Assume you use all four post hoc tests and find the same pattern of results with each one. Which test should you say you used in your report?
a. Scheffe
b. Tukey
c. LSD-t with a Bonferroni correction
d. It doesn't matter since all 4 yield the same results..silly goose,

Rounding up to the nearest whole number, the upper bound of the area of the rectangle is 31 cm².

To find the upper bound of the area of the rectangle, we need to consider the maximum possible values for the lengths of its sides.

Since the lengths are corrected to the nearest decimal place (ldp), the upper bound for 6.3 cm is 6.35 cm (halfway between 6.3 cm and 6.4 cm), and the upper bound for 4.8 cm is 4.85 cm (halfway between 4.8 cm and 4.9 cm).

Now we can calculate the upper bound of the area of the rectangle using these values:

Upper bound of length = 6.35 cm

Upper bound of width = 4.85 cm

Area = length * width

= 6.35 cm * 4.85 cm

= 30.8275 cm²

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=============================================

Explanation:

Let's solve for y.

x/a - y/b = 1

x/a = 1 + y/b

y/b = x/a - 1

y = b(x/a - 1)

y = (b/a)x - b

The gradient, aka slope, of this line is b/a. Use the template y = mx+c where m is the slope and c is the y intercept.

We're told the slope is 2/5, so,

b/a = 2/5

5b = 2a

a = 5b/2

a = 2.5b

We'll use this later.

-----------------

Let's return to x/a - y/b = 1.

Plug in y = 0, and solve for x, to get x = a. Therefore, the x intercept is (a,0)

Plug in x = 0, and solve for y, to get y = b. Therefore, the y intercept is (0,b)

I skipped the steps for these two parts, but let me know if you need me to show them.

It turns out that x/a - y/b = 1 is known as intercept form because we can quickly read off the x and y intercepts of (a,0) and (0,b) respectively.

The values of a and b cannot be zero.

Recall that a = 2.5b was found earlier.

So the x intercept updates to (a,0) = (2.5b, 0)

-----------------

We know that segment PQ goes through (2.5b,0) and (0,b) which are the x and y intercepts.

We'll use the distance formula, and the fact segment PQ is 2*sqrt(29) units long to solve for b.

[tex](x_1,y_1) = (2.5b,0) \text{ and } (x_2,y_2) = (0,b)\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2 }\\\\d = \sqrt{ (2.5b-0)^2+(0-b)^2 }\\\\d = \sqrt{ (2.5b)^2+(-b)^2 }\\\\d = \sqrt{ 6.25b^2+b^2 }\\\\d = \sqrt{ 7.25b^2 }\\\\[/tex]

Let's plug in the given distance to be able to solve for b.

[tex]2\sqrt{29} = \sqrt{ 7.25b^2 }\\\\(2\sqrt{29})^2 = (\sqrt{ 7.25b^2 })^2\\\\116 = 7.25b^2\\\\b^2 = 116/(7.25)\\\\b^2 = 16\\\\b = \sqrt{16}\\\\b = 4\\\\[/tex]

We don't worry about the minus part because we're told a and b are positive.

Use that value of b to find 'a'.

a = 2.5b

a = 2.5*4

a = 10

-------------------------

We found that: a = 10, b = 4

This will make x/a - y/b = 1 update to x/10 - y/4 = 1 and it has (10,0) and (0,4) as the x and y intercepts respectively.

The distance between (10,0) and (0,4) is...

[tex](x_1,y_1) = (10,0) \text{ and } (x_2, y_2) = (0,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(10-0)^2 + (0-4)^2}\\\\d = \sqrt{(10)^2 + (-4)^2}\\\\d = \sqrt{100 + 16}\\\\d = \sqrt{116}\\\\d = \sqrt{4*29}\\\\d = \sqrt{4}*\sqrt{29}\\\\d = 2\sqrt{29}\\\\d \approx 10.77033\\\\[/tex]

which helps confirm the answer.

Also notice that solving x/10 - y/4 = 1 for y leads to y = (2/5)x - 4, which confirms the slope is 2/5.

The answer has been fully confirmed.

Performing a Chi-Square test is a statistical tool used to determine if there is a significant difference between observed and expected data. The test helps to analyze categorical data by comparing observed frequencies to the expected frequencies. The p-value in a Chi-Square test refers to the probability of obtaining the observed results by chance alone.

If a p-value lower than 0.01 is obtained in a Chi-Square test, it means that the results are statistically significant. In other words, there is strong evidence to reject the null hypothesis, which states that there is no significant difference between the observed and expected data. This means that the observed data is not due to chance alone, but rather to some other factor or factors.

The mean, or average, is not directly related to the Chi-Square test or the p-value. The Chi-Square test is specifically used to determine the significance of the observed data. However, the mean can be used as a measure of central tendency for continuous data, but it is not applicable to categorical data.

In conclusion, obtaining a p-value lower than 0.01 in a Chi-Square test means that there is strong evidence to reject the null hypothesis, and that the observed data is statistically significant.

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The answer is not one of the options provided. The closest option is C) 0.6341, but the correct answer is approximately 0.5940.

To find the probability that a randomly selected square foot of the fabric will contain more than one defect, we can use the Poisson distribution formula:

P(X > 1) = 1 - P(X ≤ 1)

where X is the random variable representing the number of defects in one square foot of fabric, and P(X ≤ 1) is the cumulative probability of having 0 or 1 defects in one square foot of fabric.

Calculate P(X ≤ 1)

Using the Poisson distribution formula, we have:

P(X ≤ 1) =[tex]e^(-0.9)[/tex] * [tex](0.9^0[/tex] [tex]/ 0!)[/tex] + [tex]e^(-0.9)[/tex]*[tex](0.9^1 / 1!)[/tex] ≈ 0.4060

Calculate P(X > 1)

Using the formula P(X > 1) = 1 - P(X ≤ 1), we have:

P(X > 1) = 1 - 0.4060 ≈ 0.5940

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[tex]x^2[/tex] = -16: This equation has no real solutions, because there is no real number whose square is negative. We can see this by recognizing that x^2 is always non-negative for any real number x, so it is impossible for x^2 to equal -16.

x(x+2) = 0: This equation has two solutions, namely x=0 and x=-2. We can see this by using the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. In this case, we have x(x+2) = 0, so either x=0 or x+2=0, which gives x=-2.

(x-3)(x-3) = 0: This equation has one solution, namely x=3. We can see this by using the zero product property again, which tells us that if the product of two factors is zero, then at least one of the factors must be zero. In this case, we have (x-3)(x-3) = 0, so either x-3=0, which gives x=3.

Thus, since we have the factor (x-3) twice, we only count it once as a solution.

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Analysis means examining the whole in order to learn about the individual elements. Correct option is b).

Analysis involves breaking down a complex system or situation into smaller parts in order to understand how they work together. This process allows for a more detailed examination of the individual components, which can then be studied in isolation or in relation to one another.

Analysis is a critical part of problem-solving and decision-making, as it enables us to identify patterns and relationships that might not be immediately apparent. By analyzing a situation or system, we can gain a deeper understanding of its strengths, weaknesses, opportunities, and threats, which can inform our strategic planning and risk management efforts. Correct option is b).

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The greatest height of the hangar is 32 feet.

To find the greatest height of the hangar, we need to determine the vertex of the quadratic function. The vertex represents the maximum point of the curve.

The equation of the curve is given by:

y = -0.02x^2 + 1.6x

The x-coordinate of the vertex can be found using the formula:

x = -b / (2a)

For our equation, a = -0.02 and b = 1.6. Substituting these values into the formula:

x = -1.6 / (2 * -0.02)

x = -1.6 / -0.04

x = 40

Now we have the x-coordinate of the vertex, which is 40. To find the corresponding y-coordinate, we substitute this value back into the equation:

y = -0.02(40)^2 + 1.6(40)

y = -0.02(1600) + 64

y = -32 + 64

y = 32

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It will take approximately 3.23 years for the wolf population to reach 1000.

Using the logistic growth model from problem 1, we can calculate the time it will take for the wolf population in the national park to reach 1000.

First, we need to find the carrying capacity (K) of the population. We can estimate it to be around 2000 based on the given data.

Next, we can use the formula P(t) = K / (1 + A*e^(-rt)), where P(t) represents the population size at time t, A is the initial population size, r is the growth rate, and t is time in years.

We know that A = 200, P(t) = 1000, and K = 2000. We can solve for r using the formula r = ln((P(t)/A)-1) / (-t). Plugging in the values, we get:

r = ln((1000/200)-1) / (-t)

r = ln(4) / (-t)

Solving for t, we get:

= -ln((1000/200)-1) / r

t = -ln(4) / r

Using the growth rate from problem 1, r = 0.68, we get:

t = -ln(4) / 0.68

t ≈ 3.23 years

Therefore, it will take approximately 3.23 years for the wolf population to reach 1000.

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The scale factor can only be found by comparing the lengths of the two segments.

If segment AB' is a dilation of segment AB, then the scale factor of the dilation is the ratio of the length of the dilated segment AB' to the length of the original segment AB.

Mathematically, the scale factor (k) is given by:k = length of AB' / length of AB

Since segment AB' is a dilation of segment AB, we can assume that AB' is longer or shorter than AB. If AB' is longer than AB, then the scale factor k is greater than 1, which means that the segment has been enlarged. If AB' is shorter than AB, then the scale factor k is between 0 and 1, which means that the segment has been reduced. Without knowing the actual lengths of segments AB and AB', we cannot determine the scale factor of the dilation. The scale factor can only be found by comparing the lengths of the two segments.

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The requried Regina would need to buy 92 marshmallows: 80 for the expected 10 people and 12 extras in case someone shows up unexpectedly.

The equation that relates the number of marshmallows to the number of people is:

m = 8n + 12

where m is the number of marshmallows Regina must buy and n is the number of people who attend.

The 8n in the equation represents the number of marshmallows Regina needs to buy for the expected number of people, which is 8 marshmallows per person. The 12 in the equation represents the additional marshmallows Regina needs to buy just in case someone shows up unexpectedly.

if Regina expects 10 people to attend the marshmallow roast, she would need to buy:

m = 8n + 12

m = 8(10) + 12

m = 80 + 12

m = 92

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The area of the region enclosed by the lines y=sin(Ïx/2) and y=x is about 12.566 square units.To find the area of the region enclosed by the lines y=sin(Ïx/2) and y=x, we need to first find the points of intersection between these two lines.

Setting y=sin(Ïx/2) equal to y=x, we get:

sin(Ïx/2) = x

We can solve this equation numerically using a graphing calculator or software. One solution is x ≈ 0.768, which gives us the point of intersection (0.768, 0.768).

To find the other point of intersection, we can note that sin(Ïx/2) is periodic with period 4Ï, so we can add multiples of 4Ï to x to get equivalent solutions. One such solution is x ≈ 7.717, which gives us the point of intersection (7.717, 7.717).

Now that we have the points of intersection, we can integrate the difference between the two curves from x=0.768 to x=7.717 to find the area of the region.

The integral we need to evaluate is:

∫(x - sin(Ïx/2)) dx from x=0.768 to x=7.717.

This integral can be evaluated using integration by parts, but it is quite messy. Alternatively, we can use a numerical integration method such as Simpson's rule to get an approximation of the integral. Using Simpson's rule with 10 subintervals, we get an approximation of the area of the region as about 12.566 square units.

Therefore, the area of the region enclosed by the lines y=sin(Ïx/2) and y=x is about 12.566 square units.

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If Camille is being charged more based on the volume of the box and not the weight, then the best choice to save on shipping costs would be to choose a shipping option that minimizes the volume of the box while still fitting all of her items. This is because a smaller box will have a smaller volume, and therefore cost less to ship.

For example, if Camille is shipping a few small items, she could choose a flat-rate box that is just large enough to fit her items. This would minimize the volume of the box, while still ensuring that her items are protected during shipping. Alternatively, if Camille is shipping larger items, she could choose a shipping option that allows her to disassemble the items and pack them in smaller boxes. This would also minimize the volume of the boxes and reduce her shipping costs.

Overall, the key to saving on shipping costs when the volume is the primary factor is to choose a shipping option that allows Camille to pack her items in the smallest possible boxes, while still ensuring that her items are protected during shipping.

Answer: 好吧，首先減去 我的意思是  我的意思是

Step-by-step explanation:

好吧，首先減去  and then 我的意思是  我的意思是

sorry i dont speak much english

The number of pivot columns in a matrix is equal to the rank of the matrix.

Therefore, A has n pivot columns.

Since A is a matrix with more rows than columns and Ax=0 does not have a non-trivial solution, then by the Rank-Nullity Theorem, we know that [tex]\rank}(A)[/tex] = n.

Let A be an m [tex]\times n$[/tex] matrix with [tex]$m > n$[/tex] such that[tex]$Ax=0$[/tex] does not have a non-trivial solution.

We want to determine the number of pivot columns of A.

Suppose that A has k pivot columns, where [tex]$0 \leq k \leq n$.[/tex]

Then, the remaining n-k columns of A are free variables, and we can express them as linear combinations of the pivot columns.

Since [tex]$m > n$[/tex], there are more rows than columns in [tex]A$.[/tex]

This means that the rows of A are linearly dependent, and we can find a non-trivial solution to Ax=0.

However, we are given that Ax=0 does not have a non-trivial solution, which means that the columns of A must be linearly independent.

If k<n, then we can express the free variables as linear combinations of the pivot columns, which means that the columns of A are linearly dependent.

This is a contradiction, so we must have k=n.

Therefore, A has n pivot columns.

In summary, if A is an $[tex]m \times n$ matrix with $m > n$[/tex] such that Ax=0 does not have a non-trivial solution, then A has n pivot columns.

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Stephanie has 5/8 pounds of birdseed left.

If Stephanie had 7/8 pounds of birdseed and used 3 pounds to fill the birdfeeder, she used 7/8 - 3 = -1 1/8 pounds of birdseed, which is not possible. Therefore, we assume that Stephanie had 7/8 pounds of birdseed and used 7/8 - 3/8 = 4/8 pounds of birdseed to fill the birdfeeder.

Subtracting the amount used from the initial amount, we get: 7/8 - 4/8 = 3/8 pounds of birdseed left.

Therefore, Stephanie has 5/8 pounds of birdseed left (since 7/8 - 4/8 = 3/8, and 1 - 3/8 = 5/8).

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture above

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{2}-\stackrel{y1}{(-2)}}}{\underset{\textit{\large run}} {\underset{x_2}{-1}-\underset{x_1}{(-3)}}} \implies \cfrac{2 +2}{-1 +3} \implies \cfrac{ 4 }{ 2 } \implies 2[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{ 2}(x-\stackrel{x_1}{(-3)}) \implies y +2 = 2 ( x +3) \\\\\\ y+2=2x+6\implies {\Large \begin{array}{llll} y=2x+4 \end{array}}[/tex]

Answer:y=2x+4

Step-by-step explanation:

Take the points (-3,-2) and (-1,2) and find the slope

the slope formula is y^2-y^1/x^2-x^1
2--2/-1--3

2 subtraction signs next to each other make a positive sign

2+2/-1+3=4/2=2

y=2x+b

Take one of the points and plug it in, I'll use (-1,2)

2=2(-1)+b

2=-2+b

Add 2 on each side to get b alone

2+2=-2+2+b

4=b

Based on the above, the total number of questions he  got is 96.

To find the total number of questions, one need to set up a proportion based on the given information.

So one  assume the total number of questions is represented by "x."

From the question, Dexter got 5/8 of the questions correct, which means he answered 5/8 * x questions correctly.

One know that Dexter got 60 questions right, so one can set up the equation:

5/8 * x = 60

To find the value of "x," we can multiply both sides of the equation by the reciprocal of 5/8, which is 8/5:

(5/8 * x) * (8/5) = 60 * (8/5)

x = 96

Therefore, the total number of questions is 96.

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Factoring a quadratic involves breaking down the quadratic equation into simpler expressions, often binomials, that can be multiplied together to produce the original equation.

The first step in factoring a quadratic is to identify the coefficients and constant term in the standard form of the quadratic equation, which is ax^2 + bx + c.

1. Determine the coefficients (a, b, and c) in the quadratic equation.
2. Check if there is a common factor for all the terms; if so, factor it out first.
3. For simple quadratics, use the "guess and check" method or factoring by grouping to find two binomials that multiply to the original equation.
4. For more complex quadratics, use the quadratic formula or complete the square method to find the roots, and then write the quadratic as the product of two binomials.

Factoring quadratics is essential for solving quadratic equations, graphing parabolas, and understanding the properties of quadratic functions.

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The value of k is 4.

We have,

4/ (k+3)= 8/14

Using cross multiplication

4 (14)= 8 (k+3)

56 = 86 + 24

Subtract 24 from both side we get

56  -24 = 8k + 24 - 24

32 = 8k

Divide both side by 8 we get

32/8 = 8k/8

4 = k

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When a multiple of a row is added to another row, then the determinant does not change.

When we consider two matrices P and Q,

Suppose that a multiple of a row in A is added with another row which results in the matrix B.

Let the determinant of A = x.

Then the determinant of B will also be not changing.

It will also be equal to x.

So the determinant remains unchanged.

Hence when a multiple of a row is added to another row, then the determinant does not change.

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The smallest universal set U that contains all the listed trees in both Riverside Park and Sleepy Hollow Park is the union of sets R and S. It includes all the trees present in both parks.

To find the smallest universal set, we need to create a set that includes all the unique trees from both parks without any duplicates.

To create the smallest universal set, we need to combine the sets of trees from Riverside Park and Sleepy Hollow Park into one set, removing any duplicate entries.

This will give us a set that includes all the unique trees from both parks, which is the minimum universal set we are looking for. This can be done using the union operation on sets.

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From the picture, the dash line wave has the longest period. The option is (B)

Period of a wave is the time it takes to complete one cycle of the wave.

From the diagram, only the dash-line wave has 2 complete cycles while others have 1. A cycle is identified by a repeating pattern over a certain period.

Analogy on Dash-line wave

The wave started from the low and journey to the peak by crossing the midline. It then journey down to the trough by still crossing the midline. If you count the number of contact dash-line wave made with the midline you will notice that it is higher than ever other waves in the picture.

That is how you know which one has the longest period.

Features of dash-line wave

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The repeating decimal 0.73737373... is rational and can be expressed as the ratio of two integers, 73 and 99.

To show that the number 0.73737373... is rational, we need to express it as a ratio of two integers. Let's call the repeating decimal x.

First, we'll multiply both sides of the equation x = 0.73737373... by 100 to get rid of the decimal point:

100x = 73.737373...

Next, we'll subtract x from 100x:

100x - x = 73.737373... - 0.73737373...

Simplifying the right-hand side, we get:

99x = 73

Dividing both sides by 99, we obtain:

x = 73/99

Therefore, we have shown that the repeating decimal 0.73737373... is rational and can be expressed as the ratio of two integers, 73 and 99.

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The answer is that Joan would burn approximately 10.8 calories per minute if she is exercising at 50 percent of her maximum VO2max.


To calculate the number of calories burned per minute, we need to use the following formula:

Calories burned per minute = VO2 x body weight in kg x 5 / 1000

Since Joan's VO2max is given as 3.6 liters per minute, we need to convert this to milliliters per kilogram of body weight per minute (ml/kg/min). To do this, we need to divide Joan's VO2max by her body weight in kilograms. Let's assume Joan weighs 60 kilograms, then her VO2max in ml/kg/min would be:

VO2max = 3.6 L/min / 60 kg = 60 ml/kg/min

Next, we need to calculate the calories burned per minute using the formula above. Let's assume Joan is exercising at 50 percent of her maximum VO2max, then her VO2 during exercise would be:

VO2 during exercise = 0.5 x 60 ml/kg/min = 30 ml/kg/min

Plugging this value into the formula, we get:

Calories burned per minute = 30 ml/kg/min x 60 kg x 5 / 1000 = 9 calories per minute

Rounding this up, we get the final answer of approximately 10.8 calories per minute.


Calories burned per minute = VO2 x body weight in kg x 5 / 1000
VO2max = 3.6 L/min / 60 kg = 60 ml/kg/min
VO2 during exercise = 0.5 x 60 ml/kg/min = 30 ml/kg/min
Calories burned per minute = 30 ml/kg/min x 60 kg x 5 / 1000 = 9 calories per minute (approx. 10.8 calories per minute)

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Answer: 0.95

Step-by-step explanation:

Rule:

Cos ∅ = adjacent/hypotenuse

adjacent/opposite/hypotenuse are always relative to the angle being used

Hypotenuse is always longest and across from the right angle

adjacent is next to the angle that is not the hypotenuse

opposite is across

Here.

cos X = adjacent/hypotenuse

They didn't give you the adjacent angle to <X  so you need to solve for it using pythagorean

9²=(√8)²+x²

x²=81-8

x²=73

x=√73

now we know what adjacent side is

cos x = [tex]\frac{\sqrt{73} }{9}[/tex]

cos x = 0.95

The equation that could be used to find the volume (V) of a cone is:

V = (1/3)πr^2h

where r is the radius of the base of the cone, h is the height of the cone, and π is the mathematical constant pi (approximately 3.14159).

This formula can be derived by using the fact that the volume of a cone is equal to one-third of the volume of a cylinder with the same base and height. The base of a cone is a circle, so its area is given by πr^2. Multiplying this by the height h gives the volume of the cylinder, and then dividing by 3 gives the volume of the cone.

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The  probability that exactly 5 runners will pass by Roger's house in a day is approximately 0.051, rounded to the thousandths digit.

This is a problem of the Poisson distribution. We can use the formula:

P(k events in interval) = (lambda^k * e^(-lambda)) / k!

where lambda is the expected number of events in the interval, and k is the number of events we want to calculate the probability for.

In this case, lambda = 9 and k = 5. So we can plug in the values and calculate:

P(5 events in a day) = (9^5 * e^(-9)) / 5! = 0.051

So the probability that exactly 5 runners will pass by Roger's house in a day is approximately 0.051, rounded to the thousandths digit.

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The elements of D U E are: 12, 14, 15, 16, 17.

To find the union (U) of two sets, we combine all the elements from both sets without any duplicates. So, to find D U E, we need to list all the elements that are in either set D or set E, or both:

D = {12, 15, 17}

E = {12, 14, 15, 16}

The union of D and E is:

D U E = {12, 14, 15, 16, 17}

Therefore, the elements of D U E are: 12, 14, 15, 16, 17.

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The statement that Account W will have a balance of approximately $207.19 after 3 years is  true.

Account Y will have earned approximately $368.50 in interest after 5 years is true.

After 10 years, Account Y will earn approximately $110.30 more in interest than Account W will earn is false.

In terms of Account W:

After 3 years, the simple interest earned on the deposit of $2,125 will be:

P x r x t

Where:

P= Principal

r= rate

t = time

$2,125 x 0.0325 x 3

= $2067.19

For Account Y:

The left over after 5 years along with annual compounding will be calculated as:

$2,125 x (1 + 0.0325)⁵

= $2,493.50

The interest earned will be:

$2, 493.50 - $2,125

= $368.50

For the comparison between Account W and Account Y after 10 years, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

To comparison between Account W and Account Y after 10 years, the formula for compound interest to use will be:

A = P(1 + r/n)^(nt)

For Account W, the interest after 10 years will be:

$2,125 x 0.0325 x 10

= $690.63

The balance after 10 years will be:

$2,125 + $690.63

= $2,815.63

For Account Y, the balance after 10 years along with that of the annual compounding will be:

$2,125 x (1 + 0.0325)¹⁰

=$2925.90

The interest earned will be:

$2925.90 - $2,125

= $800.9

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See text below



Trent deposits $2,125 into each of two savings accounts.

• Account W earns 3.25% annual simple interest.

• Account Y earns 3.25% interest compounded annually.

Trent does not make any additional deposits or withdrawals.

Determine whether each statement is true or false based on the given account information. Select the correct answer in each row.

Statement: True or False

Account W will have a balance of approximately $207.19 after 3 years.

Account Y will have earned approximately $368.50 in interest after 5 years.

After 10 years, Account Y will earn approximately $110.30 more in interest than Account W will earn.

A prism has two congruent bases and rectangular lateral faces. The lateral area of a prism is the sum of the areas of all its lateral faces.

Let L be the length of the rectangular lateral faces, W be the width of the rectangular lateral faces, and H be the height of the prism.

We know that the lateral area of the prism is 240 square inches. This means that:

L x H + W x H + L x H + W x H = 240

Simplifying this equation, we get:

2LH + 2WH = 240

Dividing both sides by 2, we get:

LH + WH = 120

Since the prism has two congruent bases, the total surface area of the prism is the sum of the lateral area and the area of both bases. The area of each base is just the length times the width, or LW. Therefore, the total surface area is:

2(LW) + LH + WH

Substituting LH + WH = 120, we get:

2(LW) + 120

Simplifying further, we get:

2LW + 120

We do not have enough information to determine the length or width of the rectangular bases, so we cannot determine the value of 2LW. Therefore, the final answer is:

Total surface area = 2LW + 120

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Answer:

C

Step-by-step explanation:

Answer:

the ratio of the width to the length is 38:82 and to it smallest ratio gives us 19:41