An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 2775 feet and Plane B is just taking off. Plane A is gaining altitude at 25. 25 feet per second and Plane B is gaining altitude at 80. 75 feet per second

(b) 734.0 ft-lbs of work is done.

To find the work done by the force, we need to use the formula:

Work = force x distance x cos(θ)

where:

force = 56 pounds (the given constant force)

distance = 16 feet (the distance the door is being pulled)

θ = 35 degrees (the angle between the force and the displacement of the door)

We need to convert the angle to radians to use it in the formula:

theta = 35 degrees x (pi/180) = 0.6109 radians

Now we can substitute the values into the formula:

Work = 56 pounds x 16 feet x cos(0.6109 radians)

Work = 734.0 ft-lbs (rounded to one decimal place)

Therefore, the answer is (b) 734.0 ft-lbs.

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The quadratic equation that does not have a real solution is −9x² + 8x − 8 = 0. Then the correct option is C.

A quadratic equation does not have a real solution when its discriminant (b² - 4ac) is negative. Therefore, we can find which of the given equations does not have a real solution by calculating the discriminant for each equation.

a) 9x² + 6x + 1 = 0

D = b² - 4ac

D = 6² - 4(9)(1)

D = 36 - 36

D = 0

Since the discriminant is not negative, this equation has two real solutions.

b) −7x² + 8x = 0

D = 8² - 4(-7)(0)

D = 92

Since the discriminant is not negative, this equation has two real solutions.

c) −9x² + 8x − 8 = 0

D = 8² - 4(-9)(-8)

D = -224

Since the discriminant is negative, this equation has two non-real solutions.

d) 4x² − 8x + 4 = 0

D = (-8)² - 4(4)(4)

D = 64 - 64

D = 0

Since the discriminant is zero, this equation has one real solution (a double root).

Therefore, the quadratic equation that does not have a real solution is option (a) 9x² + 6x + 1 = 0.

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Kate will have a total of 38 dollars after 8 hours of work

Kate already has 5 dollars

Every hour (x) that she works, she makes 6 dollars

The total number of dollars that Kate will make after working for 8 hours can be calculated as follows

= 5 × 6

= 30

= 30 + 8

= 38

Hence Kate will make 38 dollars after working for 8 hours

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The value of x that makes the equation true is x = 16/9.

To solve for x in the equation 27=13(6x−9)+3x, we first simplify the right-hand side by distributing the 13:

27 = 78x - 117 + 3x

Then, we can combine like terms by adding 117 to both sides:

144 = 81x

Finally, we isolate x by dividing both sides by 81:

x = 144/81 = 16/9

This means that if we substitute x = 16/9 into the original equation, both sides will be equal.

In the context of the problem, this value of x represents the solution that satisfies the equation. It indicates that the given equation is consistent and has a unique solution for x.

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∫∫∫ x² dv over the region e is (3/40) a⁵ π².

What is volume?

A volume is simply defined as the amount of space occupied by any three-dimensional solid. These solids can be a cube, a cuboid, a cone, a cylinder, or a sphere. Different shapes have different volumes.

To use spherical coordinates, we need to express the volume element dv in terms of ρ, θ, and φ, where ρ is the radial distance from the origin, θ is the angle in the xy-plane measured from the positive x-axis, and φ is the angle measured from the positive z-axis.

We have x² = ρ² sin²(φ) cos²(θ). The volume element dv can be expressed as dv = ρ² sin(φ) dρ dφ dθ.

The region e is bounded by the xz-plane and the hemispheres y = ±√(a² - x²), where a > 0.

Since we're only interested in the part of e that lies in the first octant, we can restrict θ to the range [0, π/2] and φ to the range [0, π/2].

Note that since y is always positive in the first octant, we don't need to consider the negative hemisphere.

So, the integral we need to evaluate is:

∫∫∫ x² dv

= ∫[0,π/2]∫[0,π/2]∫[0,a] (ρ² sin³(φ) cos²(θ)) ρ² sin(φ) dρ dφ dθ

= ∫[0,π/2]∫[0,π/2]∫[0,a] ρ⁴ sin⁴(φ) cos²(θ) dρ dφ dθ

= ∫[0,π/2]∫[0,π/2] [(1/5)ρ⁵ sin⁴(φ) cos²(θ)]|[0,a] dφ dθ

= (1/5) a⁵ ∫[0,π/2] cos²(θ) dθ ∫[0,π/2] sin₄(φ) dφ

= (1/5) a⁵ [(1/2)π] [(3/4)(π/2)] = (3/40) a⁵ π².

Therefore, ∫∫∫ x² dv over the region e is (3/40) a⁵ π².

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Answer:

5

Step-by-step explanation:

Given a=12 and c=13,

b = 5

∠α = 67.38° = 67°22'48" = 1.17601 rad

∠β = 22.62° = 22°37'12" = 0.39479 rad

h = 4.61538

area = 30

perimeter = 30

inradius = 2

circumradius = 6.5

ans. option (a) 4

we take components of 4[tex]\sqrt{2}[/tex]

so 4[tex]\sqrt{2}[/tex] sin 45

putting values we get 4[tex]\sqrt{2}[/tex] /[tex]\sqrt{2}[/tex]

thus the answer is 4

The addition of the surds is determined as 11√19 + 38√71 + 51√13.

The surds can be added by simplifying each term as follows;

11√19 + 38√71 + 19√13 + 16√52

= 11√19 + 38√71 + 19√13 + 16(2√13)

= 11√19 + 38√71 + 19√13 + 32√13

So we will the similar terms as follows;

= 11√19 + 38√71 + (19√13 + 32√13)

= 11√19 + 38√71 + 51√13

Thus, the addition of the surds is determined by simplifying complex term to the lowest possible term.

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The area of the largest equilateral triangle that can be inscribed in a square of side length 1 unit is (1/4) * √3 square units.

To find the area of the largest equilateral triangle that can be inscribed in a square of side length 1 unit, follow these steps:

1. Draw an equilateral triangle inside the square with one of its vertices touching the midpoint of the bottom side of the square, and the other two vertices touching the midpoints of the other two sides.

2. The height (h) of the equilateral triangle can be found using Pythagorean theorem. Since the triangle is equilateral, it can be split into two 30-60-90 right triangles. In this case, the shorter leg (a) is half the side length of the square (1/2), and the longer leg (b) is the height of the equilateral triangle (h).

3. In a 30-60-90 triangle, the ratio of the sides is a:b:h = 1:√3:2. Therefore, we can write the equation:

1/2 : h : 1

4. To find the value of h, we can set up the proportion:

(1/2) / h = 1 / √3

5. Cross-multiply to solve for h:

h = (1/2) * √3

6. Now we can find the area (A) of the equilateral triangle using the formula:

A = (1/2) * base * height

In this case, the base is the side length of the square (1 unit) and the height is h:

A = (1/2) * 1 * ((1/2) * √3)

7. Simplify the expression:

A = (1/4) * √3 square units

So, the area of the largest equilateral triangle that can be inscribed in a square of side length 1 unit is (1/4) * √3 square units.

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Based on the simple linear regression results for the car's mileage, we can estimate the effect of octane levels on the car's performance.

Using a 71% confidence interval and rounding to 3 decimal places, we can say with some confidence that the impact of octane levels on the car's mileage is between -0.045 and 0.102.

This means that while there is some correlation between octane levels and mileage, the effect is relatively small and falls within a narrow range of values. It's worth noting that there may be other factors at play that influence the car's performance, so this result should be interpreted with caution.

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If we plug in n = 1, 2, 3, ..., we get the terms of the sequence as follows:

a(1) = 5(1) + 15 = 20

a(2) = 5(2) + 15 = 25

a(3) = 5(3) + 15 = 30

a(4) = 5(4) + 15 = 35

and so on.

Binomial refers to a type of probability distribution that describes the number of successes in a fixed number of independent trials, where each trial has only two possible outcomes (success or failure) and the probability of success is constant across all trials.

a) The given sequence increases by 5 with each term. Therefore, the formula to generate this sequence is:

a(n) = 5n + 1,

where n ≥ 1

So, if we plug in n = 1, 2, 3, ..., we get the terms of the sequence as follows:

a(1) = 5(1) + 1 = 6a(2) = 5(2) + 1 = 11

a(3) = 5(3) + 1 = 16

a(4) = 5(4) + 1 = 21

a(5) = 5(5) + 1 = 26

and so on.

b) The given sequence increases by 5 with each term.

Therefore, the formula to generate this sequence is:

a(n) = 5n + 15,

where n ≥ 1

So, if we plug in n = 1, 2, 3, ..., we get the terms of the sequence as follows:

a(1) = 5(1) + 15 = 20

a(2) = 5(2) + 15 = 25

a(3) = 5(3) + 15 = 30

a(4) = 5(4) + 15 = 35

and so on.

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Using permutation, there are 8 ways to arrange the letters of "millimicron" in order.

What is permutation?

A permutation is a way of arranging objects in a specific order. In mathematics, a permutation of a set is a bijection from the set to itself, where a bijection is a function that maps each element of the set to a unique element of the same set and vice versa.

To find the number of distinguishable ways the letters of the word "millimicron" can be arranged in order, we can use the method of example 9.5.11.

First, we count the number of times each letter appears in the word:

There are 2 "m"s

There are 2 "i"s

There are 2 "l"s

There is 1 "c"

There is 1 "r"

There is 1 "o"

There is 1 "n"

Then, we compute the number of permutations for each group of letters with the same count. The number of permutations of n items, where there are k items of one type, l items of another type, and so on, is given by:

n! / (k! l! ...)

Using this formula, we get:

There are 2! = 2 permutations of the "m"s

There are 2! = 2 permutations of the "i"s

There are 2! = 2 permutations of the "l"s

There is 1! = 1 permutation of the "c"

There is 1! = 1 permutation of the "r"

There is 1! = 1 permutation of the "o"

There is 1! = 1 permutation of the "n"

Therefore, the total number of distinguishable ways the letters of the word "millimicron" can be arranged in order is:

(2!)(2!)(2!)(1!)(1!)(1!)(1!) = 8

So there are 8 ways to arrange the letters of "millimicron" in order.

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The Delphi method is not a quantitative forecasting method.

What is statistics?

Statistics is the branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of data. It involves the use of mathematical methods to gather, summarize, and interpret data, which can be used to make decisions or draw conclusions about a population based on a sample of that population.

The Delphi method is a qualitative forecasting technique that involves obtaining expert opinions through a series of structured questionnaires or interviews.

It is often used in situations where there is a lack of historical data or when the future is uncertain.

The Delphi method is particularly useful when forecasting complex or novel events or when multiple sources of information need to be synthesized.

In contrast, the moving average model, classical decomposition, and simple regression are all quantitative forecasting methods that rely on historical data and statistical analysis to make predictions.

The moving average model uses a rolling average of past data to make predictions, while classical decomposition breaks down a time series into its components (such as trend, seasonality, and irregularity) to model each component separately.

Simple regression, on the other hand, uses a linear equation to model the relationship between two variables and make predictions based on that relationship.

Hence, The Delphi method is not a quantitative forecasting method.

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Divide the number of percent changes that fall within the range by the total number of percent changes to get the percentage.

What is percentage?

Percentage is a way of expressing a number or proportion as a fraction of 100. It is represented by the symbol "%".

To find the percentage of percent changes that is 1 standard deviation away from the mean in Excel, you can follow these steps:

1. Enter the percent changes in a column in Excel.

Calculate the mean of the percent changes using the AVERAGE function.

2. Calculate the standard deviation of the percent changes using the STDEV.S function.

3. Calculate the lower and upper bounds of the range that is 1 standard deviation away from the mean. To do this, subtract the standard deviation from the mean to get the lower bound, and add the standard deviation to the mean to get the upper bound.

4. Use the COUNTIF function to count the number of percent changes that fall within the range of 1 standard deviation away from the mean.

Therefore,  Divide the number of percent changes that fall within the range by the total number of percent changes to get the percentage.

Here's an example formula:

=COUNTIF(A2:A10,">="&B1-STDEV.S(A2:A10)," <="&B1+STDEV.S(A2:A10))/COUNT(A2:A10)*100

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The probability is 0.6480.

The probability is 0.9629.

1. This can be computed using the standard normal distribution as follows:

z = (70 - 69.0) / 2.8 = 0.357

Using a standard normal table or calculator, we find that P(Z ≤ 0.357) ≈ 0.6480. Therefore, the probability that a male passenger can fit through the doorway without bending is approximately 0.6480.

2. = 2.8/√25 = 0.56 inches.

We want to find P(x < 70), which is the probability that the mean height of the 25 men is less than 70 inches. This can be standardized using the standard normal distribution as follows:

z = (70 - 69.0) / 0.56 = 1.79

Using a standard normal table or calculator, we find that P(Z < 1.79) ≈ 0.9629. Therefore, the probability that the mean height of the 25 men is less than 70 inches is approximately 0.9629.

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For a 3×3 matrix A, with the real eigenvalue is 2 and two complex conjugate eigenvalues, the complex conjugate eigenvalues of matrix A are equal to 1 ± i.

Eigenvalues are defined as a special set of scalar points that is associated with set of linear equations and matrix equations. We have a matrix A of order 3×3. It has real and complex eigenvalues. As we know number of eigenvalues for 3×3 matrix are 3. The real eigenvalue, λ

= 2

Number of complex eigenvalues= 2

Also, the determinant of matrix A, det(A) = 50

Trace of matrix A, tr(A) = 8

We have to determine the complex eigenvalues.

The characteristic polynomial for 3×3 is written as below, f( λ )= det(A − λI3 )= −λ³ + 4λ² - 6 λ + 4.

For eigenvalues, −λ³ + 4λ² - 6 λ + 4 = 0

Now, one of eigenvalue of matrix is 2, λ = 2. Using the synthesis division, for calculating the remaining, follow the steps present in above figure. In the last step of division we get a quadratic equation, -λ² + 2λ - 2 = 0, solve it by quadratic formula, [tex]λ = \frac{-2 ± \sqrt{ 2² - 4 (-2)(-1)}}{2(-1)}[/tex]

[tex]= \frac{-2 ± \sqrt{4 - 8 }}{-2}[/tex]

=> λ = 1 ± i

Hence, required values are 1 ± i.

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Angle DEI is equal to the sum of angles DEF and EIG. therefore, the measure of DEI is  136°. The theorem used to solve this problem is the Angle Addition Postulate.

Based on the given information, we can determine the measure of angle EIG and angle EIH as follows:

Since IG ⊥ EG, we know that angle EIG is a right angle. Therefore, angle DEI is equal to the sum of angles DEF and EIG:

∠DEI = ∠DEF + ∠EIG = 46° + 90° = 136°

Similarly, since IH ⊥ EH, we know that angle EIH is a right angle.

The theorem used to solve this problem is the Angle Addition Postulate, which states that the measure of an angle formed by two adjacent angles is equal to the sum of the measures of the two adjacent angles.

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Each monthly payment will be approximately $20.50, which includes the principal amount of $166 and the finance charge of 8.1% simple annual interest.

To find the amount of each monthly payment for the stereo system, we need to take into account the finance charge of 8.1% simple annual interest. Since the payments are made monthly, we need to convert this to a monthly interest rate by dividing by 12, which gives us an interest rate of 0.675% per month (8.1%/12).

The balance of the stereo system after the down payment is $213 - $47 = $166. This is the amount that Anthony will be paying off in 12 equal monthly payments.

To find the amount of each payment, we can use the formula for the present value of an annuity:

PV = P * (1 - (1 + r)⁻ⁿ) / r

where PV is the present value of the annuity (the amount Anthony owes), P is the payment amount, r is the monthly interest rate (0.675%), and n is the number of payments (12).

Substituting the values we have, we get:

166 = P * (1 - (1 + 0.00675)⁻¹²) / 0.00675

Simplifying this equation, we get:

166 = P * 8.0951

Dividing both sides by 8.0951, we get:

P = 166 / 8.0951

P ≈ $20.50

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If a carpet leaves a uniform margin of "x" meters around it, then the value of x is 1.

The dimensions of the carpet are 5 meter by 3 meter,

If the carpet leaves a "uniform-margin" of "x" meter, around it,

which means that, the length of the room is = 5 + x + x = (5+2x) meter,

The width of the room is = 3 + x + x = (3+2x) meter,

So, Area of the margin is = 20 meter square, and is calculated as :

Area of Margin is = (Area of room) - (Area of Carpet);

Substituting the values,

We get,

⇒ 20 = (5+2x)(3+2x) - 15;

⇒ 35 = (5+2x)(3+2x);

⇒ 35 = 15 + 10x + 6x + 4x²,

⇒ 35 = 15 + 16x + 4x²,

⇒ 0 = 4x² + 16x - 20,

⇒ 4x² + 16x - 20 = 0

⇒ 4x² + 20x - 4x - 20,

⇒ 4x(x+5) -4(x+5) = 0,

⇒ (4x-4)(x+5) = 0

⇒ 4x = 4   or    x = -5,

⇒ x = 1  or x = -5, since the length cannot be in negative,

Therefore, the value of "x" is 1.

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The given question is incomplete, the complete question is

EFGH is a rectangular floor of a room in which a carpet 5m by 3m is laid, leaving a uniform margin of x meters round it. If the total area of the margin is 20m square find the value of x​.

The area of the base of Barbara's woodshed is 72 square feet.

To find the area of the base of Barbara's woodshed, we need to know the shape of the base. In this case, the base is in the shape of a rectangle. A rectangle is a four-sided figure with opposite sides parallel and equal in length.

To calculate the area of a rectangle, we need to multiply its length by its width. In this case, the length of the rectangle is 12 feet, and its width is 6 feet. So, the area of the base of the woodshed is:

Area = Length x Width

Area = 12 ft x 6 ft

Area = 72 square feet

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Complete Question:

Barbara built a woodshed. She made the base of the woodshed in the shape of the drawing. What is the area of the base of Barbara's woodshed? Include the unit. When the dimensions are given as 12 ft,6 ft, 11 ft and 7 ft.

Answer: 361

Step-by-step explanation:

Answer:

The answer would be 179832 Centimeters

Step-by-step explanation:

Answer: mt rushmore is 5,725 ft

Step-by-step explanation:

The correct answer is (B) t = 900V / (6V + 7).

To solve for t as a function of V, we can rearrange the given equation as:

V = 900t / (6t + 7)

Cross-multiplying and simplifying, we get:

6tV + 7V = 900t

Rearranging, we get:

6tV - 900t = -7V

Factoring out t on the left side, we get:

t(6V - 900) = -7V

Dividing both sides by (6V - 900), we get:

t = -7V / (6V - 900)

Multiplying numerator and denominator by -1, we get:

t = 7V / (900 - 6V)

Simplifying, we get:

t = 900V / (6V + 7)

Therefore, the equation that expresses t as a function of V is t = 900V / (6V + 7), which is option (B).

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The value of x in the given figure consists of Central angle and Inscribed Angle is given by, x = 2.

We know that the inscribed for a semi circle is 90 degrees.

Clearly the inscribed angle for the given figure is 90 degrees.

And rest angles of the inscribed triangle are (11x - 4) and (16x + 40) degrees.

So, the sum of the rest angles must be 90 degrees too since the sum of all interior angles of triangle is 180 degree according to the Angle Sum Property of a Triangle.

So, (11x - 4) + (16x +40) = 90

11x + 16x + 40 - 4 = 90

27x + 36 = 90

27x = 90 - 36

27x = 54

x = 54/27

x = 2

Hence the value of x is given by, x = 2.

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In order to determine the following three terms in the geometric series [tex]8, 24, 72, 216[/tex],..., we must first determine the common-ratio (r):

A geometric-sequence is a set of integers where each phrase following the first is obtained by multiplying the term before it by a fixed quantity known as the common- ratio (r).

Mathematical, scientific, and financial fields all use geometric sequences extensively. They can be used, for instance, to simulate population increase, radioactive isotope decay, asset depreciation, and the calculation of compound interest.

[tex]r = (24 / 8)[/tex]

[tex]r = (72 / 24)[/tex]

[tex]r = (72 / 24)[/tex]

[tex]r = (72 / 24)[/tex]

Consequently, the sequence's common ratio is [tex]3[/tex].

Following three terms are:

[tex]648 (216 * 3)[/tex]

[tex]648 (216 * 3)[/tex]

The finished sequence is thus [tex]8, 24, 72, 216, 648, 1944[/tex], and[tex]5832.[/tex]

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In 2020, the number of connections per person in North America was 1.4, while in the Asia-Pacific (APAC) region, it was 1.1. To determine the number of unique users in each region, we need to take into account the total population and the connections per person.

First, we should understand that a higher number of connections per person does not necessarily mean more unique users. In fact, it could imply that users in North America have multiple connections, such as smartphones, tablets, and other devices, whereas users in APAC may have fewer devices per person.

In order to calculate the number of unique users in each region, we need to know the total population for both North America and APAC in 2020. Once we have the population figures, we can divide the total number of connections in each region by the connections per person. This will give us an estimate of the unique users in both regions.

Finally, to find out how many more unique users there were in APAC in 2020 compared to North America, we can subtract the number of unique users in North America from the number of unique users in APAC. This difference will show the additional unique users present in the APAC region during 2020.

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Therefore, the 90% confidence interval for the reduction of hexane concentration after treatment is (18.3, 31.9). This means that we are 90% confident that the true reduction in hexane concentration lies between 18.3 and 31.9 micrograms per liter.

To construct a confidence interval for the reduction of hexane concentration after treatment, we can use a two-sample t-test with unequal variances. The formula for the confidence interval is:

( X1 - X2 ) ± tα/2,ν * √( s1²/n1 + s2²/n2 )

where:

X1 = sample mean of untreated ground water

X2 = sample mean of treated ground water

s1 = sample standard deviation of untreated ground water

s2 = sample standard deviation of treated ground water

n1 = sample size of untreated ground water

n2 = sample size of treated ground water

tα/2,ν = t-score from t-distribution with degrees of freedom (ν) and alpha level (α/2)

Substituting the given values, we get:

=( 720.2 - 695.1 ) ± t0.05,21 * √( 8.8²/12 + 9.1²/11 )

= 25.1 ± 2.080 * 3.544

= ( 18.3, 31.9 )

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The correct option is the second one, the quadratic equation is:

f(x) = 1 - 8x²

A quadratic equation is a polynomial where the degree is 2.

So, we only have integer exponents and the larger exponent is 2.

For example, in the first equation we can see that, but the coefficient of the term with the exponent of 2 is zero, so that term is zero, and thus, that is a linear equation.

The option that is quadratic is the second one:

f(x) = 1 - 8x²

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FAIR DATE is both in NP and NP-hard, we can conclude that FAIR DATE is NP-complete.

To prove that FAIR DATE is NP-complete, we need to show two things: (1) FAIR DATE is in NP, and (2) FAIR DATE is NP-hard.

1. FAIR DATE is in NP:
We can easily verify a potential solution for FAIR DATE in polynomial time. Given subsets A* and B*, we can check if the sum of the bills in A* equals c_A and the sum of the bills in B* equals c_B. This verification can be done in O(n) time for Alice's bills and O(m) time for Bob's bills, where n and m are the number of bills Alice and Bob have, respectively.

2. FAIR DATE is NP-hard:
To show that FAIR DATE is NP-hard, we need to reduce a known NP-complete problem to it. Let's choose the PARTITION problem for this reduction. In the PARTITION problem, given a set S of integers, we need to determine if there exists a subset S' of S such that the sum of the elements in S' is equal to half the sum of all elements in S.

Reduction: Given an instance of PARTITION, we can create an instance of FAIR DATE as follows:
- Let Alice's bill be the set A = S, and c_A = 1/2 * (sigma_a ∈ A, a).
- Let Bob's bill be the set B = {}, and c_B = 0.

Now, if there exists a subset A* of A such that sigma_a ∈ A* a = c_A, then this subset is the solution to the PARTITION problem as well. Conversely, if there is a solution to the PARTITION problem, then there exists a subset A* such that sigma_a ∈ A* a = c_A.

Since we can perform this reduction in polynomial time, FAIR DATE is NP-hard.


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The length of AD is 2 inches.

Let x be the length of AD. By the Pythagorean theorem in triangle ABD, we have:

[tex]BD^2 + x^2 = AB^2[/tex]

Substituting AB = BC, we get:

[tex]BD^2 + x^2 = BC^2[/tex]

Using the fact that triangle ABC is isosceles, we can use the Pythagorean theorem in triangle ABC to find BC:

[tex]BC^2 = AC^2 - AB^2 = 8^2 - AB^2[/tex]

Substituting this expression for[tex]BC^2[/tex] in the previous equation, we get:

[tex]BD^2 + x^2 = 8^2 - AB^2[/tex]

Since BD is the perpendicular bisector of AC, we have AD = DC = (AC/2) = 4 inches. Therefore, we can write:

AB = AD + DB = 4 + DB

Substituting this expression for AB in the previous equation, we get:

[tex]BD^2 + x^2 = 8^2 - (4 + DB)^2[/tex]

Simplifying this equation, we get:

[tex]BD^2 + x^2 = 16 - 8DB - DB^2 + x^2[/tex]

Solving for DB, we get:

[tex]DB = (16 - BD^2 - x^2)/(8 + DB)[/tex]

Now, we can use the fact that BD is the perpendicular bisector of AC to write:

[tex]BD^2 = AD \times DC = 4x[/tex]

Substituting this expression for[tex]BD^2[/tex] in the previous equation, we get:

[tex]4x = (16 - 4x - x^2)/(8 + DB)[/tex]

Simplifying this equation, we get:

[tex]32x + 4x^2 = 16 - 4x - x^2[/tex]

Solving for x, we get:

x = 2 inches

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