Find the distance between the two points rounding to the nearest tenth! PLEASE HELP ASAP!!!

Answer: No the ratio of 12/9 is not equal to 18/12

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

6 + (-4) = 2

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:)

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Answer:

8 x 4² + 10 - 5 x 108 x 42 + 10 - 5x10

8 x 16 + 10 - 22680 + 10 - 50

128 -22710 = -22528

CMIIW

I can't understand with your question but I think the qustion is like ☝

The value of the expression 8 x 4² + 10 - 5 x 108 x 42 + 10 - 5 x 10 is -22,582

To calculate the value of the given expression 8 x 4² + 10 - 5 x 108 x 42 + 10 - 5 x 10.

we need to follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders, Multiplication/Division, and Addition/Subtraction.

Let's break down the steps:

Calculate the exponent: 4² = 4 x 4 = 16.

Multiply 8 by 16: 8 x 16 = 128.

Multiply 5 by 108: 5 x 108 = 540.

Multiply 540 by 42: 540 x 42 = 22,680.

Multiply 5 by 10: 5 x 10 = 50.

Now, the expression becomes: 128 + 10 - 22,680 + 10 - 50.

=-22,582

Therefore, the value of the expression 8 x 4² + 10 - 5 x 108 x 42 + 10 - 5 x 10 is -22,582

To learn more on Expressions click:

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Answer: 11

Step-by-step explanation: [tex]y^{2} = 121, y = \sqrt{121}, y = 11[/tex]

Answer:

D

Step-by-step explanation:

[tex]11 *11[/tex] is [tex]121[/tex]

Answer:

600400

Step-by-step explanation:

Answer:

42

Step-by-step explanation:

Multiples of 14 are:

0 ,   14 ,  28 ,  42. ... .. .

Multiples of 6 are :

0, 6 ,  12 ,  18 ,  24 ,  30 ,   36 ,  42 ... ... . .

Another method is to write the prime factorization of 14 and 6:

Take all the prime numbers with the highest exponent from the prime factorization:

14 = 2 × 7 and   6 = 2 × 3

L . C . M (14 , 6 ) = 2 ×3 × 7 = 42

Answer:

it depends upon the distance up to which distance he should suppose÷24 km

Answer:

o to 2 seconds 2 to 4 seconds

Answer:

$650

Step-by-step explanation:

Her hourly rate = $12.50 then

overtime rate = 2 × $12.50 = $25

For a 46 hour week she has 6 hours overtime , then

earnings = (40 × $12.50) + (6 × $25)

               = $500 + $150

               = $650

Answer:

Hey buddy whatsup? All good

Coming to the question fig 1 and 3 aren't functions

Coz.... Reason for fig 1... Every distinct element of domain must have a unique element in codomain, but in this fig the same element has more than two unique elements which is a relation not a function.

Reason for fig 3 every element in domain must have an unique element in codomain but in this fig the element c doesn't have any unique element hence it isn't a function.....

Thank you

Answer:

fig 1 is not function because x-componet (A) has two range

Answer:

rational number

Step-by-step explanation:

Answer:

When you divide 1060 by 48, your answer will be 22.08333... ( decimal) but when rounded, it will either be 22, 22.1, or 22.08 (just for rounding, you do not have to put this in.)

Hope this helped!

Step-by-step explanation:

Answer:

22 1/12

Step-by-step explanation:

48*22=1056

1060-1056=4

=  22 4/48

= 22 1/12

So the answer is 22 1/12,

Hope this helps!

Step-by-step explanation:

(a)

34 - (-73) = 34 + 73

34 + 73 = 107

107 = 107

(b)

45 - (-30) = 45 + 30

45 + 30 = 75

75 = 75

Answer:

[tex]a + b \\ 1)a = 34 \: \: b = 73 \\ 34 + 73 = 107 \\ 2)a = 45 \: b = 30 \\ 45 + 30 = 75 \\ thank \: you[/tex]

Answer:

check the file above and got any confusion then comment it .

hope this helped you,

Answer:

si

Step-by-step explanation:

Ñ

Answer:

AC is 6.5 cm

Step-by-step explanation:

From trigonometric ratios:

[tex] \sin( \theta) = \frac{opposite}{hypotenuse} \\ [/tex]

opposite » 3 cm

hypotenuse » AC

angle » 28°

[tex] \sin(28 \degree) = \frac{3}{AC} \\ \\ AC = \frac{3}{ \sin(28 \degree) } \\ \\ AC = \frac{3}{0.46} \\ \\ AC = 6.5 \: cm[/tex]

Answer:

Here sin28 = perpendicular/hypotenuse

AC = sin28 * 3

AC = 0.46*3

AC = 1.38

Answer:

[tex] \frac{ {x}^{2} + 9 }{3 \sqrt[3]{ {x}^{2} } + 3( {x}^{2} + 3)} [/tex]

Step-by-step explanation:

attached

Since 64/3 = 21 + 1/3 > 21, I assume S is supposed to be the value of the infinite sum. So we have for some constants a and r (where |r | < 1),

[tex]S = \displaystyle \sum_{n=1}^\infty ar^{n-1} = \frac{64}3 \\\\ S_3 = \sum_{n=1}^3 ar^{n-1} = 21[/tex]

Consider the k-th partial sum of the series,

[tex]S_k = \displaystyle \sum_{n=1}^k ar^{n-1} = a \left(1 + r + r^2 + \cdots + r^{k-1}\right)[/tex]

Multiply both sides by r :

[tex]rS_k = a\left(r + r^2 + r^3 + \cdots + r^k\right)[/tex]

Subtract this from [tex]S_k[/tex]:

[tex](1 - r)S_k = a\left(1 - r^k\right) \implies S_k = a\dfrac{1-r^k}{1-r}[/tex]

Now as k goes to ∞, the r ᵏ term converges to 0, which leaves us with

[tex]S = \displaystyle \lim_{k\to\infty}S_k = \frac a{1-r} = \frac{64}3[/tex]

which we can solve for a :

[tex]\dfrac a{1-r} = \dfrac{64}3 \implies a = \dfrac{64(1-r)}3[/tex]

Meanwhile, the 3rd partial sum is given to be

[tex]\displaystyle S_3 = \sum_{k=1}^3 ar^{n-1} = a\left(1+r+r^2\right) = 21[/tex]

Substitute a into this equation and solve for r :

[tex]\dfrac{64(1-r)}3 \left(1+r+r^2\right) = 21 \\\\ \dfrac{64}3 (1 - r^3) = 21 \implies r^3 = \dfrac1{64} \implies r = \dfrac14[/tex]

Now solve for a :

[tex]a\left(1 + \dfrac14 + \dfrac1{4^2}\right) = 21 \implies a = 16[/tex]

It follows that

[tex]S_5 = a\left(1 + r + r^2 + r^3 + r^4\right) \\\\ S_5 = 16\left(1 + \dfrac14 + \dfrac1{16} + \dfrac1{64} + \dfrac1{256}\right) = \boxed{\frac{341}{16}} = 21 + \dfrac5{16} = 21.3125[/tex]

Answer:

3.4

Step-by-step explanation:

Answer:

You can only add or subtract radicals together if they are like radicals. You add or subtract them in the same fashion that you do like terms shown in Tutorial 25: Polynomials and Polynomial Functions. Combine the numbers that are in front of the like radicals and write that number in front of the like radical part.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The next step is:

This is a distributive property

Correct choice is A

Answer: x=-3

Step-by-step explanation:

7x+5-5=-16-5

7×/7=-21/7

X=-3

Answer:

x=-3

Step-by-step explanation:

7x=−16−5

7x=−21

x= − 21/7

X= -3

​

The degree of a polynomial is the value of the highest degree of a monomial in the polynomial

The degree of the polynomial h(x) is 5

The reason the above value is correct is as follows;

Given;

A zero of a polynomial function h(x) is the imaginary number, x = 3 - 4·i

The multiplicity of the root at x = 3 - 4·i is One

The given table showing the real roots of the polynomial is presented as follows;

[tex]\begin{array}{|c|cc|}\mathbf{x}&&\mathbf{h(x)}\\\displaystyle -5&&0\\-2&&3\\-1&&0\\1&&2\\4&&0\\7&&6\\10&&0\end{array}\right][/tex]

Required:

To find the degree of the polynomial, h(x)

Solution:

The maximum number of roots of a polynomial is given by the degree of the polynomial

The number of roots is given by the number zeros

The maximum number of roots an nth degree polynomial can have = n roots

From the given table, the number of zeros = 4 (each with multiplicity of one) = The number of real roots

Therefore, the total number of roots of the polynomial = 4 + 1 = 5 = The (minimum possible) degree of the polynomial

The degree of the polynomial = 5

Learn more about degree of a polynomial here:

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