An object following a straight-line path at constant speed is option C.) has zero acceleration.
Are there any forces acting on a moving item traveling in a straight line at a constant speed?There are no forces operating on a body if it is travelling straight ahead at a steady speed. There are no forces operating on a body if it is travelling straight ahead at a steady speed.
Note that the physics concept of acceleration measures how quickly an object's motion is changing. An object's speed or velocity is what largely defines its motion.
Therefore, An object is considered to be accelerating when its velocity changes over time and as such since acceleration of the object is said to be zero, one can say that the net force acting on it is also zero.
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When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large
amounts of energy, how does it transfer this energy to its surrounding environment?
Answer:
It releases some of the energy into the atmosphere as hot steam.
Explanation:
How to fix this? I need to save both
Answer:
Id say beat it with a hammer and light it on fire. Then if it doesn't work, sacrifice it.
Explanation:
The number of wavelengths that pass a fixed point on a wave is called ______?
Explanation:
it's called a wave frequency
im pretty sure but than again I'm in Middle School but just trust me
Answer:
wave frequency i think. hope its helps
The diagram below shows a 5.00-kilogram block
at rest on a horizontal, frictionless table.
5.00-kg
block
Table
Which of the following is the correct name and strength of the force holding the block up?
The name and strength of the force holding the block up is 50 N upward - Normal force.
The given parameters:
Mass of the block, m = 5 kgThe weight of the block acting downwards due to gravity is calculated as follows;
W = mg
where;
g is acceleration due to gravity = 10 m/s²W = 5 x 10
W = 50 N (downwards)
Since the block is at rest, an a force equal to the weight of the block must be acting upwards. This force is known as normal reaction.
Fₙ = 50 N (upwards)
Thus, the name and strength of the force holding the block up is 50 N upward - Normal force.
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The block will remain on the table because the normal force balances with the weight of the block. The correct answer is 50 N upward normal force
From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be
Weight W = mg
let g = 10 m/[tex]s^{2}[/tex]
W = 5 x 10
W = 50 N
The block will also produce an equal but in opposite direction of a normal force which is equal to the weight of the block. That is,
Normal force N = 50 N
The block will remain on the table because the normal force balances with the weight of the block.
Therefore, the correct name and strength of the force holding the block up is 50 N upward normal force.
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An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
Explanation:
acceleration= change in velocity/time taken
acceleration= 93/49
=2.02
Which kind of chemical reaction is best
represented by the following equation?
BaCl2 + Na2S04 --> 2NaCl + BaSO4
A. Synthesis
B. Single displacement
C. Decomposition
D. Double displacement
Answer:
Synthesis
Explanation:
[tex] \color{lime}{ \sf better \: luck \: on \: your \: exam \: lol}[/tex]
I need ideas of what kind of simple motor i can build and how i can build it. The simple motor MUST spin without using your own force. What materials would i use and how would i create it. what would i create
Answer:
i don't know but my father i think he can't answer this
in a compoumd are atoms physically or chemically combined
Answer:
They are...if I'm correct Chemically combined, sorry if I'm wrong.
Understanding what motivates anyone is not easy because each individual has different
A body is moving along a circular path with variable speed, it has both radial and tangential acceleration.
Select one:
True
False
Answer:
True; ar = v^2 / R Radial acceleration because it moves in a circular path
at = α R = tangential acceleration because its speed changes
a = at + ar total acceleration equals sum of radial and tangential
Please help me.............................
Answer:
[tex]a[/tex]
Explanation:
is a corect anser
Can you solve this question?
Hi there!
In this instance, the object's centripetal force is provided by the horizontal component of the tension, so:
Tsinθ = mv²/r
**We use sine because in this situation, the angle is with the vertical**
We can plug in the known values for tension and theta:
60sin(60) = mv²/r
51.96 = mv²/r
The radius is equivalent to the sine of the string in respect to theta:
sin(60) = O/H = r/L
2sin(60) = 1.732 m
Now, solve for the velocity:
51.96 = mv²/r
51.96r / m = v²
51.96(1.732)/.400 = v²
v² = 225
v = 15 m/s
8 N to the left , and 4 N to the right. Find the net force. Is this balanced?
Explanation:
12N by first law of newton is net force after colloision
4. The winding ridge of a screw
Answer:
Thread.
Explanation:
The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.
A car travels a certain distance from A to B with a speed of 60km/hr and then returns along the same path to the starting point with a speed of 40km/hr. Find the average speed and average velocity.
a) Km/hr
b) m/s
wrong answers will be reported!
Answer:
Explanation:
Speed is total distance traveled over time taken to do so.
If AB is measured in kilometers, time (t) for the whole trip is
t = AB/60 + AB/40
t = 2AB/120 + 3AB/120
t = 5AB/120 hrs
Average speed is distance over time
s = 2AB / (5AB/120)
s = 2(120)/5
s = 48 km/hr
s = 48(1000 m/km / 3600 s/hr) = 13.333333.... 13 m/s
Velocity is displacement over time.
As displacement is zero, velocity is zero
v = 0 km/hr = 0 m/s
Pretty harsh reporting answers just because they are wrong.
I can learn new things but I cannot change how good I am at math. A strongly agree B. agree C disagree D. strongly disagree
Mathematics is a broad subject that anyone who constantly practices by learning from first principle and from example will grow in perfection of the subject as time goes by. Hence, I strongly disagree
During my schools days, I struggled learning mathematics, at the time it was difficult, I began practising and learning from text examples, with time I got a hang of it and my grade and confidence level in the subject increased.
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A volleyball that has an initial momentum of
−
1.0
kg
⋅
m
s
−1.0kg⋅
s
m
minus, 1, point, 0, start text, k, g, end text, dot, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction changes direction after a hand hits it with a force of
150
N
150N150, start text, N, end text for
0.01
seconds
0.01seconds0, point, 01, start text, s, e, c, o, n, d, s, end text.
A hand hits a volleyball. An arrow points to the right, in the directio
Answer:
10-
Step-by-Step Explanation:
A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.
Answer:
1800 J
Explanation:
GPE= mgh
60*3*10
=1800 J
a stone is thrown down off a bridge with a velocity of 22 m/s. what is its velocity after 1.5 seconds has passed?
Answer:
Velocity of the stone after 1.5 seconds has passed = 37 m/s
Explanation:
Initial velocity (u) = 22 m/s
Time (t) = 1.5 sec
Acceleration due to gravity (g) = 10 m/s²
By using kinematics equation:
v = u + gt
v = 22 + 10 × 1.5
v = 22 + 15
v = 37 m/s
Final velocity (v) = 37 m/s
A car move at an initial velocity of 240m and reach at the final velocity of 540m in 8hours. calculate its acceleration.
Answer:
a = 0.01m/s²
Explanation:
V_f = V_0+a*t
V_f = Velocity final
V_0 = Velocity initial
a = acceleration
t = time
a = (V_f-V_0)/t
a = (540m/s-240m/s)/((8hr)*(60min/1hr)*(60s/1min))
a = 0.01m/s²
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
Answer:
don't know ....?
Explanation:
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
A 40-kg worker climbs a ladder upwards for 15m. What work was done during their climb upwards?
Answer:
Explanation:
The work increased the potential energy
W = PE = mgh = 40(9.8)(15) = 5880 J(oules)
______ uses radioactive materials to create contrast in the body and help form images of the structure and function of organs.
Answer:
Nuclear medicine or PET scanning (Positron Emission Tomography)
Explanation:
Not super sure what your question is looking for but I think it can be either. PET is a technology used in the nuclear medicine field, and nuclear medicine is a broad field of using the technology the question described.
a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C)
Answer:
0.02976°C
Explanation:
Heat Supplied = mcø
ø = 500/(4*4200)
ø = 0.02976 °C
A pendulum with a length of 2 m has a period of 2.8 s. What is the period of a pendulum with a length of 8 m
Answer:
P = 2 pi (L / g)^1/2
P2 / P1 = (8 / 2)^1/2 = 2
The period would be twice as long or 5.6 sec.
Suppose a cannon is sitting on top of a 50.0 m high hill and a 5.00 kg cannon ball is fired with a velocity of 30.0 m/s at some unknown angle. What is the velocity of the cannon ball when it strikes the earth?
The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.
The given parameters:
Height of the hill, h = 50 mMass of the cannon, m = 5 kgVelocity of the ball, v = 30 m/sThe final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;
[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]
Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.
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If you are good at activities that require agility, what are you able to do well?
1.maintain your heart rate in the upper ranges
2.quickly change the direction of your movement
3.hold a difficult position for a long period of time
4.strategize about the best way to win a game
Answer:
2.quickly change the direction of your movement
Explanation:
20 . A car of mass 2000 kg is moving with a constant velocity of 10 m/s due east. What is the momentum of the car
Answer:
P=mv
Explanation:
m = 2000kg
v = 10m/s
2000×10=20000
Answer: 2000kgm/s
The momentum will be = 2 * [tex]10^{4}[/tex] kg m/s
What is momentum ?
Momentum is a property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity
momentum = mass * velocity
mass = 2000 kg
velocity = 10 m/s
momentum = 2000 * 10 = 2 * [tex]10^{4}[/tex] kg m/s
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25 gram saturated solution of potassium nitrate at 95 C is cooled down to 55 C then how much gram of crystals of potassium nitrate will be separated if the solubility of potassium nitrate at 95 c is 100 and 55 C is 25 correspondingly
The mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.
The given parameters:
Mass of KNO₃ = 25 gInitial temperature = 95 ⁰CFinal temperature = 55 ⁰CSolubility at 95 ⁰C = 100 MSolubility at 55 ⁰C = 25 MThe mass of KNO₃ at 95 ⁰C is calculated as follows;
[tex]m = \frac{25\ g \times 100\ g}{100\ g} \\\\m = 25 \ g[/tex]
mass of water = 100 g - 25 g = 75 g
The mass of KNO₃ at 55 ⁰C is calculated as follows;
[tex]m = \frac{75 \ g \times 25 \ g}{100 \ g} \\\\m = 18.75 \ g[/tex]
The mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as;
[tex]m= 25\ g \ - \ 18.75 \ g\\\\m = 6.25 \ g[/tex]
Thus, the mass of potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.
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Is this right for the second one
Answer:
Yes.
Explanation:
There is no movement in magnetic, chemical, electrostatic, or nuclear (potential) energy. The other options for that question can't be right. Mechanical energy is a form of kinetic, so B cannot be true. Thermal energy is also kinetic, which makes C and D incorrect as well.
