at a certain temperature, 725 k, kp for the reaction,h2(g) i2(g) ⇌ 2 hi(g) is 9.96 x 1012.calculate the value of δgo in kj for the reaction at 725 k.

Answers

Answer 1

The value of ΔGo (standard Gibbs free energy change) for the reaction at 725 K is -180 kJ/mol.

The value of ΔGo (standard Gibbs free energy change) for the reaction can be calculated using the equation:

ΔGo = - RT ln(Kp)

where R is the gas constant (8.314 J/mol K), T is the temperature in kelvin, and Kp is the equilibrium constant at the given temperature.

First, we need to convert the equilibrium constant Kp from units of pressure to units of concentration. The equilibrium constant expression is:

Kp = (P(HI))^2 / (P(H2) x P(I2))

At 725 K, assume that the total pressure of the system is 1 atm. Therefore, we can use the ideal gas law to convert partial pressures to molar concentrations:

P(H2) = [H2]RT = [H2](1 atm) / (8.314 J/mol K x 725 K) = 0.000157 M

P(I2) = [I2]RT = [I2](1 atm) / (8.314 J/mol K x 725 K) = 0.000157 M

P(HI) = [HI]RT = [HI](1 atm) / (8.314 J/mol K x 725 K) = 0.00176 M

Substituting these values into the expression for Kp:

Kp = (0.00176 M)^2 / (0.000157 M x 0.000157 M)

= 9.96 x 10^12

Now we can calculate ΔGo:

ΔGo = - (8.314 J/mol K) x (725 K) x ln(9.96 x 10^12) / 1000

= -180 kJ/mol

The calculation of ΔGo for a reaction using the equilibrium constant Kp requires the conversion of partial pressures to molar concentrations, and the application of the equation ΔGo = - RT ln(Kp) using appropriate units for R, T, and Kp.

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Related Questions

what is the coordination number for each of the following complexes or compounds? [co(nh3)4cl2] [ca(edta)]2− [zn(nh3)4]2 [ag(nh3)2]no3

Answers

The coordination numbers for the given complexes or compounds are as follows: [Co(NH3)4Cl2] has a coordination number of 6, [Ca(edta)]2− has a coordination number of 8, [Zn(NH3)4]2 has a coordination number of 4, and [Ag(NH3)2]NO3 has a coordination number of 2.

The coordination number refers to the number of ligands directly bonded to the central metal ion in a coordination compound. It indicates the number of donor atoms surrounding the central metal atom.

[Co(NH3)4Cl2]: In this complex, there are four ammonia (NH3) ligands and two chloride (Cl-) ligands bonded to the central cobalt (Co) atom. Therefore, the coordination number is 6.

[Ca(edta)]2−: In this complex, the ethylenediaminetetraacetate (edta) ligand forms multiple bonds with the central calcium (Ca) ion. The edta ligand has four carboxylate groups, each with two oxygen atoms, which coordinate with the metal ion. Hence, the coordination number is 8.

[Zn(NH3)4]2: In this complex, there are four ammonia (NH3) ligands bonded to the central zinc (Zn) atom. Therefore, the coordination number is 4.

[Ag(NH3)2]NO3: In this complex, there are two ammonia (NH3) ligands bonded to the central silver (Ag) atom. Hence, the coordination number is 2.

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which compound would be most rapidly hydrolyzed by aqueous hc to give methanol as one of the products?

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We can deduce here that the compound that would be most rapidly hydrolyzed by aqueous HCl to give methanol as one of the products is: B. [tex]CH_{3} OCH_{2} CH_{2} OCH_{3}[/tex]

What is a compound?

A compound is a substance made up of two or more separate elements that are chemically linked together in a specific weight-to-volume ratio. A chemical formula that lists the number and types of atoms in a molecule to indicate the chemical structure of a compound.

Chemical reactions can create compounds, which differ from their constituent elements in terms of their properties.

Option B is correct because:

It has two polar ends.Water is also polar.

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The complete question is seen below:

Which compound would be most rapidly hydrolyzed by aqueous HCl to give methanol as one of the products?

A. [tex]CH_{3}OCH_{2} CH_{2} CH_{3}[/tex]

B. [tex]CH_{3} OCH_{2} CH_{2} OCH_{3}[/tex]

C. [tex]CH_{3}OCH_{2}CH_{2} OH[/tex]

4a. determine the ph of 1.3 x 10-6 m naoh. 4b. is this solution acidic, basic or neutral?

Answers

4a. To determine the pH of 1.3 x 10-6 M NaOH, we can use the formula pH = -log[H+]. Since NaOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-).

The concentration of hydroxide ions can be calculated using the formula [OH-] = Kw/[H+], where Kw is the ion product constant of water (1.0 x 10^-14 at 25°C). At room temperature, Kw = [H+][OH-], so [OH-] = Kw/[H+] = 1.0 x 10^-14/1.3 x 10^-6 = 7.7 x 10^-9 M. Now that we know the concentration of hydroxide ions, we can plug it into the pH formula: pH = -log(7.7 x 10^-9) = 8.11. Therefore, the pH of 1.3 x 10^-6 M NaOH is 8.11. 4b. A pH of 8.11 indicates that the solution is basic since it is greater than 7 (which is considered neutral). Basic solutions have a higher concentration of hydroxide ions than hydrogen ions (H+), resulting in a pH above 7. Therefore, the solution of 1.3 x 10^-6 M NaOH is basic.

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name the following alkene

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The name of the alkene displayed in the diagram is B. 2-methyl-1-propene.

What are alkenes?

Alkenes are a class of unsaturated hydrocarbons that contain at least one carbon-carbon double bond. They have the general chemical formula CnH₂n and are typically more reactive than their corresponding alkanes. Because of their double bond, alkenes can undergo addition reactions with other chemicals, such as hydrogen, halogens, and water.

Some common examples of alkenes include ethylene (C₂H₄) and propylene (C₃H₆), which are widely used in the chemical industry as starting materials for the production of plastics, synthetic rubber, and other materials.

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if a proton and an electron have the same de broglie wavelengths, which one is moving faster? group of answer choices the electron the proton they both have the same speed.

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The electron is moving faster than the proton if they have the same de Broglie wavelength.

The de Broglie wavelength of a particle is given by the equation:

λ = h / p

where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.

If a proton and an electron have the same de Broglie wavelength, then we can equate their respective momenta and write:

h / p_proton = h / p_electron

Simplifying the above equation, we get:

p_proton = p_electron

This means that the proton and electron have the same momentum. However, the momentum of a particle is related to its velocity by the equation:

p = mv

where m is the mass of the particle and v is its velocity.

Since the mass of a proton is much greater than the mass of an electron, the velocity of the electron must be much greater than that of the proton in order for both particles to have the same momentum.

Therefore, the electron is moving faster than the proton if they have the same de Broglie wavelength.

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Suppose a 500 mL beaker is filled to the brim with ethyl alcohol at a temperature of 5 degrees Celsius. Assume the beaker is made of tempered glass and has effectively 0 thermal expansion. What volume in milliters will overflow the beaker when its temperature reaches 21 degrees Celsius? The coefficient of volume expansion got ethyl alcohol is .0011/degrees Celsius. What volume of water in milliliters will overflow under the same conditions? The coefficient of volume expansion for water is .00021/degrees Celsius.

Answers

The temperature of the water in the beaker is raised to 21 degrees Celsius, 1.68 mL of water will overflow from the beaker.

When the ethyl alcohol in the beaker is heated to 21 degrees Celsius, its volume will increase due to thermal expansion. The coefficient of volume expansion for ethyl alcohol is given as 0.0011/degree Celsius. The increase in volume can be calculated using the formula:
ΔV = V₀ * β * ΔT
Where,
ΔV = Increase in volume
V₀ = Initial volume
β = Coefficient of volume expansion
ΔT = Change in temperature
Here, V₀ = 500 mL, β = 0.0011/degree Celsius and ΔT = (21 - 5) = 16 degrees Celsius
Plugging these values in the above formula, we get:
ΔV = 500 mL * 0.0011/degree Celsius * 16 degrees Celsius
ΔV = 8.8 mL
Therefore, when the temperature of the ethyl alcohol in the beaker is raised to 21 degrees Celsius, 8.8 mL of alcohol will overflow from the beaker.
Similarly, we can calculate the volume of water that will overflow under the same conditions. The coefficient of volume expansion for water is given as 0.00021/degree Celsius. Using the same formula as above, we get:
ΔV = 500 mL * 0.00021/degree Celsius * 16 degrees Celsius
ΔV = 1.68 mL
Therefore, when the temperature of the water in the beaker is raised to 21 degrees Celsius, 1.68 mL of water will overflow from the beaker.

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Study the Atomic radius (nm) Ionic radius (nm) 0.114 0.195 0.072 0.136 0.133 0.216 Z 0.099 0.181 (a) Would these form part of a metallic or a non-metallic group? Explain (b) Suggest an element in the table above likely to be the most reactive. Explain Element W X Y​

Answers

By the comparing the atomic radii of all of the elements,  one can notice that they are very small. Hence it shows that they may be  non-metallic group.

Reactivity in components can be affected by different variables, such as electron setup and electronegativity and as such since all are low and there is no much information, it is hard to know which is  mostly reactive

What is the atomic radius?

Metallic elements for the most part have bigger nuclear radii compared to non-metallic components. since metallic elements tend to lose electrons and shape cations, coming about in a lower  form in successful atomic charge and a boast in nuclear form.

Note that from the question:

Element W  = atomic radius of 0.114 nm

                           an ionic radius of 0.195 nm.

Element X  =  atomic radius of 0.072 nm

                       an  ionic radius of 0.136 nm.

Element Y  =  atomic radius of 0.133 nm

                       an ionic radius of 0.216 nm.

Element Z   =  atomic radius of 0.099

                            an ionic radius of 0.181

Non-metallic components, on the other hand, tend to pick up electrons and shape anions, coming about in a littler nuclear estimate.

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a procedural chanin in this experiment would be required if a student wanted to determine the acidity of tomato juice by titraing a juice sample with naoh solution. briefly explain

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A procedural chain would be required in this experiment because it involves multiple steps that must be followed in a specific order to achieve accurate results. The student would need to first prepare the tomato juice sample, followed by adding a specific indicator to the sample to help visualize the endpoint of the titration.

Next, the student would need to carefully add the standardized NaOH solution to the sample while continuously stirring until the endpoint is reached. Finally, the student would need to record the volume of NaOH solution used to neutralize the sample, which can be used to calculate the acidity of the tomato juice. A procedural chain ensures that each step is carried out correctly and in the right order to obtain reliable and accurate results.


To determine the acidity of tomato juice by titrating a juice sample with NaOH solution, a procedural chain is required. First, prepare the tomato juice sample by filtering out any pulp or seeds. Next, measure a specific volume of the sample using a burette or pipette and place it into a conical flask. Add a few drops of a suitable indicator, such as phenolphthalein, which changes color at the endpoint of the titration. Then, fill a burette with the standardized NaOH solution. Slowly add the NaOH solution to the tomato juice while stirring until the endpoint is reached, indicated by a color change. Record the volume of NaOH used, and use the volume and concentration to calculate the acidity of the tomato juice.

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A saturated solution of AgI has [Ag+]= 9.2×10−9 M and [I−]= 9.2×10−9 M.What is the value of Ksp for AgI?​

Answers

The value of Ksp for AgI is 8.464 × 10^(-17) M^2.

To determine the value of the solubility product constant (Ksp) for silver iodide (AgI) using the given concentrations of silver ions ([Ag+]) and iodide ions ([I-]), we can set up the equilibrium expression for the dissociation of AgI:

AgI ⇌ Ag+ + I-

The balanced equation tells us that the molar ratio of AgI to Ag+ and I- is 1:1:1. Therefore, at equilibrium, the concentration of Ag+ and I- is equal to the concentration of AgI.

Given [Ag+] = 9.2 × 10^(-9) M and [I-] = 9.2 × 10^(-9) M, we can substitute these values into the equilibrium expression:

Ksp = [Ag+][I-]

Ksp = (9.2 × 10^(-9) M)(9.2 × 10^(-9) M)

Ksp = 8.464 × 10^(-17) M^2

Therefore, the value of Ksp for AgI is 8.464 × 10^(-17) M^2.

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Which of the following bases would be most suitable for preparing a buffer of pH 9.0 and give reason: NH3 (Kb =1.75 x10-5) or H2NNH2 (Kb =3.0 X10-6)?

Answers

The most suitable base for preparing a buffer of pH 9.0 would be NH3. This is because NH3 has a higher Kb value than H2NNH2, which means it is a stronger base and can more effectively neutralize acidic substances in the buffer.

NH3 has a pKa value of 9.25, which is close to the desired pH of 9.0. This means that the buffer will be most effective at maintaining its pH within a narrow range around 9.0, as NH3 will readily accept protons to maintain equilibrium with NH4+. Overall, while both bases could potentially be used to prepare a buffer of pH 9.0, NH3 is the most suitable option due to its higher Kb value and pKa proximity to the desired pH.

These bases can be combined with their corresponding weak acids in appropriate proportions to make a buffer solution with a pH of 9.0. The actual pH of the buffer will depend on the ratio of the weak acid to its conjugate base and the concentration of the buffer components.

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What is the concentration of a saturated AgC2H3O2 solution? (Ksp=1.94x10^-3)

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The concentration of a saturated [tex]AgC_2H_3O_2[/tex] solution is 0.044 M.

The equilibrium expression for the dissociation of [tex]AgC_2H_3O_2[/tex] is:

[tex]AgC_2H_3O_2[/tex](s) ⇌ Ag+(aq) + [tex]C_2H_3O_2[/tex]-(aq)

We can assume that the concentration of Ag+ is equal to the solubility of [tex]AgC_2H_3O_2[/tex]. At equilibrium, the dissolution rate equals the precipitation rate, and the solution is said to be saturated. Therefore, we can use the Ksp value to calculate the concentration of Ag+ ions in a saturated solution of [tex]AgC_2H_3O_2[/tex]

The Ksp expression for the above equilibrium is:

Ksp = [Ag+][[tex]C_2H_3O_2[/tex]-]

At saturation, the concentration of Ag+ and [tex]C_2H_3O_2[/tex]- ions in solution will be equal. Let x be the concentration of Ag+ and [tex]C_2H_3O_2[/tex]- ions in solution.

Therefore, we can write:

Ksp = x^2

Substituting the value of Ksp, we get:

1.94 x 10^-3 = x^2

Taking the square root on both sides, we get:

x = 0.044 M

Therefore, the concentration of a saturated [tex]AgC_2H_3O_2[/tex] solution is 0.044 M.

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what is the maximum mass of lead (ii) chloride that you can dissolve when making a 100.0 ml solution?

Answers

The maximum mass of lead (II) chloride which can be dissolved in a 100.0 ml solution is 0.16 g.

Lead (II) chloride is the chemical compound having chemical formula PbCl₂. It is a white solid, highly soluble in water, and is commonly used in the production of lead, and inorganic pigments.

To determine the maximum mass of lead (II) chloride that can be dissolved in a 100.0 ml solution, we need to know the solubility of lead (II) chloride in the solvent being used.

Assuming the solvent is water at room temperature (25°C), the solubility of lead (II) chloride is approximately 1.6 g/L. Therefore, the maximum mass of lead (II) chloride which can be dissolved in a 100.0 ml solution is;

1.6 g/L x 0.1 L = 0.16 g

Therefore, the maximum mass of lead (II) chloride is 0.16 g.

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what is your view of the use of technology to enhance sustainability in transportation systems in the future?

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In my view, the use of technology in transportation systems has great potential to enhance sustainability in the future.

With the increasing concerns over the impact of transportation on the environment, it is important that we explore ways to reduce emissions and energy consumption. Technology can help us achieve this by improving the efficiency of transportation systems, enabling the use of alternative fuels, and promoting the use of public transportation.

For example, the use of electric and hybrid vehicles, as well as advancements in fuel cell technology, can greatly reduce emissions and promote cleaner air. In addition, the use of smart traffic management systems and connected vehicles can help reduce congestion and improve fuel efficiency.

However, it is important to note that technology alone cannot solve the sustainability challenges facing transportation systems. It is also necessary to implement policies and incentives that promote sustainable transportation practices and behavior. Overall, technology can play a vital role in enhancing sustainability in transportation, but it must be used in conjunction with other measures to achieve meaningful impact.

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without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the following exothermic reaction. 2so2(g) o2(g)2so3(g)

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For the exothermic reaction 2SO2(g) + O2(g) -> 2SO3(g), the enthalpy change (∆H) and entropy change (∆S) will have negative signs. The sign of the Gibbs free energy change (∆G) will depend on the temperature. The numerical sign of the reaction quotient (Q) cannot be determined without specific concentration or pressure values.

For the exothermic reaction 2SO2(g) + O2(g) -> 2SO3(g), the signs of various thermodynamic properties can be determined based on general principles. The enthalpy change (∆H), entropy change (∆S), Gibbs free energy change (∆G), and the reaction quotient (Q) can be matched with their appropriate numerical signs.

In an exothermic reaction, heat is released, indicating a negative value for the enthalpy change (∆H). Thus, for the given reaction, ∆H will have a negative sign.

Entropy change (∆S) is related to the disorder of the system. Since the reaction involves the formation of two moles of SO3 from fewer moles of reactants (2SO2 and O2), there is a decrease in the number of moles. Consequently, the overall disorder of the system decreases, resulting in a negative ∆S.

The sign of the Gibbs free energy change (∆G) can be determined using the equation ∆G = ∆H - T∆S, where T represents temperature. Since both ∆H and ∆S are negative for an exothermic reaction, the sign of ∆G will depend on the temperature. At lower temperatures, the ∆H term dominates, and ∆G will be negative. At higher temperatures, the ∆S term becomes more significant, and ∆G can be positive.

The reaction quotient (Q) can be determined by comparing the concentrations or pressures of the reactants and products. Without specific concentration or pressure values, the numerical sign of Q cannot be determined.

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a gas has a pressure of 995.5 mm hg at 0.1 oc. what is the temperature at standard pressure? gay lussacs law

Answers

The temperature at standard pressure is approximately -63.05 C (209.1 K - 273.15 K).

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature, provided that the volume and the amount of gas remain constant. Using this law, we can find the temperature at standard pressure.

First, we need to convert the given pressure from mm Hg to atm, which is the unit of pressure used for standard pressure. One atm is defined as 760 mm Hg, so 995.5 mm Hg is equivalent to 1.308 atm (995.5 mm Hg / 760 mm Hg/atm).

Next, we can set up the equation using Gay-Lussac's law:

[tex]$\frac{P_1}{T_1} = \frac{P_2}{T_2}$[/tex]

where [tex]P_1[/tex] and [tex]T_1[/tex] are the initial pressure and temperature, and [tex]P_2[/tex] and [tex]T_2[/tex] are the final pressure and temperature. We know that [tex]P_1[/tex] = 1.308 atm and [tex]T_1[/tex] = 0.1 oC (which we need to convert to Kelvin by adding 273.15 K). We also know that [tex]P_2[/tex] = 1 atm, since that is the standard pressure. Solving for [tex]T_2[/tex], we get:

[tex]$T_2 = \frac{P_2}{P_1} \cdot T_1$[/tex]

= (1 atm/1.308 atm) x (0.1 oC + 273.15) K

= 209.1 K

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What is the predominant form of ethylenediamine at pH 6.441 and pH 9.375? Ethylenediamine has pKb values of 4.072 (pKb1) and 7.152 (pKb2).

Answers

Ethylenediamine is a weak base with two pKb values, and it can exist in three different forms: as a fully protonated cation, a partially protonated zwitterion, or a fully deprotonated anion.

To determine the predominant form at a given pH, we need to compare the pH to the pKb values.

At pH 6.441, which is between the two pKb values, ethylenediamine is partially protonated. The dominant species will be the zwitterion, which has a positive charge on one nitrogen and a negative charge on the other nitrogen.

At pH 9.375, which is higher than both pKb values, ethylenediamine is fully deprotonated. The dominant species will be the anion, which has both nitrogens with a negative charge.

Therefore, at pH 6.441, the predominant form of ethylenediamine is the zwitterion, and at pH 9.375, the predominant form is the anion.

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a 0.05 m solution of an unknown acid is tested and its ph is measured at 2.4. calculate the ka and pka of this acid.

Answers

When, a 0.05 m solution of an unknown acid is tested and its ph is measured at 2.4. Then, the Ka of the unknown acid is approximately [tex]10^{(-2.4)}[/tex], and its pKa is approximately 2.4.

To calculate the Ka and pKa of an unknown acid based on its pH, you need to use the relationship between the concentration of the acid and the concentration of its conjugate base. Here's how you can proceed;

Convert the pH to the concentration of H⁺ ions.

Since the pH is given as 2.4, the concentration of H⁺ ions can be calculated using the equation:

[H⁺] = [tex]10^{(-pH)}[/tex]

[H⁺] = [tex]10^{(-2.4)}[/tex]

Determine the concentration of the acid and its conjugate base.

In this case, the acid is the unknown species, so let's assume its concentration is 'x' M.

The concentration of the conjugate base will also be 'x' M since the acid is a monoprotic acid.

Write the equilibrium expression for the dissociation of the acid.

The dissociation of the acid will be represented as follows;

HA ⇋ H⁺ + A⁻

Set up the expression for the acid dissociation constant (Ka).

The Ka expression is;

Ka = [H⁺][A⁻] / [HA]

Substitute the concentrations into the Ka expression.

Ka = ([H⁺][A⁻]) / [HA]

Ka = ([H⁺][x]) / [x]

Since the concentration of the conjugate base is also 'x' M, the expression simplifies to; Ka = [H⁺]

Calculate the Ka and pKa.

Substituting the calculated [H⁺] value into the Ka expression;

Ka = [H⁺] = [tex]10^{(-2.4)}[/tex]

To find pKa, you can take the negative logarithm (base 10) of Ka:

pKa = -log10(Ka)

Calculating pKa;

pKa = -log10([tex]10^{(-2.4)}[/tex])

Simplifying;

pKa = 2.4

Therefore, the Ka of the unknown acid is approximately [tex]10^{(-2.4)}[/tex], and its pKa is approximately 2.4.

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what mass of gold is produced when 21.1 a of current are passed through a gold solution for 37.0 min ? express your answer with the appropriate units.

Answers

The mass of gold that is produced when 21.1 a of current are passed through a gold solution for 37.0 min is 31.87 g

Using the formula

m = atomic mass  × It /nF

Where m is the mass

n is the number of equivalents

F is the Faraday constant ( F = 96485 C)

I is the current

and t is the time

From the given information

I = 21.1 A

t = 37.0 min = 37.0 × 60

t = 2220 secs

For gold

Atomic mass = 196.97 g/mol

and n = 3

Putting these parameters into the formula, we get

m = 196.97 gmol⁻¹ × 21.1 A × 2220 sec / 3 × 96485

m= 9226468.74/ 289455

m= 31.87 g

Hence, the mass of gold that is produced is 31,87 g

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A 1.83-L sample of aqueous solution contains 1.05 moles of calcium nitrate. What is the molarity of the calcium nitrate in the solution? Select one: a. 4.88x10-1 M b. 1.74 M c. 5.74x10-1 M d. 2.05 M

Answers

The molarity of calcium nitrate in the solution is 0.574 M (option c).

Molarity is defined as the number of moles of solute per liter of solution. To find the molarity of calcium nitrate in the given solution, we need to divide the number of moles of calcium nitrate by the volume of the solution in liters.

Number of moles of Ca(NO3)2 = 1.05 mol

Volume of solution = 1.83 L

Molarity of Ca(NO3)2 = number of moles of Ca(NO3)2 / volume of solution

Molarity of Ca(NO3)2 = 1.05 mol / 1.83 L = 0.574 M

Therefore, the molarity of calcium nitrate in the solution is 0.574 M (option c).

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C
Unit Test
Unit Test Review Active
G
If a person has the values for an object's density and volume, what value can be calculated?
the object's size
the object's mass
the shape the object forms in a container
the amount of space the object takes up

Answers

If a person has the values for an object's density and volume, they can calculate the object's mass. Hence option B) is correct.

If a person has the values for an object's density and volume, they can calculate the object's mass. Density is defined as the mass per unit volume of an object. Mathematically, density is calculated by dividing the mass of an object by its volume. Rearranging the equation, we find that mass is equal to the product of density and volume. Therefore, if the density and volume of an object are known, multiplying them together will yield the object's mass. The other options mentioned in the question are not directly calculated using density and volume. The object's size is a broader term that encompasses various dimensions and may not be specifically derived from density and volume alone. The shape the object forms in a container and the amount of space the object takes up are influenced by both the object's mass and its dimensions, which are not solely determined by density and volume. Therefore option B) is correct.

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reducing the amount of a reactant from a system that is at equilibrium causes an initial change in

Answers

An initial change brought on by cutting down on a reactant in an equilibrium system is an increase in the concentration of the products. Here option B is the correct answer.

When a reactant is reduced in a system at equilibrium, the system is no longer in equilibrium and will try to re-establish equilibrium. The system will do this by shifting the equilibrium position in the direction that reduces the effect of the change. In this case, reducing the amount of a reactant will cause the system to shift in the direction that produces more of that reactant.

This means that there will be an initial decrease in the concentration of the remaining reactants, as the system tries to produce more of the reactant that was reduced. At the same time, there will be an increase in the concentration of the products, as the increased production of the reactant leads to increased production of the products.

However, as the system moves towards a new equilibrium position, the concentrations of all species will change until a new equilibrium is established. This new equilibrium will depend on the specific equilibrium reaction and conditions of the system.

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Complete question:

Which of the following is an initial change caused by reducing the amount of a reactant from a system that is at equilibrium?

A) An increase in the concentration of the remaining reactants.

B) An increase in the concentration of the products.

C) A decrease in the concentration of the remaining reactants.

D) A decrease in the concentration of the products.

when 28.3 g of methane and 47.5 g of chlorine gas undergo a reaction that has a 72.8% yield, what mass of chloromethane (ch3cl) forms? hydrogen chloride also forms. g ch3cl

Answers

When 28.3 g of methane and 47.5 g of chlorine gas undergo a reaction that has a 72.8% yield. Then, the mass of CH₃Cl that forms is 24.66 g.

The balanced chemical equation for the reaction between methane and chlorine gas is;

CH₄ + Cl₂ → CH₃Cl + HCl

The molar mass of methane (CH₄) is 16.04 g/mol, and the molar mass of chlorine gas (Cl₂) is 70.90 g/mol. To determine which reactant is limiting, we need to calculate the number of moles of each;

moles of CH₄ = 28.3 g / 16.04 g/mol = 1.76 mol

moles of Cl₂ = 47.5 g / 70.90 g/mol = 0.67 mol

Since methane has more moles than chlorine gas, chlorine gas is the limiting reactant.

To determine the theoretical yield of CH₃Cl;

moles of CH₃Cl = moles of Cl₂ (since the reaction is 1:1)

moles of CH₃Cl = 0.67 mol

The molar mass of CH₃Cl is 50.49 g/mol, so the theoretical yield of CH₃Cl is;

mass of CH₃Cl = moles of CH₃Cl x molar mass of CH₃Cl

mass of CH₃Cl = 0.67 mol x 50.49 g/mol = 33.89 g

mass of CH₃Cl = moles of CH₃Cl x molar mass of CH₃Cl

mass of CH₃Cl = 0.67 mol x 50.49 g/mol = 33.89 g

Since the yield is given as 72.8%, we need to multiply the theoretical yield by the yield percentage to get the actual yield;

actual yield=theoretical yield x yield percentage

actual yield = 33.89 g x 0.728

= 24.66 g

Therefore, the mass of CH₃Cl that forms is 24.66 g.

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At constant pressure, the following reaction 2NO2(g)------>N2O4(g) is exothermic. the reaction (as written) isa) always spontaneousb) spontaneous at low temperatures, but not high temperaturesc) spontaneous at high temperatures, but not low temperaturesd)never spontaneouse) cannot tell

Answers

The correct answer is (c) spontaneous at high temperatures, but not low temperatures.At constant pressure, the spontaneity of a reaction is determined by the change in Gibbs free energy (∆G).

If ∆G is negative, the reaction is spontaneous and if it is positive, the reaction is non-spontaneous.

In the given reaction, 2NO2(g) ------> N2O4(g), the reaction is exothermic, which means that it releases heat.

This indicates that the products have lower energy than the reactants. However, this alone does not determine the spontaneity of the reaction. The change in entropy (∆S) also plays a role in determining the spontaneity.
In this case, the reaction involves a decrease in the number of moles of gas (2 moles of NO2 gas to 1 mole of N2O4 gas), which leads to a decrease in entropy (∆S<0). Thus, the spontaneity of the reaction depends on the temperature. At low temperatures, the decrease in entropy dominates and makes the reaction non-spontaneous (∆G>0). At high temperatures, the decrease in Gibbs free energy (∆G<0) due to the exothermic nature of the reaction dominates, making the reaction spontaneous. Therefore, the correct answer is (c) spontaneous at high temperatures, but not low temperatures.

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physio ex describe what happened to the concentration of ions in the urine when pco2 was lowered

Answers

The concentration of ions in urine is partly controlled by the partial pressure of carbon dioxide (PCO2) in the blood.

When PCO2 increases, the pH of the blood decreases, making it more acidic. This can lead to an increase in the concentration of ions in the urine.

PhysioEx is a software program used for simulating physiological experiments. One of the experiments related to this question involves the effects of varying PCO2 and pH on renal function.

In summary, PhysioEx simulation results demonstrate that when PCO2 is lowered, the concentration of ions in the urine decreases due to an increase in urine pH. This effect is explained by the relationship between PCO2, pH, and renal function. The interpretation of these results can provide valuable insights into the physiological mechanisms that regulate ion concentration in the urine and their role in maintaining overall body homeostasis.

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explain why teh ph of a solution containing both acetic acid and sodium acetate is higher than that of a solution containing the same concentration of acetic acid alone

Answers

The hydrogen ions is removed by the acetate ions making the solution to have a higher pH.

Why is the pH higher?

In general, adding sodium acetate to an acetic acid solution will raise its pH compared to using the same quantity of acetic acid alone this is due to the removal of the hydrogen ions called the buffer effect.

The number of acetate ions in the solution will depend on the concentration of sodium acetate added.

A buffer solution, which can withstand pH shifts when modest amounts of acid or base are added to it, produces this effect.

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which human activity began 160 years ago and provide the strongest evidence that humans are responsible for increased atmospheric carbon dioxide concentrations/

Answers

The human activity that began approximately 160 years ago and provides the strongest evidence that humans are responsible for increased atmospheric carbon dioxide concentrations is the widespread burning of fossil fuels, particularly the combustion of coal, oil, and natural gas. This activity releases large amounts of carbon dioxide into the atmosphere as a byproduct, contributing to the greenhouse effect and climate change. The analysis of carbon isotopes in the atmospheric carbon dioxide provides clear evidence that the increase in carbon dioxide concentrations is primarily due to the burning of fossil fuels, as the isotopic signature of fossil fuel emissions differs from natural carbon sources. This evidence points to human activities as the main driver of the increased atmospheric carbon dioxide concentrations.

Which is NOT a source that can be used to produce biodiesel?
a
Waste Cooking Oil
b
Seed Press Oil
c
Processed Vegetable Oil
d
Petroleum Oil

Answers

The answer should be C processed vegetable oil

what is the maximum amount of work that is possible for an electrochemical cell where e = 1.16 v and n = 2? (f = 96,500 j/(v・mol))

Answers

The maximum amount of work that is possible for an electrochemical cell is -223,080 J/mol.

What is electrochemical cell?

A device that produces electric current from chemical change and energy released by spontaneous redox reactions is an electrochemical cell. Chemical energy is transformed into electrical energy and vice versa.

The maximum work that can be obtained from an electrochemical cell is given by the equation:

ΔG = -nFE

where ΔG is the change in Gibbs free energy, n is the number of moles of electrons transferred in the cell reaction, F is the Faraday constant (equal to 96,500 J/(V∙mol)), and E is the cell potential.

Since the cell potential is given as E = 1.16 V and n = 2, we can calculate the maximum work as:

ΔG = -nFE = -2 x 96,500 J/(V∙mol) x 1.16 V = -223,080 J/mol

Therefore, the maximum amount of work that is possible for an electrochemical cell is -223,080 J/mol.

Note that the negative sign indicates that the reaction is exergonic (i.e., energy is released), and that the value is expressed per mole of electrons transferred in the cell reaction.

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p32 is a radioactive isotope with a half-life of 14.3 days. if you currently have 30.3 g of p32, how much p32 was present 9.00 days ago?

Answers

The P³² is the with the half-life of 14.3 days. The currently have the 30.3 g of the P³², the amount of  P³² was present in the 9.00 days ago is 56.81 g.

The amount remaining, N = 30.3 g

The Half-life, [tex]t_{1/2}[/tex] = 14.3 days

The Time, t = 9 days

The half-life is the time taken for the concentration of the known reactant that will reach the 50% of the initial concentration.

The Original amount, N₀ =?

The Number of the half-lives, n =?

n = t / [tex]t_{1/2}[/tex]

n = 9 / 14.3

n = 0.629

N₀ = 2ⁿ × N

N₀ = [tex]2^{0.629}[/tex] × 30.3

N₀ = 1.875 × 30.3

N₀ = 56.81 g

The amount of the  P³² radioactive isotope is 56.18 g.

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nahco3(s) ⇌ naoh(s) co2(g)nahco3(s) ⇌ naoh(s) co2(g) what is the free-energy change for this reaction at 298 kk ?

Answers

The free - energy change for the reaction at the 298 k is  -94.7 kJ/mol.

The chemical equation is :

NaHCO₃(s)   ⇄   NaOH(s) + CO₂(g)

The free-energy change is expressed as :

ΔG = ΔH - TΔS

Where,

The ΔH is the enthalpy change,

The T is the temperature in the Kelvin,

The ΔS is the entropy change.

The enthalpy change of reaction = -52.3 kJ/mol,

The entropy change = 142.2 J/mol·K.

ΔG = -52.3 kJ/mol - (298 K)(0.1422 kJ/mol·K)

ΔG = -52.3 kJ/mol - 42.4 kJ/mol

ΔG = -94.7 kJ/mol

The free energy change for the reaction is  -94.7 kJ/mol.

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This question is incomplete, the complete question is :

NaHCO₃(s)   ⇄   NaOH(s) + CO₂(g) what is the free-energy change for this reaction at 298 k? The entropy change is 142.2 J/mol·K. The enthalpy change is -52.3 kJ/mol.

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