Answer Immediately Please

The correct answer is option D, the two-tailed single-sample t-test.

To determine which test should be used in this scenario, we need to consider the following factors:

Type of data: The data collected from the CT scans are continuous data.

Sample size: The sample size is small (11 in total).

Relationship between samples: The data from Jimmy's hippocampus is independent from that of his family members.

Based on these factors, we can eliminate options C and B, which both involve dependent samples.

Next, we need to determine whether we are comparing Jimmy's hippocampus volume to a known value or to the average volume of his family members. If we were comparing Jimmy's hippocampus to a known value (e.g. the population average), we would use a one-sample t-test (option A). However, since we are comparing Jimmy's hippocampus volume to the average volume of his family members, we need to use a two-sample t-test.

Therefore, the correct answer is option D, the two-tailed single-sample t-test.

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a. The total number of possible committees is [tex]{10\choose 4} \times {14\choose 3} = 1001 \times 364 = 364364[/tex].

b. The number of committees on which the specific man and woman who refuses to serve on the committee are [tex]{8\choose 3} \times {9\choose 4} = 5040[/tex].

c. There are a limited number of combinations in which no two ladies are consecutive that is  [tex]4! \times {4\choose 3} 3! = 288[/tex].

(a) To form a committee of 7 people from 10 men and 9 women, we can choose 4 men out of 10 in [tex]{10\choose 4}[/tex] ways, and choose 3 more people from the remaining 5 men and 9 women in [tex]{14\choose 3}[/tex] ways. Therefore, the total number of possible committees is [tex]{10\choose 4} \times {14\choose 3} = 1001 \times 364 = 364364[/tex].

(b) If 1 woman refuses to be on the committee with a particular man, we can count the number of committees that do not include that particular man and that woman, and subtract that number from the total number of possible committees.

There are [tex]{9\choose 1}[/tex] ways to choose the woman who refuses to be on the committee with the particular man, and [tex]{8\choose 3}[/tex] ways to choose the remaining 3 women. There are [tex]{9\choose 4}[/tex] ways to choose 4 men out of the 9 remaining men.

Therefore, the number of committees that include the particular man and the woman who refuses to be on the committee is [tex]{8\choose 3} \times {9\choose 4} = 5040[/tex]. The total number of possible committees is [tex]{10\choose 4} \times {9\choose 3} = 12600[/tex]. Thus, the number of possible committees that do not include the particular man and the woman who refuses to be on the committee is 12600 - 5040 = 7560.

(c) There are [tex]{10\choose 4}[/tex] ways to choose 4 men out of the 10 men, and {9\choose 3} ways to choose 3 women out of the 9 women. The total number of possible ways to form a committee of 4 men and 3 women is [tex]{10\choose 4} \times {9\choose 3} = 12600[/tex]. To calculate the probability that no women are next to each other in the queue, we can count the number of arrangements where no two women are consecutive and divide it by the total number of possible arrangements. We can arrange the 4 men in a line in 4! ways, and arrange the 3 women in the 4 spaces between the men in [tex]{4\choose 3} 3![/tex] ways. Therefore, the number of arrangements where no two women are consecutive is [tex]4! \times {4\choose 3} 3! = 288[/tex]. The probability that no women are next to each other in the queue is 288/12600 = 0.0229, or about 2.29%.

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The gradient of the path from the trailhead to the mountain peak can be calculated by dividing the change in elevation (in feet) by the length of the trail (in miles). i.e., Gradient = (Change in Elevation) / (Trail Length)

To calculate the elevation change, we can subtract the elevation at the trailhead from the elevation at the mountain peak:

Change in Elevation = Peak Elevation - Trailhead Elevation
Change in Elevation = 9,262 ft - 3,874 ft
Change in Elevation = 5,388 ft

To calculate the length of the trail in miles, we simply divide the length in feet by the number of feet in a mile:

Trail Length = 3 miles

Now we can calculate the gradient:

Gradient = (Change in Elevation) / (Trail Length)
Gradient = 5,388 ft / 3 miles
Gradient = 1,796 ft/mi

Therefore, the gradient of the path from the trailhead to the mountain peak is 1,796 ft/mi. This means that for every mile traveled along the path, there is an increase in elevation of 1,796 feet. The steepness of this path may pose a challenge to hikers, especially those who are not accustomed to hiking at high elevations. Hikers need to be prepared and take appropriate safety precautions when hiking in mountainous terrain.

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Answer:

4 muffins to each friend

Step-by-step explanation:

72-60=3x

12=3x

4=x

The time it takes the ball to strike the ground after it is thrown, found using the kinematic equation, H = -16·t² - 24·t + 200 is approximately 2.86 seconds

We know  that,

A kinematic equation is an equation of the motion of an object moving with a constant acceleration.

The direction in which the ball is thrown = Downwards

Height of the building = 200 foot

Initial velocity of the ball = 24 ft./s

The kinematic equation that indicates the height of the ball after t seconds is, H = -16·t² - 24·t + 200

At ground level, H = 0, therefore;

H = 0 = -16·t² - 24·t + 200

-16·t² - 24·t + 200 = 0

-2·t² - 3·t + 25 = 0

t = (3 ± √((-3)² - 4 × (-2)×25))/(2×(-2))

t = (3 ± √(209))/(-4)

t =  (3 + √(209))/(-4) ≈ -4.36 and t =  (3 - √(209))/(-4)) ≈ 2.86

The time it takes the ball to strike the ground after it is thrown is approximately 2.86 seconds.

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Therefore, we have the recurrence relation: |P(S_k)| = 2 * |P(S_{k-1})|
with the initial condition |P(S_0)| = 1 (since the empty set is the only subset of the empty set).

Sure! To count the number of subsets of a set with k elements, we can use the fact that each element can either be in a subset or not. This gives us two options for each element, so there are 2^k total subsets.

To set up a recurrence relation for this, let S_k denote the set with k elements and P(S_k) denote its power set (the set of all subsets of S_k). Then, we can relate P(S_k) to P(S_{k-1}) by considering whether or not to include the kth element in each subset.

If we don't include the kth element, then each subset of S_{k-1} is also a subset of S_k, so there are |P(S_{k-1})| subsets that don't include the kth element.

If we do include the kth element, then each subset of S_{k-1} can be extended by including the kth element, giving us |P(S_{k-1})| more subsets.

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Answer:

x = 3/2 or 1.5

Step-by-step explanation:

[tex]ax^2+bx+c[/tex]

[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex], where x is the root(s)

[tex]b^2-4ac[/tex]

(a.) For 4x^2 + 16x - 9b, 4 is our a value, 16 is our b value and -9 is our c value:

[tex]16^2-4(4)(-9)\\256+144\\400 > 0[/tex]

(b.) For 2x^2 + 80x + 400, 2 is our a value, 80 is our b value, and 400 is our c value:

[tex]80^2-4(2)(400)\\6400-3200\\3200 > 0[/tex]

(c.) For x^2 - 6x - 9, 1 is our a value, -6 is our b value and -9 is our c value

[tex](-6)^2-4(1)(-9)\\36+36\\72 > 0[/tex]

(d.) For 4x^2 - 12x + 9, 4 is our a value, -12 is our b value, and 9 is our c value:

[tex](-12)^2-4(4)(9)\\144-144\\0=0[/tex]

[tex]x=\frac{-(-12)+/-\sqrt{(-12)^2-4(4)(9)} }{2(4)}\\ \\x=\frac{12+/-\sqrt{0} }{8} \\\\x=12/8=3/2\\or\\x=1.5[/tex]

After 10 rolls, we won 3 times and lost 7 times, and we have $11 left.

The probability distribution for this game is:

Outcome Probability

Lose 2/3

Win $2 1/6

Win $5 1/6

It should be noted that to calculate the anticipated value, multiply the likelihood of each scenario by its payment and add them together:

E(X) = (2/3) * (-1) + (1/6) * 2 + (1/6) * 5 = -2/3 + 1/3 + 5/6 = 1/2

As a result, the expected value of this game is $0.50. This indicates that if you play it frequently, you can expect to win $0.50 each game on average. However, you could win or lose money in any particular game.

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The value of expression is,

⇒ x ÷ 12

We have to given that;

The algebraic expression is,

⇒ x divided by 12

Hence, We can formulate;

The value of correct expression is,

⇒ x ÷ 12

⇒ x / 12

Thus, The value of expression is,

⇒ x ÷ 12

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The value ox in each of the equations given are:

1. x = 3        2. x = 5

For each of the equation given, we can solve to find the value of x by isolating the variable to one side of the equation while applying the properties of equality.

1. 2x + 5 = 11

2x = 11 - 5 [subtraction property of equality]

2x = 6

x = 6/2 [division property]

x = 3

2. 3x - 6 = 9

3x = 9 + 6 [addition property]

3x = 15

3x/3 = 15/3 [division property]

x = 5

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The sale price of the ticket is $57.05

The ticket for the summer concert is $81.50

The ticket will be on sale for 30% off

The sale price can be calculated as follows

81.50 × 30/100

= 81.50 × 0.3

= 24.45

Sale price= 81.50-24.45

= 57.05

Hence the sale price is $57.05

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The probability of getting heads or tails when flipping a coin is 0.5 or 50%. The final probability will give you the chance of getting between 4900 and 5100 heads when flipping a fair coin 10,000 times.

However, the probability of getting a certain number of heads when flipping a coin, a certain number of times can be calculated using probability theory. In this case, the probability of getting between 4900 and 5100 heads when flipping a fair coin 10000 times can be calculated using the binomial distribution formula.

The binomial distribution formula is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where P(X=k) is the probability of getting k heads, n is the number of coin flips, p is the probability of getting a head (0.5 in this case), and (n choose k) is the binomial coefficient.

Using this formula, the probability of getting between 4900 and 5100 heads when flipping a fair coin 10000 times is approximately 0.023 or 2.3%. This means that out of 1000 trials, you can expect to get between 4900 and 5100 heads around 23 times.

In summary, the probability of getting between 4900 and 5100 heads when flipping a fair coin 10000 times is around 2.3%. This probability can be calculated using the binomial distribution formula, which takes into account the number of coin flips and the probability of getting a head.

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The value of x in the equation 2x² + 10x + 12 = 0 is -2 and -3.

An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.

The standard form of a quadratic equation is:

ax² + bx + c = 0

The quadratic formula is given by:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} \\\\Given\ the\ equation\ 2x^2+10x+12=0:\\\\a=2;b=10;c=12\\\\x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} \\\\substituting:\\\\x=\frac{-10\pm\sqrt{10^2-4(2)(12)} }{2(2)} \\\\x=-3; and\ x=-2\\[/tex]

The value of x is -2 and -3.

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Based on the information provided, it appears that there are 4 independent variables included in the regression model.

This is indicated by the "regression" row in the ANOVA table, which shows that there are 4 degrees of freedom (df) for the regression. This is determined by the degrees of freedom (df) for the regression, which is 4. The df for regression represents the number of independent variables in the model.

A statistical method called regression links a dependent variable to one or more independent (explanatory) variables. A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.

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The longer leg of the triangle is 17✓3 yards based on the information of triangle and shorter leg length.

We will use law of sines relating an angle and it's opposite side -

sin shorter angle/shorter side = sin longer angle/longer side

The formula is as per the known fact that wide angle will have wider side opposite to it

Keep the values in formula -

sin 30/17 = sin 60/longer side

Longer side = 17 sin 60/sin 30

Substitute the values of sin 30 and sin 60

Longer side = (17 × ✓3/2)/(1/2)

Longer side = 17✓3 yards.

Thus, the longer leg of the right triangle is 17✓3 yards.

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(a) The growth rate in the percentage of Microsoft Word users is not explicitly provided in the given equation. To find the growth rate, we need the derivative of the function P(t) with respect to time (t).

(b) Graphing the function P(t) requires a graphing utility. The graph will show the percentage of Microsoft Word users over time.

(c) To find the percentage of Microsoft Word users in 1990, substitute t = 1990 into the equation P(t) = 99.774/(1 + 3.014e).

(d) To determine the year when the percentage of Microsoft Word users reached 90%, we need to solve the equation P(t) = 90 for t.

(e) The numerator in the model, 99.774, represents the initial percentage of companies reporting usage of Microsoft Word in 1984. It implies that almost 100% of the surveyed companies were already using Microsoft Word at that time. The model assumes a high initial adoption rate for the software.

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A 95% confidence interval for the true mean hours of exercise per week is (2.08, 8.40) for males and (2.95, 5.49) for females

To find a 95% confidence interval for the true mean hours of exercise per week for each group, we will use the following formula:

[tex]Confidence interval = Sample mean± (t \frac{Sample standard deviation}{\sqrt{n} } )[/tex]
where t is the t-score based on the degrees of freedom and the desired confidence level (95%).

(a) Males:

1. Determine the t-score: For a 95% confidence interval and 6 - 1 = 5 degrees of freedom, the t-score is approximately 2.571.

2. Calculate the margin of error: [tex]2.571 (\frac{3.01}{\sqrt{6} }) = 3.16[/tex]

3. Find the confidence interval: 5.24 ± 3.16 = (2.08, 8.40)

Males: (2.08, 8.40)

(b) Females:

1. Determine the t-score: For a 95% confidence interval and 14 - 1 = 13 degrees of freedom, the t-score is approximately 2.160.

2. Calculate the margin of error: [tex]2.160 (\frac{2.33}{\sqrt{14} })  = 1.27[/tex]

3. Find the confidence interval: 4.22 ± 1.27 = (2.95, 5.49)

Females: (2.95, 5.49)

In conclusion, a 95% confidence interval for the true mean hours of exercise per week is (2.08, 8.40) for males and (2.95, 5.49) for females.

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G and H in terms of x and y is given by H = [tex]B^d[/tex](a, 1) and G = [tex]B^{d_2}(0, 1)[/tex] , the  set S of all possible values of y is x+y≥0 the Cartesian coordinates systems is S = [-7/5, -3/5].

Choosing a point O of the line (the origin), a unit of length, and an orientation for the line are all steps in choosing a Cartesian coordinate system for a one-dimensional space, or for a straight line. The line "is oriented" (or "points") from the negative half towards the positive half when an orientation determines which of the two half-lines given by O is the positive half and which is the negative half. Then, depending on which half-line contains P, the distance between each point P on the line and O can be specified.

a) O = (0, 0) a = (2, -1)∈R²

G = [tex]B^{d_2}(0, 1)[/tex]

D = [tex]\sqrt{x^2+y^2}[/tex] < 1

So this is a circle until center at (0, 0) and no point on

[tex]x^2+y^2[/tex] and every point inside it

H = [tex]B^d[/tex](a, 1) = {v=(x,y)∈R²: d(a, v)≤1}

b) x-2 + y=1 ≤ 1

x-y ≤4

For, x-2≤0, y+1≥0  we get,

2-x+y+1≤1 y-x ≤-2

For, x-2≤0,   y+1≤0,   2-x-y-1≤1

x+y≥0

c) Therefore,

d(a, (13/5, y) ≤ 1

(13/5 -2) + (y +1) ≤ 1

S = [-7/5, -3/5].

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To represent the hourly wage of an employee at the antique store, we can use the following equation:
y = 15 + 0.75x
where y represents the worker's hourly wage, and x represents the number of years the employee has worked at the store. In this equation, 15 is the initial hourly wage, and 0.75 is the annual raise.

The equation that shows how a worker's hourly wage, y, depends on the number of years he or she has worked at the store can be written as:

y = 15 + 0.75x

where x represents the number of years the employee has worked at the antique store.

This equation takes into account the starting wage of $15 per hour and the $0.75 raise that the employee receives each year they work at the store.

So, for example, if an employee has worked at the store for 5 years, their hourly wage would be:

y = 15 + 0.75(5) = 18.75

where y represents the worker's hourly wage, and x represents the number of years the employee has worked at the store.

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T = 29 minutes.

The rate of hits per minute is 12, and the time interval of interest is from 8:14 P.M. to 8:43 P.M., which is 29 minutes. However, we need to adjust for the fact that the Poisson process is occurring within a larger time frame (7:00 P.M. to 9:00 P.M.).

To do this, we can find the proportion of time between 8:14 P.M. and 8:43 P.M. relative to the entire 2-hour period between 7:00 P.M. and 9:00 P.M.:

(29 minutes) / (2 hours × 60 minutes per hour) = 0.2417

So, the expected number of hits within the interval from 8:14 P.M. to 8:43 P.M. is:

lambda = (0.2417)(12 hits per minute) = 2.901

Thus, lambda = 2.901 hits per 29-minute period.

The value of t for this Poisson process is the length of the time interval we are interested in, which is:

t = 29 minutes.

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The team that has best overall record for the season is the falcons because they have a larger mean value of 20.9 points

The mean of the dataset is defined the sum of all values divided by the total number of values. Therefore mean can be expressed as;

mean = sum of items/number of items

The mean value of Eagles = (3 + 24 + 14 + 27 + 10 + 13 + 10 + 21 + 24 + 17 + 27 + 7 + 40 + 37 + 55)/15

= 310/15 = 20.67

The mean value of falcons = (24 + 24  + 10 + 7 + 30 + 28 + 21 + 6 + 17 + 16 + 35 + 30 + 28 + 24 + 14)/15

= 314/15 = 20.93

Therefore since the mean value of falcons is higher than eagles, falcons has the best overall performance.

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Answer:

  A.  Bay Side: mean = 17.1, median = 16; Seaside: mean = 19.5, median = 18

  B.  Bay Side: σ = 8.96, IQR = 12, range = 37; Seaside: σ = 9.03, IQR = 16, range = 31

  C. Bay Side has lower center values and less variation.

Step-by-step explanation:

Given stem and leaf plots for 15 class sizes at each of two schools, you want to know (a) their measures of center, (b) their measures of variation, and (c) which would be preferred for lower class size.

The first attachment shows the statistics for Bay Side School. It tells you the measures of center for Bay Side are ...

The second attachment shows the statistics for Seaside School. The measures of center there are ...

We note the measures of center indicate smaller classes at Bay Side.

For Bay Side School, the measures of variation are ...

For Seaside School, the measures of variation are ...

The measures of variation are generally smaller for Bay Side.

The measures of center and the measures of variation both favor Bay Side School as the school of choice for smaller classes.

__

Additional comment

The arithmetic for these descriptive statistics can be tedious and error-prone. It is convenient to let a calculator do it. The lists of data points are given as L1 and L2 for the calculator screens attached. L1 is Bay Side data, and the result of the 1-Var Stats calculation is shown in the first attachment. Seaside data was put in L2, which was used for the calculations shown in the second attachment.

The Q1 and Q3 data values are the 4th lowest and 4th highest data values in each of the lists. The median is the 8th data value, counted from either end.

<95141404393>

A) The corresponding unit rate for each package is,

For Cannie cakes;

⇒ $1.85

Bark bits;

⇒ $2.25

Woofy Waffles;

⇒ $1.9

B) The best buy by the units rates is, Cannie cakes.

We have to given that;

Jeremiah needed dog food for his new pippy.

Now, We get;

A) The corresponding unit rate for each package is,

For Cannie cakes;

⇒ 74/40

⇒ $1.85

Bark bits;

⇒ 27/12

⇒ $2.25

Woofy Waffles;

⇒ 76 / 40

⇒ $1.9

Hence, We get;

B) The best buy by the units rates is, Cannie cakes.

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The surface area of the composite figure is 1474 square feet.

In the composite figure, there are two shapes rectangular prism and triangular prism.

Surface area of rectangular prism = 2(lb+bh+hl)

= 2(19×9+9×11+11×19)

= 958 square feet

Surface area of triangular prism = (Perimeter of the base × Length of the prism) + (2 × Base Area)

= (S1 +S2 + S3)L + bh

= (13+13+10)×11+10×12

= 516 square feet

Total surface area = 958+516

= 1474 square feet

Therefore, the surface area of the composite figure is 1474 square feet.

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In the given circle, the length of major arc LNM is 29/3(π)

From the question, we are to calculate the length of the major arc in the given diagram

Length of an arc is given by the formula

Length = θ/360° × 2πr

Where θ is the angle subtended by the arc at the center of the circle

r is the radius of the circle

From the given information,

r = 6 cm

θ = 360° - 70°

θ = 290°

Substitute the parameters into the formula

Length = 290/360 × 2×π×6

Length = 29/3(π)

Hence,

Length of arc LNM is 29/3(π)

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Answer: 8 2/5 feet (positive)

Step-by-step explanation:

The evidence supports the claim that the average life of electric light bulbs is greater than 2000 hours.

a. Null Hypothesis: The average life of electric light bulbs is not greater than 2000 hours. Alternative Hypothesis: The average life of electric light bulbs is greater than 2000 hours.

b. The critical value for a one-tailed test at the 2% level of significance with 63 degrees of freedom is 2.33.

c. The relevant test statistic is:
t = (x - μ) / (s / √n)=[tex]= \frac{(2008 - 2000)}{\frac{12.31}{\sqrt{64}}}= 13.03[/tex]
Since the test statistic is greater than the critical value of 2.33, we can reject the null hypothesis and conclude that there is sufficient evidence to support the claim.

d. The p-value is the probability of obtaining a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. Using a t-distribution table with 63 degrees of freedom, the p-value is less than 0.01. Since the p-value is less than the significance level of 0.02, we can reject the null hypothesis.

e. Yes, we reject the null hypothesis.

f. No, we do not reject the claim. The evidence supports the claim that the average life of electric light bulbs is greater than 2000 hours.

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Answer:

The answer to your problem is, 2.04 inches

Step-by-step explanation:

We can assume that the width of the new phone is ‘ x ‘ inches

We know that [tex]\frac{x}{0.84} = \frac{3.4}{1.4}[/tex]

x = [tex]\frac{3.4}{1.4}[/tex] × 0.84

x = 2.04

Thus the answer to your problem is, 2.04 inches

Answer: The correct answer is A

i have no clue if this is correct if it is goodluck lol