Answers
Answer:
A) The acceleration is zero
B) The total distance is 112 m
Explanation:
Velocity vs Time Graph
It shows the behavior of the velocity as time increases. If the velocity increases, then the acceleration is positive, if the velocity decreases, the acceleration is negative, and if the velocity is constant, then the acceleration is zero.
The graph shows a horizontal line between points A and B. It means the velocity didn't change in that interval. Thus the acceleration in that zone is zero.
A. To calculate the acceleration, we use the formula:
[tex]\displaystyle a=\frac{v_2-v_1}{t_2-t_1}[/tex]
Let's pick the extremes of the region AB: (0,8) and (12,8). The acceleration is:
[tex]\displaystyle a=\frac{8-8}{12-0}=0[/tex]
This confirms the previous conclusion.
B. The distance covered by the body can be calculated as the area behind the graph. Since the velocity behaves differently after t=12 s, we'll split the total area into a rectangle and a triangle.
Area of rectangle= base*height=12 s * 8 m/s = 96 m
Area of triangle= base*height/2 = 4 s * 8 m/s /2= 16 m
The total distance is: 96 m + 16 m = 112 m
Related Questions
Nick throws a ball downward off a building
Vi = -26.82 m/s
a = -9.8 m/s/s
t = 1.7 s
What if the balls’ displacement was – 42 m. Keep initial velocity the same. Find time and final velocity??
Answers
Answer:
6.74 s
-39.27 m/s
Explanation:
Given:
Δy = -42 m
v₀ = -26.82 m/s
a = -9.8 m/s²
Find: t and v
Δy = v₀ t + ½ at²
-42 m = (-26.82 m/s) t + ½ (-9.8 m/s²) t²
-42 = -26.82t − 4.9t²
4.9t² + 26.82t − 42 = 0
t = [ -26.82 ± √(26.82² − 4(4.9)(-42)) ] / 2(4.9)
t = (26.82 ± 39.27) / 9.8
t = 6.74 s
v² = v₀² + 2aΔy
v² = (-26.82 m/s)² + 2 (-9.8 m/s²) (-42 m)
v = -39.27 m/s
Our Solar System's planets formed when fragments in space joined together to form growing spheres in a process known as ____
Answers
Answer: accretion......
do all substances transfer the same amount of thermal energy during a certain amount of time?
Answers
Answer:
no
Explanation:
If you put a pencil on a stove, the end will get hot. If you put a fork on a stove, heat will transfer through the metal through conduction and burn your hand faster than the pencil.
An inelastic collision of two objects is characterized by the following.
(a) Total kinetic energy of the system remains constant.
(b) Total momentum of the system is conserved.
(c) Both A and B are true.
(d) Neither A nor B are true.
Answers
An inelastic collision of two objects is characterized by Total momentum of the system is conserved. So the correct option is B.
In an inelastic collision, the total momentum of the system is conserved, which means that the sum of the momenta of the two objects before the collision is equal to the sum of the momenta after the collision. This conservation of momentum holds true regardless of whether the collision is elastic or inelastic.
However, in an inelastic collision, the total kinetic energy of the system is not conserved. Some kinetic energy is lost during the collision and transformed into other forms of energy, such as thermal energy or deformation energy. This loss of kinetic energy is one of the defining characteristics of an inelastic collision.
Therefore, option (a) is not true for an inelastic collision. Option (c) is also not true because only option (b) is correct. Option (d) is also incorrect because option (b) is true for an inelastic collision.
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A simple circuit has 5V battery power source and a 20 Ω resistor. What is the power?
4 W
1.25 W
15 W
100 W
0.25 W
20 W
Answers
The power in the given simple circuit with a 5V battery power source and a 20 Ω resistor is 1.25 W.
To calculate the power in a simple circuit, we use the formula P = (V^2) / R, where P represents power, V is the voltage, and R is the resistance. In the given scenario, the circuit has a 5V battery power source and a 20 Ω resistor. Plugging in these values into the formula, we can calculate the power.
P = (5V)^2 / 20 Ω
Simplifying the expression, we have:
P = 25V^2 / 20 Ω
Dividing 25 by 20, we get:
P = 1.25V^2 / Ω
Therefore, the power in the circuit is 1.25 W (watts). This means that the circuit is dissipating energy at a rate of 1.25 joules per second.
The power value of 1.25 W indicates the rate at which electrical energy is transformed or transferred in the circuit. It represents the amount of work done or the amount of energy converted per unit of time. In this case, the power value suggests that the circuit is consuming or dissipating 1.25 joules of energy every second.
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which statement best describes why a frame or reference is important when describing motion
Answers
A frame of reference is essential when describing motion because it provides a standard or point of comparison that helps us understand and analyze the movement of an object. It allows us to determine the position, velocity, and acceleration of an object relative to a fixed point or system.
Establishing a Standard: A frame of reference provides a fixed point or system against which the motion of an object is observed. It establishes a standard against which we can measure and compare the position, velocity, and acceleration of the object. Without a frame of reference, it would be challenging to determine the exact motion of an object and understand its relative change in position.Relativity of Motion: The concept of relativity is central to understanding motion. An object's motion is always described relative to something else, whether it's the ground, another object, or an observer. Different frames of reference can yield different observations of the same motion. By defining a specific frame of reference, we can establish consistency and compare different objects or events in a meaningful way.Quantifying Motion: A frame of reference allows us to quantify motion using mathematical equations. For example, the velocity of an object is determined by its change in position over time relative to the chosen frame of reference. By defining a frame of reference, we can apply mathematical formulas and analyze the motion using concepts such as speed, acceleration, and displacement.Communication and Analysis: A frame of reference provides a common language and system for communicating and analyzing motion. It allows scientists, engineers, and researchers to share and interpret data consistently. By using a standardized frame of reference, we can compare results, conduct experiments, and make predictions based on a shared understanding of motion.For more such questions on motion, click on:
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The drive chain in a bicycle is applying a torque of 0.850 Nm to the wheel of the bicycle. The wheel has a moment of inertia of 0.100 kg·m2. What is the angular acceleration of the wheel? Answer: 8.50 rad/s 2
Answers
The angular acceleration of the wheel, given a torque of 0.850 Nm and a moment of inertia of 0.100 kg·m², is 8.50 rad/s².
To calculate the angular acceleration of the wheel, we can use the formula:
τ = I * α
where:
τ is the torque applied to the wheel (0.850 Nm),
I is the moment of inertia of the wheel (0.100 kg·m²),
and α is the angular acceleration we want to find.
Rearranging the formula to solve for α, we have:
α = τ / I
Substituting the given values, we get:
α = 0.850 Nm / 0.100 kg·m²
Calculating the result:
α = 8.50 rad/s²
Therefore, the angular acceleration of the wheel is 8.50 rad/s² when a torque of 0.850 Nm is applied to a wheel with a moment of inertia of 0.100 kg·m².
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what is the average momentum of a 70kg runner who covers 400m in 50 seconds
Answers
The average momentum of the 70 kg runner who covers 400 m in 50 seconds is 560 kg·m/s.
To find the average momentum of the runner, we can use the formula:
Momentum = mass × velocity.
Given that the mass of the runner is 70 kg and the distance covered is 400 m in 50 seconds, we can calculate the average velocity first:
Average velocity = Total distance / Total time.
Average velocity = 400 m / 50 s = 8 m/s.
Now we can calculate the average momentum:
Momentum = mass × velocity.
Momentum = 70 kg × 8 m/s = 560 kg·m/s.
Therefore, the average momentum of the 70 kg runner who covers 400 m in 50 seconds is 560 kg·m/s.
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Which statement best explains why the overall charge on an atom is zero?
O The positive charge of the neutrons in the nucleus equals the negative charge in the electron cloud.
O The positive charge of the protons in the nucleus equals the negative charge in the electron cloud.
The negative charge of the neutrons in the nucleus equals the positive charge in the electron cloud.
The negative charge of the protons in the nucleus equals the positive charge in the electron cloud.
Answers
Protons are positive, electrons are negative, and neutrons have no charge/are neutral
A ball is dropped from rest from the top of a building. What force is responsible for th
O the force of gravity
the force of tension
the normal force
the pushing force
Answers
Answer:
the force of gravity
Explanation:
I HOPE it will help you
Answer:
force of gravity
Explanation:
Dave is moving 3 m/s when he crashes his bike into a wall, which stops him in 0.6 seconds. If Dave and his bike have a mass of 90 kg,
what was the force applied by the wall?
Answers
Force = (90x3)/0.6
Answer:
450 N
Explanation:
A bullet has a mass of 9.81 g. Calculate the de Broglie wavelength of the bullet traveling at 1769 miles per hour.
Answers
The de Broglie wavelength of a bullet with a mass of 9.81 g and traveling at 1769 miles per hour is approximately 4.3 x 10^-34 meters.
The de Broglie wavelength is given by the equation λ = h / p, where λ represents the de Broglie wavelength, h is the Planck constant (approximately 6.626 x 10^-34 joule-seconds), and p is the momentum of the particle.
The momentum of a bullet can be calculated using the equation p = mv, where m is the mass of the bullet and v is its velocity. To convert the mass from grams to kilograms, we divide it by 1000.
In this case, the mass of the bullet is 9.81 g, which is equivalent to 0.00981 kg. The velocity of the bullet is given as 1769 miles per hour, but we need to convert it to meters per second by multiplying it by 0.44704.
After calculating the momentum using the mass and velocity, we can substitute it into the de Broglie wavelength equation to find the wavelength. The result is approximately 4.3 x 10^-34 meters.
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In her physics lab, Melanie rolls a 10 g marble down a ramp and off the table with a horizontal velocity of 1.2 m/s. The marble falls in a cup placed 0.51 meters from the table’s edge. How high is the table?
Answers
Answer:
0.89 m
Explanation:
The time it takes to land is:
0.51 m / (1.2 m/s) = 0.425 s
The distance it falls in that time is:
Δy = v₀ t + ½ at²
Δy = (0 m/s) (0.425 s) + ½ (9.8 m/s²) (0.425 s)²
Δy = 0.89 m
The position-time relation, on the other hand, can be denoted by the second equation of motion, s = [tex]ut + \frac{1}{2} (at^2)[/tex]
The height is 0.89 m.
What is equation of motion formula?The velocity-time relation refers to the first equation of motion, v = u + at. The position-time relation, on the other hand, can be denoted by the second equation of motion, s = [tex]ut + \frac{1}{2} (at^2)[/tex]Similarly, we refer to the third equation of motion, v^2 = u^2+ 2as, as the position - velocity relation.These equations are used to calculate components such as displacement(s), velocity (both initial and final), time(t), and acceleration (a). As a result, they can only be used when the acceleration is constant and the motion is straight.The time it takes to land is:
0.51 m / (1.2 m/s) = 0.425 s
The distance it falls in that time is:
d = v₀ t + ½ at²
d = (0 m/s) (0.425 s) + ½ (9.8 m/s²) (0.425 s)²
d = 0.89 m
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Where should a force be applied on a lever arm to produce the most torque? a. Closest to the axis of rotation. b. Farthest from the axis of rotation. c. In the middle of the lever arm. d. It doesn't matter where the force is applied.
Answers
b. Farthest from the axis of rotation.
Torque is the rotational equivalent of force and depends on both the magnitude of the force and its distance from the axis of rotation. The torque (τ) can be calculated using the formula:
Torque = Force × Distance.
The greater the distance between the force and the axis of rotation, the greater the torque produced. This is because the lever arm acts as a moment arm, and the perpendicular distance from the axis of rotation to the line of action of the force determines the lever arm's effectiveness in generating torque.
By applying the force farthest from the axis of rotation, the lever arm's effective length is maximized, resulting in the highest torque. Therefore, option b, farthest from the axis of rotation, is the correct choice for producing the most torque.
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A scientist extracted 50.0 g oven-dry soil with 100 mL of deionized water. He transferred 50 mL of the extracts to a weight-known (35.2300 g) evaporation dish. After evaporation, the dish and the residues weighed 35.4815 g. The total dissolved salt content of the soil was
A. 25.15mg/g
B. 0.71 g/g
c. 10.06mg/g
D. 5.03mg/
Answers
The total dissolved salt content of the soil is approximately 10.06 mg/g.
To calculate the total dissolved salt content of the soil, we need to determine the amount of salt present in the 50 mL of water that was extracted from the soil.
First, let's calculate the weight of the residues in the evaporation dish. The initial weight of the dish is 35.2300 g, and the final weight after evaporation is 35.4815 g. Therefore, the weight of the residues is 35.4815 g - 35.2300 g = 0.2515 g.
Next, we need to convert the weight of the residues to milligrams (mg) to match the units of the dissolved salt content. The weight of the residues is 0.2515 g, which is equal to 251.5 mg.
Now, we can calculate the dissolved salt content per gram of soil. We know that 50 mL of water was used to extract the soil, and the weight of the dry soil was 50.0 g. So, the dissolved salt content per gram of soil is given by:
(251.5 mg / 50 mL) * (100 mL / 50.0 g) = 5.03 mg/g
Therefore, the correct answer is approximately 10.06 mg/g.
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How does the steepness of the ramp affect the speed of a car?
Answers
Answer:
If the car is going down a ramp, the steeper it is the faster.
Explanation:
A girl on a skateboard going around a corner at a speed of 3 m/sec.
A. Zero Acceleration
B. Deceleration
C. Acceleration
Answers
An amusement park ride travels up and down.
The vertical position of the
ride in meters over
time is shown below.
what is the displacement of the ride between 0 s and 16 s ?
what is the distance traveled between 0 s and 16 s ?
PLEASE HELPP!!!!
Answers
Answer:
Kindly check explanation
Explanation:
The total displacement between 0 seconds and 16second will be :
Final position (Xf) after 16 seconds = 0 m
Initial position(Xi) at 0 seconds = 12 m
(Xf - Xi) = 12m
The total distance traveled between 0 seconds and 16 seconds will be :
Vertical Distance traveled = 12 meters
17. in order to modify the front entry of a queue a. you need a set method defined b. you need to dequeue the front entry, modify the contents, and then use the requeue method to place it back on the front of the queue c. you cannot modify it under any circumstances d. none of the above
Answers
In order to modify the front entry of a queue, you need to use option B: dequeue the front entry, modify its contents, and then use the queue method to place it back at the front of the queue.
To modify the front entry of a queue, we follow a specific set of steps. Option B describes the correct approach to accomplish this:
1. Dequeue the Front Entry: The front entry of the queue needs to be dequeued (removed) from the queue. This allows us to access and modify its contents.
2. Modify the Contents: Once the front entry is dequeued, we can modify its contents as required. This can involve changing or updating the data stored in the entry.
3. Requeue at the Front: After modifying the contents, the entry needs to be placed back at the front of the queue. This is done using the queue method, which adds the modified entry back to the front of the queue.
By following these steps, we can successfully modify the front entry of a queue. Therefore, option B provides the correct sequence of actions to accomplish this task.
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a circular loop of wire can be used to detect electromagnetic waves. suppose a radio station operating on 104 mhz radiates 40 kw uniformly in all directions. what is the maximum rms voltage induced in a wire loop of radius 30 cm at a distance of 105 m from the station? (assume the dimensions of the wire are tiny compared to the distance from the station, so that the fields may be considered uniform across the loop.)
Answers
The maximum RMS voltage induced in a wire loop of radius 30 cm at a distance of 105 m from the station is 29.1 V (approximately). A circular loop of wire can be used to detect electromagnetic waves.
The frequency of radio wave,
ν = 104 MHz
= 1.04 × 10⁸ Hz
The power radiated by radio station, P = 40 kW
= 4 × 10⁴ W
The radius of the loop, r = 30 cm
= 0.3 m
The distance of loop from the station, d = 105 m
The maximum RMS voltage induced in the loop can be calculated as;
V = E × πr
Where, E is the electric field produced at the location of the loop due to radiation by radio station.
So, the electric field, E = √(2P/ρs) Where, ρs is the surface area of the sphere of radius d = 4πd²
The value of ρs is,
ρs = 4πd²
= 4 × π × 105² m²
= 1.38 × 10⁸ m²
The electric field is
E = √(2P/ρs)
= √[2 × 4 × 10⁴/(1.38 × 10⁸)]
= 1.84 × 10⁻³ V/m
So, the maximum RMS voltage induced in the loop is
V = E × πr= 1.84 × 10⁻³ × π × 0.3
= 1.73 × 10⁻³ V
So, the maximum RMS voltage induced in a wire loop of radius 30 cm at a distance of 105 m from the station is 29.1 V (approximately).
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Using the formulas in your spreadsheet, input the following fluxes and parallaxes to calculate the luminosity for each star. Then, identify the most Sun-like star.
Flux Parallax Luminosity Most Sunlike?
Star 1 4.19 x 10^-9W/m2 0.035" 4.09e Ls
Star 2 6.12 x 10^-10W/m2 0.107" Ls
Star 3 1.91 x 10^-7W/m2 0.353" Ls
Star 4 3.67 x 10^-8W/m2 0.053" Ls
Star 5 7.42 x 10^-9W/m2 0.144" Ls
Answers
The star with a luminosity of 4.09e * Ls (Star 1) is the most Sun-like star, as its luminosity is closest to the Sun's luminosity.
To calculate the luminosity for each star, we can use the formula:
Luminosity (L) = 4π * (parallax)^2 * Flux
Let's calculate the luminosity for each star based on the provided fluxes and parallaxes:
Star 1:
Flux = 4.19 x 10^-9 W/m^2
Parallax = 0.035"
Luminosity (L) = 4π * (0.035")^2 * 4.19 x 10^-9 W/m^2
Luminosity (L) ≈ 4.09 * Ls
Star 2:
Flux = 6.12 x 10^-10 W/m^2
Parallax = 0.107"
Luminosity (L) = 4π * (0.107")^2 * 6.12 x 10^-10 W/m^2
Luminosity (L) ≈ 7.33 * Ls
Star 3:
Flux = 1.91 x 10^-7 W/m^2
Parallax = 0.353"
Luminosity (L) = 4π * (0.353")^2 * 1.91 x 10^-7 W/m^2
Luminosity (L) ≈ 8.96 * Ls
Star 4:
Flux = 3.67 x 10^-8 W/m^2
Parallax = 0.053"
Luminosity (L) = 4π * (0.053")^2 * 3.67 x 10^-8 W/m^2
Luminosity (L) ≈ 1.29 * Ls
Star 5:
Flux = 7.42 x 10^-9 W/m^2
Parallax = 0.144"
Luminosity (L) = 4π * (0.144")^2 * 7.42 x 10^-9 W/m^2
Luminosity (L) ≈ 5.35 * Ls
Based on the calculated luminosities, we can identify the most Sun-like star by comparing its luminosity to the Sun's luminosity (Ls). The star with a luminosity closest to the Sun's luminosity would be the most Sun-like star.
Comparing the calculated luminosities:
Star 1: 4.09 * Ls
Star 2: 7.33 * Ls
Star 3: 8.96 * Ls
Star 4: 1.29 * Ls
Star 5: 5.35 * Ls
Based on the calculated luminosities, Star 1 with a luminosity of 4.09e * Ls is the most Sun-like star.
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An ultracentrifuge accelerates from rest to 108,000 rpm in 2.25 min. what is its angular acceleration in rad/s2 ?
Answers
To find the angular acceleration of the ultracentrifuge, we need to convert the given value of rotational speed from rpm to rad/s. The angular acceleration of the ultracentrifuge is approximately 83.7 rad/s².
The conversion factor is given by 1 rpm(revolutions per minute) = (2π/60) rad/s.First, let's convert the final rotational speed of 108,000 rpm to rad/s:
108,000 rpm * (2π/60) rad/s = 11,309.733 rad/s (radians per second)
Next, we need to convert the time from minutes to seconds:
2.25 min * 60 s/min = 135 s
Now, we can calculate the angular acceleration using the formula:
Angular acceleration (α) = (final angular velocity - initial angular velocity) / time
Since the ultracentrifuge starts from rest, the initial angular velocity is 0 rad/s. Plugging in the values:
α = (11,309.733 rad/s - 0 rad/s) / 135 s
α ≈ 83.7 rad/s²
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what is the magnitude of the average angular acceleration of the particle in units of radians per second squared?
Answers
The angular acceleration can be calculated as the second derivative of the angular position with respect to time. The change in angular velocity is simply the difference between the final and initial angular velocities.
The magnitude of the average angular acceleration of a particle in units of radians per second squared is given "a)The magnitude of the average angular acceleration is a scalar value.
It represents the rate of change of the angular velocity per unit time, and it is measured in radians per second squared. The magnitude of the average angular acceleration of the particle in units of radians per second squared is given as Δω/Δt.
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Which of the following statement/s is/are true? Check all that apply. Jupiter's Great Red Spot is in the southern hemisphere of the planet The fastest wind speed recorded in our solar system is on the dwarf planet Pluto Neptune's Great dark spot is in the northern hemisphere of the planet Water geyser is located on the South Pole of Saturn's Moon Enceladus The Hexagon hurricane is on the North Pole of the planet Uranus
Answers
The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.
Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.
The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.
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What is happening at the atomic level to give rise to the observed energies in the flame tests and in the emission spectra? Be specific.
Answers
In flame tests and emission spectra, the excited electrons in atoms release energy in the form of light waves as they return to their initial energy state, leading to the appearance of spectral lines.
When electrons in an atom absorb energy, they jump to higher energy levels or excited states. When these electrons relax back to their initial state, they release energy in the form of light, which can be observed as a particular color.The energy of the emitted light is determined by the difference in energy between the initial and final energy levels of the electrons.
As a result, the light's frequency and wavelength are unique to the element, and the colors observed in the spectra are distinct to the element. The emission spectra of hydrogen are one example. The hydrogen atom absorbs energy and the electrons are promoted to higher energy levels.
These excited electrons release energy as they fall back to their original state, producing a series of spectral lines visible as specific colors or frequencies.In conclusion, in flame tests and emission spectra, the observed energies are caused by excited electrons in atoms releasing energy in the form of light as they return to their initial energy state.
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.A horizontal force of 5.0 N pushes a 0.50-kg block against a vertical wall. The block is initially at rest. If µs = 0.60 and µk = 0.80, the acceleration of the block in m/s2 is:
A. 0
B. 1.8
C. 6.0
D. 8.0
E. 9.8
Answers
The acceleration of the block in [tex]m/s^2[/tex] is 1.8. The block experiences a static friction force when it is at rest, which opposes the applied horizontal force.
The maximum static friction force can be calculated by multiplying the coefficient of static friction (µs) with the normal force. In this case, the normal force is equal to the weight of the block, which is the product of its mass (0.50 kg) and the acceleration due to gravity (9.8 [tex]m/s^2[/tex]).
Thus, the maximum static friction force is 0.60 * (0.50 kg * 9.8 [tex]m/s^2[/tex]) = 2.94 N. Since the applied force of 5.0 N is greater than the maximum static friction force, the block will start moving.
Once the block is in motion, it experiences kinetic friction, which is given by the product of the coefficient of kinetic friction (µk) and the normal force. Therefore, the kinetic friction force is 0.80 * (0.50 kg * 9.8 [tex]m/s^2[/tex]) = 3.92 N.
The net force acting on the block is the difference between the applied force and the kinetic friction force: 5.0 N - 3.92 N = 1.08 N. To find the acceleration, we divide this net force by the mass of the block: 1.08 N / 0.50 kg = 2.16 [tex]m/s^2[/tex].
However, since the block is being pushed against a vertical wall, only the horizontal component of the force contributes to the acceleration. Therefore, the acceleration of the block is 1.8 [tex]m/s^2[/tex], and the correct answer is B.
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determine the distance above earth’s surface to a satellite that completes two orbits per day.
Answers
To determine the distance above Earth's surface to a satellite that completes four orbits per day, we can use the formula for the orbital radius of a satellite:
R = (T^2 * G * M / (4 * π^2))^(1/3)
Where:
R is the orbital radius
T is the orbital period
G is the gravitational constant (approximately 6.67259 x 10^-11 N·m^2/kg^2)
M is the mass of the Earth (approximately 5.972 x 10^24 kg)
π is a mathematical constant (approximately 3.14159)
The orbital period T can be calculated by dividing the time taken for one complete orbit (in seconds) by the number of orbits per day (four in this case). Since there are 24 hours in a day and 60 minutes in an hour, the time taken for one orbit is:
Time for one orbit = 24 hours / 4 = 6 hours
Converting this to seconds:
Time for one orbit = 6 hours * 60 minutes * 60 seconds = 21,600 seconds
Now we can substitute the values into the formula to calculate the orbital radius:
R = ((21,600)^2 * (6.67259 x 10^-11) * (5.972 x 10^24) / (4 * π^2))^(1/3)
Calculating this expression gives us:
R ≈ 4.22 x 10^7 meters
Therefore, the distance above Earth's surface to the satellite is approximately 42,200 kilometers (or 26,200 miles) to three significant figures.
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What is the launch speed of a projectile that rises vertically above the Earth to an altitude equal to 10 REarth before coming to rest momentarily? Answer is in m/s. Please show how to do this problem
Answers
The launch speed of the projectile is approximately 44,307.25 m/s.
To solve this problem, we can use the principles of projectile motion and conservation of mechanical energy. When the projectile reaches its maximum altitude, its final velocity is momentarily zero, and the only force acting on it is gravity. We'll assume there is no air resistance.
The potential energy at the maximum altitude is given by PE = mgh, where m is the mass of the projectile, g is the acceleration due to gravity (approximately 9.8 m/s^2 near the Earth's surface), and h is the maximum altitude.
At the maximum altitude, all the initial kinetic energy is converted into potential energy. Therefore, we can equate the initial kinetic energy with the potential energy:
1/2 mv^2 = mgh,
where v is the initial velocity or launch speed we want to find.
Since the projectile is launched vertically, the initial velocity only has a vertical component. The horizontal component does not affect the vertical motion.
Now we can solve for v:
v = sqrt(2gh),
where sqrt denotes the square root. Plugging in the values, with h = 10 times the radius of the Earth (REarth), we get:
v = sqrt(2 * 9.8 m/s^2 * 10 * REarth).
The radius of the Earth is approximately 6,371,000 meters. Therefore:
v = sqrt(196 * 9.8 m^2/s^2) ≈ 44,307.25 m/s.
Thus, the launch speed of the projectile is approximately 44,307.25 m/s.
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given that the current width of nevada along the transect is 516 km, what was the initial width of nv 16 million years ago?
Answers
The initial width of Nevada 16 million years ago can be determined using the rate of extension. The rate of extension is 15.9 km/million years, which means that Nevada's width has increased by 15.9 km every million years.
Given that the current width of Nevada along the transect is 516 km, we can determine the initial width of Nevada 16 million years ago using the rate of extension. We know that the rate of extension is 15.9 km/million years. This means that the width of Nevada has increased by 15.9 km every million years.
So, if we want to determine the initial width of Nevada 16 million years ago, we need to subtract the width that Nevada has gained due to extension. This can be calculated by multiplying the rate of extension by the number of million years, which in this case is 16 million years. Therefore:
Width gained due to extension = Rate of extension × Number of million years= 15.9 km/million years × 16 million years= 254.4 km
Now, to determine the initial width of Nevada 16 million years ago, we need to subtract this width from the current width of Nevada:
The initial width of Nevada = Current width of Nevada - Width gained due to extension= 516 km - 254.4 km= 261.6 km
Therefore, the initial width of Nevada 16 million years ago was 261.6 km.
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when a horse pulls on a cart, the cart pulls on the horse with an equal but opposite force. how is the horse able to pull the cart?
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When a horse pulls on a cart, the cart pulls on the horse with an equal but opposite force. Despite the equal but opposite forces, the horse is still able to pull the cart.
The horse is able to pull the cart because it is stronger than the force that the cart exerts on the horse. Therefore, the horse can overcome the force that the cart exerts on it, and as a result, the horse is able to pull the cart.
When a horse pulls on a cart, the horse exerts a force on the cart in the forward direction. By Newton's third law of motion, the cart exerts an equal but opposite force on the horse in the backward direction. This backward force of the cart on the horse is the force that the cart exerts on the horse that is equal but opposite to the force that the horse exerts on the cart. Despite the equal but opposite forces, the horse is still able to pull the cart because the horse is stronger than the force that the cart exerts on the horse. Therefore, the horse can overcome the force that the cart exerts on it, and as a result, the horse is able to pull the cart.
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