Find all the zeros for each function.

P(x)=x⁴-4 x³-16 x²+21 x+18

Approximately 86.64% of female brown bears have weights that are within 1.5 standard deviations of the mean.

To find the percentage of female brown bears with weights within 1.5 standard deviations of the mean, we can refer to the empirical rule (also known as the 68-95-99.7 rule) in statistics. According to the empirical rule, approximately 68% of the data falls within 1 standard deviation of the mean in a normally distributed dataset. Therefore, approximately 34% of the data is within 0.5 standard deviations on either side of the mean.

Since we want to find the percentage within 1.5 standard deviations, which is 3 times the standard deviation, we can apply the empirical rule. 1.5 standard deviations represents about 3 sections of the dataset. Each section covers approximately 34% of the data.

Therefore, the percentage of female brown bears with weights within 1.5 standard deviations of the mean is approximately 34% + 34% + 34% = 86%. Rounding to the nearest hundredth, it is approximately 86.64%.

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The perimeter of the vacant lot, rounded to the nearest foot, is approximately 410 ft.

To find the perimeter of the vacant lot, we need to calculate the total length of all its sides.

Given that the vacant lot is in the shape of an isosceles triangle with two sides facing the streets, and each of these sides is 150 ft long, we can determine the length of the base side by using the properties of an isosceles triangle.

In an isosceles triangle, the base side is the side opposite the vertex angle. Since the streets intersect at an 85.9° angle, the vertex angle of the triangle is half of that, which is 85.9°/2 = 42.95°.

To find the length of the base side, we can use the trigonometric function cosine (cos). The cosine of an angle is the ratio of the adjacent side to the hypotenuse in a right triangle. In this case, the adjacent side is half of the base side, and the hypotenuse is one of the equal sides of the triangle.

Using the cosine function, we can calculate:

cos(42.95°) = adjacent side / 150 ft

Rearranging the equation to solve for the adjacent side:

adjacent side = cos(42.95°) * 150 ft

Now, we can find the perimeter by adding up the lengths of all sides:

Perimeter = 150 ft + 150 ft + (adjacent side)

Substituting the value of the adjacent side:

Perimeter = 150 ft + 150 ft + (cos(42.95°) * 150 ft)

Calculating the value:

Perimeter ≈ 150 ft + 150 ft + (0.732 * 150 ft)

        ≈ 150 ft + 150 ft + 109.8 ft

        ≈ 409.8 ft

Therefore, the perimeter of the vacant lot, rounded to the nearest foot, is approximately 410 ft.

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The solutions of the quadratic equation 25x²+30x=12 are x=-3/5±√21/25. We can solve the equation by completing the square. First, we divide both sides of the equation by 25 to get x²+6x=0.4.

Then, we move the constant term to the right side of the equation to get x²+6x=-0.4. To complete the square, we take half of the coefficient of our x term, which is 6, and square it. This gives us 9. We then add 9 to both sides of the equation to get x²+6x+9=8.5. We can now rewrite the left side of the equation as a squared term, (x+3)²=8.5.

Taking the square root of both sides, we get x+3=√8.5. Simplifying the radical gives us x+3=±√21/5. Finally, we subtract 3 from both sides to get our solutions, x=-3/5±√21/25.

x=-b±√b²-4ac/2a

In this case, a=25, b=30, and c=-12. Substituting these values into the quadratic formula, we get:

x=-30±√30²-4(25)(-12)/2(25)

=-3/5±√21/25

As we can see, the solutions we obtained using completing the square are the same as the solutions we obtained using the quadratic formula.

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The  line at the coffee shop during rush hour is 15 people long.

Given:

- 5 people arrive at the coffee shop each minute.

- Each person has to wait for 3 minutes to be served.

Since 5 people arrive each minute,  the rate of people entering the line is 5 people/minute.

Now, Each person has to wait for 3 minutes to be served.

So, Average length of line = Rate of people entering * Time for a person to be served

Average length of line = 5 people/minute * 3 minutes

Average length of line = 15 people

Therefore, on average, the line at the coffee shop during rush hour is 15 people long.

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The two possible algebraic expression could be 1( 5x + 10y - 35), 5(x + 2y - 7)

The "inverse" operation of the distributive property is factoring common terms:

since the litera part is different for each term (we have a term involving x alone, a term involving y alone, and a pure number), we can only factor the numerical part.

5, 10 and 35 have factor 1 or 5 in common, so the two possible algebraic expression could be

5x + 10y - 35.

1( 5x + 10y - 35)

5(x + 2y - 7)

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The zeros of the function y = x³ - 2x² - 3x + 6 are x = 1, x = 3, and x = -2. These are the values of x where the function equals zero. To find the zeros of the function y = x³ - 2x² - 3x + 6, we need to solve for x when y equals zero.

Setting y = 0, we have the equation:

x³ - 2x² - 3x + 6 = 0

To find the zeros, we can use various methods such as factoring, synthetic division, or numerical methods. In this case, we will use factoring and the rational root theorem.

Using the rational root theorem, the possible rational roots of the equation are factors of the constant term (6) divided by factors of the leading coefficient (1). Therefore, the possible rational roots are ±1, ±2, ±3, and ±6.

Testing these values, we find that x = 1 is a zero of the equation:

(1)³ - 2(1)² - 3(1) + 6 = 0

Simplifying, we get:

1 - 2 - 3 + 6 = 0

Next, we can factor the equation using the synthetic division method. Dividing the polynomial by (x - 1), we get:

(x - 1)(x² - x - 6) = 0

Factoring the quadratic expression x² - x - 6, we have:

(x - 1)(x - 3)(x + 2) = 0

Setting each factor equal to zero, we find the remaining zeros:

x - 1 = 0   -->   x = 1

x - 3 = 0   -->   x = 3

x + 2 = 0   -->   x = -2

Therefore, the zeros of the function y = x³ - 2x² - 3x + 6 are x = 1, x = 3, and x = -2. These are the values of x where the function equals zero.

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The point(s) of intersection are (2, 0) and (-2, -4)

From the question, we have the following parameters that can be used in our computation:

x² + (y + 2)² = 8

y = x -2

Substitute the known values in the above equation, so, we have the following representation

x² + (x - 2 + 2)² = 8

So, we have

x² + x² = 8

2x² = 8

x² = 4

Take the square roots

x = ±2

Next, we have

y = ±2 - 2

y = 0 or -4

Hence, the intersection points are (2, 0) and (-2, -4)

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The value of x is 51.

We are given a right-angled triangle in the image. We are also given the two different sides of this triangle and we have to find the third side using Pythagoras theorem. The two sides given are 45 and 24, and the third side is taken as x.

We will apply the Pythagoras theorem to this triangle. We can see that the base is 45 cm and the perpendicular is 24 cm. The hypotenuse is assumed to be x and we have to find the value of x.

[tex](H)^2 = (B)^2 + (P)^2[/tex]

(x[tex])^2[/tex] = (45[tex])^2[/tex] + (24[tex])^2[/tex]

(x[tex])^2[/tex] = 2025 + 576

(x[tex])^2[/tex] = 2601

Taking the square root on both sides, we get;

x = 51.

Therefore, the value of x or the hypotenuse of the triangle is 51 cm.

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The given quadratic equation [tex]x^2 - 2x + 2 = 0[/tex] has no real solutions.

To find the solutions to the quadratic equation  [tex]x^2 - 2x + 2 = 0[/tex] , we can use the quadratic formula:

[tex]x = (-b \pm \sqrt{b^2 - 4ac}) / (2a)[/tex]

For the given equation, a = 1, b = -2, and c = 2. Substituting these values into the quadratic formula, we have:

[tex]x = (-(-2) \pm \sqrt{(-2)^2 - 4(1)(2)}) / (2(1))\\x = (2 \pm \sqrt{4 - 8}) / 2\\x = (2 \pm \sqrt{-4}) / 2[/tex]

The expression inside the square root, -4, indicates that the quadratic equation does not have any real solutions. The square root of a negative number is not a real number.

Therefore, the quadratic equation [tex]x^2 - 2x + 2 = 0[/tex] has no real solutions.

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cos(θ/2) = √[(1 + cosθ) / 2]

To find the exact value of cos(θ/2) given cosθ = -15/17 and 180° < θ < 270°, we can use the half-angle formula for cosine. The half-angle formula states that cos(θ/2) = √[(1 + cosθ) / 2].

First, we substitute the given value of cosθ into the formula. We have cos(θ/2) = √[(1 + (-15/17)) / 2].

Next, we simplify the expression inside the square root. 1 + (-15/17) = (17 - 15) / 17 = 2 / 17.

Therefore, cos(θ/2) = √[(2/17) / 2].

To further simplify, we divide 2/17 by 2, which gives us 1/17.

Thus, the exact value of cos(θ/2) is √(1/17), which cannot be simplified further since 17 is not a perfect square.

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The number of possible values for b depends on the number of distinct prime factors greater than p and q, where p and q are the prime factors of a. If there are n such prime factors.

The number of possible values for b can be determined by considering the prime factors of a and the conditions given in the problem. Since a = pg, where p and q are prime factors of a, we know that b must be greater than a. Additionally, the quotient a/b must be an integer.

To find the number of possible values for b, we need to analyze the conditions further. Since p and q are distinct prime factors of a, their product pg is the prime factorization of a. If we consider the prime factorization of b, it should include at least one prime factor that is greater than p or q. This is because b must be greater than a.

Considering the conditions mentioned, the number of possible values for b depends on the number of prime factors greater than p and q. If there are n prime factors greater than p and q, then there are n possible values for b. However, it's important to note that the prime factors greater than p and q must be distinct, as mentioned in the problem.

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After measuring the length of a needle, drawing the lines and doing this experiment we can summarize, the number of hits after 25 drops - 15, the number of hits after 50 drops- 35, and the number of hits after 100 drops - 64.

(b)For 25 drops,50 drops, and 100 drops the mentioned ratio should be, 3.33, 2.86, and 3.13 respectively.

(c) As the number of drops increases the ratio will approach π value.

After we measure the length of a needle we get it's 1.27 cm.

∴l=1.27cm.

Now as given, a set of horizontal lines that are l(=1.27) centimeters apart, is to be drawn.

 After the test is performed we can note our data as after 25, 50, and 100 drops the number of hits are 15,35, and 64 respectively.

(b) Now need to calculate the ratio of (2 × the total number of drops)  to the number of hits.

For 25 drops : [tex]\frac{2.25}{15}[/tex] = 3.33(Approx.)

For 50 drops: [tex]\frac{2.50}{35}[/tex] = 2.86(Approx.).

For 100 dros: [tex]\frac{2.100}{64}[/tex]=3.13(Approx.)

(c) The value of π is 3.14 approx. So as the number of drops increases and the number of hits decreases the value will approach the value of π.

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The complete question is, "Measure the length l of a needle (or toothpick) in centimeters. Next, draw a set of horizontal lines that are l centimeters apart on a sheet of plain white paper. a. Drop the needle onto the paper. When the needle lands, record whether it touches one of the lines as a hit. Record the number of hits after 25, 50, and 100 drops. b. Calculate the ratio of two times the total number of drops to the number of hits after 25, 50, and 100 drops. c. How are the values you found in part b. related to π ?"

Neither Terrence nor Rodrigo is correct in this case.

Terrence's statement is incorrect because the angle of depression is not the complement of the angle of elevation. The angle of depression is the angle below the horizontal line, while the angle of elevation is the angle above the horizontal line. These two angles are not complementary.

Rodrigo's statement is also incorrect. The angle of depression is not equal to the angle of elevation. The angle of depression is the angle at which an observer looks downward from a horizontal line, while the angle of elevation is the angle at which an observer looks upward from a horizontal line. These two angles are generally different unless the line of sight is perpendicular to the horizontal line.

The angles of elevation and depression are not complementary nor equal in general, as they represent different perspectives in relation to the horizontal line.

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To divide and simplify the expression √48x³ / √3xy², we can use the properties of square roots.

First, let's simplify the square roots separately. The square root of 48 can be written as the square root of 16 times the square root of 3, which simplifies to 4√3. Similarly, the square root of x³ can be written as x^(3/2).  Next, we simplify the denominator. The square root of 3 can be left as √3, and the square root of xy² can be written as the square root of x times the square root of y², which simplifies to √xy.

Now, we can rewrite the expression as (4√3 * x^(3/2)) / (√3 * √xy). Simplifying further, we can cancel out the square root of 3 in both the numerator and denominator, resulting in (4 * x^(3/2)) / (√xy). Therefore, the simplified expression is 4x^(3/2) / √xy.

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For the utility function U(x, y) = [tex]x^(4/1) * y^(4/3)[/tex], the indifference curve equations for U = 1, U = 2, and U = 3 are derived. The shape of the indifference curves resembles rectangular hyperbolas.

For the utility function U(x, y) = [tex]x^(4/1) * y^(4/3)[/tex], we derive the indifference curve equations for U = 1, U = 2, and U = 3. By setting the utility function equal to these values, we can solve for the corresponding relationships between x and y.

The resulting equations form rectangular hyperbolas, where the ratio of x to y remains constant along each curve. These curves are concave and exhibit diminishing marginal rates of substitution.

For the utility function U(x, y) = y - 2x, we derive the indifference curve equations for U = 1, U = 2, and U = 3. By setting the utility function equal to these values, we can solve for the relationships between x and y.

The resulting equations represent straight lines with a slope of 2, indicating a constant marginal rate of substitution between x and y. These indifference curves show a positive linear relationship between the two goods.

Both utility functions satisfy the assumptions of completeness, transitivity, and monotonicity. Completeness implies that the consumer can rank all bundles of goods, transitivity ensures consistent preferences, and monotonicity states that more of a good is preferred to less.

The derived indifference curves reflect these assumptions by providing a consistent ranking of bundles based on utility. The shapes of the indifference curves are well-defined, allowing for clear visual representations of the preferences of the consumer.

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The vertex of the parabolic function y = -x² + 2x + 1 is (1, 2), and the axis of symmetry is x = 1. The vertex is a maximum point, and the maximum value is 2. The range is (-∞, 2].

The given parabolic function is y = -x² + 2x + 1.

To identify the vertex and the axis of symmetry, we can use the formula:

x = -b / 2a

where a = -1 and b = 2. Substituting these values, we get:

x = -2 / 2(-1) = 1

This is the x-coordinate of the vertex. To find the y-coordinate, we substitute x = 1 into the function:

y = -(1)² + 2(1) + 1 = 2

Therefore, the vertex is (1, 2), and the axis of symmetry is x = 1.

To determine whether the vertex is a maximum or a minimum point, we can look at the coefficient of x². Since it is negative, the parabola opens downwards and the vertex is a maximum point.

The range of the function is all real numbers less than or equal to the y-coordinate of the vertex, which is 2.

Therefore, the vertex is (1, 2), the axis of symmetry is x = 1, the maximum value is 2, and the range is (-∞, 2].

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The IS relation is given by: Y = (intercept value rounded to two decimal places) + (slope value rounded to two decimal places) in the numerical example of the IS-LM model.

To derive the IS relation, we need to equate aggregate demand (AD) to aggregate supply (AS). Aggregate demand consists of consumption (C), investment (I), government spending (G), and net exports (NX). In this case, we assume net exports to be zero.

Given:

C = 233 + 0.47YD

I = 143 + 0.22Y - 1,094i

G = 299

T = 239

Aggregate demand (AD) = C + I + G

Substituting the given equations into AD:

AD = (233 + 0.47YD) + (143 + 0.22Y - 1,094i) + 299

Simplifying:

AD = 233 + 143 + 299 + 0.47YD + 0.22Y - 1,094i

Combining like terms:

AD = 675 + 0.47YD + 0.22Y - 1,094i

Since we want an equation with Y on the left side, we need to express YD in terms of Y by substituting YD = Y - T.

AD = 675 + 0.47(Y - T) + 0.22Y - 1,094i

AD = 675 + 0.47Y - 0.47T + 0.22Y - 1,094i

Combining like terms again:

AD = (0.47Y + 0.22Y) + (675 - 0.47T - 1,094i)

AD = 0.69Y - 0.47T - 1,094i + 675

Comparing with the IS relation Y = a + bAD, we have:

Y = 0.69Y - 0.47T - 1,094i + 675

Rearranging terms to have Y on the left side:

Y - 0.69Y = -0.47T - 1,094i + 675

0.31Y = -0.47T - 1,094i + 675

Dividing both sides by 0.31:

Y = (-0.47T - 1,094i + 675) / 0.31

Now, we can calculate the intercept and slope terms:

Intercept term = (-0.47T - 1,094i + 675) / 0.31

Slope term = 1 / 0.31

Rounding these values to two decimal places, the IS relation is:

Y = Intercept term + Slope term = (intercept value rounded to two decimal places) + (slope value rounded to two decimal places).

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For the given data set (7, 10, 7, 5, 7, 8, 4, 4, 8, 25), the range is 21, the population variance is approximately 33.4 (rounded to one decimal place), and the population standard deviation is approximately 5.8

To calculate the range of a data set, we subtract the smallest value from the largest value. In this case, the range is 25 - 4 = 21.

To find the population variance, we first need to calculate the mean (average) of the data set. The mean is (7 + 10 + 7 + 5 + 7 + 8 + 4 + 4 + 8 + 25) / 10 = 8.5. Then, for each data point, we subtract the mean, square the result, and calculate the average of these squared differences. The population variance is approximately 33.4 (rounded to one decimal place).

The population standard deviation is the square root of the population variance. Taking the square root of the population variance, we find that the population standard deviation is approximately 5.8 (rounded to one decimal place).

Therefore, for the given data set, the range is 21, the population variance is approximately 33.4, and the population standard deviation is approximately 5.8.

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Question 4: Laura applies for the position of ambulance medic. To give her a job simulation (behavioral interview) screening test, the interviewer...

This question involves providing a job simulation or behavioral interview, which allows the interviewer to observe how the candidate performs in a simulated work situation. This type of question assesses the candidate's skills, abilities, and behavior in a real or simulated work scenario, providing a more accurate evaluation of their capabilities for the job.

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The solution to the given system of simultaneous equations is x = 1, y = 2, and z = -3. The value of 3 - 2 is 1.

To solve the system of simultaneous equations, we can use the matrix method or any other appropriate method. Here, we'll use the matrix method.

   Representing the system of equations as a matrix equation AX = B, we have:

   A =

   [1 2 -1]

   [3 5 -1]

   [-2 -1 -2]

X =

[x]

[y]

[z]

B =

[6]

[2]

[4]

   To find X, we multiply both sides of the equation by the inverse of matrix A:

   X = [tex]A^(-1) * B[/tex]

   Calculating the inverse of matrix A, we have:

 [tex]A^(-1) =[/tex]

   [3/5 -1/5 1/5]

   [-1/5 2/5 -1/5]

   [1/5 1/5 -3/5]

   Multiplying [tex]A^(-1)[/tex]by B, we obtain:

   X =

   [1]

   [2]

   [-3]

Therefore, the solution to the given system of simultaneous equations is x = 1, y = 2, and z = -3.

Now, let's find the value of 3 - 2:

3 - 2 = 1

Therefore, the value of 3 - 2 is 1.

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Using the given information, the calculation shows that the probability of passing the course is 0.86, as determined by Dr. Miriam Johnson's observations.

Let's calculate the specific probability values based on the information provided:

P(A) = 0.70 (Probability of doing homework regularly)
P(B|A) = 0.96 (Probability of passing the course given that homework is done regularly)
P(B) = 0.86 (Probability of passing the course)

We can use the formula P(B) = P(A) * P(B|A) + P(A') * P(B|A') to calculate the probability of passing the course:

P(B) = P(A) * P(B|A) + P(A') * P(B|A')

P(A') = 1 - P(A) (Probability of not doing homework regularly)

Substituting the values:
P(B) = (0.70 * 0.96) + ((1 - 0.70) * P(B|A'))

To find P(B|A'), we can rearrange the formula as follows:
P(B|A') = (P(B) - P(A) * P(B|A)) / (1 - P(A))

Substituting the values and calculating:
P(B|A') = (0.86 - 0.70 * 0.96) / (1 - 0.70)
        = (0.86 - 0.672) / 0.30
        = 0.188 / 0.30
        = 0.6267

Now, we can substitute the value of P(B|A') back into the original equation:
P(B) = (0.70 * 0.96) + ((1 - 0.70) * 0.6267)
     = 0.672 + (0.30 * 0.6267)
     = 0.672 + 0.188
     = 0.86

Therefore, the calculated value of P(B) is 0.86, confirming the information given in the problem.

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To solve the equation x² + 6x + 9 = 1, we can first simplify it by combining like terms. Then, we can rearrange the equation into a quadratic form and use factoring or the quadratic formula to find the solutions.

To solve the equation x² + 6x + 9 = 1, we can simplify it by subtracting 1 from both sides, which gives us x² + 6x + 8 = 0.

Next, we can factor the quadratic equation as (x + 4)(x + 2) = 0. By setting each factor equal to zero, we find two possible solutions: x = -4 and x = -2.

Alternatively, we can use the quadratic formula, which states that the solutions of a quadratic equation of the form ax² + bx + c = 0 are given by x = (-b ± √(b² - 4ac)) / (2a). By substituting the coefficients from our equation into the formula, we can find the solutions.

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By following these steps, we have constructed a segment with a measure of 2. To verify this, we can use a ruler to measure the constructed segment directly. The measurement should confirm that the length of the constructed segment is indeed 2 units, in line with the given measure.

To construct a segment with a measure of 2, we can follow these steps:

1. Begin by drawing a straight line segment XY as a reference line.

2. Using a compass, set the width of the compass to any convenient length, such as the length of XY itself.

3. Place the compass point at point X and draw an arc that intersects XY.

4. Without changing the compass width, place the compass point at the intersection of the arc and XY and draw another arc above XY.

5. From the point where the second arc intersects XY, draw a straight line segment to point Y.

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The probability that all four movie tickets were won by girls is approximately 0.0499 or 4.99%.

To calculate the probability that all four movie tickets were won by girls out of a total of 30 participants (15 boys and 15 girls), we need to determine the number of favorable outcomes (where all four tickets are won by girls) and divide it by the total number of possible outcomes.

Since there are 15 girls and we want all four tickets to be won by girls, we need to select 4 girls out of the 15 available. This can be done using combinations. The number of ways to select 4 girls from 15 is denoted as "15 choose 4" or written as C(15, 4), and it can be calculated as follows:

C(15, 4) = 15! / (4! * (15 - 4)!) = 1365.

This gives us the number of favorable outcomes, which is 1365.

Now, let's calculate the total number of possible outcomes. Since there are 30 participants in total, we need to select 4 winners out of the 30. This can be calculated using combinations as well:

C(30, 4) = 30! / (4! * (30 - 4)!) = 27,405.

Therefore, the total number of possible outcomes is 27,405.

To calculate the probability, we divide the number of favorable outcomes by the total number of possible outcomes:

Probability = Favorable outcomes / Total outcomes = 1365 / 27,405 ≈ 0.0499.

Hence, the probability that all four movie tickets were won by girls is approximately 0.0499 or 4.99%.

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A. No, because the alternatives are not quantifiable.

B. No, because the alternatives are quantifiable.

C. Yes, because the alternatives are quantifiable.

D. Yes, because the alternatives are not quantifiable.

In decision-making, the quantifiability of alternatives refers to the ability to assign numerical values or measures to different options. Option A states that the alternatives are not quantifiable, suggesting that they cannot be measured or compared using numerical values. On the other hand, option B asserts that the alternatives are quantifiable, indicating that they can be measured and compared using quantifiable criteria.

To determine the correct answer for each scenario, we need to consider the nature of the decision and whether the alternatives involved can be assigned numerical values or measures. For example, when deciding on the paint color for the factory floor or extending cafeteria business hours, the alternatives may involve both quantifiable costs and benefits, making option B the appropriate choice.

However, in scenarios such as hiring a new engineer or changing the work shift, the qualities, qualifications, or effects involved may not be easily quantifiable, leading us to choose options D and C, respectively.

Ultimately, the correct answer depends on the specific context and the extent to which the alternatives can be measured or compared using quantifiable criteria.

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The simplified form of the radical expression ³√(8/216) is 6.

To simplify the radical expression ³√(8/216), we can simplify the numerator and denominator separately before taking the cube root.

First, let's simplify the numerator:

³√8 = ∛(2^3) = 2

Next, let's simplify the denominator:

³√216 = ∛(6^3) = 6

Now, we can rewrite the expression as:

²/₃√(2/6)

Simplifying the fraction:

²/₃√(2/6) = ²/₃√(1/3)

Since the cube root is an odd-indexed root, we can rewrite the expression using absolute value to ensure that the result is positive:

= ²/|₃√(1/3)|

Finally, simplifying the absolute value of the cube root:

= ²/(1/₃) = ² * ³/₁ = ² * ³ = 6

Therefore, the simplified form of the radical expression ³√(8/216) is 6.

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The solution of the fraction is as follows:

2 3 / 8 - 1 5 / 12 = 23 / 24

A fraction is a number with numerator and denominator. The fraction can be simplified as follows:

Therefore,

2 3 / 8 - 1 5 / 12 =

let's turn the improper fractions to proper fraction as follows:

2 3 / 8 = 19 / 8

1 5 / 12 = 17 / 12

Therefore,

2 3 / 8 - 1 5 / 12 = 19 / 8 - 17 / 12

let's find the lowest common factor of the denominators

19 / 8 - 17 / 12 =  57 - 34/ 24 = 23 / 24

Therefore,

2 3 / 8 - 1 5 / 12 = 23 / 24

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No, (x-4) is not a factor of x³ + x² - 10x + 8 is obtained by using  Remainder Theorem.

To determine whether a binomial is a factor of a polynomial, we can use the Remainder Theorem.

In this case, we want to determine if (x-4) is a factor of x³ + x² - 10x + 8.

To do this, we need to divide the polynomial x³ + x² - 10x + 8 by (x-4) using long division or synthetic division.

Performing the division, we get:

        x² + 5x - 2
     ____________________
x - 4 | x³ +  x² - 10x + 8
        - (x³ - 4x²)
        ________________
                 5x² - 10x
                 - (5x² - 20x)
                ________________
                          10x + 8
                          - (10x - 40)
                         ________________
                                    48

After dividing, we get a remainder of 48.

Since the remainder is not zero, (x-4) is not a factor of x³ + x² - 10x + 8.

So, the answer to your question is: No, (x-4) is not a factor of x³ + x² - 10x + 8.

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The qualifying time for the race, to the nearest minute, is 66 minutes.

To find the qualifying time, we need to determine the value of the running time that corresponds to the fastest 16% of all applicants. Since the running times are normally distributed, we can use the properties of the normal distribution.

First, we need to find the z-score corresponding to the 16th percentile. Using a standard normal distribution table or a calculator, we find that the z-score for the 16th percentile is approximately -0.994.

Next, we can use the formula for z-score to find the corresponding running time:

z = (x - mean) / standard deviation

Rearranging the formula, we have:

x = z * standard deviation + mean

Substituting the given values, we get:

x = -0.994 * 4 + 63 ≈ 66

Therefore, the qualifying time for the race is approximately 66 minutes.

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The quadratic  equation 3x² + kx + 12 = 0 will have no real solutions when the discriminant (b² - 4ac) is negative.

The discriminant of the quadratic equation is given by the formula

Δ = b² - 4ac, where a = 3, b = k, and c = 12.

For the equation to have no real solutions, the discriminant must be negative. Therefore, we have:

b² - 4ac < 0

k² - 4(3)(12) < 0

k² - 144 < 0

To find the values of k that satisfy this inequality, we can solve for k:

k² < 144

|k| < [tex]\sqrt{144}[/tex]

|k| < 12

This means that the value of k must lie between -12 and 12 (excluding -12 and 12) for the quadratic equation 3x² + kx + 12 = 0 to have no real solutions.

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