An attacker compromises the Washington Post's web server and proceeds to modify the homepage slightly by inserting a 1x1 pixel iframe that directs all website visitors to a webpage of his choosing that then installs malware on the visitors' computers. The attacker did this explicitly because he knows that US policymakers frequent the website. This would be an example of a ___________ attack.

Answers

Answer 1

Answer:

Water holing is the correct answer to this question.

Explanation:

Waterholing:-

It is a kind of attack in which the attacker detects the sites that the targets of the group frequently access and then afflicts the sites with the ransomware. Which afflicts selected representatives of the target group.

The watering hole assault is a data breach wherein the individual attempts to infiltrate a particular demographic of end-users by harming sites reported to be visited by team members. The aim is to compromise a specific target data and gain network access at the perpetrator's place of work.


Related Questions

Trace the complete execution of the MergeSort algorithm when called on the array of integers, numbers, below. Show the resulting sub-arrays formed after each call to merge by enclosing them in { }. For example, if you originally had an array of 5 elements, a = {5,2,8,3,7}, the first call to merge would result with: {2, 5} 8, 3, 7 ← Note after the first call to merge, two arrays of size 1 have been merged into the sorted subarray {2,5} and the values 2 and 5 are sorted in array a You are to do this trace for the array, numbers, below. Be sure to show the resulting sub-arrays after each call to MergeSort. int[] numbers = {23, 14, 3, 56, 17, 8, 42, 18, 5};

Answers

Answer:

public class Main {

public static void merge(int[] arr, int l, int m, int r) {

int n1 = m - l + 1;

int n2 = r - m;

int[] L = new int[n1];

int[] R = new int[n2];

for (int i = 0; i < n1; ++i)

L[i] = arr[l + i];

for (int j = 0; j < n2; ++j)

R[j] = arr[m + 1 + j];

int i = 0, j = 0;

int k = l;

while (i < n1 && j < n2) {

if (L[i] <= R[j]) {

arr[k] = L[i];

i++;

} else {

arr[k] = R[j];

j++;

}

k++;

}

while (i < n1) {

arr[k] = L[i];

i++;

k++;

}

while (j < n2) {

arr[k] = R[j];

j++;

k++;

}

printArray(arr, l, r);

}

public static void sort(int[] arr, int l, int r) {

if (l < r) {

int m = (l + r) / 2;

sort(arr, l, m);

sort(arr, m + 1, r);

merge(arr, l, m, r);

}

}

static void printArray(int[] arr, int l, int r) {

System.out.print("{");

for (int i = l; i <= r; ++i)

System.out.print(arr[i] + " ");

System.out.println("}");

}

public static void main(String[] args) {

int[] arr = {23, 14, 3, 56, 17, 8, 42, 18, 5};

sort(arr, 0, arr.length - 1);

}

}

Explanation:

See answer

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