Azo dyes do not fade in light
t/f

A solution having a pH of 1.4 would be described as distinctly acidic. So the correct option is a.distinctly basic

This is because the pH scale ranges from 0 to 14, where a pH of 0 indicates a strong acid, a pH of 7 indicates a neutral solution, and a pH of 14 indicates a strong base. Therefore, a pH of 1.4 indicates a solution that is much closer to the acidic end of the scale than to the neutral or basic end. Solutions with pH values between 0 and 7 are acidic, while those between 7 and 14 are basic.

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The concentration of H+ is negligible, as [tex]NH_4NO_3[/tex] is a neutral salt.

pH = 14 - pOH = 9.57.

To calculate the pH of this solution, we first need to determine the concentration of hydroxide ions (OH-) present.

Since [tex]NH_3[/tex] acts as a weak base, it will undergo partial hydrolysis to produce OH-. The equilibrium expression for this reaction is: [tex]NH_3[/tex] + [tex]H_2O[/tex] ⇌ [tex]NH_4[/tex]+ + OH-.

Kb = [[tex]NH_4[/tex]+][OH-]/[[tex]NH_3[/tex]].

Since the initial concentration of [tex]NH_3[/tex] is 0.15 M, we can assume that the concentration of [tex]NH_4[/tex]+ is also 0.15 M (due to the stoichiometry of the reaction).

Using Kb, we can solve for [OH-], which is found to be 2.4 x [tex]10^{-4}[/tex] M.

Given that NH4NO3 is a neutral salt, the concentration of H+ is extremely low. [tex]NH_4NO_3[/tex]

pH = 14 - pOH = 9.57 as a result.

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The mass percent of a vinegar solution with a total mass of 96.37 g that contains 3.85 g of acetic acid is 3.99%

The solution composition is often described in mass percentage. It shows the mass of solute present during a given mass of solution. The number of solutes is expressed in mass or by moles.

Mass percentage = ( mass of the component / total mass ) × 100

The Mass per cent formula is expressed as solving for the molar mass also for the mass of each element in 1 mole of the compound.

Given,

Total mass = 96.37g

Mass of acetic acid = 3.85g

Mass percentage = ( mass of acetic acid / total mass ) × 100

= ( 3.85 / 96.37) × 100

= 3.99 %

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The mathematical relationship between Ka and pKa is expressed as pKa = -log(Ka). When the Ka value is large, the pKa value will be small (i.e. more acidic).


1. Ka represents the acid dissociation constant, which measures the strength of an acid in a solution.
2. pKa is the negative logarithm of Ka, so the formula is pKa = -log(Ka).
3. When Ka is large, it means the acid is strong and dissociates easily in a solution.
4. Since pKa is the negative logarithm of Ka, when Ka is large, the pKa value will be small, indicating a strong acid.

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A balanced chemical equation provides valuable quantitative information about various aspects of a chemical reaction. However, it does not offer details about the time of reaction. The correct answer is (a) time of reaction.

A balanced equation illustrates the stoichiometry of a reaction, ensuring that the number of atoms (option b) and molecules (option c) of reactants and products are conserved. Additionally, it allows for the calculation of atomic weights (option d) of reactants and products, which is crucial for determining reaction yields and carrying out stoichiometric calculations.

In summary, a balanced chemical equation is a powerful tool that helps chemists understand and predict the outcome of chemical reactions. However, it does not directly provide information about the time it takes for a reaction to occur. That information typically comes from experimental observations or kinetic studies of the reaction.

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When looking at elements within the same group on the periodic table, there are several properties that can be predicted based on the behavior of other elements in that group.

These properties include:

1. Atomic radius: As you move down a group, the atomic radius tends to increase. This is because there are more energy levels in the atom, which means that the outermost electrons are farther away from the nucleus.

2. Electronegativity: Electronegativity is the ability of an atom to attract electrons towards itself. In general, as you move down a group, electronegativity decreases. This is because the electrons are farther away from the nucleus, which means that they are less strongly attracted to the atom.

3. Ionization energy: Ionization energy is the energy required to remove an electron from an atom. As you move down a group, ionization energy tends to decrease. This is because the electrons are farther away from the nucleus, which means that they are less strongly attracted to the atom and are easier to remove.

4. Reactivity: The reactivity of an element can be predicted based on its position in the periodic table. For example, elements in group 1 (the alkali metals) are highly reactive because they have only one valence electron, which is easily lost in a chemical reaction. Similarly, elements in group 7 (the halogens) are also highly reactive because they have only one electron short of a full valence shell, which makes them eager to gain an electron in a reaction.

In summary, by examining the behavior of other elements in the same group, we can make predictions about properties such as atomic radius, electronegativity, ionization energy, and reactivity for other elements in that group.

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Some possible amounts that you can use to carry out this experiment are 200 ml of vinegar combined with 50, 100, and 10 grams of baking soda.

The purpose of this experiment is to compare how the amount of carbon dioxide changes if you change either the amount of vinegar or the amount of baking soda.

Based on this, we need to have different trials and change one substance while keeping the other constant. In this way, we can know the effect of changing the substance.  

Therefore, we can use:

Note: This question is incomplete; here is the missing information:

Change the ratio of baking soda and vinegar to see whether it changes the amount of carbon dioxide.

Estimated time to complete: 30 minutes

You will need these materials:

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The amount in grams of NaCl that are contained in 350 mL of a 0.287 M solution of sodium chloride is B) 5.87 g.

To determine the grams of NaCl contained in 350 mL of a 0.287 M solution of sodium chloride, we can use the formula:

moles of solute = molarity × volume of solution (in liters)

First, we need to convert the volume of the solution from mL to liters:
350 mL × (1 L / 1000 mL) = 0.350 L

Next, we can calculate the moles of NaCl in the solution:
moles of NaCl = 0.287 M × 0.350 L = 0.10045 moles

Now, we'll convert moles of NaCl to grams using the molar mass of NaCl, which is approximately 58.44 g/mol:
grams of NaCl = 0.10045 moles × 58.44 g/mol ≈ 5.87 g

So, 5.87 grams of NaCl are contained in 350 mL of a 0.287 M solution of sodium chloride. The correct answer is option B) 5.87 g.

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In photophosphorylation, the absorption of light energy in chloroplast "light reactions" leads to the production of ATP and NADPH, which are essential for the synthesis of glucose during the subsequent "dark reactions" of photosynthesis.

Light energy is absorbed by chlorophyll and other pigments in the thylakoid membrane, where light-dependent reactions occur. This absorbed energy is then used to drive two main processes: the flow of electrons along the electron transport chain and the pumping of protons across the thylakoid membrane to create a proton gradient. The electron transport chain, which includes Photosystem II and Photosystem I, enables the conversion of light energy into chemical energy. When light is absorbed, electrons in the chlorophyll become excited and are transferred to a higher energy level. These excited electrons are then passed along the electron transport chain, where their energy is utilized to pump protons into the thylakoid lumen. This process, called the chemiosmotic mechanism, establishes a proton gradient, which is critical for ATP synthesis.

As protons flow back into the stroma through the enzyme ATP synthase, their potential energy is used to synthesize ATP from ADP and inorganic phosphate. This process is called photophosphorylation. Concurrently, electrons that have traveled through the electron transport chain are used to reduce NADP+ to NADPH. In summary, photophosphorylation involves the absorption of light energy in chloroplast light reactions, which leads to the production of ATP and NADPH. These energy-rich molecules are then used in the dark reactions of photosynthesis to synthesize glucose.

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The molecular weight is the sum of the atomic weights of all atoms in the molecule. Atomic weights are the average mass of an element's atoms relative to carbon-12. In the case of ammonia molecular weight is approximately 17.

The molecular weight of a molecule is the sum of the atomic weights of all the atoms that make up the molecule. In the case of [tex]NH_{3}[/tex], the molecular weight is calculated by adding the atomic weights of one nitrogen atom and three hydrogen atoms. The atomic weight of nitrogen is 14.01 atomic mass units (amu) and the atomic weight of hydrogen is 1.01 amu. Therefore, the molecular weight of [tex]NH_{3}[/tex] is 14.01 + (3 x 1.01) = 17.04 amu.

Atoms are the basic units of matter, and they are made up of protons, neutrons, and electrons. Molecules, on the other hand, are formed when two or more atoms chemically bond together. In the case of [tex]NH_{3}[/tex], one nitrogen atom and three hydrogen atoms combine to form a molecule of ammonia. Understanding molecular weight is important in many areas of chemistry, including chemical reactions, stoichiometry, and the determination of the concentration of a solution. It allows chemists to accurately measure and calculate the amount of a substance in a sample.

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In order of increasing root-mean-square speed at 0°C, NO would have the highest root-mean-square speed, followed by NO2, N2O4, and N2O5.

The root-mean-square speed of a gas is directly proportional to the square root of its temperature and inversely proportional to its molar mass. At 0°C, the molar masses of NO, NO2, N2O4, and N2O5 are 30 g/mol, 46 g/mol, 92 g/mol, and 108 g/mol, respectively. Therefore, the gases with lower molar masses will have higher root-mean-square speeds.

In increasing order, the ranking would be N2O5, N2O4, NO2, and NO. This is because N2O5 has the highest molar mass, followed by N2O4 and NO2, and finally NO has the lowest molar mass. Therefore, NO would have the highest root-mean-square speed, followed by NO2, N2O4, and N2O5.

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True, both the nucleophile and solvent play crucial roles in determining the mechanism of a substitution reaction. They can influence the reaction's rate and favor either the SN1 or SN2 mechanism.

True. The nucleophile and solvent can have a significant impact on the mechanism of a substitution reaction. For example, a polar solvent may stabilize the intermediate or transition state, leading to a different mechanism than a non-polar solvent. Similarly, a strong nucleophile may react through a different mechanism than a weak nucleophile. Therefore, both the nucleophile and solvent should be considered when attempting to determine the mechanism of a substitution reaction.
True, both the nucleophile and solvent play crucial roles in determining the mechanism of a substitution reaction. They can influence the reaction's rate and favor either the SN1 or SN2 mechanism.

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39% is the percentage of the total concentration is in the phosphate ion form at pH 7.

At pH 7, the equilibrium between phosphate and monohydrogen phosphate is:

HPO4²- + H2O ⇌ H2PO4- + OH-

The equilibrium constant for this reaction is:

Kw/Ka2 = ([HPO4²-][OH-])/[H2PO4-] = 1.6 x 10^-4

Using the Henderson-Hasselbalch equation, we can calculate the ratio of [HPO4²-]/[H2PO4-] at pH 7:

pH = pKa2 + log([HPO4²-]/[H2PO4-])
7 = 7.20 + log([HPO4²-]/[H2PO4-])
log([HPO4²-]/[H2PO4-]) = -0.20
[HPO4²-]/[H2PO4-] = 0.63

Therefore, the concentration of phosphate ion ([HPO4²-]) is 0.63/(1+0.63) = 0.39 times the total combined phosphate/monohydrogen phosphate concentration (10^-4 M). So, the percentage of the total concentration in the phosphate ion form is: 0.39 x 100% = 39%

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The values of the angular momentum quantum number (l) corresponding to the letters s, p, d, and f are as follows: s=0, p=1, d=2, and f=3. These letters are used to denote the values of l because they are easier to remember and provide a simpler way to represent the different shapes of electron orbitals in atoms.

The letters originated from early spectroscopic studies where the spectral lines were categorized as sharp (s), principal (p), diffuse (d), and fundamental (f) based on their appearance. These categories were later connected to the angular momentum quantum number, which defines the shape and energy of an electron's orbital. Using these letters simplifies the notation for atomic orbitals and makes it easier to understand their properties.

Overall, the use of s, p, d, and f to denote the values of l is a practical choice that has been carried forward from early spectroscopy to modern quantum chemistry.

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The change in Gibbs free energy (ΔGo') for the hydrolysis of ATP is a constant value, which is -31 kJ/mol in this case.

The ΔGo' remains the same regardless of changes in the concentrations of the components involved in the reaction. The change in Gibbs free energy (ΔGo') for the hydrolysis of ATP is a constant value, which is -31 kJ/mol in this case. Doubling the ATP concentration does not affect the value of ΔGo', as it is an intrinsic property of the reaction itself and is independent of the concentration of reactants or products. The ΔGo' remains the same regardless of changes in the concentrations of the components involved in the reaction. The change in Gibbs free energy (ΔGo') for the hydrolysis of ATP is a constant value, which is -31 kJ/mol in this case. The ΔGo' remains the same regardless of changes in the concentrations of the components involved in the reaction.

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The grams of 0.119 g of magnesium nitride was used up in the reaction.

To solve this problem, we need to use the ideal gas law PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the volume of ammonia from liters to m³ is 13.0 L = 0.0130 m³. Next, we can rearrange the ideal gas law to solve for the number of moles n = PV/RT where R = 0.08206 L·atm/(mol·K) is the gas constant.

Plugging in the values, we get

n = (1.00 atm)(0.0130 m³)/(0.08206 L·atm/(mol·K))(23°C + 273.15)

= 0.00708 mol

Now, we need to use the balanced chemical equation to relate the number of moles of ammonia to the number of moles of magnesium nitride.

From the equation, we can see that 6 moles of ammonia react with 1 mole of magnesium nitride. Therefore, the number of moles of magnesium nitride used up in the reaction is mass

= 0.00118 mol × 100.95 g/mol

= 0.119 g

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The half-filled p orbital in nitrogen requires more energy to remove an electron than the partially filled p orbital in oxygen.

Nitrogen has an electronic configuration of 1s² 2s² 2p³, where the last three electrons are in the p orbital. This p orbital is half-filled, which makes it more stable than a partially filled orbital. Thus, it requires more energy to remove an electron from this stable configuration.

On the other hand, oxygen has an electronic configuration of 1s² 2s² 2p⁴, where the p orbital is partially filled. This partially filled orbital is less stable and requires less energy to remove an electron. Therefore, even though oxygen has one more proton in its nucleus, its first ionization energy is lower than nitrogen.

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The substance that is nonpolar is more likely to dissolve in CCl4. Among the given substances, the one that is nonpolar is more likely to dissolve in CCl4

Carbon tetrachloride (CCl4) is a nonpolar solvent because of its tetrahedral molecular geometry, where the four chlorine atoms are arranged symmetrically around the carbon atom. Therefore, only nonpolar or weakly polar substances are expected to dissolve in CCl4 through van der Waals interactions, including London dispersion forces and dipole-induced dipole forces. In contrast, polar and ionic substances are not expected to dissolve in CCl4 because of the lack of electrostatic interactions with the nonpolar solvent molecules. Therefore, among the given substances, the one that is nonpolar is more likely to dissolve in CCl4

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A balanced chemical reaction does not provide the information about the d: exchange rate of reactants and products.

A balanced chemical reaction provides information about the molecular ratio of reactants and products, the mole ratio of reactants and products, and the mass ratio of reactants and products. These ratios are important for understanding the stoichiometry of the reaction, determining the amount of each substance involved, and predicting the products formed.

However, the balanced chemical reaction does not provide information about the exchange rate of reactants and products. The exchange rate refers to the speed or rate at which the reactants are converted into products, which is not determined solely by balancing the chemical equation. Factors such as temperature, concentration, and catalysts can influence the rate of the reaction.

Option d is answer.

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0.125 moles of NO2 can be produced from 14.0 g of NO and 4.00 g of O2.

To find the number of moles of NO2 produced, we first need to determine the limiting reactant. This is the reactant that is completely used up in the reaction and determines the maximum amount of product that can be formed.

Number of moles of NO = mass/molar mass = 14.0 g / 30.01 g/mol = 0.466 mol
Number of moles of O2 = mass/molar mass = 4.00 g / 32.00 g/mol = 0.125 mol

According to the balanced equation, the stoichiometric ratio of NO to O2 is 2:1. This means that 2 moles of NO react with 1 mole of O2 to produce 2 moles of NO2. Therefore, we need twice as many moles of NO as O2 to use up all the O2 and produce the maximum amount of NO2.

Since we have 0.466 moles of NO and 0.125 moles of O2, O2 is the limiting reactant because we need 2 x 0.125 = 0.250 moles of NO to react with all of the O2. This means that only 0.125 moles of NO will react, and we will only produce half as many moles of NO2.

Number of moles of NO2 produced = 0.125 mol x (2 mol NO2 / 2 mol NO) = 0.125 mol

Therefore, 0.125 moles of NO2 can be produced from 14.0 g of NO and 4.00 g of O2.

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Because of their differing nuclear charges, and as a result of shielding by inner electron shells, the different atoms of the periodic table have different affinities for nearby electrons.

The electron affinity is the potential energy change of the atom when an electron is added to a neutral gaseous atom to form a negative ion. So the more negative the electron affinity the more favourable the electron addition process is.

Not all elements form stable negative ions in which case the electron affinity is zero or even positive.

Electron affinity depends on the nuclear charge of an atom.

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The percent yield of benzoic acid in the Grignard synthesis is 64.1%, which means that the reaction did not go to completion and some of the starting material was not converted to product.

What is Benzoic acid?

Benzoic acid is a white, crystalline organic compound with the chemical formula [tex]C_6H_5COOH[/tex]. It is a common food preservative and is used in the manufacture of various products, including dyes, plastics, and perfumes. Benzoic acid can be synthesized by the oxidation of toluene, or by the hydrolysis of benzoyl chloride, among other methods.

We start with 6.00 g of bromobenzene, which has a molar mass of 157.01 g/mol. This means we have 0.0382 moles of bromobenzene. According to the balanced equation for the Grignard synthesis, one mole of bromobenzene should produce one mole of benzoic acid. Therefore, the theoretical yield of benzoic acid is also 0.0382 moles.

We are told that the actual yield of benzoic acid is 3.01 g, which has a molar mass of 122.12 g/mol. This means we have 0.0247 moles of benzoic acid. To calculate the percent yield, we divide the actual yield by the theoretical yield and multiply by 100%:

percent yield = (actual yield / theoretical yield) x 100%

percent yield = (0.0247 / 0.0382) x 100%

percent yield = 64.1%

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The percent yield of benzoic corrosive within the Grignard blend is around 100%.

To calculate the percent yield of benzoic corrosive within the Grignard amalgamation, we got to compare the real surrender (3.01 g) to the percentage yield.

The molar mass is the most extreme sum of benzoic corrosive that can be gotten based on the stoichiometry of the response.

The adjusted chemical condition for the Grignard amalgamation of benzoic corrosive from bromobenzene is:

C₆H₅Br + 2Mg + 2H₂O → C₇H₆O₂ + 2MgBrOH

The molar mass of benzoic corrosive (C₇H₆O₂) is 122.12 g/mol.

To begin with, calculate the number of moles of benzoic corrosive gotten:

moles of benzoic corrosive = mass of benzoic corrosive/molar mass of benzoic corrosive

moles of benzoic corrosive = 3.01 g / 122.12 g/mol ≈ 0.0247 mol

From the adjusted condition, we will see that 1 mole of bromobenzene produces 1 mole of benzoic corrosive. Hence, the molar mass of benzoic corrosive is additionally 0.0247 mol.

Another, calculate the hypothetical mass of benzoic corrosive:

percentage mass of benzoic corrosive = percentagel yield (moles) × molar mass of benzoic corrosive

molar mass of benzoic corrosive = 0.0247 mol × 122.12 g/mol ≈ 3.01 g

Presently we are able calculate the percent yield:

molar mass = (real abdicate / b) × 100

percent yield = (3.01 g / 3.01 g) × 100 ≈ 100%

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When aldehydes or ketones are added, the reaction proceeds to completion which results in the formation of an acetal and a ketal. Acetals and ketals are important functional groups in organic chemistry.

They are formed by the reaction of aldehydes or ketones with alcohols in the presence of an acid catalyst. The reaction is called acetalization or ketalization, respectively.
Acetals and ketals are important in the synthesis of many organic compounds, such as carbohydrates, steroids, and some natural products. They are also useful protecting groups in organic synthesis, which can protect sensitive functional groups from unwanted reactions during a multi-step synthesis.
Overall, the formation of acetals and ketals is a significant transformation in organic chemistry that has many practical applications. The addition of aldehydes or ketones to the reaction mixture promotes the formation of these compounds, resulting in a reaction that proceeds to completion.

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The mass of H2 gas collected is 0.0561 g. To calculate the mass of H2 gas collected, we need to first correct the measured pressure for the presence of water vapor.

The pressure of the water vapor is 25 mm Hg, so the partial pressure of H2 gas is:

P_H2 = P_total - P_water

P_H2 = 742 mm Hg - 25 mm Hg

P_H2 = 717 mm Hg

Next, we need to use the ideal gas law to calculate the number of moles of H2 gas:

PV = nRT

where P is the partial pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the gas constant, and T is the temperature in Kelvin.

Converting the given temperature to Kelvin:

T = 26 + 273 = 299 K

Substituting the given values:

n = (P_H2 * V) / (R * T)

where R = 0.0821 Latm/(molK) is the gas constant.

n = (717 mm Hg * 0.748 L) / (0.0821 Latm/(molK) * 299 K)

n = 0.0279 mol

Finally, we can use the molar mass of H2 gas (2.016 g/mol) to calculate the mass of the gas collected:

mass = n * molar mass

mass = 0.0279 mol * 2.016 g/mol

mass = 0.0561 g

Hydrogen gas, or H2, is a diatomic molecule made up of two hydrogen atoms. It is the lightest and most abundant element in the universe. H2 is colorless, odorless, and highly flammable in the presence of air, oxygen, or heat. It is commonly used in industrial processes, such as the production of ammonia and methanol, as well as in fuel cells for powering vehicles and generating electricity.

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To find the z-score of the standardized normal random variable, we first need to calculate the standard deviation of X by taking the square root of its variance, which is 1.5.

Therefore, the standard deviation of X is √1.5 = 1.22.
Next, we can use the formula for calculating the z-score, which is:
z = (x - μ) / σ
where x is the given value, μ is the mean, and σ is the standard deviation.
Plugging in the values, we get:
z = (13.5 - 9) / 1.22 = 3.61
This means that the standardized normal random variable is 3.61 standard deviations above the mean.  In other words, the value of 13.5 is very unlikely to occur randomly in a normal distribution with a mean of 9 and a standard deviation of 1.22. It is an extreme value that is far from the typical range of values for this distribution.

The z-score is a useful tool for standardizing values from different distributions and comparing them on a common scale. It tells us how many standard deviations a value is from the mean, which helps us understand how unusual or extreme it is. In this case, the z-score of 3.61 indicates that the value of 13.5 is very unusual and suggests that there may be some underlying factor or reason for why it is so much higher than the typical values for this distribution.

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The activation energy for the reaction 2 N2O5(g) → 4 NO2(g) + O2(g) is approximately 122.9 kJ/mol.

To calculate the activation energy for the given reaction, we can use the Arrhenius equation: k = Ae^(-Ea/RT) where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

We can take the natural logarithm of both sides of the equation to get: ln(k) = ln(A) - Ea/RT We can then take the difference of the two ln(k) equations for the two temperatures given: ln(k2/k1) = ln(A) - Ea/R * (1/T2 - 1/T1)

Rearranging this equation to solve for Ea, we get: Ea = -R * ln(k2/k1) / (1/T2 - 1/T1)

Substituting in the values given for k1, k2, T1, and T2, we get: Ea = -8.31 J/mol*K * ln(3.46 x 10^-5 / 7.78 x 10^-7) / (1/298 K - 1/273 K) Ea = 122.9 kJ/mol

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The order of a reaction refers to the power to which the concentration of a reactant or product is raised in the rate law equation. The rate law equation describes the rate of a reaction as a function of the concentration of the reactants.

For example, if the rate law equation for a reaction is given by Rate = k [A]² [B]³, then the reaction is second-order with respect to A and third-order with respect to B. The overall reaction order is the sum of the orders of all the reactants in the rate law equation, which in this case would be (2 + 3) = 5.

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During heavy exercise, the buildup of lactic acid in muscle cells results in oxygen debt.

During exercise, the body needs more energy to fuel muscle contractions. Initially, this energy is supplied through the breakdown of glucose in the presence of oxygen, a process known as aerobic respiration. However, as the intensity of exercise increases, the body may not be able to supply enough oxygen to the muscles to sustain aerobic respiration. In this case, the body switches to anaerobic respiration, which does not require oxygen but produces lactic acid as a byproduct.

Lactic acid buildup in the muscles can lead to fatigue and a burning sensation. Additionally, when the body switches to anaerobic respiration, it produces less ATP per glucose molecule than in aerobic respiration. This means that the body needs to break down more glucose to produce the same amount of ATP, which creates an oxygen debt. The oxygen debt must be repaid after exercise, as the body needs oxygen to convert lactic acid back into glucose and to replenish ATP stores.

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In the reaction 2Ca(s) + O₂(g) → 2CaO(s), the species that is oxidized is Ca (option C).

To explain this, let's look at the reaction step-by-step:

1. In the initial reaction, we have 2 calcium atoms (Ca) and one oxygen molecule (O₂).
2. During the reaction, each calcium atom loses 2 electrons, turning it into a Ca²⁺ ion. This is the process of oxidation, as the calcium atoms are losing electrons.
3. The oxygen molecule gains those 4 electrons (2 from each calcium atom), turning it into two separate O²⁻ ions.
4. The Ca²⁺ ions and O²⁻ ions combine to form calcium oxide (CaO), which is the product of the reaction.

In summary, Ca is the species that is oxidized in the reaction 2Ca(s) + O₂(g) → 2CaO(s).

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