The overall momentum of a system is constant.
Hence, The time taken to get to the shuttle is 4.49 min.
What is the conservation of momentum ?The conservation of linear momentum is a general law of physics which states that the overall momentum of a system is constant and that the quantity called momentum which characterizes motion never changes in an isolated collection of objects.according to the linear momentum conservation theorem, we have:
M1 V1 + M2 V2 =M1 V[tex]_0[/tex]1 + M2 V[tex]_0[/tex]2.
the initial velocity is Zero
then,
M1 V1 = - M2 V2
V1 = ( - M2 V2)/ M1
V1 = - [tex]\frac{0.767 *12}{54.8}[/tex] = - 0.168 m/s
That is 0.168 m/s in the opposite direction of the camera.
the time taken to get to the shuttle is given by:
t = d/v
t = [tex]\frac{45.3}{0.168}[/tex] = 269.64 s
[tex]t_{min} =\frac{269.64}{60}[/tex] = 4.49 min.
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a hydrogen balloon rises up when released. within a short period of time, the balloon expands and does a work of 6000 j to the outside environment. during the same period of time, it also loses 12000 j of heat. how much does the internal energy of the balloon changes?
It's internal energy decreases of 18000J.
ΔQ = ΔU + ΔW
-12000J = ΔU + 6000
ΔU = - 18000J
Internal energy is the energy attributed to the disorderly, haphazard motion of molecules. It refers to the intangible microscopic energy on the atomic and molecular levels, which is distinct in scale from the macroscopic organised energy connected to moving objects. A glass of water that is at normal temperature and is resting on a table, for instance, has no discernible potential or kinetic energy. Although it is a seething mass of molecules moving at hundreds of metres per second at the microscopic level. When we superimpose an ordered big scale motion on the water as a whole, this tiny energy would not necessarily alter if the water were thrown across the room.
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how much work is done when a 125 g tomato is lifted 13.6 m ? express your answer with the appropriate units.
Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .
What do you understand by work done?The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.
Work can be calculated by multiplying force with distance in the direction of force , and can be written as :
W = F × d
Given m= 125g = 0.125 kg
h= 13.6 m
W= P E
= m *g *h
= 0.125 * 9.8 * 13.6
Work done = 16.66 J
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A 1.5 kg block is pulled across a horizontal surface that has a coefficient of kinetic friction of 0.60. What is the acceleration of the block?
Answer:
Therefore the acceleration of the block is 6m/s.
Yet some men say in many parts of England that king Arthur is not dead, but had by the will of our Lord Jesu into another place. And men say that he shall come again, and he shall win the Holy Cross. Yet I will not say that it shall be so, but rather I would say: here in this world he changed his life. And many men say that there is written upon his tomb this verse: HIC IACET ARTHURUS, REX QUONDAM REXQUE FUTURUS (Here lies Arthur, the once and future king. )A. ) This passage ends the Morte Darthur by holding out the possibility that Arthur may one day return. B. ) This passage ends with romance displacing history. C. ) This passage evinces Malory’s nostalgia for the past. D. ) Both A and C. E. ) A, B, and C
However, some people in many regions of England claim that King Arthur is still alive and has only been transferred by the will of our Lord Jesus to another location. They also assert that he will return and claim the holy cross.
What a name is King Arthur
He was a warrior, a knight, and a king who defeated giants, witches, and other creatures while leading a group of brave adventurers on numerous perilous journeys. He is renowned for bringing the peoples of his realm together and for his Knights of the Round Table. Even though he met a horrible end, he is still revered and honored today in every country. Although some historians suggest that King Arthur was a real warrior who led British armies against Saxon invaders in the sixth century, historians cannot corroborate his existence. Up until his son Mordred reveals the relationship between his queen and best friend, Arthur continues to be a decent and honourable king. Throughout all of these tales, Guinevere is either kidnapped by a villainous lord and must be freed, or other ladies are in need of a brave knight's help
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a satellite moves on a circular earth orbit that has a radius of 6.7 x 106 m. a model airplane is flying on a 15-m guideline in a horizaontal circle. the guideline is parallel to the ground. find the speed of the plane such that the plane and the satellite have the same centripetal acceleration.
The speed of the plane will have a factor of 0.668 with the satellite speed at the same centripetal acceleration.
We need to know about centripetal acceleration to solve this problem. The centripetal acceleration depends on the angular velocity and the radius. It can be written as
a = v² / R
where a is centripetal acceleration, v is velocity and R is radius.
From the question above, the given parameters are
R1 = 6.7 x 10⁶ m
R2 = 15 m
a1 = a2
By substituting the given parameters, we can calculate the speed of plane
a1 = a2
v1² / R1 = v2² / R2
v2² / v1² = R1 / R2
v2² / v1² = 6.7 x 10⁶ / 15
v2² / v1² = 6.7 x 10⁶ / 15
v2/v1 = 0.668
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after a day of testing race cars, you decide to take your own 1550-kg car onto the test track. while moving down the track at 10.0 m/s, you uniformly accelerate to 30.0 m/s in 10.0 m/s. what is the average net force that the track has applied to the car during the 10.0-s interval?
Average net force that the track has applied to the car during 10.0 sec is 3100 Newton.
In the given question we have,
mass of testing Car = 1550 kg
initial velocity of car on test track = 10.0 m/sec
final velocity of car on test track = 30.0 m/sec
Net force that track has applied to car (F) = m × a
where m ----> mass of car
a ----> acceleration
firstly, we shall find out the value of acceleration.
Using the relation formula between initial velocity, final velocity and acceleration
v - u = at
where, v---> final velocity
u---> initial velocity
a---> acceleration
t-----> time
given , v = 30m/sec , u= 10m/sec , t = 10 sec
10× a = 30 - 10 = 20 => a = 2m/sec²
So, Net force = mass × acceleration
F = 1550×2 = 3100 Newton
Hence, the net force applied on car during 10.0 sec interval is 3100 Newton.
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an electron is released within a uniform electric field of a magnitude of 28,000 n/c generated by two parallel plates. the plates are separated by 4 cm. if the electron has moved across the entire gap between the plates, what is its speed?
Within a uniform electric field of magnitude 28,000 n/c produced by two parallel plates, an electron is expelled at a speed of 3.51 * 10^15 m/s^2. The distance between the plates is 4 cm.
The electron is a subatomic particle with the symbol e or with an electric field of one elementary negative charge. Due to their lack of known components or substructure, electrons, which are part of the first generation of the lepton particle family, are typically considered to be elementary particles. When the electric field strength at the electron's location, E, is taken into account, the force acting on it has the size F=eE. Newton's second law provides the electron's acceleration as follows:
a= F/m = eE/m
= (1.60*10^-19)(2.00*10^4)/9.11*10^-31
= 3.51 *10^15 m/s^2
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A car traveling at 5m/s brakes and skids through a displacement of 6m. if it slows down at the rate of 2m/s/s, determine the length of time during which it breaks.
When a car travels at 5m/s and brakes at the rate of 2 m/s², the length of time to travel 6 m is 2 or 3 seconds.
Use the equation of motion for deceleration:
s = u . t - 1/2. a t²
Where:
s = distance
u = initial velocity
t = travel time
a = acceleration (minus sign means deceleration)
Parameters given in the problem:
s = 6 m
u = 5 m/s
a = 2 m/s²
Plug these parameters into the formula:
6 = 5t - 1/2. 2 . t²
t² - 5t + 6 = 0
(t - 3) (t - 2) = 0
t = 3 or t = 2
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a horizontal meter stick has a mass of 213 g.213 g. three weights ride on the meter stick: 259 g259 g at 41.3 cm,41.3 cm, 193 g193 g at 75.5 cm,75.5 cm, and 207 g207 g at 90.3 cm.90.3 cm. at what location on the meter stick would the system be in balance if it were suspended there?
To find about the suspended, learn suspended and suspended particles.
What is suspension?
A heterogeneous mixture called a suspension is one in which the solid components are dispersed throughout the liquid without actually dissolving in it. A homogeneous mixture of particles with a diameter greater than 1000 nm and that are visible to the unaided eye is referred to as a suspension.
What is suspended particle?
Finely divided solids or liquids, known as suspended particulate matter (SPM), may be released into the atmosphere as a result of industrial processes, natural processes, or human activity.
Xcm= mini/mi
⇒ (259)(41.3)+(193)(75.5)+(207)(90.3)/259+193+207
⇒10696.7+14571.15+18692.1/659
⇒Xcm=66.707 cm
Therefore, the suspended balance is 66.707 cm.
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A 10,764.0 kg and a 12,008.0 kg object has a force of attraction of 0.0000630000 N. How far away are they from each other?
The distance between the two masses of 10764 kg and 12008 kg, with a force of attraction of 0.00006 N cating on them is 36.99 m.
What is distance?Distance can be defined as the length between two points.
To calculate the distance between the masses, we use the formula below.
Formula:
r = √(GMm/F)............ Equation 1Where:
r = Distance between the massesM = First massm = Second massG = Universal constantF = Force of attraction.From the question,
Given:
M = 10764 kgm = 120080 kgF = 0.000063 NG = 6.67×10⁻¹¹ Nm²/kg²Substitute these values intoe quation 1
r = √[(10764×120080×6.67×10⁻¹¹)/0.000063]r = 36.99 mHence, the distance between the masses is 36.99 m.
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