Answer: Smaller planets are easier to detect using the transit method.
Explanation:
The transit method is a technique for detecting exoplanets, or planets outside our solar system, by observing the periodic dimming of a star as a planet passes in front of it (transits). The size of the planet affects the amount of light that is blocked, and therefore the magnitude of the dimming.
Smaller planets block less light than larger planets, making it more difficult to detect the transit. However, smaller planets are more numerous, and their transits are more frequent and easier to observe. Additionally, smaller planets are more likely to be located in the habitable zone of their star, where conditions may be suitable for life.
Therefore, smaller planets are easier to detect using the transit method, as they cause a smaller but more frequent dimming of the star, making them easier to detect with current technology. The relative size of the planet does matter in the transit method, as smaller planets are easier to detect.
Answer:
larger planets (correct)
Explanation:
**DUE TOMORROW, NEED ANSWER ASAP**
NASA has asked you to evaluate a number of proposals for telescopes. These proposals include information about where the telescope would be built and what wavelengths it intends to observe at. Based only on these factors, evaluate whether NASA should consider funding each proposal. Justify your recommendations. (Some telescopes may have more than one "correct" answer depending on how you justify it).
a.) An ultraviolet telescope in space
b.) An optical telescope in a remote location in Michigan's upper peninsula
c.) A radio telescope in the Mojave desert in Arizona
d.) An x-ray telescope in the Andes mountains in Chile
e.) An optical telescope in space
An ultraviolet telescope in space.
What is a telescope?
The oldest known instance of a telescope is a patent for a refracting telescope that Middelburg spectacle maker Hans Lipperhey filed to the Dutch government in 1608. Although the true inventor is unknown, word of it quickly spread across Europe. After learning about it, Galileo constructed his own model and began making telescopic observations of celestial objects in 1609.Soon after the refracting telescope was created, it was being considered if the objective, or light-gathering element, might instead be a mirror. Due to the potential benefits of using parabolic mirrors—a reduction in spherical aberration and the absence of chromatic aberration—many designs and attempts to construct reflecting telescopes have been proposed. Isaac Newton created the first useful reflecting telescope in 1668.To know more about telescope, click the link given below:
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Which statement describes the difference between a covalent bond and a
hydrogen bond?
OA. A covalent bond forms between two atoms that can share a pair
of valence electrons, while a hydrogen bond forms between two
atoms that can form ions.
OB. A covalent bond forms between electrons and positive ions, while
a hydrogen bond forms between two polar molecules.
C. A covalent bond forms between two atoms that can share a pair
of valence electrons, while a hydrogen bond forms between two
polar molecules.
OD. A covalent bond forms between two polar molecules, while a
hydrogen bond forms between two atoms that can share a pair of
valence electrons.
A covalent bond forms between two atoms that can share a pair
of valence electrons, while a hydrogen bond forms between two
atoms that can form ions.
When two atoms share valence electrons, do covalent bonds form?
An electron exchange that results in the formation of electron pairs between atoms is known as a covalent bond. Bonding pairs or sharing pairs are the names given to these electron pairs. Covalent bonding is the stable equilibrium of the attractive and repulsive forces between atoms when they share electrons.
Not a covalent link to a hydrogen atom, hydrogen bonding is an unique kind of dipole-dipole interaction between molecules. It comes about as a result of the attraction between two extremely electronegative atoms, such as N, O, or F, and a hydrogen atom that is covalently bound to one of them.
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When you toss a ball straight up, what happens to its velocity while it is traveling upward?
Answer:
Explanation:The object slows down as it moves upward until it reaches a maximum height, at which time the velocity is zero. Then the velocity increases as the object falls toward the ground.
Suppose that the two speakers in the figure below are separated by 2.50 m and are vibrating exactly out of phase at a frequency of 429
Hz. The speed of sound is 343 m/s. Does the observer at C observe constructive or destructive interfernce when his distance from
speaker B is (a) 1.15 m and (b) 2.00 m?
(a) The observed interference is destructive, as the phase difference between the waves exceeds π.
(b) The phase difference between the waves is less than π, so the observed interference is constructive.
What does observer observe at the positions?
When the observer is 1.15 m from speaker B, the path difference between the waves from the two speakers is:
Δx = x₂ - x₁ = 2.50 m - 1.15 m = 1.35 m
The corresponding phase difference is:
Δφ = 2π (Δx / λ) = 2π (1.35 m / (343 m/s / 429 Hz)) ≈ 4.16 rad
Since the two speakers are vibrating exactly out of phase, the phase difference between their waves is π, which is approximately 3.14 rad. Therefore, the observed interference is destructive, as the phase difference between the waves exceeds π.
When the observer is 2.00 m from speaker B, the path difference between the waves from the two speakers is:
Δx = x₂ - x₁ = 2.50 m - 2.00 m = 0.50 m
The corresponding phase difference is:
Δφ = 2π (Δx / λ) = 2π (0.50 m / (343 m/s / 429 Hz)) ≈ 1.55 rad
Since the phase difference between the waves is less than π, the observed interference is constructive.
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Two boys Raghav and Ramesh make a toy telephone by joining two
bod plastic cups through a long string. They both stand apart. Raghav
speaks softly into one cup and Ramesh hears by putting his ear in the
other cup. Now Ramesh speaks and Raghav listens.
(a) What type of waves are produced by voice of Raghav and Ramesh
in the air inside the plastic cup?
garo (b) What type of waves are produced in the string?
(c) Write any one difference between these types of waves.
OR
wavelength of a sound wave.
(b) Wha type of waves are produced in the string
Transverse wave is produced by the string. longitudinal wave is formed by the voice of both of them in plastic cup
You have a set of calipers that can measure thicknesses of a few inches with an uncertainty of ± 0. 005 inches. You measure the thickness of a deck of 52 cards and get 0. 590 in:a. If you now calculate the thickness of 1 card, what is your answer, including its uncertainty?b. You can improve this result by measuring several decks together. If you want to know the thickness of 1 card with an uncertainty of only 0. 00002 in. , how many decks do you need to measure together?
a. The thickness of 1 card (of a deck of 52) = 0.011346 in/card
b. The decks that need to be measured together = 62,500
To calculate the thickness of 1 card, we divide the measured thickness of the deck by the number of cards in the deck:
(a)
0.590 in / 52 cards = 0.011346 in/card
The uncertainty of the measurement is also divided by the number of cards:
±0.005 in / 52 cards
= ±0.000096 in/card
So the thickness of 1 card is 0.011346 in ± 0.000096 in.
b. To reduce the uncertainty to 0.00002 in, we can use the formula:
uncertainty / √n = desired uncertainty
Where,
n is the number of decks measured together.
Rearranging the formula and plugging in the values:
n = (uncertainty / desired uncertainty)²n
= (0.005 in / 0.00002 in)²
n = 62,500
So we need to measure 62,500 decks together to achieve the desired uncertainty of 0.00002 in.
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An 1800-kg truck pulls a 620-kg trailer away from a stoplight with an acceleration of 1. 16 m/s2, what is the force exerted by the truck on the trailer?.
The force exerted by the truck on the trailer is approximately 2951.6 N.
To find the force exerted by the truck on the trailer, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration. The net force in this case is the force exerted by the truck on the trailer, and we can express this as:
F = [tex]m_{total}[/tex] × a
where F is the net force, [tex]m_{total}[/tex] is the total mass of the truck and trailer, and a is the acceleration.
Substituting the given values, we get:
F = (1800 kg + 620 kg) × 1.16 m/s^2
Simplifying, we get:
F = 2951.6 N
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A toy car of mass 50g travels down a smooth incline at 30 degrees to
the horizontal. Calculate:
(a) The net force acting on the car as it rolls down the slope, and
(b) The force of the incline on the car as it travels down the slope.
The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.
What is Force?a) F = mg sin θ.
F = 50 * 10−3 9.8 * 1/2
= 0.245 N
If the slope is 30 degrees, the top corner will be 90 30 degrees, and the normal to the vertical force will also be 90 60 degrees, thus we will use mg cos 30 perpendicular to the slope.
b) FN = mg cos θ
= m × g × cos θ
= 50 × 10−3 × 9.8 × cos 30
= 0.43N
Therefore, The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.
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ASAP PLEASE HELP!!!!
A 3.0 kg object swings back and forth as a simple pendulum with a small amplitude. The potential energy U of the object as a function of distance x from its equilibrium position is shown above. This particular object has a total energy E of 0.4 J.
b) What is the farthest the object moves along the x-axis in the positive direction? Explain your reasoning.
The farthest that particular object will move along the x-axis in the positive direction is 0.2 m. This is the amplitude of the pendulum's motion.
What is potential energy?Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
Since the total energy of the object is given by E = U + K, where U is the potential energy and K is the kinetic energy, and the pendulum has a small amplitude, we can assume that the kinetic energy of the object is negligible.
Therefore, we have:
E = U = [tex](1/2)kx^2[/tex]
Khere k is the spring constant of the pendulum and x is the displacement from the equilibrium position.
So, the value of x can be:
x = sqrt(2E/k)
Substituting the given values, we have:
x = sqrt(2(0.4 J)/(20 N/m)) = 0.2 m
Thus, the farthest the object moves along the x-axis in the positive direction is 0.2 m.
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2 Examples of adverse events (AE) include which of the following?
A. Damaged wheelchair.
OB. Anxiety.
C. Decreased blood sodium.
D. Enlarged thyroid on physical examination.
OE. B, C, and D only
OF. All the above are adverse events (AES).
(17%) Problem 2: The drawing shows a small sphere of mass m=0.26 g that carries a charge of q = 85 x 10-10 C. The sphere is attached to one end of a very thin silk string of length L = 6.25 cm. The other end of the string is attached to a large vertical conducting plate that has a charge density of o = 30 x 10-6C/m². + + + + + + L m, A 25% Part (a) Write an expression for the magnitude of the electric field due to the charge distribution on the conductive plate. E = 0 Grade Summary Deductions 0% Potential 100% €0 B 0 Y b 0 Submissions Attempts remaining: 20 (% per attempt) detailed view d h ( 789 HOME 1456 1 23 + 0 END VO BACKSPACE GEL CLEAR g k j m n P S Submit Hline Feedback I give up! Hints: for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Date Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work. Time Answer Hints Feedback 24 25% Part (b) Write an expression for the horizontal component of the net force acting on the charged sphere in terms of the tension T in the string, the electric field, and the given variables. A 25% Part (c) Write an expression for the vertical component of the net force acting on the charged sphere in terms of the tension T in the string and the given variables. 425% Part (d) What is the angle in degrees that the string makes with respect to the vertical?
θ = 39.7º is the angle in degrees that the string makes with respect to the vertical using Newtons law.
In each exercise, we construct the equations at the equilibrium point using Newton's second law for the sphere. We'll assume that plate 1 is on the left for this exercise.
Y Axis
Y= -W = 0 = W
X axis
X= - F_{e2} + Tₓ = 0
Let's utilize trigonometry to determine the tension's component parts. We gauge the angle in relation to the vertical
sin θ = Tₓ / T
cos θ = T_{y} / t
Tₓ = T sin θ
T_{y} = T cos θ
Gauss's law can be used to determine the electric field of each leaf. Since a cylinder forms a Gaussian surface, the component of the field perpendicular to the cylinder's base is the one containing electric flow.
F = ∫ E. dA
The flow is towards both sides of the plate in this instance, and the scalar product is reduced to the algebraic product.
F = 2E A = q_{int} / ε₀
let's use the concept of surface charge density
σ = q_{int} / A
we substitute
2E A = σ A /ε₀
E = σ / 2ε₀
T cos θ = mg
- q σ₁ / 2ε₀ - q σ₂ /2ε₀ + T sinθ = 0
we introduce t in the second equations
- q /2 ε₀ (σ₁ + σ₂) + (mg / cos θ) sin θ = 0
mg tan θ = q /2ε₀ (σ₁ + σ₂)
θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)
data indicates the mass of 0.26 g = 0.26 10⁻³ kg
give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²
let's calculate
θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2 (6.25 10⁻¹² *0.26 10⁻³ 9.8))
θ = tan⁻¹ 8.3 10⁻¹)
θ = 39.7º
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The tires of a car make 73 revolutions as the car reduces its speed uniformly from 94.0 km/h to 60.0 km/h. The tires have a diameter of 0.84 m.
Part C: If the car continues to decelerate at this rate, how far does it go? Find the total distance.
Express your answer to three significant figures and include the appropriate units.
If the car continues to decelerate at this rate then the total distance of car is 324.91 meters.
What is decelerate?
When an object slows down, it undergoes deceleration, which is the opposite of acceleration. There are usually two ways that acceleration slows down. The first occurs when an object slows down by itself. Gravity, friction, or momentum loss could be to blame. The second is when the object is subjected to an external force, such as when a car driver applies the brakes or a pilot deploys the air brakes in an airplane. A journey that is both safe and successful requires deceleration, which is an essential component of movement.
When the vehicle revs at 73, then :d₁ = R × θ
= 0.42×73×2× π
= 192.6 m
Using 2nd kinematic equation for distance traveled in next 16 sec:
θ₁ = wi × t + (1/2)× α ×t²
θ₁ = 39.69 × 16 + (1/2) × (-2.5) × 16²
= 315.04 rad
d₂ = R× θ₁
= 0.42× 315.04
= 132.31 m
So total stopping distance = 192.6 + 132.31
= 324.91 m
Therefore, the total distance is 324.91 m.
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If the line on a distance versus time graph and the line on a speed versus time graph are both straight lines going through the origin and the 2 graphs be displaying the motion of the same object
No, because covering uniform distance in uniform units of time ( which the graph one represents) is constant speed, and not uniform speed (as represented in the second graph).
What is a graph?
A generalisation that enables several edges to share the same pair of endpoints is a multigraph. Multigraphs are sometimes simply referred to as graphs in writings.The edges that connect a vertex to itself are known as loops, and they are occasionally permitted in graphs. The definition above needs be modified to define edges as multisets of two vertices rather than sets in order to support loops.When it is obvious from the context that loops are permitted, such generalised graphs are referred to as graphs with loops or just graphs.The set of edges must also be finite because the set of vertices V is typically assumed to be finite. Although occasionally taken into consideration, infinite graphs are typically seen as a specific type of binary relation because most findings on finite graphs are binary.To know more about graph, click the link given below:
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A Simple Machines Webquest
Simple machines are devices with few or no moving parts that make work easier by multiplying, reducing, or changing the direction of force
What are simple machines?Simple machines can be combined to form complex machines and mechanisms that make many tasks easier to perform. Examples of six types of simple machines include;
Lever: a rigid bar that rotates around a fixed pivot point to lift or move loads.Pulley: a wheel with a groove in its circumference that allows a rope or cable to run over it to change the direction of a lifting force.Inclined plane: a flat surface that is higher at one end than the other, used to raise or lower objects by reducing the amount of force needed.Wedge: a triangular shape that splits materials apart or holds them in place by applying force along its slanting surface.Screw: a spiral ramp wrapped around a cylinder or cone that transforms rotational motion into linear motion.Wheel and axle: a wheel that rotates around a central axle to move objects or apply force.Learn more about simple machines here: https://brainly.com/question/11683867
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state the energy transfer that takes place;
as the changes shape during the contact between the racquet and the ball
The energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball is due to the changes in shape results in deformation of the ball that converts kinetic energy from the racquet into elastic potential energy in the ball.
What is the importance of the kinetic energy of the substance?When a ball strikes a racquet, the kinetic force of racquet causes the ball to compress, which results in a change in its shape and the energy is transferred from the racquet to the ball, and the work done by the racquet on the ball increases the potential energy stored in the compressed ball, and the ball bounces.
Hence, changes in shape results in deformation of the ball and converts kinetic energy present in the racquet to elastic potential energy in the ball and bounces it.
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The question is incomplete, the complete question is here
State the energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball.
Two opposite charges of the same magnitude Q = 2x10^-7c are separated by a distance of 15.0cm. What is the magnitude and direction of the force acting on an electron placed at the midpoint
The direction of the force is along the line joining the two charges, and its magnitude is approximately 1.44 x 10^-12 N.
What is magnitude?Magnitude can be defined as the maximum extent of size and the direction of an object.
The force on the electron can be found using Coulomb's law:
F = k * (q1 * q2) / r^2
where
k is Coulomb's constant (k = 9 x 10^9 N*m^2/C^2)q1 and q2 are the magnitudes of the two charges r is the distance between themF is the magnitude of the forceIn this case, the two charges have the same magnitude Q = 2 x 10^-7 C, so we can write:
F = k * [(Q * -Q) / (0.15 m)^2]
where the negative sign for one of the charges indicates that it has the opposite charge to the other. Simplifying this expression, we get:
F = k * (Q^2 / 0.0225)
F = (9 x 10^9 N*m^2/C^2) * (2 x 10^-7 C)^2 / 0.0225
F ≈ 1.44 x 10^-12 N
Therefore, the direction of the force is along the line joining the two charges, and its magnitude is approximately 1.44 x 10^-12 N.
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(2 of 5)
Now, decrease the planet size by sliding the Planet Properties 'radius' slider to the left until
it is one-tenth (0.100) the radius of Jupiter. For this configuration, the normalized flux
(relative amount of star light reaching an observer on Earth) when the planet is off to he
side (not transiting) is. while the normalized flux when the planet is transiting is
O 1.000, 0.990
O 0.990,1.000
O 1.00000, 0.99990
O 0.99990,1.00000
Its normalized flux for this configuration while the planet is off to the side is, and the normalized flux whenever the planet equals transiting is, respectively, 1.00000 and 0.99990.
What defines a planet?It specifies three requirements for a planet: It must move about a sun. It must be large enough for gravity to pull it in a spherical direction. It must be massive sufficient that its gravity wiped away any other things of a similarly sized in its circle of the Sun.
What is a planet made of?Earth is formed of rock, as are the three inner planets of the solar system (Mercury, Venus, and Mars), which also contain metals like aluminum and aluminum as well as typical minerals like feldspar.
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Answer:
1.00000,0.99990 (correct)
Explanation:
A truck moving across an ice road is spreading sand across the ice. The truck can be considered a closed, isolated system. Which of the following is true? A. The mass of the truck decreases with no change in the velocity of the truck B. The mass of the truck decreases while the velocity of the truck increases. C. The mass of the truck decreases while the velocity of the truck decreases. D.The mass of the truck remains the same while the velocity of the truck remains the same.
The mass of the truck decreases while the velocity of the truck increases. Option B
What is a closed system?A closed system is a system in which matter cannot enter or leave the system, but energy can be exchanged between the system and its surroundings. In other words, a closed system is isolated from its environment in terms of mass, but not in terms of energy.
Closed systems can be found in many different areas of science and engineering, including thermodynamics, mechanics, and engineering. For example, in thermodynamics, a closed system is a system in which heat can be transferred between the system and its surroundings, but no mass can be transferred. In mechanics, a closed system is a system in which the total momentum of the system remains constant, regardless of any external forces acting on the system.
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What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?.
The energy transformation that takes place when using a wind turbine to generate usable energy is mechanical-to-electrical.
This is done by converting the kinetic energy of the wind into mechanical energy, which then turns a generator to produce electrical energy. Then, residences and businesses can be powered by this electrical energy. Wind drives the rotor blades of contemporary wind turbines, which transform kinetic energy into rotational energy. Kinetic energy is a particular kind of power that can be present in a moving object or particle. An object can perform work, which involves the transfer of energy, by applying a net force. The effect is that the object accelerates and acquires kinetic energy. Aerodynamic force is used by the rotor blades of a wind turbine, which function similarly to an aeroplane wing or a helicopter rotor blade, to transform wind energy into electricity. The air pressure drops on one side of the blade as the wind passes across it.
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complete question: What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?
A) friction- electrical
B) kinetic - mechanical - electrical
C) friction - mechanical - electrical
D) mechanical - friction - electrical
A heart defibrillator being used on a patient has an RC time constant of 23.0
ms due to the resistance of the patient and the capacitance of the defibrillator. If the defibrillator has an 9.75
μF capacitance, what is the resistance of the path through the patient?
If the initial voltage is 12.0
kV, how long does it take to decline to 115
V?
A heart defibrillator being used on a patient has an RC time constant of 23.0 ms. ,If the defibrillator has a 9.75 μF capacitance, then it takes approximately 21.1 ms for the initial voltage of 12.0 kV to decline to 115 v.
What is the calculation of the voltage of the defibrillator ?The calculation is explained below,
RC = resistance x capacitance
resistance = RC / capacitance
resistance = (23.0 ms) / (9.75 μF) = 2,359 ohms
Time for the initial voltage of 12.0 kV to decline to 115 V,
V(t) = V₀ × [tex]{e}^(^-^t^/^R^C^)[/tex] ( here, V(t)=voltage at time t, V₀= initial voltage, e= constant= 2.71828, t= time, R= resistance, C= capacitance)
For t= -RC × ln(V(t) / V₀)
t = - (23.0 ms) × ln(115 V / 12.0 kV) = 21.1 ms
Hence, a heart defibrillator being used on a patient has an RC time constant of 23.0 ms. ,If the defibrillator has a 9.75 μF capacitance, then it takes approximately 21.1 ms for the initial voltage of 12.0 kV to decline to 115 v.
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fill in the balance equation below with the name of missing compuod. The answer the question that follow in the space provided
____ ____ sunlight ____ ___ ____
The answer to the question that follows in the space provided is
carbon dioxide + water + sunlight = glucose + oxygen.
What is photosynthesis?Green plants produce their food in the presence of sunlight during photosynthesis. The process is only done by autotrophs.
They use carbon dioxide and water, which are inorganic components from the environment, to create glucose, and oxygen gas is released into the atmosphere.
Carbon dioxide + water → Glucose + Oxygen
Therefore, the correct option is
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WRITE ABOUT HOW YOU THINK PEOPLE CAN MAKE CHANGES TO IMPROVE THE
ENVIRONMENT IN THE UNITED STATES
Environmentally responsible involves more than just avoiding plastic bags; it also means making daily decisions that, quite literally, will determine whether or not we succeed as a species.
What is Enviornment?We can slow the pace of climate change by becoming more aware of how we can reduce pollution, safeguard species, conserve natural resources, and take other steps.
Everyone can make a difference, especially when wise environmental decisions become routine and perhaps even start inspiring others to follow suit.
Even immediate personal advantages can result from acting morally in favor of the future of life on Earth. It can help you express your creativity, become more involved in your community and the wider world, and lead to a healthier living.
Therefore, Environmentally responsible involves more than just avoiding plastic bags; it also means making daily decisions that, quite literally, will determine whether or not we succeed as a species.
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Question:
a) The amount of charge that passes through a copper wire in 5.4 s is 2.37 C. Find the current in the wire.
The wire has a charge carrier density of 7.5 × 10^26 /3
and a radius of 1.0 mm.
b) What is the cross sectional area of the wire?
c) What is the charge of the charge carriers in the copper wire?
d) Using all of the above, calculate the drift speed of the electrons in this wire
Answer:
Explanation:
a) To find the current in the wire, use the formula:
I = Q / t
Where I is the current, Q is the amount of charge that passes through the wire (2.37 C), and t is the time (5.4 s).
I = 2.37 C / 5.4 s = 0.44 A
So the current in the wire is 0.44 A.
b) To find the cross-sectional area of the wire, use the formula:
A = π * r^2
Where A is the cross-sectional area, r is the radius of the wire (1.0 mm = 0.001 m), and π is Pi (3.14).
A = π * (0.001 m)^2 = 3.14 * 10^-6 m^2
So the cross-sectional area of the wire is 3.14 * 10^-6 m^2.
c) To find the charge of the charge carriers in the wire, use the formula:
Q = n * e
Where Q is the charge, n is the number of charge carriers, and e is the elementary charge (1.60 × 10^-19 C).
The wire has a charge carrier density of 7.5 × 10^26 /3, so the number of charge carriers can be calculated as:
n = (charge carrier density * cross-sectional area of the wire)
n = (7.5 × 10^26 / 3) * (3.14 * 10^-6 m^2)
n = 7.5 × 10^26 * 3.14 * 10^-6 / 3
n = 2.35 × 10^20
So the charge of the charge carriers in the wire is:
Q = n * e = 2.35 × 10^20 * 1.60 × 10^-19 C = 3.72 × 10^-19 C
d) To find the drift speed of the electrons in the wire, use the formula:
v = I / (n * e * A)
Where v is the drift speed, I is the current (0.44 A), n is the number of charge carriers (2.35 × 10^20), e is the elementary charge (1.60 × 10^-19 C), and A is the cross-sectional area of the wire (3.14 * 10^-6 m^2).
v = 0.44 A / (2.35 × 10^20 * 1.60 × 10^-19 C * 3.14 * 10^-6 m^2)
v = 0.44 / (2.35 × 10^20 * 1.60 × 10^-19 * 3.14 * 10^-6)
v = 0.44 / (3.74 × 10^-5)
v = 11766 m/s
So the drift speed of the electrons in this wire is 11766 m/s.
Which of the following statements concerning momentum is true?*
A.Momentum is a scalar quantity.
B.The momentum of an object is always positive.
C.Momentum is a force.
D.Momentum is a vector
E.The SI unit of momentum is the Newton.
Answer:
D. it is vector
Explanation:
Well it have both direction and magnitude
It's direction is same as the direction of velocity
Electric rail cars often use magnetic braking. The brake consists of a set of electromagnets that are held just above the rails. To brake the train, the electromagnets are switched on, creating a magnetic field that induces eddy currents in the metal rails passing beneath them. In the figure, which of the choices correctly represents the eddy currents induced in the rails? The diagrams represent a view from above, looking down at the rail through the electromagnet. The electromagnet moves to the right, and the magnetic field points into the screen.
Choose the correct answer A,B,C, or D
The correct choice for the direction of the eddy currents induced in the rails is option A,
As the electromagnet moves to the right and the magnetic field points into the screen, the magnetic flux passing through the metal rails changes, which induces eddy currents in the rails. These eddy currents produce their own magnetic field that opposes the motion of the electromagnet and slows down the train.
Based on the given information, we can determine that the correct choice for the direction of the eddy currents induced in the rails is option A, which shows a circular current flowing in a clockwise direction as viewed from above. This direction of the eddy currents corresponds to Lenz's law, which states that the direction of the induced current will be such that it opposes the change in the magnetic field that produced it. In this case, the eddy currents produce a magnetic field that opposes the motion of the electromagnet, creating a braking force on the train.
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Applying the maximum force you can exert, the heaviest box you can push at constant speed across a level floor with coefficient of kinetic friction μ has weight ω. Another box sits on a ramp that is inclined at an angle of β
above the horizontal. The coefficient of kinetic friction between the box and the ramp is μ.
If you apply the same magnitude maximum force, now parallel to the ramp, that you applied to the box on the floor, what is the heaviest weight box that you can push up the ramp at constant speed? (in both cases assume you can give enough extra push to get the box started moving)
The heaviest box you can push up the ramp at constant speed with a maximum force F is: ω = F / (μ sin(β))
Let F be the maximum force applied to the box, and let N be the normal force between the box and the ramp.
We can use the following equation to solve for the maximum weight of the box on the ramp:
F + μN = ω sin(β)
Where ω is the weight of the box, and β is the angle of the ramp.
hence, the heaviest box you can push up the ramp at constant speed with a maximum force F is:
ω = F / (μ sin(β))
What is speed?
Speed is the rate of change of an object's position over time, or the rate at which an object moves. Speed is a scalar quantity and is measured in metres per second (m/s).
Therefore, The heaviest box you can push up the ramp at constant speed with a maximum force F is: ω = F / (μ sin(β))
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how many times more light can a telescope with a diameter of 17 inches gather compared to one that has a diameter of 3 inches?
Answer:
The telescope with a 17-inch diameter can gather more than 60 times more light than the one with a 3-inch diameter.
Explanation:
Find the momentum of a 0.0231 kg bullet fired at 621 m/s.*
A.0.0269 kg·m/s
B.14,200 kg·m/s
C.26.9 kg·m/s
D. 14.3 kg·m/s
Answer:
The momentum of a 0.0231 kg bullet fired at 621 m/s is calculated by multiplying the mass of the bullet by its velocity:0.0231 kg * 621 m/s = 14.3 kg·m/sSo the answer is D. 14.3 kg·m/s.
Explanation:
Formula for momentum:
[tex]p=mv[/tex]
momentum(measured in kg*m/s) = mass(measured in kg) * velocity(measured in m/s)
__________________________________________________________
Given:
[tex]m=0.0231kg[/tex]
[tex]v=621m/s[/tex]
[tex]p=?[/tex]
__________________________________________________________
Finding momentum:
[tex]p=mv[/tex]
[tex]p=0.0231\times621[/tex]
[tex]p=14.3kg*m/s[/tex]
__________________________________________________________
Answer:
[tex]\fbox{Option D}[/tex]
If the mass of the cart is 250 kg, solve for PE at A (height 100 m) and D
(height 75 m). Velocity at A is 0, solve for velocity at location D.
To solve for the potential energy at points A and D, we need to use the formula for gravitational potential energy:
[tex]PE = mgh[/tex]
What is potential energy?At point A, the height is h = 100 m and the mass of the cart is m = 250 kg. The acceleration due to gravity is g = 9.81 m/s^2. Therefore, the potential energy at point A is:
[tex]PE_A = mgh = (250 kg)(9.81 m/s^2)(100 m) = 245250 J[/tex]
At point D, the height is h = 75 m and the mass of the cart is still m = 250 kg. The potential energy at point D is:
[tex]PE_D = mgh = (250 kg)(9.81 m/s^2)(75 m) = 183937.5 J[/tex]
To solve for the velocity at point D, we can use the conservation of energy principle. At point A, the cart has only potential energy (no kinetic energy), so the total mechanical energy is equal to the potential energy:
[tex]E_A = PE_A = 245250 J[/tex]
At point D, the cart has both potential energy and kinetic energy. Therefore, the total mechanical energy is the sum of the potential and kinetic energies:
[tex]E_D = PE_D + KE_D[/tex]
where [tex]KE_D[/tex] is the kinetic energy at point D, and it is what we want to find.
According to the conservation of energy principle, the total mechanical energy at point D must be equal to the total mechanical energy at point A (assuming no non-conservative forces such as friction act on the cart between A and D). Therefore:
[tex]E_A = E_D[/tex]
Substituting in the values we have calculated:
[tex]245250 J = 183937.5 J + KE_D[/tex]
Solving for [tex]KE_D[/tex], we get:
[tex]KE_D = 61212.5 J[/tex]
To find the velocity at point D, we can use the formula for kinetic energy:
[tex]KE = (1/2)mv^2[/tex]
where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.
Substituting in the values we have calculated, we get:
[tex]KE_D = (1/2)mv_D^2Solving for v_D, we get:v_D = sqrt((2KE_D) / m) = sqrt((2(61212.5 J)) / (250 kg)) = 17.6 m/s[/tex]
Therefore, the velocity at point D is 17.6 m/s.
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The speed of light in vacuum is 3* 10^8. If the refractive index of a transparent liquid is 4/3, then what is the speed of light in the liquid?
The speed of light in vacuum is 3 × 10⁸ m/s. If the refractive index of a transparent liquid is 4/3, then the speed of light in water will be 2.25 × 10⁸ m/s.
What is Refractive index?Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to the speed of light in the second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n'.
R.I. of water = Speed of light in vacuum / speed of light in water
n' = 4/3
Speed of light in vacuum = 3 × 10⁸
n' = Speed of light in vacuum / speed of light in water
Speed of light in water = Speed of light in vacuum/ n'
Speed of light in water = 3 × 10⁸/ 4/3
Speed of light in water = 2.25 × 10⁸
Therefore, the speed of light in water medium will be 2.25 × 10⁸ m/s.
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