Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3. 0×108m/s. what are the wavelengths of these signals?

The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

Given

Let Torque = т

P = т * ω

т = P/ ω

т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)

Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.

We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.

Angular speed is the speed of the object in rotational motion.

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Answer:

Correct option is D)

Steel

Answer:

Steel gives

Explanation:

Glass: 50−90GPa

Rubber:0.01−0.1GPa

Steel:200GPa

Copper: 117GPa

The resistance is 5  Ω.

Resistance is a degree of the opposition to present day waft in an electrical circuit. Resistance is measured in ohms, symbolized via the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the connection between voltage, modern-day and resistance.

Ohm's regulation states that the voltage or capacity difference among points is without delay proportional to the modern or energy passing through the resistance, and directly proportional to the resistance of the circuit. The system for Ohm's regulation is V=IR.

Potential difference (V) = 3.0 volt

current (I) = 0.60 ampere

   V = IR

 Resistance (R) = v/I

                         = 3/0.60

                         = 5 Ω

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The change in Potential energy is =  662,292.459  J.

Here, to calculate the potential energy change we use the formula,

[tex]W= F \times d \times cos\theta[/tex]

Or, [tex]W= m\times g \times d \times cos\theta[/tex]

Here we are given,

d= Distance the car makes = 62. 2 m.

[tex]\theta[/tex] = Angle that the car make along the hill =  28. 3°

F= The amount of force affect on the car = [tex]m\times g[/tex] .

m= Mass of the car = 1234 kg.

g= Acceleration of gravity = 9.8 [tex]m/s^2[/tex]

Now we substitute the known values in the above equation,

[tex]W= m\times g \times d \times cos\theta[/tex]

Or, [tex]W= 1234 \times 9.8 \times 62.2 \times cos(28.3)[/tex]

Or, [tex]W= 662,292.459 J[/tex]

From the above calculation we can conclude that the amount of work done on the car is, 662,292.459 J.

We know, from the work energy theorem that,

The change in Potential energy = The work done on the mass.

So, From the above theorem the change in potential energy is 662,292.459 J.

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The unit vectors along the three co-ordinate axes are described as. i > j > k > 1. is D. i = j = k = 1

A vector that has a volume of 1 is a unit vector. It is also known as a direction vector because it is generally used to denote the direction of a vector. The vectors i, j, k, stand the unit vectors along the x-axis, y-axis, and z-axis respectively.

There are three essential unit vectors which are commonly employed and these are the vectors in the direction of the x, y and z-axes. The unit vector in the direction of the x-axis is i, the unit vector in the direction of the y-axis is j and the unit vector in the demand of the z-axis is k.

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Explanation:

Acceleration= 15-3/2

=6m/s²

Answer:

acceleration = [tex]\bf 6 m/s^2[/tex]

Explanation:

We can calculate the acceleration of an object using the following formula:

[tex]\boxed{acceleration = \frac{Resulatant \space\ force}{Mass}}[/tex].

The resultant force is the effective force that is being applied to an object. In this case, there is a 15N force to the right, and a 3N force to the left.

∴ Resultant force = 15N - 3N

                             = 12N

Now we can use the formula for above formula to calculate acceleration:

[tex]acceleration = \frac{12}{2}[/tex]

                    = [tex]\bf 6 m/s^2[/tex]

The total magnification will be 200x.

It quantifies the comparison of the image's size to that of the object's size. In terms of how big or little the picture is produced, it informs us about the image. The height of the picture divided by the height of the object is known as magnification. m=hiho.

Objective lens - An essential component of the microscope's optics is the objective lens. The sample, specimen, or item being examined is situated close to the microscope's objective. It plays a crucial part in imaging since it creates the initial magnified picture of the sample.

Ocular lens - The component of the microscope known as the eyepiece, or ocular lens, is responsible for enlarging the picture created by the objective so that it can be viewed by the human eye.

20x objective lens was used by specimen

10x ocular lens was also used by him.

we have to find the total magnification.

For calculating the total magnification we 'll simply do multiplication

Total Magnification = 20 × 10x

Total Magnification = 200x

So , the total magnification will be 200x .

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voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

[tex]c = \frac{c1 \times c2}{c1 + c2} [/tex]

[tex] = \frac{2 \times 4}{2 + 4} [/tex]

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

[tex] = 1.33 \times 10 {}^{ - 6} \times 8[/tex]

[tex] = 10.64 \times 10 {}^{ - 6} [/tex]

charge on 2.0μf capacitor is

[tex] \frac{Qeq}{2 \times 10 {}^{ - 6} } [/tex]

[tex] = \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} } [/tex]

=5.32v

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A process with a negative change in enthalpy and a negative change in entropy will generally be: spontaneous.

Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:

                                      ΔG = ΔH - TΔS

Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.

One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.

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The cylinder is pulled in the direction of the knob's turn. If the knob is not twisted, a latch at the end of the cylinder that extends into a recess in the doorframe stops the door from being opened.

The opposing force that is produced when two surfaces attempt to move in the same direction or in opposite directions is known as frictional force. A frictional force is primarily intended to produce resistance to the mobility of one surface over another.

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The focal length of the mirror will be 0.33 m

Focus is defined as the point through which the reflected light rays pass (or appear to pass) when incident light rays are parallel to the principal axis. It is located at the midpoint of pole and center of curvature. The distance between the pole and the focus of the mirror is called the focal length of the mirror.

F =2R or focal length of a mirror is half of its radius of curvature.

The radius of curvature of convex or concave mirror is equal to two times of the focal length of convex or concave mirror. The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature.

F = 1/R

R = 3 m (given )

F = 1 / 3 = 0.33 m

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A Final statement or concluding statement

The aspect of lighting that refers to the relative intensity of illumination is called Lightning Quality.

Based on the luminosity function, luminous intensity is a measure of the  wavelength-weighted power emitted by a light source in a specific direction per unit solid angle.

Photometry is the science of measuring visible light as it is experienced by human eyes.

The human eye can only sense light in the visible range and is sensitive to different wavelengths of light within that spectrum.

The eye is most sensitive to greenish-yellow light at 555 nm when it is acclimated for bright settings (photopic  vision).

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[tex]x = \frac{at {}^{2} }{2} + vt + x(0)[/tex]

[tex]x = \frac{20 \times (10) {}^{2} }{2} + 0 + 0 = \frac{2000}{2} = 1000 \: meters[/tex]

The kinetic energy is 1.8 × 10^ -1 J.

Rolling items each rotate and have linear (or translational) movement. consequently, they've both linear and rotational kinetic power. since the rotational kinetic strength of a rolling object depends at the inertia of the item.

The only kinetic energy involved here is rotational kinetic energy.

Kinetic Energy (Rotational) = 1/2Iω²

I = Moment of Inertia of a thin hoop =(Mass)(Radius)2

Mass = 3.0 kg

Radius = 10 cm = 0.10 m

ω = angular speed = 3.5 rad/s

Kinetic Energy (Rotational) = 1/2 * 3 * 12.25 J.

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The Kinetic energy is of thin hoop can be found out using the formulas of Rotational Kinetic Energy. The Kinetic Energy of the hoop is 18.375J.

Rolling items rotate and have linear or translational movement. consequently, they have both linear and rotational kinetic power. Since the rotational kinetic strength of a rolling object depends on the Inertia of the item.

The only kinetic energy involved here is Rotational Kinetic Energy.

Rotational Kinetic Energy = 1/2Iω²

where, I = Moment of Inertia of a thin hoop =(Mass)(Radius)²

              where, Mass of hoop, m = 3.0 kg

                           Radius of loop, R = 10 cm = 0.10 m

                           Angular speed, w= 3.5 rad/s

Since, Rotational Kinetic Energy = 1/2 × 3 × 12.25 J.

             Rotational Kinetic Energy = 18.375J

Hence, Rotational Kinetic Energy is 18.375J

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The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

                      [tex]Q=\frac{\pi Pr^4}{8\beta l}[/tex]

where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, [tex]\beta[/tex] is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.

                [tex]Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95[/tex]

                [tex]P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.[/tex]

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.

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Total distance covered is 47.1 m whereas displacement is zero.

Given,

Diameter, d = 5 m

No. of revolutions = 3

Radius, r = 5/2 = 2.5 m

To find,

Distance =?

Displacement =?

Distance covered in one revolution = 2πr

Put the values in this,

Distance = 2 × 3.14 × 2.5

               = 15.7 m

Total distance covered in 3 revolution = 3 × 31.4

                                                                = 47.1 m

Displacement is the change in the position of the object or the distance between the initial and final position.

After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.

Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.

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When we consider unguided wireless communications, we must understand the signal attenuation that occurs between transmit and receive antennas.

The information, or message, that we wish to transmit, is modulated onto a frequency carrier, which is then emitted from a transmit antenna in the form of an electromagnetic (EM) wave.

The signal power (watts) received by the antenna is much less than the transmitted power due to attenuation loss. The Friis equation (also known as the Free Space Loss, FSL equation) describes this attenuation loss.Attenuation, as treated in the Friis equation, is the spreading of power over an ever increasing surface area as it propagates away from the transmit antenna.

We can measure how much power resides in a 1 meter2 area as a function of distance from the isotropic antenna.

Power Density, Pd = Pt/(4πd2)

where the (λ/4πd)2 term is sometimes referred to as the path loss or free space loss. The following definitions are assumed:

Pt - The transmitted signal power.

λ - The wavelength of the carrier (i.e., the center frequency of the radiated signal)

d - The distance between the transmitting and receiving antennas.

We can also place the above equation into decibel format:

FSLdB = [FSL] = 20log10(4πd/l) = 20log10(4π) + 20log10(d) - 20log10(l)

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The 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy than the 5kg of 20% salt brine at 50 Degrees Celsius.

Enthalpy is defined as the total heat content of a system. The enthalpy is a measure of the total work which the system can do plus the internal energy of the system.

The enthalpy of the given solutions can be calculated as follows:

For the 3kg of 20% of salt brine at 65 degrees;

mass of salt = 3 * 20%  = 0.6 kg

specific heat capacity = 3.56kJ/kg*C

temperature change = 65°C

Enthalpy = 0.6 * 3.56 * 65

Enthalpy = 232 kJ

For the 5kg of 20% salt brine at 50 Degrees Celsius;

mass of salt = 5 * 20%  = 1 kg

specific heat capacity = 3.56kJ/kg*C

temperature change = 50°C

Enthalpy = 1 * 3.56 * 50

Enthalpy = 178 kJ

Therefore, the 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy.

In conclusion, the enthalpy or heat content of the solutions depends on the mass and temperature change.

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The frequency of the oscillation is (f)=  284.21Hz

To calculate the frequency we used the formula,

[tex]f=\frac{\omega}{2\pi }[/tex]

Here , we are given,

I= The peak current across an ac generator = 0.50 A.

V= The peak Voltage across an ac generator = 8.0 V.

C= The capacitance of the capacitor = 35 μf.

We have to find the angular frequency of  an ac generator [tex]\omega[/tex].

We know, The maximum charge of the generator is,

[tex]Q=CV[/tex]

Or,[tex]Q=(35\times 10^{-6}) \times 8.0[/tex]

Or, [tex]Q=28\times 10^{-5} C[/tex]

So, The maximum charge of the generator is (Q)= [tex]28\times 10^{-5} C[/tex]

Now, for the angular frequency we can write that,

[tex]I=\omega\times Q[/tex]

Or,[tex]\omega=\frac{I}{Q}[/tex]

Now we put the value of [tex]\omega[/tex] in the first equation , we can find that

[tex]f=\frac{\omega}{2\pi }[/tex]

Or,[tex]f=\frac{1}{2\pi } \times \frac{I}{Q}[/tex]          [Note: from above[tex]\omega=\frac{I}{Q}[/tex]]

Or,[tex]f=\frac{1}{2\pi } \times \frac{0.50}{28\times 10^{-5} }[/tex]

Or, [tex]f=284.21 Hz[/tex]

Therefore, from the above calculation we can conclude that the frequency of the oscillation is 284.21 Hz.

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Answer:

250 kts

Explanation:

is the flight restriction for BasicMed

The amount of heat generated is 654.5 joules.

q=mCΔT

Given,

m=100, C=0.385  j ⁄ g · °c,  [tex]T_{1} =18^{0}C , T_{2} =35^{0} C[/tex],

q=100*0.385*(35-18)= 654.5 j

Heat is defined as energy that is transferred to or from a thermodynamic system by means other than thermodynamic work or the movement of matter (e.g. conduction, radiation, and friction). Similar to thermodynamic work, heat transfer affects a system's surrounds in addition to the system itself; as a result, it is not a characteristic of the system alone, even while it helps to change the internal energy of the system, which is a property of the system alone. This differs from the common linguistic usage of the word "heat" as a system feature in and of itself. The quantity of energy that is transported as heat in a process is the amount of energy that has been transferred minus any thermodynamic work that has been done and any energy that has been contained in the substance being moved.

How much heat in joules will it take to raise the temperature of a 100. 0 g piece of copper from 18°c to 35°c? the specific heat capacity of copper is 0. 385 j ⁄ g · °c

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If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.

To find the answer, we need to know about the Kepler's third law of planetary motion.

                       [tex]a=1AU\\T=(1)^{3/2}=1 year[/tex]

Thus, we can conclude that, If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.

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Its Scalar projection [tex]\sqrt{2}[/tex] and Vector projection 1 (i+0j+k).

We have been given two vectors <1 -1 1> and vector <1 0 1> , we are to find out the scalar and vector projection of vector <1 -1 1> onto vector <1 0 1>

We have vector a = <1 -1 1>  and vector b = <1 0 1>

The scalar projection of vector a onto vector b means the magnitude of resolved component of vector a in the direction of vector b and is given by

The scalar projection of vector a onto vector b = [tex]\frac{vector b . vector a}{|vector b| }[/tex]

                                                                             = [tex]\frac{(1-1+1)(1+0+1)}{\sqrt{1^{2} }+0+1^{2} }[/tex]

                                                                             =[tex]\frac{1^{2} + 1^{2} }\sqrt{2}[/tex]

                                                                             = [tex]\sqrt{2}[/tex]

The Vector projection of vector a onto vector b means the resolved component of vector a in the direction of vector b and is given by

The vector projection of vector a onto vector b .

                                    = [tex]\frac{vector b . vector a}{| vector b|^{2} }[/tex] (i+0j+k)

                                   = [tex]\frac{(1-1+1)(1+0+1)}{{1^{2} }+0+1^{2} }[/tex]. (i+0j+k)

                                   =  [tex]\frac{1^{2} + 1^{2} }{\sqrt{2} }[/tex] (i+0j+k)

                                   = 1 (i+0j+k).

Thus from the above conclusion we can say that scalar projection scalar projection [tex]\sqrt{2}[/tex] and vector projection 1 (i+0j+k).  

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Answer: 12 to 19 months

Explanation:

The magnitude of the force is 1.6*10^-16 N. The direction of force is upward.

The definition of force is the push or pull that causes a massed object to change its velocity. Force is an external agent that has the power to alter a body's resting or moving position. It has a direction and a magnitude. The total amount of forces exerted on an object is referred to as the magnitude of force.

The strength of the force increases when all the force is pulling in the same direction. When force is exerted on an item from different angles, the force's strength reduces. The amount that encapsulates the force's strength is known as its magnitude.

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the speed of flywheel is 300 rpm just before a punching operation,then the speed of the flywheel immediately after the punching operation is 299.93 rpm.

The answer of the above question is as follows:

mass of the flywheel of the punching machine (m) is 300 kg .

radius of gyration of the flywheel is :

[tex]k = 600 mm \times \frac{1m}{100mm} = 6m[/tex]

work to be done against each punching by the wheel (W) is 2500J.

initial angular velocity of the flywheel is:

[tex]w = 300rpm \times \frac{ \frac{\pi}{30} \frac{rad}{s} }{1rpm} = 10 \frac{\pi \: rad}{s} [/tex]

therefore the angular speed of the flywheel immediately after punching is given by

w1 =299.93 rpm

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Disclaimer : the given question is incomplete, thus the complete question is as follows:

Question: The flywheel of a punching machine has a mass of 300 kg mass and a radius of gyration of 600 mm. each punching operation requires 2500 J of work.

(a) knowing that the speed of the flywheel is 300 rpm just before a punching,determine the speed immediately after the punching.

_______________

λ=500 nm = 500·10⁻⁹ m

c=3·10⁸ m/s

h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s

_______________

E - ?

_______________

[tex]\displaystyle \boldsymbol{E}=h\nu =h \frac{c}{\lambda} =4,14\cdot 10^{-15} \; eV\cdot s\cdot \; \frac{3\cdot 10^8\; m/s}{500\cdot 10^{-9}\; m} =2,484\; eV\approx \boldsymbol{2,5\; eV}[/tex]

By Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.

To find the answer, we have to know about Wien's distribution law.

             [tex]wavelength*T=2.898*10^{-3}mK\\wavelength=\frac{2.898*10^{-3}mK}{5800K}=499nm.[/tex]

Thus, by Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.

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The voltage is reduced by a factor of 2.

What is resistance?

                                                     R = V I.

        where,

        R is the resistance of the resistor R in ohms (Ω)

        V is the voltage   drop in the resistor in volts.

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