Answer:
[tex]W=5.16 J[/tex]
Explanation:
Using the Hooke's law we can find the elasticity constant:
[tex]F=-k\Delta x[/tex]
[tex]30.8=-k*0.177[/tex]
[tex]k=|-\frac{30.8}{0.177}|[/tex]
[tex]k=174 N/m[/tex]
Now, we know that the work done is equal to the elastic energy, so we will have:
[tex]W=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})[/tex]
x2 is the final distance (x2 = 0.177+0.124 = 0.301 m)
x1 is the initial distance (x1 = 0.177 m)
[tex]W=\frac{1}{2}*174(0.301^{2}-0.177^{2})[/tex]
[tex]W=5.16 J[/tex]
I hope it helps you!
What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make a larger set of waves in the same direction as that of the smaller waves. A label Wave motion is above the series of waves and an arrow next to the label points right. The particles will move up and down over large areas. The particles will move up and down over small areas. The particles will move side to side over small areas. The particles will move side to side over large areas.
Answer:
D
Explanation:
The particles will move side to side over large areas
Answer:
→A←Explanation:
D its incorrect in edge
A chemical reaction occurs. Which of the following would indicate that energy is transformed during the reaction? A. an electrical charge is produced B. heat is produced C. light is produced D. all of these
Answer:
b
Explanation:
A magnetic field applies forces on blank
Answer:
moving charges
Explanation:
In witch water environment would holdfast be most useful
Answer: Holdfast is a root- like structure by which an aquatic sessile algae are attached to a substrate. Its primary function is to secure the organism to the sea floor, i.e anchorage.
Part F A system experiences a change in internal energy of 14 kJkJ in a process that involves a transfer of 36 kJkJ of heat into the system. Simultaneously, which of the following is true? A system experiences a change in internal energy of 14 in a process that involves a transfer of 36 of heat into the system. Simultaneously, which of the following is true? 22 kJkJ of work is done by the system. 22 kJkJ of work is done on the system. 50 kJkJ of work is done by the system. 50 kJkJ of work is done on the system
Answer:
Explanation:
According to first law of thermodynamics :
Q = ΔE + W
Q is heat added , ΔE is increase in the internal energy of the system and W is work done by the system .
Here Q = 36 KJ
ΔE = 14 kJ
Putting the values in the equation
36 = 14 + W
W = 36 - 14
= 22 kJ .
Work done by gas or system = 22 kJ.
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1q1q_1 = -15.0 nCnC , is located at x1x1x_1 = -1.660 mm ; the second charge, q2q2q_2 = 34.5 nCnC , is at the origin (x=0.0000)(x=0.0000).
What is the net force exerted by these two charges on a third charge q3q3q_3 = 47.0 nCnC placed between q1q1q_1 and q2q2q_2 at x3x3x_3 = -1.240 mm ?
Your answer may be positive or negative, depending on the direction of the force.
Answer:
Explanation:
Force between two charges of q₁ and q₂ at distance d is given by the expression
F = k q₁ q₂ / d₂
Here force between charge q₁ = - 15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = (1.66 - 1.24 ) = .42 mm
k = 1/ 4π x 8.85 x 10⁻¹²
putting the values in the expression
F = 1/ 4π x 8.85 x 10⁻¹² x - 15 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²
= 9 x 10⁹ x - 15 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²
= 35969.4 x 10⁻³ N .
force between charge q₂ = 34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = ( 1.24 - 0 ) = 1.24 mm .
putting the values in the expression
F = 1/ 4π x 8.85 x 10⁻¹² x 34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²
= 9 x 10⁹ x - 34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²
= 82729.6 x 10⁻³ N
Both these forces will act in the same direction towards the left (away from the origin towards - ve x axis)
Total force = 118699 x 10⁻³
= 118.7 N.
Forests have been completely wiped out in some parts the world. In areas that are economically depressed, people use the cut wood to fuel fires for cooking and for making shelters or homes. How would deforestation most likely impact Earth's biogeochemical cycles?
Group of answer choices
Less carbon dioxide will be present in the atmosphere because the people living in the area still breath in oxygen.
An increase in carbon dioxide will occur in the atmosphere because there are less trees to use the gas in the process of photosynthesis.
Carbon dioxide levels will not change, since plants do not have a role in the carbon cycle.
More water will be released into the atmosphere because transpiration and condensation will produce more precipitation.
Answer: An increase in carbon dioxide will occur in the atmosphere because there are less trees to use the gas in the process of photosynthesis.
Explanation: Photosynthesis can be simply defined as a process where green plants uses minerals from the soil, water and carbon dioxide to produce their own food (energy-rich organic compound/starch) while oxygen is released into the environment.
On the other hand, Human beings and other animals inhales the oxygen released into the environment by green plants and breath out carbon dioxide.
Deforestation is the permanent removal trees either for commercial or household use or in some cases, to make room or space for other activities or development.
Now when these trees (green plants) are permanently cut down without replacement, humans and other animals continuously exhale carbon dioxide and there will be little or no green plants (trees) available to convert this carbon dioxide into oxygen.
Hence, there will be an increased amount of carbon dioxide in the atmosphere as their are little or no tress to use the gas (carbon dioxide) in the process of photosynthesis.
What is (9x10^9)(2.6x10^-6)(1.4x10^-6) / 36
Answer:
0.00091
Explanation:
(9x10^9) (2.6x10^-6) (1.4x10^-6) / 36
(9,000,000,000) (0.0000026) (0.0000014) /36
|
23,400(0.0000014) /36
|
0.03276 /36
|
0.00091
A radiator rests snugly on the floor of a room when the temperature is 10 oC. The radiator is connected to the furnace in the basement by a pipe that is 15 m long. How far off the floor will the radiator be lifted when it is filled with steam at 102 oC? The iron expands 1.0 * 10-5 / oC.
A long solid conducting cylinder with radius a = 12 cm carries current I1 = 5 A going into the page. This current is distributed uniformly over the cross section of the cylinder. A cylindrical shell with radius b = 21 cm is concentric with the solid cylinder and carries a current I2 = 3 A coming out of the page. 1)Calculate the y component of the magnetic field By at point P, which lies on the x axis a distance r = 41 cm from the center of the cylinders.
Answer:
Explanation:
We shall use Ampere's circuital law to find magnetic field at required point.
The point is outside the circumference of two given wires so whole current will be accounted for .
Ampere's circuital law
B = ∫ Bdl = μ₀ I
line integral will be over circular path of radius r = 41 cm .
Total current I = 5A -3A = 2A .
∫ Bdl = μ₀ I
2π r B = μ₀ I
2π x .41 B = 4π x 10⁻⁷ x 2
B = 2 x 10⁻⁷ x 2 / .41
= 9.75 x 10⁻⁷ T . It will be along - ve Y - direction.
Which of the following is correct? When a current carrying wire is in your left hand, thumb in the direction of the magnetic field lines, your fingers point in the direction of the current. When a current carrying wire is in your left hand, thumb in the direction of the current, your fingers point in the direction of the magnetic field lines. When a current carrying wire is in your right hand, thumb in the direction of the magnetic field lines, your fingers point in the direction of the current. When a current carrying wire is in your right hand, thumb in the direction of the current, your fingers point in the direction of the magnetic field lines.
Answer:
When a current carrying wire is in your left hand, thumb in the direction of the magnetic field lines, your fingers point in the direction of the current
Explanation:
This is in line with the left hand rule
B.) When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
g Which one of the following statements is false?The "ray model" of light can explain how images are formed by spherical mirrors. The "ray model" of light can explain the phenomenon known as a shadow. The "wave model" of light is necessary to explain phenomena such as diffraction and interference. The "ray model" of light can explain how images are formed by thin lenses. According to the "ray model", light is an electromagnetic wave that consists of oscillating electric and magnetic fields.
Answer
Correct option : According to the "ray model", light is an electromagnetic wave that consists of oscillating electric and magnetic fields.
Explanation : According to Ray model light is a simple transverse wave not a electromagnetic wave.
A 20-kilogram box is sitting on an inclined plane with a 30-degree slope. If the box is at rest, what is the force
on the box due to friction?
Answer:
Explanation:
The box is at rest because , the component of weight along the surface downwards is equal to frictional force .
frictional force = mgsinθ
= 20 x 9.8 sin 30
= 98 N .
A particle with charge q = +1e and mass m = 5.5×10^-26 kg is injected horizontally with speed 2.4×10^6 m/s into the region between two parallel horizontal plates. The plates are 22 cm long and 1.2 cm apart. The particle is injected midway between the top and bottom plates. The top plate is negatively charged and the bottom plate is positively charged, so that there is an upward-directed electric field between the plates, of magnitude E = 33 kN/C. Ignore the weight of the particle.
(a) How long, in seconds, does it take for the particle to pass through the region between the plates?
(b) When the particle exits the region between the plates, what will be the magnitude of its vertical displacement from its entry height, in millimeters?
Answer:
a) t = 9.16*10^{-18} s
b) y = 0.402 mm
Explanation:
(a) To find the time that the particle takes to pass trough the region between parallel plates, you take into account that the horizontal component of the velocity is constant in all trajectory of the particle. Then, you use the following formula:
[tex]t=\frac{x}{v_x}\\\\[/tex]
x: length of the sides of the plates = 0.22m
v_x: horizontal component of the velocity = 2.4*10^6 m/s
[tex]t=\frac{0.22m}{2.4*10^6m/s}\\\\t=9.16*10^{-8}s=91.6ns[/tex]
(b) To find the vertical displacement of the particle you first calculate the acceleration of the particle generated by the electric force:
[tex]F_e=ma\\\\qE=ma\\\\a=\frac{qE}{m}\\\\a=\frac{(1.6*10^{-19}C)(33*10^3N/C)}{5.5*10^{-26}C}=9.6*10^{10}\frac{m}{s^2}[/tex]
where you have used that the charge is 1.6*10^-19 C (charge of an electron).
With the values of the acceleration and time you use the following kinematic equation to calculate the vertical displacement:
[tex]y=v_{oy}t+\frac{1}{2}at^2\\\\v_{oy}=0m/s\\\\y=\frac{1}{2}(9.6*10^{10}\frac{m}{s^2})(9.16*10^{-8}s)^2=4.02*10^{-4}m=0.402mm[/tex]
Following are the solution to the given points:
When calculating the time required the particle will pass through the zone between plates, remember that such a horizontal component of the particle's velocity is fixed throughout the particle's route. The following formula is then used:
[tex]\to t=\frac{x}{v_x}[/tex]
[tex]\to x:[/tex] plate length = 0.22m
[tex]\to v_x :[/tex]velocity's horizontal component[tex]= 2.4\times 10^{6} \ \frac{m}{s}\\\\[/tex]
[tex]\to t=\frac{0.22\ m}{ 2.4 \times 10^6 \frac{m}{s}}= 9.16 \times 10^{-8} \ s = 91.6 \ ns[/tex]
To determine the particle's vertical displacement, firstly compute the particle's acceleration due to electric force:[tex]\to F_e=ma\\\\\to qE=ma\\\\\to a=\frac{qE}{m}\\\\[/tex]
[tex]=\frac{1.6 \times 10^{-19}\ C \times 33 \times 10^3 \frac{N}{C}}{5.5 \times 10^{-26} C} \\\\ =\frac{1.6 \times 10^{-16} \times 33 \times 10^{26}}{5.5} \\\\ =\frac{1.6 \times 33 \times 10^{10}}{5.5} \\\\ =\frac{16 \times 33 \times 10^{10}}{55} \\\\ = 9.6 \times 10^{10} \ \frac{m}{s^2}\\\\[/tex]
when you have used that charge [tex]1.6\times 10^{-19}\ C[/tex]electronic charge).The following kinematic formula is used to determine vertical displacement using the values of acceleration and time:[tex]\to y=v_{oy} t+\frac{1}{2} at^2\\\\\to v_{oy}= 0 \ \frac{m}{s}\\\\\to y=\frac{1}{2} (9.6 \times 10^{10} \frac{m}{s^2}) (9.6 \times 10^{-8}\ s)^2[/tex]
[tex]= 4.02 \times 10^{-2} \ m \\\\ = 0.402 \ mm\\\\[/tex]
Find out more information about the displacement:
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What types of mediums are involved in the energy transfer
Answer:
In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.
A student performs an experiment that involves the motion of a pendulum. The student attaches one end of a string to an object of mass M and secures the other end of the string so that the object is at rest as it hangs from the string. When the student raises the object to a height above its lowest point and releases it from rest, the object undergoes simple harmonic motion. As the student collects data about the time it takes for the pendulum to undergo one oscillation, the student observes that the time for one swing significantly changes after each oscillation. The student wants to conduct the experiment a second time. Which two of the following procedures should the student consider when conducting the second experiment?
a) Make sure that the length of the string is not too long.
b) Make sure that the mass of the pendulum is not too large.
c) Make sure that the difference in height between the pendulum's release position and rest position is not too large.
d) Make sure that the experiment is conducted in an environment that has minimal wind resistance.
Answer:
the answers the correct one is cη
Explanation:
In this simple pendulum experiment the student observes a significant change in time between each period. This occurs since an approximation used is that the sine of the angle is small, so
sin θ = θ
with this approach the equation will be surveyed
d² θ / dt² = - g / L sin θ
It is reduced to
d² θ / dt² = - g / L θ
in which the time for each oscillation is constant, for this approximation the angle must be less than 10º so that the difference between the sine and the angles is less than 1%
The angle is related to the height of the pendulum
sin θ = h / L
h = L sin θ.
Therefore the student must be careful that the height is small.
When reviewing the answers the correct one is cη
Considering the approximation of simple harmonic motion, the correct option is:
(c) Make sure that the difference in height between the pendulum's release position and rest position is not too large.
Simple Harmonic MotionAccording to Newton's second law in case of rotational motion, we have;
[tex]\tau = I \alpha[/tex]
Applying this, in the case of a simple pendulum, we get;
[tex]-mg\,sin\,\theta =mL^2 \,\frac{d^2 \theta}{dt^2}[/tex]
On, rearranging the above equation, we get;
[tex]mL^2 \,\frac{d^2 \theta}{dt^2} + mg\,sin\,\theta=0\\\\\implies \frac{d^2 \theta}{dt^2} +\frac{g}{L} sin \,\theta=0[/tex]
Now, if angular displacement is very small, i.e.; the bob of the pendulum is only raised slightly.
Then, [tex]sin\, \theta \approx \theta[/tex]
[tex]\implies \frac{d^2 \theta}{dt^2} +\frac{g}{L} \,\theta=0[/tex]
This is now in the form of the equation of a simple harmonic motion.
[tex]\frac{d^2 \theta}{dt^2} +\omega^2 \,\theta=0[/tex]
Comparing both these equations, we can say that;
[tex]\omega = \sqrt{\frac{g}{L}}[/tex]
[tex]T=2\pi\sqrt{\frac{L}{g}}[/tex]
This relation for the time period can only be obtained if the angular displacement is very less.
So, the correct option is;
Option (c): Make sure that the difference in height between the pendulum's release position and rest position is not too large.
Learn more about simple harmonic motion here:
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Electric motors convert electrical energy to mechanical energy. When the current-carrying coil is placed between the magnetic poles, a force acts on it that causes it to rotate. The image below shows a simple electric motor. The motor is used to lift metal boxes. How can the motor be changed to be able to lift a heavier box? A. rotate the coil in a counter-clockwise direction B. add more loops of wire between the magnets C. change the polarity of the magnet D. decrease the size of the magnets
Answer:
B. add more loops of wire between the magnets
Explanation:
this would increase the magnetic force acting on the rod therefore increasing
By adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.
What is an electric motor?An electric motor is a mechanism that turns electricity into mechanical energy.
The interaction between the motor's magnetic field and electric current in a wire winding generates force in the form of torque imparted to the motor's shaft in most electric motors.
An electric generator is physically equivalent to an electric motor, but it converts mechanical energy into electrical energy using a reversed flow of power.
The load capacity in the motor can be increased by increasing the no of loops. So by adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.
Hence option B is correct.
To learn more about the electric motor refer to the link;
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A particular coil has 100 turns and a diameter of 6.0 m. When it's time for a measurement, a 4.5 A current is turned on. The large diameter of the coil means that the field in the water flowing directly above the center of the coil is approximately equal to the field in the center of the coil. The field is directed downward and the water is flowing east. The water is flowing above the center of the coil at 1.5 m/s .
What is the magnitude of the field at the center of the coil?
Answer:
The magnetic field at the center of the coil = 5.23 * 10 ^ -5 T
Explanation:
Information from the question:
Number of turns of the coil = 100 turns
The diameter of the coil = 6 m
The radius of the coil = diameter / 2 = 3 m
The coil current = 2.5 A
Formula : The Magnetic field at the center of the coil =
k * number of turns * current / 2 * radius
Therefore, The Magnetic field at the center of the coil=
(4 * [tex]\pi[/tex] * 10 ^ -7 * 100 * 2.5 ) / (2 * 3)
The Magnetic field at the center of the coil = 5.23 * 10 ^ -5 T
the speed of sound is 343m/s. dezeirey is positioned 5m behind her. how many seconds will it take for the echo from the wall to reach her
Answer:
t = 0.029 s
Explanation:
We have,
Speed of sound is 343 m/s.
Dezeirey is positioned 5 m behind her.
It is required to find the time taken for the echo from the wall to reach her. The total distance covered by the echo when it reaches her is 2d or 10 m.
Time taken,
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{10\ m}{343\ m/s}\\\\t=0.029\ s[/tex]
So, it will take 0.029 seconds for the echo from the wall to reach her.
A 50 Ohm resistance causes a current of 5 milliamps to flow through a circuit connected to a battery. What is the power in the circuit?
Answer:0.00125 watts
Explanation:
resistance=50 ohms
Current=5 milliamps
Current=5/1000 milliamps
Current =0.005 amps
power=(current)^2 x (resistance)
Power=(0.005)^2 x 50
Power=0.005 x 0.005 x 50
Power=0.00125 watts
The power in the circuit is 1.25 mW.
What is Ohm's law?
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points, provided the temperature and other physical conditions remain constant.
In other words, the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R):
I = V/R.
This relationship is often written as V = IR or R = V/I. Ohm's law is named after Georg Simon Ohm, a German physicist who first formulated the relationship in the early 19th century.
Here in the Question,
Using Ohm's law, we can find the voltage in the circuit as:
V = IR
V = (5 mA)(50 Ω) = 0.25 V
Using the formula for power, we can find the power in the circuit as:
P = IV
P = (5 mA)(0.25 V) = 0.00125 W or 1.25 mW
Therefore, the power in the circuit is 1.25 mW.
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Which of the following characteristics of Earth's crust is likely to contribute to geological events?
A. can be broken into many plates
B. has has uniform thickness throughout
C. cysts on top of the solid rock of the lower mantle
D. is composed of a single layer that surrounds Earth
Answer:A
Explanation:
The crust Of The earth's has plates boundaries,when the layers that forms to boundaries glide on each other, vibrations occur which are known as earthquakes
Answer:
A) Can be Broken Into Many Plates
A three-phase Y-connected four-pole winding is installed in 24 slots on a stator. There are 40 turns of wire in each slot of the windings. All coils in each phase are connected in series. The flux per pole in the machine is 0.060 Wb, and the speed of rotation of the magnetic field is 1800 r/min. (a)What is the frequency of the voltage produced in this winding?(b)What are the resulting phase and terminal voltages of this stator?
Given Information:
Number of slots = 24
Number of turns = 40
Flux per pole = 0.060 Wb
Speed of rotation of magnetic field = 1800 rev/min
Required Information:
a) Frequency = ?
b) Phase and Terminal voltage = ?
Answer:
a) Frequency = 60 Hz
b) Phase voltage = 2560 V
Terminal voltage = 4434 V
Explanation:
(a)What is the frequency of the voltage produced in this winding?
The relation between frequency of the voltage produced and the speed of rotation of magnetic field is given by
[tex]f = \frac{nP}{120}[/tex]
Where n is the speed of rotation of magnetic field and P is the number of poles in the winding.
[tex]f = \frac{1800\times 4}{120}\\\\f = \frac{7200}{120}\\\\f = 60 \: Hz[/tex]
(b)What are the resulting phase and terminal voltages of this stator?
The phase voltage is given by
[tex]E = \sqrt{2} \cdot \pi\cdot N\cdot \phi\cdot f[/tex]
Where N is the number of turns, Ф is the flux per pole and f is the frequency calculated in part a.
[tex]E = \sqrt{2} \cdot \pi\cdot 40\cdot \ 0.060\cdot 60\\\\E = 639.77\\\\E = 640 \:V\\\[/tex]
There are total 24 slots so each phase has 24/3 = 8 slots
We know that the number of poles are 4 so that means each phase has 4 sets of coils.
So the voltage in each phase is
Vp = 4*640
Vp = 2560 V
Since it is a Y-connected machine, The terminal voltage is will be
[tex]V_T = \sqrt{3} V_p\\\\V_T = \sqrt{3} \cdot2560\\\\V_T = 4434 \: V\\\\[/tex]
A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. The block sticks to the spring and momentarily stops after compressing the spring 14.9 cm. How much work is done (a) by the block on the spring and (b) by the spring on the block? (c) What is the value of h0? (d) If the block were released from height 3h0 above the spring, what would be the maximum compression of the spring?
Answer:
a)5.88J
b)-5.88J
c)0.78m
d)0.24m
Explanation:
a) W by the block on spring is given by
W= [tex]\frac{1}{2}[/tex]kx² = [tex]\frac{1}{2}[/tex](530)(0.149)² = 5.88 J
b) Workdone by the spring = - Workdone by the block = -5.88J
c) Taking x = 0 at the contact point we have U top = U bottom
So, mg[tex]h_o[/tex] = [tex]\frac{1}{2}[/tex]kx² - mgx
And, [tex]h_o[/tex]= ( [tex]\frac{1}{2}[/tex]kx² - mgx )/(mg) = [tex][\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)[/tex]]/(0.645x9.8)
[tex]h_o[/tex]= 0.78m
d) Now, if the initial initial height of block is 3[tex]h_o[/tex]
[tex]h_o[/tex] = 3 x 0.78 = 2.34m
then, [tex]\frac{1}{2}[/tex]kx² - mgx - mg[tex]h_o[/tex] =0
[tex]\frac{1}{2}[/tex](530)x² - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0
265x² - 6.321x - 14.8 = 0
a=265
b=-6.321
c=-14.8
By using quadratic eq. formula, we'll have the roots
x= 0.24 or x=-0.225
Considering only positive root:
x= 0.24m (maximum compression of the spring)
Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of
Answer:
18
Explanation:
got it right on edge
How do most black holes form?
Which of the following actions would decrease the energy stored in a parallel plate capacitor when a constant potential difference is applied across the plates? (Choose from: Increasing the area of the plates; Decreasing the area of the plates; Increasing the separation between the plates; Decreasing the separation between the plates; Inserting a material with a higher dielectric constant between the plates
Answer:
increasing the separation between the plates
Explanation:
The increase in the vacuum/separation between the plates in a parallel plate capacitor connected to a constant potential difference decreases the energy stored in the capacitor. the increase in the separation of the plates of a parallel plate capacitor reduces the capacitance of the capacitor because
Q(charge) = CV V = VOLTAGE , c = capacitance
E = 1/2 eAV^2/ D ( ENERGY STORED )
where D = distance between plates, e = dielectric, A = area of capacitor , V = potential difference
which one of the following statements is true? A.in an elastic collision,only momentum is conserved B. in any collision,both momentum & kinetic energy are conserved C.in an inelastic collision,both momentum & kinetic energy are conserved D.in an elastic collision,only kinetic energy is conserved
Answer:
option C is correct
................
Answer:
C- in an inelastic collision, both momentum & kinetic energy are conserved
Explanation:
Took the test
Many more earthquakes occur along the San Andreas Fault in California than in other parts of the United States. Scientists claim that these earthquakes are caused by activity along a transform plate boundary.
Which evidence would best support this claim?
Subduction causes new crust to form.
Subduction causes old crust to be destroyed.
Plates slip past each other at the boundary.
Plates collide with each other at the boundary.
The correct answer is C. Plates slip past each other at the boundary.
Explanation
A geological fault is a fracture in the Earth's crust, in which the rocky blocks that compose the crust move. Faults often occur in transform plate boundaries in which the two plates displace laterally with respect to the other plate, this means plates slip past each other. Evidence of this type of fault is in the United States, where the cities of Los Angeles and San Francisco in California, United States, located on different plates of the San Andres fault move to different sides due to the transform plate boundary. In this way, the city of San Francisco moves to the East while Los Angeles moves to the West as the plates in which the cities are located slip past each other or move laterally. So, the correct answer is C. Plates slip past each other at the boundary.
Answer:
c
Explanation:
One of your classmates, Kevin, is trying to calculate the acceleration due to gravity at the top of Mt. Everest. Looking at an equation sheet, he sees that the acceleration due to gravity is g = G M r 2. For G, he plugs in the gravitational constant. For M, he plugs in the mass of the Earth. For r, Kevin plugs in the elevation (the height above sea level) of Mt. Everest. Will Kevin arrive at the right answer for g at the top of Mt Everest?
Answer:
no.
Explanation:
No because for M he put the mass of the earth instead of the mass of the object.
Kevin will not arrive at the right answer for g if he calculates the height from sea level, it must be from the center of the earth.
Gravitational acceleration:The force of gravity on an object of mass m is given by:
F = GMm/r²
where G is the gravitational constant
M is the mass of the earth
r is the distance from the center of the earth
This force is equal to the weight of the object given by:
mg = GMm/r²
so,
g = GM/r²
But here r is the distance of the object from the center of the earth not from the sea level.
So, Kevin will not arrive at the right answer for g if he calculates the height from sea level.
Learn more about gravitational acceleration:
https://brainly.com/question/13769294?referrer=searchResults
As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which compresses the gases in their blood. What happens to the volume of gas in their blood as the diver rises quickly to the surface?
Answer:
The volume of gas in an early diving bell full of air at sea level is halved at 10 m according to Boyle’s law
Explanation:
;at 20 m pressure is 300 kPa absolute and the gas is compressed into one third the volume.
HOPE THIS HELPS i did this before
