Answer:
To solve this problem, we can use the formula:
q = -Ccalorimeter x ΔT
where q is the heat absorbed by the calorimeter, Ccalorimeter is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.
First, we need to calculate the amount of heat released by the combustion of diborane. We can use the molar mass of diborane to convert the given mass to moles:
moles of diborane = 0.491 g / 27.66 g/mol = 0.01775 mol
The heat released by the combustion of 1 mole of diborane is -1958 kJ, so the heat released by the combustion of 0.01775 mol is:
q = 0.01775 mol x (-1958 kJ/mol) = -34.76 kJ
The negative sign indicates that heat is released by the reaction.
Now we can use the formula above to find the change in temperature of the calorimeter:
-34.76 kJ = -7.854 kJ/°C x ΔT
ΔT = 4.43°C
Therefore, the final temperature of the calorimeter is 19.63°C - 4.43°C = 15.20°C.
Which is one way that spring tides are different from regular tides?
Answer:
high tides are a little higher and low tides are a little lower than average
Explanation:
A spring tide is the highest tide (when the greatest difference between the high and low tides). This happens during the new and full moon.
Answer: It's worth noting that low tides can sometimes be lower than usual, which is referred to as spring tides. Despite its name, this phenomenon isn't related to spring and has a different historical origin.
Which equation represents a redox reduction
An oxidation-reduction reaction will have 2 half reactions in which the different molecules involved in the reaction are gaining or losing electrons.
For example, if our reaction was x 2+ + y --> x + y 2+, x is being reduced and y is being oxidized. Our half reactions will be:
x 2+ + 2e 1- --> x
y --> y 2+ + 2e 1-
When mixing a strong base and strong acid together, the net ionic equation will be H₃O⁺(aq) + OH⁻(aq) → 2H₂O(l).
which of the statements about light is false?
a. light travels through space at a speed of 3.00 x 10^8m/s
b. light travels much faster than sound
c. a pack of light energy is called a photon
d. a characteristic feature of light the determined its color is its wavelength
e. all of the above statements are true
The false statement about light is:
e. all of the above statements are true.
Properties of lightThe speed of light in a vacuum is constant at approximately 3 00 x 10 8 m/s
light does travel much faster than sound which has a speed of around 343 meters per second
a photon is a packet of light energy and the energy of a photon is proportional to its frequency the wavelength of light is
a characteristic feature that determines its color therefore statements a b c and d are true
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At 7:00 A.M., a patient receives a 1.00-mg dose of I-131 to treat thyroid cancer.
If the nuclide has a half-life of 8.0 days, what mass of the nuclide remains in the patient at 10:00 P.M. the next day? (Assume no excretion of the nuclide from the body.)
Approximately 0.874 mg of I-131 remains in the patient's body at 10:00 P.M. the next day.
First, we need to calculate how many half-lives have elapsed from 7:00 A.M. to 10:00 P.M. the next day, which is approximately 33 hours.
33 hours / 24 hours per day = 1.375 days
1.375 days / 8.0 days per half-life = 0.172
This means that approximately 0.172 half-lives have elapsed since the initial dose.
Next, we can calculate the fraction of I-131 that remains in the patient's body using the radioactive decay equation:
[tex]fraction\ remaining = (1/2)^{(number\ of\ half-lives\ elapsed)}[/tex]
[tex]fraction\ remaining = (1/2)^{0.172}\\fraction\ remaining = 0.874[/tex]
Finally, we can calculate the mass of I-131 that remains in the patient's body:
mass remaining = initial mass x fraction remaining
mass remaining = 1.00 mg x 0.874
mass remaining = 0.874 mg
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Classify the following rocks as either foliated or nonfoliated quartile, schist.
Answer:
d. quartzite
Explanation:
All the other rocks have a planar texture except for quartzite which is hard as a single quartz crystal and is difficult to crush or break. That is the picture of a quartz
air contains O2N2Co2 and other gasses what is the partial pressure of N2 at 101.3kpa if the partial pressure of O2 is 75.1kpa and Co2 is 21.22kpa and the trace gasses are 0.04kpa
The partial pressure of the nitrogen gas from the calculation is 4.94 kPa
What is partial pressure of a gas?When all other gases in a mixture are held constant, a gas's partial pressure is the pressure it exerts on its own. It is calculated by dividing the total pressure of the gas mixture by the percentage of the mixture's total volume occupied by the specific gas.
Partial pressure of nitrogen = Total pressure - (Partial pressure of carbon dioxide + Partial pressure of oxygen + Partial pressure of other gases)
= 101.3 - (21.22 + 75.1 + 0.04)
= 4.94 kPa
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10th grade chemistry. I’m so confused on what I need to do. What do I draw?
In chemistry, drawing chemical structures is a fundamental skill that allows us to communicate and understand chemical concepts.
A chemical structure is a diagram of a molecule or compound that depicts the arrangement of atoms as well as the chemical bonds that hold them together. Depending on the complexity of the molecule and the level of detail required, there are various methods for drawing chemical structures. Lewis structures, line structures, and condensed structures are the most prevalent types of chemical structures.Lewis structures are diagrams that depict a molecule's valence electrons and bonding patterns. To create a Lewis structure, you must first determine how many valence electrons each atom has and then use them to form bonds and fill octets.
When designing Lewis structures, you should additionally consider formal charges, resonance, and electronegativity.Line structures are a method of depicting molecules that is simplified by the use of lines to represent bonds and atoms. In line structures, each vertex or endpoint represents a carbon atom unless otherwise indicated. Hydrogen atoms are not usually shown unless they are attached to a heteroatom. Line structures are useful for quickly drawing and comparing structures, but they do not show the three-dimensional arrangement of atoms.Condensed structures are another way of representing molecules by using symbols and abbreviations to represent atoms and functional groups. In condensed structures, bonds are implied rather than drawn, and atoms are listed in the order of their connectivity.
Condensed structures are useful for representing large and complex molecules, but they can be ambiguous and difficult to read without practice.
Overall, drawing chemical structures is an essential skill in chemistry that requires practice and attention to detail. By learning how to draw Lewis structures, line structures, and condensed structures, you can better understand chemical concepts and communicate your ideas to others.
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