely in place and to the engine. If any part of the front support of the radiator core is damaged, it might interfere with the cooling system, that in turn can lead to a host of other expensive issues that are best avoided at all costs.

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a w18x65 of a992 steel is laying on its side and is being bent about its weak or y-axis. assuming the member is only supported at its ends and is simply supported, what is the maximum span length it can have before it reaches its design moment capacity based on it plastic moment due to its self-weight only? (hint: do not apply a load factor since the self-weight is well-known.)

Answers

A framework for a shared understanding of the acceptable standards when contracting for structural steel is provided by the AISC Code of Standard Practice.

What is meant by AISC?The AISC created the American Institute of Steel Construction (AISC), a company-level accreditation for the manufacture and construction of structural steel. Companies that construct steel structures, such as buildings, bridges, and the parts of bridges and highways, are eligible for this certification.IS: 2062 - General Steel Purpose Specifications.AISC Certification looks at a company's QMS as a whole, going much beyond the minimal standards for product inspection. AISC-Certified businesses must have a comprehensive QMS that addresses every aspect of fabrication or erection, from quality objectives to employee development to product delivery.All errata to earlier printings have been incorporated into the most recent version of ANSI/AISC 360-16, which was published in March 2021 (the following errata lists also include updates to other sections of the 15th Edition Steel Construction Manual).

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a half-wave rectifier circuit with a 500-q load operates from a 120-v (rms) 60-hz household supply through a 12-to-l step-down transformer. it uses a silicon diode that can be modeled to have a 0.7-v drop for any current. what is the peak voltage of the rectified output? for what fraction of the cycle does the diode conduct? what is the average output voltage? what is the average current in the load?

Answers

A sinusoidal waveform's average voltage (VAV) is calculated by multiplying the peak voltage value by the constant 0.637,which is equal to two divided by pi.

Explain about the Average output voltage?

A waveform's level that is determined by the requirement that the region enclosed by the curve above it is exactly equal to the region enclosed by the curve below it.

The amount of power averaged throughout time is referred to as average power. By averaging the instantaneous power's time throughout a single cycle, we may determine average power.

By multiplying the peak value by 0.637 or the RMS value by 0.9, average or mean voltage and current values may be derived that can be used to calculate the same amount of power consumption as for analogous DC values. When converting from AC to DC, the average or mean value is frequently utilized (rectification).

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Tech A says that the principle of thermal expansion is what pushes the piston down the cylinder on the power stroke. Tech B says that the piston is pulled down the cylinder on the intake stroke. Who is correct?

Answers

Tech A is correct because Tech A says that the principle of thermal expansion is what pushes the piston down the cylinder on the power stroke.

What motion does the compression piston make?

while the intake and exhaust valves are kept closed by valve springs, the piston advances up the cylinder during the compression stroke to pressurize the fuel/air combination. A high-tension spark from the spark plug ignites the mixture of fuel and air during the power stroke.

Note that By pushing the piston downward and expanding the chamber's capacity, the heat energy generated by combustion is put to use in the chamber. Due to the fact that this is when the thermal energy is converted into motion to power the device or vehicle, it is sometimes referred to as the "power stoke."

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the renewable composite insulation material must have the following characteristics: an overall uniform thickness less than or equal to one inch. a consistent internal composition. environmentally friendly and/or recyclable. must be economical. dimensions must not exceed the overall of the top of the heat box apparatus.

Answers

The correct anwser is that this does not exceed the overall off the top of renewable of the heat box.

Renewable Insulation introductionThe largest amount of energy consumed within the average home is related tomaintaining adequate climate control through heating and cooling systems. Toconserve energy and decrease expenses associated with climate control, properhome insulation techniques are required. Insulation technologies relating tomaterials and application have advanced throughout the home building industry withtime. The home building industry once relied on straw and newspaper for insulatingmaterial. The industry currently utilizes technology such as fiberglass and blownexpandable foam. Insulation material advancement is driven by consumersdemanding insulation material designed for high insulation value along with positiveoccupant health and environmental impact.

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Two Liquids, A and B, are mixed. A is 5% solids, the rest is water. B is 11% solids; the rest is water. To the mixture is added 18.5 kg of bone-dry solids resulting in a mixture of 2,150 Kg containing 8.25% solids. What were the original amounts of the liquids A and B? Show all work

Answers

The original amounts of the liquids A and B based on the information will be 1260kg and 872kg.

What is an equation?

An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

Based on the information given, let us call the liquids illustrated as A and B, while the weight is in kg.

The first equation is the amount of solids and this will be represented thus:

0.05A + 0.11B + 18.5 = 0.0825(2150) = 177.375

0.05A + 0.11B = 158.875

5A + 11B = 15887.5

The second equation will be represented thus:

A + B + 18.5 = 2150

Collect like terms

A + B = 2150 - 18.5

A + B = 2131.5

Multiplying the equation will be:

6B = 5230

Divide through by 6

6B / 6 = 5230 / 6

B = 872 kg

Therefore, A will be 1260 kg.

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A signal was acquired at 200 hz and the spectrum showed a peak at 70 hz. no anti-aliasing filter was used. find the 5 lowest possible frequencies that the original signal may have.

Answers

f1 = 70 Hz

f2 = 130 Hz

f3 = 270 Hz

f4 = 330 Hz

f5 = 470 Hz

-6. When we say the flip-flop is in the set condi-
_____ is at a
tion, we mean output
logical
MT
CL

Answers

The term “Flip-flop” relates to the actual operation of the device, as it can be “flipped” into one logical  Set state or “flopped” back into the opposing logical set.

A flip-flop is a device which stores a single bit (binary digit) of data; one of its two states represents a "one" and the other represents a "zero". Such data storage can be used for storage of state, and such a circuit is described as sequential logic in electronics.

STATIC RAM (SRAM) consists of flip-flops, a circuit composed of four to six transistors. Once a flip-flop stores a bit, it keeps that value until the opposite value is stored in it.

Hence, logical set is used.

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what best describes concrete? group of answer choices the matrix is cement and the particulates are sand and gravel it is a structural composite it is a laminate composite it is a fiber-reinforced composite

Answers

Pre-tensioning or post-tensioning procedures that apply compressive stress to the concrete result in prestressed concrete.

For a more flexible and long-lasting end result, steel tendons, such as high-strength wires or alloys, are stretched to reinforce the tension into the concrete substance. Families of importance and performance properties. To give the plastic a particular hue, pigments—insoluble organic or inorganic particles—are added to the polymer basis. Plasticizers are typically nonvolatile, high boiling, low molecular weight compounds that are added to a polymer to alter the mechanical properties and increase its processability, flexibility, and stretchability. Major Families & Performance Properties of Pigments. To give the plastic a particular hue, pigments—insoluble organic or inorganic particles—are added to the polymer basis.

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What polymer is a package made of?

Answers

Answer:

polyethylene

Explanation:

The elasticity of polyethylene makes it an ideal material for food packaging. Polyethylene is used extensively in the automotive industry. Polyethylene is often used for manufacturing stock poly bags, zip lock bags, bottles, food containers, food crates, stretch film, tape, pallets and plastic sheeting.

Answer:

Polythene is commonly used as a packaging material. The most common polyethylene types used in food packaging are high-density polyethylene (HDPE), low-density polyethylene (LDPE), and linear low-density polyethylene (LLDPE).

Explanation:

One of the most popular materials used in the food industry for packaging is petroleum plastics (synthetic polymers). Such polymers include polyethylene terephthalate (PET), low and high-density polyethylene (LDPE and HDPE respectively), polypropylene (PP), polyvinyl chloride (PVC), and polystyrene (PS). Paper, paperboard, and cardboard cartons are frequently used as packaging for products in stores as well as used in shipping. Corrugated cardboard, for example, has excellent structural stability for shipping, storing, and even marketing products.

part c - spherical pressure vessel a spherical pressure vessel is required to contain 1.8 m3 of compressed natural gas at 22 mpa . if the tank is made of a516 grade 60 steel with a maximum normal stress 150 mpa , what is the required thickness of the tank wall?

Answers

The required tank wall thickness is 87.7668 millimeters.

Detailed explanation:

Given:

V=1.5 m3 is the vessel's volume.

P=22 MPa compressed natural gas is contained in a spherical pressure vessel.

In the event that the tank is constructed of A516 grade 60 steel with a 150 MPa maximum normal stress.

ie omax =  150 Mpa

Solution :

The vessel's diameter is determined by,

d/2 =√3v/4[tex]\pi[/tex]

d/2 =√3*.5/4*3.14

d/2=√0.358

d/2 =1.196m

Convert into mm,

d= 1.96*1000=1196.82mm

The wall tank's thickness is determined by,

t=pd/20

t=22*1196.82/2*150

t=26330.04/300

t=87.7668

Therefore, the required thickness of the tank wall is 87.7668 mm.

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In conducting a test on the kind of music that may encourage plant growth, what practice upholds the fair test standard? A. using different kinds of plants B. giving some plants more water than others C. exposing the plants to different types of music D. using nutrient-rich soil for one and plain soil for others

Answers

In conducting a test on the kind of music that may encourage plant growth, the practice that upholds the fair test standard are:

using different kinds of plants  (Option A)giving some plants more water than others  (Option B)using nutrient-rich soil for one and plain soil for others (Option D).

What are the factors that determine plant growth?

Water, light, temperature, and nutrients are the four most important factors influencing plant development.

Plants go through the following stages: seed to sprout, vegetative, budding, blooming and maturing. Similarly, when individuals and plants develop, their dietary requirements alter.

The following are major elements influencing plant growth: Temperature: As the temperature rises, growth accelerates. Light intensity, duration, and quality all have an impact on various physiological processes that occur in plants. Water: Water is necessary for plant development.

Playing classical or jazz music stimulated growth in most plants, but harder metal music generated stress. This might be because the vibrations of metal music are too strong for plants and activate cells excessively. We compare it to massaging your plant with music; they prefer a softer touch.

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a cylindrical rod 380 mm long and having a diameter of 10.0 mm is to be subjected to a tensile load. if the rod is to experience neither plastic deformation nor an elongation of more than 0.9 mm when the applied load is 24,500 n, which of the four metals or alloys listed below are possible candidates? justify your choice(s). (2 points)

Answers

Answer:

Steel

Explanation:

Aluminium and copper alloys are not viable options because their permissible strain is less than the rod's estimated strain.

What is Strain?

When an object is stressed, the amount of deformation or lengthening is measured as strain. Strain is typically stated as a ratio or percentage of the original length, area, or volume of the object. In other terms, strain is the amount of deformation in relation to an object's initial size or shape.

Calculating the stress and strain that the cylindrical rod would encounter under the specified conditions and comparing it to the permitted stress and strain values for each material will help us choose which of the four metals or alloys listed below are likely choices.

Let's begin by determining the rod's cross-sectional area:

Area = πr^2 = π(5 mm)^2 = 78.54 mm^2

The stress can then be calculated by:

[tex]Stress = Force / Area = 24,500 N / 78.54 mm^2 = 312.5 MPa[/tex]

We must apply the following formula to determine the strain:

Elongation / Initial Length = Strain

Given that the elongation shouldn't be greater than 0.9 mm:

Strain = 0.9mm/380mm =0.00237

Now that we have the stress and strain values and the permissible values for each material, we can compare them:

Allowable strain in aluminium alloy is 0.003 and allowable stress is 275 MPa.Steel alloy: 450 MPa of stress and 0.002 of strain are permitted.Copper alloy: 205 MPa of stress and 0.0035 of strain are permitted.Allowable stress for titanium alloy is 880 MPa, while allowable strain is 0.002.

Therefore, due to their permissible stress and strain being more than or equal to that calculated for the cylindrical rod under the specified conditions, both the steel alloy and titanium alloy are potential options based on the comparison made above.

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refrigerant 134a is the working fluid in a solar power plant operating on an ideal rankine cycle. saturated vapor at 60 oc enters the turbine, and the condenser operates at a pressure of 6 bar. the rate of energy input to the collectors from solar radiation is 0.4 kw per m2 of collector surface area. determine the solar collector surface area, in m2, per kw of power developed by the plant.

Answers

The solar collector surface area, in m2, per kW of power developed by the plant is [tex]25.3 m^2/kW[/tex].

1. T1=[tex]60 ^{0}[/tex]C

H1=275.99 kJ/Kg (Enthalpy for saturated vapor [tex]60^{0}[/tex]C)

Hfg=137.42 kJ/Kg

2. P2= 6 bar

T2=21.58 C ( temperature of sat. liquid  6 bar)

H2=259.19  (enthalpy of sat. liquid  6 bar)

From the above conditions, the power generated can be found.

Wt.=H1-H2=275.99-259.19=16.8 KW )

3.After condensing:

T3=21.58 C

P3= 6 bar

4. After pump:

T4=21.58 C

the power required by the solar collector to bring the temperature of the fluid up to 60 C  and vaporize the fluid :

W=CpT + [tex]H_{fg}[/tex]

Cp= 0.857 KJ/kg

[tex]H_{fg}[/tex]=137.42

W=0.857x(60-21.58) + 137.42=170.35 KW

Area required:

A=[tex]170.35 kw/0.4 KW/m^2[/tex]

A=[tex]425.86 m^2[/tex]

Area/Power generated= A / Wt=[tex]425.86 m^2/16.8 KW[/tex]

Area/Power generated=[tex]25.3 m^2/KW[/tex]

What is solar radiation?

Solar radiation often referred to as solar energy or simply sunlight, is the general term for electromagnetic radiation emitted by the sun. Solar radiation can be captured and converted into useful forms of energy such as heat and electricity using various technologies.

Solar radiation produces heat, light and energy that all living organisms need. Infrared radiation provides heat to all habitats both on land and in water Without solar radiation, the earth would be about 32°C colder 25. Solar radiation provides the heat and light necessary for life on earth.

TYPES OF SOLAR RADIATION

Direct solar radiation. Diffuse solar radiation. Reflected solar radiation.

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a venturi meter with a 7 in diameter throat is installed in a 14 in diameter water line. the venturi is perfectly smooth, so that the discharge coefficient is 1.00. an attached mercury manometer registers a 3 in differential. what is the volumetric flow rate?

Answers

Micrometer for brake rotors. For air disc brakes, the steering axle brake lining/pad thickness must be at least 3.2 mm (1/8 inch), and for hydraulic disc, drum, and electric brakes, it must be at least 1.6 mm (1/16 inch).

Every 45° (1/8 of a rotation), take a measurement of the brake rotor thickness of 0.40 inches (10mm) inside the outside circumference of the brake rotor. 6. Compare the lowest result obtained to the brake rotor's minimum thickness requirements. Depending on the vehicle, replacement brake pads can range in thickness from roughly 3/8" to 1/2". When the pads are down to around 1/4 inch, some shops advise changing them; others advise doing so at 1/8 or when only 20 to 25 percent of the original thickness remains.

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What is the correct way to mark False Starts in Full Verbatim?

Answers

The use of double dashes is the correct way to mark False Starts in Full Verbatim.

How do you appropriately double  dashes?

Double dashes are used to distinguish the beginning and finish of a sequence that would otherwise be misunderstood. In dialogue, dashes are also used to indicate when a sentence has been cut off.

To indicate a range or that material has been incorporated into a statement, dashes can be used in place of parenthesis. Only in casual writing should dashes be used; in academic and business writing, commas, parenthesis, or colons should be used instead. A space should not come before or after a dash.

Therefore, False Starts should be marked in Full Verbatim with double dashes.

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a steam power plant operating on the simple ideal rankine cycle is considered. the heat input into the cycle is 2728 kj/kg, and the heat output is 2018 kj/kg. determine the thermal efficiency of this cycle.

Answers

The average temperature at which heat is fed to the cycle is raised, increasing the Rankine cycle's thermal efficiency. lowering the typical temperature at which the cycle rejects heat.

Power plants that employ coal or nuclear energy frequently use the Rankine cycle, also known as the Rankine Vapor Cycle. A fuel is used in this mechanism to generate heat in a boiler, turning water into steam that expands via a turbine to provide useful work. The Rankine cycle's efficiency is lower than that of a Carnot cycle operating between the same maximum and minimum temperatures because the mean temperature at which heat is provided is lower than the maximum temperature,

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tech a says that duo-servo brake shoes are only anchored on the top. tech b says that duo-servo brake shoe systems typically adjust automatically during normal brake applications in a forward direction. who is correct?

Answers

Tech A is correct. Duo-servo Brakes with the Bendix design are simple to recognize. At the top of the backing plate, they feature a single fixed anchor pin, and below the anchor is a dual-piston wheel cylinder.

Two brake shoes, referred to as the primary shoe and secondary shoe, are connected by an adjuster in the duo servo type's mechanism. Strong pressure from the primary shoe's servo effect (self-boosting effect) is transferred to the linked secondary shoe, creating a significant amount of braking force. The disadvantage of a dual servo is that it will use 80% of the braking force in reverse as opposed to a single servo's 20%, which will make it simpler to reverse your trailer.

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3. When using the Cold Saw what is the correct Water to Coolant ratio?
a.
b.
10:1
20:1
c. 15:1
d. 25:1

Answers

When using the cold saw, the correct water-to-coolant ratio should be 20:1.

What is a cold saw?

A cold saw is a sawing machine that uses a circular saw blade to cut metal.

What happens if coolant to water ratio is too high?

Having too much water will not cool the engineHaving too much antifreeze could cause your water pump to fail.

What happens if you don't add water to the coolant?

Water has minerals that can deform deposits inside the radiator and the cooling system passages of your engine. And over a long period of time, they can lead to overheating.

Therefore, in a cold saw the water-to-coolant ratio should always be 20:1.

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The two switches in the circuit seen in Fig. P7.6 are synchronized. The switches have been closed for a long time before opening at t = 0. a) How many microseconds after the switches are open is the energy dissipated in the 4 Ohm resistor 10% of the initial energy stored in the 6 H inductor? b) At the time calculated in (a), what percentage of the total energy stored in the inductor has been dissipated?

Answers

0.3 A is the calculated current. Because the sum of the currents entering and leaving the junction is equal, Kirchhoff's first law is based on the conservation of charge.

The algebraic sum of potential drops in a closed circuit must equal zero, according to Kirchhoff's second law.

The capacitors will begin charging through resistor 2 as soon as switch S is closed, and there won't be any current flowing through resistors 8 and 4.

As a result, I1=2/6

=3A,

I2=0,

and I3=0.

The charging of the capacitors will cease a long time after switch S is closed, but current will still flow through resistors 8 and 4.

Applying Kirchhoff's law, loops 1 and 2 are equal to (3/2)0.6

=0.9A and loop 3 is equal to

(0.90.6=0.3A).

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Salt in crude oil must be removed before the oil undergoes processing in a refinery. The crude oil is fed to a washing unit where freshwater fed to the unit mixes with the oil and dissolves a portion of the salt contained in the oil. The oil (containing some salt but no water), being less dense than the water, can be removed at the top of the washer. If the “spent” wash water contains 15% salt and the crude oil contains 5% salt, determine the concentration of salt in the “washed” oil product if the ratio of crud oil (with salt) to water used is 4:1.​

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QUESTION 8
Per the Machinery's Handbook, close-fitting bushings in drill jigs may increase
holes.
wear
friction
heat
damage
on the drill and cause swarf to plug up the drill

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heat

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