An AP Statistics class starts a project to estimate the average number of hours a student at their high school sleeps per night. Their high school has 1200 students, and they take a sample of the first 120 students that arrive at school on a particular day. They ask each of the 120 students how many hours of sleep they got the night before and then calculate an average.

Which of the following statements is an accurate description of the elements of this survey?

(A) Population: the 120 students surveyed. Parameter of interest: the average number of hours a student at this high school sleeps per night.
(B) Sample: the 1200 students of the school. Population: all high school students in the United States. Statistic: the average number of hours a student at this high school sleeps per night
(C) Sample: the 120 students surveyed. Population: the 1200 students at the high school. Parameter of interest: the average number of hours a student at this high school sleeps per night.
(D) Sample: the 120 students surveyed. Population: the 1200 students at the high school. Statistic: The average number of hours a student at this high school sleeps per night.
(E) This is not a survey because a convenience sample was used.

Answers

Answer 1

Answer:

Step-by-step explanation:

Hello!

To estimate the average number of hours a student their highschool sleeps per night, the students of the statistics class took as sample the first 120 students that arrived at the school on a particular day, out of the 1200 student population, and asked how many hours of sleep they got the night before.

The population of interest is the entire group of experimental units that exists in the world, in this example is the student body of the high school: 1200 students.

The sample is formed by the students that were interviewed: 120 students.

The parameter of interest is the average sleep time per night of the students in high school.

Correct answer:

(D) Sample: the 120 students surveyed. Population: the 1200 students at the high school. Statistic: The average number of hours a student at this high school sleeps per night.


Related Questions

Classify this triangle.


Acute scalene triangle
Obtuse isosceles triangle
Right isosceles triangle
Right scalene triangle

Answers

right scalene triangle

Answer: right isosceles

Step-by-step explanation:

the angle at the bottom is right therefore you need to figure out the lengths of the sides to conclude if it is isosceles or scalene. because two of the sides are the same length and the other is not it is isosceles

How do I type in exponents

Answers

Answer:

on what

Step-by-step explanation: normaly you have a button that you can have certain characters

Solve SA = πrs + π r2 for s A) -r B) SA + r C) SA π2r3 D) SA - πr2 πr

Answers

Answer:

(SA - π r^2)/πr = s

Step-by-step explanation:

SA = πrs + π r^2

Subtract  π r^2 from each side

SA - π r^2 = πrs + π r^2-π r^2

SA - π r^2 = πrs

Divide each side by  πr

(SA - π r^2)/πr = πrs/πr

(SA - π r^2)/πr = s

Answer:

D

Step-by-step explanation:

SA = πrs + πr²

SA - πr² = πrs

s = (SA - πr²)/πr

The Vacaville tax assessor determined that the market value of the Perry’s house is $132,000. The rate of assessment in Vacaville is 50% of market value. The tax rate is 48.75 mills. What is the real estate tax on the Perry’s house?
1 point
$32.18
$321.75
$3217.50
$6435.00

Answers

Answer:

  $3217.50

Step-by-step explanation:

The tax is computed as ...

  ($132,000)(1/2)(48.75/1000) = 66·48.75 = 3217.50

The real estate tax on the Perry's house is $3217.50.

how to solve x^2+8x+3 using the quadratic formula​

Answers

Answer:

x = sqrt(13) - 4 or x = -4 - sqrt(13)

Step-by-step explanation:

Solve for x:

x^2 + 8 x + 3 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 3 from both sides:

x^2 + 8 x = -3

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 16 to both sides:

x^2 + 8 x + 16 = 13

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x + 4)^2 = 13

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x + 4 = sqrt(13) or x + 4 = -sqrt(13)

Hint: | Look at the first equation: Solve for x.

Subtract 4 from both sides:

x = sqrt(13) - 4 or x + 4 = -sqrt(13)

Hint: | Look at the second equation: Solve for x.

Subtract 4 from both sides:

Answer: x = sqrt(13) - 4 or x = -4 - sqrt(13)

Need done ASAP please

Answers

Step-by-step explanation:

a. 81 ÷ 9 = 9

b. 40 ÷ 5 = 8

c. 21 ÷ 3 = 7

d. 54 ÷ 6 = 9

e. 42 ÷ 7 = 6

f. 63 ÷ 9 = 7

g. 36 ÷ 4 = 4

h. 45 ÷ 9 = 5

i. 39 ÷ 3 = 12

j. 24 ÷ 6 = 4

Please answer number 5 find the surface area

Answers

Ill edit this later to answer the question, but what is the question???

Pete's checking account showed a balance at the beginning of the month of $180. After 3 days the checking account showed a balance of $160. Write a linear equations to represent the total in the checking account f(x) according to the day x.

Answers

Answer:

180 - 172 =$8 8/3=2.56

A bag contains 10 Yellow, 4 Green and 7 Blue marbles. Find the following probabilies.
P(blue)

Answers

Answer:

1/3

Step-by-step explanation:

The total number of marbles

10+4+7 = 21

P(blue) = blue marbles / total marbles

            = 7 / 21

            = 1/3

What is the value of 5+5⋅34

Answers

Answer:

175

Step-by-step explanation:

$3.50 for 1/2 pound of cheese

Answers

Answer:

two pounds of cheese would be $7.00

Step-by-step explanation:

because if you add the price for half a pound plus itself you would get $7.00

Answer:

7.00 1 pound

Step-by-step explanation:

Rewa Delta Union RugbyCEOhas become concerned about the slow pace of the rugby gamesplayed inthe current union rugby, fearing that it will lower the spectator attendance. The CEOmeets with the union rugbymanagers and refereesanddiscusses guidelines for speeding upand makingthe gamesmore interesting and lively. Before the meeting, the mean duration of the15-sided rugbygame timewas 3 hours, 5 minutes, that is, 185 minutes.This includes all the breaks and injury times during the game. A random sample of 36 of the 15-sided rugbygames after themeeting showed a mean of 179 minutes with a standard deviation of 12 minutes.Testing at the 1% significance level, can you concludethat the mean duration of 15-sided union rugbygames has decreased after the meeting?

Answers

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

You commute to work by riding a bus each day for $4.25 round trip. A weekly pass is available for $19.75 a week. If you work 5 days a week, how much can you save by buying the pass?

Answers

Answer:

  $1.50

Step-by-step explanation:

The cost of 5 daily fares is ...

  5($4.25) = $21.25

The difference between that and the cost of a pass is ...

  $21.25 -19.75 = $1.50

You can save $1.50 per week by buying the pass.

Use substitution to solve the system of equations algebraically.

x2 + y2 = 32

y = x



One solution to the system of equations is (–4, –4).

The other solution to the system of equations is _______

Answers

Answer:

The other solution to the system of equations is : (4,4)

Step-by-step explanation:

[tex]x^{2}}+y^{2} =32 \\y=x\\\\x^{2} +x^{2} =32\\2x^{2} =32\\x^{2} =16\\\\x=4 Or x=-4\\y=4 Or y=-4[/tex]

Answer:

(4, 4)

Step-by-step explanation:

There are k students in the class. m of them are girls. How many boys are in the class? How many more boys than girls are there? HELP

Answers

Answer:

[tex]k-m=b[/tex]

[tex]b-m=diff[/tex]

Step-by-step explanation:

If there are total of k students in a class, and m of those students are girls, the total amount of boys would be:

[tex]k-m=b[/tex]

(Where k, m, b are variables that represent the total number of students, the amount of girls and the amount of boys respectively)

As the amount of girls subtracted from the total amount would leave you with the amount of boys.

There would be:

[tex]b-m[/tex] more boys than girls.

If there were 10 total students in the class and 3 of those students were girls, lets use our above equations to see if they are correct - and if we get the expected amounts of:

7 boys in the class, and 4 more boys than there are girls.

[tex]k-m=b\\10-3=7\\7=7[/tex]

This is correct, as we expected this amount.

[tex]b-m=diff\\7-3=4[/tex]

The difference between them is 4, so this is correct.

Direct mail advertisers send solicitations​ ("junk mail") to thousands of potential customers in the hope that some will buy the​ company's product. The response rate is usually quite low. Suppose a company wants to test the response to a new flyer and sends it to 1030 people randomly selected from their mailing list of over​ 200,000 people. They get orders from 103 of the recipients.

Required:
Create a 95% confidence interval for the percentage of people the company contacts who may buy something. (Show your work. Step by step)

Answers

Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

1. Conditions

First we must check the conditions.

Randomization condition: The sample is given to be random, so we can assume independence.

Success/failure condition: Both np>10 and nq>10 must be met.

np = 1030(103/1030) = 103 ✓ nq = 1030(927/1030) = 927 ✓

10% condition: The sample cannot be greater than 10% of the population.

10n < N, 10(1030) < 200000 ✓

All conditions are met, so we can use a 1-proportion z-interval to represent the data.

2. Mechanics

Find [tex]\hat{p}[/tex], the sample proportion.

103/1030 = .1

[tex]\hat{q}[/tex], then, the probability of not p, is 1 - .1 = .9

Find z* (z star), the critical z-value.

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

Plug values into the equation.

[tex]\hat{p}[/tex] ± z*[tex]\sqrt{\frac{\hat{p}\hat{q}}{n} }[/tex]

.1 ± 1.96[tex]\sqrt{\frac{.1*.9}{1030} }[/tex]

.1 ± 1.96(.00935)

.1 - .0183 = .0817

.1 + .0183 = .118

(.0817, .118)

3. Conclusion

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

3.6 x 0.025 is my question to be answered

Answers

Answer:

0.09

because I multiplied...

Answer:

0.09

Step-by-step explanation:

36/ 10 x 25/ 1000 = 18/ 5 x 1/40 = 9/100 = 0.09

The roots of a quadratic equation are 6 and 3/4. If one of the two factors of the equation is x – 6, what is the second factor?

A. 3x - 4
B. 3x + 4
C. 4x - 3
D. 4x + 3​

Answers

Answer:

  C.  4x - 3

Step-by-step explanation:

The factor could be (x -3/4). Apparently, you're expected to show the factor as 4 times this, or ...

  4x -3 . . . . . matches choice C

___

If r is a root, then (x -r) is a factor. As here, factors containing fractional roots can be multiplied by the denominator to make the coefficients be integers.

The revenue for a business, as a function of units produced, x, is shown below by R(x). C(x) represents the cost of producing x units. Calculate the profit function and then determine how many units must be produced for the business to make a profit of $1220.

Answers

Did you ever figure this out. I need the answer for a test.

Please help ASAP! I will mark Brainliest! Please answer CORRECTLY! No guessing! CHECK ALL THAT APPLY

Answers

Answer:

A8

B 0

F 5

Step-by-step explanation:

x+22<32

Subtract 22 from each side

x+22-22 <32-22

x < 10

8 is less than 10

0 is less than 10

5 is less than 10

If a pair of standard dice are rolled,
what is the probability that at least
one die shows a 5?
?

Answers

Answer:

The correct answer is 11/36

Step-by-step explanation:

The probability that at least one die shows a '5' is 11/36.

What is the probability of an event?

The probability of an event is the chance of happening that particular event.

Here, a pair of standard dice are rolled.

Therefore, the total number of combinations of two dice is = 6² = 36.

The case at which one die shows a '5' are: (1, 5); (2, 5); (3, 5); (4, 5); (5, 5); (6,5); (5, 1); (5, 2); (5, 3); (5, 4); (6, 5)

Therefore, the total number of cases at which one die shows a '5' is = 11.

Therefore, the required probability of the given event is

= 11/36

Learn more about the probability of an event here: https://brainly.com/question/9548010

#SPJ3

Divide 45 minutes in the ratio 2:3

Answers

Answer: 18 minutes: 27 minutes

Here the steps see attachment

The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed and a sample mean of 5.25 was obtained. Suppose that the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3. Does this indicate conclusively that the true average is smaller than 5.5? Carry the procedure at a 0.01 significance level. Use only the P-Value approach. State H0 and Ha

Answers

Answer:

a)  Null hypothesis : H₀ : μ = 5.5

 Alternative Hypothesis : H₁ : μ < 5.5

b) The test statistic

        |t| = |-3.33| = 3.33

c) P - value lies between in these intervals

0.001 < P < 0.005

Step-by-step explanation:

Step( i ):-

Given data the Population mean 'μ' = 5.5

The small sample size 'n' = 16

The sample mean (x⁻) = 5.25

Given the  percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

Null hypothesis : H₀ : μ = 5.5

 Alternative Hypothesis : H₁ : μ < 5.5

 Level of significance ∝ = 0.01

Step(ii):-

 The test statistic

                              [tex]t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }[/tex]

                             [tex]t = \frac{5.25 -5.5}{\frac{0.3}{\sqrt{16} } }[/tex]

On calculation , we get

                            t = -3.33

                           |t| = |-3.33| = 3.33

Step(iii):-

P - value

The degrees of freedom γ = n-1 = 16-1 =15

The calculated value t = 3.33 (check t-table) lies between the 0.001 to 0.005

0.001 < P < 0.005

Condition(i)

P - value < ∝ then reject H₀

Condition(ii)

P - value > ∝ then Accept H₀

we observe that  0.001 < P < 0.005

P- value < 0.01

we rejected  H₀

(or)

The tabulated value  = 2.60 at 0.01 level of significance with '15' degrees of freedom

The calculated value t = 3.33 > 2.60 at 0.01 level of significance with '15' degrees of freedom

The null hypothesis is rejected

Conclusion:-

Accepted Alternative hypothesis H₁

The Claim that the true average is smaller than 5.5

             

If 5 pizzas cost 60$, how much will 9 pizzas cost

Answers

Answer:

$108

Step-by-step explanation:

If 5 pizzas cost $60, then each pizza costs $12.  9 x 12 = 108.

Answer:

108

Step-by-step explanation:

if 5 pizzas cost 60,

each pizza cost 60/5= 12dollars

then, 9 pizzas cost 12 x 9 = 108dollars

Patricia, Luca and Dauda shared an amount of money such that, Patricia had twice as much
s Dauda and Luca had GH<600.00 more than Dauda. Il Patricia had GH2,000.00. W
was the average share, to the nearest GH!
Answer:​

Answers

Answer:

GH 1533

Step-by-step explanation:

Let Dauda's share of the money=x

Patricia had twice as much  as Dauda, therefore:

Patricia's share=2x

Luca had GH 600.00 more than Dauda, therefore:

Luca's Share =x+600

If Patricia had GH 2,000.00

Then: 2x=2000

x=1000

Therefore:

Dauda's Share=GH 1000Patricia's share=GH 2000Luca's Share =1000+600=GH 1,600

Next, we determine the average share.

[tex]\text{Average Share=}\dfrac{1000+2000+1600}{3}\\=\dfrac{4600}{3}\\\\=$GH 1533.33\\\text{Average Share} \approx $GH 1533 (to the nearest GH)[/tex]

Find the middle term of the expansion of (x+y)^8 a40x^2y^2 b70x^2y^2

Answers

Answer:

the middle term = 70x⁴y⁴

Step-by-step explanation:

Given;

(x+y)⁸

This expression can be expanded as follows, using Paschal triangle;

                                                 1      1

                                               1    2     1

                                             1     3      3      1

                                         1     4       6      4     1

                                    1       5     10    10       5    1

                            1           6      15     20     15     6        1

                    1            7         21      35     35      21     7          1

        1                 8          28        56     70     56    28       8         1

At level 8, the middle coefficient is 70

Also the power of x and y will be equal in the middle term = A(xⁿ yⁿ)

A = 70 ,

n +n = 8

n = 4

Thus, the middle term = 70x⁴y⁴

A line has the equation 3x–4y–12=0.

Is the point (2, −1) on the graph?

Answers

Answer:

The point (2, -1 ) is not on the graph of the line.

Step-by-step explanation:

3x–4y–12=0

3*2 - 4*(-1) - 12= 0

6 + 4 - 12 =0

10 - 12 = 0

- 2 = 0 , false, so the point (2, -1 ) is not on the graph of the line.

HELP WITH THIS EASY MATH AUESTION DOWN HELOW!! WILL MARK AS BRANLIEST AND I NEED AN EXPLANTION TOO

Answers

Answer:

A. 36, -36

Step-by-step explanation:

y = x^2 - 12x - 5

steps to complete the square

add a 5 to both sides to move the constant

x^2 - 12x = 5

Then take -12, the coefficient of the variable and divide by 2 and square.

12/2 = 6, 6^2 = 36

Then add 36 to both sides.

x^2 - 12x + 36 = 5 + 36

Then subtract the 5 and 36 from both sides.

x^2 - 12x + 36 - 36 - 5

A group of 75 college students from a liberal arts college were randomly sampled and asked about the number of alcoholic drinks they have in a typical week. The file containing the data is linked below. The purpose of this study (Links to an external site.) was to compare the drinking habits of the students at the college to the drinking habits of college students in general. In particular, the dean of students, who initiated this study, would like to check whether the mean number of alcoholic drinks that students at his college have in a typical week differs from the mean of U.S. college students in general, which is estimated to be 4.73.

Let u be the mean number of alcoholic beverages that students in the college drink in a typical week. State the hypotheses that are being tested in this problem.

Answers

Answer:

Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 4.73  

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 4.73

Step-by-step explanation:

We are given that a group of 75 college students from a liberal arts college were randomly sampled and asked about the number of alcoholic drinks they have in a typical week.

In particular, the dean of students, who initiated this study, would like to check whether the mean number of alcoholic drinks that students at his college have in a typical week differs from the mean of U.S. college students in general, which is estimated to be 4.73.

Let [tex]\mu[/tex] = mean number of alcoholic beverages that students in the college drink in a typical week.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 4.73      {means that the mean number of alcoholic drinks that students at his college have in a typical week does not differs from the mean of U.S. college students in general}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 4.73     {means that the mean number of alcoholic drinks that students at his college have in a typical week differs from the mean of U.S. college students in general}

The test statistics that can be used here is One-sample t test statistics or One-sample z test statistics depending on whether population standard deviation is given or not.

Hence, this is the hypothesis that are being tested in this problem.

The article Effect of Environmental Factors on Steel Plate Corrosion Under Marine Immersion Conditions (C. Soares. Y. Garbatov, and A. Zayed, Corrosion Engineering, Science and Technology, 2011 :524? 541 ) describes an experiment in which nine steel specimens were submerged in seawater at various temperatures, and the corrosion rates were measured. The result are presented in the following table (obtained by digitizing a graph).

Temperature (C) Corrosion (mm/y)
26.6 1.58
26.0 1.45
27.4 1.13
21.7 0.96
14.9 0.99
11.3 1.05
15.0 0.82

a. Construct a scatterplot of corrosion (y) versus temperature (x). Verify that a linear model is appropriate.
b. Compute the least-squares line for predicting corrosion from temperature.
c. Two steel specimens whose temperatures differ by 10◦ C are submerged in seawater. By how much would you predict their corrosion rates to differ?
d. Predict the corrosion rate for steel submerged in seawater at a temperature of 20◦ C.

Answers

Answer:

Check the explanation

Step-by-step explanation:

a) from the scatter plot in the attached image below, it appears that relationship is approximately linear

b) least square line: that =0.3940+0.0355x

c) for 10 C difference expected difference in corrosion rate =0.0355*10=0.355

d) for x=20 ; predicted temperature =0.3940+0.0355*20=1.1041

e) fitted values are:

X                      ŷ

26.600        1.3385

26.000        1.3172

27.400        1.3669

21.700         1.1645

14.900        0.9230

11.300          0.7952

15.000        0.9266

8.700          0.7029

8.200          0.6851

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