Apply the Pythagorean theorem to find the distance between two points in a coordinator system
Answers
Using pythagoras theorem to find the distance between two points in a coordinate:
[tex]\begin{gathered} A=(-5,5) \\ B=(-1,1) \end{gathered}[/tex][tex]\begin{gathered} A=(-5,5)\longrightarrow x_1=-5,y_1=5 \\ B=(-1,1)\longrightarrow x_2=-1,y_2=1 \\ \text{vertical line = opposite =5-1=4} \\ \text{horizontal line = adjacent = -5--1=-5+1=-4} \end{gathered}[/tex]To calculate the distance between the points AB = hypotenuse
[tex]\begin{gathered} \text{Hypotenuse}^2=opposite^2+adjacent^2 \\ AB^2=4^2+(-4)^2 \\ AB^2=16+16 \\ AB^2=32 \\ AB=\sqrt[]{32} \\ AB=4\sqrt[]{2} \end{gathered}[/tex]Therefore the distance between the points in the coordinate system = 4√2
Related Questions
3.5.3 Test (CST): Functions Does this graph show a function? Explain how you know. 66 PE -2 E C N 6 8 A. No; there are y-values that have more than one x-value. B. Yes; the graph passes the vertical line test. C. Yes; there are no y-values that have more than one x-value. D. No; the graph fails the vertical line test. here is the answer for the people who need it
Answers
Solve the following equation using the zero product property 5(-v-5)(v-8)=0
Answers
The expression to be solved is:
[tex]5\cdot(-v-5)\cdot3\cdot(v-8)\text{ = 0}[/tex]The zero product property states that the solution to this equation is the values of each term equals to 0.
[tex]\begin{gathered} (-v\text{ - 5) = 0} \\ -v\text{ = 5} \\ v\text{ = -5} \end{gathered}[/tex][tex]\begin{gathered} (v\text{ - 8) = 0} \\ v\text{ = 8} \end{gathered}[/tex]The answers are -5 and 8.
6 3/8 - 2 5/8 what is the value of this expression?A) 3B) 3 6/8C) 4 2/8D) 5
Answers
6 3/8 - 2 5/8
=4 3 - 5/8
= 3 8 + 3 - 5/8
= 3 6/8
Option B) 3 6/8
Evaluate the expression when y=5 and x=20.x - 4y
Answers
To evaluate the expression we need to replace with the given values, as follows:
x - 4y =
= 20 - 4*5 =
= 20 - 20 =
= 0
1/11 as an decimal for long division
Answers
Question: 1/11 as an decimal for long division??
Answer: 1/11 as a decimal is 0.090909090909091.
Step-by-step explanation:
÷= 1
÷=.
(×)÷= .
1÷11=0.0
(×)÷= ,,,
1÷11=0.09 , 1 . ÷=.…
÷=.
: )✨
Find loss and loss percent.
cost price = 850
selling price = €595
Answers
If sin 0
=
40/41 and lies in Quadrant I, what does tan theta equal to?
Answers
answer of this trigonometric function is 4.49
what is trigonometric function?
The trigonometric functions are real functions that connect the angle of a right-angled triangle to the ratios of its two side lengths. They are also known as circular functions, angle functions, or goniometric functions.
LETS ASSUME Given sinθ= 40/41
tan(θ)= sinθ/[tex]\sqrt{1-sin^{2} (theta) }[/tex]....(1)
putting sin theta value in (1)
⇒tan(θ)= 4.49
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Mai works a total of 31 hours per week at two jobs. The number of hours she works at a coffee stand is 5 less than 2 times the number of hours she works at the animal shelter. How many hours does Mai work at the animal shelter?
Show the equation you use and your work solving the equation.
Answers
Answer:
12
Step-by-step explanation:
Let x = number of hours at the shelter
"The number of hours she works at a coffee stand is 5 less than 2 times the number of hours she works at the animal shelter."
The number of hours at the coffee stand is
2x - 5
The total number of hours is 31, so x added to 2x - 5 must equal 31.
2x - 5 + x = 31
3x - 5 = 31
3x = 36
x = 12
She works 12 hours at the shelter.
the radius of a circle in 6 miles. what is the area of a sector bounded by a 126° arc?
Answers
The area of a sector of a circle is:
[tex]A=\pi r^2\cdot\frac{\theta}{360}[/tex]Where θ is the angle of the arc and r is the radius.
In this case,
• r = 6mi
,• θ = 126º
Then:
[tex]A=\pi(6mi)^2\cdot\frac{126}{360}=\pi\cdot\frac{36mi^2\cdot126}{360}=\frac{63}{5}\pi[/tex]Thus the correct option is the 4th one:
[tex]\frac{63}{5}\pi\text{ }mi^2[/tex]Write the following decimal number in standard form Two and four hundredths
Answers
ANSWER
[tex]The\text{ standard form of 2.04 is 2.04}\times10^0[/tex]STEP-BY-STEP EXPLANATION
We are two convert decimal numbers to standard form
Given information
Two and four hundredths
Step 1; write the above data in decimal
[tex]\begin{gathered} \text{four hundredths } \\ 4\text{ x }\frac{1}{100} \\ \frac{4}{100\text{ }}\text{ = 0.04} \end{gathered}[/tex]Step 2: Add the four hundredths to two
[tex]\text{ 2 + 0.04 = }2.04[/tex]Step 3: convert the decimal to standard form
[tex]2.04\text{ }\times10^0[/tex]Which expressions are equal to 10^5? ☐ (10^4)¹ 10³x10² 1/10^5 (10³) ² 10x10x10x10x10
Answers
Using the rule of exponents, the only expressions that are equal to 10⁵ are; 10³x10² and 10x10x10x10x10
How to use Laws of Exponents?
The laws of exponents are as follows;
1) The Product Rule for Exponents: To get the product of two numbers that have the same base, ensure you add the exponents.
2) The Quotient Rule for Exponents: To get the quotient of two numbers that have the same base, ensure that you subtract the exponent of the denominator from the exponent of the numerator.
3) The Power Rule for Exponents: To raise a number with an exponent to a power, ensure that you multiply the exponent times the power.
4) Negative Exponent Rule: Make sure to Invert the base in order to change a negative exponent into a positive.
5) Any non-zero number that is raised to the zeroth power is 1.
We want to find an expression that is equivalent to 10⁵. Thus, applying the rules of exponents above, the only one that is correct is 10 ³x 10² or 10x10x10x10x10
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Find the greatest common factor for the list of monomials. 20x4y2z, 4x4y, 60x3y3 The greatest common factor is
Answers
The monomials given are:
[tex]\begin{gathered} 20x^4y^2z \\ 4x^4y \\ 60x^3y^3 \end{gathered}[/tex]First, we will write each monomial as a product of each individual factors. So,
[tex]\begin{gathered} 20x^4y^2z=2\cdot2\cdot5\cdot x\cdot x\cdot x\cdot x\cdot y\cdot y\cdot z \\ 4x^4y=2\cdot2\cdot x\cdot x\cdot x\cdot x\cdot y \\ 60x^3y^3=2\cdot2\cdot3\cdot5\cdot x\cdot x\cdot x\cdot y\cdot y\cdot y \end{gathered}[/tex]Now, we will circle the factors/numbers that are common to all 3 monomials.
That is,
Thus, we can write the GCF as,
[tex]\begin{gathered} 2\cdot2\cdot x\cdot x\cdot x\cdot y \\ =4x^3y \end{gathered}[/tex]Error Analysis
Louie and Nicky were asked to find point P that divides the directed line segment FG so that the ratio of FP
to PG is 4 to 1. Louie says the coordinate of point P is (-4,- 4), while Nicky says the coordinate of point P
is (2, 5). Who is correct? Describe the mistake that was made by the student who was incorrect.
Answers
Using proportions, it is found that Louie is correct, while Nicky's mistake was in building the proportional equation.
What is a proportion?A proportion is a fraction of a total amount, and equations can be built to find the desired measures in the problem using operations such as multiplication and division.
The endpoints of the line segment are given as follows:
G(-6,-7) and F(4,8).
Point P divides the ratio of FP to PG is 4 to 1, meaning that the following equation is built:
P - F = 4/5(G - F)
Hence the x-coordinate of P is found as follows:
x - 4 = 4/5(-6 -4)
x - 4 = -8
x = -4.
The y-coordinate is found as follows:
y - 8 = 4/5(-7 - 8)
y - 8 = -12
y = -4.
Hence Louie is correct, while Nicky's mistake was in building the proportional equation, as he found the wrong coordinates.
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6. Mishell bought some sugar and strawberries to make strawberry jam.Sugar costs $1.80 per pound, and strawberries cost $2.50 per pound.Mishell spent a total of $19.40. Which point on the coordinate plane couldrepresent the pounds of sugar and strawberries that Mishell used to makejam?*
Answers
Okay, here we have this:
We obtain the following equation.
Let's take x as pounds of sugar, and y as pound of strawberries:
x(Sugar Costs)+y(Strawberries cost)=Total Cost
x(1.80)+y(2.50)=19.40
We are going to replace the coordinates of each point to see which one satisfies the total cost:
Point A (0,0):
x(1.80)+y(2.50)=19.40
0(1.80)+0(2.50)=19.40
0+0=19.40
0=19.40 (We can see that this equality is false, therefore the option is incorrect)
Point B (8,2):
x(1.80)+y(2.50)=19.40
8(1.80)+2(2.50)=19.40
14.4+5=19.40
19.40=19.40 (This equality is true, therefore this option may be correct, however let's analyze the rest)
Point C (6,1)
x(1.80)+y(2.50)=19.40
6(1.80)+1(2.50)=19.40
10.8+2.5=19.4
13.3=19.4 (We can see that this equality is false, therefore the option is incorrect)
Point D (7, 5)
x(1.80)+y(2.50)=19.40
7(1.80)+5(2.50)=19.40
12.6+12.5=19.40
25.1=19.4 (We can see that this equality is false, therefore the option is incorrect)
Finally we obtain that the correct answer is the Point B.
how do you solve 3/4 % of 387?
Answers
To calculate the 3/4% of 387, you have to use cross multiplication:
The fraction 3/4 can be expressed as a decimal value to make the calculations easier: 3/4=0.75
100% is 387
0.75% is x
Both relations are at the same ratio, so that
[tex]\begin{gathered} \frac{387}{100}=\frac{x}{0.75} \\ x=\frac{387}{100}\cdot0.75 \\ x=2.9025 \end{gathered}[/tex]This means that the 3/4% of 387 is 2.9025
4. The table represents a proportional relationship. Find the constant ofproportionality and write an equation to represent the relationship.aу23110103124Constant of proportionality:Equation: y =
Answers
Given the table which represents a proportional relationship
The general form for a proportional relationship is :
[tex]y=k\cdot a[/tex]Where k is the constant of the proportionality
As shown in the table :
when a = 2 , y = 2/3
And when a = 3 , y = 1
It is better to substitute with the second row
[tex]\begin{gathered} a=3\rightarrow y=1 \\ \\ 1=k\cdot3 \\ \\ k=\frac{1}{3} \end{gathered}[/tex]So, the equation will be :
[tex]y=\frac{1}{3}a[/tex]
16. Read the following passage below and solve the questions based on it.
There are seven professors P,Q,R,S,T,U and V teaching seven subjects History, Geography,
Physics, Chemistry, Maths, Biology and English from Monday to Friday at Nkrumah University.
Each professor teaches a different subject and not more than two subjects are taught on any one
of the days.
i. Chemistry is taught by professor Q on Tuesday
ii. Professor S teaches on Friday but neither Geography nor Physics
iii. Professor U teaches History but neither on Thursday nor on Friday
iv. Professor P teaches English on the day on which History is taught
v. Professor R teaches Maths on Monday
vi. Geography and Chemistry are taught on the same day
vii. Professor V teaches on Thursday
Answer the below questions:
Answers
After solving simple arithmetic we have found that, Professor V teaches physics as Professor P = English, Professor Q =Chemistry, Professor R = Maths, Professor S = Biology, Professor T= Geography, Professor U = history.
What is arithmetic?Arithmetic is the branch of mathematics concerned with the study of numbers through various operations on them. The basic operations of math are addition, subtraction, multiplication, and division.
It is said that Each professor teaches a different subject and not more than two subjects are taught on any one which means
1 teacher = 1 subject
1 day = 2 subjects
We have given that
Chemistry is taught by professor Q on Tuesday
Professor Q is Chemistry teacher
Professor S teaches on Friday but neither Geography nor Physics
Professor U teaches History but neither on Thursday nor on Friday
Professor U is History teacher
Professor P teaches English on the day on which History is taught
Professor P is English teacher
Professor R teaches Maths on Monday
Professor R is Maths teacher
Geography and Chemistry are taught on the same day
Which means geography is taught on Tuesday
Tuesday = geography and Chemistry (1 day = 2 subjects)
Professor U and Professor P teaches history and English on the same day and it is either Monday or Wednesday as Tuesday already filled and they don't teach on Thursday or Friday.
But it couldn't be Monday as Professor R teaches Maths on Monday and there could only be two subjects
So,
Wednesday = history and English (1 day = 2 subjects)
Professor S teaches on Friday but neither Geography nor Physics and other teachers are taken for Chemistry, math, English and history, so Professor S is Biology teacher
There are seven subjects and 5 days which means three subjects are learned twice at the end of the week
Mondays = Maths and 1 other subject
Tuesday = geography and Chemistry
Wednesday = history and English
Thursday = Professor V(subject) and any of the repeated subject
Friday = Biology and any of the repeated subject
As Biology is a repeated subject we can assume that it is also learned on Monday, We have found that Professor U and Professor P teaches history and English on the same day and Geography and Chemistry are taught on the same day, so the repeated subjects are neither history, English, Geography, nor chemistry.
Which means repeated subject could only be Maths, Physics and biology
But for Friday it could only be maths or physics
As Geography could only be taught on same days with chemistry it means professor T teaches geography as Chemistry is taught by professor Q on Tuesday and Geography and Chemistry are taught on the same day so Professor V wont be teaching on that Tuesday.
Thus, we have
Professor P = English
Professor Q =Chemistry
Professor R = Maths
Professor S = Biology
Professor T= Geography
Professor U = history
Professor V = ?
Only subject left is Physics
So, professor V teaches physics
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Full question
Which of the following subjects is taught by professor V?
30 cars are in a race. In how many different ways can cars finish in the top 3 positions?
Answers
Given:
There are 30 cars in a race.
The number of ways that cars finish in the top 3 positions is given as,
[tex]\begin{gathered} ^nP_r=\frac{n!}{(n-r)!} \\ n=30,r=3 \\ ^{30}P_3=\frac{30!}{(30-3)!} \\ =\frac{30!}{27!} \\ =28\times29\times30 \\ =24360 \end{gathered}[/tex]Answer: There are 24360 ways that cars finish in the top 3 positions.
-
g+3 1/2=10 answer to g
Answers
Answer:
Exact form: G = 12/2
decimal form: G = 6.5
Slope: -1
Point 3,-5
Answers
y=-x-2
Slope is -1
y intercept is -2
Define an exponential function, h(x), which passes through the points (1,16) and(5, 1296). Enter your answer in the form a*b^xh(x) =
Answers
We want the answer in exponential form:
[tex]h(x)=a\cdot b^x[/tex]where a and b are the constants to be determined. We can find a and b by substituting the given points and construct a system of equatons, that is, by replacing point (1,16) we have
[tex]\begin{gathered} 16=a\cdot b^1 \\ so \\ 16=a\cdot b \end{gathered}[/tex]and by substituting point (5,1296), we get
[tex]1296=a\cdot b^5[/tex]Then, we have 2 equations in 2 unknonws:
[tex]\begin{gathered} a\mathrm{}b=16 \\ a\mathrm{}b^5=1296 \end{gathered}[/tex]By isolating a from the first equation and substituting this result into the second one, we get
[tex]\begin{gathered} (\frac{16}{b})b^5=1296 \\ \end{gathered}[/tex]which gives
[tex]\begin{gathered} 16b^4=1296 \\ b^4=\frac{1296}{16} \\ b^4=81 \\ b=\sqrt[4]{81} \\ b=3 \end{gathered}[/tex]Then, by substituting this result into the first equation of our system, we obtain
[tex]\begin{gathered} a\cdot3=16 \\ \text{then} \\ a=\frac{16}{3} \end{gathered}[/tex]Therefore, the answer is
[tex]h(x)=\frac{16}{3}\cdot(3)^x[/tex]Consider the following graph of two functionsStep 2: Find (g-f)(-5)Step 3: Find (g.f)(1)Step 4: Find (f/g)(-3)
Answers
Answer:
• (g-f)(-5)=16
,• (g.f)(-1)=-16
,• (f/g)(-3)=-1
Explanation:
Given the graph of f(x) and g(x):
Part 2
• When x=-5, f(x)=-8.
,• When x=-5, g(x)=8
Thus:
[tex]\begin{gathered} f(-5)=-8 \\ g(-5)=8 \end{gathered}[/tex]The composition of the functions:
[tex]\begin{gathered} (g-f)(-5)=g(-5)-f(-5) \\ =8-(-8) \\ =8+8 \\ \implies(g-f)(-5)=16 \end{gathered}[/tex]The answer is 16.
Part 3
• When x=1, f(x)=4.
,• When x=1, g(x)=-4
Therefore:
[tex]\begin{gathered} f(1)=4 \\ g(1)=-4 \\ \implies(g\cdot f)(-1)=(g)(-1)\cdot(f)(-1) \\ =-4\times4 \\ =-16 \end{gathered}[/tex]The answer is -16.
Part 4
• When x=-3, f(x)=-4.
,• When x=-3, g(x)=4
Therefore:
[tex]\begin{gathered} f(-3)=-4 \\ g(-3)=4 \end{gathered}[/tex]The composition is calculated below:
[tex](\frac{f}{g})(-3)=\frac{f(-3)}{g(-3)}=-\frac{4}{4}=-1[/tex]The answer is -1.
help me please
thank you
Answers
Answer:
Domain: [tex](-\infty, \infty)[/tex]
Range: [tex](-\infty, 4][/tex]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
If y varies jointly as x and z when x = 5, y = 80, and z = 8. what is y when x = 16 and z = 2?
Answers
We are given that y varies jointly as x and z
Mathematically,
[tex]y=kxz[/tex]Where k is the constant of proportionality.
When x = 5, y = 80, and z = 8
[tex]\begin{gathered} y=kxz \\ 80=k\cdot5\cdot8 \\ k=\frac{80}{5\cdot8} \\ k=2 \end{gathered}[/tex]So, the relationship becomes
[tex]y=2xz[/tex]What is y when x = 16 and z = 2?
[tex]\begin{gathered} y=2xz \\ y=2\cdot16\cdot2 \\ y=64 \end{gathered}[/tex]Therefore, the value of y is 64
Salary 75000Salary increase to 81000 in 4 years Future earnings in any given year y= Toms salary X=number of years worked Use the data given to find the rate of Chamorro the salary increase per year Use the data given and the slope value from step 1 to write the slope intercept form of the lineBased on your equation from step 2 what will Toms salary be in Ten years?
Answers
Given that Tom's initial salary is;
[tex]y_0=\text{ \$}75000[/tex]In four years the salary increases to;
[tex]y_4=\text{ \$}81000[/tex]The rate at which his salary increase per year is;
[tex]\begin{gathered} m=\frac{y_4-y_0}{4}=\frac{81000-75000}{4}=\frac{6000}{4} \\ m=1500 \end{gathered}[/tex]The rate at which his salary increase per year is;
[tex]\text{ \$}1500\text{ per year}[/tex]Using the given initial salary and the slope(rate) abo
subtract P - 2 q + r from the sum of 10 P - R and 5 p + q
Answers
Answer:
14p +4q-2r
Step-by-step explanation:
Sum of (10p-r+5p+2q)
10p+5p+2q-r
15p+2q-r
Now subtract( p-2q+r) from (15p+2q-r)
(15p+2q-r) - (p-2q+r)
15p+2q-r-p+2q-r
15p-p+2q+2q-r-r
14p +4q-2r
The answer is 14p +4q-2r
First Drop down: Yes or NOSend drop down: is or is not
Answers
Looking at the number line, the length between 0 and 1 is not divided into 3 equal parts. Hence, the answer is no. Victoria is not correct.
First drop-down: No
Second drop-down: is not
You spin a spinner with 5 sections: 1 yellow (Y), 1 purple (P), 1red (R), 1 blue (B), and 1 green (G).What is the sample space for one spin of this spinner?
Answers
Given:
The spinner has five sections that are 1 yellow (Y), 1 purple (P), 1 red (R), 1 blue (B), and 1 green (G).
Required:
We need to find the sample space for one spin of the given spinner.
Explanation:
The sample space = the collection of all sections of the spinner.
[tex]S=\lbrace\text{ yellow, purple, red, blue, green \textbraceright}[/tex][tex]S=\lbrace\text{ Y, P, R, B, G\textbraceright}[/tex]Final answer:
[tex]\lbrace\text{ Y, P, R, B, G\textbraceright}[/tex]Option D is correct.
Please help and provide explanation I want to understand this!
Answers
We will have to find the equation that follows the form:
[tex]a+bx=y[/tex]That is:
*The value of a is:
[tex]a=547.4666667[/tex]*The value of b is:
[tex]b=29.91428571[/tex]So, the linear regression is:
[tex]y=29.91428571x+547.4666667[/tex]We can see it graphically as follows:
Here we can see the linear regression line and the points used.
***How to manually determine linear regressions***
We will start as follows:
We will have to use the following expressions in order to manually find the linear regression:
[tex]b=\frac{n(\sum^{}_{}xy)-(\sum^{}_{}x)(\sum^{}_{}y)}{n(\sum^{}_{}x^2)-(\sum^{}_{}x)^2}[/tex]And:
[tex]a=\frac{\sum ^{}_{}y-b(\sum ^{}_{}x)}{n}[/tex]Here we have that n is the number of values on the dataset. So, we solve for b as follows [Based on the problem given]:
*We will determine the values of n, the sum of x, the sum of y, xy, x^2 & y^2 as follows:
Sum of x:
[tex]\sum ^{}_{}x=1+2+3+4+5+6\Rightarrow\sum ^{}_{}x=21[/tex]Sum of y:
[tex]\sum ^{}_{}y=588+298+640+650+707+730\Rightarrow\sum ^{}_{}y=3913[/tex]Value of n: We have that the number of datasets given is 6 [6 pairs of values on the table].
[tex]n=6[/tex]*The sum of xy:
[tex]\sum ^{}_{}xy=(1)(588)+(2)(598)+(3)(640)+(4)(650)+(5)(707)+(6)(730)\Rightarrow\sum ^{}_{}xy=14219[/tex]*The sum of X^2:
[tex]\sum ^{}_{}x^2=1^2+2^2+3^2+4^2+5^2+6^2\Rightarrow\sum ^{}_{}x^2=91[/tex]*The square of the sum of x:
[tex](\sum ^{}_{}x)^2=21^2\Rightarrow(\sum ^{}_{}x)^2=441[/tex]Now that we have all the values, we replace in the first equation and solve for b:
[tex]b=\frac{(6)(14219)-(21)(3913)}{(6)(91)-(441)}\Rightarrow b=29.91428571[/tex]And we solve now for a:
[tex]a=\frac{(3913)-(29.91428571)(21)}{(6)}\Rightarrow a=548.4666667[/tex]And then we simply replace on the expression:
[tex]y=bx+a[/tex]And the expression after the replacement of a & b is the linear regression.
Mike read of a novel. Katy read as much of the same novel as Mike. How much of the novel did Katy read?
What type of comparison is shown in the question above?
A.
additive comparison
B.
multiplicative comparison
Answers
The type of comparison shown is multiplicative comparison.
As the number of novel increase in the case of Mike, the number for Katy will also increase simultaneously.
For example, if the novel read count for Mike is 3 then the novel read count for Katy will be also 3.
Additive comparison defines a relationship between two quantities by specifying or saying how much greater or less one is than the other.
Multiplicative Compare - compares two values and multiplies one by a specified number to get the other.
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