Before determining the limiting reactant, you must convert all values from grams to moles. This is because the balanced chemical equation gives the mole ratios of the reactants and products, not the gram ratios. Converting to moles allows for a more accurate comparison of the amounts of each reactant.
To determine the limiting reactant in a chemical reaction, you need to compare the amounts of reactants used and see which one runs out first. These amounts are usually given in grams, but in order to compare them, they must first be converted to moles. This is because the stoichiometry of the reaction, which describes the ratio of reactants and products, is based on molar ratios, not mass ratios.
To convert grams to moles, you need to use the molar mass of the substance, which is the mass of one mole of the substance. This can be found by adding up the atomic masses of all the atoms in the molecule. Once you have the molar mass, you can divide the given mass by the molar mass to get the number of moles.
After converting all the given masses to moles, you can then use the stoichiometry of the reaction to determine which reactant is limiting. The limiting reactant is the one that is completely used up first, and once it is used up, the reaction stops. The other reactant is in excess and will have some amount left over after the reaction is complete.
It is important to convert all values to moles before determining the limiting reactant in order to compare the amounts of reactants on an equal basis and to use the stoichiometry of the reaction correctly. The example on page 131 of the CHM review may provide additional context and practice on this concept.
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How many milliliters of 0.120 m naoh are required to titrate 50.0 ml of 0.0998 m butanoic acid to the equivalence point? the ka of butanoic acid is 1.5 × 10-5.
The 41.6 mL of 0.120 M NaOH solution are required to titrate 50.0 mL of 0.0998 M butanoic acid to the equivalence point.
What is the balanced equation for the reaction between sodium hydroxide?
The balanced equation for the reaction between sodium hydroxide (NaOH) and butanoic acid (CH3CH2CH2COOH) is:
NaOH + CH3CH2CH2COOH → CH3CH2CH2COONa + H2O
From the equation, we can see that 1 mole of NaOH reacts with 1 mole of butanoic acid. So, we can use the following equation to calculate the amount of NaOH needed to react with the given amount of butanoic acid:
moles of butanoic acid = Molarity × volume in liters
moles of NaOH = moles of butanoic acid (from the balanced equation)
volume of NaOH solution = moles of NaOH ÷ Molarity
First, let's calculate the moles of butanoic acid present in the given volume:
moles of butanoic acid = 0.0998 M × 0.0500 L = 0.00499 mol
Since the reaction is a 1:1 stoichiometry, the moles of NaOH needed to neutralize the acid are also 0.00499 mol.
Now, let's calculate the volume of the NaOH solution needed to provide 0.00499 mol of NaOH:
moles of NaOH = 0.00499 mol
Molarity of NaOH = 0.120 M
volume of NaOH solution = moles of NaOH ÷ Molarity
= 0.00499 mol ÷ 0.120 M
= 0.0416 L or 41.6 mL
Therefore, 41.6 mL of 0.120 M NaOH solution are required to titrate 50.0 mL of 0.0998 M butanoic acid to the equivalence point.
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Write balanced net ionic equation for the first stage of dissociation of the diprotic acid H2SeO4. Express your answer as a chemical equation. Identify all of the phases in your answer.
The first stage of dissociation of H₂SeO₄ can be represented as follows:
H₂SeO₄(aq) + H₂O(l) ↔ H₃O+(aq) + HSeO₄⁻(aq)
The net ionic equation for this reaction is:
H₂SeO₄(aq) ↔ H⁺(aq) + HSeO₄⁻(aq)
In this equation, the spectator ion is the H₂O molecule, which is not involved in the reaction and appears on both sides of the equation.
The phases of the species involved in this equation are:
H₂SeO₄(aq) - aqueous (dissolved in water)
H⁺(aq) - aqueous (dissolved in water)
HSeO₄⁻(aq) - aqueous (dissolved in water)
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what is the topic of the dove and the ant and the boy and the bee
The topics of "The Dove and the Ant" and "The Boy and the Bee" are moral lessons or fables that teach a moral or ethical lesson through storytelling.
What is storytelling ?
Storytelling is the art of conveying a message, idea, or information through the use of a narrative or story. It is an ancient human tradition that has been used for centuries to pass down cultural values, traditions, and history. Storytelling can take many forms, such as oral storytelling, written stories, films, television shows, and other forms of media. Stories can be fictional or based on real-life events, and can be used to educate, entertain, inspire, or persuade an audience.
"The Dove and the Ant" is a fable that teaches the lesson that kindness is always rewarded, while "The Boy and the Bee" is a fable that teaches the lesson that one should be careful in their actions and think before acting.
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a solution in which solute-solvent interactions are the same or similar to the solute-solute and solvent-solvent interactions is called a(n):
A solution in which solute-solvent interactions are the same or similar to the solute-solute and solvent-solvent interactions is called a Ideal solution.
Generally an ideal solution is defined as a mixture in which the molecules of different species are often distinguishable, however, unlike the ideal gas, the molecules in ideal solution usually exert forces upon one another. And when these forces are the same for all the molecules independent of species then a solution is said to be ideal in nature.
Also, an ideal solution is defined as that solution in which each component obeys Raoult's law under each and every conditions of temperature and concentrations.
A solution is said to be ideal in nature in which solute-solvent interactions are the same or similar to the solute-solute and solvent-solvent interactions.
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the key component of smog is group of answer choices sulfur dioxide. particulate matter. carbon monoxide. ground-level ozone.
The key component of the smog is ground-level ozone.
The Ground-level ozone that is O₃ is the major component of the smog. This is formed from the photochemical reactions and with the pollutants like as the volatile in the organic compounds, the carbon monoxide and the nitrogen oxides (NOx) and it will emitted from the vehicles, and the industry.
Ozone at the ground level is very harmful air pollutant, this is because of the effects on the people and to the environment, and it is the main source of the smog. The smog is the air pollution is that the reduces visibility.
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1. correct for the water vapor present in the wet dry ice experiment and compare with the mean value for the dry ice experiment. does the presence of water vapor affect the result? use the equations in this laboratory to prove why water vapor does or does not have a large effect on the value obtained
In the wet-dry ice experiment, water vapor is present due to the reaction of dry ice with water. It is important to correct the presence of water vapor when comparing the results to the mean value obtained from the dry ice experiment.
The presence of water vapor can have a small effect on the value obtained in the wet-dry ice experiment, but it should not have a large effect. This is because the mass of water vapor is much smaller than the mass of dry ice used in the experiment.
To prove this, we can use the following equations:
For the wet-dry ice experiment:
Mass of dry ice = Initial mass of dry ice - Final mass of dry ice and water vapor
For the dry ice experiment:
Mass of dry ice = Initial mass of dry ice - Final mass of dry ice
By subtracting the final mass from the initial mass in each experiment, we can determine the mass of dry ice used.
In the wet-dry ice experiment, the final mass includes both the dry ice and any water vapor that has formed. By subtracting the mass of water vapor from the final mass, we can determine the mass of dry ice that was actually used.
If we compare the mass of dry ice obtained in the wet-dry ice experiment (corrected for water vapor) to the mass obtained in the dry ice experiment, we should see a similar mean value.
In summary, the presence of water vapor can have a small effect on the results of the wet-dry ice experiment, but it should not have a large effect due to the much smaller mass of water vapor compared to dry ice. Correcting for water vapor will ensure accurate comparisons to the mean value obtained from the dry ice experiment.
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you are asked to help with the radiodating of a plant based sample excavated from an archaeological site. the rate of 14c decay in the sample is 81.0% of the 14c decay rate in a living plant. what is the estimated age of the archaeological sample? (the half-life for 14c is 5730 years.)
The estimated age of the archaeological plant-based sample is approximately 1912 years.
1. Understand that decay refers to the process where the radioactive isotopes, such as 14C, break down over time, and half-life refers to the time it takes for half of the radioactive isotopes to decay.
2. Given that the 14C decay rate in the archaeological sample is 81.0% of the decay rate in a living plant, this means that the sample has 0.81 times the amount of 14C as a living plant.
3. Since the half-life of 14C is 5730 years, you can use the decay formula to calculate the age of the sample:
N = N0 * (1/2)^(t / half-life)
where N is the final amount of 14C, N0 is the initial amount, t is the age of the sample, and half-life is the half-life of 14C (5730 years).
4. Plug in the values given:
0.81 = 1 * (1/2)^(t / 5730)
5. Solve for t:
t / 5730 = log(0.81) / log(0.5)
t = 5730 * (log(0.81) / log(0.5))
t ≈ 1912 years
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Which reaction occurs most rapidly at standard conditions?
a. H2(g) + I2(s) arrow 2HI(g)
b. Cu(s) + S(s) arrow CuS(s)
c. C6H12O6(s) + 6O2(g) arrow 6CO2(g) + 6H2O(g)
d. 5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) arrow 10CO2(g) + 2Mn2+(aq) + 2H2O(l)
e. Ag+(aq) + I-(aq) arrow AgI2(s)
The reaction that occurs most rapidly at standard conditions is option (e) Ag⁺(aq) + I⁻(aq) → AgI₂(s), as it has very low activation energy.
The activation energy, temperature, and reactant concentrations are a few of the variables that affect a chemical reaction's rate. But under normal circumstances, the rate of a reaction is solely determined by its mechanism and activation energy.
In this situation, we can identify which reaction happens more quickly under typical conditions by using the reaction mechanism and activation energies.
a. H₂(g) + I₂(s) → 2HI(g)
There is a radical mechanism at work in this gas-phase reaction. Since this reaction has a relatively large activation energy, it proceeds slowly under normal circumstances.
b. Cu(s) + S(s) → CuS(s)
This reaction occurs in the solid state and is carried out by a surface mechanism. Since this reaction has a low activation energy, it proceeds quickly under normal circumstances.
c. C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)
This gas-phase reaction moves forward by means of burning. Since this reaction has a relatively large activation energy, it proceeds slowly under normal circumstances.
d. 5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺(aq) → 10CO₂(g) + 2Mn⁺(aq) + 8H₂O(l)
An oxidation-reduction mechanism drives this solution-phase process. Since this reaction has a relatively large activation energy, it proceeds slowly under normal circumstances.
e. Ag⁺(aq) + I⁻(aq) → AgI₂(s)
It is a precipitation mechanism that drives this solution-phase reaction. Since this reaction has a low activation energy, it proceeds quickly under normal circumstances.
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in this lab, yeast is used as a catalyst to decompose hydrogen peroxide.
true
false
True. In this lab, yeast is used as a catalyst to decompose hydrogen peroxide, speeding up the decomposition of hydrogen peroxide. Here's a step-by-step explanation:
1. Yeast, a fungus, contains an enzyme called catalase.
2. When yeast is added to a solution containing hydrogen peroxide, catalase acts as a catalyst.
3. A catalyst is a substance that increases the rate of a chemical reaction without being consumed or altered.
4. Catalase helps to decompose hydrogen peroxide into water and oxygen gas at a faster rate.
5. This decomposition reaction is important because hydrogen peroxide can be harmful to cells if not broken down.
So, yeast acts as a catalyst in this lab, hastening the decomposition of hydrogen peroxide.
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Name 3 ways that enzymes enable a quicker reaction.
If a drug that blocked the reabsorption of sodium were taken, what would happen to the reabsorption of glucose?
a. increase
b. decrease
c. no change
If a drug that blocked the reabsorption of sodium were taken, it would not have a direct effect on the reabsorption of glucose. The two processes are independent of each other.
If a drug that blocked the reabsorption of sodium were taken, the reabsorption of glucose would likely decrease (b). This is because glucose reabsorption in the kidneys is often dependent on sodium-glucose co-transporters, which require the presence of sodium to effectively transport glucose back into the bloodstream. Blocking sodium reabsorption would lead to less sodium being available for these co-transporters, thereby reducing glucose reabsorption.
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write the first four member of alcohol homologous series
Answer:
Explanation:
Thus, the first member of the alcohol homologous series is methyl alcohol, the second is ethyl alcohol, the third member is propyl alcohol and the fourth member is butyl alcohol. The formula that shows the arrangement of atoms in a molecule of a compound is known as a structural formula.
Gives what happens at low pH for aluminum hydroxide.
A) Al(H2O)6^3+ dissolves
B) Al(H2O)2(OH)4^- precipitates
C) Al(OH)6 dissolves
D) Al precipitates
E) Al dissolves
What happens at low pH for aluminum hydroxide. At low pH, Al(H2O)6^3+ dissolves.
This occurs because the acidity of the solution increases the concentration of H+ ions, which results in the dissolution of Al(H2O)6^3+ complex ions. So, the correct answer is A) Al(H2O)6^3+ dissolves.
It probably has a low pH and too many hydrogen ions. Acid mine drainage (AMD), which lowers the pH of water resources and makes dissolved metals easily available for uptake by benthic animals and fish, is a significant contributor to the entry of these contaminants into the human food chain.
The term "acid mine drainage" refers to the runoff that results from water coming into touch with exposed sulfur-bearing minerals. These minerals react with the water and air to produce sulfuric acid and dissolved iron.
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From the following list, select all reagents commonly used in organic oxidation reactions. multiple select question. lialh4 with aqueous workup o3 acidic aq. na2cr2o7 pd/c mcpba
The reagents commonly used in organic oxidation reactions are: 2- O₃ (acidic aq.), 3-Na₂Cr₂O₇, PD/C, and 4- MCPBA.
Organic oxidation reactions involve the addition of oxygen or removal of hydrogen from organic molecules. The choice of reagent depends on the specific reaction and desired outcome.
Ozone (O₃) in acidic aqueous solution is used for oxidative cleavage of alkenes and alkynes. It attacks the double bond and cleaves it to form carbonyl compounds.
Sodium dichromate (Na₂Cr₂O₇) is a powerful oxidizing agent used to oxidize alcohols to aldehydes or ketones, and to oxidize aldehydes to carboxylic acids.
Palladium on carbon (PD/C) is used as a catalyst for the oxidation of alcohols to aldehydes, ketones, or carboxylic acids.
MCPBA (meta-chloroperoxybenzoic acid) is a mild oxidizing agent used to convert alkenes to epoxides, sulfides to sulfoxides, and imines to oximes. It is also used for oxidative cleavage of alkenes and oxidation of alcohols to ketones or aldehydes.
Lithium aluminum hydride (LiAlH₄) is a reducing agent commonly used for reducing carbonyl compounds to alcohols. It is not commonly used as an oxidizing agent, as it reduces rather than oxidizes organic molecules.
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the complete question is:
From the following list, select all reagents commonly used in organic oxidation reactions. multiple select question.
1-lialh4 with aqueous workup
2-o3 acidic aq.
3-na2cr2o7 pd/c
3-mcpba
Ksp= 2.45x10^-5
Calculate the molar solubility of barium fluoride in each liquid or solution * K_sp = 2.45 x 10^-5
a. Pure water
b. 0.10 M Ba(NO_3)_2
c. 0.15 M NaF
Laughing gas (nitrous oxide, N₂O) is sometimes used as an anesthetic in dentistry.
NH4NO3(S) -> N₂O(g) + 2H₂O(1)
How many moles of NH4NO3 are required to produce 33.0g of N₂O? (2 pts)
Answer: 0.750
Explanation:
NH4NO3 decomposes to make 1 mole of N20 for every mole of NH4NO3. Therefore we can solve for how many moles of N2O is 33.0g and we will also have our answer.
the molar mass of N2O is 44.01g/mol
33.0g/44.01g = 0.7498 moles
using 3 sig figs we get 0.750 moles
what is the molarity of a hcl solution prepared by dissolving 0.165 moles of hcl in sufficient water to producea 200. ml solution?
The molarity of the HCl solution prepared by dissolving 0.165 moles of HCl in sufficient a water is produce a 200 ml solution will be 0.825 M.
Molarity (M) is the unit of concentration that represents the number of moles of solute dissolved in one liter of solution. It is termed as the amount of the solute (in moles) divided by the volume of the solution in liters.
To calculate the molarity (M) of a solution, we can use the formula;
Molarity (M) = moles of solute/volume of solution (in liters)
Given; moles of HCl = 0.165 moles
volume of solution = 200 ml = 200/1000 L (since 1 L = 1000 ml)
Plugging in the values;
Molarity (M) = 0.165 moles / 200/1000 L
Molarity (M) = 0.165 moles / 0.2 L
Molarity (M) = 0.825 M
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To calculate the Ksp value in the presence of ion activity, it is necessary to measure the ion product at the point of saturation for multiple . The ion product nears the Ksp value at Choose... Choose... concentrations is finally used to determine the Ksp Value. due to lower ionic strer temperatures compounds
To calculate the Ksp value in the presence of ion activity, it is necessary to measure the ion product at the point of saturation for multiple concentrations.
The ion product nears the Ksp value at higher concentrations, and this value is finally used to determine the Ksp value. This is because at higher concentrations, there is a lower ionic strength and lower temperatures which promote the formation of solid compounds and increase the solubility of the ions.
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The acid-dissociation constant at 25.0°C for hypochlorous acid (HClO) is 3.0 × 10^-8. At equilibrium, the molarity of H3O+ in a 0.044 M solution of HClO is
A) 3.6 × 10^-5
B) 0.044
C) 2.8 × 10^-10
D) 4.44
E) 1.36
The molarity of H3O+ in a 0.044 M solution using acid dissociation of HClO at equilibrium is 3.6 × 10^-5 (Option A).
To find the molarity of H3O+ in a 0.044 M solution of HClO, we will use the acid dissociation Ka expression:
Ka = [H3O+][ClO-]/[HClO]
Since the initial concentration of HClO is 0.044 M, we can set up the equation as follows:
3.0 × 10^-8 = [x][x]/(0.044-x)
Assuming x is much smaller than 0.044, the equation simplifies to:
3.0 × 10^-8 = x^2/0.044
Now, we can solve for x (the molarity of H3O+):
x^2 = 3.0 × 10^-8 * 0.044
x^2 = 1.32 × 10^-9
x = √(1.32 × 10^-9)
x = 3.6 × 10^-5
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Use the following equation to help you. TK=2.9x10 nm(K)/peak The blackbody curve for a star named Gamma is shown below. What is the surface temperature of this star rounded to the nearest whole number? Intensity 50 2000 Odyssey, no. 5,273 K 9,666 K O2,900 K 3,625 K 200 250 300 360 400 450 500 550 800 500 700 750 900 950 900 960 1,000 1060 1,100 1,150 Wavelength (nm)
14,500 K is the surface temperature of this star rounded to the nearest whole number. It indicates the direction through which the heat energy will naturally flow,
Temperature is a unit of temperature that can be defined in the context of any number of arbitrary scales. It indicates the direction through which the heat energy will naturally flow, i.e., through a hotter (body) to a colder (body) body.
Temperature is not the same as the thermal energy of a thermodynamics system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at an extremely high temperature. 14,500 K is the surface temperature of this star rounded to the nearest whole number.
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In the induced fit model for enzyme-substrate binding, what part is endergonic and which is exergonic?
In the induced fit model for enzyme-substrate binding, the endergonic part is the formation of the enzyme-substrate complex, while the exergonic part is the release of products and the enzyme returning to its original state.
Step-by-step explanation:
1. Endergonic: The enzyme and substrate come together and the enzyme changes shape slightly (induced fit) to form the enzyme-substrate complex. This requires energy input, making it endergonic.
2. Exergonic: The enzyme catalyzes the reaction, converting the substrate into products. The products are released, and the enzyme returns to its original shape. This process releases energy, making it exergonic.
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‼️I have balanced the EQ already, but I'm lost on part B. will be awarding all my points (100+) to someone who can help and provide steps :) ‼️
Mrs. Webb placed a cup containing 10.0 g of water into a beaker, then placed 2.0 g of calcium carbide, CaC₂ into the H₂O. The reaction produced flammable ethyne (C₂H₂) gas an calcium hydroxide.
a. Write the balanced equation for the reaction. CaC₂+ H₂O → C₂ H₂ + Ca(OH)₂
b. How many L of ethyne (at STP) can form?
Explanation:
To determine how many liters of ethyne (C₂H₂) can form at STP, we need to use stoichiometry and the ideal gas law.
First, let's determine the number of moles of CaC₂ and H₂O that reacted. From the given information, we know that the mass of water is 10.0 g and the mass of CaC₂ is 2.0 g. We can use the molar masses of CaC₂ (64.10 g/mol) and H₂O (18.02 g/mol) to convert the masses to moles:
moles of CaC₂ = 2.0 g / 64.10 g/mol = 0.0312 mol
moles of H₂O = 10.0 g / 18.02 g/mol = 0.555 mol
Next, we need to determine the limiting reactant to find out how many moles of ethyne can form. To do this, we compare the mole ratio of CaC₂ to H₂O in the balanced equation:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
1 2
For every 1 mole of CaC₂, we need 2 moles of H₂O to react. The moles of H₂O we have (0.555 mol) are more than enough to react with the moles of CaC₂ we have (0.0312 mol). Therefore, CaC₂ is the limiting reactant.
Now we can use the mole ratio of CaC₂ to C₂H₂ in the balanced equation to find the moles of C₂H₂ that can form:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
1 1
1 mole of CaC₂ produces 1 mole of C₂H₂. Therefore, the moles of C₂H₂ that can form is also 0.0312 mol.
Finally, we can use the ideal gas law to find the volume of C₂H₂ at STP. The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. At STP, the pressure is 1 atm and the temperature is 273 K.
Plugging in the values, we get:
V = (nRT) / P
V = (0.0312 mol)(0.0821 L·atm/mol·K)(273 K) / 1 atm
V = 0.738 L
Therefore, the volume of C₂H₂ that can form at STP is 0.738 L.
an aqueous solution is made with the salt obtained from combining the weak acid cyanic acid, hcno, with the weak base methylamine, ch2nh2. is the solution acidic, basic, or neutral?select the correct answer below:neutralbasicacidicthere is not enough information.
The aqueous solution made with the salt obtained from combining the weak acid cyanic acid, HCNO, with the weak base methylamine, [tex]CH_2NH_2[/tex], is basic.
When a weak acid and a weak base are combined, they form a salt that can have acidic, basic, or neutral properties depending on the relative strengths of the acid and base. In this case, cyanic acid (HCNO) is a weak acid, and methylamine [tex](CH_2NH_2)[/tex] is a weak base. Methylamine can accept a proton from cyanic acid to form the salt [tex]CH_2NH^{3+}CNO^-[/tex].
The conjugate base of a weak acid is usually a weak base, and the conjugate acid of a weak base is usually a weak acid. Since the conjugate base of [tex]HCNO (CNO^-)[/tex] is a weak base and the conjugate acid of [tex]CH_2NH_2 (CH_3NH^{3+})[/tex] is a weak acid, the salt [tex]CH_2NH^{3+}CNO^-[/tex] is a basic salt.
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The question is -
An aqueous solution is made with the salt obtained from combining the weak acid cyanic acid, HCNO, with the weak base methylamine, CH2NH2. Is the solution acidic, basic, or neutral?
Determine the molar solubility for Zn(OH)2 in pure water. Ksp for Zn(OH)2 is 3.00 × 10^-17.
A) 3.0 × 10^-17 M
B) 7.5 × 10^-18 M
C) 3.11 × 10^-6 M
D) 1.96 × 10^-6 M
E) 5.5 × 10^-19 M
3.11 × 10⁻⁶ M is the molar dissolvability for Zn(OH)₂ in unadulterated water.
Option C is correct.
Define molar solubility.The molar solubility of a solute is the amount that can dissolve in one liter of solution without becoming saturated. This sum can be determined utilizing the stoichiometry and the item solvency consistent, or Ksp.
Molarity and dissolvability are two free sub-atomic characteristics that are utilized to describe two distinct parts of a substance, and the unit for molar solvency is mol/L. A particle's ability to deteriorate in a dissolvable is known as dissolvability. A substance's fixation in an answer, by and large given in moles per liter, is known as its molarity.
Zn(OH)₂ ⇔Zn₂+ + 2OH-
Ksp ⇒ [Zn²⁺][OH-]²
If S is solubility,
Ksp = S × (2S)² i.e. 4S³
S will be cube root of Ksp/4
S ⇒ 3.11 × 10⁻⁶ M
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which combination of aqueous solutions should produce a precipitate?a) AgNO3 and Ca(CH3COO)2
b) NaCH3COO and HCl c) KNO3 and CaCl2
d) KOH and Ca(NO3)2
e) NaOH and HCl
The combination of aqueous solutions that should produce a precipitate is a) AgNO₃ and Ca(CH₃COO)₂. When these two solutions are mixed, the Ag⁺ ions from the AgNO₃ solution react with the CH₃COO⁻ ions from the Ca(CH₃COO)₂ solution to form a solid silver acetate (AgCH₃COO) precipitate. The other options do not produce a precipitate as they do not have ions that will react to form a solid.
When AgNO₃ and Ca(CH₃COO)₂ aqueous solutions are combined, a double displacement reaction occurs, and the products formed are AgCH₃COO and Ca(NO₃)₂. Among these products, AgCH₃COO (silver acetate) is insoluble in water and forms a precipitate, while Ca(NO₃)₂ remains soluble.
Here's a step-by-step explanation:
1. Write down the reactants: AgNO₃ (aq) + Ca(CH₃COO)₂ (aq)
2. Perform a double displacement reaction: AgCH₃COO (s) + Ca(NO₃)₂ (aq)
3. Identify the precipitate: AgCH₃COO (s) is the insoluble compound that forms the precipitate.
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What are physical properties? Give 6 examples (D. COMBS)
Physical properties are characteristics of a material that can be observed or measured without changing the substance's chemical composition.
Briefly explain physical properties. Here are 6 examples of physical properties (D. COMBS):
1. Density: The mass per unit volume of a substance.
2. Color: The visual appearance of a substance based on the wavelengths of light it reflects or emits.
3. Hardness: The resistance of a material to deformation, indentation, or penetration.
4. Melting point: The temperature at which a solid substance changes to a liquid state.
5. Boiling point: The temperature at which a liquid substance turns into a vapor or gas.
6. Solubility: The ability of a substance to dissolve in a solvent, such as water.
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If there are 7.00 moles of Al(OH)3, how many grams of Ca(OH)2 will be formed?
3CaCl2 + 2Al(OH)3 = 3Ca(OH)2 + 2AlCl3
Answer: Mass of Ca(OH)2 formed will be 777g.
Explanation:
As from the reaction we can see,
2 moles of Al(OH)3 gives 3 moles of Ca(OH)2.
1 mole of Al(OH)3 gives 3/2 moles of Ca(OH)2.
7 moles of Al(OH)3 gives ((3/2)x 7) moles of Ca(OH)2.
7 moles of Al(OH)3 gives (21/2) moles of Ca(OH)2.
So, no. of moles of Ca(OH)2= 21/2 mole
Molar mass of Ca(OH)2 = 74 g/mole
Mass of Ca(OH)2 = No. of moles x Molar mass
= (21/2) x 74
= 777g
Highest priority groups are the most or least oxidized?
The concept of oxidation applies to chemical reactions involving the loss or gain of electrons. In organic chemistry, functional groups containing more electronegative elements (such as oxygen, nitrogen, or halogens) are typically more oxidized than those containing primarily carbon and hydrogen.
Therefore, the highest priority groups in organic chemistry, such as carboxylic acids or esters, are generally the most oxidized functional groups. However, it is important to note that oxidation can also refer to changes in the oxidation state of an element, which is determined by the number of electrons that it has gained or lost.
In this sense, the term "most oxidized" would refer to an element with the highest oxidation state, regardless of the specific functional group that it is a part of.
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an organic aromatic compound reacted with excess bromine to give a tribromo derivative by electrophilic substitution reaction. when reacted with nitrous acid, it gave intermediate ionic compound which reacted with 2-naphthol to give a colored product with molecular formula c16h12n2o. a. what is the structural formula of the original organic compound? 5 pts
To determine the structural formula of the original organic compound, we can follow these steps:
1. The original compound is an aromatic compound, which implies that it has a benzene ring as its core structure.
2. The compound reacts with excess bromine to form a tribromo derivative through electrophilic substitution. This means that three hydrogen atoms on the benzene ring are replaced by bromine atoms.
3. When reacted with nitrous acid, the compound forms an intermediate ionic compound that reacts with 2-naphthol to give a colored product with a molecular formula of C₁₆H₁₂N₂₀. This information suggests that the original compound has an amine group (-NH₂) that reacts with nitrous acid.
4. We can now determine the molecular formula of the original compound by subtracting the molecular formula of the product (C₁₆H₁₂N₂₀) by the formula of the 2-naphthol (C₁₀H₈₀) and the three bromine atoms that were replaced by hydrogen. This gives us C₆H₆ - 3H + NH₂ = C₆H₅NH₂.
5. The structural formula of the original organic compound is therefore C₁₆H₁₂N₂₀, which is aniline, an aromatic amine with an NH₂ group attached to the benzene ring.
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5) Given that the density of CO2 at the temperatures we used is 1.25 g/L, calculate the theoretical
and actual yield (based on the amount of sodium acetate produced!) for CO2, in liters, for the
experiment.
+ Hco
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6) How many grams of sodium hydrogen carbonate would be necessary to produce 425 mL of CO₂?.
Use the density of CO2 from #5 and show your calculations.
1.596 grams of sodium hydrogen carbonate would be necessary to produce 425 mL of [tex]CO_{2}[/tex] at STP.
To calculate the amount of sodium hydrogen carbonate needed to produce 425 mL of [tex]CO_{2}[/tex], you can use the following steps:
Convert the volume of [tex]CO_{2}[/tex] to moles using the molar volume at STP:
425 mL ÷ 1000 mL/L = 0.425 L [tex]CO_{2}[/tex]
0.425 L [tex]CO_{2}[/tex] ÷ 22.4 L/mol = 0.019 moles [tex]CO_{2}[/tex]
Use the balanced chemical equation to determine the stoichiometry between sodium acetate and carbon di oxide:
[tex]NaC_{2} H_{3} O_{2}[/tex] [tex]+ H_{2} O + CO_{2}[/tex] → [tex]Na HC_{3} O_{2}[/tex][tex]+ CH_{3} COOH[/tex]
For every 1 mole of sodium acetate, 1 mole of CO2 is produced. Therefore,
0.019 moles CO2 = 0.019 moles [tex]NaC_{2} H_{3} O_{2}[/tex]
Calculate the mass of sodium hydrogen carbonate needed using its molar mass:
0.019 moles [tex]NaC_{2} H_{3} O_{2}[/tex] × 84.01 g/mol = 1.596 g [tex]Na HC_{3} O_{2}[/tex]
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