The given matrix [4 7; 3 5] has an inverse. The inverse matrix is [5 -7; -3 4].
To determine if a matrix has an inverse, we need to check if its determinant is nonzero. Let's denote the given matrix as A: A = [4 7; 3 5]
The determinant of A, denoted as det(A), can be calculated by cross-multiplying and subtracting: det(A) = (4 * 5) - (7 * 3)
= 20 - 21
= -1
Since the determinant is nonzero (-1 ≠ 0), the matrix A has an inverse.
To find the inverse matrix, we can use the formula:
[tex]A^(-1)[/tex]= (1/det(A)) * adj(A)
Where adj(A) represents the adjugate of matrix A, obtained by swapping the elements of the main diagonal and changing the sign of the off-diagonal elements. Applying the formula, we have:
[tex]A^(-1)[/tex] = (1/(-1)) * [5 -7; -3 4]
= [-5 7; 3 -4]
Therefore, the inverse of the given matrix [4 7; 3 5] is [5 -7; -3 4].
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in the diagram below, from the congruent marks, we would know that the red line is referred to as the:
Answer: d. median
Solution:
In a triangle, a median is a line segment joining a vertex to the midpoint of the opposite side.
In the given diagram, we can see that the red line is drawn from the vertex to the midpoint of the opposite side, which makes it a median.
The congruent marks on the other two sides indicate that they are of equal length.
We want to prove that, for any two stable matchings μ,μ
′
, If μ(m)⪰
m
μ
′
(m) for every m∈M, then μ
′
(w)⪰
w
μ(w) for every w∈W. Fill out three small steps (a)-(c) below. Proof: Suppose, toward contradiction, that ∃w such that μ(w)≻
w
μ
′
(w). (a) Explain that w is matched to a man (instead of remaining single) in μ. (b) Denote μ(w) by m. Explain that μ
′
(m)
=w. (c) Explain that (m,w) is a blocking pair of μ
′
. The last observation contradicts that μ
′
is stable, which completes the proof. Remark: M-optimal stable matching is the best stable matching for every man. Thu the above result implies that M-optimal is the worst stable matching for every woman
If μ(m) ⪰ m μ'(m) for every man m, then μ'(w) ⪰ w μ(w) for every woman w. This implies that the M-optimal stable matching is the worst stable matching for every woman.
(a) If μ(w) ≻ w μ'(w) holds, it means that woman w prefers her partner in μ(w) over remaining single in μ'. Therefore, w is matched to a man (instead of remaining single) in μ.(b) Let's denote μ(w) as m. Since w is matched to m in μ, it follows that μ'(m) ≠ w. If μ'(m) = w, it would contradict the assumption that μ(m) ⪰m μ'(m) for every man m.
(c) Since μ'(m) ≠ w and w prefers μ(w) over remaining single, (m, w) forms a blocking pair for μ'. This means that there exists a woman-woman pair that prefers each other over their current partners in μ'. This contradicts the stability of μ', as stable matchings do not have blocking pairs.
The contradiction in (c) demonstrates that the assumption of μ(m) ⪰m μ'(m) for every man implies that μ'(w) ⪰w μ(w) for every woman. Therefore, the result shows that the worst stable matching for every woman is the M-optimal stable matching.
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After estimating the regression model in Question 1, you want to test
at the 5% significance level. Choose the correct statement.
a.
We reject because the standard error of is approximately 0.128.
b.
We reject because the maximum of the p-values associated with and is larger than 0.05.
c.
We do not have sufficient evidence to reject because = 0.67. d.
We have to test two restrictions jointly and the critical value for this test is 3.
e.
For this test, the F statistic is 154.9 and we use the F distribution with degrees of freedom 3 and 216.
The correct statement among the options depends on the specific details of the regression model and hypothesis being tested. Let's analyze each option:
a. The statement mentions rejecting because the standard error of is approximately 0.128. However, it does not provide any information about the hypothesis being tested or the test statistic. Therefore, we cannot determine if this statement is correct without further information.
b. This statement suggests rejecting because the maximum of the p-values associated with and is larger than 0.05. Again, without knowing the specific hypothesis being tested or the test statistic used, we cannot determine the correctness of this statement.
c. The statement claims that we do not have sufficient evidence to reject because = 0.67. However, it does not provide any information about the hypothesis, test statistic, or critical values. Thus, we cannot assess the accuracy of this statement.
d. This statement mentions testing two restrictions jointly and the critical value for this test being 3. While it provides more information about the hypothesis being tested, without further context or details, we cannot evaluate the correctness of this statement.
e. The statement states that the F statistic for the test is 154.9, and it utilizes the F distribution with degrees of freedom 3 and 216. This statement provides specific information about the test statistic and degrees of freedom, suggesting that it is more likely to be the correct statement. However, we still need to consider the hypothesis being tested to confirm its accuracy.
Without additional information about the hypothesis being tested, we cannot definitively select the correct statement.
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use the set of values below.
1 1 1 1 1 1 2 3 5 8 13 21 34 55 89 89 89 89 89 89. At what percentile is 34?
The value 34 is at the 55th percentile in the given dataset, meaning it is higher than 55% of the values and lower than 45% of the values.
To determine the percentile of 34 in the given dataset, we first need to arrange the values in ascending order: 1 1 1 1 1 1 2 3 5 8 13 21 34 55 89 89 89 89 89 89.
The percentile of a value represents the percentage of values in a dataset that are equal to or less than that value. In this case, there are 12 values that are less than or equal to 34. The total number of values in the dataset is 20.
To calculate the percentile, we use the formula:
Percentile = (Number of values less than or equal to the given value / Total number of values) × 100.
Therefore, the percentile of 34 is (12/20) × 100 = 60%. This means that 34 is higher than 60% of the values and lower than 40% of the values in the dataset.
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Jalissa and Mateo each have the same type of MP3 player, but in different, colors. The players are congruent rectangular prisms. The volume of Jalissa's player is 4.92 cubic inches, the width is 2.4 inches, and the depth is 0.5 inch. What is the height of Mateo's player?
The height of Mateo's player based on the congruency with Jalissa's player is 4.1 inches.
As stated, both the MP3 players are congruent. This means the dimensions of both the players will be same.
Now, the volume of the rectangular prism is calculated using the formula -
Volume = length × width × height
Height = 4.92/(2.4 × 0.5)
Performing multiplication on denominator on Right Hand Side of the equation
Height = 4.92/1.2
Performing division on Right Hand Side of the equation
Height = 4.1 inches
Hence, the height of Mateo's player is 4.1 inches.
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Someone already calculated the 5-number summary and IQR for you.
52,74,78,79,85,87,88,90
Min: 52
Q1:76
Median:85
Q3:88
Max:90
IQR:12
The low end cutoff is ______
The high end cutoff is______
Question 3
Students were asked how much many they had in their pocket. the results are as follows:
0,0,1,3,3,5,5,5,6,7,9,10,10,13,20,20,22,23,25,31,95
The 5 number summary and IQR have been calculated for you.
Min:0 Q1: 4 Median:9 Q3:21 Max:95 IQR:17
Leave your answer as decimal if needed. Don’t round.
The low end value is:____
The High end value is____
Does this Data set have outliers? Type Yes or no
If yes, type the outlier here:
Question 4
Minimum: 6
Q1:8
Median:10
Q3:14
Maximum:26
IQR:6
Check for outliers…
Low End:____
High End:____
The outlier is______. If there is no outlier, WRITE NONE
Question 2:
The low end cutoff is 52.
The high end cutoff is 90.
Question 3:
The low end value is 0.
The high end value is 45.5.
This dataset does have outliers.
The outlier is 95.
Question 4:
The low end is -1, the high end is 23, and there are no outliers in this dataset.
Question 2:
The low end cutoff is 52.
The high end cutoff is 90.
Question 3:
The low end value is 0.
The high end value is 45.5.
This dataset does have outliers.
The outlier is 95.
Question 4:
To check for outliers, we can use the following rule: An observation is considered an outlier if it falls below the low end or above the high end of the range defined by the following equation:
Low End = Q1 - 1.5 * IQR
High End = Q3 + 1.5 * IQR
Calculating the low end and high end using the given values:
Low End = 8 - 1.5 * 6 = -1
High End = 14 + 1.5 * 6 = 23
The outlier is NONE since there are no observations that fall below the low end or above the high end.
Therefore, the low end is -1, the high end is 23, and there are no outliers in this dataset.
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captain rusczyk tracked down a pirate who had stolen $2345 {6}$ dollars worth of goods from his ship. after winning an epic duel, the captain demands that the pirate return $41324 {5}$ dollars. how much has the pirate gone in debt due to his encounter with rusczyk? express your answer in base $10$.
The pirate has gone into debt by $38,979 in base 10 due to his encounter with Captain Rusczyk.
To determine the amount of debt, we need to calculate the difference between the value of the goods the pirate stole and the amount demanded by Captain Rusczyk. The pirate initially stole $2345_6, which means it is in base 6. Converting this to base 10, we have $2\times6^3 + 3\times6^2 + 4\times6^1 + 5\times6^0 = 2\times216 + 3\times36 + 4\times6 + 5\times1 = 432 + 108 + 24 + 5 = 569$.
Captain Rusczyk demanded $41324_5, which means it is in base 5. Converting this to base 10, we have $4\times5^4 + 1\times5^3 + 3\times5^2 + 2\times5^1 + 4\times5^0 = 4\times625 + 1\times125 + 3\times25 + 2\times5 + 4\times1 = 2500 + 125 + 75 + 10 + 4 = 2714$.
Therefore, the pirate has gone into debt by $569 - 2714 = -2145$. Since the pirate owes money, we consider it as a negative value, so the pirate has gone into debt by $38,979 in base 10.
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Simplify. State any restrictions on the variables.
(x² - x)² / x(x-1)⁻² (x²+3 x-4)
Since division by zero is undefined, the expression is not defined for values of x that make the denominator equal to zero. Therefore, the restrictions are x ≠ 0 and x ≠ 1.
To simplify the expression (x² - x)² / x(x-1)⁻² (x²+3x-4), we can simplify each term individually and then combine them. Let's break it down step by step:
1. Simplify the numerator:
(x² - x)² = x⁴ - 2x³ + x²
2. Simplify the denominator:
x(x-1)⁻² = x / (x-1)² = x / (x-1)(x-1) = x / (x² - 2x + 1)
3. Multiply the simplified numerator and denominator:
(x⁴ - 2x³ + x²) / (x / (x² - 2x + 1)) (x²+3x-4)
4. Simplify further by canceling out common factors:
(x⁴ - 2x³ + x²) / (x / (x² - 2x + 1)) (x²+3x-4)
= (x² - 2x + 1) (x²+3x-4)
5. Expand and simplify the expression:
(x² - 2x + 1) (x²+3x-4)
= x⁴ + x³ - 2x³ - 2x² + x² + 3x² - 4x - 2x + 1
= x⁴ - x³ + 2x² + 3x - 4
The simplified expression is x⁴ - x³ + 2x² + 3x - 4.
As for restrictions on the variables, we need to consider the denominator (x(x-1)²). Since division by zero is undefined, the expression is not defined for values of x that make the denominator equal to zero. Therefore, the restrictions are x ≠ 0 and x ≠ 1.
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Daily high temperatures in St. Louis for the last week were as follows: 95,92,94,92,95,90,93 (yesterday). a) The high temperature for today using a 3-day moving average = degrees (round your response to one decimal place). b) The high temperature for today using a 2-day moving average = degrees (round your response to one decimal place). c) The mean absolute deviation based on a 2-day moving average = degrees (round your response to one decimal place). d) The mean squared error for the 2-day moving average = degrees
2
(round your response to one decimal place).
a) The high temperature for today using a 3-day moving average is [tex]\frac{183+x}{3}[/tex] degrees.
b) The high temperature for today using a 2-day moving average is 91.5 degrees.
c) The mean absolute deviation based on a 2-day moving average is 1.5 degrees.
d) The mean squared error for the 2-day moving average is 2.25 degrees.
To calculate the requested values, we'll use the given high temperatures for the last week: 95, 92, 94, 92, 95, 90, 93.
a) The high temperature for today using a 3-day moving average:
To calculate the 3-day moving average, we take the average of the high temperatures for the past three days, which are 90, 93, and today's temperature (unknown). So, the average is [tex]\frac{90+93+x}{3}[/tex] = [tex]\frac{183+x}{3}[/tex] , where x represents today's temperature.
b) The high temperature for today using a 2-day moving average:
Similarly, for the 2-day moving average, we take the average of the high temperatures for the past two days, which are 90 and 93. So, the average is [tex]\frac{90+93}{2}[/tex] = 91.5.
c) The mean absolute deviation based on a 2-day moving average:
To calculate the mean absolute deviation (MAD) based on a 2-day moving average, we find the absolute difference between each day's high temperature and the 2-day moving average (91.5). Then we take the average of those absolute differences. Let's calculate it:
|90 - 91.5| + |93 - 91.5| = 1.5 + 1.5 = 3
MAD = [tex]\frac{3}{2}[/tex] = 1.5
d) The mean squared error for the 2-day moving average:
To calculate the mean squared error (MSE) for the 2-day moving average, we find the squared difference between each day's high temperature and the 2-day moving average (91.5). Then we take the average of those squared differences. Let's calculate it:
(90 - 91.5)² + (93 - 91.5)² = 2.25 + 2.25 = 4.5
MSE = [tex]\frac{4.5}{2}[/tex] = 2.25
Therefore, the answers to the given questions are:
a) The high temperature for today using a 3-day moving average = [tex]\frac{183+x}{3}[/tex] degrees
b) The high temperature for today using a 2-day moving average = 91.5 degrees
c) The mean absolute deviation based on a 2-day moving average = 1.5 degrees
d) The mean squared error for the 2-day moving average = 2.25 degrees
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Find a general solution to the differential equation using the method of variation of parameters y'' 25y=3sec5t
We substitute the values of u1(t) and u2(t) back into the particular solution form:
y_p(t) = u1(t)*e^(5t) + u2(t)*e^(-5t)
The general solution to the given differential equation is then:
y(t) = y_h(t) + y_p(t)
To find the general solution to the given differential equation using the method of variation of parameters, let's start by rewriting the equation in standard form:
y'' - 25y = 3sec(5t)
The corresponding homogeneous equation for this differential equation is y'' - 25y = 0, which has a characteristic equation of r^2 - 25 = 0. Solving this equation, we find that the roots are r = ±5.
Since the roots are distinct, the general solution to the homogeneous equation is given by:
y_h(t) = c1e^(5t) + c2e^(-5t)
Now, let's find the particular solution using the method of variation of parameters. We'll assume the particular solution has the form:
y_p(t) = u1(t)*y1(t) + u2(t)*y2(t)
where y1(t) = e^(5t) and y2(t) = e^(-5t) are solutions to the homogeneous equation.
Next, we need to find the derivatives of y1(t) and y2(t):
y1'(t) = 5e^(5t)
y2'(t) = -5e^(-5t)
Substituting these values into the particular solution form, we have:
y_p(t) = u1(t)*e^(5t) + u2(t)*e^(-5t)
Differentiating with respect to t, we get:
y_p'(t) = u1'(t)e^(5t) + u1(t)*5e^(5t) + u2'(t)e^(-5t) - u2(t)*5e^(-5t)
Now, we substitute y_p(t) and y_p'(t) back into the original differential equation:
y_p''(t) - 25y_p(t) = 3sec(5t)
(u1''(t)e^(5t) + u1'(t)*5e^(5t) + u2''(t)e^(-5t) - u2'(t)*5e^(-5t)) - 25(u1(t)*e^(5t) + u2(t)*e^(-5t)) = 3sec(5t)
Expanding and simplifying, we get:
u1''(t)e^(5t) + u2''(t)e^(-5t) = 3sec(5t)
To solve this equation for u1''(t) and u2''(t), we differentiate the homogeneous solutions y1(t) and y2(t) with respect to t:
y1'(t) = 5e^(5t)
y2'(t) = -5e^(-5t)
Now, we can set up a system of equations based on the coefficients of e^(5t) and e^(-5t):
u1''(t)e^(5t) + u2''(t)e^(-5t) = 0
u1''(t)5e^(5t) + u2''(t)(-5e^(-5t)) = 3sec(5t)
Solving this system of equations will give us the values of u1''(t) and u2''(t). Once we find those, we can integrate twice to find u1(t) and u2(t).
Finally, we substitute the values of u1(t) and u2(t) back into the particular solution form:
y_p(t) = u1(t)*e^(5t) + u2(t)*e^(-5t)
The general solution to the given differential equation is then:
y(t) = y_h(t) + y_p(t)
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Describe a situation in which the number of outcomes is given by ₉P₂.
The situation in which the number of outcomes is given by ₉P₂ can be described as selecting and arranging two items from a set of nine distinct items without replacement permutations.
For example, let's consider a scenario where there are nine students competing for the positions of president and vice-president in a student council election. Each student can only hold one position.
In this case, the number of outcomes can be calculated using the permutation formula ₙPᵣ, where n is the total number of items and r is the number of items being selected.
In ₉P₂, we have nine students to choose from and we need to select two students for the positions of president and vice-president. The order in which the students are chosen matters, as the positions of president and vice-president are distinct.
Therefore, ₉P₂ will give us the number of possible outcomes for selecting and arranging two students from the group of nine for the positions of president and vice-president in the student council election.
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Kwan-Yong bought two computer games for just over 80 before tax. A few weeks later, his friend asked how much each game cost. Kwan-Yong could not remember the individual prices. Use indirect reasoning to show that at least one of the games cost more than 40 .
If we assume the cost of both games is more than 40 then by assumption and contradiction we can conclude that at least one of the games costs more than 40.
Firstly, let's assume that the games are x and y.
Also, assume that x≤40 and y≤40 is true.
Given. they bought two games for just over 80.
or, x+y>80................ (i)
As per assumption, x≤40 and y≤40.
∴x+y≤40+40.
⇒x+y≤80... Now that's a contradiction as we know, x+y>80 always.
So our assumption was wrong. x [tex]\nleq[/tex]40 and y[tex]\nleq[/tex] 40. So the conclusion that x > 40 or y > 40 must be true.
Hence, proved that at least one of the games cost more than 40.
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I WILL MARK
Q.17
A vase can be modeled using x squared over 5 and 5225 ten thousandths minus quantity y minus 5 end quantity squared over 42 and 25 hundredths equals 1 and the x-axis, for 0 ≤ y ≤ 20, where the measurements are in inches. Using the graph, what is the distance across the base of the vase, and how does it relate to the hyperbola?
A. 5.93 inches; distance between the x-intercepts
B. 4.50 inches; length of the transverse axis
C. 2.97 inches; distance between the intercepts
D. 2.35 inches; length of the transverse axis
The distance across the base of the vase is equal to the length of the transverse axis of the hyperbola.
D. 2.35 inches; length of the transverse axis.
From the given equation, we can identify that it represents a hyperbola in standard form:
[tex](x^2/5) - (y-5)^2/42.25 = 1[/tex]
Comparing this equation to the standard form of a hyperbola:
[tex](x-h)^2/a^2 - (y-k)^2/b^2 = 1[/tex]
We can determine that:
The center of the hyperbola is at (h, k) = (0, 5)
The value of [tex]a^2[/tex] is 5, which means a = sqrt(5)
The value of [tex]b^2[/tex] is 42.25, which means b = sqrt(42.25) = 2sqrt(10.5625) = 2 * 3.25 = 6.5
The distance across the base of the vase corresponds to the length of the transverse axis of the hyperbola.
In this case, the length of the transverse axis is 2a, which is equal to 2 * sqrt(5) = 2sqrt(5).
Therefore, the correct answer is:
D. 2.35 inches; length of the transverse axis.
The distance between the x-intercepts or the distance between the intercepts is not related to the length of the transverse axis in a hyperbola.
It is important to understand the geometric properties and equations of different conic sections to interpret the graph correctly.
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Only manipulate one side. Please type the answer
cotβ − cotβcos²β = sinβcosβ
Answer:
Step-by-step explanation:
Consider the RHS:
cot(β)-cot(β)(cos^2(β)=sin(β)cos(β)
Factor cot
cot(β)(1-cos^2(β)=sin(β)cos(β)
Use Pythagorean Idenity
cot(β)(sin^2(β)= sin(β)cos(β)
Simplify cot(β)= sin(β)cos(β)
(cos(β)/sin(β))(sin(β)sin(β)= sin(β)cos(β)
sin(β)cos(β)=sin(β)cos(β)
QED
Consider a sample space defined by events A
1
,A
2
,B
1
, and B
2
, where A
1
and A
2
are complements. Given P(A
1
)=0.3,P(B
1
∣A
1
)=0.6, and P(B
1
∣A
2
)=0.5, what is the probability of P(A
1
∣B
1
) ? P(A
1
∣B
1
)= (Round to three decimal places as needed.)
The probability of A1 occurring given B1 is approximately 0.375, rounded to three decimal places.
To find the probability of P(A1|B1), we can use Bayes' theorem:
P(A1|B1) = (P(B1|A1) * P(A1)) / P(B1)
Given that A1 and A2 are complements, P(A2) can be calculated as 1 - P(A1), which means P(A2) = 0.7.
We are given P(B1|A1) = 0.6 and P(B1|A2) = 0.5.
Now, to calculate P(B1), we can use the law of total probability:
P(B1) = P(B1|A1) * P(A1) + P(B1|A2) * P(A2)
Substituting the given values, we get:
P(B1) = (0.6 * 0.3) + (0.5 * 0.7)
= 0.18 + 0.35
= 0.53
Finally, we can calculate P(A1|B1) using Bayes' theorem:
P(A1|B1) = (P(B1|A1) * P(A1)) / P(B1)
= (0.6 * 0.3) / 0.53
≈ 0.375
Therefore, the probability of A1 occurring given B1 is approximately 0.375, rounded to three decimal places.
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A DVD that originally cost $30 is on sale for 10 percent off. Complete the steps to solve the problem.
Step 1: Find the amount of the discount.
Answer: Cost price of DVD = $30
Discount rate = 10%
Discount amount = $ (10/100)* 30 = $3
Step-by-step explanation :
Data given,
original price = $30discount rate = 10%discount amount = ?Discount Price
The discount price of the product can be calculated when we multiply the discount rate with the cost price. The formula is given below
discount amount = discount rate × cost price
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The ratio of the measures of the three sides of a triangle is 1/4 : 1/8 : 1/6 . Its perimeter is 4.75 feet. Find the length of the longest side.
The length of the longest side is 3.17 feet.
To find the length of the longest side, we need to determine the actual measurements of the sides of the triangle.
Given:
Ratio of side lengths: 1/4 : 1/8 : 1/6
Perimeter of the triangle: 4.75 feet
Let's assume the common ratio between the side lengths is x. We can set up the equation:
(1/4)x + (1/8)x + (1/6)x = 4.75
Simplifying the equation:
(3/24)x + (2/24)x + (4/24)x = 4.75
(9/24)x = 4.75
x = (4.75 * 24) / 9
x = 12.67
Now we can find the actual measurements of the sides by multiplying each ratio by x:
Longest side = (1/4)x = (1/4)(12.67) = 3.17 feet
Therefore, the length of the longest side is 3.17 feet.
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i need help with 1 and 2!!
1. select the graph(s) and/or table(s) thag represent functions. choose all that apply.
2. Which set of ordered pairs does NOT represent a function?
1. The graphs and table that represent functions include the following: B, C, and E.
2. The set of ordered pairs that does not represent a function are:
A. {(-4, 9), (-4, 7), (1, -5), (7, -7)}.
C. {(-2, 0), (0, -2), (1, 1), (2, 0)}.
D. {(-5, 4), (-3, 4), (-1, 4), (2, 4)}.
What is a function?In Mathematics and Geometry, a function is used for defining and representing the relationship that exists between two or more variables in a relation, table, ordered pairs, or graph.
Part 1.
Based on the given graphs and tables, we can logically deduce that the graph of a circle represent a relation because it does not have an inverse function. Also, tables D and F does not represent a function because the input values (domain) are not uniquely mapped to the output values (range).
Part 2.
Based on the given set of ordered pairs, we can logically deduce that only set A represent a function because the input values (domain) its uniquely mapped to the output values (range).
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Derive u(c,n)=ln(c)+0.4×ln(1−n) w.r.t. n which stands for labor. 1/c 1/n 0.4/(1−n) 0.4 ∗
1/(1−n) ∗
(−1) QUESTION 18 Derive the following function u(c,n,h)=(5×ln(c)×2×ln(1−n))+ 1−γ
h 1−γ
where γ=2.5 w.r.t. h. The evaluate the numeric value of this derivative at the point c=1, n=0.5, and h=2
To derive the function u(c, n, h) = [tex](5 * ln(c) * 2 * ln(1 - n)) + (1 - γ) / h[/tex]with respect to h, we can follow the standard rules of differentiation. the numeric value of the derivative at the given point is -0.375.
Step 1: Take the derivative of each term separately.
The derivative of 5 * ln(c) * 2 * ln(1 - n) with respect to h is 0 since h does not appear in this term.
The derivative of (1 - γ) / h with respect to h can be found using the quotient rule:
[tex]d/dh [(1 - γ) / h] = [(h * 0 - (1 - γ) * 1) / h^2] = -(1 - γ) / h^2[/tex]
Step 2: Simplify the derivative.
The derivative of u(c, n, h) with respect to h is -(1 - γ) / h^2.
Now, we can evaluate the numeric value of this derivative at the point c = 1, n = 0.5, and h = 2.
γ = 2.5
c = 1
n = 0.5
h = 2
Substituting these values into the derivative expression:
[tex]d/dh [(5 * ln(c) * 2 * ln(1 - n)) + (1 - γ) / h][/tex]
= -(1 - γ) / h^2
= -(1 - 2.5) / 2^2
= -1.5 / 4
= -0.375
Therefore, the numeric value of the derivative at the given point is -0.375.
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You invested money in a company and each month you receive a payment for your investment. Over the first four months, you received $ 50, $ 52, $ 56 , and $ 62 . If this pattern continues, how much do you receive in the tenth month?
c. How can you use your formula to find the amount you receive in the tenth month?
You would receive $68 in the tenth month based on the given pattern and formula.
To find the amount you receive in the tenth month, we need to identify the pattern in the payments and use it to establish a formula.
From the given information, we can observe that the payments are increasing each month. Let's denote the first month as month 1 and the corresponding payment as [tex]P_1[/tex], the second month as month 2 with payment [tex]P_2[/tex], and so on. We have:
Month 1: [tex]P_1[/tex] = $50
Month 2: [tex]P_2[/tex] = $52 (an increase of $2 from the previous month)
Month 3: [tex]P_3[/tex] = $56 (an increase of $4 from the previous month)
Month 4: [tex]P_4[/tex] = $62 (an increase of $6 from the previous month)
We can see that the increase in payment is consistent, increasing by $2 each month. We can express this pattern with a formula:
[tex]P_n = P_1 + (n - 1) * d[/tex]
where [tex]P_n[/tex] represents the payment in the nth month, [tex]P_1[/tex] is the initial payment, we can see that the pattern is in arithmetical progression, n is the month number, and d is the common difference between the payments.
In this case, [tex]P_1[/tex] = $50, and the common difference d = $2. Using this formula, we can calculate the payment in the tenth month (n = 10):
[tex]P_{10} = P_1 + (10 - 1) * d[/tex]
= $50 + 9 * $2
= $50 + $18
= $68
Therefore, you would receive $68 in the tenth month based on the given pattern and formula.
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π is an irrational number you can use to calculate the circumference or area of a circle.
(b) The value of π is often represented as (22/7) . How does this representation compare to the decimal representation your calculator gives using the π key?
The value of pi = 22/7, used by all is a larger approximation used for all purposes. It can be used to calculate both the circumference and area of any circle.
As we all know, pi is an irrational number, and one of the most used constants in mathematical history. It was originally discovered by ancient civilizations like the Egyptians and was defined as the ratio of the circumference to the diameter of any circle after it turned out to be the same for circle of any radius.
They found out the approximation we used nowadays. Using the ratio 3 (1/7), they performed their calculations. Now we directly use it as 22/7, since it was and is, a really good approximation for Pi.
But 22/7 = 3.142857, and the same 6 digits recur repeatedly to infinity. This wasn't the case with the actual value of Pi, found out later. The original Pi is an irrational number, and thus can't be written as a fraction.
Pi = 3.141592...
Although the fractional form 22/7 has a slight error, it was considerably ignorable for practical purposes of calculations to a large extent. Only where the precise decimals were necessary, the original value was used, otherwise it was just 22/7 or 3.14 for general work.
As we can observe,
22/7 > Pi.
Error percentage: 4 * 10⁻² %
Thus, we can calculate both area and circumference of a circle. 22/7 is a larger approximation of the original value of Pi.
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Consider the following cost function (C): C=0.3q
3
−4q
2
+80q+F The equation for average cost (AC) is: AC=
q
0.3q
3
−4q
2
+80q+F
. (Properly format your expression using the tools in the palette. Hover over tools to see keyboard shortcuts. E.g., a superscript can be created with the
∧
character.) The equation for variable cost (VC) is: VC=0.3q
3
−4q
2
+80q. (Properly format your expression using the tools in the palette.) The equation for marginal cost (MC) is: MC = (Properly format your expression using the tools in the palette.)
The cost function C is given by[tex]C = 0.3q^3 - 4q^2 + 80q + F[/tex], where q represents the quantity produced and F represents a fixed cost. The average cost (AC) equation is[tex]AC = (0.3q^3 - 4q^2 + 80q + F) / q[/tex], and the variable cost (VC) equation is [tex]VC = 0.3q^3 - 4q^2 + 80q[/tex]
The cost function C represents the total cost of production, which includes both variable costs (costs that change with the level of production) and fixed costs (costs that remain constant regardless of the level of production). In this case, the cost function is a polynomial equation of degree 3.
To calculate the average cost (AC) ,we divide the total cost (C) by the quantity (q) produced. This gives us the average cost per unit of output.
The variable cost (VC) represents the cost associated with producing each unit of output and is obtained by excluding the fixed cost component from the total cost function.
The marginal cost (MC) represents the additional cost incurred by producing one additional unit of output. It is calculated by taking the derivative of the variable cost equation with respect to the quantity (q).
By understanding these equations, we can analyze and make decisions regarding production levels, pricing, and cost optimization in the given scenario.
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For trapezoid Q R T U, V and S are midpoints of the legs.
If Q R=12 and U T=22 , find V S .
In a trapezoid where V and S are the midpoints of the legs Q R and U T, we can use the property that the segment connecting the midpoints of the legs is parallel to the bases and its length is equal to the average of the lengths of the bases.
Given that QR = 12 and UT = 22, we can find VS using the formula:
VS = (QR + UT) / 2
Substituting the values:
VS = (12 + 22) / 2
VS = 34 / 2
VS = 17
Therefore, the length of VS in trapezoid QRTU is 17.
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Write a two-column proof.
Theorem 7.11
Given CD bisects ∠ACB .
By construction, AE|CD .
Prove: A D/DB = A E/BC
Using the two column proof, we use the fact that corresponding sides of similar triangles are proportional to state that AD/DB is equal to AE/BC
To write a two-column proof, we need to provide statements and reasons for each step. Here is the proof for the given problem:
Statement | Reason
------------------------------------------------------
1. CD bisects ∠ACB | Given
2. AE|CD | By construction
3. ∠AED ≅ ∠CDB | Corresponding angles
4. ∠ADE ≅ ∠CBD | Vertical angles
5. △ADE ~ △CDB | Angle-angle similarity
6. AD/DB = AE/BC | Corresponding sides of similar triangles are proportional
In this proof, we start by stating the given information (statement 1) that CD bisects angle ACB. Then, we mention that AE is parallel to CD (statement 2) by construction.
Next, we use the corresponding angles theorem to state that angle AED is congruent to angle CDB (statement 3). We also use the fact that angle ADE is congruent to angle CBD (statement 4) because they are vertical angles.
Based on the congruent angles, we conclude that triangles ADE and CDB are similar (statement 5) by angle-angle similarity.
Finally, we use the fact that corresponding sides of similar triangles are proportional to state that AD/DB is equal to AE/BC (statement 6).
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Determine whether there is a minimum or maximum value to the quadratic function.
h(t)=−8t²+4t−1
O minimum
O maximum
The quadratic function h(t) = -8t² + 4t - 1 has a maximum value.
To determine whether the quadratic function has a minimum or maximum value, we need to examine the coefficient of the squared term (t²). In this case, the coefficient is negative (-8), which means the parabola opens downward, indicating a maximum value.
To find the coordinates of the maximum point, we can use the formula t = -b / 2a, where a, b, and c are the coefficients of the quadratic function. In this case, a = -8 and b = 4. Plugging these values into the formula, we get t = -4 / (2 * (-8)), which simplifies to t = 1/4.
Substituting t = 1/4 back into the original equation, we find h(1/4) = -8(1/4)² + 4(1/4) - 1. Simplifying this expression, we get h(1/4) = -1/2.
Therefore, the quadratic function h(t) = -8t² + 4t - 1 has a maximum value of -1/2, which occurs at t = 1/4.
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Add or subtract.
4 /√5 - √3 - 4 /√5+√3
The solution of expression is,
⇒ [tex]\frac{4}{\sqrt{5} - \sqrt{3} } - \frac{4}{\sqrt{5} + \sqrt{3}}[/tex] = 2 (2√3)
We have to give that,
An expression to solve,
⇒ [tex]\frac{4}{\sqrt{5} - \sqrt{3} } - \frac{4}{\sqrt{5} + \sqrt{3}}[/tex]
Now, Simplify the expression by adding or subtraction as,
⇒ [tex]\frac{4}{\sqrt{5} - \sqrt{3} } - \frac{4}{\sqrt{5} + \sqrt{3}}[/tex]
Take 4 as common,
⇒ 4 ([tex]\frac{1}{\sqrt{5} - \sqrt{3} } - \frac{1}{\sqrt{5} + \sqrt{3}}[/tex])
⇒ 4 (√5 + √3)- (√5 - √3) / (5 - 3)
⇒ 4 (√5 + √3 - √5 + √3) / 2
⇒ 2 (2√3)
Therefore, The solution is,
⇒ [tex]\frac{4}{\sqrt{5} - \sqrt{3} } - \frac{4}{\sqrt{5} + \sqrt{3}}[/tex] = 2 (2√3)
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State the dimensions of each matrix. 6 9 0 3 , 4 6 2 7
State the dimensions of each matrix.
[6 9 0 3]
[4 6 2 7]
4 × 2 matrix.
What is dimensionsThe dimension of Col A, also known as the column space of the matrix A, is the dimension of the subspace spanned by the columns of the matrix A.
In other words, it is the number of linearly independent columns of matrix A.
The sum of two matrices has as a result a matrix with the same number of rows and columns. This is done by adding each corresponding element of the matrices, that means, the each element (same row and column) of matrix A adding with each element (same row and column) of matrix b, and so on.
What is determinantIn linear algebra, the determinant is a scalar value that can be computed from the elements of a square matrix and encodes certain properties of the linear transformation described by the matrix.
The determinant of a matrix A is denoted det(A), det A, or |A|.
To determine the dimensions of each matrix. 6 9 0 3 , 4 6 2 7
[6 9 0 3]
[4 6 2 7]
The number of linearly independent columns of matrix is 4 × 2.
Therefore this matrix is called 4 × 2 matrix.
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HELP FASTERRRRRRRRRRRR
BROOOO CHILLLLLLLL
its the first one
i dont know how to explain
What is the simplest formula of a compound if a sample of the compound contains 0.309 mol x, 1.545 mol y, and 2.472 mol z?
The resulting ratio is 1:5:8, which indicates that the simplest formula of the compound is XY₅Z₈.
Given:
Moles of element X: 0.309 mol
Moles of element Y: 1.545 mol
Moles of element Z: 2.472 mol
To find the simplest formula, we need to divide the number of moles of each element by the smallest number of moles among them.
In this case, 0.309 mol is the smallest number of moles.
Moles of element X: 0.309 mol / 0.309 mol = 1
Moles of element Y: 1.545 mol / 0.309 mol = 5
Moles of element Z: 2.472 mol / 0.309 mol = 8
Thus, the resulting ratio is 1:5:8, which indicates that the simplest formula of the compound is XY₅Z₈.
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Which of the following is NOT impacted by changing the chart style? The data in the chart The color of the chart area The color of the plot area The depth of the chart
The depth of the chart is NOT impacted by changing the chart style. When changing the chart style, various elements of the chart may be affected.
The data in the chart is directly influenced by the chart style. Different chart styles can present the data in various formats, such as bar charts, line charts, or pie charts, altering how the data is visually represented.
The color of the chart area can be influenced by changing the chart style. The chart area refers to the background or border color surrounding the chart. Different chart styles may utilize different color schemes or themes, which can impact the chart area color.
Similarly, the color of the plot area, which represents the space within the chart where the data is plotted, can be influenced by changing the chart style. Different chart styles may use different color palettes for the plot area, affecting the visual representation of the data points.
However, the depth of the chart, referring to the three-dimensional perspective or layered effect of the chart, is not typically impacted by changing the chart style. The depth of a chart is usually a separate setting or option within charting software, allowing users to control the 3D effect or stacking of chart elements. Changing the chart style does not inherently alter this depth setting.
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