an electron moves with velocity v in a direction opposite to the direction of the current in the neighboring long wire. what is the direction of the magnetic force acting on the electron?

Answers

Answer 1

An electron moves with velocity v in a direction opposite to the direction of the current in the neighboring long wire the direction of the magnetic force acting on the electron is perpendicular.

We can don't forget this diagram the use of the proper-hand rule. If you factor your pointer finger withinside the course the superb price is transferring, after which your center finger withinside the course of the magnetic area, your thumb factors withinside the course of the magnetic pressure pushing at the transferring price.

The magnetic pressure on a current-wearing cord is perpendicular to each the cord and the magnetic area with course given via way of means of the proper hand rule.Moving electric powered costs produce magnetic fields. F = qv × B. The pressure F is perpendicular to the course of the magnetic area B. It is also perpendicular to the course of the rate v.

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Related Questions

A skydiver of mass 80.0kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0m/s. (a) What is her acceleration when her speed is 30.0m/s? What is the drag force on the skydiver when her speed is (b) 50.0m/s and (c) 30.0m/s?

Answers

Her acceleration when her speed is 30.0m/s is 10m/sec².

Calculation:-

mg = bv

I am also not quite sure if I should use 9.8 m/s2 or if it is ok to round and use 10m/s2 for physics.

Given: m = 80 kg, vt = 50 m/s.

(a) What is the acceleration of the skydiver, when her speed is 30 m/s?

(b) What is the drag force on the diver when her speed is 50 m/s?

(c) What is the drag force on the diver when her speed is 30 m/s?

(a) Using we can find DρA.  DρA = 2mg/vt2 = 0.6272 kg/m.

Therefore a = dv/dt = 9.8 m/s2 - (0.6272/(160 m))v2.

When v = 30 m/s, a = 6.272 m/s2.

(b).When v = vt = 50 m/s, the drag force is equal in magnitude to mg = 784 N.

(c.) When v = 30 m/s, the total force is equal in magnitude to

ma = (80 kg)(6.272 m/s2) = 502 N.  The magnitude of the drag force is mg - ma = 282 N.

After a maximum velocity, the acceleration stops due to the high drag force. and in most of the problems, g is taken to be 10m/sec².

The drag equation states that the drag force D is equal to the drag coefficient Cd density r half velocity V squared reference area A. For a given air condition object shape and tilt, we need to determine the value of Cd to determine the drag force.

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What are the 4 stages of the rock cycle?.

Answers

One type of rock can become another rock type through a number of procedures. Crystallization, erosion and sedimentation, and metamorphism are the main components of the rock cycle.

Rock cycle: what is it?

The changes between the three primary rock types are shown by a notion known as a "rock cycle" (metamorphic, igneous and sedimentary). The many types of rocks that make up the Earth's crust are created and altered via a series of processes.

Very brief explanation of the rock cycle.

The igneous, metamorphic, and sedimentary rock types all go through a geological process known as the rock cycle. Through erosion into sediment and cementing, or heating and pressure, or both, the three kinds of rock are changed in this process. Rocks can change from igneous to sedimentary.

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a ball is held at rest at the top of a hill. the ball is then released and starts rolling down the hill. at the bottom, it reaches level ground and keeps rolling along the ground. consider the level ground at the bottom of the hill as zero height. select the type or types of energy the ball has at the top of the hill.

Answers

Gravitational Potential Energy is the type of energy the ball has at the top of the hill.

What is meant by Gravitational Potential Energy ?The energy that an item has due to its location in a gravitational field is known as gravitational potential energy. For an object close to the surface of the Earth, when the gravitational acceleration may be considered to remain constant at around 9.8 m/s, gravitational potential energy is most frequently used.Gravitational potential energy may be defined as an energy that has a connection to gravitational force or gravity.If an item is placed at a height above (or below) the zero height, it has gravitational potential energy. If an item is not in its equilibrium position on an elastic material, it has elastic potential energy.

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a proton moves through a magnetic field at 33.5% of the speed of light. at a location where the field has a magnitude of 0.00659 t and the proton's ve

Answers

The proton's velocity forms an incidence of 139* together with field at a site where it has an amplitude of 0.00635 T.

What is a speed series of questions?

The ratio below 1 translates reached to the time needed to travel that distance is known as speed. Since speed just has a constituent and no magnitude, it is a proportionality constant.

How do you respond to a question regarding Speed?

By multiplying the distance covered by the time needed to get there, speed is computed. To calculate the passing time, multiply the kilometers by the speed. To calculate the distance, multiply the movement by the time. These equations might be abbreviated as s=d/t.

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a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running track, find the dimensions that will make the area of the rectangular region as large as possible.

Answers

The dimensions of the rectangle are:

l = 50 m

b = [tex]100/\pi[/tex] m

What is a perimeter in math?

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

How do we find a perimeter of a rectangle?

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

Given:

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =[tex]\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l[/tex]

Therefore,  [tex]\pi b+2l=200[/tex]

[tex]b=(200-2l)/\pi[/tex]

Now,

Area, A = [tex]l(200-2l)/\pi=(200l-2l^{2} )/\pi[/tex]

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

[tex]d^{2} A/dl^{2} =-4l/\pi[/tex]< 0

Thus we get maximum are when [tex]dA/dl=0[/tex]

Therefore,

[tex](200-4l)/\pi=0[/tex]

l = 50 m

Now, from

[tex]\pi b+2l=200[/tex]

[tex]\pi b=200-2*50[/tex]

[tex]b=100/\pi[/tex]

[tex]r=b/2=50/\pi[/tex]

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a horizontal spring with spring constant 210 n/mn/m is compressed by 20 cmcm and then used to launch a 300 gg box across the floor. the coefficient of kinetic friction between the box and the floor is 0.23. What is the box's launch speed?

Answers

The box's launch speed across the floor is 5.2 m/s. The result is obtained by using the law of conservation of energy.

What is law of conservation of energy?

The law of conservation of energy states that "The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and transferred from one object to another, but the total amount remains constant."

E initial = E final

We have a horizontal spring with:

The spring constant, k = 210 N/m.The extension of the spring, Δx = 20 cm = 0.2 m.The mass of the box launched, m  = 300 g = 0.3 kg.The coefficient of kinetic friction,  = 0.23.What is the box's launch speed?

In that case, we know that there is elastic potential energy and force of kinetic friction. The total work done would be:

W = 1/2 k(Δx)² - Ff.Δx

At the final condition, there is only the kinetic energy.

E final = 1/2 mv²

Using the law of conservation of energy, we get the speed:

E initial = E final

W = E final

1/2 k(Δx)² - Ff.Δx = 1/2 mv²

1/2 k(Δx)² - μmg.Δx = 1/2 mv²

1/2 (210)(0.2)² - 0.23(0.3)(9.8)(0.2) = 1/2 (0.3)v²

4.2 - 0.135 = 0.15v²

4.2 - 0.135 = 0.15v²

4.065 = 0.15v²

v² = 27.1

v = √27.1

v = 5.2 m/s

Hence, the box's launch speed is 5.2 m/s.

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Provided following are stages that occurred during the formation of our solar system. Rank these stages from left to right based on when they occurred, from first to last.
large cloud of gas and dust
contraction of solar nebula
condensation of solid particles
accreition of planetesimals
clearing the solar nebula

Answers

The correct order for the stages that occurred during the formation of our solar system from left to right are large cloud of gas and dust > contraction of solar nebula > condensation of solid particles > accretion of planetesimals > clearing the solar nebula.

When a cloud of gas and dust collapsed, it formed a solar nebula which is a swirling disk of material, which is made up of hydrogen and helium. It starts collapsing under its own gravity and compresses in the centre. Then the solid particles are gas condensed into tiny dust grains. These dust grains are stuck to each other forming larger particles. This forms the accretion of planetesimals. These large particles grow and accumulate creating larger planetesimals, after a billion years of clearing the nebula, planets are formed.

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the electronic circuitry in an ultrasonic receiver measures the transit time and calculates the distance from the receiver to the surface of material.

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It is true that electronic circuitry in an ultrasonic receiver measures the transit time and calculates the distance from the receiver to the surface of material.

What is ultrasonic receiver?

Ultrasonic sensors works by sending out a sound wave at frequency above the human hearing range. Transducer of the sensor acts as microphone to receive and send the ultrasonic sound. Ultrasonic sensors use a single transducer to send a pulse and to receive the echo.

Ultrasonic receivers and transmitters detect and transmit high frequency sound waves, respectively and are characterized by frequency, rated voltage, and beam angle.

Ultrasonic transducers and ultrasonic sensors are devices that generate or sense ultrasound energy and can be divided into three: transmitters, receivers and transceivers.

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he following images show six objects in our solar system. Rank the objects from left to right based on their average distance from the Sun, from farthest to closest.
Pluto, Saturn, Jupiter, Mars, Earth, Mercury

Answers

Objects, farthest to the closest will be Pluto, Saturn, Jupiter, Mars, Earth, and Mercury.

Our solar system consists of our megastar, the solar, and the whole thing sure to it by gravity – the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune; dwarf planets such as Pluto; dozens of moons; and thousands and thousands of asteroids, comets, and meteoroids. past our personal solar system, we have discovered thousands of planetary systems orbiting other stars inside the Milky manner.

The planets orbit the solar, roughly within the same plane. The solar system moves through the galaxy with approximately a 60° perspective between the galactic plane and the planetary orbital aircraft. The solar seems to transport up-and-down and in and out with respect to the rest of the galaxy because it revolves across the Milky Way.

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A 0. 0035 m aqueous solution of a particular compound has ph = 2. 46. The compound is.

Answers

A 0.0035 M aqueous solution of a certain substance has a pH of 2.46. The compound is a strong acid.

How does pH determine a solution's acidity or basicity?

The pH of water indicates how acidic or basic it is. The scale runs from 0 to 14, with 7 being neutral. pHs less than 7 indicate acidity, while pHs greater than 7 imply baseness. The pH of water is a measure of the relative number of free hydrogen and hydroxyl ions. Water with a higher concentration of free hydrogen ions is acidic, whereas water with a higher concentration of free hydroxyl ions is basic. Because chemicals in water can influence pH, pH is a significant indicator of chemically changing water. pH is expressed in "logarithmic units." Each value reflects a 10-fold increase or decrease in the acidity/basicity of the water. Water with a pH of 5 is ten times as acidic as water with a pH of 6.

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At the bow of a ship on a stormy sea, a crew member conducts an experiment by standing on a bathroom scale.
In calm waters, the scale reads 755 . During the storm, the crew member observer a maximum reading of 920 and a minimum reading of 555 .
A) Find the maximum upward acceleration experienced by the crew member.
B) Find the maximum downward acceleration experienced by the crew member.

Answers

2.14 m/s² is the maximum upward acceleration experienced by the crew member. 3.53 m/s² is the maximum downward acceleration experienced by the crew member.

How to calculate the maximum upward acceleration ?

To calculate the maximum upward acceleration experienced use this formula

[tex]a = \left(\frac{W_{2} - W_{1}}{W_{1}} \right ) g[/tex]

where,

W₁ = Scale reading in calm water

W₂ = Maximum reading in the storm

g = acceleration due to the gravity

Now put the values in above formula we get the acceleration as

[tex]a = \left(\frac{W_{2} - W_{1}}{W_{1}} \right ) g[/tex]

  [tex]= \left(\frac{920\ lb - 755\ lb}{755\ lb} \right ) (9.8\ m/s^2)[/tex]

  [tex]= \frac{165\ lb}{755\ lb} \times (9.8\ m/s^2)[/tex]

  = 2.14  m/s²

How to calculate the minimum downward acceleration ?

To calculate the minimum downward acceleration experienced use this formula

[tex]a = \left(\frac{W_{1} - W_{3}}{W_{3}} \right ) g[/tex]

where,

W₁ = Scale reading in calm water

W₃ = Minimum reading in the storm

g = acceleration due to the gravity

Now put the values in above formula we get the acceleration as

[tex]a = \left(\frac{W_{1} - W_{3}}{W_{3}} \right ) g[/tex]

  [tex]= \left(\frac{755\ lb - 555\ lb}{555\ lb} \right ) (9.8\ m/s^2)[/tex]

  [tex]= \frac{200\ lb}{555\ lb} \times (9.8\ m/s^2)[/tex]

  = 3.53  m/s²

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which of the following statements about the use of combustible materials in type i construction is ftec

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Limited use of combustible materials is permitted in Type I construction.

What is Type 1 a construction?Any structure taller than 75 feet falls under this category.All residential and commercial high-rise buildings must adhere to this. Apartment complexes, workplaces, and hotels are all included. These structures are made to sustain extreme heat for an extended period of time without collapsing. Beyond that, none of the materials used in construction can catch fire. Reinforced concrete and protected steel are used to construct the walls, floors, and roofs. These elements boost construction expenses while also giving the buildings an incredibly long lifespan.To stop flames from spreading, certain Type 1 buildings incorporate HVAC systems and self-pressurizing stairwells. Firefighters find it simpler to reach and put out fires thanks to these structural features. Their primary goal while entering a Type 1 building is to lock stairwells to guarantee a secure evacuation.

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a particle moves along the x axis. it is initially at the position 0.340 m, moving with velocity 0.210 m/s and acceleration -0.210 m/s2. suppose it moves with constant acceleration for 6.00 s. (a) find the position of the particle after this time.

Answers

a particle moves along the x axis. it is initially at the position 0.340 m.the position of the particle after this time is 2.52 metres towards negative x direction.

what is displacement?

Displacement (symbolized d or s ), also called length or distance, is a one-dimensional quantity representing the separation between two defined points. The standard unit of displacement in the International System of Units ( SI ) is the meter

Displacement is the change in position by a body. It's defined as shortest distance between initial and final position of the body. It's a vector quantity. Hence, it has both magnitude and direction. To understand the magnitude and direction of displacement, consider a body moving from position A to position B.

s=ut+1/2at².

on solving the eqn we get displacement as -2.52 metres

which means the body is 2.52 metre towards negative x.

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A square wire loop with 2.4 m sides is perpendicular to a uniform magnetic field, with half the area of the Ioop in the field as shown in the figure. The loop contains an ideal battery with emf 824 V If the magnitude of the field varies with time according to B = 0.035-0.81 t, with B In teslas and t in seconds, what are (a) the net emf in the circuit and (b) the direction of the (net) current around the loop? (b counterclockwise

Answers

This statement about distance is proved.

What is distace?

It is length of space between two points.

Okay so the first three parts of this problem is more mathematics and physics. Um So part A were given Ds equals R. D. Data. We're required to find S. So we just integrate both sides then as equals integration of R. D. Data. Our data is given. So the upon integration over our data is simply R zero santa plus one half beta zeta squared for part B. We'll fix that S equals V. T. Um And using as equals dis above equation we combine these two. We see this is Justin equation for data so we can suffer it to get to roots once positive. The other negative of course which is a positive one because it has the correct physical meaning a negative data would mean that uh the direction of rotation is in the opposite direction.

standard uh standard unit is zero point 247 times turn to the negative six nature radio. And we're also given the time 74 minutes or equivalently 4440 seconds. So plugging all this. So plugging data mm hmm and R zero into the expression of um data. So we plug in better Data. V is also given. So everything is known. We can safely find data to be um 1.337 Times 10-5 brilliant. Or in terms of revolutions is 2.13 times 10 to 4 revolution. Okay. In the last part of the problem, we simply well plugging again the numbers for beta, tr zero V to the previous expressions for omega and alpha. You can enjoy the using mathematical or even by hand or maybe he looks like this shape while um the alpha t looks more like this.

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when landing after a spectacular somersault, a 25.0 kg gymnast decelerates by pushing straight down on the mat. calculate the force (in n) she must exert if her deceleration is 9.00 times the acceleration of gravity. (enter a number.)

Answers

The force exerted by the 25 kg gymnast after a spectacular somersault is 2940 N.

Given,

Mass of the gymnast, m = 25 kg

The deceleration experienced by the gymnast, a = 9×g (acceleration due to gravity)

Now, according to Newtons second law of motion, the net force on the gymnast will be:

[tex]F_{net}[/tex] = F - W = ma

Where F is the force on the gymnast, W is the weight and a is the acceleration experienced.

So, we can also rewrite the above equation as

F = ma +W

= ma + mg

= m(a + g)

= 30 kg( 9×9.8 + 9.8)

= 30 (88.2+9.8)

= 30×98

=2940 N

Hence, the force exerted by the gymnast is 2940 N.

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What are similarities between solar and hydro energy?.

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The parallels between hydroelectricity and solar energy are rather striking. Both employ 100% renewable sources to generate power with zero carbon emissions when the necessary machinery is built and installed.

What are the parallels and distinctions between hydropower and wind power?

A considerable volume of water is used in hydropower, which runs through pipes into a power station. Gravity forces high-pressure water through pipelines or canals, causing the turbine to revolve and create energy. Wind power works by spinning the turbine blades, which spin the magnet.

Both types of solar panels, solar photovoltaic (PV) and solar thermal, work on the same concept. They take raw solar energy and convert it into useable energy.

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A potential difference of 0.090V is developed across the 10-cm-long wire of the following figure as it moves through a magnetic field perpendicular to the plane of the figure.
What is the strength of the magnetic field?

Answers

The strength of magnetic field is 0.18T.

The magnetic influence on moving electric charge, electric current and magnetic materials is described by magnetic field.

Given that, potential difference = 0.09 V

Length = 10 cm = 10/100 m = 0.1 m

Velocity = 5 m/s

We know the relation, Potential difference = B*l*v

where, B is the magnetic field strength

l is the length

v is the velocity

Potential difference = B*l*v

0.09 = B* 0.1* 5

B = 0.09/0.5 = 0.18 T

Thus, the strength of magnetic field is 0.18 T.

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A horizontal section of narrow pipe is filled with water whose flow speed is negligible
(v1 ≈0)
. The gauge pressure inside the pipe is P gauge =4.0 atm
. There is a pinhole-sized leak in the wall of the pipe, and water exits the hole with speed
v2
. What is
v2

? For the limit check, investigate what happens to
v2

if the gauge pressure inside the pipe drops to zero
(Pgauge →0)

Answers

Consequently, if the pipe is extended by two times its original length, the gauge pressure would be 2.234 ×10⁴ Pa.

How does gauge pressure work?

Gauge pressure is the measurement of pressure in respect to the surrounding atmosphere. With one side of the textile exposed to the took shape that has to be measured the other accessible to the outside air density, a diaphragm sensor is able to measure gauge pressure.

Briefing:

By using the continuity equation

A ₁V₁ = A₂V₂

When the area is doubled from what it was originally,

A ₁V₁ = 2A₁V₂

V₂ =V₁/2

By using Bernoulli's equation

P₁ + 1/2 ρV₁² = P₂ + 1/2 ρV₂²

P₂ =  2×10⁴ + 1/2 ×1000×(2.5² -1.25²)

   = 2×10⁴ + 2343.75

   =22343.75 Pa

   =2.234 ×10⁴ Pa

Consequently, if the pipe is extended by two times its original length, the gauge pressure would be 2.234 ×10⁴ Pa.

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You are watching an object that is moving in SHM. When the object is displaced 0.600 m to the right of its equilibrium position, it has a velocity of 2.20m/s to the right and an acceleration of 8.40m/s2 to the left.How much farther from this point will the object move before it stops momentarily and then starts to move back to the left?

Answers

The object can move as farther as 0.2m.

Using the Sine Equation,

= x(t) = Asin(ωt)

=Here, t=0, x=0,

Given that,

Distance = x(t) = 0.60 = A sin(ωt)

Velocity = v(t) = 2.20 m/s = Aωcos(ωt)

Acceleration = a(t) = 8.40 m/s² = -Aω²sin(ωt)

Using wave equation,

= x(t) / a(t) = A sin(ωt) / -Aω²sin(ωt)

= ω² = 14 rad²/s²

= ω = 3.74 rad/s

The amplitude of the motion =

=  x(t) / v(t) = A sin(ωt) / Aωcos(ωt)

= A = 0.2 m

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what happens to the core of a star after the start of helium nuclear reactions in its core compared to what it was like before these reactions began?

Answers

Fusion of helium nuclei to form carbon and oxygen in the core of a star after the start of helium nuclear reactions in its core compared.

The positions of the stars in relation to one another are largely constant. Orion and Taurus are constantly converging. Draco is always near Ursa Minor. When we look at the sky, the stars are a never-ending backdrop painting that barely move in relation to one another.

There are some minute movements as we orbit the sun throughout the year. Stars closer to us move more left and right than stars farther away. It makes sense, even if it only has a small impact. If you keep your eyes fixed out into the distance as you walk down the street, you'll notice that objects farther away move less in relation to you than ones closer to you.

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what is the angular momentum of a 0.225 kg ball rotating on the end of a thin string in a circle of radius 1.50 m at an angular speed of 10.5 rad/s ?

Answers

Angular momentum of a 0.225kg ball rotating on the end of a thin string in a circle of radius 1.50 m at an angular speed of 10.5 rad/s is 5.315 kg-m²/sec

Angular momentum is defined as the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity.

It is expressed as L = I ω for rotating body.

where, L = angular momentum, I = moment of inertia, ω = angular speed

L = ?, I =?, ω = 10.5

Moment of inertia for the string-mass system is I = mr²

I=?, m= 0.225 , r=1.50

I = 0.225(1.50)²

So, I = 0.506 kg-m²

since, L = I ω

substituting the values I= 0.506, ω= 10.5

L = 0.506 × 10.5

Therefore, L= 5.315 kg-m²/sec

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You are riding a bicycle. If you apply a forward force of 125 n, and you and the bicycle have a combined mass of 82 kg, what will be the forward acceleration of the bicycle? (assume there is no friction. ).

Answers

The forward acceleration of the bicycle will be 1.52 m/s²

Given parameters:

Force  = 125N

Mass combined = 82kg

Acceleration of the bicycle  = ?

From Newton second law of motion suggests that:

Force = mass x acceleration

 Acceleration =  force/mass = 125/82 = 1.52 m/s²

What is acceleration?

In mechanics, acceleration is the rate of change of an object's velocity with respect to time. Acceleration is a vector quantity (as long as it has magnitude and direction). The direction of an object's acceleration is given by the direction of the net force acting on that object. As described in Newton's second law , the magnitude of an object's acceleration is the combined effect of two sources.

The mass of this object is inversely proportional to the mass of the object, depending on the material from which it is made.

Therefore, The forward acceleration of the bicycle will be 1.52 m/s².

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A piece of wood is floating in a tub of water. A second piece of wood rest on top of the first piece; it does not touch the water. If the second piece is removed from the first and placed in the water, what happens to the water level in the tub?.

Answers

If the second piece is removed from the first and placed in the water, then the water level remains unchanged.

The water level is the water level reached in the container.

Initially, the weight of the pieces of wood was balanced by the buoyancy provided by the water, which depended on the volume of the first piece of wood that was inside the water (which was equal to the volume of water displaced).

Now, when the other piece was placed in the water, then again the weight of both blocks individually (which does not change) would be balanced by the lift of the total volume (coming from the contribution from both blocks), which would be the same. as before.

The water level would thus remain unchanged.

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Compressed gases aren't ideal. Let's consider a gas that's non-ideal only because the volume available to each of the N molecules is reduced because each other molecule occupies volume v. Instead of pV=NkT, we get: p(V-Nb)=NkT. Let b=7 × 10^-29 m3. Let's look at 3 moles of this gas at T=300K starting in 0.001 m3 volume

Answers

Work done is given by

dw=Pdv, w=∫₁²(NkT/V-Nb)dv

The amount of work is 5708.00923 J.

What sort of moles are cancerous?

border that is erroneous Frequently, the edges are jagged, serrated, or blurry in outline. It's possible for the pigment to penetrate the nearby skin. unbalanced color: There could be various tones of tan, brown, and black. There may also be white, black, red, pink, and blue patches.

What is the quickest method for eliminating moles?

Using traps or bait with in spring or fall will increase your chances of successfully eliminating moles from your yard. The primary runway, or active runway, should be used for both goods. Usually, these are the vertical tunnels in your grass or the ones that round the outside of your property.

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how much work is required to move it at constant speed 5.0 m along the floor against a friction force of 230 n .\

Answers

(a) To move the crate, you need to exert 7150 J of energy.

(b) The Vertical Movement of the Crate Will Take 6000 J of Work.

Determine a constant speed?

A frictional force is one that tends to oppose the motion of two bodies in contact.

The crate must be moved using both effort against resistance and effort across a distance of 5.0 meters.

Wr = Wf plus Wd.

Where Wr = work needed to move the crate, Wf = work done to overcome friction, and Wd = work needed to move the crate 5.0 meters.

Given are the following values: Wf = friction force distance = 2305 = 1150 J and Wd = force distance = 12005.0 = 6000 J.

Wr = 6000 + 1150 Wr = 7150 J when these values are substituted into equation 1.

The amount of effort needed to move the crate is therefore 7150 J.

(b) The amount of labor necessary to lift the crate vertically: mgh or

Vertically moving the crate requires the following amount of work: Wh. Equation 2 h = vertical height, W = weight of the block

Provided:W = 1200 N, h = 5.0 m

Equation 2 can be solved by substituting these numbers as follows: Vertical movement of the crate: work required = 12005

Moving the box upward will require 6000 J of work.  

The complete question is,

On the ground is a crate weighing 1200 N. How much effort is needed to move it (a) 5.0 m along the floor while battling a 230 N friction force; and (b) 5.0 m vertically?

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describe the resultant chromosome number of the two daughter cells. indicate the genetic make-up of each cell.

Answers

Two identical daughter cells are produced during mitosis, and both of these cells have the same number of chromosomes as their parent cell. meiosis results in the production of four different daughter cells.

As a result, mitosisproduces four haploid daughter cells, each of which has a unique genetic makeup and half the DNA of the parent cell (Figure below). The parent cell of a human cell contains 46 chromosomes (23 pairs), hence the meiotic cells created have 23 chromosomes. They will develop into gametes. At this time, nuclear division starts, dividing the parent cell in half to create two daughter cells. Each daughter cell will contain 23 chromosomes, or half of the initial 46 chromosomes. Two sister chromatids make up each chromosome. The sister chromatids of each chromosome then separate during mitosis, resulting in one chromatid being received by each daughter cell from each chromosome. Two daughter cells with the same genetic makeup as the original cell are produced as a result of mitosis, and they all have two N chromosomes.

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What is the frequency of a 5. 0 m wave?.

Answers

The frequency of the wave be the wavelength 5m is 6 × 10⁷ Hz.

The frequency of a wave is given by the speed of light divided by the wavelength of the wave.

In this case the wavelength of the wave is 5m.

And, as we know the speed of light is 3 × 10⁸ m/s.

So we can write the above statement in the formula as,

V = c/λ

Where,

V is frequency,  

c is speed of light and λ is the wavelength.

Putting values,

V = 3 × 10⁸/5

V = 6 × 10⁷ Hz.

So, the frequency of this wave is 6 × 10⁷ Hz.

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if the cat has a mass of 3.7 kg , how far to the right of sawhorse b can it walk before the plank begins to tip?

Answers

If the cat has a mass of 2.9 kg, 1.8m far to the right of sawhorse B can it walk before the plank.

plank will tip when the weight of the cat about B is greater than the torque by the weight of the plank.

mg[tex]d_{2}[/tex] = mg[tex]d_{1}[/tex]

Rearrange for [tex]d_{2}\\[/tex].

[tex]d_{2}[/tex] = [tex]\frac{Mgd_{1}}{mg}[/tex]

[tex]d_{2}[/tex] = [tex]\frac{Md_{1}}{m}[/tex]

   = [tex]\frac{(6.00kg)(0.85)}{2.9kg}[/tex] = [tex]1.758m[/tex]

[tex]d_{2}[/tex] ≈ 1.8m

Mass is the amount of matter in a bodily frame. it's also a measure of the body's inertia, the resistance to acceleration (alternate of speed) while a net force is carried out. An item's mass additionally determines the electricity of its gravitational enchantment to different bodies.

In physics, mass is not similar to weight, even though mass is regularly decided by way of measuring the object's weight with the usage of a spring scale, instead of a stability scale evaluating it immediately with regarded masses.

An object on the Moon could weigh much less than it does in the world because of the decreased gravity, but it would nevertheless have the same mass. that is because weight is a force, at the same time as mass is the belongings that (alongside gravity) determine the electricity of this pressure.

The worldwide gadget of units (SI) unit of mass is the kilogram (kg). The kilogram is 1000 grams (g) and turned into first described in 1795 because of the mass of 1 cubic decimetre of water on the melting factor of ice. however, because the precise size of a cubic decimetre of water at the required temperature and strain changed into tough, in 1889 the kilogram was redefined because the mass of a metallic object

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Complete Question:

A cat walks along a plank with a mass of M= 6.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a distance d1= 0.850 m to the left of sawhorse B. When the cat is a distance d2= 1.11 m to the right of sawhorse B, the plank just begins to tip.

If the cat has a mass of 2.9 kg, how far to the right of sawhorse B can it walk before the plank begins to tip?

What is the wavelength of a 500 Hz wave?.

Answers

The correct answer is 0.6 x 10⁶.

Wavelength is the distance between the start of the wave and the end of the wave which is also the start of the next wave.

This wavelength describes how long the wave is.

Given,

Frequency = 500 Hz

Wavelength = λ = ?

c = speed of light = 3 x 10⁸

To find wavelength, we apply a formula,

Wavelength = speed of light / frequency

λ = 3 x 10⁸ / 5 x 10²

λ = 0.6 x 10⁶ m

Wavelength = 6 x 10⁵ m

Therefore, the wavelength of a 500 Hz is 6 x 10⁵ m.

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which statement is not a postulate of the kinetic molecular theory? which statement is not a postulate of the kinetic molecular theory? the attractive or repulsive forces between the gas molecules resulting in collisions that involve a slight loss of energy. the pressure of a gas in a container results from collisions between the gas molecules and the walls of the container. the volume of the gas molecules are negligibly small compared to the volume of the container. the root mean square speed of the gas molecules increases as the kelvin temperature of the gas increases.

Answers

According to kinetic molecular theory, there is no attractive and repulsive forces between the gas molecules.

The kinetic molecular theory is based on the following postulates:

Gases are made up of a large number of particles which behave like hard, spherical objects in a state of constant, random motion.These particles move in a straight path until they collide with another particle or the walls of the container.These particles are very smaller than the distance between particles. Most of the volume of a gas is hence empty space.There is no force of attraction between gas particles or between the particles and the walls of the container.Collisions between gas particles or collisions with the walls of the container are perfectly elastic. None of the energy of a gas particle is lost when it collides with another particle or with the walls of the container.The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.

So, correct option is 1 which states attractive or repulsive force between the gas molecules resulting in collisions that involve a slight lose of energy.

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