The two objects pass each other at a height of 41 m above the ground.
What are equations of motion?The equations of motion are the set of equations that describe the relationship between the velocity, acceleration, time, and distance traveled by the object.
The equation used to calculate the distance or height covered by an object is:
S = ut + 1/2 at²
Given, the first object has speed downward, u₁ = -10 m/s
The height of the first object from the ground, S₁ = 60 m
The initial speed of the second object, u₂ = 40 m/s
The distance S for the first object thrown downward:
S = S₁ + u₁t -(1/2)gt²
S = 60 - 10t - (1/2)gt² ...........(1)
The distance S for the second object thrown upward:
S = u₂t -(1/2)gt²
S = 40 t - (1/2)gt² ............(2)
The equation (1) and (2) solve to find the value of 't':
60 - 10t - (1/2)gt² = 40 t - (1/2)gt²
60 = 50 t
t = 6/5 sec
Substitute the value of 't' in equation (2) to find the value of S:
S = (40) (6/5) - (1/2)× (9.81) ×(6/5)²
S = 41 m
Therefore, both objects pass each other at a height of 41 m above the ground.
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How does Newton's second law affect a seat-belted vs. an unseat-belted passenger in an automobile that is involved in a car crash (before the crash, during the crash, and immediately after the crash).
According to Newton's Second Law, acceleration increases as force does. The acceleration decreases with increasing mass.
Newton's Second LawSeat belts are related to Newton's Second Law since it asserts that larger forces result in greater acceleration, whereas bigger masses result in less acceleration. It goes without saying that a seat belt prevents you from accelerating. If you were in a car accident and were hit hard, you would accelerate more quickly, but the seat belt would prevent you from doing so. Have you ever heard the belief that if a tissue box is on a car's back dashboard, it will suddenly stop? The tissue box, which might pierce a person's head, flew from the back dashboard forward and toward the front of the vehicle.To learn more about Newton's Second Law refer :
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13 of the group visited the eiffel tower 16 of the group visited the notra-dame cathederal 7 of the group did not visit any of these places. a person is chosen at random from the group what is the probibility that this person only visited 1 of the 2 placesThere are 30 people in total
Answer:
0.5667
Explanation:
If there are 30 people in total and 7 of them didn't visit any of the places, we have 23 people that visit the Eiffel tower or the Notre-dame cathedral because
30 - 7 = 23
Now, we know that 13 people visited the Eiffel tower and 16 people visited the Notre-dame cathedral. If we add these numbers, we get
13 + 16 = 29
Since 29 is greater than 23 and 29 - 23 = 6, we get that 6 people visited the Eiffel tower and the Notre-dame cathedral.
Then,
13 - 6 = 7
16 - 6 = 10
So, 7 people only visited the Eiffle tower and 10 people only visited the Notre-dame cathedral. It means that 17 people (10 + 7 = 17) from the 30 visited only 1 of the 2 places.
Then, the probability is calculated as
[tex]P=\frac{17}{30}=0.5667[/tex]Therefore, the answer is 0.5667
A 1200-kg car accelerates from rest to 20.5 m/s in 4.50 s. What is the average power delivered by the engine? Use the work-energy theorem to calculate for the work (in terms of kilojoules [kJ]). Show your complete solutions.
Answer:
Explanation:
Given:
m = 1200 kg
V₀ = 0 m/c
V = 20.5 m/s
t = 4.50 s
____________
N - ?
1)
Car acceleration:
a = (V - V₀) / t = (20.5 - 0) / 4.50 ≈ 4.56 m/s²
2)
Vehicle traction force:
F = m·a = 1200·4.56 ≈ 5 470 N
3)
Vehicle speed:
V = V₀ + a·t = 0 + 4.56·4.50 ≈ 20.5 m/s
4)
Average vehicle speed:
N = F·V / 2 = 5 470·20.5 / 2 ≈ 56 000 W
A 100 watt lamp has a resistance of 120 Ω. Find the current in the lamp.Group of answer choices2.15 A1.20 A0.913 A0.833 A
0.913 A
Explanation
the poweris given by
[tex]P=I^2R[/tex]so
Step 1
Let
[tex]\begin{gathered} I=I \\ P=100\text{ watts} \\ \text{resistance}=120\text{ ohm} \end{gathered}[/tex]b) now replace
[tex]\begin{gathered} P=I^2R \\ 100=I^2\cdot120 \\ \text{divide boths sides by 120} \\ \frac{100}{120}=\frac{I^2\cdot120}{120} \\ 0.8333=I^2 \\ \text{square root in both sides} \\ \sqrt{0.8333}=\sqrt{I^2} \\ 0.91287=I \\ \text{rounded} \\ I=0.913\text{ Amperes} \end{gathered}[/tex]therefore, the answeris
0.913 A
I hope this helps you
in which ecosystem would a lion hunt a zebra? freshwater
savanna
desert
Answer:
Savanna
Explanation:
lions are in Africa right? Hot deserty climat so the answer would be Savanna.
Answer:
Savanna
Explanation:
Lions are predators in African savanna. They hunt on large herbivore populations of buffalos, impalas, zebras, and even elephants and giraffes.
Question 2 of 25Which of the following is an SI unit of measurement?OA. LiterOB. YardOC. QuartOD. Gallon
Given:
Some units are given
To find:
The unit of measurement
Explanation:
Liter, Quart, and Gallon are the units of measurement of the volume of a fluid.
The Yard is the unit of the measurement of length.
The SI unit of measurement is Liter.
The dust in a molecular cloud emits at maximum intensity at a wavelength of 101 µm. What is the temperature of the cloud (in K)?
The temperature of the cloud is mathematically given as
T = 28.683k
This is further explained below.
. What is the temperature of the cloud in K?Generally, using wiens law to calculate the temperature the equation is mathematically given as
T = b/landa* m
where b = 2.897 x 10^-3
T = 2.897*10^-3/101 x 10^-6
T = 28.683k
In conclusion, The interstellar medium often consists of dust as its typical minor component. It is usually considered that its dynamic involvement in the contraction of the diffuse gas into molecular clouds plays no significant role at all because of the tiny mass fraction, which is f less than 0.01.
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Electric potential differences are measured in amperes.Question 19 options:TrueFalse
The change in potential energy between two positions when work is done on a charge is called the electric potential difference.
Electric potential difference is measured in joules per coulomb or volt.
Whereas ampere is the unit of current.
Therefore, we can conclude that the given statement is false.
A planet moving in an elliptical orbit moves1) slower when it is closer to the Sun.2) faster when it is farther away from the Sun.3) slower when it is farther away from the Sun.4) faster when it is closer to the Sun.5) both c and d.
4) faster when it is closer to the Sun.
According to Keplers second Law, the closer the planet is to the sun, the stronger the sun's gravitational pull on it, and the faster the planet moves.
What type of evidence do you think would be most difficult to collect? Why?
Answer: I think the evidence that would be most difficult to record and find would be trace evidence.
Explanation: I think trace evidence is the hardest type of evidence to collect. Trace evidence would be most difficult to collect because they are often small evidence like blood or hair.
How does the Coulomb force affect charge interactions?A.Like and opposite charges attract.B.Like charges repel, and opposite charges attract.C.Like and opposite charges repel.D.Like charges attract, and opposite charges repel.
B. Like charges repel, and opposite charges attract.
Given Data:
Let us consider two e
Electrons are transferred from one atom to another Covalent bonds onlylonic bonds onlyBoth ionic and covalent chemical bonds
When electrons are transferred from one atom to another, the atom that gained an electron becomes negatively charged, and the one that has lost an electron becomes positively charged. Atoms like these are called ions.
These 2 ions are held together by an ion bond.
Answer: Ionic Bond
a car is speeding down your street at a constant rate of 45 meters per second what is the net force acting on the car?
There is no acceleration if the velocity remains constant. In other words, the acceleration value is 0.
Why does a car accelerate while moving at constant velocity but not when moving at constant speed?The rate at which an object's velocity (speed and direction) varies is known as acceleration. Therefore, even though an object's speed is constant, it can accelerate if its direction does.
The automobile presses on your back as it accelerates you as it speeds up. Your body has a forward inertia (tendency to continue travelling at the same speed) that causes you to continue moving until the force of your seat belt causes you to slow down at the same pace as the vehicle.
In both the horizontal and vertical axes, the net force acting on the car must be zero. However, a constant force is required to keep it travelling at a constant speed, hence the net force vertically must be zero.
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An airplane flies on a level path. There is a pressure difference of 587 Pa between the lower and upper surfaces of the wings. The area of each wing surface is about 100 m2. The air moves below the wings at a speed of 80.5 m/s. Estimate the weight of the plane.
ANSWER:
117400 N
STEP-BY-STEP EXPLANATION:
Given:
Pressure difference = 587 Pa
Surface area of the wing = 100 m^2
Speed of the sir below the wing = 80.5 m/s
The weight of the plane is the force due to the pressure difference of upper and lower side of both wings. Therefore:
[tex]\begin{gathered} F=\Delta P\cdot2A \\ F=587\cdot2\cdot100 \\ F=117400\text{ N} \end{gathered}[/tex]The weight is a force of 117400 N.
projectile motion lab work i need report
The Projectile Motion Lab is focused on a different type of projectile motion - that of a non-horizontally launched projectile.
What is Projectile Motion LabThe goal of this experiment is to accurately estimate and measure the range and time-of-flight of an angled projectile. Finding the ball's initial speed (muzzle velocity) is necessary before estimating the projectile's range when it is fired off a table at an angle other than horizontal. The projectile motion highlights the important fact that even constant acceleration, which is essentially unidirectional, can produce two-dimensional motion. The primary cause is that the object's initial velocity and force are not in the same direction.To learn more about Projectile Motion Lab refer :
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calculate the pressure exterted by liquid having a density of 13600 kg/m3 and a depth of 12 meter.
The density of the liquid is,
[tex]d=13600kg/m^3[/tex]The depth is,
[tex]h=12\text{ m}[/tex]The pressure at any depth for a liquid is given by,
[tex]P=\text{hdg}[/tex]Substituting the values we get,
[tex]\begin{gathered} P=12\times13600\times9.8 \\ =1.599\times10^6N/m^2 \end{gathered}[/tex]The required pressure at that depth is,
[tex]1.599\times10^6N/m^2[/tex]5. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position xfor two trials in an experiment. W, and W, are the work done on the object by force 1 and force 2, respectively.How do w, and W2 compare, and why?(A) W, > W2, because the maximum value of force 1 is greater than the maximum value of force 2.(B) W, > Wą, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.(C) W,
We are given the graphs of two forces F1 and F2.
Notice that the graph of force 1 is increasing whereas the graph of the force 2 is decreasing.
This means that the slope of force 1 is increasing and the slope of force 2 is decreasing.
So, the work done by force 1 is greater than the work done by force 2.
Therefore, the correct answer is option B.
W1 > W2, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.
A 75W outdoor lamp is connected to 240V source and left to turn on continuously for an average 14 hours per day. Determine:i) the current through the lamp when it is in operation.ii) the cost of operating the light for one year (365 days) if electricity costs in Malaysia is RM0.22 per kWh
We are given that a 75W lamp is connected to a 24V source. To determine the current passing through the lamp we will use the following formula:
[tex]P=VI[/tex]Where:
[tex]\begin{gathered} P=\text{ electric power} \\ V=\text{ voltage} \\ I=\text{ current} \end{gathered}[/tex]Now we plug in the given values:
[tex]75W=(240V)I[/tex]Now we divide both sides by 240 to solve for "I":
[tex]\frac{75W}{240V}=I[/tex]Solving the operation we get:
[tex]0.31A=I[/tex]Therefore, the current passing is 0.31 Ampere.
Now we will calculate the cost of operating the lamp for one year. To do that we will calculate first the number of hours the lamp will be connected for the year. Since the lamp is connected 14 hours a day, this means that in 365 days the number of hours is:
[tex]14\frac{hours}{day}\times365day=5110hours[/tex]Now we determine the kWh. To do that we will multiply the number of hours by the electrical power and we will divide the result by 1000 to convert the W into kW. We get:
[tex]75W\times\frac{1kW}{1000W}\times5110h=383.25kWh[/tex]Now we determine the cost by multiplying the kWh of the lamp by the cost per kWh:
[tex]0.22\frac{RM}{kWh}\times383.25kWh=84.32RM[/tex]Therefore, the cost of operating the lamp for a year is 84.32 RM:
What is the energy of a baby who weighs 20 N sitting in a high chair 1.5 m high?
The gravitational potential energy of a baby with a weight of 20N and 1.5m from the ground is 30 Joules.
What is the energy of the baby?The gravitational potential energy is equal to the weight of a body multiply by its height from ground level.
It is expressed as;
U = mgh
Where m and g are the mass and acceleration due to gravity, which is also called weight, h is the height from the ground level.
Given the data in the question;
Weight of the baby mg = 20NHeight h = 1.5mGravitational potential energy U = ?Plug the given values into the formula and solve for U.
U = mg × h
U = 20N × 1.5
U = 30Nm
U = 30 Joules.
Therefore, the gravitational potential energy is 30 Joules.
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As the swings ride hits top speed, what applies centripetal force to keep the riders traveling in a circle?
a the chains holding the seats on the ride
b the people themselves
c nothing
d the seat
As the swings ride hits top speed, the force that applies to the centripetal force to keep the riders traveling in a circle is option A: the chains holding the seats on the ride.
Which provides the centripetal force in a rotating swing carnival ride?The centripetal force is the resultant force because the swings move in a circle. The centripetal force is seen aa the force that keeps the rider in a circle and the horizontal component of the tension force that is said to be produced by the total of the forces acting along the x-axis.
Therefore, Moving objects are continuously forced to shift their path toward the center of rotation by centripetal force, which stops them from escaping a curve.
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The deflection of a 160-cm-long beam in bending will be _____ times the deflection of an equivalent 120-cm-long beam.1.330.560.751.782.370.42
Given data
*The deflection of the length of the beam in bending is 160 cm
*The equivalent length of the beam is 120 cm
The deflection of a 160-cm-long beam in bending is calculated as
[tex]\begin{gathered} l=\frac{160}{120} \\ =1.33 \end{gathered}[/tex]Hence, the deflection of a 160-cm-long beam in bending will be 1.33 times the deflection of an equivalent 120-cm-long beam
Which of the following most directly limits the number of organisms in a community?
A. Amount of available shelter
B. Wind
C. Hours of daylight/day
D. UV radiation
The following most directly limiting the number of organisms in a community is the amount of available shelter. Option A.
Examples of limiting factors are biological in nature such as competition with other organisms for food mates and resources. Others are abiotic such as space temperature altitude and the amount of sunlight available in the environment. Limiting factors are usually expressed as a lack of a particular resource.
Limiting factors are resources or other factors in the environment that can limit population growth. The limiting factors are the lack of food supplies and the lack of space. Competition for resources such as food and space will stop the rate of increase and the population will plateau. Immigration is the permanent immigration of some individuals coming into an existing population from outside.
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If a piece of paper is cut in half, it will become two pieces of paper that are each half the size of the original piece. If one of the half-pieces is cut in half again, it will become two pieces of paper that are each one quarter the size of the original piece
If the piece of paper is cut in half over and over again, will there ever be a point at which it is no longer paper? Explain your answer.
No, cutting paper is a physical alternative. which means that it's far nonetheless paper irrespective of how many times you narrow it.
Upon infinite cutting, we reach its atom, which further can not be broken but at this point, it will not be called paper any longer.
An atom is a particle of remember that uniquely defines a chemical element. An atom includes a central nucleus that is surrounded by way of one or greater negatively charged electrons. The nucleus is undoubtedly charged and consists of one or greater pretty heavy debris called protons and neutrons.
Atoms encompass 3 essential types of debris, protons, electrons and neutrons. Neutrons and protons have about equal mass and in the assessment of this, the mass of an electron is negligible. A proton includes a fantastic price, a neutron has no price and an electron is negatively charged.
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What would happen to the orbits of the planets if the amount of gravity produced bythe Sun were reduced to almost zero?A. The planets would abandon their orbit and move out into space.B. The planets would start crashing into each other.C. The planets would orbit as usual.
Given:
The amount of gravity produced by the Sun was reduced to almost zero.
To find:
What would happen to the orbits of the planets
Explanation:
The centripetal force for the rotation of every planet is supplied by the gravitational force between the sun and the planet. If the gravitational force by the sum becomes zero, the planets would begin moving away from their usual path into space.
Hence, the planets would abandon their orbit and move out into space.
In a classroom, who is a receiver of messages?
Why can your contact with both very hot and very cold objects cause skin burns?
Contact with very cold objects cause skin burns because skin cells freeze, forming sharp ice crystals that can damage the skin cell structure.
contact with very hot objects cause skin burns because there are tissue damage that results from heat exposure to the skin.
What is the skin?The h skin is the outer covering of the body and is the largest organ of the integumentary system.
The skin also serves as a protective shield against heat, light, injury, and infection.
There are symptoms associated with damage or burn to the skin, which includes;
numbnesspainred, dark, white or grey skintinglingblistersLearn more about the skin at: https://brainly.com/question/306377
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calculate the work done by gravity as a 3.9 kg object is movies from point A to point B , in figure along paths 1,2 and 3
Answer:
-76.44 J
Explanation:
The force due to gravity is conservative, it means that no matter the path, the work done from A to B will be always the same and it depends on the vertical distance between A and B which in this case is 2.0 m.
So, the work done by the gravity is
W = Fdcosθ
Where the force is the weight so, F = mg = (3.9 kg)(9.8 m/s²) = 38.22 N
d is the vertical distance, so , d = 2.0 m
And θ is the angle between the displacement and the weight, so, θ = 180
Then,
W = (38.22N)(2.0 m)cos(180)
W = -76.44 J
Therefore, the work done by gravity along paths 1, 2, and 3 was -76.44 J
A mover pushes a 20 kg crate across a level floor with a force of 200 N, but the crate accelerates at a rate of only 7.5 m/s2 because a friction force opposes the crate's motion. What is the magnitude of this force of friction?Force of FrictionA. 50 NB.100 NC. 15 ND. 25 N
ANSWER
[tex]A\text{.}50N[/tex]EXPLANATION
Parameters given:
Mass of crate, m = 20 kg
Force of push, F = 200 N
Acceleration of crate, a = 7.5 m/s²
To find the force of friction, we have to apply the net force acting on a body. The sum of all forces acting on the crate is equal to the product of its mass and its acceleration.
Therefore, we have:
[tex]F_{\text{net}}=F-F_f[/tex]where Ff = force of friction
Therefore, we have that:
[tex]\begin{gathered} m\cdot a=200-F_f \\ 20\cdot7.5=200-F_f \\ 150=200-F_f \\ \Rightarrow F_f=200-150 \\ F_f=50N \end{gathered}[/tex]That is the force of friction. (Option A)
Converting the number0.700 to Scientific Notation7.00 x 10-17.00 x 101O 7x 1010 7x10-1
Explanation
Step 1
Place a decimal by counting the steps to the left until the coefficient of the number is between 1 and 9.
so
[tex]0.700\rightarrow move\text{ the decimal place 1 position 7.000}[/tex]Step 2
Count the number of steps moved. This will be the power of the base 10.
Moving the decimal point to the right gives a negative exponent, whereas moving the decimal point to the left makes a positive exponent.
1 place to the rigth so the exponent is -1
Step 3
In this case, the coefficient is 7 and the 1 steps are moved
so, Multiply the coeeffcient by 10 exp(1), the (1) we got from the previous step
so, the number is scientific notation is
[tex]\begin{gathered} 0.700\rightarrow7\cdot10^{-1} \\ 7\cdot10^{-1} \end{gathered}[/tex]I hope this helps you
A particle’s position along the x-axis is described byx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -3.15 m/sB = 2.4 m/s21 what is the position of the particle when the velocity is zero.
Given data:
Position of the particle along the x-axis;
[tex]x(t)=At+Bt^2[/tex]Here, A and B are constants with A=-3.15 m/s and B=2.4 m/s².
Therefore,
[tex]x(t)=-3.15t+2.4t^2[/tex]The velocity of the particle is given as,
[tex]v(t)=\frac{dx(t)}{dt}[/tex]Substituting x(t),
[tex]\begin{gathered} v(t)=\frac{d}{dt}(-3.15t+2.4t^2) \\ =\frac{d}{dt}(-3.15t)+\frac{d}{dt}(2.4t^2) \\ =-3.15+2\times2.4t \\ =-3.15+4.8t \end{gathered}[/tex]The time when the velocity will be zero is calculated by substituting v(t)=0 in the above expresion,
[tex]\begin{gathered} 0=-3.15+4.8t \\ 4.8t=3.15 \\ t=\frac{3.15}{4.8} \\ \approx0.66\text{ s} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is calculated by substituting t=0.66 s in the equation for the position of the particle,
[tex]\begin{gathered} x(0.66\text{ s})=-3.15\times0.66+2.4\times(0.66)^2 \\ \approx-1.03\text{ m} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is -1.03 m (1.03 m to the left of its initial position).
