Answer:
angle <B = 76
Step-by-step explanation:
The measure of an exterior angle is equal to sum of two interior angles that is not adjacent to the exterior angle.
We can write the following equation with this information to find the value of angle <B
<B + 71 = 147 subtract 71 from both sides
<B = 76
4 1/3 - 1 2/3 how to solve this please
Answer:
[tex]2\frac{2}{3}[/tex]
Step-by-step explanation:
1) Convert [tex]4\frac{1}{3}[/tex] to improper fraction. Use this rule: [tex]a\frac{b}{c} =\frac{ac+b}{c}[/tex].
[tex]\frac{4\times3+1}{3} -1\frac{2}{3}[/tex]
2) Simplify 4 * 3 to 12.
[tex]\frac{12+1}{3}[/tex]
3) Simplify 12 + 1 to 13.
[tex]\frac{13}{3} -1\frac{2}{3}[/tex]
4) Convert [tex]1\frac{2}{3}[/tex] to improper fraction. Use this rule: [tex]a\frac{b}{c} =\frac{ac+b}{c}[/tex].
[tex]\frac{13}{3} -\frac{1\times3+2}{3}[/tex]
5) Simplify 1 * 3 to 3.
[tex]\frac{13}{3} -\frac{3+2}{3}[/tex]
6) Simplify 3 + 2 to 5.
[tex]\frac{13}{3} -\frac{5}{3}[/tex]
7) Join the denominators.
[tex]\frac{13-5}{3}[/tex]
8) Simplify.
[tex]\frac{8}{3}[/tex]
9) Convert to mixed fraction.
[tex]2\frac{2}{3}[/tex]
(Decimal Form: 2.666667)
Thank you,
Eddie
The formula =MID("ABCDEFGHI",3,4) would yield the result
If the formula, =MID("ABCDEFGHI",3,4) is used, the result yielded would be CDEF.
What would =MID("ABCDEFGHI",3,4) yield?When using the =MID function on a spreadsheet, the number after the text in the formula would show the position of the text from the left that the function would begin to count from.
The text in the third position from the left as shown in ABCDEFGHI is C so we need to start counting from letter C.
The second number in the function would then show the number of texts that needs to be counted and selected from the row of letters. That number is 4.
So from the letter C, you'll count 4 letters including the letter C itself.
The result you get would therefore be C, D, E, F which are the four letters from C.
In conclusion, the formula =MID("ABCDEFGHI",3,4) would yield the result, "C, D, E, F,."
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Tami earned $20.64 in simple interest by investing a principal of $400 in a Treasury bill.
If the interest rate was 1.72%/a, for how many years did she have her investment?
The number of years she had her investment is after 3 years
How to determine the years of investment?From the question, the given parameters are:
Principal Amount, P = $400Interest Rate, r = 1.72%Simple Interest, I = $20.64The number of years (T) is calculated from the following simple interest formula
I = PRT
Substitute the given parameters in the above equation
20.64 = 400 * 1.72% * t
Express 1.72% as decimal without percentage
20.64 = 400 * 0.0172 * t
Evaluate the product
20.64 = 6.88 * t
Divide both sides by 6.88
20.64/6.88 = 6.88/6.88 * t
Evaluate the quotient
3 = t
Rewrite the equation as
t = 3
This means that she had her investment after 3 years
Hence, the number of years she had her investment is after 3 years
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Find the product of the complex numbers. Express your answer in trigonometry form. Z1= 7cos(15) + isin(15)) z2= 2(cos(110)+ isin(110))
Answer:
14(cos(125°) +i·sin(125°))
Step-by-step explanation:
The product of two complex numbers is the product of their magnitudes at an angle equal to the sum of their angles.
ApplicationFor A = a·cis(α) and B = b·cis(β), the product AB is ...
AB = (a·cis(α))·(b·cis(β)) = ab·cis(α+β)
where "cis(x)" stands for the sum (cos(x) +i·sin(x)).
The product of interest is ...
Z1·Z2 = (7cis(15°))·(2cis(110°)) = (7·2)cis(15°+110°)
Z1·Z2 = 14cis(125°) = 14(cos(125°) +i·sin(125°))
Dominique has been working at an regular rate of $14. He works 54 hours per week and is paid time and a half for overtime. What is Dominique's average hourly rate?
Based on the given task content about the average hourly rate, Dominique's average hourly rate is $0.26.
Average hourly rateRegular rate of Dominique payment = $14Number of hours worked = 54 hoursAverage hourly rate = Regular rate of Dominique's payment ÷ Number of hours worked
= $14 / 54 hours
= 0.25925925925925
Approximately,
Average hourly rate = $0.26
Therefore, Dominique's average hourly rate is $0.26
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Find the measure of XY
Answer:
18
Step-by-step explanation:
For this problem, you have to look at the ratios of the corresponding sides.
Side DC and ZY correspond. It has a length of 10 and 15, respectively. So The ratio is 2:3. Same with BC and XY. If 12 is 2, than 3 must be 18 since 12x(2/3)=18
Is the answer true or false?
George paid a total of $985 to rent a storage unit.
He initially paid $290 plus an extra amount for
each month that he rented the storage unit. Write
an equation to find the extra amount George paid
each month if he had the storage unit for 5 months.
[?] + 5m= [ ]
Answer:
290 + 5m = 985
Step-by-step explanation:
Given information:
Initial payment = $290Total payment = $985Extra amount each month = mLength of rental = 5 monthsFrom the given information, we can create the following equation:
Initial payment plus extra amount each month for 5 months equals total payment.
⇒ 290 + 5m = 985
To solve the equation:
Subtract 290 from both sides:
⇒ 290 + 5m - 290 = 985 - 290
⇒ 5m = 695
Divide both sides by 5:
⇒ 5m ÷ 5 = 695 ÷ 5
⇒ m = 139
Therefore, the extra amount George paid each month was $139.
Answer: [tex]\Large\boxed{290+5m=985}[/tex]
Step-by-step explanation:
Given information
Initial cost = $290
Total cost = $985
Number of months = 5 months
Cost each month = ?
Set variable
Let [ m ] be the cost each month
The equation in verble sense
Initial paid + Extra each month = Total cost
Convert verbal equation to mathematical sense
$290 + 5m = $290
Therefore, to find the extra amount paid each month, the equation is [tex]\Large\boxed{290+5m=985}[/tex]
---------------------------------------------------------------------------------------------------------
EXTRA The following will be solving the derived equation, please ignore this part if it is useless for you.
Given equation
290 + 5m = 985
Subtract 290 on both sides
290 + 5m - 290 = 985 - 290
5m = 695
Divide 5 on both sides
5m / 5 = 695 / 5
m = $139
Hope this helps!! :)
Please let me know if you have any questions
A satellite orbits the Earth at a height of 343 kilometers. If the satellite makes 8 revolutions around the Earth, how many kilometers does it travel? (Earth's diameter is 6371 kilometers.).
The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.
What is the distance in kilometres covered by the satellite after 8 revolutions?Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;
D = 6371 + (343)×2
Hence, we have; diameter, D = 7057 km.
Hence, the distance travelled after 8 revolutions is;
C = 8 × πd
C = 8 × 3.14 × 7057
C = 177,271.8 km.
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(02.03)
Figure ABCD is transformed to A′B′C′D′, as shown:
A coordinate plane is shown. Figure ABCD has vertices A at 3 comma 1, B at 3 comma 4, C at 5 comma 5 and D at 5 comma 3. Figure A prime B prime C prime D prime has vertices A prime at negative 5 comma 1, B prime at negative 5 comma 4, C prime at negative 7 comma 5 and D prime at negative 7 comma 3.
Which of the following sequences of transformations is used to obtain figure A′B′C′D′ from ABCD? (4 points)
Group of answer choices
Reflection about the x-axis followed by a translation right by 2 units
Reflection about the y-axis followed by a translation left by 2 units
Counterclockwise rotation by 90 degrees about the origin followed by a translation right by 2 units
Counterclockwise rotation by 90 degrees about the origin followed by a translation left by 2 units
The sequence of transformation carried out on ABCD is; B: Reflection about the y-axis followed by a translation left by 2 units
What is the type of Transformation used?
As in rotation, reflection and translation the transformed image is congruent to the original figure (i.e all the points undergo same change). Thus, analyzing any one point will give the series of transformation undertaken.
Taking point A(3, 1) into consideration; Reflecting a point (x, y) over y axis, it becomes (-x, y).
Thus, reflecting A(3, 1) over y - axis gives the the new coordinates as (-3, 1)
Now, translating a point (x, y) k units left, gives a new coordinate (x - k, y).
Thus, translating point (-3, 1) 2 units left, gives the new coordinates as A'(-5, 1).
This is the coordinates for A'.
Thus, we can conclude by saying that the sequence of transformation carried out on ABCD is reflected about the y-axis followed by a translation left by 2 units.
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A rectangle has a width w that is 5units longer than its lenght/. Which equation expresses the rectangle's area, A?
Area equals Length times Width.
since the width of this equation is 5 units Longer then its Length
W = L + 5
To put this area in a equation we could say
L(L+5)=A
Simplify the equation, L^2 + 5L = A.
Can someone help on this?
Step-by-step explanation:
this just means that the first function with input value x = 0 is calculated. that result becomes the input value x for the second function. and that result becomes the input value x for the 3rd function. and that result is then our result.
to answer a and b we only need to look at the main operation of each function :
the first one uses only basic multiplication and subtraction.
the second one uses squaring.
the third one is a 1/x operation.
a.
since the final result is a negative number (-31), the second function with the square operation cannot be last.
because a square operation always delivers a positive result.
+a × +a = +a²
-a × -a = +a²
remember, for a square operation we multiply the same number by itself. therefore we cannot mix signs like -a × +a, because then they would not be the same numbers anymore.
b.
since the initial input value is 0, the third function (1/x) cannot be the first, because 1/0 is not defined.
c.
because of the "large" -32 term in the first function I guess that this will be the last one to create such a low negative result of -31.
since 1/x cannot be first, (x - 2)² is then first. that makes 1/x second, and (4x - 32) third, as mentioned.
let's try :
x = 0
(x - 2)² = (0 - 2)² = (-2)² = 4
x = 4
1/x = 1/4
x = 1/4
4x - 32 = 4×1/4 - 32 = 1 - 32 = -31
hurrah ! we are correct !
Inverse Functions: Mastery Test
Select the correct answer.
Consider this function.
f(x) = -3z + 3
Which graph represents the inverse of function f
The inverse function of the function [tex]f(x)=-3x+3[/tex] will be [tex]x=g(y)=-\frac{y}{3}+1[/tex].
How to find the inverse of a function of type y=f(x)=ax+b?An inverse function is a function that undoes the action of another function. For example, if the function [tex]f[/tex] produces the number [tex]y[/tex] after applying on [tex]x[/tex] i.e., [tex]y=f(x)[/tex], then the inverse function of [tex]f[/tex], which is denoted by [tex]f^{-1}[/tex], produces [tex]x[/tex] after applying on [tex]y[/tex] i.e., [tex]f^{-1}(y)=x[/tex].To find the inverse of a function of type [tex]y=f(x)=ax+b[/tex], we just need to rewrite the equation as [tex]x=g(y)[/tex] which can be illustrated as follows: [tex]y=ax+b\Longrightarrow x=\frac{y}{a}-\frac{b}{a}[/tex] i.e., [tex]g(x)=\frac{x}{a}-\frac{b}{a}[/tex] is the inverse function of [tex]f(x)=ax+b[/tex].Here, the given function is [tex]f(x)=-3x+3[/tex].
Then we get:
[tex]y=-3x+3\\\Longrightarrow x=-\frac{y}{3}+1[/tex]
Thus, the inverse function of the function [tex]f(x)=-3x+3[/tex] will be [tex]g(x)=-\frac{x}{3}+1[/tex].
The graph representing this inverse function is given as follows:
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How many three-digit positive integers have three different digits and at least one prime digit?
Answer:
252
Step-by-step explanation:
using a brute force method in c++
#include <stdio.h>
int main(){
int a, b, c, n = 0;
for(a = 1; a <= 9; a++)
for(b = 0; b <= 9; b++)
for(c = 0; c <= 9; c++)
if((a==3 || b==3 || c==3)) n++;
printf("%d\n", n);
}
Is 3 1/4 a rational or irrational number?
Answer:
It is a rational number.
Step-by-step explanation:
A number is only irrational if it has a decimal that never ends and doesn't have a pattern. So a number like Pi (3.141592653589...) is irrational while a number like 1/3 (0.33333333...) is rational.
Hi :)
Below is the difference between rational & irrational numbers
______________RATIONALA number that can be expressed in [tex]\sf{\dfrac{p}{q}}[/tex] form, where [tex]\large\boldsymbol{q\ne0}[/tex]Evidently,
An irrational number is a number that cannot be expressed in [tex]\sf{\dfrac{p}{q}}[/tex] formLet's test the given number, [tex]\boldsymbol{3\dfrac{1}{4}}[/tex]
Well isn't it already in [tex]\sf{\dfrac{p}{q}}[/tex] form? It is.
Thus
[tex]\longrightarrow\darkblue\boldsymbol{3\dfrac{1}{4}\:is\:rational}[/tex]
[tex]\tt{Learn\:More;Work\:Harder}[/tex]
:)
−5y2−3y−2, when y=2.
y=2
-5(2)²-3(2)-2
-5(4)-3(2)-2
-20-6-2
=12
Katrina has the option of an 8-year nonsubsidized student loan of $29,000 at an annual interest rate of 2.5% or an 8-year subsidized loan of $29,000 at an annual interest rate of 4.5%. Determine for which loan Katrina will pay less interest over the term of the loan if she starts making payments 2 years after obtaining the loan. (Assume Katrina makes monthly payments for each loan. Round your answers to the nearest cent, as appropriate.) The total interest paid on the nonsubsidized loan is $
Katrina would pay less amount of interest on the nonsubsidized student loan
The total interest paid on the nonsubsidized loan is $3,860.80
What is monthly compounding?
Monthly compounding means that the interest is computed and added to existing outstanding loan balance at the end of each month.
In this case, the loan would be repaid monthly but the first monthly payment would occur after 2 years of taking out the loans.
In other words, for the first 2 years, the interest would increase the balances with no corresponding reductions by a way of loan repayment, note that interest to be added monthly, as a result, we can compute outstanding balance 2 years for both loans using the future value formula of a single cash flow shown below:
FV=PV*(1+r/n)^(n*t)
FV=balance after 2 years=unknown
PV=loan amount
r=annual interest rate
n=number of times interest is compounded annually=12
t=number of years before repayments commence=2
Non-subsidized loan:
FV=$29,000*(1+2.5%/12)^(12*2)
FV=$30,485.28
Subsidized loan:
FV=$29,000*(1+4.5%/12)^(12*2)
FV=$31,725.71
Having determined the loan balances after 2 years, we can now compute the monthly payments that would be made in the remaining 6 years using the present value formula of an ordinary annuity because monthly payments would occur at the end of each month:
PV=PMT*(1-(1+r)^-N/r
PV=balance of loan after 2 years
PMT=monthly payment=unknown
r=monthly interest rate=annual interest rate/12
N=number of monthly payments in 6 years=12*6=72
Non-subsidized loan:
$30,485.28=PMT*(1-(1+2.5%/12)^-72/(2.5%/12)
PMT=$456.40
total monthly payments=$456.40*72
total monthly payments=$32,860.80
Interest= total monthly payments-loan
interest=$32,860.80-$29,000
interest=$3,860.80
Subsidized loan:
$31,725.71 =PMT*(1-(1+4.5%/12)^-72/(4.5%/12)
PMT=$503.61
total monthly payments=$503.61 *72
total monthly payments=$36,259.92
Interest= total monthly payments-loan
interest=$36,259.92 -$29,000
interest=$7,259.92
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help urgently need help
Answer:
[tex]y=\dfrac{8}{7}x - \dfrac{23}{7}[/tex]
Step-by-step explanation:
Rearranging the terms, we get [tex]7y=8x-23[/tex]. Dividing both sides by 7, we get [tex]\dfrac{7y}{7} = \dfrac{8x-23}{7}[/tex], so [tex]\boxed{y=\dfrac{8}{7}x - \dfrac{23}{7}}[/tex]
Answer:
y = [tex]\frac{8}{7}[/tex]x -[tex]\frac{23}{7}[/tex]
Step-by-step explanation:
You are changing this to the slope-intercept form of a line.
y = mx + b
8x -7y = 23 Subtract 8x from both sides of the equation
-7y = -8x + 23 Divide both sides of the equation by -7
y = [tex]\frac{-8}{-7}[/tex] - [tex]\frac{23}{7}[/tex]
[tex]\frac{-8}{-7}[/tex] is the same as [tex]\frac{8}{7}[/tex]
y = [tex]\frac{8}{7}[/tex]x - [tex]\frac{23}{7}[/tex]
A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 729 cubic feet. The concrete for the base cost $8 per square foot, The material for the roof costs $3 Per square foot, and the material for the sides costs $5.50 Per square foot. Find the dimensions of the most economical shed.
The dimensions of the most economical shed are 9 ft in length, 9 ft in width, and 9 ft in height if the storage shed is to be built in the shape of a box with a square base.
What is volume?It is defined as a three-dimensional space enclosed by an object or thing.
It is given that:
A storage shed is to be built in the shape of a box with a square base.
It is to have a volume of 729 cubic feet.
Let x be the length of the base
Let y be the height of the box.
V = 729 cubic feet
The base is square:
l = w = x
V = x²y
y = 729/x²
Cost of the base = $8x²
Cost of the roof = 3x²
Cost of the sides = 4(5.50)xy
= 22xy
Total cost
C= 8x² + 3x² + 22xy
C = 11x² + 22x(729/x²)
C = 11x² + 16038/x
Find the first derivative:
dC/dx = 22x - 16038/x²
Equate; dC/dx = 0
22x - 16038/x² = 0
22x = 16038/x²
22x³ =16038
x³ = 729
x = 9
y = 729/(9)² = 9
Length of base = 9 ft
Width of base = 9 ft
Height of box = 9 ft
Thus, the dimensions of the most economical shed are 9 ft in length, 9 ft in width, and 9 ft in height.
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Two sides of a triangle are 5 and 55 cm. Complete the inequality to show the possible lengths of the third side. If the third side of the triangle is x then...
The third side of the triangle falls between (50, 60).
How to find the third side of a triangle?Inequality triangle theorem states that the sum of any two sides of a triangle is greater than or equal to the third side.
Therefore, the other two sides are 5 cm and 55 cm. The range of the third side x can be computed using inequality triangle theorem.
Hence,
x < 5 + 55
x < 60
And,
x > 55 - 5
x > 50
Therefore, 50 < x < 60.
Hence, the third side of the triangle falls between (50, 60).
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Please help me w this question! ASAPP
Answer: None of these are correct
Step-by-step explanation:
I believe that the equation is showing transitive property.
Let f= {(-5,-4),(6,-5),(2, -3)}.
Find f(-5).
Answer:
f(–5)=–4
Step-by-step explanation:
as it is defined
Can anyone please help me with this assignment
1. The sentences translated to equations looks like:
a) 4x = 32.
b) x + 6y = 43.
c) 3x + 7 = 9x - 4.
d) 76 - 2x = 8x.
2. The equations translated to sentences looks like:
a) The sum of 16 and 9 times x is 50.
b) The sum of the square of x and 6 times y is 4 times w.
c) Three times x is 52.
d) Five-sixth is equal to the product of -10 and x.
Practice Part 1: Translate sentence to equation
a)Four times a number is thirty-two.
Assuming the number to be x, we get the equation, 4x = 32.
b)The sum of and six times is equal to forty-three.
The sentence, when translated to an equation looks like, x + 6y = 43.
c)The sum of 7 and three times equals the difference of 9 times and 4.
The sentence, when translated to an equation looks like, 3x + 7 = 9x - 4.
d)Two times less than 76 is equal to the product of 8 and
The sentence, when translated to an equation looks like, 76 - 2x = 8x.
Practice Part 2: Translate equation into sentence
a) 9x + 16 = 50.
- The sentence for the given equation is, the sum of 16 and 9 times x is 50.
b) x² + 6y = 4w.
- The sentence for the given equation is, the sum of the square of x and 6 times y is 4 times w.
c) 3x = 52.
- The sentence for the given equation is, three times x is 52.
d) 5/6 = -10x.
- The sentence for the given equation is, five-sixth is equal to the product of -10 and x.
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Please help! Help Will Give 100 PTS
Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.
Square Root 3x+12 = 9
Answer:
x = 23; not extraneous
Step-by-step explanation:
A solution is extraneous if it does not satisfy the original equation. Extraneous solutions can sometimes be introduced in the process of solving radical and rational function equations.
SolutionSquaring both sides of the given equation, we get ...
√(3x +12) = 9
3x +12 = 81 . . . . . . square both sides
x +4 = 27 . . . . . . . divide by 3
x = 23 . . . . . . . . . . subtract 4
CheckThere is only one solution, and it satisfies the equation:
√(3×23 +12) = √81 = 9
The solution x = 23 is not extraneous.
Answer: x = 23; not extraneous
Step-by-step explanation:
The following information is available for Brownstone Products Company for the month of July:
Actual Master Budget
Units 3,500 4,000
Sales revenue $ 54,300 $ 60,000
Variable manufacturing costs 10,000 16,000
Fixed manufacturing costs 13,000 14,000
Variable selling and administrative expenses 6,500 8,000
Fixed selling and administrative expenses 8,000 9,100
Required:
1. What was the master budget variance for July? Was this variance favorable or unfavorable?
2. Compute the July sales volume variance and the flexible-budget variance for the month, both in terms of contribution margin and in terms of operating income.
4. Prepare pro-forma budgets for activities within its relevant range of operations. Prepare a flexible budget for each of the following two output levels:
a. 3,560 units.
b. 3,980 units.
1. The master budget variance for July was $3,900, and this variance was favorable.
2. The July sales volume variances in terms of contribution margin and operating income are $2,800 F and $3,900 F, respectively.
3. The July flexible-budget variances in terms of contribution margin and operating income are $5,550 F and $6,650 F, respectively.
4. Flexible budgets for the following output levels are:
3,560 units 3,980 units
Sales revenue $53,400 $59,700
Variable manufacturing costs 14,240 15,920
Fixed manufacturing costs 12,460 13,930
Variable selling and
administrative expenses 7,120 7,960
Fixed selling and
administrative expenses 9,100 9,100
Operating Income $10,480 $12,790
Data and Calculations:Actual Master Budget Per Unit Variance
Units 3,500 4,000 500 U
Sales revenue $ 54,300 $ 60,000 $15.00 $ 5,700 U
Variable manufacturing costs 10,000 16,000 4.00 6,000 F
Fixed manufacturing costs 13,000 14,000 3.50 1,000 F
Variable selling and
administrative expenses 6,500 8,000 2.00 1,500 F
Contribution margin $24,800 $22,000 $2,800 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Total costs $37,500 $47,100
Operating income $16,800 $12,900 $3,900 F
Sales volume variance:
Revenue per unit $15.51 $15.00 $0.51 F
Flexible-budget:Actual Master Budget Variance
Units 3,500 3,500 U
Sales revenue $ 54,300 $ 52,500 $ 1,800 F
Variable manufacturing costs 10,000 14,000 4,000 F
Fixed manufacturing costs 13,000 12,250 750 U
Variable selling and
administrative expenses 6,500 7,000 500 F
Contribution margin $24,800 $19,250 $5,550 F
Fixed selling and
administrative expenses 8,000 9,100 1,100 F
Operating income $16,800 $10,150 $6,650 F
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Copy the problems onto your paper, mark the given and prove the statements asked. Prove, triangle CAV is congruent to triangle CEV
Quadrilateral is a family of plane shapes that have four straight sides. Thus the sum of their internal angles is [tex]360^{o}[/tex]. Examples include rectangle, square, rhombus, trapezium, and kite.
A kite is a plane shape that has its adjacent sides to have equal measures.
The given diagram in the question is a kite that has its specific properties compared to other quadrilaterals.
Thus, the required proof is stated below:
Given: ΔCAV and ΔCEV
Prove that: ΔCAV ≅ ΔCEV
Then,
CE ≅ CA (length of side property of a kite)
EV ≅ AV (length of side property of a kite)
<ACV ≅ <ECV (bisected property of a given angle)
<AVC ≅ <EVC (bisected property of a given angle)
CV is a common side to ΔCAV and ΔCEV
Therefore it can be deduced that;
ΔCAV ≅ ΔCEV (Angle-Angle-Side congruent theorem)
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Any help with this greatly appreciated.
Put the equation in standard linear form.
[tex]x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}[/tex]
Find the integrating factor.
[tex]\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5[/tex]
Multiply both sides by [tex]\mu[/tex].
[tex](t+5) x'(t) + x(t) = 5(t+5)e^{5t}[/tex]
Now the left side the derivative of a product,
[tex]\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}[/tex]
Integrate both sides.
[tex](t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt[/tex]
On the right side, integrate by parts.
[tex](t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C[/tex]
Solve for [tex]x(t)[/tex].
[tex]\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}[/tex]
Cross Multiply With Fractional Ratios.
5 (1/2)
=
8 x
cross multiply to find the awnser
Answer:
5/16
Step-by-step explanation:
assuming you mean 5(1/2) = 8x
5(1/2) is the same as 5/2
so, 5/2 = 8x
5 = 16x
x= 5/16
P: 2,012
1) El volumen de un cubo de arista 1 es Vc = 1³ y el
Volumen de una esfera de radior es
JE
V₁ = πr ²³ Entonces si en un cubo de arista 4cm
3
y se introduce una pelota de diametro 4 cm, al Calcular
aproximación con cuatro cifras decimales, por exceso.
Calcular el volumen que queda entre la esfera y el cubo.
(toma π =
3,141592654)
El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?
En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.
Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:
Cubo
V = l³
V = (4 cm)³
V = 64 cm³
Esfera
V' = (4π / 3) · R³
V' = (4π / 3) · (2 cm)³
V' ≈ 33.5103 cm³
Segundo, determinamos la diferencia de volumen entre los dos elementos:
V'' = V - V'
V'' = 64 cm³ - 33.5103 cm³
V'' = 30.4897 cm³
El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
Para aprender más sobre volúmenes: https://brainly.com/question/23940577
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Please help me with this question <3 ASAP!
Answer:
54°
Step-by-step explanation:
Opposite angles of a parallelogram are congruent, so;
[tex]9x+9=8x+14 \\ \\ x=5 \\ \\ m\angle S=9(5)+9=54^{\circ}[/tex]
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Angle S = 54°[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
In a Parallelogram, opposite angles are equal, so we infer that :
[tex] \qquad❖ \: \sf \:9x + 9 = 8x + 14 [/tex]
[tex] \qquad❖ \: \sf \:9x - 8x = 14 - 9[/tex]
[tex] \qquad❖ \: \sf \:x = 5 \degree[/tex]
Next,
Measure of Angle S is :
[tex] \qquad❖ \: \sf \:9x + 9[/tex]
[tex] \qquad❖ \: \sf \:9(5) + 9[/tex]
[tex] \qquad❖ \: \sf \:45 + 9[/tex]
[tex] \qquad❖ \: \sf \:54 \degree[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
Angle S = 54°