The maximum height the object reaches be 5.81 m.
The object's final velocity as it hits the ground be 10.67 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s.
So, maximum height obtained by it be: H = 5 m + (4²/2×9.8) m = 5.81 m.
The object's final velocity as it hits the ground = √(2gH)
= √(2×9.8×5.81) m/s
= 10.67 m/s.
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A 215-g object is attached to a spring that has a force constant of 77.5 N/m. The object is pulled 7.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless table. Calculate the maximum speed of the object.Find the locations of the object when its velocity is one-third of the maximum speed. Treat the equilibrium position as zero, positions to the right as positive, and positions to the left as negative.
(a) The maximum speed of the object is 1.37 m/s.
(b) The locations of the object when its velocity is one-third of the maximum speed is 5.87 cm.
In easy words, speed is the rate at which some thing actions in a specific direction. For instance as the rate of a vehicle journeying north on a highway, or the rate a rocket travels after launching. The scalar method absolutely the cost value of the rate vector is constantly be the rate of the motion.
Velocity is a vector expression of the displacement that an item or particle undergoes with appreciate to time . The preferred unit of speed value (additionally called speed ) is the meter according to second (m/s). Alternatively, the centimeter according to second (cm/s) may be used to specific speed value.
Maximum speed for the object:
[tex]w=\sqrt{ \frac{k}{m}\\\\\\w=\sqrt{ \frac{77.5}{0.215}\\\\\\\\\\\\\w=\sqrt{ 360.46}\\\\\\\\w=18.98[/tex]
Maximum velocity = ωr
v= 18.98*0.0725
v= 1.37.
Maximum velocity = ωr = 1.37.
The speed of the object at a distance x from its mean position is given as:
[tex]v=w\sqrt{a^2- x^{2} } } \\so,\\ v=x\\x=\sqrt[]{8(*7.25} \\x= 5.87[/tex]
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A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with? Visible Infrared Radio UV?
UV (Ultraviolet) is the regions in the electromagnetic type of spectrum that could photon must be associated with it. Option (4)
Ultraviolet radiation will reaches the Earth's floor is made of forms of rays, referred to as UVA and UVB. Ultraviolet radiation additionally comes from solar lamps and tanning beds. It can reason pores and skin damage, untimely aging, melanoma, and different forms of pores and skin cancer.
A photon become absorbed via way of means of a hydrogen atom in its floor state, and the electron become precipitated to the 5th orbit. When the excited atom returned. to its floor state, seen and different quanta had been emitted. Absorbed mild is mild that is not visible at the same time as emitted mild is mild this is visible. Emission is while electrons go back to power levels. Absorption is while electrons advantage power and soar to better power levels.
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Correct Question:
A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with?
1. Visible
2. Infrared
3. Radio
4. UV (Ultraviolet).
A 50 g rock is launched vertically in the air by a slingshot. The slingshot exerts an average force of 53 N on the rock over a distance of 0.750 m.
The work done by the average force is 39.75 J.
What is the work done by the average force?The work done by the average force of the slingshot is calculated by applying the following equation as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the average forced is the displacement of the rockThe given parameters include;
average force, f = 53 Ndisplacement, d = 0.75 mThe work done by the average force is calculated as follows;
W = 53 N x 0.75 m
W = 39.75 J
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A 1800 kg car traveling at a speed of 23 m/s skids to a halt on wet concrete where μk = 0.60. How long are the skid marks?
The length of the skid marks of a car of mass 1800 kg is 21.59 m.
What is length?Length is the distance between two points.
To calculate the length of the skid mark, we use the formula below
Formula:
d = (v²-μv²)/g.................. Equation 1Where:
d = Length of the skid marksv = Velocity of the carμ = Coefficient of kinetic frictiong = Acceleration due to gravityFrom the question,
Given:
v = 23 m/sμ = μk = 0.6g = 9.8 m/s²Substitute these values into equation 1
d = [23²-(0.6×23²)]/9.8d = (529-317.4)/9.8d = 211.6/9.8d = 21.59 mHence, the length of the skid marks is 21.59 m.
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define the principal focus of a concave mirror
The principal focus of a concave mirror is a point on the axis of the mirror at which parallel rays of light are brought to focus after being reflected by the mirror. A concave mirror is a mirror with a curved surface that is shaped like the inside of a bowl, with the center of the curve facing outward. When light rays are reflected by a concave mirror, they are brought to a focus at the principal focus of the mirror. The distance from the center of the mirror to the principal focus is known as the focal length of the mirror. The principal focus of a concave mirror is an important concept in optics and is used in the design and operation of various optical instruments, such as telescopes and cameras.
A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.
Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.
Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)
Ao = 58.2*10^-6m
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)
comparable to case two
Ao = 40.6*10^-6m
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Two ball bearings from different manufacturers are being considered for a certain application Bearing A has a catalog rating of 2.0 kN based on a catalog rating system of 3000 hours at 500 rev/min. Bearing B has a catalog rating of 7.0 kN based on a catalog that rates at 10^{6 cycles. For a given application, determine which bearing can carry the larger load.
CB =7 KN , Since CA > Cg bearing A can carry the larger load.
In order to compare the bearings, both bearings need to be rated in
terms of same catalog rating.
Calculation :
Calculate basic load rating for bearing A for one million
revolutions.
CA = FA[tex](\frac{LA}{LR} )^{1/a}[/tex]
= [tex]2(\frac{3000*500*60}{10^{6} } )^{1/3}[/tex]
= 8.96kN
Bearing B already is rated at one million revolutions, CB =7 KN
Since CA > Cg bearing A can carry the larger load.
Bearings are mechanical elements that limit relative motion to a desired degree and reduce friction between moving parts. The bearing design can, for example, provide free linear motion of the moving part or free rotation about a fixed axis. Alternatively, movement can be prevented by controlling the normal force vector acting on the moving part. Most bearings facilitate the necessary movement by minimizing friction. Bearings are broadly classified according to the type of motion, permissible motion, and the direction of load (force) applied to parts.
Slewing bearings support rotating components such as shafts and axles in mechanical systems, transferring axial and radial loads from the load source to the supporting structure. Plain bearings, the simplest type of bearing, consist of a shaft that rotates in a bore.
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A runner can jog at 5m\s how many laps or a 400m track could she complete in 4 minutrs?
Answer:
3 laps
Explanation:
1 minute = 60 seconds.
4 minutes * 60 seconds/ 1 minute = ==> use seconds-minutes conversion
factor to solve for the number of
seconds in 4 minutes
4 * 60 seconds/1 = ==> cancel the minutes unit
4 * 60 seconds = 240 seconds in 4 minutes
Now solve for the number of meters completed in 240 seconds by using the meters-seconds conversion
240 seconds * 5 meters/1 second=
240 * 5 meters/1= ==> cancel the seconds unit
240*5 meters = 1200 meters
Now solve for the number of laps equivalent to 1200 meters by using the laps-meters conversion
1200 meters * 1 lap/400 meters =
1200 * 1 lap/400 = ==> cancel the meters unit
1200 laps/400 =
1200/400 laps = 3 laps
Light is refracted and spread out by a ____. Question 14 options: concave lens convex mirror concave mirror convex lens
Light is refracted and spread out by a concave lens.
What is refraction?Refraction refers to a phenomenon which describes a change (bend) in the path taken by light when it comes in contact with surfaces between different transparent materials. The refraction of light is inversely proportional to its wavelength.
When parallel rays of light enter into a concave lens, the light waves refract outward (spread out). The light rays refract twice: first when entering the lens and second when leaving the lens. Only the light rays passing through the center of the lens remain straight.
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How do you calculate the rotation speed for a rotating living quarters on a spaceship for 1 g?
To produce the equal of 1 G, you would require a superstructure with a diameter of around 900m and a leisurely 1rpm.
For artificial gravity, how so many rotations per minute are required?Solution:The orbiter must rotate at a rate of 0.04 revolutions per second, or 2.4 revolutions per minute, to imitate Earth's gravity.
How do you determine the g-force in a turn?Just use following formula to translate rotations per minute (RPM) into relative centrifugal (RCF), also known as g force:RCF = (RPM)2 × 1.118 × 10-5 × r.The length of the particle from the rotating center and the rotational speed, measured in RPM, both affect the relative centrifugal force.
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what will the pressure inside the container become if the piston is moved to the 1.20 l mark while the temperature of the gas is kept constant?
The new pressure of the system when we move the piston to the 1.20 L mark is obtained as 0.833 atm.
What is the pressure inside the container?We know that if we want to obtain any of the parameters that has to do with a gas we have to apply any of the gas laws that pattern to the ideal gas and in this case we are looking at an ideal gas.
We are told that;
Initial pressure [tex]P_{1}[/tex]= 1 atm, Initial volume [tex]V_{1}[/tex]= 1 L
Final pressure [tex]P_{2}[/tex] = ? , Final volume [tex]V_{2}[/tex]= 1.20 L
By the use of the formula;
[tex]P_{1}[/tex] [tex]V_{1}[/tex] = [tex]P_{2}[/tex] [tex]V_{2}[/tex]
[tex]P_{2}[/tex] = 1 atm * 1L/1.20 L
= 0.833 atm
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Missing parts;
Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?
A 2.50-kg solid, uniform disk rolls without slipping across a level surface, translating at 3.75 m/s. If the disk’s radius is 0.100 m, find its (a) translational kinetic energy and (b) rotational kinetic energy.
The translational & rotational kinetic energy is :
a) The translational kinetic energy of the disk across the level surface is 17.58J.
b) The rotational kinetic energy of the disk is 8.79J.
How do you find total kinetic energy with translational and rotational?The combined translational and rotational kinetic energies of an item in motion determine its total kinetic energy. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. Total kinetic energy is 12mvCM2 plus 12I2.Ek=12mv2, where m is the mass (mass of the molecule, atom, or ion) and v is the velocity of its Centre of mass, is the energy associated with the movement of a chemical entity.There is just one distinction between rotational and translational kinetic energy: translational energy moves in a straight path, but rotational energy does not. When a bicycle is being ridden down a bike path, its tyre provides an illustration of both kinetic and translational kinetic energy.Learn more about translational & rotational kinetic energy refer to :
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What Are Balanced and Unbalanced Forces?
Balanced forces are equal in size and opposite in direction, whereas unbalanced forces are not equal in magnitude.
When forces are balanced, there's no alter in motion. In one of your circumstances within the last section, you pushed or pulled on an object from opposite directions but with the same force. To have unbalanced forces implies that the force applied in one direction is greater than the force applied within the opposite direction. When unbalanced forces are acting on an object, there's an alteration in speed and/or direction. By applying an unequal force, you'll be able to alter the motion of an object. Unbalanced forces can make an object at rest begin moving, make a moving object halt, or alter the direction and speed of the object.
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Consider a fish swimming forward in the ocean. Which of the following describes the basic action/reaction forces between the fish and the water? Explain the answer.
a. The forces point in the same direction because forces in liquid media behave differently than forces in air.
b. The force of the fish points forward while the force of the water points back.
c. The force of the fish points back while the force of the water points forward.
d. The force of the fish points upward while the force of the water pulls downward.
Answer:
turn off the force
Explanation:
Find the kinetic energy KKK of the block at the moment labeled B.
Express your answer in terms of kkk and AAA.
The kinetic energy KKK of the block at the moment labeled B is 3/8kA^2.
Kinetic energy is the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
Kinetic energy is the energy a body has due to its motion. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.
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The depth of snow after n hours of a snowstorm is
The depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.
A polynomial function exists as a function that examines only non-negative integer powers or only positive integer exponents of a variable in a formula like the quadratic equation, cubic equation, etc.
Given, depth of the snow after n hours of a snowstorm exists represented by the function f(n+1) = f(n) + 0.8 where, f(0) = 2.5
To find, which statement explains the sequence of numbers rendered by the function.
Given function f(n + 1) = f(n) + 0.8 where f(0) = 2.5
Hence, the depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.
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bob's car ran out of gas 3.4 km from the nearest gas station. if it requires a 500 n force to push his car, how much work will bob do to get his car to the gas station? (1.7 MJ or 1.7 10 j)
The mileage of the car is calculated by dividing the number of miles traveled by the amount of gas used. Car's Gas Mileage is 147.0
How do you calculate how far you can go on a tank of gas?Gas Run Out.Turn on your hazard lights and safely pull your car over to the right shoulder.If you have emergency gear, such as a reflective triangle, set it up as needed.Go for a stroll to the closest gas station.Place a roadside assistance call.How to Calculate Your Car's Gas MileageThe outcome is your car's normal miles per gallon, which you can calculate by dividing the distance traveled by the number of petrol tanks you filled up.For instance, your car would average 25 miles per gallon if you traveled 200 miles on 8 gallons of gas.Car's Gas Mileage = 500/3.4
=147.0
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b(4+a) ;where a = 6 and b - 2
= 2(4+6)
= 2×10
= 20
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(figure 1) shows five identical light bulbs a-e connected to a battery. initially, some of the bulbs light up because the two terminals of each bulb are connected to opposite terminals of the battery. if any wire in the circuit is cut, some bulbs may go out. figure1 of 1 part a part complete which bulbs, if any, go out when a single cut is made at location a? check all that apply. a b c d e none previous answers correct part b which bulbs, if any, go out when a single cut is made at location b? check all that apply. which bulbs, if any, go out when a single cut is made at location ?check all that apply. a b c d e none request answer part c which bulbs, if any, go out when a single cut is made at location c? check all that apply.
Figure shows five identical light bulbs a-e connected to a battery.
Part A: The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B: If a cut is made at point b, then no bulb will go out because C is already fused.
Part C: If a cut is made on C, then no bulb will go out because D and E were already fused.
What is the potential difference?When two places in a circuit contain different amounts of charge carriers' energy, this is referred to as a potential difference.
Part A:
Use the concept of potential difference to understand this question.
The bulb will only be lit when there is some potential difference. If the potential difference is zero, then the bulb will not light.
First, redraw the diagram and shown it below:
The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B
The potential at points 3 and 4 is the same because there is no resistance between them and the potential across C is 3 and 4. So, the potential difference is zero across C and it was already fused.
So, if a cut is made at point b, then no bulb will go out because C is already fused.
Part C
The potential at points 2, 4, 5, and 6 is the same. The potential across D and E is 5 and 6. The potential difference is zero across them, so they were already fused.
If a cut is made on C, then no bulb will go out because D and E were already fused.
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The complete question is as follows:
An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns
the electron's velocity will be approximately
At the end of 20 ns, the electron's velocity will be approximately 5.2 × 10⁶ m/s.
What is electric field?The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
Electric charge or magnetic fields with variable amplitudes can produce an electric field. The attraction forces that keep together atomic nuclei and electrons at the atomic scale are brought on by the electric field.
Given that:
the electric field is 1.25 kN/C
So, acceleration of the electron: a = eE/m
= (1.6 × 10⁻¹⁹×1.25×10³)/(9.1×10⁻³¹) m/s²
= 2.6 × 10¹⁴ m/s².
Hence, after the end of 20 ns the electron's velocity will be = at
= 2.6 × 10¹⁴ × 20 × 10⁻⁹ second
= 5.2 × 10⁶ m/s.
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24. Circle each letter beside something that continues to happen as long as the
switch is closed in the primary circuit.
a. A current flows in the secondary circuit.
b. A voltage is applied across the secondary circuit.
c. A magnetic field exists around the primary coil.
d. A magnetic field exists around the secondary coil.
When the switch in the primary circuit is closed, the following continue to happen:
1. the current flows in the secondary circuit
2. voltage is supplied across the secondary circuit and
3. A magnetic field exist around the primary coil.
What happens when the primary circuit is closed?Closing the switch in the primary circuit produces a constant electric current in the conducting wire. This constant electric current produces a magnetic field in the primary coil. The soft-iron ring enhances the strength of the magnetic field, and the ring itself becomes magnetized.
The primary circuit refers to the input section of an isolated power supply, which is connected to the AC mains. This section of the power supply has dangerous voltage levels and not designed to be directly accessed by users.
Therefore when the primary circuit switch is closed, the current flows in the secondary circuit, a voltage is supplied across the secondary circuit and a magnetic field exist around the primary coil.
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Ultrasound in Medicine. A 1.70-MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 72 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Calculate the speed of the fetal heart wall at the instant this measurement is made.
The speed of the fetal heart wall at the instant is 0.031 m/s when 72 beats per second of hart beat was detected.
The Doppler Effect, defined as the change in frequency of a wave in relation to an observer moving relative to the wave source, must be used.
Let
v= magnitude of the heart wall speed
V= speed of sound = 1500
fh= the frequency the heart receives (and reflects) =
fi= original frequency
ff= reflected frequency
fb= frequency for the beats=72
Make use of the Doppler Effect formula.
We have this formula because the heart is a moving observer and the device is a stationary source.
[tex]f_h = [(V+ v)/(v)] fi....(1)[/tex]
We can use this formula if we consider the heart to be a moving source and the device to be a stationary observer.
[tex]f_f = [(V)/(V-v)] fh....(2)[/tex]
The beats' frequency would be the difference between the original and reflected frequencies.
[tex]f_b = f_f -f_i......(3)[/tex]
substituting (1) and (2) into (3),
[tex]f_b=\frac{V}{V-v}\frac{V+v}{V}f_i-f_i\\\\f_b=f_i(\frac{V+v}{V-v}-1)\\\\f_b=f_i\frac{V+v-V+v}{V-v}\\\\f_b=\frac{2v}{V-v}[/tex]
solving for v ,
[tex]v=V\frac{f_b}{2f_i-f_b}=1500\frac{72}{2(1.70*10^6)-72}=0.031 m/s[/tex]
Thus, the speed of fetal heart is 0.031 m/s
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a block of mass 500 g is attached to a horizontal spring, whose force constant is 25.0 n/m . the block is undergoing simple harmonic motion with an amplitude of 6.00 cm . at t
The block is undergoing simple harmonic motion with an amplitude of 6.00 cm . at t = 0.325343 sec.
What is simple harmonic motion ?
Simple harmonic motion is defined as a periodic motion of a point along a straight line, such that its acceleration is always towards a fixed point in that line and is proportional to its distance from that point.
given
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
we know simple harmonic motion equation as
y = A sin (ωt + Φ)
where [tex]$\Phi=\sin ^{-1}(-4 / 6)$[/tex]
so we get
[tex]$\Phi=-0.729727656 \mathrm{rad}$[/tex]
and we know
[tex]$$\begin{aligned}& \omega=\sqrt{\frac{k}{m}} \\& y=A \sin \left(t \sqrt{\frac{k}{m}}-0.729727656\right)\end{aligned}$$[/tex]
now substitute the values we get as
[tex]$$\begin{aligned}& \mathbf{y}=\mathbf{0 . 0 6} \mathbf{m} \\& \left.0.06=0.06 \sin \left(t \sqrt{\left(\frac{25}{0.5}\right.}\right)-0.729727656\right) \\& \left(t \frac{25}{0.5}-0.729727656\right)=\frac{\pi}{2}\end{aligned}$$[/tex]
on solving these equation we get[tex]$t=0.325343 \mathrm{sec}$[/tex]
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what is the maximum speed of a 330 kg car if the spring is compressed the full amount? express your answer with the appropriate units.
A spring that has been fully compressed can move at a maximum speed of 4.993 m/s. According to kinetic theory, molecules in any system are orientated arbitrarily.
Determine the maximum speed?The weight of the spring is 330 kg, According to kinetic theory, molecules in any system are orientated arbitrarily. The radial and angular components of every molecule are unique.According to theory, the root mean square notion is used to compute energy leakage in any system.An illustration of determining energy dissipation parameters in electronics is zero current.When 3RT = mv2 and v2 = 3RT/m T/m = 1, K.E = 3RT/2 and K.V = mv2.A spring that has been fully compressed can move at a maximum speed of 4.993 m/s.To learn more about Maximum speed refer to:
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If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity of object 2 if the two objects collide and bounce off of each other and object 1 has a final velocity of -2 m/s?
The final velocity of object 2 is: 3 m/sec
What is the conservation of mass?According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
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A 2.10 mH toroidal solenoid has an average radius of 5.80 cm and a cross-sectional area of 2.20 cm^2 .A.How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the variation of B with distance from the toroidal axisB.At what rate must the current through it change so that a potential difference of 2.40 V is developed across its ends?
A toroidal solenoid has 1664 turns.
The rate of current is across it is 1142.86 A/s.
What is a solenoid?
A solenoid is a machine made of a casing, a coil of wire, and a moving plunger (armature). A magnetic field that generates around the coil when an electrical current is applied pulls the plunger in. A solenoid, to put it simply, transforms electrical energy into mechanical work.
Given,
Length L = 2[tex]\pi[/tex]r
= 2[tex]\pi[/tex]×0.058 = 0.3644 m
L = [tex]u_{o}[/tex][tex]N^{2}[/tex]A/l
N= [tex]\sqrt{LXl/u_{oA} }[/tex]
N = [tex]\sqrt{2.1X10^{-3}X0.3644/4\pi X10^{-7}X2.2X10^{-4}}[/tex]
N= 1664 turns
B) V = L [tex]\frac{dl}{dt}[/tex]
[tex]\frac{dl}{dt}[/tex] = [tex]\frac{V}{L}[/tex] = [tex]\frac{2.4}{2.1X10^{-3} }[/tex]
[tex]\frac{dl}{dt}[/tex] = 1142.86 A/s
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fgure 24-30 shows a system of three charged particles. if you move th particle of charge from pooint a to point d
A) Moving the three-particle system from A to D has no effect on its electric potential energy.
B) When a particle is transferred from A to D, the total electric force exerted on it produces negative work.
C) When your force is shifted from A to D, it does not produce any work.
D) The values will be zero, negative, and zero if the particle is transferred from B to C.
comprehension of the potential energy idea.The total energy resulting because of all the charges present in the system determines the total potential energy for moving a charge from one location to another. Therefore, total potential energy is positive for two positive charges.
recognizing the idea of completed work.or work done, we just take into account the polarity of charges. The effort completed for equal polarity is found to have a positive regardless of its value. Our force's course determines the job that is accomplished by our force. The work done will be negative for the opposing path and force direction.
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The complete question is -
The figure shows a system of three charged particles. If you move the particle of charge from point A to point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three-particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from B to C?
A planet travels in an elliptical orbit around its star, as shown above. Which arrow best shows the direction of the net force exerted on the planet?
The arrow that best shows the direction of the net force exerted on the planet is arrow B.
What is the net force exerted on a planet orbiting the sun?
The net force exerted on an object travelling round the sun is known as gravitational force.
According Newton's law of universal gravitation, every two objects in the universe attract each other with a force that is directly proportional to the product of masses of the objects and inversely proportional to the square of the distance between them.
Fg = Gm₁m₂/R²
where;
m₁ is the mass of the first object (planet)m₂ is the mass of the second object (planet)R is the distance between the two objectsThus, gravity is the primary force that controls the orbit of the planets around the sun and it is directed towards the sun.
Each planet has its own gravity based on the size of the planet and the speed at which it travels round the sun.
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What is the mass of a ball with a momentum of 18 kg*m/s and a velocity of 9 1 m/s? O 2 m/s O 2 kg O 162 m/s O 162 kg
Answer:
B: 2 kg.
Explanation:
To find the mass of an object given its momentum and velocity, you can use the following formula:
mass = momentum / velocity
In this case, the momentum of the ball is 18 kg*m/s and its velocity is 9 1 m/s, so the mass of the ball is:
mass = 18 kg*m/s / 9 1 m/s
= 2 kg
Therefore, the correct answer is B: 2 kg.
which of the following statements about a mercury barometer are correct? select all that apply. multiple select question. the atmospheric pressure is proportional to the height of the mercury in the tube. the space above the mercury in the inverted tube contains air at atmospheric pressure. the mercury tube is sealed at the top. the barometer contains a tube filled with mercury that is inverted in a container of mercury.
The mercury tube is sealed at the top, and ambient pressure is inversely proportional to the height of the mercury within.
On Mercury, are people still alive?Living on Mercury wouldn't be simple, but it might not be impossible. Remember that you wouldn't last very long without a space suit because there isn't any atmosphere up there. On top of all of this, Mercury experiences one of the Solar System's biggest temperature variations.
What makes Mercury so valuable?Mercury is frequently utilized in numerous devices, including switches and batteries, since it is an effective electrical conductor. In small-scale mining operations, it is utilized to amalgamate gold and silver because it easily joins with other metals.
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