The time it takes for the rotor to stop, assuming constant angular acceleration, can be calculated using the equation:
t = (Vf - Vi) / a
where:
t = time
Vf = final angular velocity (0 revs/min in this case)
Vi = initial angular velocity (350 revs/min)
a = angular acceleration (constant)
The value of the angular acceleration (a) must be known or estimated to solve for t
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the half-life of sodium-24 is 14.96 hours. if a sample contains 320 mg, how many mg will remain after 150 hours?
The half-life of a radioactive isotope is the time it takes for half of the initial amount to decay. So 0.31 mg will remain after 150 hours.
For sodium-24, the half-life is 14.96 hours. To determine the amount of sodium-24 that remains after 150 hours, we need to calculate the number of half-lives that have occurred during that time. We can do this by dividing the total elapsed time by the half-life of the isotope:
150 hours / 14.96 hours = 10.07 half-lives
Since each half-life reduces the amount of the isotope by half, after 10 half-lives, we would expect the amount to be reduced by a factor of [tex]2^{10}[/tex] = 1024. So, the amount of sodium-24 that remains after 150 hours would be:
320 mg × (1/1024) = 0.31 mg
This is the theoretical minimum amount of sodium-24 that would remain after 150 hours. In practice, other factors such as environmental conditions and decay products can affect the actual amount remaining.
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To practice Problem-Solving Strategy 8.1 Static equilibrium problems.When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a forearm is 1.50kg . If the biceps is connected to the forearm a distance dbiceps = 2.50cmfrom the elbow, how much force Fbiceps must the biceps exert to hold a 700g ball at the end of the forearm at distance dball = 30.0cm from the elbow, with the forearm parallel to the floor? How much force Felbow must the elbow exert? (Figure 1)
The biceps force (F biceps) and the elbow force (F elbow) is mathematically calculated to be F biceps = 188.352 N towards the upward direction, F elbow = 165.295 N towards the downwards direction.
Generally, the equation for the Weight of the forearm is mathematically given as
W = mass × gravity
W = 1.50 kg × 9.81 m/s²
W = 14.715 N
The moment about the elbow is, since the sum of moments about the elbow is equated to 0.
[0.85 × 9.81 = 8.3385 N]
8.3385 N× 30 cm + 14.715 N× 15 cm - F biceps × 2.5 cm = 0
250.155 + 220.725 - F biceps × 2.5 cm = 0
F biceps × 2.5 cm = 470.88 N cm
F biceps = (470.88 N cm)/(2.5 cm)
F biceps= 188.352 N towards the upward direction
The sum of moments about the point b/w biceps and forearm is
F elbow × 2.5 cm = 8.3385 N × 27.5 cm + 14.715 N× 12.5 cm
F elbow × 2.5 cm = 229.30 + 183.9375
F elbow = 165.295 N towards the downwards direction
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In the song Cupid Shuffle, Cupid instructions the dancer to move: "To the right, to the right, to the right, to the right. To the left, to the left, to the left, to the left." What is the displacement of the dancer, relative to the starting position, at the end of this refrain if each step is 45 cm?
Answer:
0
Explanation:
The dancer starts and ends at the same place
if pi is the indicated horsepower and pb is the brake horsepower of a compressor, then what is mechanical efficiency equal to?(1 point) pi/pb pi-pb pb-pi pb/pi
The correct option is (4) i.e. pb/pi, is mechanical efficiency, if pi is the indicated horsepower and pb is the brake horsepower of a compressor.
The mechanical efficiency of a compressor is equal to the ratio of the brake horsepower (pb) to the indicated horsepower (pi). Mathematically, it can be expressed as:
Mechanical efficiency = pb / pi
The brake horsepower is the actual power developed by the engine and it is the power that is available for useful work. The indicated horsepower, on the other hand, is the power developed inside the engine cylinders and it includes the power lost due to friction and other inefficiencies. So, the mechanical efficiency gives an indication of how much of the power developed inside the engine cylinders is actually available for useful work. The higher the mechanical efficiency, the less power is lost to inefficiencies, and the more power is available for useful work.
Therefore, the correct answer is pb / pi.
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Question - If pi is the indicated horsepower and pb is the brake horsepower of a compressor, then what is mechanical efficiency equal to? Select the correct option. (1) pi/pb (2) pi-pb (3) pb-pi (4) pb/pi
(a)
Figure 1 shows a spanner being used to tighten a nut.
Figure 1
25 cm
20 cm
200 N
Calculate the moment being applied to the nut in the figure.
Give your answer in newton metres (Nm).
15 cm
If a 15 cm long spanner is subjected to a 5.0 N force, the resultant moment of force is 0.75 Nm.
What is the moment calculation equation?Using the equation, we can determine the moment of a force. Motion equals The force is doubled by the perpendicular distance to the pivot.If a 15 cm long spanner is subjected to a 5.0 N force, the resultant moment of force is 0.75 Nm.The radius of the pulley, which is the distance from the rotating axis, is multiplied by the force (F) to determine load torque (r). The needed torque for the application is 20 N x 0.05 m = 1 Nm when the radius of the pulley is 5 cm distant and the mass of the load (blue box) is 20 Newtons.To learn more about moment of force refer to:
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chloe, a russian cosmonaut, goes outside her ship for a spacewalk, but when she is floating 15 m from the ship, her tether catches on a sharp piece of metal and is severed. chloe tosses her 2.0 kg camera away from the ship with a speed of 12 m/s. a) how fast will chloe , whose mass is now 68 kg, travel toward the spaceship? b) assuming the spaceship remains at rest with respect to chloe, how long will it take her to reach the ship? (0.352941 / 42.5)
Answers to part A and B are as follows:
A: At 0.352941 m/s Chloe travels toward the spaceship.
B: The time it takes Chloe to reach the ship is 42.5 s.
A) After Chloe tosses the camera, the momentum of the system (Chloe + Camera) must be conserved. The momentum of Chloe before she tosses the camera is:
p_before = m_chloe * v_before = 68 kg * 0 m/s = 0 kg m/s
The momentum of Chloe and the camera after she tosses the camera is:
p_after = m_chloe * v_after + m_camera * v_camera = 68 kg * v_after + 2.0 kg * 12 m/s
Since momentum must be conserved, we have:
p_before = p_after
0 = 68 kg * v_after + 2.0 kg * 12 m/s
Solving for v_after:
v_after = -2.0 kg * 12 m/s / 68 kg = -0.352941 m/s
B) To find the time it takes Chloe to reach the ship, we can use the kinematic equation:
d = v_0 * t + 0.5 * a * t^2
where d is the distance from Chloe to the ship, v_0 is her initial velocity, t is time, and a is acceleration due to gravity.
We know that the distance from Chloe to the ship is 15 m, her initial velocity is -0.352941 m/s, and acceleration due to gravity is 9.8 m/s^2.
Substituting these values into the kinematic equation:
15 = -0.352941 * t + 0.5 * 9.8 * t^2
Solving for t using the quadratic formula:
t = (-0.352941 +/- sqrt(0.352941^2 - 4 * 0.5 * 9.8 * 15)) / (2 * 0.5 * 9.8)
The time it takes Chloe to reach the ship is the positive value of t:
t = (0.352941 + sqrt(0.352941^2 + 4 * 0.5 * 9.8 * 15)) / (2 * 0.5 * 9.8)
t = 42.5 s
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what are (a) the kinetic energy, (b) the rest energy, and (c) the total energy of a 1.10 g particle with a speed of 0.800 c ?
Answer:
(a) The kinetic energy of a 1.10 g particle with a speed of 0.800 c can be calculated using the equation KE = (1/2)mv^2, where m is the mass of the particle and v is its velocity. In this case, the mass of the particle is 1.10 g and the velocity is 0.800 c, so the kinetic energy would be:
KE = (1/2) * (1.10 * 10^-3 kg) * (0.800 * 3 * 10^8 m/s)^2
(b) The rest energy of a particle is the energy it has when it is at rest. According to the equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. In this case, the rest energy would be:
E = (1.10 * 10^-3 kg) * (3 * 10^8 m/s)^2
(c) The total energy of a particle is the sum of its kinetic energy and rest energy. Thus,
Total energy= kinetic energy + rest energy
at a certain altitude above the earth's surface, the electric field has a magnitude of 108 v/m. how much energy is stored in 1.00 m3 of air due to this field?
108kg energy is stored in 1.00 m3 of air due to this field.
How is energy density calculated?
To = [M0 L3 T0]-1 [M1 L-1 T-2] [M1 L2 T-2] [M0 L2 T-2] As a result, the energy density is represented in dimensions as [M1 L-1 T-2].
The quantity of energy held between the plates of a parallel-plate capacitor is given by the formula UC=uE(Ad)=120E2Ad=120V2d2Ad=12V20Ad=12V2C, which is the energy density times the volume between the plates.
We will use small u to represent the quantity known as energy density, which is straightforward to define. It is described as the amount of energy per volume that the capacitor's electric fields can hold. It is equal to the volume of the area between the capacitor's plates divided by u sub E.
In this case-
108 * 1.00 = 108.
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two point charges, q1=-15.0mc and q2= 75.0 mc are separated at distance of 8.0 cm. what is the distance (in cm) from charge q2 to the point at which net electric field is equal 0?
The distance from charge q2 to the point at which net electric field is 4 cm. The electric field is a vector field that describes the force experienced by a charged particle due to an electric charge distribution.
Using Coulomb's law:
E1 = k x q1 / r^2
E2 = k x q2 / (d-r)^2
where k is Coulomb's constant, d is the separation between the charges (8 cm), and r is the distance from charge q2 to the point at which the net electric field is equal to zero.
Setting E1
= E2:k x q1 / r^2
= k x q2 / (d-r)^2
Solving for r:r
= d x sqrt(q1/q2)
= 8 cm x sqrt(-15.0 mc / 75.0 mc)
= 4 cm
So, the distance from charge q2 to the point at which the net electric field is equal to zero is 4 cm.
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can someone please help me with this
The acceleration of Argus in the first 25 s is approximately 0.8 m/s2.
Calculate the distance of the mother from the father?The distance of the mother from the father can be calculated by using the equation v = u + at, where v is the velocity of Argus, u is the initial velocity of Argus, a is the acceleration of Argus and t is the time taken for Argus to run from the father to the mother. Using the values from Graph 1, we can calculate the distance to be approximately 12.5 m.Graph 1 shows the velocity of Argus as a function of time. The graph shows that Argus has a negative acceleration in the first 25 s of its motion, meaning that it is slowing down. This is consistent with the family playing with their dog, as Argus is initially running towards the girl and then reversing his direction of movement to run towards the mother. The acceleration of Argus in the first 25 s can be calculated by taking the derivative of the velocity graph. This gives a result of -0.16 m/s2.The distance of the mother from the father can also be calculated from Graph 1. By taking the area under the graph from 0 to 150 seconds, we get a result of 150 m. This indicates that the mother is 150 m away from the father.In conclusion, Graph 1 shows the velocity of Argus as a function of time. By taking the derivative of the graph, we can calculate the acceleration of Argus in the first 25 seconds and by taking the area under the graph, we can calculate the distance of the mother from the father.To learn more about The acceleration refer to:
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as an astronomer observes an object in space that has an irregular shape, that orbits the sun in a highly elliptical orbit, and that is made of ice and rock. which object is the astronomer most likely observing?
An astronomer sees an irregularly shaped, ice-and-rock object orbiting the sun in a highly elliptical orbit. Astronomers are most likely to observe comets. Thus, B is the correct option.
Comets are made of ice and rock, and they have irregular shapes. They also orbit the sun in highly elliptical orbits, meaning that their distance from the sun changes greatly over time. Unlike asteroids, which are usually made of rock or metal and have a more spherical shape, comets are known for their bright, glowing tails that result from the sublimation of ice as they near the sun.
Unlike meteoroids, which are small, rocky or metallic objects that can burn up in the Earth's atmosphere, comets are much larger and remain intact as they orbit the sun.
Options should be provided along with this question:
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Answer: Hes observing a comet.
Explanation: Comets are small, irregularly shaped bodies in the solar system composed mainly of ice and dust that typically measure a few kilometers across. They travel around the sun in very elliptical orbits that bring them very close to the Sun, and then send them out past Neptune.
Comets are cosmic snowballs of frozen gases, rock, and dust that orbit the Sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the Sun, it heats up and spews dust and gases into a giant glowing head larger than most planets.
When freshly cut sodium metal is exposed to all the mass of the substance increases. Which of the following is the best explanation for this apparent violation of the Law of Conservation of Mass? a. The air "pushes down on the metal, causing the balance to display a falsely high mass b. The sodium atoms move closer to one another, causing the sample to gain mass c. The sodium reacts with a component of the air, and the total mass of the reactants is equal to the total of the producte d. Thermal energy of the air is converted into the additional mass e. The Law of Conservation of Moss does not apply to metals
The best explanation for the statement "when freshly cut sodium metal is exposed to all the mass of the substance increases" is that the sodium reacts with a component of the air, and the total mass of the reactants is equal to the total mass of the products.
Hence, the Correct Option is c. i.e. sodium reacts with a component of the air, and the total mass of the reactants is equal to the total mass of the products.
Due to the oscillations of free electrons, freshly cut sodium metal has a brilliant, sparkling surface that rapidly turns dull grey when it interacts with oxygen in the air surrounding it. The metal eventually develops a white crust of sodium oxide that inhibits the metal and oxygen from reacting further.
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Using this relationship, what is the position of the bowling ball at times t = 4.0s and t = 8.0s? a. x(4.0 s) = 5.0 m and x(8.0 s) = 15m b. x(4.0 s) = = 15m and x(8.0 s) = 25 m c. x(4.0 s) = = -17.5m and x(8.0 s) = -37.5m d. x(4.0 s) = 10 m and x(8.0 s) = 20m
Using this relationship, the position of the bowling ball at times t = 4.0s and t = 8.0s is x(t=4s) = 5m and x(t=8s) = 15m.
Given the initial time (t1) = 4s
The final time (t2) = 8s
The relationship is taken as: x0(t) = v0 x t + x
where x0 is the position at particular time, v0 is the velocity = 2.5 and x = -5m which is the initial distance of the object from origin.
So, at time t1 the position of object is taken as:
x0(t = 4s) = 2.5 x 4 -5
x0(t = 4) = 5m
Similarly, at time t2 the position of object is taken as:
x0(t = 8s) = 2.5 x 8 - 5
x0(t = 8) = 15m
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the cart impacts the safety barrier with speed v0 = 3.30 m/s and is brought to a stop by the nest of nonlinear springs which provide a deceleration a = -k1x - k2x3, where x is
The cart impacts the safety barrier with speed [tex]v_0[/tex] = 3.30 m/s, the values of the constants are approximately [tex]k_1[/tex] is 45.513 N/m, and [tex]k_2[/tex] is 79.173 N/m.
The values for the constants [tex]k_1[/tex] and [tex]k_2[/tex] can be calculated as:
Here, it is given that:
Initial speed, [tex]v_0[/tex] = 3.00 m/s
Maximum spring deflection, [tex]x_{max[/tex] = 415 mm = 415 × [tex]10^{(-3)[/tex] m
Velocity at half-maximum deflection, [tex]v_{half[/tex] = 2.64 m/s
At maximum deflection ( [tex]x_{max[/tex]), the cart comes to a stop, so the final velocity ([tex]v_f[/tex]) is 0 m/s.
Using the equation for deceleration:
a = - [tex]k_1[/tex] x - [tex]k_2[/tex][tex]x^3[/tex]
When the cart is at maximum deflection, x = [tex]x_{max[/tex] and [tex]v_f[/tex] = 0, so we have:
0 = - [tex]k_1[/tex] ( [tex]x_{max[/tex]) - [tex]k_2[/tex]( [tex]x_{max[/tex])³
When the cart is at half-maximum deflection, x = [tex]x_{max[/tex] /2 and [tex]v_f[/tex] = [tex]v_{half[/tex], so we have:
[tex]v_{half[/tex] = - [tex]k_1[/tex] ( [tex]x_{max[/tex]/2) - [tex]k_2[/tex][tex](xmax/2)^3[/tex]
We have a system of two equations to solve for [tex]k_1[/tex] and [tex]k_2[/tex].
From the first equation, we can express [tex]k_1[/tex] in terms of [tex]k_2[/tex]:
[tex]k_1[/tex] = -( [tex]k_2[/tex][tex](xmax)^3[/tex]) / [tex]x_{max[/tex]
Substituting this expression for [tex]k_1[/tex] into the second equation, we get:
[tex]v_{half[/tex] = ( [tex]k_2[/tex][tex](xmax)^2[/tex]) / 2 - [tex]k_2[/tex][tex](xmax)^3[/tex] / 8
To solve for [tex]k_2[/tex], we rearrange the equation:
[tex]k_2[/tex][tex](xmax)^3[/tex] / 8 - ( [tex]k_2[/tex][tex](xmax)^2[/tex]) / 2 + [tex]v_{half[/tex] = 0
Substituting the given values:
([tex]415^3[/tex]/8) [tex]k_2[/tex] - ([tex]415^2[/tex]/2) [tex]k_2[/tex] + 2.64 = 0
Simplifying and solving the equation, we find:
[tex]k_2[/tex] ≈ 79.173 [tex]N/m^3[/tex]
Substituting this value of [tex]k_2[/tex] back into the expression for [tex]k_1[/tex] :
[tex]k_1[/tex] = -( [tex]k_2[/tex] [tex](xmax)^3[/tex]) / [tex]x_{max[/tex]
[tex]k_1[/tex] ≈ -79.173 × [tex](415 * 10^{(-3)} )^3 / (415 * 10^{(-3)} )[/tex]
[tex]k_1[/tex] ≈ 45.513 N/m
Thus, the values for the constants are approximately [tex]k_1[/tex] = 45.513 N/m and [tex]k_2[/tex] = 79.173 N/m.
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Your question seems incomplete, the probable complete question is:
The cart impacts the safety barrier with speed v0 = 3.00 m/s and is brought to a stop by the nest of nonlinear springs which provide a deceleration a = -k1x - k2x3, where x is the amount of spring deflection from the undeformed position and k1 and k2 are positive constants. If the maximum spring deflection is 415 mm and the velocity at half-maximum deflection is 2.64 m/s, determine the values for the constants k1 and k2.
A car of mass 2000 kg accelerates from rest to 20 m/s in 10 seconds. Calculate the average power output of its engine. In answering this question, you may assume that all of the energy which is supplied by the car’s engine is transferred to its kinetic store.
A car of mass 2000 kg accelerates from rest to 20 m/s in 10 seconds. The average power output of its engine is 40,000 W.
What is the definition of energy? In physics, energy is a quantitative property that is transferred to a body or a physical system and is observable in the performance of work as well as in the form of heat and light. Energy is a conserved quantity, which means that it can be converted in form but not created or destroyed.The ability to do work, which is the ability to exert a force causing an object to move, is defined as energy. Despite this perplexing definition, the meaning is straightforward: energy is simply the force that causes objects to move. There are two types of energy: potential and kinetic.To learn more about energy refer to:
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two 2.0-cm-diameter insulating spheres have a 5.30 cm space between them. one sphere is charged to 79.0 nc , the other to - 84.0 nc . part a what is the electric field strength at the midpoint between the two spheres?
The electric field strength at the midpoint between the two sphere is 110.63 × 10⁴ N/C, if the distance between them is 5.30 cm.
Diameter of each sphere, D = 2 cm = 0.02 m
Radius of each sphere, r = 0.02/2 = 0.01 m
Charge on first sphere, q₁ = 79 × 10⁻⁹ C
Charge on second sphere, q₂ = -84 × 10⁻⁹ C
Permittivity constant, ε₀ = 8.8 × 10⁻¹² Farad/meter
Distance of the center of first sphere from the mid-point, d = 0.01 + 0.053/2
d = 0.0365 m
Electric field strength at the midpoint due to the first sphere, E₁ = q₁/(4πε₀d²)
E₁ = 79 × 10⁻⁹/(4π × 8.8 × 10⁻¹² × 0.0365²)
E₁ = 53.62 × 10⁴ N /C
Similarly, electric field strength at the midpoint due to the second sphere, E₂ = q₂/(4πε₀d²)
E₁ = -84 × 10⁻⁹/(4π × 8.8 × 10⁻¹² × 0.0365²)
E₁ = -57.02 × 10⁴ N /C
So the strength at the mid point will be E = E₁ - E₂
E = 53.62 × 10⁴ - (-57.02 × 10⁴)
E = 110.63 × 10⁴ N/C
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circuit b has battery voltage = 9.0 volts and three identical bulbs. with the switch open, lamps 1 and 2 are in series, and the ammeter reads an initial current of 0.60 a.
To calculate the total current of the circuit, we must first determine the equivalent resistance of the series connection of lights 1 and 2, which can be accomplished using Ohm's law.
I = V/R. Because we know the current (0.60 A) and the voltage (9.0 V), we can calculate the equivalent resistance: R = V/I = 9.0 / 0.60 = 15. We can use the same approach to determine the current through each light now that we know the equivalent resistance of lamps 1 and 2. I = V/R = 9.0 / 15 = 0.6 A. Finally, in order to compute the current through lamp 3, we must first calculate the total resistance of the complete circuit with the switch closed, which can be calculated as the sum of the equivalent resistances of lights 1 and 2. and 2, as well as the lamp's resistance 3. If the lights are similar, they will have the same resistance, and we can compute the total resistance using the current calculated in the previous step (0.6 A). The current flowing through bulb 3 may therefore be calculated using Ohm's law: I = V/R.
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Speed= 11.8m/ S +9%
what's s? how do I find it??
Answer:
Explanation:
Not sure what you're asking here, but I'll take a guess. If the question is what is the final speed if there is a 9% increase in speed from a starting speed of 11.8 m/s, then the answer is:
(11.8 m/s) + (11.8 m/s)(0.09) = 12.86 m/s
A permanent test instrument is a device that is installed in a process or at a bench to continually measure and display quantities.
True False
The given statement 'A permanent test instrument is a device that is installed in a process or at a bench to continually measure and display quantities' is true.
A measuring instrument is a device used to measure a physical amount. Measurement, in the physical sciences, quality control, and engineering, is the process of gathering and contrasting the physical amounts of things that actually happen in the real world. As units, pre-defined standard things and occurrences are used, and the measuring procedure yields a number that connects the subject-matter under investigation to the used unit of measurement. These numerical relationships are attained through the employment of measuring devices and formal test methodologies that specify the device's use.
The instrument error and measurement uncertainty that affect all measuring devices varies in severity. From basic tools like stopwatches and rulers to electron microscopes and particle accelerators, these instruments can be used for various purposes.
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consider a typical mammalian cell to be a cube of 20 microns (µ) on an edge. compute the volume of the cell in cm3.
A typical mammalian cell to be a cube of 20 microns (µ) on an edge has the volume of the cell in cm3 is 8 x 10-9 cm3.
Why does the volume of a cell matter?
Every cell has a limit of surface area to volume ratio to ensure that the exchange of resources and waste occurs quickly enough for the cell to survive. If cells were too big, diffusion would take an extremely long time, and a cell could die from starvation or poison itself with its wastes.
Given mammalian cell to be a cube with edge length 20 microns
1 micron = 10-4 cm
So, Edge length = 20 micron or 20 x 10-4 cm or 0.002 cm
Volume of cell which is of cube shape = (Edge length)3 = (0.002 cm)3 = 0.000000008 = 8 x 10-9 cm3.
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2.2.1. collapse depth (or crush depth) is the submerged depth that a submarine cannot exceed without collapsing because of the surrounding water pressure. the collapse depth of modern submarines is not quite a kilometer . assuming seawater to be incompressible , what is the crush depth pressure in and ? is the pressure you computed absolute or gauge pressure?
The collapse depth of a submarine is the depth at which the surrounding water pressure becomes great enough to cause the submarine's hull to collapse. At this depth, the pressure is sufficient to cause the submarine's material to reach its crush strength.
Given that the collapse depth of modern submarines is around a kilometer, and assuming seawater to be incompressible, the crush depth pressure can be calculated as follows:
Pressure = density of seawater * depth * gravitational acceleration
Density of seawater = 1025 kg/m^3
Gravitational acceleration = 9.8 m/s^2
Crush depth = 1000 m
So the pressure at crush depth would be:
Pressure = 1025 kg/m^3 * 1000 m * 9.8 m/s^2 = 10,250,000 N/m^2 = 10.25 MPa
The pressure you computed is an absolute pressure. It is the force per unit area exerted by the water on the submarine's hull. It is measured relative to a perfect vacuum and it is independent of any other external pressure.
The main reason why vegetables take longer to cook in boiling water at high altitudes is because:
A Water boils at a higher temperature with higher altitude
B The temperature of the boiling water decreases with increasing altitude
C There is less oxygen in the air at high altitude
D Saturation vapor pressure decreases with increasing altitude
The main reason why vegetables take longer to cook in boiling water at high altitudes is because the temperature of the boiling water decreases with increasing altitude. Correct option is B.
High altitudes have relatively low air pressure when compared to sea level. High altitude cooking is different from cooking at sea level. As a result, at high altitudes, water boils at a lower temperature. When air pressure is lower, it requires less energy to bring water to the boiling point.
Foods cooked by boiling or simmering will cook at a lower temperature and take longer to cook because water boils at a lower temperature at higher altitudes. Low humidity is common in high altitude regions, which can speed up the evaporation of moisture from food during cooking.
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calculate the static deflection in a linear spring of stiffness 4000 n/m when a mass of 20 kg is hanging from it.
The static deflection in the linear spring with a stiffness of 4000 N/m and a mass of 20 kg hanging from it is 0.049 meters, or 49 millimeters. We can use Hooke's law to calculate this.
The static deflection in a linear spring is the change in length of the spring when a force is applied to it. The force applied to the spring can be calculated by multiplying the mass of the object hanging from the spring by the acceleration due to gravity (g), which is 9.8 m/s^2. The formula for the force applied to the spring is given by F = mg, where m is the mass of the object and g is the acceleration due to gravity.
The deflection of the spring can then be calculated using Hooke's Law, which states that the force applied to a spring is proportional to its extension (x) and is given by F = kx, k being spring constant. Solving for x, we get x = F/k. Substituting the values, we get x = (20 kg * 9.8 m/s^2) / 4000 N/m = 0.049 m.
Therefore, the static deflection in the linear spring with a stiffness of 4000 N/m and a mass of 20 kg hanging from it is 0.049 meters, or 49 millimeters.
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Why do you wet the lighter and dry it to best of your ability prior to taking its mass?
Although it appears that the soil particles are touching, there are gaps between them. Pores are the name for these voids.
Dry soil can be observed to include a variety of particles of various mass when it is crushed in the hand. These are known as mineral particles, and the majority of them come from the breakdown of rocks. Some are known as organic particles, and some come from leftovers of plants or animals (rotting leaves, bones, etc). (or organic matter). Although it appears that the soil particles are touching, there are gaps between them. Pores are the name for these voids. The pores in "dry" soil are primarily air-filled. The pores mostly contain water after rain or irrigation. In the soil is living material. Live roots, beetles, worms, larvae, and other organisms are all possible. By aerating the soil, they aid to improve the plant roots' growing environment.
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You break a piece of Styrofoam packing material, and it releases lots of little spheres whose electric charge makes them stick annoyingly to you. If two of the spheres carry equal charges and repel with a force of 22 { mN} when they're 16 { mm} apart, what's the magnitude of the charge on each?
The magnitude of the charge on each sphere is 1.51 x 10^-7 C.
The magnitude of the charge on each sphere can be calculated using Coulomb's law:
F = k * q1 * q2 / r^2
where F is the force of repulsion, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges on the spheres, and r is the separation distance between the spheres.
Rearranging the equation to solve for the charge:
q = sqrt(F * r^2 / k)
Substituting the given values:
q = sqrt(22 * 10^-3 N * 16 * 10^-3 m^2 / 8.99 * 10^9 Nm^2/C^2) = 1.51 x 10^-7 C.
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help!! Rochelle is a chemist who primarily studies thermodynamics. Which of the following topics might Rochelle research for her job? chose all that apply
a.the vibrations that are produced by musical instruments
b.the temperature required to melt a certain metal
c.the amount of heat produced by a certain reaction
d.how a new engine converts thermal energy into work
e.how light is affected by passing through a plastic lens
f.how subatomic particles behave at extremely high speeds
Rochelle is a chemist who mainly studies thermodynamics, so she is likely to research: b. the temperature required to melt a certain metal, c. the amount of heat produced by a certain reaction and d. how a new engine transforms thermal energy into work.
Describe Thermal energy.Thermal energy is a form of energy that results from the movement of particles in matter. It is the energy that is associated with the temperature of a substance and is proportional to the amount of heat it contains.
What is the significance of thermal energy?Thermal energy is a form of internal energy and is often used to describe the energy stored in a system due to the random motion of its constituent particles. Thermal energy can be transferred from one object to another through heat conduction, convection, and radiation.
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physics ia how does the concentration of salt in water affect the specific heat capacity?
The concentration of salt in water affects the specific heat capacity by changing the thermal properties of the solution, causing it to require less heat to be raised in temperature.
The specific heat capacity of water is the amount of heat required to raise the temperature of a certain mass of water by 1 degree Celsius. The concentration of salt in water affects its specific heat capacity because the presence of ions in the solution changes the thermal properties of the water.
As the concentration of salt in water increases, the specific heat capacity of the solution decreases. This is because the ions in the salt solution require less heat to be raised in temperature than pure water molecules. Additionally, the ions in the salt solution also increase the mobility of water molecules, causing them to transfer heat more efficiently and therefore, the heat energy required to raise the temperature of the solution is reduced.
It should be noted that the effect of salt concentration on specific heat capacity is small, and significant changes in specific heat capacity usually require very high salt concentrations. Nevertheless, the change in specific heat capacity can have a significant impact on the thermal dynamics of systems such as oceans, which contain high salt concentrations.
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at 25°c, water has a density of 0.9982 g/ml. if the unknown liquid had been water, what volume would it have had?
Water should have a density of about 1 g/cm3. For 100, 50, or 25 mL, this is accurate.
Pour water into a graduated cylinder, measure the volume, submerge the object, and measure the volume again. The volume of the object is the difference between the two volume measurements. To determine the object's density, just divide the mass by the volume. At 25 °C, pure water has a concentration of 55.5 M (mol/L). H+ and OH- ions are ionized to a minor extent. Electrical conductivity studies show that the equilibrium constant, also known as the dissociation constant, is 1.8 10-16 M at 25 °C.
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the coefficient of static friction between teflon and scram- bled eggs is about 0.04. what is the smallest angle from the hori- zontal that will cause the eggs to slide across the bottom of a teflon-coated skillet?
The smallest angle from the horizontal that will cause the eggs to slide across the bottom of a teflon-coated skillet is approximately 2.3 degrees.
Calculating the maximum angle of static friction yields the minimal angle that will cause an item to slide. The coefficient of static friction between two objects is defined as the ratio of the maximal frictional force to the normal force. The maximal frictional force is denoted as follows:
f_max = friction coefficient * normal force
The normal force is equal to the weight of the object, and can be represented as follows:
N = m * g
where m is the mass of the object, and
g is the acceleration due to gravity ([tex]9.8 m/s^2[/tex]).
We can then use the maximum frictional force to find the maximum angle of static friction, using the equation:
tan([tex]\theta_{max}[/tex]) = [tex]f_{max} / N[/tex]
The minimum angle that will cause an object to slide is equal to the maximum angle of static friction.
Given that the coefficient of static friction between teflon and scrambled eggs is 0.04,
we can find the minimum angle that will cause the eggs to slide as follows:
[tex]tan(\theta_{min}) = 0.04 = f_{max} / (m \times g)[/tex]
Solving for [tex]\theta_{min}[/tex], we find:
[tex]\theta_{min} = tan^{-1(0.04)}[/tex]
= 2.3 degrees (to the nearest tenth of a degree)
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possible mountain wave turbulence could be anticipated when winds of 40 knots or greater blow
Mountain wave turbulence can occur when winds reach 40 knots or higher.
Mountain wave turbulence is a type of turbulence that can occur when strong winds blow over mountains or other obstructions. The wind creates a wave-like pattern in the atmosphere, which can cause turbulence for aircraft flying through it.
This turbulence can range from mild to severe and can make flying challenging and potentially dangerous. To anticipate the possibility of mountain wave turbulence, it is important to monitor wind conditions and pay attention to wind speeds.
If winds are 40 knots or higher, there is an increased likelihood of mountain wave turbulence and it is important for pilots to take precautions and plan their flight accordingly.
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