Answer part ABCDE


B options is Z , T , chi-square, F

Answer Part ABCDE B Options Is Z , T , Chi-square, F

Answers

Answer 1
The null and alternative hypotheses would be given by H₀: μ = 7 and H₀: μ ≠ 7.The test statistic is equal to 1.198. The p-value is equal to 0.1262.In conclusion, yes the mean discharge differs from 7 fluid ounces.

What is a null hypothesis?

A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.

How to calculate value of the test statistic?

The test statistic can be calculated by using this formula:

[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]

Where:

x is the sample mean.u is the mean.is the standard deviation.n is the number of hours.

For this clinical trial (study), we should use a t-test and the null and alternative hypotheses would be given by:

H₀: μ = 7

H₀: μ ≠ 7

Next, we would calculate the t-test as follows:

[tex]t=\frac{7.08\;-\;7}{\frac{0.25}{\sqrt{14} } }\\\\t=\frac{0.08}{\frac{0.25}{3.7417 } }[/tex]

t = 0.08/0.0668

t = 1.198.

For the p-value, we have:

P-value = P(t < 1.198)

P-value = 0.1262.

Therefore, the p-value (0.1262) is greater than α = 0.10. Based on this, we should fail to reject the null hypothesis.

In conclusion, yes the mean discharge differs from 7 fluid ounces.

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Related Questions

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Service Department Charges and Activity Bases

Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.

CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:

• The sector has 5,200 employees, of whom 25% are office employees.

• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.

• One hundred percent of the employees with a computer also have an e-mail account.

• The average number of help desk calls for October was 1.5 calls per individual with a computer.

• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.

a. Determine the service charge rate for the four CCS service categories for October.

CCS Service Category Service Charge Rate
Help desk $fill in the blank 1

Per call
Network center $fill in the blank 3

Per device monitored
Electronic mail $fill in the blank 5

Per user or e-mail account
Smartphone support $fill in the blank 7

Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.

October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a. Divide the budgeted cost by the budgeted activity base quantity for each category.

b. Determine the Help desk charge by multiplying the rate from (a) by the number of employees times the percentage of office employees times the percentage with a computer times the number of calls. Follow a similar process for each of the other three categories.

Learning Objective 3.

Answers

The service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

Service charge rate

a. Service charge rate

Service charge rate=Budgeted cost/ Budgeted activity base quantity

Help desks:

Service charge rate=$160,000/3,200 calls

Service charge rate=$50 per call

Network center:

Service charge rate=$735,000/9,800 devices

Service charge rate=$75 per device monitored

Electronic mail:

Service charge rate=$100,000/10,000 accounts

Service charge rate=$10 per user or per e-mail account

Local voice support:

Service charge rate=$124,600/8,900 phone extensions

Service charge rate=$14 per phone extension

b.  Help desk charge

Help desk charge =(Number of employees times × Percentage of office employees× Percentage with a computer ×Number of calls)× Service charge rate

Help desk charge:

(5,200 employee×25%×96%×1.5)× $50 per call

=$93,600

Network center charge:

[(5,200 employee×25%×96%)+ 600]× $75 per device

=$138,600

Electronic mail:

(5,200 employee×25%×96%×100)×$10 per user or per e-mail account

=$12,480

Local voice support:

(5,200 employee×25%)× $14 per phone extension

=$18,200

Therefore the service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

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Captain's Autos sells 22 used cars on
Monday, and 18 cars on Tuesday. This was
25% of the number of sales for the week.
How many cars did they sell altogether that
week

Answers

Answer:

160

Step-by-step explanation:

22 + 18 = 25 percent

40 = 25 percent

100 / 25 = 4

40 x 4 = 160.

(05.03 LC)

The equation shows the relationship between x and y:

y = −4x + 9

What is the slope of the equation? (5 points)

Group of answer choices

−9

−4

4

9

Answers

Answer is -4 9 would be the y-intercept

A study was conducted to determine whether there were significant differences between medical students admitted through special programs (such as retention incentive and guaranteed placement programs) and medical students admitted through the regular admissions criteria. It was found that the graduation rate was 92.5% for the medical students admitted through special programs. Round your answers to 4 decimal places. If 12 of the students from the special programs are randomly selected, find the probability that at least 11 of them graduated.

Answers

The probability that at least 11 of them graduated is 0.7739 if graduation rate is 92.5%.

Given that graduation rate is 95.2%.

We are required to find the probability that out of 12 selected candidates atleast 11 should be graduated.

Probability is basically the chance of happening an event among all the events possible. It cannot be negative. It lies between 0 and 1.

Probability=Number of items/ Total items.

Probability that atleast 11 will be graduated out of 12 selected candidates is as under:

It will be a binomial distribution.

So,

P(X>=11)=[tex]12C_{11}(0.925)^{11} (0.075)^{1} +12C_{12}(0.925)^{12} (0.075)^{0}[/tex]

=12*0.4241*0.075+1*0.3923

=0.3816+0.3923

=0.7739

Hence the probability that at least 11 of them graduated is 0.7739 if graduation rate is 92.5%.

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during one semester, the time elaine spent doing homework or participating in extracurricular activities was 20 percent less than the time she spent attending class. if she spend a total of 981 hours attending class, doing homework, or participating in extracurricular activities, how many hours did she spend attending class?

Answers

Answer:

963 hours

Step-by-step explanation:

I subtracted 20 from the 981

The correct answer for the hours elaine spend attending classes is  [tex]817.5[/tex]  hours.

Given,

The time spent doing homework was 20% less than the time she spent attending class.

Assume the time Elaine spent attending class is "x" hours.

So, the time spent on these activities is 0.2 * x hours.

Now, the total time  spent attending class, doing homework, or  in extracurricular activities is 981 hours.

The equation representing the total time is:

[tex]x + 0.2x = 981[/tex]

solve for "x":

[tex]1.2x = 981[/tex]

[tex]x= \dfrac{981}{1.2}[/tex]

[tex]x= 817.5[/tex]

Elaine spent approximately [tex]817.5[/tex] hours attending class.

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Find the area of the trapezoid

Answers

Answer:

[tex]52\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\frac{1}{2}(11+15)(4\sqrt{3})=52\sqrt{3}[/tex]

Interpreting Slope in a Line of Best Fit
Use the scatterplot and equation to answer the question.
AY
180+
160+
140+
120+
100+
80+
Number of Customers Served
2
60+
40+ y= 17.9x+6.67
20+
3 4 5 6 7 8 9
Number of Hours
x
The data reflects the number of hours an employee
spends working a checkout line (x), paired with the
number of customers served (y). How can the slope of
the line be interpreted?
With each additional hour, between 6 and 7
customers are served.
With each additional hour, nearly 18 customers are
served.
Each additional customer requires 17.9 minutes to
check out.
O Each additional customer requires 6.67 minutes to
check out.
Done

Answers

Answer:

b

Step-by-step explanation:

b

Your Turn
Solve the equation by using Properties of Equality.
3. 5x − 10 = 20
4.
+9=21

Answers

Answer: for number 3, x= 6

Step-by-step explanation:

A golf lesson lasts from 10:00 a.m. - 11:15 a.m. and includes a 15 minute break with equal lengths of time before and after the break. At what time should the break start?

Answers

The time at which the break started is 10 : 30 am.

What time did the break start?

The first step is to convert the time between  10:00 a.m. - 11:15 a.m. to minutes.

The time  between  10:00 a.m. - 11:15 a.m. is 1 hour 15 minutes

In order to convert hours to minutes, multiply hour by 60

1 x 60 = 60 minutes

60 minutes +  15 minutes =  75 minutes

The second step is to subtract the time from the break from the duration of the golf lesson

75 minutes -  15 minutes = 60 minutes

The third step is to divide 60 minutes into equal halves by dividing 60 by 2

60 / 2 = 30 minutes

The last step is to add 30 minutes to the time the lesson started : 10 : 00 am + 30 minutes = 10 : 30 am

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Merger_Model_Evaluation_-_Question.xlsx 19 The implied enterprise value of Snap Inc., calculated using the assumptions and acquisition premium provided, is: $92,165 $30,498 $92,661
$91,669​

Answers

The implied enterprise value of Snap Inc., calculated using the assumptions and acquisition premium provided, is $91,669

How to calculate the value?

Share Price, P = 44.29

Premium on the acquisition, p = 20%

Therefore, effective share price for acquisition, P* = P x (1 + p) = 44.29 x (1 + 20%) = $ 53.15

Number of shares outstanding, N = 1,734 MM

Equity value, E = P* x N = 53 x 1,734

= $92,158.63 MM

Net Debt, D = - 496

Hence, the implied enterprise value:

= Equity value + net debt

= 92,158.63 + (- 496)

= $$91,669

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How many three-digit positive integers have three different digits and at least one prime digit?

Answers

The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.

What are prime numbers?

The definition of a prime number is a natural number larger than 1 that is not the sum of two lesser natural numbers. A composite number is any natural number that is more than 1 but not a prime.

The only two components in prime numbers are 1 and the number itself.

Any whole number greater than one is a prime number.

It has exactly two factors—1 and the actual number.

There is just one 2-digit even prime number.

Every pair of prime numbers is always a co-prime.

The product of prime numbers can be used to represent any number.

Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960

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The double number line shows that the distance from the start of a hiking trail to a cave
entrance is 700 m.

Answers

Answer:

100, 25, 50

Step-by-step explanation:

[tex]700: \frac{700}{700} \times 100=100 \\ \\ 175: \frac{175}{700} \times 100=25 \\ \\ 350: \frac{350}{700} \times 100=50[/tex]

Enter the correct answer in the box. If z>0, what is the quotient of 20 square root of z^6 • square root of 16x^7 in simplest radical form? If necessary, rationalize the denominator

Answers

The correct answer which represents the quotient of 20√z⁶ ÷ √16z⁷ in simplest radical form is; (5√z)/z.

What is the quotient of the expression in its simplest radical form?

The quotient given can be evaluated by means of the laws of indices as follows;

20√z⁶ ÷ √16z⁷

= 20√z⁶ ÷ 4√z⁷

= 5 √(z⁶/z⁷)

= 5 √z^(-1)

= 5 × z^(-1/2)

= 5/√z

Hence, by rationalisation; we have;

= (5√z)/z.

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A coin is flipped, and a number cube is rolled. What is the probability of getting heads on the coin and a number less than 3 on the number cube?

a.one eighth
b. one sixth
c. one fourth
d. one half

Answers

Answer:  one sixth (choice B)

=============================================================

Explanation:

The probability of getting heads is 1/2 because there's one side we want out of two sides total

The probability of getting less than 3 is 2/6 = 1/3 since we have two sides we want (rolling a "1" or a "2") out of six sides total.

Multiply the two mentioned fractions: 1/2 times 1/3 = 1/6

1/6 can be written as "one sixth", but I prefer the first format better since it's shorter.

---------------

If you are a visual learner, you can make a table with 2 rows and 6 columns, or vice versa (6 rows and 2 columns). The order doesn't matter.

The two rows represent the events Heads or Tails. The 6 columns show the different outcomes on the number cube. We have 6*2 = 12 different outcomes of rolling a die and flipping a coin.

Of those 12 outcomes, shade in 2 boxes to represent getting heads and either a "1" or "2". Refer to the diagram below.

We have 2 shaded rectangles out of 12 total to get 2/12 = 1/6

The visual representation of a table like this may help show why we multiplied the fractions 1/2 and 1/3 to get the answer. Hint: think of area = length*width.

The probability of getting heads on the coin and a number less than 3 on the number cube is 1/6, Option A is correct.

What is Probability?

It is a branch of mathematics that deals with the occurrence of a random event.

Given,

A coin is flipped, and a number cube is rolled.

We need to find the probability of getting heads on the coin and a number less than 3 on the number cube.

The probability of getting heads when flipping a coin is 1/2

The probability of getting less than 3 is 2/6 = 1/3 since we have two sides

Now  the probability of getting heads on the coin and a number less than 3 on the number cube

The product of 1/2 and 1/3

1/2×1/3

1/6

Hence, the probability of getting heads on the coin and a number less than 3 on the number cube is 1/6, Option A is correct.

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A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum height of 16 mm halfway across a horizontal distance of 80 mm.

Part A: Write the equation of the parabola in standard form that models the spider's jump. Show your work. (4 points)

Part B: Identify the focus, directrix, and axis of symmetry of the parabola. (6 points)

Answers

Answer:

[tex]\textsf{A)} \quad (x-40)^2=-100(y-16)[/tex]

B)  Focus = (40, -9)

    Directrix:  y = 41

    Axis of symmetry:  x = 40

Step-by-step explanation:

The x-intercepts of a parabola are the points at which the curve intercepts the x-axis (when y = 0).

The x-coordinate of the vertex of a parabola is halfway between the x-intercepts.

The y-coordinate of the vertex if the minimum or maximum height of the parabola.

Part A

A jumping spider's movement is modeled by a parabola.

Define the variables:

x = horizontal distance of the spidery = height of the spider

From the information given:

x-intercepts = (0, 0) and (80, 0)vertex = (40, 16)

Standard form of a parabola with a vertical axis of symmetry:

[tex](x-h)^2=4p(y-k) \quad \textsf{where}\:p\neq 0[/tex]

Vertex:  (h, k)Focus:  (h, k+p)Directrix:  y = (k-p)Axis of symmetry:  x = h

If p > 0, the parabola opens upwards, and if p < 0, the parabola opens downwards.

Substitute the vertex (40, 16) and one of the x-intercept points (0, 0) into the formula and solve for p:

[tex]\implies (0-40)^2=4p(0-16)[/tex]

[tex]\implies 1600=-64p[/tex]

[tex]\implies p=-25[/tex]

Substitute the vertex and the found value of p into the formula:

[tex]\implies (x-40)^2=4(-25)(y-16)[/tex]

[tex]\implies (x-40)^2=-100(y-16)[/tex]

Part B

Given:

Vertex = (40, 16)  ⇒  h = 40 and k = 16p = -25

Substitute the given values into the formulas for focus, directrix and axis of symmetry:

Focus

⇒ (h, k+p)

⇒ (40, 16 + (-25)))

⇒ (40, -9)

Directrix

⇒ y = (k-p)

⇒ y = (16 - (-25))

⇒ y = 41

Axis of symmetry

⇒ x = h  

⇒ x = 40

Because of stormy weather a pilot flying at 35,000 ft descends 8,000 ft.
What is his new altitude

Answers

Answer:

35,000 - 8000=27,000 altitude

Which pair of functions are inverses of each other? O A. F(a) = I - 9 and g(2) = 2*9 O B. Ax) = 5x - 11 and g(a) = 2+11 O C. F(a) = V2m and g(2) = (3) ° O D. f(a) = ; + 8 and g(x) = 6x - 8 SUBMIT

Answers

The pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

How to determine the function and the inverse?

The complete question is added as an attachment

Function 1

f(x) = 5x - 11 and g(x) = (x + 11)/5

Represent 5x - 11 with y in f(x) = 5x - 11

y = 5x - 11

Swap x and y

x = 5y - 11

Add 11 to both sides

x + 11 = 5y

Divide by 5

y = (x + 11)/5

Express as a function

g(x) = (x + 11)/5

From the question, we have:

f(x) = 5x - 11 and g(x) = (x + 11)/5

This means that the function g(x) is an inverse of the function f(x)

Hence, the pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

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what is the period for tangent functions? (Answer in radians)

Answers

Answer: 2 radians

Step-by-step explanation: You welcome

A newspaper article reported that people spend a mean of 7 hours per day watching TV, with a standard deviation of 1.8 hours. A psychologist would like to conduct interviews with the 5% of the population who spend the most time watching TV. She assumes that the daily time people spend watching TV is normally distributed. At least how many hours of daily TV watching are necessary for a person to be eligible for the interview? Carry your intermediate

Answers

According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

According to the statement

we have given that the mean of 7 hours per day watching TV, and a standard deviation of 1.8 hours.

And we have to find that the At least how many hours of daily TV watching are necessary for a person to be eligible for the interview.

So, For this purpose,

The confidence interval is is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level.

Let us Assume x is the amount of hours that 5% of the persons exceeds.

Then P(z<(x-7)/1.8) = 0.95

From a standard normal table, we know that:

(x-7)/1.8 = 1.6449

x-7 = 2.9607

x = 9.9607

So, According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

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The equation y equals 15 times 2 to the power of t shows the number of infected people from an outbreak of the measles. The variable y represents the number of infected people, and t represents time in weeks. In how many weeks will the number of infected people reach 1200?

Answers

It will take 6 weeks for the number of infected people to reach 1200

How to determine the number of weeks?

The function is given as:

y equals 15 times 2 to the power of t

Rewrite the function properly as follows

y = 15 * 2^t

When the population is 1200, the equation becomes

15 * 2^t = 1200

Divide both sides by 15

2^t = 80

Take the logarithm of both sides

t * log(2) = log(80)

Divide both sides by log(2)

t = 6.3

Approximate

t = 6

Hence, it will take 6 weeks for the number of infected people to reach 1200

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PLEASE HELP ME !” ASAP?

Answers

Answer:

39°

Step-by-step explanation:

Opposite angles of a parallelogram are congruent.

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

" The opposite angles of a Parallelogram are always equal to one another "

[tex] \qquad \large \sf {Conclusion} : [/tex][tex] \qquad \large \sf {Conclusion} : [/tex]

Angle M = Angle N = 39°

The standard deviation of the following data set is 0.31. 99% of the data would fall in which range? 4.3, 5.1, 3.9, 4.5, 4.4, 4.9, 5.0, 4.7, 4.1, 4.6, 4.4, 4.3, 4.8, 4.4, 4.2, 4.5, 4.4

Answers

Answer: Pr(4.19 ≤ X ≤ 4.81)

Step-by-step explanation:

First of all, let's calculate the mean;

x¯ = (4.3 + 5.1 + 3.9 + 4.5 + 4.4 + 4.9 + 5.0 + 4.7 + 4.1 + 4.6 + 4.4 + 4.3 + 4.8 + 4.4 + 4.2 + 4.5 + 4.4)/17

x¯ = 76.5/17

x¯ = 4.5

We are given standard deviation; s = 0.31

Now, z-value for a 68% Confidence interval is 1

Range in which the data falls is;

Range = x¯ ± zs

Range = 4.5 ± (1 × 0.31)

Range is;

Pr[(4.5 - 0.31) ≤ X ≤ (4.5 + 0.31)]

Pr(4.19 ≤ X ≤ 4.81)

Answer:

Pr (3.57 ≤ X ≤ 5.43)

Step-by-step explanation:

Took the quiz.

Please help 50 points

Answers

Answer:

m∠RQS = 109°

Step-by-step explanation:

Angles on a straight line sum to 180°.

Therefore:

⇒ m∠RQS + m∠SQT = 180°

⇒ (15x + 4) + (10x + 1) = 180

⇒ 15x + 4 + 10x + 1 = 180

⇒ 15x + 10x + 4 + 1 = 180

⇒ 25x + 5 = 180

⇒ 25x + 5 - 5 = 180 - 5

⇒ 25x = 175

⇒ 25x ÷ 25 = 175 ÷ 25

⇒ x = 7

Now that we have found the value of x, substitute this into the expression for m∠RQS:

⇒ m∠RQS = 15(7) + 4

                  = 105 + 4

                  = 109°

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Sierra buys lunch in the cafeteria everyday. Lunch costs $2.00 each day, how much did she spend after 5 days.

Answers

Answer:

$2.00 each day so $2.00 x 5 = $10

NO LINKS!! Please help me with this problem​

Answers

Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

a = 7 - 3 = 4 units

Now, it's focus can be represented as ;

[tex]\qquad \sf  \dashrightarrow \: (3 + ae, - 5 )[/tex]

so,

ae + 3 = 9

and we know, a = 4

[tex]\qquad \sf  \dashrightarrow \: 4e + 3 = 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4e = 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{3}{2} [/tex]

Now, let's find the measure of semi - conjugate axis (b)

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = {a}^{2} ( {e}^{2} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9}{4} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9 - 4}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{5}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 20[/tex]

[tex]\qquad \sf  \dashrightarrow \: b = \sqrt{20} [/tex]

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(x - h)}^{2} }{ {a}^{2} } - \cfrac{( {y - k)}^{2} }{ {b}^{2} } = 1[/tex]

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ ({x-3)}^{2} }{ {16}^{} } - \dfrac{ {(y+5)}^{2} }{ { {20} }^{} } = 1[/tex]

Hello and Good Morning/Afternoon:

Let's solve this problem step-by-step:

Let's find the format of the standard form of hyperbole:

 [tex]\hookrightarrow \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1[/tex]

(h,k): hyperbole center ⇒(3,-5)

Let's find the value of a, b:

value of a: distance between vertex (7, -5) and center (3, -5)

             [tex]a = \sqrt{(7-3)^2+(-5--5)^2} =\sqrt{16} =4[/tex]

value of b: [tex]\sqrt{c^2-a^2}[/tex]

           ⇒value of c: distance between focus (9, -5) and center (3, -5)

                  [tex]c = \sqrt{(3-9)^2+(-5--5)^2}=\sqrt{36} =6[/tex]

            ⇒ therefore:

                  [tex]b = \sqrt{c^2-a^2} =\sqrt{6^2-4^2}=\sqrt{20}[/tex]

Let's plug everything into our standard form of the equation:

   [tex]\frac{(x-3)^2}{4^2} -\frac{(y--5)^2}{(\sqrt{20})^2 } =1\\\frac{(x-3)^2}{16} -\frac{(y+5)^2}{20 } =1[/tex] <== Answer

Hope that helps!

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A poll was conducted by a home mortgage company regarding home ownership in the United States. The company polled 1,488 Americans and found that 69% of those polled own a home. What is the approximate margin of error, assuming a 99% confidence level?

Answers

If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.

We are required to find the approximate margin of error.

Margin of error is the difference between calculated values and real values.

n=1488

p=0.69

Margin of error=z*[tex]\sqrt{p(1-p)/n}[/tex]

Z score when confidence level is 99%=2.576.

Margin of error=2.576*[tex]\sqrt{0.69(1-0.69)/1488}[/tex]

=2.576*[tex]\sqrt{(0.69*0.31)/1488}[/tex]

=2.576*[tex]\sqrt{0.2139/1488}[/tex]

=2.576*[tex]\sqrt{0.0001437}[/tex]

=2.576*0.01198

=0.03088

Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

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Answer:

0.031

Step-by-step explanation:

Plato/Edmentum



Which expression shows the factored form of 49x² - y²?

Answers

Step-by-step explanation:

49x^2-y^2

=(7x)^2-(y)^2

=(7x+y) (7x-y)

Therefore, a^2-b^3

=(a+b) (a-b)

Suppose that 5 workers can complete a certain task in 12 days. If there are 4 workers, how many days would it take for them to finish the same task

Answers

Answer:

15 days

Step-by-step explanation:

5 workers times 12 days is 60 days per worker which gets reduced based on how many workers there are. 60 divide by 4 workers now brings down to 15 days. 5 workers, 12 days. 10 workers 6 days etc.

The area of the entire figure below is 111 square unit.
A rectangle that has been split into 24 parts, set in 4 rows of 6 parts each. The parts in the top 3 rows have been shaded blue. The parts in the left 5 columns have been shaded purple. The first 5 parts in the top 3 rows are striped to show they are shaded both blue and purple. Along the top of the rectangle, the columns are labeled one-sixth. Along the left side of the rectangle, the rows are labeled one-fourth.










A rectangle that has been split into 24 parts, set in 4 rows of 6 parts each. The parts in the top 3 rows have been shaded blue. The parts in the left 5 columns have been shaded purple. The first 5 parts in the top 3 rows are striped to show they are shaded both blue and purple. Along the top of the rectangle, the columns are labeled one-sixth. Along the left side of the rectangle, the rows are labeled one-fourth.
What is the area of the striped rectangle?

Answers

The striped rectangle has a total area of 69,375 cm².

How to calculate the area of the striped rectangle?

To find the area of the striped rectangle we must carry out the following procedures.

Find the area of each segment of the rectangle, that is, what is the area of each of the 24 squares that make up the rectangle, for that we divide the 111cm² of the total area into 24.

111cm² ÷ 24 = 4.625cm²

According to the above, we infer that each square has an area of 4.625cm².

On the other hand, to find the area of the striped rectangle we must take into account that it is 5 squares long by 3 squares high, that is, its area is 15 squares.

3 × 5 = 15

Finally, each square has an area of 4.625cm², so to find the total area of the striped area we must multiply the area of each square by the number of squares.

15 × 4.625cm² = 69.375cm²

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help pleaseeeee
tysm

Answers

Answer: Either Rohmbus or Parallelogram...

Step-by-step explanation: Your picture is a bit small, sry

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