Answer:
What is the figure? please provide
Mrs Jones is baking a cake and the recipe calls for 7 ounces of sugar.The only problem is that Mrs Jones scale can only measure in grams.How many grams of sugar will Mrs Jones need to add to her batter?
Which element on the periodic table contains 13 protons?
Answer:
Al
Explanation:
From periodic table: Aluminum
At which point is the water table closest to the surface? Explain.
I need to get it done right now
The point is the water table closest to the surface in valleys.
In areas of topographic relief, the water table generally follows the surface but tends to approach it in valleys and intersect the surface with streams and lakes. Closest to the surface is the vented zone where the interstices between the soil are filled with both air and water. Below this layer is a saturation zone where the gaps are filled with water.
The water table is the subsurface boundary between the soil surface and the area where groundwater saturates the space between sediment and rock fissures. At this boundary, water pressure equals atmospheric pressure. The top surface of the groundwater is the groundwater table. Beneath this surface, all pore spaces and cracks in sediments and rocks are completely filled and saturated with water. Groundwater occurs in these saturated layers known as saturation zones or water vapor zones.
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A car with a mass of 1,500 kg is driving at 20 m/s. What is the kinetic energy of the car?
O 15,000 J
O 300,000 J
O 30,000 J
O 150,000 J
The kinetic energy of the car is 300,000J
What is Kinetic energy?Kinetic energy is the energy of motion.
The formula for kinetic energy is given as [tex]K.E = \frac{1}{2} mv^{2}[/tex]
where m = mass of object , v = speed of object.
An object having some speed and mass will have kinetic energy while an object at rest will not have any kinetic energy since the speed of object at rest is zero.
Since at rest speed is zero, an object has kinetic energy only when it is in motion.
From the question,
m = 1,500kg
v = 20m/s
K.E = (1/2) x 1,500 x 20 x 20
K. E = 300,000J
The car now possess a kinetic energy of 300,000J
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Write an equation for the relationship between initial conditions v1, p1 and t1, and the final conditions v2, p2 and t2?.
By using combined gas law,
P₁V₁/T₁ = P₂V₂/T₂
What is the combined gas law?Boyle's Law, Gay Lussac's Law, and Charles Law are all combined into the Combined Gas Law. According to the Combined Gas Law, a gas's pressure, volume, and temperature must be constant.
The combined gas law's equation is therefore PV/T = K, where P is pressure, T is temperature, V is volume, and K is a constant. To compare two sets of circumstances in one substance, one can modify the combined gas law's formula.
The combined gas law combines the provisions of the Charles, Gay-Lussac, and Boyle laws. It is a combination of the first three laws that were discovered. According to these rules, one thermodynamic variable is related to another while keeping the other variables constant.
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A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
give answer in 3 significant figures, with units.
The amount of energy lost by the car when it descended from a height of 3000 m to 2000 m is 980×10⁴ J
How do I determine the energy lost?We'll begin by obtaining the energy at the top of the mountain (height = 3000 m). This is shown below:
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 3000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 3000
E = 29400000 J
Next, we shall obtain the energy at height = 2000 m
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 2000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 2000
E = 19600000 J
Finally, we shall obtain the the energy lost by the car. Details below:
Energy (at height 3000 m) = 29400000 JEnergy (at height 2000 m) = 19600000 JEnergy lost =?Energy lost = Energy (at height 3000 m) - (at height 2000 m)
Energy lost = 29400000 - 19600000
Energy lost = 980×10⁴ J
Thus, we can conclude that the energy lost is 980×10⁴ J
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Complete question:
A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
How much energy did the car lose on descent? Give you answer to 3 significant figures, with units.
Energy lost =?
A student constructs a catapult that fires a ping pong ball horizontally. What can the student do to make the ping pong ball stay in the air longer.
Since the student constructs a catapult that fires a ping pong ball horizontally, the thing that the student do to make the ping pong ball stay in the air longer is to stretch the rubber bank longer before shooting the ball.
What is the ping pong ball shooting about?Rubber bands serve as the ping pong catapult's power source. Rubber bands are stretched when the catapult arm is pulled back, which causes them to store potential energy.
Rubber bands constrict as soon as the catapult's arm is released, converting their potential energy into the kinetic energy or motion energy of the ping pong ball as it soars through the air. The kinetic energy of an object is determined by its mass (how much weight it has) and velocity (how fast it is going).
Therefore, The heavier object will have more kinetic energy when two things are travelling at the same speed. The object travelling more quickly will have greater kinetic energy if the two objects have the same mass but are moving at different speeds.
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voltage amplifiers use a voltage input signal and a current output signal. select one: true false
Voltage amplifiers use a voltage input signal and a current output signal. This statement is false.
A voltage amplifier uses a voltage input and a voltage output.
In an electric circuit, the job of a voltage amplifier is to amplify the high input voltage as compared to the low input voltage.
In general, transistor function as voltage amplifiers in a circuit and are used to increase the power, voltage, and current of a signal.
Generally, these amplifiers are used in audio devices and equipment, radio and television broadcasting, wireless communications, and so on.
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A golf ball rolls off a horizontal shelf with a velocity of 0.25 m/s. If it takes the ball 1.7 seconds to hit the ground, how high was the table? Choose the closest answer.
Answer:
Explanation:
Given:
V₀ = 0.25 m/s
t = 1.7 s
g = 9.8 m/s²
_____________
H - ?
H = V₀*t + g*t²/2
H = 0.25*1.7 + 9.8·1,7² / 2 = 14.6 m
If a 60 kg student is standing on the edge of a cliff. Find the student's
gravitational potential energy if the cliff is 40 m high.
Formula with variables (letters):
Formula with numbers:-
Answer with units:
Answer: PE = 23535.96 J
Explanation: Screenshot is formula
A 2 kg basketball is thrown towards a stationary 1.35 kg kickball with a velocity of 2.37 m/s. After impact the kickball moves forward at a rate of 1.5 m/s. What is the velocity of the basketball after the collision?
Given,
Mass of basketball is 2 kg.
Mass of kickball is 1.32 kg
The initial velocity of the basket ball is 2.37m/s.
The final velocity of the kickball is 1.5 m/s
By conservation of momentum,
[tex]\begin{gathered} 2\times2.37=1.32\times1.5+2v \\ \Rightarrow v=\frac{1.38m}{s} \end{gathered}[/tex]The velocity of the basketball is 1.38 m/s
what is the average velocity of a race car that traveled 88km in 20 min
Answer:
73.3333meters per second
Explanation:
average velocity= distance ÷ time
=(88×1000)/(20×60)
=73.3333m/s
A block (5 kg) is pulled by a 50 N at an angle of 30◦tothe ground. The block experiences a 4,2 N frictional force and moves 2,60 m. The block starts from rest. Use the work-energy principle to calculate the speed of the block after the 2,60 m.
Please explain/name all formulas used.
The speed of the block after the 2,60 m is determined as 6.38 m/s.
What is the work done on the block?
The work done on the block is calculated by applying the principle of Newton's second law of motion to determine the net work done on the block as shown below.
W = F(net)d
where;
F(net) is the net forced is the distanceF(net) = Fcosθ - Ff
where;
F is the applied forceFf is the frictional forceF(net) = 50 cos(30) - 4.2
F(net) = 39.1 N
The speed of the block is calculated by applying the principle of work energy theorem.
K.E = W
¹/₂mv² = F(net)d
mv² = 2F(net)d
v² = [2F(net)d] / m
v = √[2F(net)d] / m]
v = √[2 x 39.1 x 2.6] / 5]
v = 6.38 m/s
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Please help me!!!!!! It’s due soon
According to the picture Vector A and Vector B is shown. After the subtraction the vector difference will be Vector A-Vector B are shown in the picture below. We are using the triangle law for this question.
What is Vector?Vector is a quality that shows that shows that a physics term has two main characteristics. It has value and direction both. The addition and subtraction is not usual for this quantity. It has some specific rules to add and subtract.
How can we calculate the subtraction of vectors?Vector is a quantity which have value and direction both. So its subtraction is not going to happen in regular algebraic ways. It has some specific laws. It has mainly two laws that we use,
Triangle Law of Vector.Parallelogram Law of Vector.In these two laws we use the triangle law to subtract the two vectors. Vector A which direction was in fourth quadrant an Vector B which direction is in first quadrant.
After the subtraction we got that the third and the resultant vector was shown in a manner in the picture that makes a perfect triangle.
So according to the discussion we got that, after using the triangle law of subtraction the (Vector A-Vector B) are shown in the picture below.
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an object has two forces acting on it. the first force acts upward and has a magnitude of 5.6 n. the second force also acts upward and has a magnitude of 1.2 n. if the object has a mass of 2.7 kg, what is the acceleration of the object?
A1 = F1 / M
A1 = 5.6 / 2.7 = 2.074 m/s²
A2 = F2 / M
A2 = 1.2 / 2.7 = 0.444 m/s²
Therefore, total acceleration = A1 + A2 = (2.074 + 0.444)m/s²
= 2.518 m/s²
calculating acceleration using mass and force:
It can be summed up by the following equation: force (N) = mass (kg) x acceleration (m/s2). When a result, an object with constant mass will accelerate directly as force is applied. When two objects of different masses are subjected to the same force, the heavier object accelerates more slowly than the lighter object.
When a physical influence called force is imparted to an item, the object accelerates in the direction the force was applied from. The quantity of substance a thing contains is expressed by its mass, which is expressed in kilograms. The rate at which an object's velocity along the same straight line as the unbalanced force changes is known as its acceleration.
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4. A team of physicists is testing how long it takes for a charged particle to travel through a magnetic field. They measure the time as 4.050*10^-6 seconds. How many significant figures does this
measurement have?
05
2
Significant figures 4.050*10^-6 seconds has is four as exponential digits in scientific notation are not significant.
Five rules for significant figures are
All the non-zero numbers are significant.Zeros between two non-zero digits are also significant. Leading zeros are not said significant.Trailing zeros to the right of the decimal are taken as significant. Trailing zeros in a whole number with the decimal are taken significant.All the digits known with certainty or those indicated by the markings on the measuring device and the first estimated, digit that is one digit past the smallest marking on the measuring device is called the significant figures of a measured quantity.
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what kind of motion does the alpha particle experience? what forces on the alpha particle could cause this motion?
The alpha particle experience electric repulsive force forces on the alpha particle could cause this motion.
Briefing:The nuclear positive charge would exert an electric repulsive force on an alpha particle if it were outside the nucleus, giving it a significant electric potential energy as indicated. According to the slope of the potential energy curve, it would be subject to the inverse square law Coulomb force.
Why is it called alpha particle?These substances are also known as alpha emitters as a result. The symbol for an alpha particle is typically the Greek letter alpha, after which it is named. Prior to the discovery of beta particles and gamma rays, it was the first form of nuclear radiation.
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a stores sign has a mass of 20kg and is 3.0 m long. it is unfirm. what is the magnitude of the force that the boly exerts on the sign
The boly pulls on the sign with a force of 60N, according to the magnitude formula f=MxA.
How would you define magnitude?Magnitude means essentially "distance or amount" in the perspective of physics. In terms of motion, it shows the relative or absolute size, direction, or movement of an object. It is employed to describe something's size or scope. Magnitude in physics generally refers to a quantity or quantity.
What are magnitude and intensity?The magnitude scale, which measures an earthquake's size, is unchanged by distance from the event. Nevertheless, strength reflects the level of rocking brought on by an earthquakes at a specific location and diminishes with distances from the epicentre.
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A chemist performs an experiment in which she compresses an air sample and then measures its pressure. She records her results in the following table:Volume (cm)³100.050.025.0Pressure (kPa)33.3 66.7 133.2 If the chemist continues to compress the air to a volume of 12.5 cm³, what will itspressure most likely be?A. 266.4 kPaB. 366.4 kPaC. 212.2 kPaD. 12.5 kPa
Apply Boyle's law:
P1 V1 = P2 V2 =P3 V3 = P4 V4
(33.3)(100) = P4 ( 12.5 )
3330 = 12.5 P4
3330/12.5 = P4
P4 = 266.4 kPA
Answer:
A. 266.4 kPa
a 11 g particle is moving to the left at 29 m/s . how much net work must be done on the particle to cause it to move to the right at 33 m/s ?
Work must be done on the particle to cause it to move to the right at 33 m/s is 5.54 J
What is work done?
When we apply force "F" to a block, the body moves with some acceleration or, additionally, its speed increases or decreases depending on the direction of the force. The system's kinetic energy changes as speed increases or decreases. Since we are aware that energy cannot be created or destroyed, it must be changed into another form. This perspective refers to it as completed work. When negative energy is finished, the energy declines, and when positive energy is finished, the energy rises. Now, we'll see how to gauge the amount of work done.
Work Done on a Particle:
The change in a particle's kinetic energy is what is referred to as work done on a particle. The particle has an initial kinetic energy if it is originally moving. However, there is also a change in the particle's kinetic energy if its direction of travel changes.
u=29m/s
v=43m/s
from work- energy theorem
W=change in K.E
= 1/2mv^2 -1/2mu^2
= 1/2m(v^2 - (-u)^2)
=0.5*0.011*(43*43-29*29)
W=5.54 J
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I need to know what the answer is to this
I agree with Katelyn's statement
Explanation:Netwon's first law of motion states that an object will remain at rest or in uniform motion except acted upon by an external (unbalanced) force.
When balanced forces are acting on an object in motion, the object maintains its speed and direction.
This means that balanced forces do not change the speed and direction of an object in motion. We can say that the object is in equilibrium. It either remains at rest or in uniform motion.
Therefore, I agree with Katelyn's statement
An object accelerates from rest to a speed of 24 m/s over a distance of 56 m. What
acceleration did it experience?
Answer:
5.14 m/s^2
Explanation:
v * t = distance AVERAGE velocity = (24-0) / 2 = 12 m/s
distance / v = time
56 m / 12 m/s = 4.67 s
vf = at
24 = a ( 4.67) a = 5.14 m/s^2
5. A 950 kg car is driven up a hill at constant velocity of 7 m/s, where 1200 N of friction
and drag oppose its motion.
constant velocity
a. Draw a force diagram for the car.
b. What is the weight of the car?
c. Calculate the normal force on the car.
d. Calculate the force on the car that allows it to go up the hill.
a)The image is attached to the question
b) The weight is 9310 N
c) The normal force is -9310 N
d) The net force is 8110 N
What is the normal force on the car?Let s recall that action and reaction are equal and opposite. This implies that the normal force and the weight of the object are the same in magnitude but opposite in direction. Given this, we can now answer the question as shown.
b) The weight of the car is obtained from 950 kg * 9.8 m/s^2 = 9310 N
c) The normal force on the car = -9310 N
d) The force on the car that allows it to go up the hill is the net force which is obtained from ;
9310 N - 1200 N = 8110 N
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help please i need help
Explain how the values and needs of contemporary society influence the focus of research into car safety. Using Newton’s laws of motion, describe three key safety features in the design of cars that help reduce personal injury in a car crash.
500 words please
Sir Isaac Newton's three laws of motion are manifested in nearly every activity of everyday life including traffic accidents. From flying birds to racing cars these laws of motion are everywhere. In fact, nearly 99% of all activity in our physical world is usually governed by these laws.
Newton's laws of motion are very important when engineers design airplanes sports equipment cars train toys and more. This article describes Newton's three laws of motion in car accidents. Newton's first law of motion states that when an object is in motion, it will move at the same speed and in the same direction, or if it is at rest, it will continue to move until acted upon by an external force. In other words, objects have a natural tendency to continue doing what they were doing until they respond.
In the absence of an external force, a moving object maintains its original state of motion or remains stationary. This law is usually called the law of inertia. Newton's second law of motion states that an object subjected to a force experiences an acceleration such that the force is equal to the mass times the acceleration. Mathematically this is expressed as . In other words, the force exerted during a collision is proportional to the mass of the colliding vehicle. This means that the more force a car collides with the more force it applies which means more destruction. The opposite is also true If the mass of the colliding vehicle is less, less force will be applied and there will generally be less destruction.
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A boy walks 1/4th of his journey at 2 m/s and run the rest at 3 m/s - what is his average speed?
Answer:
See below
Explanation:
1/4 d / 2 = time for 2 m/s
3/4d / 3 = time for 3 m/s
total distance / total time = average speed :
d / [ 1/4 d / 2 m/s + 3/4 d/ 3 m/s ] <=====simplify ( 'd' goes away)
1 / [ 1/4 / 2 + 3/4 / 3 ] = 2 2/3 m/s
a hypothetical planet has a radius 2.0 times that of earth but has the same mass. what is the acceleration due to gravity near its surface?
If a hypothetical planet has a radius 2.0 times that of the earth but has the same mass, then the acceleration due to gravity near its surface would be one-fourth of the acceleration due to gravity of the earth.
What is gravity?It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.
As given in the problem, a hypothetical planet has a radius 2.0 times that of the earth but has the same mass.
Gravity = GM / R²
= GM / ( 2R )²
g' = g / 4
Thus, the acceleration due to gravity near its surface would be one-fourth of the acceleration due to the gravity of the earth.
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Suppose that you observe a spaceship passing in front of you at a relative velocity v=0.75c. According to a clock on Earth, 2.5 seconds passed in the spaceship clock.Find the time elapsed for an observer inside the spaceship.
Given,
The velocity of the spaceship in as observed by an observer at the earth, v=0.75c
The time interval as observed by the observer on the earth, t₁=2.5 s
The time elapsed in the ship's frame of reference is given by,
[tex]t_2=\frac{t_1}{\sqrt[]{1-\frac{v^2}{c^2}}}[/tex]On substituting the known values,
[tex]\begin{gathered} t_2=\frac{2.5_{}}{\sqrt[]{1-\frac{(0.75c)^2}{c^2}}} \\ =\frac{2.5}{0.66} \\ =3.79\text{ s} \end{gathered}[/tex]Thus the time elapsed for an observer in the spaceship is 3.79 s
two particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation between the particles is tripled. find the new force of gravitational interaction f1.express your answer in terms of f0.
The force would be F0=9×F1
Solution
The equation describing the attractive force between two masses (m) separated by a distance (r) is known as Sir Isaac Newton's universal law of gravitation (F=Gmm/r²)
By putting the values given in the question -
F0= Gm1m2÷r²
F1=Gm1m2÷(3r)²
By dividing F0 and F1 we get -
F0=9×F1
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starting from rest, a 93-kg firefighter slides down a fire pole. the average frictional force exerted on him by the pole has a magnitude of 810 n, and his speed at the bottom of the pole is 3.4 m/s. how far did he slide down the pole?
If the pole's height is "h," then the firefighter will experience a net downward force of F = mg - frictional mg-1 force.
Work done to bring him down equals F x h = 1014 x h because F = 93 x 9.8 - 810 = 9114 - 810 = 101.4N.
This is going to become his kinetic energy.
Therefore, 1 mu 2 2 equals 101.4 h, where V = 3.4 m/s, 2x93 X(3.4)2 equals 101.4 h, and h = (933.43.4) / (2x101.4) equals 5.3 m.
Kinetic energy is the power a thing has as a result of motion. Applying a force is necessary if we want to accelerate an object. We must exert effort in order to apply a force. Once the job is finished, energy is transferred to the item, which then moves at a new, constant speed.
The force produced when two surfaces slide against and touch one another is referred to as frictional force. There are a few things that affect the frictional force: The surface texture of these forces and the amount of force pressing them together have the biggest impact.
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