an experiment contestar of the stages. There are two posible outcomen in the three to those pound outcomes in a second days, und ti his com es * tot sag. The uns vorm of outcomes of this experimentis O a 24 O b. 26 Oc9 Od 18 Activate Windows

Answer: B: y-axis, because the x-coordinate is the opposite

Step-by-step explanation:

If the x coordinate is negative, it must have been reflected over the y axis.

likewise, if the y coordinate is negative, it must have been reflected over the x axes.

it should make intuitive sense :)

Answer:b

Step-by-step explanation:

The probability of exactly one success in the binomial experiment would be 20. 4 %.

The probability that there is one success in a binomial probability which has a chance of success of 5 % can be found by the formula :

P ( X = 1) = (5 choose 1) x ( 0.05 ) x  (0.95 ) ⁴

= ( 0.05 ) x  ( 0. 95 ) ⁴

= 0.05 x 0.8145

= 0.040725

Multiplying both gives:

P(X = 1) = 5 x 0.040725

= 0.203625

In conclusion, the probability of one success is 0.203625 or 20. 4 %.

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The evaluation gives 8.

Quotient is division of two given integers; which is expressed as a fraction. It can be expressed in the form of either proper fraction or improper fraction.

Considering the given question, we have;

quotient of 25 and 5 = 25/ 5

Then increased by 3, we have;

25/5 + 3

find the LCM of the expression

25/5 + 3 = (25 + 15)/5

              = 40/5

              = 8

Therefore on evaluation, the final answer is 8.

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The complex number can be written in polar form as 2 + ((2+m) + 3i) = √(m² + 6m + 25)∠tan⁻¹(3/(2+m)).

What is complex number?

A complex number is obtained by adding real and imaginary numbers. Complex numbers have the formula a + ib and are usually symbolized by the symbol z. Here the numbers a and real are both. The value "a" is known as the real component and is denoted Re(z), while "b" is known as the imaginary part and is denoted Im(z). Also known as imaginary number, ib. Hero of Alexandria, a Greek mathematician, first used the idea of complex numbers in the first century when he tried to calculate the square root of a negative integer.

a. A complex number is a number that consists of a real part and an imaginary part, where the imaginary part is the real number multiplied by the imaginary unit "i", defined as the square root of -1. The modulus of a complex number is the distance between the starting point and the point representing the complex number on the complex plane. This can be calculated using the Pythagorean theorem. For example, the real part of the complex number z = 3 + 4i is 3 and the imaginary part is 4, and its modulus is √(3²+4²)=5.

b. Let z = a + bi be a complex number, where a and b are real numbers. The modulus of z is defined as |z| = √(a² + b²). Therefore, for the complex number z = 1 + 2i, the modulus is |z| = √(1² + 2²) = √5.

c. To write the complex number 2 = ((2+ m) + 3i) in polar form, we need to find the modulus and argument of the complex number. The modulus is |2 + ((2+m) + 3i)| = |4 + mi + 3i| = √(4² + (m+3)²) = √(m² + 6m + 25). The argument is given by tan⁻¹(Im/Re) = tan⁻¹(3/(2+m)), which gives us the angle that the complex number makes with the positive real axis. Therefore, the complex number can be written in polar form as 2 + ((2+m) + 3i) = √(m² + 6m + 25)∠tan⁻¹(3/(2+m)).

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There is 75% of getting at least two tiles of vowels

Fits, less than two of the tiles are vowels

= 11 + 39

= 50

Now, at least two of tiles are vowels

= 200 - 50/ 200

= 150/200

= 0.75 x 100

= 75%

There is 75% of getting at least two tiles of vowels

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If Triangle ABC is reflected over the line y = 1. Then the coordinates of B' are (-2, 5)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Graph transformation is the process by which an existing graph, or graphed equation, is modified to produce a variation of the proceeding graph.

Now, we should reflect point B with respective to line y=1,

let us consider the reflected point coordinates be (h,k).

As  B is reflected with respect to line y=1 which is parallel to X-axis, the X-coordinate will be same.

and the midpoint of B and reflected point (h,k)  lies on line y=1

Hence h=-2 and (K-3)/2=1

k-3=2

k=5

Hence the reflected point of B i.e B' is (-2, 5)

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The reference angle for -400 is 5.729 degrees.

We have,

To find the reference angle for -400, we need to find the acute angle formed by the terminal side of the angle and the x-axis.

We start by drawing the angle in the standard position, which means placing the initial side of the angle along the positive x-axis and rotating the terminal side in the clockwise direction.

Since -400 is in the fourth quadrant, the terminal side of the angle would lie 400 units clockwise from the negative x-axis.

To find the reference angle, we need to find the acute angle formed by the terminal side and the x-axis.

This is simply the angle formed by the terminal side and a perpendicular line dropped from the endpoint of the terminal side to the x-axis.

In this case, the perpendicular line would drop 40 units to the x-axis, forming a right triangle with legs of 40 and 400 units.

Using the Pythagorean theorem, we can find the hypotenuse of this right triangle, which is the distance from the origin to the endpoint of the terminal side:

h = √(40² + 400²) = 404

The sine of the reference angle is the ratio of the opposite leg to the hypotenuse:

sin Ф = opposite/hypotenuse = 40/404 = 0.099

Taking the inverse sine of this value, we can find the reference angle:

Ф = [tex]Sin^{-1}[/tex](0.099) = 5.729 degrees

Therefore,

The reference angle for -400 is 5.729 degrees.

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The cumulative distribution function of X is F(x) = (x-0)/(5.2-0) = x/5.2. The value of x such that F(x) = 0.75 is the upper quartile. Solving for x, we get x = 3.9 seconds.

a. The mean of this distribution is (0+5.2)/2 = 2.6 seconds.

b. The standard deviation is (5.2-0)/sqrt(12) = 1.5 seconds.

c. The probability that wave will crash onto the beach exactly 3.1 seconds after the person arrives is P(x = 3.1) = 1/5.2 = 0.1923.

d. The probability that the wave will crash onto the beach between 0.8 and 4.2 seconds after the person arrives is P(0.8 < x < 4.2) = (4.2-0.8)/(5.2-0) = 0.7692.

e. The probability that the wave will crash onto the beach before 2.34 seconds after the person arrives is P(x < 2.34) = 2.34/5.2 = 0.45.

f. Suppose that the person has already been standing at the shoreline for 0.5 seconds without a wave crashing in. The time until the wave crashes onto the shoreline follows a uniform distribution from 0.5 to 5.2 seconds. The probability that it will take between 2.7 and 3.9 seconds for the wave to crash onto the shoreline is P(2.7 < x < 3.9) = (3.9-2.7)/(5.2-0.5) = 0.204.

g. 12% of the time a person will wait at least how long before the wave crashes in? Let X be the time until the wave crashes onto the shoreline. The probability that a person will wait at least X seconds is P(X > x) = (5.2-x)/5.2. We want to find the value of x such that P(X > x) = 0.12. Solving for x, we get x = 4.576 seconds.

h. The upper quartile is the 75th percentile of the distribution. Let X be the time until the wave crashes onto the shoreline. The cumulative distribution function of X is F(x) = (x-0)/(5.2-0) = x/5.2. The value of x such that F(x) = 0.75 is the upper quartile. Solving for x, we get x = 3.9 seconds.

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Answer:

Step-by-step explanation:

358 in

A=2(wl+hl+hw)=2·(6·15.5+4·15.5+4·6)=358

The surface area of the rectangular prism is 358 square inches.

Given dimensions of the prism are:

The formula to find the surface area of a rectangular prism is:

Surface Area = 2*(length * width + length * height + width * height)

Plugging in the values we have:

Surface Area = 2*(15.5 * 6 + 15.5 * 4 + 6 * 4) = 2*(93 + 62 + 24) = 2*(179) = 358 square inches

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Therefore, the ending balance after 6 years would be $2,728.31

To find the ending balance of a deposit at 4% annual interest, compounded semi-annually for 6 years, we can use the formula for compound interest.

A = P (1 + r/n)^(nt)

Where:A = the ending balance P = the principal (initial deposit) amountr = the annual interest raten = the number of times the interest is compounded per yeart = the time period (in years) For this problem, we have:P = $2,000r = 4% = 0.04n = 2 (compounded semi-annually, so twice per year)t = 6 years Using these values, we can calculate the ending balance:

A = 2000(1 + 0.04/2)^(2*6)A = 2000(1.02)^12A = $2,728.31

.

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The non-skewness criterion using estimates for p₁ and p₂ is 0.21 and null hypothesis test for whether a higher proportion of people in Toronto own a French bulldog relative to the proportion of people in Guelph is Z= 1.47.

A statistical hypothesis known as a null hypothesis asserts that no statistical significance can be found in a collection of provided observations. Using sample data, hypothesis testing is performed to judge a theory' veracity. It is sometimes referred to as the "null," and it is denoted by the symbol H₀.

To determine if a theory regarding markets, investment methods, or economies is correct or wrong, quantitative analysts employ the null hypothesis, often known as the conjecture.

a) n₁ = 55, n₂ = 62

x₁ = 15, x₂ = 10

a) Toronto = [tex]P_1[/tex] = [tex]\frac{x_1}{n_1}[/tex] = 15/55 = 0.27

Guelph = [tex]P_2[/tex] = [tex]\frac{x_2}{n_2}[/tex] = 10/62 = 0.21

P = [tex]\frac{x_1+x_2}{n_1+n_2}[/tex] = 15+10/55+62 = 0.21

b) The null hypothesis

H₀ = P₁ - P₂ = 0

H₁ = P₁-P₂ > 0

Test statistics (Z) = [tex]\frac{(P_1-P_2)-0}{\sqrt{P(1-P)(\frac{1}{n_1}+\frac{1}{n_2}) } }[/tex]

= 0.11/0.075

Z= 1.47.

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There are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

To seat three adults and three children at a circular table such that each child must be next to two adults, we can use the following steps:

There are 2! options for the other two adults and 3! options for children.

The number of ways for two adults and children:

= 2! × 3!

= 2 × 6

= 12 ways to seat them

There are 3 ways to pick the two children, two ways to seat them, and two ways for them to begin the circle, for a total of six options.

The third child has a pair of choices:

6 × 2 so far

Then, there are 3! =6  ways to seat the adults.

6 × 2 × 6 = 72 ways

Putting it all together, the total number of seating arrangements is:

12+72 = 84 ways  

Therefore, there are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

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Answer:

The sum of the interior angles of any quadrilateral is 360 degrees.

So, let x be the measure of the fourth angle. Then we can write the equation:

98 + 139 + 80 + x = 360

Simplifying this equation gives:

317 + x = 360

Subtracting 317 from both sides gives:

x = 43

Therefore, the measure of the fourth interior angle of this convex quadrilateral is 43 degrees.

Step-by-step explanation:

The measure of the fourth interior angle of the convex quadrilateral is 43 degrees. To find the measure of the fourth interior angle of a convex quadrilateral, we'll use the following terms: interior, angles, quadrilateral, and measure.

Step 1: Remember that the sum of interior angles of a quadrilateral is always 360 degrees.

Step 2: Add the three given interior angles: 98 + 139 + 80 = 317 degrees.

Step 3: Subtract the sum of the three angles from the total sum of quadrilateral angles (360 degrees) to find the measure of the fourth angle: 360 - 317 = 43 degrees.

The measure of the fourth interior angle of the convex quadrilateral is 43 degrees.

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Answer:

24 is the answer

Step-by-step explanation:

add the numbers and divide them by 7

The Quasilinearization Method is defined as a numerical method used to approximate the solutions of nonlinear differential equations. In the context of first-order initial value problems (IVPs), a maximal solution is the largest possible solution that exists for the given initial value, while a minimal solution is the smallest possible solution that exists for the given initial value.

In other words, a maximal solution is a solution that extends as far as possible beyond the given initial value without encountering any singularities or breaking down, while a minimal solution is a solution that is defined only on a minimal interval around the initial value, beyond which it cannot be extended without encountering a singularity or breaking down.

It is worth noting that not all first-order IVPs have both maximal and minimal solutions, as some may have either no solution, a unique solution, or multiple solutions that overlap or intersect.

However, if a maximal solution and a minimal solution do exist for a given IVP, they are guaranteed to be unique and continuous.

In summary, the Quasilinearization Method can be used to approximate both the maximal and minimal solutions of a first-order IVP, which represent the largest and smallest possible solutions that exist for the given initial value.

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The dimensions of section B are 36 inches by 48 inches, and the area of the piece of sheet metal after both sections are cut and removed is 6336 square inches.

Given the width and length of a rectangular piece of sheet metal as 60 inches and 44 inches, we need to find the dimensions of section B and the area of the piece of sheet metal after both sections are cut and removed.

The length of rectangle B can be found as TR = SR - ST = PQ - ST, where SR and PQ are opposite sides of the rectangle. Here, PQ is the length of the rectangular sheet metal, which is 60 inches, and ST is the width of the rectangle WVTX, which is 24 inches. Therefore, the length of rectangle B is:

TR = PQ - ST = 60 - 24 = 36 inches

The breadth of rectangle B can be found as UR = QR - QV - VT - TU. Here, QR and PS are opposite sides of the rectangle PQRS, so QR = PS = 144 inches. Also, QV is the width of rectangle WVTX, which is 36 inches, and VT and TU are the lengths of rectangle WVTX, which are both 24 inches. Therefore, the breadth of rectangle B is:

UR = QR - QV - VT - TU = 144 - 36 - 24 - 36 = 48 inches

So, the dimensions of section B are 36 inches by 48 inches.

Next, we need to find the area of the piece of sheet metal after both sections are cut and removed.

The area of rectangle B is the product of its length and breadth, which is:

Area of rectangle B = length × breadth = 36 × 48 = 1728 square inches

The area of rectangle WVTX is the product of its length and breadth, which is:

Area of rectangle WVTX = length × breadth = 24 × 24 = 576 square inches

The area of rectangle PQRS is the product of its length and breadth, which is:

Area of rectangle PQRS = PQ × PS = 60 × 144 = 8640 square inches

Therefore, the area of the piece of sheet metal after both sections are cut and removed is:

Area of the piece of sheet metal = Area of rectangle PQRS - Area of rectangle B - Area of rectangle WVTX

= 8640 - (1728 + 576)

= 8640 - 2304

= 6336 square inches

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The number of possibilities to make three-digit numbers from 1,4,5,6,3 that the first digit is even and the third digit is odd is 24.

1) To find the number of possibilities to make three-digit numbers from 1, 4, 5, 6, 3 where the first digit is even and the third digit is odd, follow these steps:

Identify the even numbers (for the first digit) - 4 and 6.
Identify the odd numbers (for the third digit) - 1, 3, and 5.
Calculate the possibilities for the second digit. Since we're using the remaining digits, there are 3 options left for each combination.
Multiply the possibilities together: 2 (even numbers) x 3 (second digit options) x 3 (odd numbers) = 18 possibilities.

2) To find the number of ways 5 students can seat in a circle, use the formula (n-1)!. Where n is the number of students.

For 5 students, there are (5-1)! = 4! = 4 x 3 x 2 x 1 = 24 ways for them to sit in a circle.

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Answer:

A. 4^2 - 4(2)(26) = 16 - 208 = -192

B. This equation has no real roots.

C. (-4 + √-192)/(2×2) = (-4 + 8i√3)/4

= -1 + (2√3)i

y(x) = y_c(x) + y_p(x)

To find the general solution of the given differential equations using the variation of parameters method:

(i) y" - 4y' + 3y = e^x

The complementary solution of the homogeneous equation is found by solving the characteristic equation:

r^2 - 4r + 3 = 0

(r - 1)(r - 3) = 0

The roots are r = 1 and r = 3, so the complementary solution is:

y_c(x) = C1e^x + C2e^(3x)

Now, we need to find the particular solution using the variation of parameters method. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

where u1(x) and u2(x) are functions to be determined.

Differentiating y_p(x), we have:

y_p'(x) = u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x)

y_p''(x) = u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x)

Substituting y_p(x), y_p'(x), and y_p''(x) back into the original equation, we get:

(u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x))

4(u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x))

3(u1(x)e^x + u2(x)e^(3x)) = e^x

Now, we equate the coefficients of like terms on both sides of the equation:

e^x terms:

u1''(x) - 2u1'(x) + u1(x) = 1

e^(3x) terms:

u2''(x) + 6u2'(x) + 9u2(x) = 0

Solve these two differential equations to find u1(x) and u2(x). Once you have u1(x) and u2(x), substitute them back into the particular solution:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

Finally, the general solution is given by:

y(x) = y_c(x) + y_p(x)

(ii) y" - 2y' + y = e^x / (x^2 + 1)

The process is similar to the first equation, but with a slight difference in the particular solution. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^xln(x^2 + 1)

Differentiate y_p(x) and substitute it back into the original equation to find u1(x) and u2(x). Then the general solution is given by:

y(x) = y_c(x) + y_p(x)

Note: Solving the differential equations for u1(x) and u2(x) in both cases can be quite involved, and the exact form of the particular solution may vary depending on the specific calculations.

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Broker U's package costs $156.02 less money than Broker V's package. The Option C is correct.

Broker U: 2.8% commission

2 par value bonds $1,000 x 96.674% = $1,933.48

3 par value bond $500 x 109.330% = $1,639.95

2 par value bonds $1,000 x 103.851% = $2,077.02

Silvia's total investment:

= ($1,933.48 + $1,639.95 + $2,077.02) x 1.028

= $5,808.66

Broker V: $65 per bond plus

4 par value bonds $500 x 105.142% = $2,102.84

1 par value bond $500 x 85.990% = $429.95

3 par value bonds $1,000 x 97.063% = $2,911.89

Silvia's total investment:

= $2,102.84 + $429.95 + $2,911.89 + (8 x $65)

= $5,964.68

By how much of less that these bond package cost is:

= Broker V's offer - Broker U's offer

= $5,964.68 - $5,808.66

= $156.02

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To find the equation of the line of intersection of two planes, we need to find the direction vector of the line. This can be done by taking the cross product of the normal vectors of the two planes.

Let the two planes be:
P1: 2x - y + 3z = 5
P2: x + 2y - 4z = -1
The normal vectors of these planes are:
n1 = <2, -1, 3>
n2 = <1, 2, -4>
Taking the cross product of these two vectors, we get:
n1 x n2 = <14, 10, 5>
This is the direction vector of the line of intersection.
To get the vector form of the equation, we need a point on the line. We can choose any point that lies on both planes. To make it easy, we can set z = 0 in both planes and solve for x and y.
From P1:
2x - y = 5
From P2:
x + 2y = -1
Solving these equations, we get:
x = -7/5
y = -3/5
So a point on the line is (-7/5, -3/5, 0).
Using this point and the direction vector, the vector form of the equation of the line of intersection is:
r = <-7/5, -3/5, 0> + t<14, 10, 5>
Here, t represents the parameter.

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The test statistic for this sample is -3.861, and the p-value for this sample is 0.0001. The p-value is less than the significance level α.

To test the claim (Ha) at a significance level of α = 0.005, with the given information, we will first find the test statistic and then the p-value.

1. Calculate the sample proportions: p1 = 31.8% successes in a sample of size n1 = 600, and p2 = 44.6% successes in a sample of size n2 = 314.

2. Find the difference between the sample proportions: d = p1 - p2.

3. Calculate the pooled proportion: P = (p1 * n1 + p2 * n2) / (n1 + n2).

4. Find the standard error: SE = sqrt(P * (1 - P) * (1/n1 + 1/n2)).

5. Calculate the test statistic (z): z = (d - 0) / SE.

Using the given information, the test statistic is -3.861.

Now, let's find the p-value:

6. Using the standard normal distribution table or calculator, find the p-value corresponding to the test statistic.

The p-value for this sample is 0.0001.

Now, compare the p-value to the significance level α:

The p-value (0.0001) is less than the significance level α (0.005).

Therefore, the test statistic for this sample is -3.861, and the p-value for this sample is 0.0001. The p-value is less than the significance level α.

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The solutions to the equation 5x²+14x=x+6 are x = 4/5 or x = -3 we solved by using quadratic formula

The given equation is 5x²+14x=x+6

We have to solve for x

Subtract x from both sides

5x²+13x=6

Subtract 6 from both sides

5x²+13x-6=0

Now we can use the quadratic formula to solve for x:

x = (-b ± √(b²- 4ac)) / 2a

where a = 5, b = 13, and c = -6.

Substituting these values and simplifying:

x = (-13 ±√(13²- 4(5)(-6))) / (2 × 5)

x = (-13 ± √289)) / 10

x = (-13 ± 17) / 10

So we get two solutions:

x = 4/5 or x = -3

Therefore, the solutions to the equation 5x^2 + 14x = x + 6 are x = 4/5 or x = -3.

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Answer:

Let x be the length of Danika's old running route in miles.

Then, her new running route can be represented by x + 4, since it is 4 miles longer than her old route.

Step-by-step explanation:

The required manager should charge $1600 for one-bedroom units and $2250 for two-bedroom units to maximize revenue.

Let x be the number of $20 increases in the price of a one-bedroom unit, and y be the number of $60 increases in the price of a two-bedroom unit. Then the rental prices for one-bedroom and two-bedroom units can be expressed as:

One-bedroom price = $1200 + $20x

Two-bedroom price = $1800 + $60y

The total number of customers for one-bedroom units is 90 minus the number of customers lost due to the price increase, which is x. Similarly, the total number of customers for two-bedroom units is 100 minus the number of customers lost due to the price increase, which is 2y. Therefore, the total revenue can be expressed as:

Revenue = (90 - x) * ($1200 + $20x) + (100 - 2y) * ($1800 + $60y)

Expanding and simplifying this expression, we get:

Revenue = 216000 + 9600x - 240x² + 180000 + 108000y - 7200y²

Collecting like terms, we get:

Revenue = -240x² - 7200y² + 9600x + 108000y + 396000

To find the rental price that maximizes revenue, we need to find the values of x and y that maximize the revenue. We can do this by taking partial derivatives of the revenue function with respect to x and y and setting them equal to zero:

dRevenue/dx = -480x + 9600 = 0

dRevenue/dy = -14400y + 108000 = 0

Solving for x and y, we get:

x = 20

y = 7.5

Therefore, the rental prices that maximize revenue are:

One-bedroom price = $1200 + $20x = $1600

Two-bedroom price = $1800 + $60y = $2250

So the manager should charge $1600 for one-bedroom units and $2250 for two-bedroom units to maximize revenue.

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Answer: 11.76

Step-by-step explanation:  you have to divide by 12 everything and multiply by 6 and you can get the answer

The only option that has a number that is divisible by both 5 and 6 is: D.193.560

We want to find a number that is divisible by both 5 and 6.

Now, looking at the options, since they are all decimals, the one that would be the most appropriate is the one that does not contain a recurring decimal.

Thus:

A) 132.359/5 =26.4718

132.359/6 = 22.0598333..

B) 142.645/5 = 28.529

142.645/6 = 23.77416666666..

C) 164.780/5 = 32.956

164.780/6 = 27.46333333

D) 193.560/5 = 38.712

193.560/6 = 32.26

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Answer:

68 squer meter

Step-by-step explanation:

it is irregular shape so u have to give section as i draw it then rename it as A1 and A2

A1 = L×W

=13m × 2m

= 26m2

A2= L × W

=7m × 6m

= 42m2

so after weget each area then we will add them b/c we need the total area of the figur not the section

let At = area of totalAt = A1 + A2

= 26m2 + 42m2

=68m2 good luck..

The equation for money collected m for h boxes of chocolate bars sold is m = 30h.

We are given that the band is selling every bar of chocolate for $1.50

Now, they have boxes of chocolate, with every box containing 20 bars of chocolate in them.

Hence if we are going to calculate the amount of money collected on selling one box it will be

20 X $1.5

= $30

We need to find the equation for the amount of money collected based on the number of boxes of chocolate bars sold.

We have been given that money collected should be represented b m while the number of chocolate boxes sold should be represented by h

Now we know that

Money collected = price per box X no.of boxes sold

we have already calculated the price per box hence we get

m = 30h

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