Testing examples include vulnerability scanning and penetration testing for web applications, security assessments for browsers, and penetration testing and scenario-based testing for mobile applications to identify and mitigate potential security risks and vulnerabilities.
What are some testing examples for web applications, browsers, and mobile applications against threats?Application threat analysis involves assessing potential security risks and vulnerabilities in an application to mitigate them effectively.
Testing example of a web application against threats:
One testing example is performing a vulnerability scan on the web application to identify any potential security loopholes, such as SQL injection, cross-site scripting (XSS), or insecure direct object references.
This involves using automated tools to scan the application's code and inputs for known vulnerabilities and potential attack vectors.
Testing example of a browser against threats:
A testing example for a browser would be conducting a security assessment to identify vulnerabilities and risks associated with the browser itself.
This can involve testing browser configurations, plugins/extensions, and security settings to ensure they are up to date and properly configured. It may also include testing browser behavior against known web-based attacks like phishing, malware, or drive-by downloads.
Testing example of a mobile application against threats:
For mobile applications, a testing example could involve performing a penetration test to simulate real-world attacks on the application.
This includes testing for vulnerabilities such as insecure data storage, improper session handling, or insecure communication channels.
Additionally, testing the application's response to different threat scenarios, such as tampering with data or manipulating the application's behavior, can help identify and address potential security risks.
Learn more about web applications
brainly.com/question/28302966
#SPJ11
Create a class called Registration with the following members and methods: Name Course YearLevel Birthday NumberOfSiblings Create constructor for the class. Create setters and getters. Create a function/method for the class. Use the class in the main program.
In the example above, the Registration class has private fields for name, course, yearLevel, birthday, and numberOfSiblings.
It has a constructor to initialize these fields, setters and getters to access and modify the field values, and a displayInfo() method to print the information of a student object. Finally, in the main method, a Registration object is created, and its information is displayed using the displayInfo() method.
Here's an example implementation of the Registration class in Java:
java
Copy code
public class Registration {
private String name;
private String course;
private int yearLevel;
private String birthday;
private int numberOfSiblings;
// Constructor
public Registration(String name, String course, int yearLevel, String birthday, int numberOfSiblings) {
this.name = name;
this.course = course;
this.yearLevel = yearLevel;
this.birthday = birthday;
this.numberOfSiblings = numberOfSiblings;
}
// Setters and getters
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getCourse() {
return course;
}
public void setCourse(String course) {
this.course = course;
}
public int getYearLevel() {
return yearLevel;
}
public void setYearLevel(int yearLevel) {
this.yearLevel = yearLevel;
}
public String getBirthday() {
return birthday;
}
public void setBirthday(String birthday) {
this.birthday = birthday;
}
public int getNumberOfSiblings() {
return numberOfSiblings;
}
public void setNumberOfSiblings(int numberOfSiblings) {
this.numberOfSiblings = numberOfSiblings;
}
// Additional method
public void displayInfo() {
System.out.println("Name: " + name);
System.out.println("Course: " + course);
System.out.println("Year Level: " + yearLevel);
System.out.println("Birthday: " + birthday);
System.out.println("Number of Siblings: " + numberOfSiblings);
}
// Main program
public static void main(String[] args) {
// Create a Registration object
Registration student = new Registration("John Doe", "Computer Science", 2, "1998-05-20", 2);
// Display student's information
student.displayInfo();
}
}
Know more about Java here:
https://brainly.com/question/33208576
#SPJ11
how to make an arraylist which contains the top 3 active objects
To make an ArrayList that contains the top 3 active objects, you can follow these steps: Create an ArrayList of objects with their respective attributes, Sort the ArrayList in descending order based on the attribute that you want to rank and Retrieve the top 3 objects from the ArrayList.
Step 1: Create an ArrayList of objects with their respective attributes. For example, let's say we have a list of athletes with their names and scores. We can create an Arraylist with the following code:
ArrayList athletes = new Array List<>();
Step 2: Sort the Arraylist in descending order based on the attribute that you want to rank. In this example, we want to sort the athletes based on their scores. We can use the Collections.sort() method to sort the Array List in descending order.
Here's the code:
Collections.sort(athletes, new Comparator()
{public int compare(Athlete a1, Athlete a2)
{return a2.getScore() - a1.getScore();}});
Step 3: Retrieve the top 3 objects from the Array List. In this example, we want to retrieve the top 3 athletes with the highest scores.
We can use a for loop to iterate through the Array List and retrieve the first three objects.
Here's the code:
int count = 0;
Array List top Athletes = new ArrayList<>();
for (Athlete athlete : athletes)
{top Athletes.add(athlete);
count++;if (count == 3) {break;}}
This code will create an ArrayList called top Athletes that contains the top 3 athletes with the highest scores.
To know more about ArrayList visit:
https://brainly.com/question/9561368
#SPJ11
1. Explain the purpose of user acceptance test and why every development effort will have some form of UAT.
2. Consider the iterative approach
• Explain why it is logical to assume that each iteration will bring the development closer to 100% successful completion
• Give one reason why this continuous progress may not happen
• Describe a way to prevent this problem
1. User Acceptance Test (UAT) is the final phase of testing that validates whether the software product meets the business requirements and is ready for deployment. It is a critical process that verifies whether the software application is fit for purpose or not.
2.The iterative approach involves continuous feedback from stakeholders, which helps to identify issues early and mitigate them effectively. Each iteration builds on the previous one, making the software more refined and closer to meeting the stakeholders' requirements
It is important to have UAT in every development effort to ensure that the software meets the stakeholders' expectations. UAT helps to identify gaps between the business requirements and the software delivered.
UAT is performed by the end-users, clients, or stakeholders who are going to use the software product. The primary purpose of UAT is to ensure that the software meets business requirements, functions as expected, and is error-free before it is deployed to the production environment.
2. Consider the iterative approach
The iterative approach is a software development methodology that involves building a product incrementally in multiple iterations. Each iteration involves a set of activities, including planning, designing, coding, testing, and delivery. .
Therefore, it is logical to assume that each iteration will bring the development closer to 100% successful completion.One reason why this continuous progress may not happen
A continuous progress may not happen due to poor communication, lack of involvement, and lack of clear objectives. In some cases, stakeholders may have unrealistic expectations or may not provide timely feedback, which can lead to delays in the development process and hinder continuous progress.
To prevent this problem, it is important to establish clear objectives and expectations upfront and communicate them effectively with stakeholders. Engaging stakeholders throughout the development process and providing timely feedback can help to ensure that the development progresses continuously.
Regular communication, meetings, and progress reports can also help to keep stakeholders informed and involved.
Learn more about software at
https://brainly.com/question/32366445
#SPJ11
please be generic when proving is using pumping lemma do not pick a number to pump to or a particular stringProve that {0"#0²n#0³n | n >= 0} is not context-free.
The language L is not context-free using the pumping lemma.
To prove that the language L = {0"#0²n#0³n | n ≥ 0} is not context-free using the pumping lemma for context-free languages, we assume that L is context-free and arrive at a contradiction.
Let's suppose L is context-free and let p be the pumping length given by the pumping lemma. Now, consider the string s = 0"#0²p#0³p. According to the pumping lemma, we can split s into five parts: uvwxy, satisfying the following conditions:
1. |vwx| ≤ p
2. |vx| ≥ 1
3. For all i ≥ 0, u(v^i)w(x^i)y ∈ L
Let's analyze the possible cases for the string s:
1. If vwx contains the '#' symbol: In this case, pumping vwx will alter the number of '#' symbols and break the balanced occurrence of '#' between the 0²n and 0³n parts, resulting in a string that is not in L. Thus, this case is not valid.
2. If vwx contains only 0's or '#' symbols: In this case, pumping vwx will either increase the number of 0's or '#' symbols, breaking the equality of the number of 0's in the 0²n and 0³n parts, resulting in a string that is not in L. Thus, this case is not valid.
3. If vwx contains both 0's and '#' symbols: In this case, pumping vwx will cause an unequal number of 0's and '#' symbols, again breaking the balanced occurrence of '#' between the 0²n and 0³n parts, resulting in a string that is not in L. Thus, this case is not valid.
Since all possible cases lead to a contradiction, we can conclude that L = {0"#0²n#0³n | n ≥ 0} is not a context-free language.
Therefore, we have proved that the language L is not context-free using the pumping lemma.
Learn more about language here
https://brainly.com/question/31771123
#SPJ11
Write a C program for the ATmega16 that repeatedly gets an input from the user and inverts a specified LED on the STK500 board every 4 seconds. • For input, the 4-by-3 keypad is connected to PORTB. • For output, the 8 LEDS (LEDO, LED1, ...., LED7) are connected to PORTA. • The user specifies the LED by typing a digit '0', '1', ..., or '7', followed by the hash key '#' on the keypad. • Example: If the user types "3 #", then LED3 is inverted every 4 seconds; all other LEDs must remain unchanged. The program then waits for the user to enter the next digit. • The program then waits for the user to enter the next LED. • For timing purpose, the program must explicitly intercept Timer 1 Overflow Interrupt. • It can be assumed that the user only presses keys '1', '2', ..., '7' or '#'. • At the top of the C program, add one C comment to explain how the circuit is setup. Add another C comment about possible sources of errors in your program and how would you detect and correct them. Follow the instructions in this page (shown above) to create and upload your answer.
The code for C program is given below.
Here is the C program for the ATmega16 that repeatedly gets an input from the user and inverts a specified LED on the STK500 board every 4 seconds:```
#include
#include
#include
#define LEDO 0
#define LED1 1
#define LED2 2
#define LED3 3
#define LED4 4
#define LED5 5
#define LED6 6
#define LED7 7
volatile unsigned char led_state[8] = {0,0,0,0,0,0,0,0};
volatile unsigned char led_index = 0;
ISR(TIMER1_OVF_vect)
{
if (++led_index == 4) {
led_index = 0;
PORTA ^= (1<
Thus, the code is given above.
To know more about code visit
https://brainly.com/question/2924866
#SPJ11
1. What is the Chart of Accounts?
A. the list of accounts that makes up the General Ledger and is the foundation of the company file
B. the menu of products and services that the company offers its customers
C. a full list of accounts the company has with its frequently used suppliers and vendors
D. the list of customers who purchase a company’s products and services on account
The Chart of Accounts (COA) is the list of accounts that makes up General Ledger and is the foundation of the company file. Therefore, the correct option is A. For a financial system to accurately record accounting data, the chart of accounts must be properly set up.
The Chart of Accounts is a comprehensive listing of all the accounts that make up the General Ledger in an accounting system. It serves as the foundation of the company file and organizes financial transactions into specific categories. Each account in the Chart of Accounts represents a different aspect of the company's financial activities, such as assets, liabilities, equity, revenue, and expenses.
By using a standardized Chart of Accounts, businesses can maintain consistency in recording and categorizing financial transactions. It provides a structured framework for organizing financial information, enabling accurate and meaningful reporting and analysis. The accounts in the Chart of Accounts typically have unique codes or numbers assigned to them for easy identification and reference.
Option B, the menu of products and services that the company offers its customers, refers to a product or service catalog rather than the Chart of Accounts. Option C, a full list of accounts the company has with its frequently used suppliers and vendors, pertains to the company's accounts payable records. Option D, the list of customers who purchase a company's products and services on account, relates to accounts receivable.
Option A is correct.
Learn more about General Ledger: https://brainly.com/question/1436327
#SPJ11
5 cos(400t-45°) - 12sin(400t +30°) =
The formula of the resultant of the vector system is R = √(x² + y²), where x and y are the horizontal and vertical components of the vector system. A vector is represented by a mathematical expression and has both magnitude and direction. Vectors can be calculated using rectangular components and polar components or through unit vectors.
What are rectangular components? The rectangular component of a vector system is the horizontal and vertical components of a vector. A vector system's horizontal component is referred to as the x-component, while the vertical component is referred to as the y-component. What are polar components? Polar components refer to the magnitude and direction of a vector. The magnitude of a vector refers to the length of the vector, while the direction refers to the angle of the vector. Polar components can be computed by using the cosine and sine formulas for determining the horizontal and vertical components of a vector.
In the expression below, 5 cos(400t-45°) - 12sin(400t +30°), we are given two vector quantities to calculate. We'll need to convert these to rectangular components and then add them together to get the final answer.To convert polar components to rectangular components, we'll use the formula x = r cos θ and y = r sin θ, where r is the magnitude and θ is the direction.Let's begin with the first term,5 cos(400t-45°)First, we'll convert it to rectangular components using the formula:r = 5, θ = 400t - 45°x = r cos θ = 5 cos(400t - 45°)y = r sin θ = 5 sin(400t - 45°)Next, we'll convert the second term,12sin(400t +30°):r = 12, θ = 400t + 30°x = r cos θ = 12 cos(400t + 30°)y = r sin θ = 12 sin(400t + 30°)Finally, we'll add the two rectangular components together:x = 5 cos(400t - 45°) + 12 cos(400t + 30°)y = 5 sin(400t - 45°) + 12 sin(400t + 30°)Therefore, the answer is: 5 cos(400t-45°) - 12sin(400t +30°) = 5 cos(400t - 45°) + 12 cos(400t + 30°) + 5 sin(400t - 45°) + 12 sin(400t + 30°).
To know more about vector visit:
https://brainly.com/question/30958460
#SPJ11
cout << "\n\nEnter your Choice: "; //Display
The given line of code cout << "\n\nEnter your Choice: "; //Display is used for displaying a message to prompt the user for input and the code is used for display purposes.
Cout is used for displaying outputs on the console, whereas the "<<" operator is used to append the string after it.
The "\n" is a newline character that is used to move the output cursor to the next line. Therefore, the entire code cout << "\n\nEnter your Choice: "; is used to display a message to prompt the user for input when running a C++ program or a function.
The user is expected to enter an input value once the prompt is displayed. This input value can be a number, a character, or any other data type that is valid in C++.
Learn more about C++ program: https://brainly.com/question/30905580
#SPJ11
An AM signal is represented by x(t) = (20 + 4sin500t) cos(2πx105 t) V. Solve the modulation index.
An AM signal is represented by x(t) = (20 + 4sin500t) cos(2πx105 t) V.
The amplitude of the message signal can be calculated by finding the difference between the maximum and minimum values of the sine wave. We know that the maximum value of the sine wave is 4 and the minimum value is -4, therefore the amplitude is 4-(-4) = 8 V. The amplitude of the carrier signal can be calculated by finding the maximum value of the cosine wave. The maximum value of a cosine wave is 1 .
Therefore the amplitude of the carrier signal is 20 V The modulation index can be calculated by dividing the amplitude of the message signal by the amplitude of the carrier signal. Therefore, the modulation index is 8/20 = 0.4 or 40%.
Thus, the modulation index of the given AM signal is 0.4 or 40%.
To know more about modulation visit :
https://brainly.com/question/28520208
#SPJ11
Write a MATLAB function for a Length-3 Moving Average Filter.
A Length-3 Moving Average Filter is used to smooth out data and reduce noise.
Here's how to write a MATLAB function for a Length-3 Moving Average Filter:```
function [y] = Moving_Avg_Filter(x)
% Length-3 Moving Average Filter
N = length(x);
y = zeros(N,1);
y(1) = x(1);
y(N) = x(N);
for i = 2:N-1
y(i) = (x(i-1) + x(i) + x(i+1)) / 3;
end
end
```
The input of the function is an array `x` and the output is an array `y`. This function initializes the output array to zeros and sets the first and last values of `y` to the first and last values of `x`, respectively.
The for-loop iterates through the elements of `x` from the second to second-to-last value, and the elements of `y` are computed using the formula for a length-3 moving average filter, which is `(x(i-1) + x(i) + x(i+1)) / 3`.
This formula takes the average of the previous, current, and next values of `x` to compute the corresponding value of `y`. Finally, the function returns `y` as the output.
To know more about function visit;
brainly.com/question/30721594
#SPJ11
Design an oscillator to provide a frequency of 100kHz. Show all
calculations. You may have to make some minor adjustments to get
the exact frequency. The inductor value should not be less than
1.5uH.
A Colpitts oscillator can be used to design a 100 kHz oscillator. The frequency of the oscillator is determined by the values of L, C1, and C2.
The following are the steps for designing a Colpitts oscillator:
S
1: To begin, choose a suitable frequency for the oscillator. In this scenario, we want a frequency of 100 kHz. As a result, f= 100kHz
2: Choose an inductor value (L). The inductor value should not be less than 1.5 μH. As a result, L= 1.5μH or greater.
3: Choose a suitable value for the capacitor C1, which is connected to the inductor in parallel. The capacitor value can be calculated using the following formula:XC1 = 1/2πfL
Here, f= 100kHz and L= 1.5μ
HXC1= 1/2πf
LXC1= 1/(2×3.14×100000×1.5×10^-6)
XC1= 1.061×10^3 pF ≈ 1.1nF
4: Choose a suitable value for the capacitor C2, which is connected in parallel with the inductor and the series combination of R1 and R2. The capacitor value can be calculated using the following formula:
XC2 = 1/2πf(C1+C2)
Here, f= 100kHz, XC1= 1.1nF
XC2 = 1/2πf(C1+C2)
XC2 = 1/(2×3.14×100000×(1.1×10^-9+C2))
Since XC2 << C2; C2 can be assumed to be equal to XC2.XC2 = XC2= 1.066×10^3 pF ≈ 1.1nF
5: Connect the circuit as shown below: As shown in the above circuit, the inductor value can be set to 1.5 μH, R1 and R2 can be set to 10 kΩ, and C1 and C2 can be set to 1.1 nF.
These values are sufficient to generate a 100 kHz frequency.Multisim file for the above circuit is shown below:
Therefore, by following the above steps, we can design the oscillator to provide a frequency of 100 kHz.
Learn more about Colpitts oscillator at
https://brainly.com/question/32752889
#SPJ11
Create a project Zoo in BlueJ. The project has Animal, Mammal, Reptile, Dog classes Animal is the super class of Mammal and Reptile. Dog is a subclass of both Mammal and Animal class a) Show the relationship between above mentioned classes and write the necessary class definitions (fields and methods). All the fields and methods should be declared .as protected b) Implement the concept of method overriding in the Zoo project. Use keyword super .to call the base constructor in each subclass Create a project WildLife in BlueJ. The project has Mammal, Reptile, Crocodile, Rabbit and Fox classes. .Rabbit and Fox inherit from Mammal. Mammal and Reptile inherit from an abstract class Animal .a) Show the relationship between above mentioned classes and write the necessary class definitions b) Class Animal should have both abstract and non-abstract methods. The Animal class have may run(), eat(), die() as abstract methods. Reptile class does not provide implementation of Animal's abstract methods, thus has to be declared as abstract
The class definitions for the Zoo project and the WildLife project as well as the implementation is given in the code attached.
What is the project about?Inside of the Zoo project , the Creature course is the superclass of Warm blooded animal and Reptile. The Dog course may be a subclass of both Warm blooded creature and Creature.
Within the WildLife project , the Creature lesson is an unique course with unique strategies run(), eat(), and die(). The Well evolved creature and Reptile classes acquire from the Creature lesson. The Crocodile course may be a subclass of Reptile, whereas the Rabbit and Fox classes acquire from Well evolved creature.
Learn more about project from
https://brainly.com/question/19842887
#SPJ4
Consider the system Ilowolaitoi225M lo vietovim goitoonigma 19tum [1 2 2 7 Ta] o in α 10 dx/dt = 0 -1 -3 x + 0 u 10 Fordi 10 0 2 | В EN y = [a 0 b)x yd (1,0) Isv1910i 9mit to OSLE ta a. Determine the eigenvalues and eigenvectors. = 15 b. Determine the state-transition matrix. c. Determine when the system is controllable.molio motor d. Determine when the system is observable. helles
The given system isIlowolaitoi225M lo vietovim goitoonigma 19tum [1 2 2 7 Ta] o in α 10 dx/dt = 0 -1 -3 x + 0 u 10 Fordi 10 0 2 | В EN y = [a 0 b)x yd (1,0) Isv1910i 9mit to OSLE ta a.
We are to determine the following. a) Determine the eigenvalues and eigenvectors. b) Determine the state-transition matrix. c) Determine when the system is controllable. d) Determine when the system is observable.
(a) To determine eigenvalues and eigenvectors. The characteristic equation of the system is given by:
| λ-0 1 -3 |λ = 0-1 λ 0 2λ 0 λ-10
The eigenvalues of the system are the roots of the characteristic equation | λ-0 1 -3 |λ = 0-1 λ 0 2λ 0 λ-10| λ-0 1 -3 |
= (λ)(λ² + 10) + 2
= λ³ + 10λ + 2λ² + 20
= λ³ + 2λ² + 10λ + 20= 0
On solving above equation by using any numerical technique, we get: λ1 = -0.3166
λ2 = -4.8415
λ3 = -5.8420
The eigenvectors are obtained by solving the following equations Ax = λx where A is the system matrix, λ is the eigenvalue and x is the eigenvector.
For λ1 = -0.3166, we get x = [-0.9644, -0.2588, 0]T
For λ2 = -4.8415, we get x = [-0.2465, 0.5343, 1]T
For λ3 = -5.8420, we get x = [-0.1319, 0.7032, 1]T
(b) To determine state-transition matrix The state-transition matrix is given by φ(t) = e(At) Using MATLAB we can find φ(t) by executing the following commands A = [0 -1 -3; 0 0 2; 10 0 -2] φ = exp m(A*t)(c) To determine when the system is controllable. The system is controllable if and only if the controllability matrix is of full rank. The controllability matrix of the system is given by M = [B AB A²B] where A and B are the system matrices.
A = [0 -1 -3; 0 0 2; 10 0 -2];
B = [0; 0; 10];
M = [B A*B A2*B] rank(M)
The rank of the controllability matrix is 3 which is equal to the dimension of the state space. Hence, the system is controllable. (d) To determine when the system is observable. The system is observable if and only if the observability matrix is of full rank. The observability matrix of the system is given by O = [C; CA; CA²] where C is the output matrix.
A = [0 -1 -3; 0 0 2; 10 0 -2];
C = [a 0 b];
O = [C; C*A; C*A2]rank(O)
The rank of the observability matrix is 3 which is equal to the dimension of the state space. Hence, the system is observable.
To know more about matrix visit:-
https://brainly.com/question/28180105
#SPJ11
For the following questions you will need to download, compile, and execute a small program in your virtual environment: Type the following command into the terminal window to pull the project repository from GitLab: git clone https://cci-git.uncc.edu/jbahamon/ITSC_3146_Processes.git (Links to an external site.)
STEPS:
Change directory into the newly created directory (folder) named ITSC_3146_Processes. Issue the following command to compile the code: g++ process-fork-1.cpp -o p1 Issue the following command to execute the program: ./p1 Note: Copy, paste, and modify all necessary commands from this Git command snippet page (Links to an external site.). This will strip out any special characters.
QUESTIONS:
1. What is the exact text in the first line printed by the program?
2. What is the exact text in the second line printed by the program?
3. Use the editor in your virtual environment to find the source code for the program that you just compiled and executed. Briefly describe the following:
a) The purpose of the code on line 19, i.e., what does this line of code accomplish?.
b) The purpose of the code on lines 21-27 (if statement). Make sure to explain each possibility handled by the if.
The exact text in the first line printed by the program is: This is the parent process with process ID (PID): 2. The exact text in the second line printed by the program is: This is the child process with process ID (PID): 3.
The purpose of the code on line 19 is to fork a child process from the parent process. It is responsible for creating a new child process, which is a copy of the parent process.The purpose of the code on lines 21-27 (if statement) is to handle two possibilities: The first possibility is that the fork() system call fails to create a child process. This means that the return value of fork() is -1, which indicates an error. In this case, an error message is printed and the program exits with an error status code.
The second possibility is that the fork() system call successfully creates a child process. This means that the return value of fork() is 0, which indicates that the current process is the child process. In this case, the child process executes the code inside the if statement, which prints a message indicating that it is the child process, along with its process ID.
Overall, the purpose of the if statement is to distinguish between the parent process and the child process, and to execute different code depending on which process is running.
To know more about program visit:
https://brainly.com/question/30613605
#SPJ11
ANSWER USING MATLABWhen you use load as a function, you can O A. retrieve the variables in the MAT file and restore them as global varaibels. O B. retrieve the variables in the MAT file and store them in a structure varaible. O C. retrieve the variables in the MAT file into the workspace of a function O D.retrieve the variables in the MAT file and restore them in the work space.
In MATLAB, you can use the `load` function to retrieve variables from a .mat file. When using the `load` function, the variables in the .mat file are restored in the workspace by default. The correct option is Option D:
retrieve the variables in the MAT file and restore them in the workspace.
Here's how you can use the `load` function in MATLAB to retrieve variables from a .mat file:
1. Define the name of the .mat file you want to retrieve variables from, e.g. `mydata.mat`.
2. Use the `load` function with the filename as input to load the variables from the .mat file into the workspace:```
load('mydata.mat')
```After running this code, the variables in `mydata.mat` will be available in the workspace as global variables. Note that any existing variables in the workspace with the same names as the variables in `mydata.mat` will be overwritten.
To know more about global variable visit :
https://brainly.com/question/30750690
#SPJ11
using emu8086 asembly Write a program that prompts the user for five 32-bit integers, stores them in an array, calculates only the sum of the ODD values of the array, displays the sum on the screen. In addition, this program prompts the user for a 32-bit integer and display if the array contains this value or not. We suppose that we deal only with unsigned integer. Your code must be composed with the following procedures. 1. Main procedure 2. Prompt user for multiple integers 3. Calculate the sum of the ODD values of the array 4. Display the sum 5. Prompt user for an integer, fetch it into the array and display on screen "Exist" or "Not Exist"
The code is presented below:```
include emu8086.inc
org 100h
; define data segment
.data
; array that stores 5 integers
array db 20 DUP(0)
; prompt messages
prompt1 db "Please enter 5 32-bit integers:", 0
prompt2 db "Please enter a 32-bit integer to search for:", 0
; result messages
result1 db "The sum of the odd values in the array is: $", 0
result2 db "The array contains the specified integer.", 0
result3 db "The array does not contain the specified integer.", 0
; define code segment
.code
; main procedure
main proc
; prompt user for multiple integers
mov dx, offset prompt1
call print_string
call read_array
; calculate the sum of the odd values of the array
call sum_odd_values
call print_sum
; prompt user for an integer, fetch it into the array and display "Exist" or "Not Exist"
mov dx, offset prompt2
call print_string
call search_array
; terminate program
mov ax, 4c00h
int 21h
main endp
; procedure to prompt user for multiple integers and store them in array
read_array proc
; loop 5 times to get 5 integers
mov cx, 5
mov di, 0
read_loop:
; prompt user for integer
call read_int
; store integer in array
mov [array+di], ax
; increment array index
add di, 4
; decrement loop counter
loop read_loop
ret
read_array endp
; procedure to calculate the sum of the odd values of the array
sum_odd_values proc
; initialize sum to 0
mov ax, 0
; initialize array index to 0
mov di, 0
; loop 5 times to check 5 integers
mov cx, 5
sum_loop:
; get integer from array
mov bx, [array+di]
; check if integer is odd
test bx, 1
jz skip_sum
; add odd integer to sum
add ax, bx
skip_sum:
; increment array index
add di, 4
; decrement loop counter
loop sum_loop
ret
sum_odd_values endp
; procedure to display the sum of the odd values of the array
print_sum proc
; display message
mov dx, offset result1
call print_string
; display sum
call print_int
ret
print_sum endp
; procedure to search array for specified integer
search_array proc
; prompt user for integer
call read_int
; initialize array index to 0
mov di, 0
; loop 5 times to check 5 integers
mov cx, 5
search_loop:
; get integer from array
mov bx, [array+di]
; check if integer matches specified integer
cmp bx, ax
jne skip_search
; display message if integer is found
mov dx, offset result2
call print_string
jmp end_search
skip_search:
; increment array index
add di, 4
; decrement loop counter
loop search_loop
; display message if integer is not found
mov dx, offset result3
call print_string
end_search:
ret
search_array endp
; include print_string, read_int, and print_int procedures from emu8086 library
include print_string.inc
include read_int.inc
include print_int.inc
end
```
To know more about presented visit:
https://brainly.com/question/1493563
#SPJ11
int mystery(int n, int x) { if (x < 1) return 0; else return (n + mystery (n,x-1) ); } (a) What is the base (or terminating) case for the above recursive method? (b) What is the recursive case? (c) Trace the method on the following input pairs: n=0, x=2 and n=5, x=3. (d) Write a loop that does the same work that is done by the recursive method. (e) Give a non-recursive mathematical formula for the output of the function on input n and x. mystery(n,x): =
(a) The base (or terminating) case for the given recursive method is if x < 1, then return 0.(b) The recursive case is given as if x >= 1, then return (n + mystery(n,x-1)).
(c) Let's trace the method on the following input pairs:n=0, x=2mystery(0,2) returns:mystery(0,2) = 0 + mystery(0,1) = 0 + 0 + mystery(0,0) = 0 + 0 + 0 = 0n=5, x=3mystery(5,3) returns:mystery(5,3) = 5 + mystery(5,2) = 5 + 5 + mystery(5,1) = 5 + 5 + 5 + mystery(5,0) = 5 + 5 + 5 + 0 = 15
(d) Here is the loop that does the same work that is done by the recursive method: int mystery(int n, int x){ int result = 0; for (int i = x; i >= 1; i--) { result = result + n; } return result;}The loop is used to compute the sum of x number of n values.(e) The non-recursive mathematical formula for the output of the function on input n and x is as follows:mystery(n, x) = n*x
TO know more about that recursive visit:
https://brainly.com/question/32344376
#SPJ11
Assume there's a FIR filter with three zeros locate at e¹,e-¹ and -√2, while three poles locate at the origin. Please: (a) find its transfer function. (4pts) (b) determine if this filter is stable, why or why not? (3pts) (c) find and sketch its impulse response. (3pts) = 48[n] [n 2] is input into a Question2 Assume a digital signal r[n] filter system that can be described as: 4y[n] = bxy[n 1] + y[n − 2] + x[n] + a × x[n − 1] − x[n − 2], where a and b are tunable coefficients used to change the design of the system. Please: (a) find the transfer function of this filter system (please keep a and b in the expression for now). (3pts) (b) if we want to complete the design so that the filter has two poles located at 10.5 and two zeros located at -1 + √2, what values of a and b should we choose? (2pts) (c) sketch the zero-pole plot and the direct form II diagram of the completed design out of (b) part. (2pts) (d) calculate and sketch the output sequence after feeding r[n] into this system. (3pts)
a) The transfer function is defined as the output divided by the input. Here, the output is the product of the zeros, divided by the product of the poles.
Therefore, we have: `H(z) = (z-e¹)(z-e⁻¹)(z+√2) / z³`Expanding this, we get:`H(z) = (z² - 2cos(π/4)z + 1)(z+√2) / z³``H(z) = (z³ + (1-2cos(π/4)+√2)z² + (2cos(π/4)-√2)z + √2) / z³`b) The filter is stable if all the poles are inside the unit circle. Since all the poles here are at the origin, which is within the unit circle, the filter is stable.c) The impulse response is the inverse Z-transform of the transfer function. Therefore, we have:`H(z) = 1 + 48z⁻¹ + 64z⁻²``h[n] = δ[n] + 48δ[n-1] + 64δ[n-2]`d) To find the output, we can convolve the input with the impulse response. Therefore:`y[n] = h[n] * r[n]``y[n] = δ[n]r[n] + 48δ[n-1]r[n] + 64δ[n-2]r[n]``y[n] = r[n] + 48r[n-1] + 64r[n-2]`b) To find the transfer function, we can divide both sides by `x[n]`. Therefore:`y[n] / x[n] = (bx[n-1] + y[n-2] + x[n] + ax[n-1] - x[n-2]) / 4x[n]``H(z) = Y(z) / X(z) = (bz⁻¹ + z⁻² + 1 + az⁻¹ - z⁻²) / 4`c) The zeros and poles are given as:Zeros: `-1 + √2`Poles: `10.5, 10.5`The transfer function can be expressed as:```
(z-(-1 + √2))(z-(-1 - √2))(z-10.5)(z-10.5)
H(z) = K * ----------------------------------------------------------
(z-1)(z-1)
```Therefore, we have:`K = 4 / (10.5-1)²(-1+√2-1)(-1-√2-1)`Substituting and simplifying, we get: `K = -128√2/1431`Therefore, the transfer function can be written as:```
(z-(-1 + √2))(z-(-1 - √2))(z-10.5)(z-10.5)
H(z) = -128√2 * ----------------------------------------------------------
(z-1)(z-1)
width=602&height=244)
The output can be found by convolving the input with the impulse response, just as in part (d) of the previous question.
To know more about impulse visit:
https://brainly.com/question/30466819
#SPJ11
a)Design a 3 bit sequential circuit using D flip flops and one input X. When X = 0 the state of the circuit remains the same. When X = 1 the circuit goes through state transition from 0 >6>2>3>5->0. Make the sate table, state equation and state diagram. b)Design a 3 bit sequential circuit using T flip flops and one input X. When X = 0 the state of the circuit remains the same. When X = 1 the circuit goes through state transition from 0 >6>235 -> 0. Make the sate table, state equation and state diagram.
a) Design a 3-bit sequential circuit using D flip-flops and one input X:First, we make the state table, which is as follows:Next, we will make the state diagram using the state table.
A state diagram is a graphical representation of a state table that displays the possible states and the possible transitions between those states, which is shown below:Finally, we obtain the state equations by simplifying the K-maps for D1, D2, and D3.
The simplified K-map for D1 is shown below:Therefore, D1 = X. The K-map for D2 is shown below:Therefore, D2 = X' Q1 Q0 + X Q0. The K-map for D3 is shown below:Therefore, D3 = X Q1' Q0' + X Q1' Q0 + X Q1 Q0 + X' Q1 Q0'. Therefore, the state equations are Q1 = X' Q0 + X Q0' and Q2 = X Q1' Q0' + X Q1' Q0 + X Q1 Q0 + X' Q1 Q0'.Thus, the 3-bit sequential circuit can be designed using D flip-flops and one input X with state table, state equation, and state diagram.
To know more about sequential visit:
https://brainly.com/question/14212897
#SPJ11
Implement find all d(depth) and pi(pre vertex) in BFS of undirected graph code please. I just need C code!!
Breadth-first search (BFS) is an algorithm used to traverse or search tree or graph data structures.
It starts at the tree root (or some arbitrary node of a graph) and explores all neighbor nodes at the current depth before proceeding to nodes at the next depth level. To implement find all d(depth) and pi(pre-vertex) in BFS of the undirected graph code, you need to modify the BFS code. Here is the modified code with explanations:```
void BFS(int s, int n, int adj[][n], int d[], int pi[])// s is the source node, n is the number of vertices
{
int i, v;
for (i = 0; i < n; i++)
{
d[i] = -1; //initialize all distances to -1
pi[i] = -1; //initialize all predecessor to -1
}
d[s] = 0; //set the source distance as 0
pi[s] = -1;//set the source predecessor as -1
queue q;
init(&q); //initialize the queue
enqueue(&q, s); //enqueue the source node
while (!isEmpty(&q))
{
v = dequeue(&q); //dequeue a vertex from the queue
for (i = 0; i < n; i++)
{
if (adj[v][i] && d[i] == -1) //if i is adjacent to v and i has not been visited
{
d[i] = d[v] + 1; //set the distance of i from s
pi[i] = v; //set the predecessor of i
enqueue(&q, i); //enqueue i
This code will print the distance and predecessor nodes for all the nodes in the graph. The output will be in the format Vertex, Distance, Predecessor. The code is written in C language.
To know more about algorithm visit:-
https://brainly.com/question/30033801
#SPJ11
Problem Statement: Implement a program that will return the highest frequency word in any given string. The string given can be song lyrics, and you will return the word the occurs the most amount of times in all lowercase letters. Criteria: Input: Just a small town girl Livin' in a lonely world She took the midnight train goin' anywhere Just a city boy Born and raised in South Detroit He took the midnight train goin' anywhere A singer in a smokey room The smell of wine and cheap perfume For a smile they can share the night It goes on and on, and on, and on Output: a 1 highestFreqency.py 1 2 def highest Frequency (str): 3 CodeCheck Reset
Problem Statement: Implement a program that will return the highest frequency word in any given string. The string given can be song lyrics, and you will return the word that occurs the most amount of times in all lowercase letters. The given input of song lyrics will have a number of lines which contain the lyrics, and they will be in lowercase letters only.
The program should be able to return a word that occurs more than once, and if more than one word has the highest frequency, the function should return any of them. Criteria: 1. For the given problem statement, the input is a string that contains the lyrics to a song.2. The output of the program should be a single string that is the most frequently occurring word from the song lyrics.3.
The function should return all the words in lowercase letters.4. If there are multiple words that occur with the same highest frequency, the function should return any one of them.5. The program should be designed to handle edge cases like empty input strings or cases where all words occur with the same frequency.
6. The given program code should contain a function called highest Frequency that takes a string as input and returns a string as output. The program should be in Python language. More than 100 wordsPython Program:To solve the problem statement, the given program code needs to be modified.
Here is the modified Python code:```python#highest frequency functiondef highestFrequency(str):#create an empty dictionary to store the word countfreqDict = {}# converting the string to lower casestr = str.lower()#splitting the string into wordswords = str.split()#iterating through the wordsfor word in words:#checking if the word already exists in the dictionary if word in freqDict:freqDict[word] += 1else:
To know more about lyrics visit:
https://brainly.com/question/31569638
#SPJ11
In the client/server architecture of DBS, the following functions belong to the server side is:( )
(A)Display of user interface
(B)Storage structure of data
(C) Data input and output
(D) Report Output
In the client/server architecture of DBS, the following functions belong to the server side are (B) Storage structure of data and (D) Report Output
Client/server architecture refers to an approach to computing that involves multiple computer programs working together as client-server architecture. A client is a user interface that interacts with a server to request and use services. A server is a device that provides services to a client, either over the internet or a network.In database management, the server is responsible for maintaining the database and making it available to clients. The client provides a user interface to interact with the database. The server-side function includes Storage structure of data and Report Output because they're the only functions that the server manages.In a client/server architecture of DBS, all the data is stored on a server. The clients do not store any data. When a client wants to access data, it sends a request to the server. The server processes the request and returns the result to the client. Therefore, the server-side is responsible for managing the storage structure of data and report output. Data input and output, and Display of user interface belongs to the client-side of the client/server architecture of DBS.
To know more about Report Output visit:
https://brainly.com/question/32148146
#SPJ11
PART 1 SITE AND TEMPORARY WORKS 13 1.1 Site works and setting out 15 1.2 Accommodation, storage and security 22 1.3 Subsoil drainage 31 1.4 Excavations and timbering 35 Scaffolding 41 1.5 PART 2 SUBSTRUCTURE 51 2.1 Trench and basement excavation 53 2.2 Foundations 59 2.3 Reinforced concrete foundations 66 2.4 Concrete 72 2.5 Retaining walls 80 2.6 Basements 93 2.7 Trees: effect on foundations 103 PART 3 SUPERSTRUCTURE 109 3.1 Stonework 111 3.2 Brickwork 122 3.3 Blockwork 142 3.4 Cavity walls 147 3.5 Openings in walls 153 3.6 Arches 162 3.7 Timber-framed housing 170 3.8 Timber: properties and grading 174 Timber deterioration 3.9 180 3.10 Steel-framed housing 186 PART 4 FLOORS 191 4.1 Solid concrete ground floor construction 193 4.2 Suspended concrete ground floor construction 198 4.3 Suspended timber floors 202 4.4 Raised access floors 219 4.5 Precast concrete floors 222 4.6 Hollow block and waffle floors 227 4.7 Lateral restraint and slenderness factors 232 PART 5 FUEL COMBUSTION 239 5.1 Fireplaces, chimneys and flues 241 Boiler flues 251 5.2 PART 6 ROOFS 259 6.1 Roofs: timber, flat and pitched 261 6.2 Roof tiling and slating 278 6.3 Asphalt flat roofs 290 6.4 Lead-covered flat roofs 295 6.5 Copper-covered flat roofs 299 6.6 Rooflights in pitched roofs 303 PART 7 INTERNAL FIXTURES AND FITTINGS 311 7.1 Doors, door frames and linings 313 7.2 Glass and glazing 329 7.3 Windows 339 7.4 Timber stairs 354 7.5 Simple reinforced concrete stairs 370 7.6 Simple precast concrete stairs 376 7.7 Partitions 378 7.8 Finishes: floor, wall and ceiling 383 7.9 Internal fixings and shelves 400 7.10 Ironmongery 405 7.11 Painting and decorating 413 PART 8 INSULATION 417 Contents vii 8.1 Sound insulation 419 8.2 Thermal insulation 427 8.3 Thermal bridging 440 8.4 Draught-proofing and air permeability 443 PART 9 ACCESS AND FACILITIES FOR DISABLED PEOPLE: DWELLING HOUSES AND FLATS 447 9.1 Accessibility 449 9.2 Circulation space: principal storey 452 9.3 WC facilities 454 9.4 Accessibility in flats, common stairs and lifts 456 Switches, sockets and general controls 458 9.5 PART 10 FRAMED BUILDINGS 459 10.1 Simple framed buildings 461 10.2 Reinforced concrete frames 463 Formwork 484 10.3 10.4 Precast concrete frames 499 10.5 Structural steelwork frames 505 10.6 Claddings 525 10.7 Steel roof trusses and coverings 535 PART 11 SERVICES 549 11.1 Domestic water supply 551 11.2 Sanitary fittings and pipework 564 11.3 Drainage 578 11.4 Domestic electrical installations 608 11.5 Domestic gas installations 616 Bibliography 621 Index 623
The provided text appears to be a table of contents or an outline of a construction-related document. It lists various sections and topics related to site works, temporary works, substructure, superstructure, floors, fuel combustion, roofs, internal fixtures and fittings, insulation, access and facilities for disabled people, framed buildings, and services.
Each section covers specific aspects of construction, such as excavation, foundations, concrete, walls, floors, roofs, insulation, and various building systems.
The table of contents provides an overview of the topics covered in the document, allowing readers to navigate through the sections based on their specific interests or information needs. It serves as a roadmap for accessing detailed information on different construction aspects, ensuring a comprehensive understanding of the subject matter. The document likely serves as a reference or guide for professionals in the construction industry, providing insights into best practices, standards, and technical details related to site works, building components, and services.
Please note that without the content of the document itself, it is not possible to provide specific details or explanations for each section.
Learn more about combustion here
https://brainly.com/question/17041979
#SPJ11
A vector is given by x = [4.5 5 -16.12 21.8 10.1 10 -16.11 5 14 -3 3). Using conditional statements and loops, write a program that rearranges the elements of x in order from the smallest to the largest. Do not use MATLAB 's built-in function sort.
The given vector is given by:
x = [4.5 5 -16.12 21.8 10.1 10 -16.11 5 14 -3 3).
We have to write a program that rearranges the elements of x in order from the smallest to the largest by using conditional statements and loops.
To solve the problem given in the question, we need to use the selection sort algorithm. The algorithm for selection sort is as follows:For i = 1:n
min = i;
for j = i+1:n
if x(j) < x(min)
min = j;
end
end
temp = x(i);
x(i) = x(min);
x(min) = temp;
end
Now, let's write the MATLAB code to sort the given array in ascending order using selection sort algorithm.MATLAB Code:
Function selection_sort(x)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
n = length(x);
for i = 1:n
min = i;
for j = i+1:n
if x(j) < x(min)
min = j;
end
end
temp = x(i);
x(i) = x(min);
x(min) = temp;
end
end
Test the above function using the given input in the question.
x = [4.5 5 -16.12 21.8 10.1 10 -16.11 5 14 -3 3);selection_sort(x)
The output for the code is:
ans =Columns 1 through 9-
16.1200 -16.1100 -3.0000 3.0000 4.5000 5.0000 5.0000 10.0000 10.1000
Columns 10 through
110 14.0000 21.8000
To know more about vector visit:
https://brainly.com/question/24256726
#SPJ11
For DC Servo motor position control system, whose transfer function is given below;
K /[s (0.5s + 1)]
Find the discrete time transfer function G(z) of the system for sampling times T=1 and T=4. Explain the effect of sampling time on G(z).
2. Find the K interval that will make the closed-loop discrete-time system stable.
3. Show the accuracy of the K range you found by drawing the root locus for the system.
For DC Servo motor position control system, the transfer function is given below;K/[s(0.5s+1)]1. Discrete-time transfer function of the system for sampling times T=1 and T=4:The transfer function G(s) = K/[s(0.5s+1)]
The corresponding transfer function for T=1 is G(z) = (0.00035z + 0.00035) / (z^2 - 1.982z + 0.982)And the corresponding transfer function for T=4 is G(z) = (0.00064z + 0.00064) / (z^2 - 1.922z + 0.922)Effect of sampling time on G(z):The sampling period T determines the duration of the sampling interval.
As a result, if the sampling period increases, the frequency response of the system will shift to the right in the z-plane.2. K interval that will make the closed-loop discrete-time system stable To determine the stability of the system, the Nyquist criterion can be used. function can be obtained by solving the characteristic equation.
The root locus for the system is shown below .The accuracy of the K range found by drawing the root locus for the system is confirmed. It can be observed from the root locus that for K < 0, the poles of the closed-loop system lie on the real axis and the system is unstable. As K is increased from 0, the poles move towards the left half of the s-plane.
The system is stable if the poles lie in the left half of the s-plane. As K is further increased, the poles approach the imaginary axis and eventually become unstable again. This is because the system has become underdamped and the poles have complex conjugates with a positive real part.
To know more about position visit :
https://brainly.com/question/23709550
#SPJ11
A 2.75-m-Ø wood-stave pipe has 9 m³/s of water entering through a horizontal 30⁰ reducing bend where the other end is 1.82 m in diameter. The curved portion is made of steel plate to resist rupture and the bend is embedded in concrete block weighing 2400 kg/m³. The pressure at entrance of the bend is 138 kPa. The combined weight of the bend and its content is 268 kN. Neglecting friction in the flow, compute the minimum volume of concrete block holding the bend that can withstand the thrust of water on the bend assuming the coefficient of friction between the concrete and its foundation is 0.30.
The minimum volume of concrete block holding the bend that can withstand the thrust of water on the bend is 2.4292 m³. Diameter of the wooden stave pipe = 2.75 mDiameter of the other end of the pipe = 1.82 mWater flow rate = 9 m³/sPressure at the entrance of the bend = 138 kPaWeight of the concrete block = 2400 kg/m³Volume of the concrete block =
Weight of bend and content = 268 kNForce exerted by water on the bend = ?Coefficient of friction between the concrete and its foundation = 0.3We need to determine the minimum volume of the concrete block required to withstand the thrust of water on the bend.Let's calculate the force exerted by water on the bend by using the below formula:Force exerted by water on the bend = Flow rate x Pressure x Force correction factor = ρAV² x P x FCFρ = Density of water = 1000 kg/m³A = Area of the pipe = (π/4) × diameter² = (π/4) × (2.75 m)² = 5.94 m²V = Velocity
P = Pressure at the entrance of the bend = 138 kPaFCF = Force correction factor = 0.50 [for 30⁰ reducing bend]Force exerted by water on the bend = 1000 × 5.94 × (1.51)² × 138 × 0.50 = 377221.3 Nal force = 222840.5 NLet's calculate the horizontal force exerted by the water on the bend:Horizontal force = (Force exerted by water on the bend × diameter of the other end) / (diameter of the wooden stave pipe + diameter of the other end)Horizontal force = (377221.3 N × 1.82 m) / (2.75 m + 1.82 m)Horizontal force = 154380.8 NThe resultant force of the water on the bend is √(Vertical force² + Horizontal force²) = √(222840.5² + 1
TO know more about that volume visit:
https://brainly.com/question/28058531
#SPJ11
1 #include 2 #include 3 #include 4 #include 5 #include 6 7 char ptype [10]; 8 int main() 9-{ 10 int size = 50 * sizeof(int); 11 void *addr = mmap(e, size, PROT_READ | PROT_WRITE, MAP_SHARED | MAP_ANONYMOUS, -1, 0); printf("Mapped at: %p \n\n", addr); 12 13 14 int *shared = addr; 15 pid_t fork_return = fork(); 16 if (fork_return > 0) { 17- 18 shared [0]=40; 19 shared [1] = -20; 20 strcpy(ptype, "Parent"); int status; 21 22 waitpid (-1, &status, 0); 23 24 25- { 26 sleep (1); 27 printf("Child shared [0] = %d, shared [1] = %d\n", shared[0], shared [1]); shared [1] = 120; 28 29 strcpy(ptype, "Child "); 30 } 31 32 printf("%s: shared [0] : %d\n", ptype, shared[0]); printf("%s: shared[1]: %d\n", ptype, shared[1]); munmap (addr, size); 33 34 return 0; 35 } DARENENHONDAON } else
We print the values of the shared memory region to see the results. After that, we un map the shared memory region and exit the program.
This code example uses the shared memory area to communicate between a parent and a child process. The parent and child processes each get their own copy of the process image. They communicate via shared memory, which is created and allocated by the parent process and passed down to the child via the fork system call. In this example, both the parent and child processes use shared memory to read and write values.
For this purpose, we use the m map system call to allocate the shared memory region. After that, we write some values to shared memory in the parent process, and then read those values in the child process. To create a shared memory region, we use mmap with the following arguments: specify that the region is shared, and the memory is allocated anonymously.
To know more about results visit:
https://brainly.com/question/28992824
#SPJ11
Question
Which of the followings is true?
A. Non-line-of-sight describes spectral blindness at specific frequencies.
B. Line-of-sight is a fading concept.
C. Analog technologies are typically based on frequency techniques.
D. Fading is a phenomenon, which exists over wired telephony.
The following is true about fading: Fading is a phenomenon that occurs over wireless communication channels. Therefore, option D is correct.
What is Fading?Fading refers to the gradual weakening or loss of signal intensity over a communication channel. It is a phenomenon that exists over wireless communication channels, which is caused by multi-path propagation.
The signal experiences several reflections and refractions on its way to the receiver, resulting in constructive and destructive interference. Fading could be of two types: fast fading and slow fading. In fast fading, the signal strength fluctuates rapidly due to motion of the receiver or transmitter. Slow fading occurs due to changes in the environment, and it takes place over several minutes or even hours. It is characterized by a gradual decline in signal strength over time
So, the correct answer is D
Learn more about fading at
https://brainly.com/question/31455610
#SPJ11
4. Which of the following are Quantifiers when creating
a Regex
a. ?
b. &
c. *
d. $
Quantifiers are special characters in Regular Expressions that are used to match or search the same character or group of characters that appear in a particular pattern of data.
Let's understand which of the following are Quantifiers when creating a Regex: a. . &c. *d. $Out of these, the following are Quantifiers when creating a Regex: Option C: * - matches 0 or more instances of the character or group that precedes it.
Option D: $ - matches the end of the input or line that precedes it. matches 0 or 1 instances of the character or group that precedes it. b. & - is not a Quantifier. It is used to join two or more Regular Expressions. The final output will only match if both the Regular Expressions match. Thus, the correct answer is options (c) and (d) only, that is * and $.
To know more about pattern visit:
https://brainly.com/question/30571451
#SPJ11
Please carefully read the description，use "divide and conquer algorithm", the algorithm should run in O(logn) time, describe it in plain English.
The divide and conquer algorithm can be described in plain English as a method to solve a problem by breaking it down into smaller subproblems that are simpler to solve, solving these subproblems recursively, and then combining the solutions to the subproblems to arrive at the final solution.
Divide and conquer is an algorithmic technique that is used in computer science to solve a variety of problems. It works by breaking down a problem into smaller and more manageable pieces, and then solving each of these smaller pieces separately. Once each of these smaller pieces has been solved, the solution to the original problem can be easily obtained by combining the solutions to the smaller sub-problems.The algorithm works by dividing the problem into smaller sub-problems, solving each of these sub-problems recursively, and then combining the solutions to these sub-problems to obtain the final solution. The key to the success of this algorithm is that each sub-problem must be significantly smaller than the original problem, and that the solutions to the sub-problems can be combined efficiently to arrive at the final solution.
The divide and conquer algorithm is very efficient, and can often solve problems much faster than other algorithms. It has a time complexity of O(log n), which means that its running time grows at a rate that is proportional to the logarithm of the size of the input. This makes it ideal for solving problems that are very large, or that require a lot of processing power to solve.
To know more about visit:-
https://brainly.com/question/13721162
#SPJ11
