a. The z-score is approximately 0.43.
Draw the Normal curve and shade the area to the left of the z-score.
b. The corresponding z-score is approximately -1.10.
Draw the Normal curve and shade the area to the left of the z-score.
A standard Normal distribution means that we have a bell-shaped curve with a mean of 0 and a standard deviation of 1. A Normal curve, we can use a graphing calculator or a standard Normal distribution table.
a. The z-score that gives a left area of 0.6768, we need to look up the value in the Standard Normal distribution table. A printed table or an online calculator to find that the z-score is approximately 0.43.
Draw the Normal curve and shade the area to the left of the z-score.
b. To find the z-score that gives a left area of 0.1332, we can again use the Standard Normal distribution table.
This time, we look up the area that corresponds to 0.1332 and find that the closest value is 0.1335.
The corresponding z-score is approximately -1.10.
We can then draw the Normal curve and shade the area to the left of the z-score.
To draw a well-labeled Normal curve for each part, we first need to find the corresponding z-score using a Standard Normal distribution table.
The z-score to shade the area to the left of the curve and label the mean and standard deviation on the x-axis.
Drawing the Normal curve helps us visualize the distribution and calculate probabilities for various events.
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In a population, µY = 100 and σ2Y = 43. Use the central limit theorem to answer the following questions. A. In a random sample of size n = 100, find Pr(Ӯ <101). B. In a random sample of size n = 64, find Pr(101< Ӯ <103). C. In a random sample of size n = 165, find Pr(Ӯ >98)
So for the population which is normally distributed using central limit theorem we get,
(A) For sample size n = 100, Pr(Ӯ <101) = 0.937.
(B) For random sample size n = 64, Pr(101< Ӯ <103) = 0.110.
(C) For sample size of n = 165, Pr(Ӯ >98) = 0.893
Given that the population mean (µY) = 100 and the population standard deviation σ2Y = 43.
For the sample size of n = 100.
Now the sample mean (Ӯ) = µY = 100 also.
The sample standard deviation (σ) = square root of (σ2Y/n) = square root of (43/100) = square root of (0.43) = 0.66 (Rounding off to two decimal places).
Now, (101 - Ӯ)/σ = (101 - 100)/0.66 = 1.53
From the normal distribution table we can find P(Z < 1.53) = 0.937 (approximately).
Hence, Pr(Ӯ < 101) = 0.937 (approximately).
For random sample size n = 64.
sample standard deviation = (σ) = square root of (σ2Y/n) = square root of (43/64) = 0.82
Now,
(101 - 100)/0.82 = 1.22
(103 - 100)/0.82 = 3.66
From standard normal table we can get,
P(Z < 3.66) = 0.999
P(Z < 1.22) = 0.889
So, P(1.22 < z < 3.66) = 0.999 - 0.889 = 0.110
Hence, Pr(101< Ӯ <103) = 0.110.
Again for sample size of n = 165.
Sample standard deviation = square root of (σ2Y/n) = square root of (43/165) = 0.51
Now,
(98 - 100)/0.51 = - 1.24
From the standard normal distribution table we get, P(Z < - 1.24) = 0.107.
Now, Pr(Ӯ >98) = 1 - Pr(Ӯ < 98) = 1 - 0.107 = 0.893.
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which phrase best describes the relationship between the number of miles driven and the amount of gasoline used?
The phrase that best describes the relationship between the number of miles driven and the amount of gasoline used is "correlated, but not causal." So, the correct answer is B).
While there is a clear correlation between the number of miles driven and the amount of gasoline used (i.e., as the number of miles driven increases, the amount of gasoline used generally increases), this relationship is not necessarily causal.
There may be other factors at play, such as the efficiency of the vehicle, driving habits, and road conditions, that can affect the amount of gasoline used. Therefore, while the two variables are clearly related, it cannot be concluded that one variable causes the other. So, the correct option is B).
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--The given question is incomplete, the complete question is given
" Which phrase best describes the relationship between the number of miles driven and the amount of gasoline used?
A) causal, but not correlated
B) correlated, but not causal
C) both correlated and causal
D) neither correlated nor causal"--
A bag contains the following marbles: 12 blue marbles, 10 red marbles, and 8 green marbles. Whenever a marble is selected at random, it is then returned to the bag. Find the following probabilities
P(-green)
0 0. 45
O 0. 73
O 0. 27
O 22
Answer:
0.27
Step-by-step explanation:
Probability of picking a green is 0.27 (t nearest hundredth).
Use the distributive property to rewrite the expression as a multiple of a sum of two numbers with no common factor. 18+30 ( I will give brainliest to whoever answers correctly)
The equivalent expression of 18 + 30 using distributive property is 6(3) + 6(5)
What are the distribution of the numbers?The distributive property states that for any numbers a, b, and c, a multiplied by (b+c) equals a multiplied by b plus a multiplied by c.
a(b + c) = a(b) + a(c)
The prime factor of 18 + 30 is written as;
18 + 30 = 2 x 3 x 3 + 2 x 3 x 5
18 + 30 = 2 x 3 x (3 + 5)
Simplifying the expression inside the parentheses gives:
2 x 3 x (3 + 5) = 6 (3 + 5)
applying distributive property we will have;
6 (3 + 5) = 6(3) + 6(5)
Thus, the final expression is; 18 + 30 = 6(3) + 6(5)
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Help I don't understand.
Answer:
On x < -5, the function is increasing.
Fill in the missing numbers for 6x-10y=-8 and 6x-5y=2 by using elimination.
if i was helpful Brainliests my answer ^_^
The percentage, P(t), of information memorized by Bridget is a function of the time, t,
in minutes, of the length of a lecture.
P(t) = t-t²
50
Bridget's friend wanted to determine the percentage memorized at various times and
evaluated the four values: P(40), P(50), P(60), P (70).
During what length of a lecture did Bridget memorize the most information?
40 min
O 50 min
60 min
O 70 min
Answer:
P(40) = 64, P(50) = 70, P(60) = 72,
P(70) = 70
60 minutes is correct.
(L7) A Pythagorean Triple is a set of three nonzero positive _____ numbers, a,b, and c, such that a²+b²=c².
A Pythagorean Triple is a set of three integers that are positive whole numbers, namely a, b, and c, such that a²+b²=c².
A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c), and a well-known example is (3, 4, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any positive integer k. A primitive Pythagorean triple is one in which a, b and c are coprime (that is, they have no common divisor larger than 1). For example, (3, 4, 5) is a primitive Pythagorean triple whereas (6, 8, 10) is not. A triangle whose sides form a Pythagorean triple is called a Pythagorean triangle, and is necessarily a right triangle
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The table shows the possible outcomes of spinning a fair spinner twice with sections labeled A, B, C, and D.
AB
А
CD
с
A
A, A
B, A
C, A
D, A
B
A, B
B, B
C, B
D, B
Match the situation with its probability.
Spinner landing on at least one A
Spinner landing on C and D in any order
Spinner landing on two Bs
Spinner landing on C on the second spin
с
A, C
B, C
C, C
D, C
16
ロ
0
0
O
0
D
A, D
B, D
C, D
D, D
1
0
0
0
16
0
The correct matches for the probabilities are:
Spinner landing on at least one A is 7/16Spinner landing on C and D in any order 1/8Spinner landing on two Bs is 1/16Spinner landing on C on the second spin 1/4What are the probabilities?The probabilities are calculated based on the result of the spin.
The results of the spin;
A, A
A, B
A, C
A, D
B, A
B, B
B, C
B. D
C, B
C, C
C, D
D, B
D, C
D, D
The probabilities are as follows:
Spinner landing on at least one A is 7/16 since there are 7 out of 16b options having an A.
Spinner landing on C and D in any order 1/8 since there are 2 such occurrences out of 16.
Spinner landing on two Bs is 1/16 since there is 1 such occurrence out of 16.
Spinner landing on C on the second spin 1/4 since there are 4 such occurrences out of 16.
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The article referenced in this lesson also stated that the pig landed on its right side lesson also stated that the pig landed on its right side 4,172 times out of 11,954 tosses. You will construct a 90% confidence interval for the population proportion of tosses of a plg die in which the pig lands on A Are the criteria for approximate normality met? es of a pig die in which the pig lands on its right side. B Find the sample proportion and the critical value: 0571 and Z= C Find the estimated standard error, SA, and compute the margin of error, m. 0349U-2349) = 0,004 11,954 m=2 si: 2x 0,004 -0.008 D Find the 90% confidence interval. Provide an interpretation of the confidence interval in context of this problem. E Would you support the claim that 33% of all tosses have the pig landing on its right side? Explain your reasoning. F What is the best way to decrease the margin of error and create a more precise estimate for the population proportion? Why would you want a smaller margin of error? G If you were to compute the 99% confidence interval, would it be wider or narrower than the 90% confidence interval? Explain briefly.
To determine if the criteria for approximate normality is met, we need to check if both the sample size and sample proportion are large enough. The sample size is n = 11,954 which is greater than 10.
Additionally, the sample proportion of landing on its right side is p = 0.571 which is also greater than 10. Therefore, the criteria for approximate normality is met.
A 99% confidence interval would be wider than the 90% confidence interval. This is because a higher confidence level requires a larger range to ensure the true population proportion is captured within the interval with a higher degree of certainty.
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Pls help me I am stuck I. This question
The pocket money that Sam had to start with is: £24
How to solve Fraction Word Problems?Let the amount of money he had at the beginning be x.
He spent 1/4 of the money on magazines. Thus:
Amount left = ³/₄x
He spent ²/₃ of what he had left on a present. Thus< he spent:
²/₃ * ³/₄x = ¹/₂x
Amount left = ³/₄x - ¹/₂x
He had £6 left. Thus:
³/₄x - ¹/₂x = 6
9x - 6x = 72
3x = 72
x = £24
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Find the mean for the number of yards gained by Roger during his seven carries in thefootball game: {2, 6, 20, 11, 8, 12, 4}.A 08B 09C 63D 07
The answer is option B) 09. To find the mean (average) of the yards gained by Roger during his seven carries, we need to add up all the yards gained and divide the sum by the number of carries.
So, for the given data set {2, 6, 20, 11, 8, 12, 4}, the total yards gained is:
2 + 6 + 20 + 11 + 8 + 12 + 4 = 63
The number of carries is 7.
Therefore, the mean yards gained per carry is:
Mean = Total yards gained / Number of carries
= 63 / 7
= 9
Hence, the answer is option B) 09.
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"The Centers for Disease Control lists causes of death in the United States during 2011. Cause of Death Percent
Heart disease 23.7
Cancer 22.9
Circulatory diseases and stroke 5.1
Respiratory diseases 5.7
Accidents 5.0
a) Is it reasonable to conclude that heart or respiratory diseases were the cause of approximately 29% of U.S. deaths in 2011?
A. No, because there is the possibility of overlap.
B. Yes, because there is the possibility of overlap.
C. No, because there is no possibility for overlap.
D. Yes, because there is no possibility for overlap
The answer to this question is A. It is not reasonable to conclude that heart or respiratory diseases were the cause of approximately 29% of U.S. deaths in 2011 because there is a possibility of overlap.
This means that some people who died from heart disease may have also had respiratory diseases, and vice versa.
Therefore,
It is impossible to accurately determine the exact percentage of deaths caused by each individual disease.
It is important to note that the Centers for Disease Control lists the causes of death in the United States as the underlying cause, which is defined as the disease or injury that initiated the train of events leading directly to death.
However,
Many people who die from one disease may also have other underlying or contributing conditions.
This makes it difficult to determine the exact cause of death in some cases.
There could be potential overlap between heart and respiratory diseases, it is not reasonable to conclude that heart or respiratory diseases were the cause of exactly 29% of U.S. deaths in 2011.
In summary,
While heart and respiratory diseases were listed as the cause of a significant percentage of deaths in the United States in 2011, it is not accurate to conclude that they were the sole cause of approximately 29% of deaths due to the possibility of overlap.
It is important to consider all contributing factors when analyzing causes of death data.
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If a bat catches a total of 560 bugs in 7 nights, and each night the bat catches the same number of bugs, how many bugs did the bat catch on the fifth night?
Answer:
400
Step-by-step explanation:
get the number of bugs caught in night and multiply it by five
Is it true that If A is invertible, then detA^−1 = det A.
Yes,
It is true that if A is invertible, then det(A⁽⁻¹⁾) = det(A).
The determinant of a matrix and its inverse are closely related.
The determinant of a matrix is nonzero, then the matrix is invertible, and its inverse has the same determinant as the original matrix.
The following properties of determinants:
det(AB) = det(A)det(B) for any square matrices A and B
If A is invertible, then det(A⁽⁻¹⁾) = 1/det(A)
Using these properties, we can write:
det(A⁽⁻¹⁾) = det(A⁽⁻¹⁾)det(AI) = det(A⁽⁻¹⁾A) = det(I) = 1
And:
det(A) = det(AA⁽⁻¹⁾) = det(A)det(A⁽⁻¹⁾)
Multiplying both sides by det(A⁽⁻¹⁾), we get:
det(A)det(A⁽⁻¹⁾) = det(A⁽⁻¹⁾)det(A⁽⁻¹⁾) = det(A⁽⁻¹⁾)det(A)
det(A⁽⁻¹⁾) = det(A).
The determinant of a matrix and its inverse are closely related.
The determinant of a matrix is nonzero, then the matrix is invertible, and its inverse has the same determinant as the original matrix.
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for which of the following is frequency analysis not useful? group of answer choices locating outliers. determining the degree of item nonresponse. understanding the relationships among multiple variables. analyzing categorical and continuous variables.
Frequency analysis is not useful for understanding the relationships among multiple variables.
Frequency analysis is a statistical technique that involves counting the frequency of each value or category within a dataset. It is useful for analyzing categorical and continuous variables and determining the degree of item nonresponse. It can also help in locating outliers, as the frequencies of unusual values can be easily identified.
However, frequency analysis alone cannot provide insights into the relationships among multiple variables, as it only focuses on the distribution of individual variables. To understand the relationships among variables, more advanced statistical techniques such as correlation analysis or regression analysis need to be employed.
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which communication contrast is accurate? multiple choice only 10% of native-born americans speak a second language; 56% of european union citizens speak a second language. most native-born americans speak a second language, while few european union citizens speak a second language. less than 1% of native-born americans speak a second language; 76% of european union citizens speak a second language. at least half of native-born americans speak a second language, while about one-fourth of european union citizens speak a second language. almost all native-born americans speak a second language, while only a few european union citizens speak a second language.
the correct answer is: Only 10% of native-born Americans speak a second language; 56% of European Union citizens speak a second language.
The accurate communication contrast is:
Only 10% of native-born Americans speak a second language; 56% of European Union citizens speak a second language.
what is communication?
Communication refers to the exchange of information, ideas, thoughts, and messages between two or more individuals or groups. It involves the transmission and reception of messages through various channels, including verbal, nonverbal, and written modes. Effective communication requires the ability to express oneself clearly and listen actively to others, understand their perspectives, and respond appropriately.
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Okay so out of these estimated solutions which ones correct? PLEASE THIS IS MY FINAL HELP! 50 POINTS! THE IMAGE IS BELOW THIS!
Answer:
The answer is D!!!
Step-by-step explanation:
x=-7/5,=8/5 or (x=-1 2/5,y= 1 3/5) D one -7/5 = 1 2/5. 8/5 = 1 3/5
D IS THE CORRECT ANSWER
In robust optimization, a constraint that cannot be violated is known as a
a. optional constraint
b. soft constraint
c. hard constraint
In robust optimization, a constraint that cannot be violated is known as a hard constraint.
Hard constraints must be satisfied by any feasible solution to the optimization problem, while soft constraints are allowed to be violated, but at a cost. Optional constraints are constraints that can be included or excluded from the problem formulation depending on the specific needs of the application.
On the other hand, optional constraints or soft constraints are those that can be violated to some extent without significantly affecting the overall objective of the optimization problem. Soft constraints are used to express preferences or goals that are desirable but not strictly necessary for the problem to be solved.
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Identify the test statistic for this hypothesis test.The test statistic for this hypothesis test is(Round to two decimal places as needed.)Identify the P-value for this hypothesis test.The P-value for this hypothesis test is(Round to three decimal places as needed.)Identify the conclusion for this hypothesis test.A.Reject Upper H 0. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.B.Fail to reject Upper H 0. There is sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.C.Fail to reject Upper H 0. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.D.Reject Upper H 0. There is sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.
A. Reject Upper H0. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.
B. Fail to reject Upper H0. There is sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.
C. Fail to reject Upper H0. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.
D. Reject Upper H0. There is sufficient evidence to warrant support of the claim that more than 20% of users develop nausea.
The test statistic for this hypothesis test is the difference between the sample proportion and the hypothesized proportion. In this case, the hypothesis is that more than 20% of users develop nausea, and the sample proportion is the proportion of users who reported nausea in the sample.
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PLEASE HELP ME I AM GROUNDED AND NEED THIS FINISHED NOWWW
Answer:
x = 8
Step-by-step explanation:
-4x + 10 = -2x - 6
-4x + 2x = -6 - 10 (Calculate)
-2x = -16 (Divide both sides by -2)
x = 8
Have a nice day! :D
Answer:
x=8
Step-by-step explanation:
-4x+10=-2x-6 original equation
-4x+16=-2x add 6 both sides
16=2x add 4 both sides
x=8 divide 2 both sides
Which expressions are equivalent to 6 +(–x) + 2x + (–7) + 2x? Check all that apply.
A. x + x + 6 – 7 + x
B. 2x + 2 + x
C. 3 – x + 2x – 4 + 2x
D. x – 1
E. x + 1
(The answer is A and C)
The expressions are equivalent to the given expression are x + x + 6 – 7 + x and 3 – x + 2x – 4 + 2x. Therefore, the options A and C are correct answer.
The given expression is 6+(-x)+2x+(-7)+2x.
If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.
Here, group the like terms, we get
(-x+2x+2x)+(6-7)
= 3x-1
Therefore, the options A and C are correct answer.
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Answer:
yo
Step-by-step explanation:
the answers are A and C
x + x + 6 – 7 + x and 3 – x + 2x – 4 + 2x
Edge 2023
The height of an amusement park ride is 157.5 feet. If the ride's shadow is 60 feet long, how long will a person's shadow be if the person is 5.3 feet tall?
Answer
2.019 ft
Step by step explanation
divide the product of the man's height and the shadow of the ride with the height of the ride
The middle of {1, 2, 3, 4, 5} is 3. The middle of {1, 2, 3, 4} is 2 and 3. Select the true statements (Select ALL that are true)
An even number of data values will always have one middle number.
An odd number of data values will always have one middle value
An odd number of data values will always have two middle numbers.
An even number of data values will always have two middle numbers.
Answer:
An odd number of data values will always have one middle value
B, D
Step-by-step explanation:
123
2
12345
3
1234567
4
ALWAYS
What is the solutioWhat is the solution set to log(x + 7) > log3x?
n set to log(x + 7) > log3x?
Answer:
[tex] log(x + 7) > log(3x) [/tex]
[tex]x + 7 > 3x[/tex]
[tex]7 > 2x[/tex]
[tex]0 < x < 3.5[/tex]
{x | x > 0 and x < 3.5}
A bag contains 9 red balls numbered 1, 2, 3, 4, 5, 6, 7, 8, 9 and 6 white balls numbered 10, 11, 12, 13, 14, 15. One ball is drawn from the bag. What is the probability that the ball is white, given that the ball is odd-numbered? (Enter your probability as a fraction.)
The probability of drawing a white ball given that the ball is odd-numbered is 1/3.
We have,
There are a total of 15 balls in the bag, out of which 6 are white and odd-numbered.
To find the probability of drawing a white ball given that it is odd-numbered, we need to use conditional probability.
Let A be the event that the ball is white and B be the event that the ball is odd-numbered.
Then, we need to find P(A|B), the probability of A given B.
We know that P(B), the probability of drawing an odd-numbered ball, is:
P(B) = number of odd-numbered balls / total number of balls
= 9 / 15
= 3 / 5
We also know that P(A and B), the probability of drawing a white odd-numbered ball, is:
P(A and B) = number of white odd-numbered balls / total number of balls
= 3 / 15
= 1 / 5
Using the formula for conditional probability, we have:
P(A|B) = P(A and B) / P(B)
= (1/5) / (3/5)
= 1/3
Therefore,
The probability of drawing a white ball given that the ball is odd-numbered is 1/3.
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A new credit card holder must decide between two credit cards. The first card offers a current APR of 14.99%. The second card has a current daily periodic interest rate of 0.038%. Which card would be the better choice?
The first card is the better choice because the daily periodic interest on the first card is 0.038%, compared to 0.041% on the second card.
The first card is the better choice because the daily periodic interest on the first card is 0.041%, compared to 0.038% on the second card.
The second card is the better choice because the daily periodic interest on the first card is 0.038%, compared to 0.041% on the second card.
The second card is the better choice because the daily periodic interest on the first card is 0.041%, compared to 0.038% on the second card.
Answer:
The answer to your problem is, D. The second card is the better choice because the daily periodic interest on the first card is 0.041%, compared to 0.038% on the second card.
Step-by-step explanation:
Our daily periodic rate is = [tex]\frac{APR}{365}[/tex] %
For the first card it can be represented as, ( daily periodic rate equaling )
[tex]\frac{14.99}{365}[/tex] = 0.041%.
For the second it can be represented as, ( daily periodic rate equaling )
0.038%. We know because it can be given.
Compare them; 0.041% > 0.038% ( by 0.003% )
Making Option D correct.
Thus the answer to your problem is, D. The second card is the better choice because the daily periodic interest on the first card is 0.041%, compared to 0.038% on the second card.
Calcula el valor de la hipotenusa de un triangulo rectangulo de catetes 32 y 24
De acuerdo con la información, podemos inferir que el valor de la hipotenusa es 40.
¿Cómo calcular el valor de la hipotenusa?Para calcular el valor de la hipotenusa de este triángulo debemos utilizar el Teorema de Pitágoras. Entonces, debemos aplicar esta fórmula:
a² + b² = c²En este caso, el valor de a sería 32, el valor de b sería 24. Una vez remplazamos los valores debemos solucionar la fórmula para hallar el valor de c (hipotenusa):
32² + 24² = c²c = 40Entonces podemos inferir que 40 es el valor de la hipotenusa de este triángulo.
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Determine whether the sequence is divergent or convergent. If it is convergent, evaluate its limit.
(If it diverges to infinity, state your answer as inf . If it diverges to negative infinity, state your answer as -inf . If it diverges without being infinity or negative infinity, state your answer as div ) limnâ[infinity](â1)nsin(11/n)
According to the given information, the sequence is divergent.
What is the convergence and divergence of the sequence?
Convergence: A sequence approaches a fixed number as the number of terms increases.
Divergence: A sequence does not approach a fixed number as the number of terms increases.
We can use the limit comparison test to determine the convergence/divergence of the sequence.
Let's consider the sequence bₙ = 1/n. We know that lim[n→∞] (1/n) = 0, and since sin(x) is a bounded function, we have |sin(11/n)| ≤ 1 for all n. Therefore,
0 ≤ |(−1)ⁿ sin(11/n)|/bₙ = |(−1)ⁿ sin(11/n)|n → 0
As a result, we can apply the limit comparison test with bₙ = 1/n. Since the series ∑ 1/n diverges (i.e., harmonic series), we conclude that the original series ∑ (−1)ⁿ sin(11/n) also diverges.
Therefore, the sequence is divergent.
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D
0
Find the composition of
transformations that
map ABCD to EHGF.
Reflect over the [? ]-axis,
then translate
(x+y+[]).
Note: teror y for axis.
The composition of transformations that map ABCD to EHGF are:
Reflect over the x-axis, then translate (x + 3, y + 1)
What is a reflection over the x-axis?In Mathematics and Geometry, a reflection over or across the x-axis is represented by this transformation rule (x, y) → (x, -y).
By applying a reflection over the x-axis to coordinate A of the image ABCD, we have the following:
(x, y) → (x, -y)
Coordinate A = (-5, 2) → Coordinate A' = (-5, -(2)) = (-5, -2).
Furthermore, the transformation rule for the translation of a point by h units right and k units up is given by;
A' (x + h, y + k) → E(x', y')
A' (-5 + h, -2 + k) → E(-2, -1)
-5 + h = -2
h = 3
-2 + k = -1
k = 1
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