an object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. the maximum displacement from equilibrium is a and the total mechanical energy of the system is e .what is the object's velocity when its potential energy is 23e ?

Answers

Answer 1

The velocity of the object is A√(k/3m), when its potential energy is 2/3E.

For simple harmonic motion,

kinetic energy + potential energy = total mechanical energy

When the displacement is maximum, = A, then kinetic energy will be zero, so total mechanical energy will be only potential energy = E

E = 0.5kA²

The spring constant is k, and the maximum displacement is A.

When potential energy is 2E/3, so kinetic energy would be K = E - 2E/3

K = E/3 = kA²/6

Let the velocity of the object is v.

0.5 mv² = kA²/6

v² = kA²/3m

v = A√(k/3m)

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--The given question is incomplete, the complete question is:

"An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement from equilibrium is A and the total mechanical energy of the system is E.

What is the object's velocity when its potential energy is 2/3E?"--


Related Questions

What is required to bring about a phase change?

Question 2 options:

an increase in energy only


a decrease in energy only


an increase or decrease in pressure


an increase or decrease in energy

Answers

An increase or decrease in energy is required to bring about a phase change. Hence, option (D) is correct.

What is phase change?

Phase change in chemistry is the physical process of changing a medium's state from one to another. The phrase is frequently used to describe transitions between the three fundamental states of matter—solid, liquid, and gas—and, in rare instances, plasma.

The physical characteristics of a phase of a thermodynamic system and the states of matter are constant. Certain properties of a given medium change during a phase transition as a result of a change in the environment, such as temperature or pressure.

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The intensity of the Sun's radiation at the position of the Earth is approximately
1400 W m-2.
Suggest why the average power received per unit area of the Earth is 350 W m-2.

Answers

The intensity of the Sun's radiation at the position of the Earth is approximately 1400 W m-2, which is the total amount of energy that reaches the Earth's surface from the Sun. However, the average power received per unit area of the Earth is only 350 W m-2. This is because the Sun's radiation is not evenly distributed over the Earth's surface.

Some parts of the Earth receive more of the Sun's radiation and some parts receive less. Factors like the Earth's tilt, the atmosphere and clouds, and the Earth's rotation all play a role in determining the amount of solar radiation reaching different areas on the planet. Additionally, the intensity of the Sun's radiation at the position of the Earth is reduced as it passes through the atmosphere, further reducing the amount of energy available for the Earth's surface. Thus, the average power received per unit area of the Earth is only 350 W m-2, significantly lower than the 1400 W m-2 of the Sun's radiation at the position of the Earth.

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if the moon is relatively far from earth, so that the umbra does not reach earth, someone directly behind the umbra will see: group of answer choices a total solar eclipse. a partial solar eclipse. an annular solar eclipse. no eclipse.

Answers

if the moon is relatively far from earth, so that the umbra does not reach earth, someone directly behind the umbra will see an annular solar eclipse.

Due to its opaque nature, the Umbra is the dark portion of the shadow zone where no light from the sun's source can penetrate. When there is an eclipse, these shadows are created.

The moon appears to be much smaller and unable to fully cover the Sun because it is at its farthest distance from Earth during an annular eclipse. As a result, this condition results in the formation of a structure resembling a ring, and the moon's periphery carries light from the sun. The annular lunar eclipse and solar eclipse occur simultaneously.

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A 3 kg ball is moving at 2.0 m/s to the right. It runs into a 1 kg ball moving at 0.5 m/s to the left. The balls bounce off each other. If the 3 kg ball moves at 1 m/s to the left after the collision, how fast must the 1 kg ball be going after the collision?

Answers

Answer:

6 tiuyeiydtidsrjs

Explanation:

Jfxjtzkgsjtsitdtditd I don't know

The time needed for one-half of a given amount of radioactive substance to decay.
Radioactive atoms breakdown from a less stable atom into a more stable atom. Scientists compare the amount of radioactive atoms remaining in a sample with the number of atoms of the new stable element it breaks down into.
For example: the half-life of carbon-14 is 5,730 years. If an initial sample contained 12 grams of C-14, after 5,730 years, how much would be left? (6 grams).
What about after 11,460 years? (3 grams). After 17,190 years? (1.5 grams)
Eventually, the amount becomes too small to measure. Other radioactive isotopes are good for dating things of different ages—really old, to really new.

Answers

After 11,460 years, half of the remaining 6 grams will have decayed, leaving 3 grams, and after 17,190 years, half of the remaining 3 grams will have decayed, leaving 1.5 grams. Over time, the number of radioactive atoms in a sample will decrease as they decay into more stable elements.

What is meant by half life of a substance?

The half-life of a radioactive substance is the amount of time it takes for half of the initial amount of radioactive atoms to decay. Over time, the amount of radioactive atoms in a sample will decrease.

Why is radioactive dating useful?

Radioactive dating is a useful tool for scientists to determine the age of rocks, fossils, and other materials by measuring the amount of radioactive isotopes and their decay products in the sample. This helps them to learn more about the history of the earth.

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what must the separation between charges of 2 and 2 be for the electrostatic potential energy between them to be the same as that between charges of 2 and 3 separated by a distance of 1.00 mm

Answers

The separation between the two charges, each of 2C, should be 0.66 mm.

The electrostatic potential energy U between two point charges q1 and q2 separated by a distance r is given by the equation:

U = k q1 q2 / r

Where k is Coulomb's constant, = 8.99 x 10⁹ Nm²/C²

The electrostatic potential energy between charges of 2C and 2C is the same as that between charges of 2C and 3C separated by a distance of 1.00 mm, we have:

k×2×2/r = k×2×3 / 1.00

r = (2 × 2 × 1) / (2 × 3) = 4/6

r = 0.66 mm

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what is the expected thermal doppler broadening at this temperature

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The thermal Doppler broadening at this temperature is the result of molecules undergoing random thermal motion due to thermal energy is [tex]2.2*10^{-4}Hz.[/tex]

This motion causes a broadening of spectral lines, which can be estimated by the equation:

Δν = (2kT/mc2)1/2 ν

Where k is Boltzmann's constant, T is the temperature in Kelvin, m is the mass of the molecule, and c is the speed of light.

the expected thermal Doppler broadening at this temperature is:

 [tex]\frac{(2 * 1.38 * 10^{-23} *300)\frac{1}{2} }{ (3 * 10^{-26} * 3 * 10^{8})\frac{1}{2}} \\\\=2.2 *10^{-4 }Hz.[/tex]

Therefore[tex]2.2*10^{-4}Hz.[/tex] is the expected thermal Doppler broadening at this temperature.

Doppler broadening in atomic physics is the broadening of spectral lines as a result of the Doppler effect brought on by a variation in the velocities of atoms or molecules. Distinct emission (or absorption) particle velocities produce different Doppler shifts, which together have the effect of widening the emission (or absorption) line.

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what mass of vitamin e contains 0.500 g given that vitamin e is 80.8 carbon by mass

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The mass of vitamin E that contains 0.500 g given that vitamin e is 80.8 carbon by mass  is approximately 12.5 g.

To find the mass of vitamin E that contains 0.500 g, we need to determine the molecular weight of vitamin E.

Since vitamin E is 80.8% carbon by mass, it can be assumed that the molecular weight of vitamin E is largely composed of carbon, with a molecular weight of approximately 12.01 g/mol.

Next, we need to calculate the number of moles of vitamin E contained in 0.500 g:

moles = mass / molar mass

moles = 0.500 g / (12.01 g/mol)

moles = 0.0417 mol

Finally, we can use Avogadro's number to find the number of molecules of vitamin E contained in 0.500 g:

molecules = moles x Avogadro's number

Since the molecular weight of vitamin E is largely composed of carbon, we can estimate the molecular weight of vitamin E to be approximately 300 g/mol.

Therefore, the mass of vitamin E that contains 0.500 g is:

mass = moles x molar mass

mass = 0.0417 mol x (300 g/mol)

mass = 12.5 g

The mass of vitamin E that contains 0.500 g is approximately 12.5 g.

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if you have a choice of using other type of agents, which one would you choose and how would it prevent vacuum from moving after all squares are cleaned? [3]

Answers

I would choose a vacuum agents with sensors to detect when all squares are cleaned would prevent further movement and maintain a clean state.

Vacuum agents with sensors can be used to detect when all squares of a given area have been cleaned. This would prevent the agent from continuing to move, thus maintaining the clean state. The sensors would detect when the area is clean and the agent would stop moving, ensuring that the area remains clean.

This technology could be extremely useful in keeping homes and businesses clean and tidy. Additionally, this technology could be used to automate cleaning tasks, saving time and effort.

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how many two-liter bottles would be needed to contain all the co2 in a car

Answers

8. 2055 is the number of 2-liter bottles required to contain the CO2 produced .

Jaguar 30 Hybrid, Cadillac Sedan In a single year, each car covers 15,000 kilometres.39,049,389 litres.874,706,324 is the result of multiplying 47 mol of CO2 by 22.4 l.874,706,324 millilitres.4,373,531,621 litres divided by two .Octane mass of 12 molar: Calculate litres and CO2 particles at STP using 114 g/mol of octane and 1073160900 g of octane.

9,413,692 mol of octane is equal.

105 mol of octane and 114 g of octane per mole. Seven,5309,536 litres. 1,686,933,625 litres are equal to 84 mol of CO2 multiplied by 22.4 litres.

1,686,933,625 Liters divided by two equal 843,466,812.

5 litres My 2009 Mitsubishi Galant produces 843,466,812.5 2-liter bottles worth of CO2, or 1 for every 8 octane, or 8. 2055.

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Calculate the gel/space ratio and theoretical strength of a sample of concrete made with 500 gram of cement with 0.5 water/cement ratio, on fully hydration and at 60 percent hydration?

Answers

In the case of fully hydrated concrete, the gel/space ratio would be 0.678 which can be calculated by using the formula.

The gel/space ratio of concrete refers to the ratio of the volume of the solid material (the gel) to the volume of the voids (the space) in the material.

Gel-space ratio = (0.657C)/(0.319C+Wo)

where C is the cement weight measured in grams

Wo is volume of water that is to be mixed

C = 600 gm is value given to us

W0 is product of Water-cement ratio and cement weight

= 0.65 * 600 = 390 ml

Therefore,

Gel-space ratio = (0.657 * 600)/(0.319*600+390) = 0.678

Therefore, gel/space ratio will be 0.678

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Answer:

Explanation:

To calculate the gel/space ratio and theoretical strength of a sample of concrete, we need additional information such as the density of the cement, the properties of the aggregate used, and the mix proportions of the concrete (including the amount of aggregate and water).

Without specific information, we cannot accurately calculate the gel/space ratio and theoretical strength. These parameters depend on various factors, including the type and quality of the cement, the aggregate grading, the water-cement ratio, and the curing conditions.

It is important to note that the gel/space ratio represents the ratio of the volume of cementitious gel (hydration product) to the total void space in the concrete mixture. The theoretical strength is influenced by the water-cement ratio, aggregate properties, curing conditions, and other factors.

To provide a meaningful calculation, please provide additional information about the specific mix design, including the properties of the aggregate and the density of the cement, as well as any other relevant details about the concrete mixture.

an 18 cm aluminum rod with an electrical resistivity of 18 ohm-cm and a 3 cm^2 cross-sectional area is cut into thirds (6 cm pieces). what is the electrical resistivity of each piece?

Answers

An 18 cm aluminum rod with an electrical resistivity of 18 ohm-cm and a 3 cm² cross-sectional area is cut into thirds (6 cm pieces). 18 ohm-cm is the electrical resistivity of each piece.

Electrical resistivity: It is the measure of the resistance offered by the material to allow the current to pass through it.

The resistivity only depends on the temperature of the material and it does not depend on the length, cross-sectional area, or density of the material.   

[tex]R_{0} = \frac{\rho l}{A}[/tex]

     [tex]= \frac{18\ cm \times 6\ cm}{18\ \text{ohm-cm}}[/tex]

     = 6 /ohm-cm

Electrical resistivity = R₀ × Cross sectional area

                                = 6 ohm-cm⁻¹ × 3 cm²

                                = 18 ohm-cm

Hence if an 18 cm aluminum rod with an electrical resistivity of 18 ohm-cm and a 3 cm² cross-sectional area is cut into three pieces of 6 cm each the resistivity still remains 18 ohm-cm as it only depends on temperature.

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Complete Question:

An 18 cm aluminum rod with an electrical resistivity of 18 ohm-cm and a 3 cm² cross-sectional area is cut into thirds (6 cm pieces). What is the electrical resistivity of each piece?

(A) 54 ohm-cm

(B) 18 ohm-cm

(C) 3 ohm-cm

(D) 6 ohm-cm

(E) 36 ohm-cm

how far from the lens should an object be placed so that its (virtual) image is at the near-point distance of 25 cm ?

Answers

The near-point distance, or the closest distance that an object can be placed from the eye and still be seen clearly, is 25 cm.

To find the distance from the lens that an object should be placed to form a virtual image at the near-point distance, you can use the formula for the distance of a virtual image formed by a convex lens:

1/f = 1/d o + 1/d i

Where f is the focal length of the lens, d o is the object distance, and d i is the image distance.

Since the image is at the near-point distance, d i = 25 cm. The focal length of a convex lens is positive, so 1/f is positive.

Substituting the values into the formula, we have:

1/f = 1/d o + 1/25

Solving for d o , we get:

d o = 25f / (25 - f)

So, the distance from the lens that an object should be placed to form a virtual image at the near-point distance depends on the focal length of the lens.

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satellite a has mass m. satellites a and b have circular orbits around a planet with distances of r and 2r, respectively. the gravitational force between the planet and satellite a is f. the mass of satellite b is 3m. in terms of f, what is the gravitational force between the planet and satellite b?

Answers

The gravitational force between the planet and satellite b is 3/4 f. The result is obtained by using the concept of Newton's law of universal gravitation.

What is the Newton's law of universal gravitation?

The Newton's law of universal gravitation states that every object with the mass in the universe attracts to each other. The pulling force is called gravitational force. The gravitational force can be expressed as

F = Gm₁m₂/r²

Where

F = gravitational force (N)G = gravitational constant (6.6743 × 10⁻¹¹ m³kg⁻¹s⁻²)m₁ and m₂ = mass of objects (kg)r = distance of mass of objects (m)

We have two satellites a and b.

Mass of satellite a = mMass of satellite b = 3 mDistance between the planet and satellite a = rDistance between the planet and satellite b = 2rGravitational force between the planet and satellite a = f

Find the gravitational force between the planet and satellite b!

Let's say the mass of the planet is M.

We use the formula above to solve the problem.

Fa/Fb = (GM ma/ra²)/(GM mb/rb²)

f/Fb = (m/r²)/(3m/(2r)²)

f/Fb = (m/r²)/(3m/4r²)

f/Fb = 4mr²/3mr²

f/Fb = 4/3

Fb = 3/4 f

Hence, the planet and satellite b has the gravitational force of 3/4 f.

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Annie has a soccer ball and a kickball. She kicks each
ball with the same force. The soccer ball accelerates at 3
m/s-. and the kickball accelerates at 5 m/s2.
Use Newton's laws to describe why the kickball has a
greater acceleration.

Answers

The ball with less mass can acceleration more quickly when both ball have been kicked same force, according to Newton's second law. The soccer with a soccer ball because it accelerates more quickly.

Describe acceleration.

Acceleration seems to be the measure of a change in velocity. Acceleration frequently, though not always, denotes a shift in speed. Even though the direction of it's own motion is fluctuating, an object moving at consistent speed in a circular path is still travelling forward.

Why does time accelerate up?

A net force affects an object's motion; the more accelerated it undergoes, the greater the overall combined force. Positive net forces are required in order to accelerate at around the same proportion as less supermassive black holes.

Acceleration soccer ball,

a₁ = 3 m/s²

Acceleration of kickball,

a₂ = 5 m/s²

F = m a

m₁ a₁ = m₂ a₂

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which process or feature is a carbon dioxide sink? a. air b. ocean c. carbon

Answers

The process or feature is a carbon dioxide sink in (b). ocean is correct option.

As a result of its interactions with the atmosphere, the ocean stores carbon, so the carbon cycle uses the ocean as a carbon sink. This is how carbon atoms are transported from the Earth to the repeatedly from the Earth to the upper atmosphere. Oceans are one type of carbon sink because they act as a storage space for carbon. due to a variety of biological and physical activities that take place in the region. This is why using the ocean as a carbon sink is the best option.

Carbon is a chemical element with the symbol C and atomic number 6 (from the Latin carbo, meaning "coal"). It has a tetravalent atom, which means that four of its electrons can be used to create covalent chemical bonds. It is nonmetallic.

After hydrogen, helium, and oxygen, carbon is the fourth most prevalent element in the universe by mass and the fifteenth most abundant element in the crust of the Earth.

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in parallel rlc circuits, the ? is the same and is ? phase across all branches and is used as the main reference for calculations.

Answers

In parallel RLC circuits, the voltage is the same and is in-phase across all branches and is used as the main reference for calculations.  

In a parallel RLC circuit, the current is determined by the resistance, inductance, and capacitance. The maximum current and the maximum voltage occur simultaneously because the voltage and current through the resistor are in phase. This is so that there is no phase shift between the voltage and the current caused by the resistance.

On the other hand, the voltage is 90 degrees behind the current passing through the capacitor, and the voltage is 90 degrees ahead of the current going through the inductor. As a result, the resistive current and voltage are in phase, which means that when the voltage is at its highest, the resistive current likewise reaches its peak and vice versa.

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A stone is thrown upwards with an initial velocity of 25 m/s at an angle of 30^0 to the ground. c) Using the answer to a), show that the stone will rise to a
height of about 8 m.

Answers

The stone will rise to a height of about 8 m when it  is thrown upwards with an velocity of 25 m/s at an angle of 30° to the ground.

What is projectile?

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center . Such a particle's route is referred to as a projectile.

Acceleration due to gravity = 9.8 m/s²

Initial velocity of the projectile: u = 25 m/s

Angle of projection = 30°

Hence, maximum height obtained by the stone

= (25² × sin²30°)/(2× 9.8) meter

= 7.97 meter

= 8 meter (approx.)

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you are measuring the n-th harmonic of a string, you found that when n=4, the harmonic frequency is 1,362hz. what is the string's fundamental frequency?

Answers

This means that the string is vibrating at a fundamental frequency of 340.5 Hz when it is in its first harmonic state.

The fundamental frequency of a string is the lowest frequency at which it vibrates, and is sometimes referred to as the first harmonic. The higher harmonics are integer multiples of the fundamental frequency, so if you know the frequency of one of the higher harmonics, you can find the fundamental frequency.

In this case, you have measured the fourth harmonic, with a frequency of 1,362 Hz. Therefore, the fundamental frequency can be found by dividing the harmonic frequency by the harmonic number:

fundamental frequency = harmonic frequency / harmonic number

fundamental frequency = 1,362 Hz / 4 = 340.5 Hz

The higher harmonics are multiples of the fundamental frequency, so the fourth harmonic will have a frequency of 4 times the fundamental frequency.

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The following statements are about simple series circuits. Which of the statements IS true?

Series circuits are usually much more complicated to build than simple parallel circuits

Electrons can only flow along one path in a series circuit.

If one component of a series circuit fails, current completely stops flowing.

Answers

If one element of a series circuit fails, current ceases to flow completely is accurate.

What is circuit?

A circuit is a closed conduct for electricity to travel through and is made up of parts like wires, resistors, capacitors, and transistors that regulate the flow of energy.

The components of a series circuit are connected in a line, the current passes through each one in turn. A broken circuit results from one component failing or being open, which stops the electricity from flowing at all. This is because a series circuit only has one path for the current to go, so if one component breaks down, the circuit as a whole is disturbed.

However, the first claim that series circuits are typically far more difficult to construct than straightforward parallel circuits is untrue. Series circuits just need components connected in a straight line, making them comparatively easy to build. It is also true that in a series circuit, electrons can only flow in one direction.

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How can the atomic orbital be described in the quantum mechanical wave model of the orbitals?
A. A collection of balloons
B. A circular ring
C. A probability density

Answers

The atomic orbital can be described as a probability density in the quantum mechanical wave model of the orbitals.

In the quantum mechanical theory, orbitals and energy levels are used to describe electrons. Schrodinger's wave equation serves as its foundation. This intricate model takes the electron's wave-particle duality into account.

According to quantum physics, an atom's orbital is the area with the best possibilities of harbouring an electron. This has a mathematical definition.

Probability density is explored in relation to these orbitals' forms. The square of the wave function serves to define it.

This model deals with the quantum numbers, which can be used to locate the electrons in various energy levels.

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(a) Compute the Maclaurin polynomial M_2(x) for f(x) = cos x. (b) Use the polynomial of part (a) to estimate cos pi/12. (c) Use a calculator to compute the error made using the estimate from part (b) for the value of cos pi/12. Remember that the error is defined to be the absolute value of the difference between the true value and the estimate.

Answers

(a) For the function f(x) = cos x, the Maclaurin polynomial M 2(x) of order 2 is given by:
M 2(x) = 1 - x 2/2! + x 4/4! -... = 1 - x 2/2! + x 4/24!


Defining a Maclaurin polynomial, we can say that it is a polynomial that approximates a function f(x) approximately the point x = 0. It is a polynomial of degree n that agrees with f(x) and its first n derivatives at x = 0. The Maclaurin polynomial of order n for f(x) is a polynomial of degree n. When f(x) is expanded as a power series around x = 0, one can find the Maclaurin polynomial by truncating the series after the nth term.
(b) We may calculate cos pi/12 by substituting pi/12 for x in the Maclaurin polynomial M 2(x) as follows:

Pi (12) M 2(pi/12) = 1 - (pi/12)2/2 + (pi/12)4/24 = 0.974927912
(c) To determine the mistake resulting from the estimation of the value of cos pi/12 from part (b), we deduct the estimation from the actual value of cos pi/12 and then calculate the absolute value:
error is equal to |cos pi/12 - M 2(pi/12)|, which is equal to [0.965925826 - 0.974927912] = [0.009002086].

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3. an iron cannonball is launched with a speed of 70.0 m/s and an angle of 41 degrees above the horizontal, from the top of a 75.0 m high cliff onto a flat valley floor at the base of the cliff. (a) how long does it take the projectile to reach the valley floor?

Answers

To calculate it: Start from the equation for the vertical motion of the projectile: y = vᵧ × t - g × t² / 2, where vᵧ is the initial vertical speed equal to vᵧ = v₀ × sin(θ) = 5 × sin(40°) = 3.21 m/s

How long does it take the projectile to reach the valley floor?

Ttof=2(v0sinθ0)g. T tof = 2 ( v 0 sin θ 0 ) g . This is the time of flight for a projectile both launched and impacting on a flat horizontal surface.

The time taken by the body to reach the maximum height is called the time of ascent. Let v0 = Velocity of projection and θ = Angle of projection. Resolving v0 into two components viz.
To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.The angular momentum of projectile = mu cos Θ × h where the value of h denotes the height. The angle between the velocity and acceleration in the case of angular projection varies from 0 < Θ < 180 degrees.

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is the frequency of this wave higher, lower, or the same after the light enters a piece of glass?

Answers

The frequency of wave remains the same after the light enters a piece of glass.

The quantity of waves which pass a specific place in a predetermined period of time is known as the wave frequency. The hertz (Hz) is the SI unit for wave frequency, and 1 hertz is equivalent to 1 wave crossing a fixed point in 1 second. A wave with a higher frequency has more energy than a wave with a lower frequency of the same amplitude.

Electromagnetic radiation that can be seen by the human eye is known as light or visible light. Typically, visible light is characterised as having wavelengths between 400 and 700 nanometers, or 750 and 420 terahertz, or frequencies between the infrared and the ultraviolet.

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calculate the height (in m) of a cliff if it takes 2.50 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.13 m/s.

Answers

The height of the cliff is approximately 20.32 meters.

The formula used to calculate the height of the cliff is derived from the motion equation of a freely falling object. According to this equation, the vertical position of an object can be described as a function of time, given its initial velocity and acceleration due to gravity.

The equation takes into account that an object falls under the influence of gravity, and therefore its velocity increases over time.

The height of a cliff can be calculated using the formula:

h = v0 × t + 0.5 × g × t^2,

Where t is the time it takes for the rock to contact the ground (2.50 s), g is the acceleration caused by gravity (9.8 m/s2), h is the height of the cliff, v0 is the initial velocity (8.13 m/s), and t is the initial velocity (8.13 m/s).

Plugging in the values, we get:

h = 8.13 × 2.50 + 0.5 × 9.8 × 2.50^2

h = 20.32 m

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an automobile battery is charged with a constant current of 2 a for 5 hours. the terminal voltage of the battery is v = 11 0.5t for t>0, where t is in hours. find the energy delivered to the battery

Answers

The energy delivered to the battery is 55.0 Wh (Watt-hours).

The energy delivered to the battery is equal to the product of the charging current, the time the battery is charged, and the terminal voltage. We can calculate the energy delivered to the battery by integrating the power (current multiplied by voltage) over time.

The current is constant and equal to 2 A, and the voltage is a function of time given by v = 11 - 0.5t for t > 0, where t is in hours. To calculate the energy delivered to the battery, we need to find the integral of the power over the 5 hour charging period:

Energy = ∫ (current * voltage) dt

= ∫ (2 A * (11 - 0.5t)) dt

= 2 A * ∫ (11 - 0.5t) dt

= 2 A * (11t - 0.25t^2)

= 2 A * (11 * 5 - 0.25 * 5^2)

= 2 A * (55 - 12.5)

= 2 A * 42.5

= 85 Wh

So the energy delivered to the battery is 85 Wh, or 85 Watt-hours.

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how many times greater is the sound pressure level of a typical rock concert (110 db) than a normal conversation (50 db)?

Answers

The rock concert is approximately 1,000,000 times greater in terms of sound pressure level.

The decibel (dB) is a unit used to measure sound pressure level (SPL) or loudness. A difference of 10 dB represents a ten-fold increase in sound pressure level, which corresponds to a perceived doubling of loudness.

A typical rock concert has an SPL of 110 dB, which is 60 dB greater than a normal conversation at 50 dB. To find the ratio of the two SPLs, we can use the formula:

Ratio = 10^(difference in dB/10)

Substituting the values, we get:

Ratio = 10^(60/10) = 10^6 = 1,000,000

So, the SPL of a typical rock concert is 1 million times greater than the SPL of a normal conversation.

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a sonar echo returns to a submarine 3.80 s after being emitted. what is the distance to the object creating the echo? (assume that the submarine is in the ocean, not in fresh water.)

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A sonar echo returns to a submarine 3.80 s after being emitted. Assuming the speed of sound in seawater is 1500 m/s, the distance to the object creating the echo is 5,700 meters (3.80 s * 1500 m/s).

This is because sound waves travel at a constant speed underwater, so the time it takes for the echo to return is directly related to the distance between the submarine and the object creating the echo.  The speed of sound in seawater depends on a few factors, including the temperature, pressure, and salinity of the water, but it's generally accepted that it averages around 1500 m/s.

This means that for every second an echo takes to return, it has traveled 1500 meters away from its source. To calculate the distance to the object creating the echo, you simply multiply the time it takes for the echo to return by the speed of sound in seawater.  

In this example, the echo takes 3.80 seconds to return, so the distance to the object creating the echo is 5,700 meters (3.80 s * 1500 m/s). This calculation assumes the submarine is in the ocean and not in freshwater since the speed of sound varies in different mediums. Fresh water is generally warmer than seawater, so the speed of sound in freshwater is usually faster than it is in seawater.

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what is the mass number of a beryllium atom?​

Answers

Answer:

hii:))

Explanation:

the mass number of a beryllium atom is 9.012182 u

hope it will help u :)

it takes 110. s for 1.00 m to decrease to 0.150 m. how much time is required for 4.00 m to decrease to a concentration of 0.350 m?

Answers

It will take 472.35 seconds to decrease from 4.00 m to 0.350 m, if it takes 110 seconds to go from 1.0 m to decrease to 0.150 m.

Total distance decrease, d₁ = 1 - 0.150 = 0.85 m

Total time taken to decrease that distance, T₁ = 110 sec

Time taken to decrease unit distance, t₁ = 110/0.85 = 129.4 sec

Now, decrease in distance, d₂ = (4.0 - 0.350) = 3.65 m

Total time requires to decrease that distance, T₂ = 3.65 × 129.4

T₂ = 472.35 sec.

We can also use interpolation method to calculate this:

T₂ = 110 × (4.0 - 0.35)/(1 - 0.150) = 472.35 sec.

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