help me pleaseeeeeeeeeeeeeeeeeeeeeee
thank you
Answer:
Domain: A, [tex][2, \infty)[/tex]
Range: [tex](-\infty, \infty)[/tex]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
Jonathan needs to buy some food for his dog. At the nearest store, 6 bags of dog food cost $30.72. How much would Jonathan spend on 4 bags?
Group of answer choices
$15.36
$20.48
$25.60
$22.40
Answer: B
Step-by-step explanation: find the amount for one bag, by doing 30.72/6, to get 5.12. Then multiply that by 4 to get $20.48
Answer: $20.48
Step-by-step explanation:
first divide the total ( 30.72) by six and you will get 5.12 which is how much it cost to by one bag now since they want to know how much it would cost if you bought four bags multiply that by four and you will get 20.48 which is the correct answer
The graph below shows the profits for a circus.a. What is the dependent variable?b. What is the independent variable?c. What is the slope (rate of change) of the line?d. What does this number mean for the circus?
Most of the time, the independent variable is located in the horizontal axis (x) and the dependent variable is located in the vertical axis (y), a change in the independent variable causes an influence on the value of the dependent variable, in this case, the dependent variable would be the profit in $ (thousands) and the independent variable is the # of tickets sold (thousands).
The slope of a line (m) is calculated by means of the formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Where (x1,y1) and (x2,y2) are points of the line, i this case, the x coordinate of the line represents # of tickets sold and the y coordinate the profit in $.
We can take whatever point from the line, I'll take the points (0,0) and (40,60), then the slope of the line is:
[tex]m=\frac{60-0}{40-0}=\frac{60}{40}=\frac{6}{4}=\frac{3}{2}[/tex]Then, the slope of the line equals 3/2
The slope of this line represents the earnings per ticket
A) Determine the equation of the parabola with a vertex at (-2, 12) and also goes through (1, -15).
y = 23.6(x + 2)² + 12 is the equation of the parabola with a vertex at (-2, 12) and also goes through (1, -15).
The vertex form equation of a parabola is,
y = a(x - h)² + k
where (h,k) is the vertex coordinates and an is a multiplier.
here (h,k) = (-2,12)
Taking, y = a(x - h)² + k
Substitute (1, -15) in the equation to derive.
(-15)² = a(1 - (-2))² + 12
225 = a(1 + 2)² + 12
225 - 12 = a(3)²
213 = a × 9
213 ÷ 9 = a
a = 23.6
The vertex form: y = 23.6(x + 2)² + 12
simplifying,
23.6 × (x² + 2 × x × 2 + 4) + 12
= 23.6 × (x² + 4x + 4) + 12
= 23.6x² + 94.4x + 94.4 + 12
= 23.6x² + 94.4x + 106.4
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Write an inequality for the following problem. Use M for your variable.
22 less than 5 times a number is greater than 65.
Helppp
Answer:
5m - 22 > 65
I hope this helps!
If f(x) = 5x+27, find the instantaneous rate of change of f(x) at x=9
The instantaneous rate of change refers to the derivative of f(x), so let's find that first, following the power rule, we have.
[tex]f^{\prime}(x)=1\cdot5x^{1-1}=5x^0=5\cdot1=5[/tex]As you can observe, the instantaneous rate of change is a constant, which means we don't have to evaluate it at x=9.
Therefore, the instantaneous rate of change is f'(x) = 5.The cost for renting a truck for one day is $19.95 and has a rate of$0.50 per mile. Write a function rule to model the cost of renting atruck for one day. Then evaluate the function for traveling 73 miles.
The cost of renting a truck for one day is $19.95 and has a rate of $0.50 per mile.
We can write a function rule to model the cost of renting a truck for one day.
[tex]y=0.50x+19.95[/tex]Where x is the number of miles and y is the corresponding cost of renting.
Now we can find the cost of renting for traveling 73 miles.
Substitute x = 73 into the function.
[tex]\begin{gathered} y=0.50(73)+19.95 \\ y=36.5+19.95 \\ y=\$56.45 \end{gathered}[/tex]Therefore, the cost of renting the truck for one day and 73 miles will be $56.45
A box of cereal states that there are 81 calories in a
3/4-cup serving. What is the unit rate for calories per cup? How many calories are there in of the cereal?
What is the volume of the pyramid shown below?A. 294 cu. unitsB. 1008 cu. unitsC. 112 cu. unitsD. 196 cu, units
Step 1
Write an expression for the volume of a square-based triangular pyramid
[tex]\text{Volume(V) =}\frac{1}{3}\times base\text{ area(b)}\times height[/tex]height= 12
Step 2
Find the base area
[tex]\begin{gathered} \text{Base area = length }\times\text{ width} \\ \text{Length = 7} \\ \text{Width = 7} \\ \text{Base area = 7}\times7=49unit^2 \end{gathered}[/tex]Step 3
Find the volume of the shape
[tex]\begin{gathered} V\text{ = }\frac{1}{3}\times49\times12 \\ V\text{ =}196unit^3 \end{gathered}[/tex]Please help it’s due tonight I will give a brainlist
The percentage of the markdown amount is approximately 30%.
What is the percentage?A percentage is a number or ratio expressed as a fraction of 100 in mathematics. Although the abbreviations "pct.", "pct.", and occasionally "pc" is also used, the percent sign, "%," is frequently used to indicate it. A percentage is a number without dimensions and without a standard measurement. By dividing the value by the total value and multiplying the result by 100, one can determine the percentage. The percentage calculation formula is (value/total value)100%.So, the percentage of markdown amount:
The total amount is $54.88.The markdown amount is $16.38.So, the markdown percentage is calculated as follows:
16.38/54.88 × 1000.2984 × 10029.84Rounding off: 30%
Therefore, the percentage of the markdown amount is approximately 30%.
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Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-3,5) and parallel to x + 2y = 5.
we need to find the equation of a like, in two different ways
a) slope-interceppt Y=mX+b
b) standard form aX+bY=c
the information we have is,
it's parallel to x+2y=5 (this mean the have the same slope
so, let's find it
x+2y=5
2y=5-x
y=5/2 - 1/2 x
the slope is m= -1/2
The other thing we know is the line passing through (-3,5)
so when x=-3 the value of Y has to be 5
So let's check, until now we have the slope, our line is y= -1/2x + B
let's find out the value of B, replacing the values of x and y
5= -1/2 * -3 +B
5= 3/2 + B
7/2= B
So, the answer to (a) is=
Y= -1/2 X + 7/2
b) we need to change from slope to standard form
Y= -1/2 X + 7/2
Y + 1/2 X= 7/2
i think that's standard form, but also you can divide for 7/2 to get
2/7 Y + 1/7 X = 1
The mean of a set of data is 25 with a standard deviation of 2. What is the interval about the mean of the data within one standard deviation? Where is my answer?
Mean = 25
Standard deviation= 2
The interval about the mean is
Thus the interval will be
(mean - SD) to (mean + SD)
(25-2) to ( 25 +2)
23 to 27
The interval will be between 23 - 27
helppppppppppppppppppppppppppppppppppppppp
Answer:
8, 11, 10
Step-by-step explanation:
Which of the following is the once of a rhombus?
Product of its diagonals.
Half of sum of its diagonals
Half of product of its diagonals.
The answer is Half of product of its diagonals which is option C .
Let d1 and d2 be the diagonals of the rhombus.
A rhombus can be defined as a special parallelogram as it fulfills the requirements of a parallelogram, i.e. a quadrilateral with two pairs of parallel sides. In addition to this, a rhombus has all four sides equal just like a square. That is why it is also known as a tilted square.
Area of rhombus using diagonals (A) = 1/2 * d1 * d2.
where ,
d1 = length of diagonal 1
d2 = length of diagonal 2.
Therefore the answer is Half of product of its diagonals which is option C.
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17. Points W and Z are 8 unitsapart on the coordinate grid. Four facts aboutthe coordinates of the points are shown.• Point W is located at (-3, p).• The variable p has a value greater than 0.• Point Z is located at (-3, r).• The variable r has a value less than 0.What are possible values of p and r?p=OOlolOOO OCOOOOOOOOOOOOOSOOCOOOOOOOOOO0 0 0 0OOOOOOOCCO0 0
Possible values of p are from 1 to 7 while possible values of r are from -1 to -7
Here, we want to get the possible values of p and r
From the question, we have it that both W and Z are located at the same axis coordinate
What this mean is that it is a vertical line that connects both
Variable p has a value greater than zero means that it has a positive value
Variable r has a value less than zero means it has a negative value
Since the two are 8 units apart, we have it that;
p-r = 8
or p = 8 + r
Also, we have it that;
p > 0
r < 0
So, we need pairs of numbers that could work
We can use different values, minding the fact that p is positive and r is negative
If we have p = 7
r will be 7-8 = -1
p = 7 and r = -1 is a possible value
p = 6 and r = -2 is a possible value
p = 5 and r = -3 is a possible value
p = 4 and r = -4 is a possible value
p = 3 and r = -5 is a possible value
p = 2 and r = -6 is a possible value
p = 1 and r = -7 is a possible value
Thus, we have it that the value of p ranges from 1 to 7 while the value of r ranges from -1 to -7
I need to use factorials and doing it step-by-step for the bio normal probability formula Please help me figure this A through C step-by-step they want the factorial symbol! When showing my workGiven the number of trials and the probability of success, determine the probability indicated: (Hint use binomial distribution formula use factorials ! in showing your work)n = 15, p = 0.4, find P(4 successes) n = 12, p = 0.2, find P(2 success ) n = 20, p = 0.05, find P(at most 3 successes) (hint for c. P (at most 3 successes) = P(x ≤3)= P(x= 0) + P(x = 1)+ P(x = 2)+ P(x = 3)I just got disconnected from my tutor who said it would take 20 minutes to song and help me go over it step-by-step so if you were that tutor or any tour available please contact
Binomial distribution formula:
[tex]P(x)=\frac{n!}{(n-x)!x!}*p^x*q^{n-x}[/tex]________
n = 15, p = 0.4, find P(4 successes)
[tex]\begin{gathered} n=15 \\ x=4 \\ p=0.4 \\ q=1-0.4=0.6 \\ \\ P(x=4)=\frac{15!}{(15-4)!*4!}*0.4^4*0.6^{15-4} \\ \\ P(x=4)=\frac{15!}{11!*4!}*0.4^4*0.6^{11} \\ \\ P(x=4)=\frac{15\times14\times13\times12\times11!}{11!*4!}*0.4^4*0.6^{11} \\ \\ P(x=4)=\frac{15\times14\times13\times12}{4\times3\times2\times1}*0.4^4*0.6^{11} \\ \\ P(x=4)=1365*0.4^4*0.6^{11} \\ \\ P(x=4)=0.1268 \end{gathered}[/tex]__________________
n = 12, p = 0.2, find P(2 success )
[tex]\begin{gathered} n=12 \\ x=2 \\ p=0.2 \\ q=1-0.2=0.8 \\ \\ P(x=2)=\frac{12!}{(12-2)!*2!}*0.2^2*0.8^{12-2} \\ \\ P(x=2)=\frac{12!}{10!*2!}*0.2^2*0.8^{10} \\ \\ P(x=2)=\frac{12\times11\times10!}{10!*2!}*0.2^2*0.8^{10} \\ \\ P(x=2)=\frac{12\times11}{2\times1}*0.2^2*0.8^{10} \\ \\ P(x=2)=66*0.2^2*0.8^{10} \\ \\ P(x=2)=0.2835 \end{gathered}[/tex]_________________________
n = 20, p = 0.05, find P(at most 3 successes)
Find each part (P(x=0), P(x=1), P(x=2), P(x=3)) and then sum the results
[tex]\begin{gathered} n=20 \\ p=0.05 \\ q=1-0.05=0.95 \\ \\ \end{gathered}[/tex][tex]\begin{gathered} P(x=0)=\frac{20!}{(20-0)!0!}*0.05^0*0.95^{20-0} \\ \\ P(x=0)=\frac{20!}{20!*0!}*1*0.95^{20} \\ \\ P(x=0)=\frac{20!}{20!*1}*1*0.95^{20} \\ P(x=0)=1*1*0.95^{20} \\ P(x=0)=0.3585 \end{gathered}[/tex][tex]\begin{gathered} P(x=1)=\frac{20!}{19!*1!}*0.05^1*0.95^{19} \\ \\ P(x=1)=\frac{20\times19!}{19!*1}*0.05*0.95^{19} \\ \\ P(x=1)=20*0.05*0.95^{19} \\ P(x=1)=0.3774 \\ \end{gathered}[/tex][tex]\begin{gathered} P(x=2)=\frac{20!}{18!*2!}*0.05^2*0.95^{18} \\ \\ P(x=2)=\frac{20\times19\times18!}{18!*2\times1}*0.05^2*0.95^{18} \\ \\ P(x=2)=190*0.05^2*0.95^{18} \\ P(x=2)=0.1887 \end{gathered}[/tex][tex]\begin{gathered} P(x=3)=\frac{20!}{17!*3!}*0.05^3*0.95^{17} \\ \\ P(x=3)=\frac{20\times19\times18\times17!}{17!*3\times2\times1}*0.05^3*0.95^{17} \\ \\ P(x=3)=1140*0.05^3*0.95^{17} \\ P(x=3)=0.0596 \end{gathered}[/tex][tex]P(x\leq3)=0.3585+0.3774+0.1887+0.0596=0.9842[/tex]Express the statement in symbolic form and construct the truth table for the statement. "Cheap Trick does not play at the White House and Jacque is the president."Use the symbolic representationsp: cheap trick plays at the White Houseq: Jacque is the president(May complete on your paper or in the space provided)
Answer:
Explanation:
Here, we want to express the statement in symbolic form and construct the truth table for the statement
From what we have, the symbolic form is as follows:
[tex]\text{ \textasciitilde p }\wedge\text{ q}[/tex]Now, let us complete the truth table as follows:
Can you prove these triangles are congruent from the information given?
Given:
Give names to the triangles
Aim:
We need to find whether these triangles are congruent.
Explanation:
The lines AE and DC are perbenticular.
[tex]\angle ABC\cong\angle\angle DBE\text{ since perpendicular lines makes right angles.}[/tex]Recall that the dashes on the lines show they are equal in length.
[tex]BC\cong BD\text{ Since both sides have single dashes.}[/tex][tex]AC\cong DE\text{ Since both sides have double dashes.}[/tex]Two sides and an angle not included between them are respectively equal to two sides and an angle of the other than the two triangles are equal.
[tex]\Delta ABC\cong\Delta DBE\text{ by SSA postulates}[/tex]Final answer:
The triangles ABC and DBE are congruent.
It’s asking to find / solve for X. I just can’t remember how to do it
Given:
There are given that arc length is 192 degrees and angle G is:
[tex]31x+3[/tex]Explanation:
To find the value of x, we need to use the circle properties:
So,
From the circle properties:
[tex]31x+3=192^{\circ}[/tex]Then,
Subtract 3 from both sides of the equation:
So,
[tex]\begin{gathered} 31x+3=192^ \\ 31x+3-3=192^-3 \\ 31x=189 \end{gathered}[/tex]Now,
Divide by 31 on both sides of the above equation:
So,
[tex]\begin{gathered} 31x=189 \\ x=\frac{189}{31} \\ x=6.096 \end{gathered}[/tex]Final answer:
Hence, the value of x is shown below:
[tex]x=6.096[/tex]What are the domain and the range of this function? please i need this fast ill give 15 pts
Given data:
The given graph is shown.
The domain is the value of x for which the given function is defined, the domain of the given graph is,
[tex]D=\lbrack-5,1)[/tex]The range is the value of y for which the given function is defined, the range of the given graph is,
[tex]R=\lbrack-4,\text{ 7)}[/tex]Thus, the domain of the given function is [-5,1), and range is [-4, 7).
In parallelogram FGHJ if m^GHJ=55° find m ^ FGH. I
Given:
[tex]m\angle GHJ=55^o\text{ and m}\angle FGH=x^o[/tex]Recall that the adjacent angles of the parallelogram are supplementary.
[tex]\begin{gathered} m\angle GHJ\text{ and m}\angle FGH\text{ are adjacent angles of the given parallelogram and these are supplementary.} \\ \end{gathered}[/tex]We know that the sum of the supplementary angles is 180 degrees.
[tex]m\angle GHJ+\text{m}\angle FGH=180^o[/tex][tex]55^o+x^o=180^o[/tex][tex]x^o=180^o-55^o[/tex][tex]x^o=125^o[/tex]Hence the answer is
[tex]\text{ m}\angle FGH=125^o[/tex]Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Zoe is making greeting cards, which she will sell by the box at an arts fair. She paid $22 for a booth at the fair, and the materials for each box of cards cost $4. She will sell the cards for $15 per box of cards. At some point, she will sell enough cards so that her sales cover her expenditures. How many cards will that take? How much will the sales and expenditures be?
Let x be the number of box cards
Expenditures: $22 plus $4 times x
[tex]E=22+4x[/tex]Sales: $15 times x
[tex]S=15x[/tex]At some point, she will sell enough cards so that her sales of her cover her expenditures of her: Equal E and S
[tex]E=S[/tex]Substitute the values of E and S:
[tex]22+4x=15x[/tex]Solve x:
[tex]\begin{gathered} 22+4x-4x=15x-4x \\ 22=11x \\ \frac{22}{11}=\frac{11}{11}x \\ 2=x \\ \\ \\ x=2 \end{gathered}[/tex]Use the value of x to find the sales and expenditures:
[tex]\begin{gathered} S=15x \\ S=15(2) \\ S=30 \\ \\ E=22+4x \\ E=22+4(2) \\ E=22+8 \\ E=30 \end{gathered}[/tex]Then, It takes to Zoe sell 2 box cards to cover the expenditures, the sales need to be $30 to cover the expendituresThree. 5 m away from the base of the building. How I is window B?
Explanation
Given that each ladder is 3.5 meters away from the base of the building, we are asked to find the height of the building. This can be seen below,
Number 1:
The height of ladder A is 5.5 meters. We can then use the Pythagoras theorem to find the height of the window.
[tex]\begin{gathered} 5.5^2=3.5^2+A^2 \\ A^2=5.5^2-3.5^2 \\ A=\sqrt{5.5^2-3.5^2}=\sqrt{30.25-12.25} \\ A=4.24m \end{gathered}[/tex]
Answer: Height of window A =4.24m
Number 2
The height of ladder B is 8.8 meters. We can then use the Pythagoras theorem to find the height of the window.
[tex]\begin{gathered} 8.8^2=3.5^2+B^2 \\ B^2=8.8^2-3.5^2 \\ B=\sqrt{8.8^2-3.5^2}=\sqrt{77.44-12.25}=\sqrt{65.19} \\ B=8.07 \end{gathered}[/tex]Answer: Height of window B =8.07m
Number 3
The height of ladder B is 9.3 meters. We can then use the Pythagoras theorem to find the height of the window.
[tex]\begin{gathered} 9.3^2=3.5^2+C^2 \\ C^2=9.3^2-3.5^2 \\ C=\sqrt{9.3^2-3.5^2}=\sqrt{86.49-12.25}=\sqrt{74.24} \\ C=8.62 \end{gathered}[/tex]Answer: Height of window C =8.62m
Number 4
The height of ladder B is 7.9 meters. We can then use the Pythagoras theorem to find the height of the window.
[tex]\begin{gathered} 7.9^2=3.5^2+D^2 \\ D^2=7.9^2-3.5^2 \\ D=\sqrt{7.9^2-3.5^2}=\sqrt{62.41-12.25}=\sqrt{50.16} \\ D=7.08 \end{gathered}[/tex]Answer: Height of window D = 7.08m
Which relation is a function?
Answer:
The V (Bottom left)
Step-by-step explanation:
The top left is NOT a function because it fails the vertical line test. In fact, it is a vertical line.
The top right is NOT a function because it also fails the vertical line test. This graph may be considered as an inverse of a different function but it will not be a true inverse.
The bottom left IS a function because it passes the vertical line test. It has 1 x value for every y value.
The bottom right is NOT a function because it fails the vertical line test. At most x values, it has 2 y values.
The vertical line test is an imaginary line that you draw to test a function. If only 1 point hits the vertical line, then it is a function. The vertical line can be placed at any point in the graph.
Hope that helps
The Jurassic Zoo charges $5 for each adult admission and $3 for each child. The total bill for the 243 people from a school trip was $823. How many adults and how many children went to the zoo? There were adults and children on the trip
Let x be the number of adult and let y be the number of children
5x + 3y = 823 --------------------------(1)
x + y = 243 ----------------------------(2)
We can now solve simultaneously
Multiply through equation (2) by 3
3x + 3y =729 -----------------(3)
subtract equation (3) from equation (1)
2x =94
Divide both-side of the equation by 2
x =47
substitute equationx = 47 into equation (2) and then solve for y
47 + y = 243
subtract 47 from both-side of the equation
y = 243 - 47
y = 196
Hence
Complete the description of how to find the sums −4 + 1 and −4 + (−1) on a number line.
To find −4 + 1, start at −4 and move 1 unit to the _____ to _____.
To find the sum −4 + (−1), start at −4 and move 1 unit to the ______ to ______
Integer Sums on a Number Line,
Start in the location that the first number denotes. Move the equivalent amount of units to the left if the second number is negative. Move that many units if it's affirmative.
How can I calculate the total on a number line?
Result for an image Fill in the blanks to describe how to locate the sums 4 + 1 and 4 + (1) on a number line. Start at 4, then move one unit to the ____ to ____ to find 4 + 1. Start at 4, then move 1 unit to the _____ to _____ to find the sum 4 + (1).
Utilizing a number line, combine two integers:
Make a number line first.
Next, locate the first integer's position on the number line.
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change the height for Ramp 2 to make a smooth slide
First answer:
If you look carefully to the measures of the three triangles that are the ramps of the exercise, you will notice they are similar after comparing them.
• Ratio of Ramp 1 = 2/3
,• Ratio of Ramp 2 = 4/6
,• Ratio of Ramp 3 = 6/9
Second answer
The information is given on the image and we can calculate the missing measures for make a smooth slide:
• Ramp 1 - Base 10 - Height 12
,• Ramp 2 - Base 15 - Height 18
,• Ramp 3 - Base 30 - Height 36
We used the ratio 2/3 for answering the first question, now we have the ratio
5/6, as follows:
• Ramp 1 - 5/6 * 2/2 = 10/12
,• Ramp 2 - 5/6 * 3/3 = 15/18
,• Ramp 3 - 5/6 * 6/6 = 30/36
Bill paints murals. He recorded the total amount of white paint that he used for his murals each month in the table below. In April, Bill used 2/3 of the amount that he used in March. Fill in the amount of white paint Bill used in April in the table below.month liters of white paint usedMarch 4/5Aprilmay 1 1/4
Answer:
8/15 (in litres).
Explanation:
In April, Bill used 2/3 of the amount that he used in March.
[tex]\begin{gathered} \text{Amount used in April}=\frac{2}{3}\text{ of the amount used in March} \\ =\frac{2}{3}\times\frac{4}{5} \end{gathered}[/tex]Next, we simplify:
[tex]\begin{gathered} =\frac{2\times4}{3\times5} \\ =\frac{8}{15} \end{gathered}[/tex]The amount he used in April was 8/15 (in litres).
Which is an x-intercept of the graphed function?
O (0, 4)
(-1, 0)
(4, 0)
(0, -1)
A line's x-intercept and y-intercept are the points at which the x axes- and y-axes, respectively, are crossed. We find it easier to graph linear equations when we consider intercepts.
We set y = 0 and solve the equation for x to determine the x-intercept.
The graphed function derived from the choices has the x-intercept (-1, 0)
How do you calculate the x-intercept?A graph's x-intercept is the location where the graph crosses the x-axis.
The graph in the accompanying image crosses the x-axis at:
(-2, 0), (-1, 0), (1, 0) and (2, 0) (2, 0)
Consequently, the x-intercept of the graphed function derived from the alternatives (-1, 0)
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A rectangular backyard has a length of of 68 feet and a width if 40 1/2 feet. the owner wants to play 75% of the yard with grass seed the planting rate for the seed is 1.5 pounds per 1000 square feet of area.To the nearest tenth of a pound ,how much grass seed will tye owner need to plant
We have the following:
The first thing to do is calculate the area of the backyard
[tex]\begin{gathered} A=l\cdot w \\ l=68 \\ w=40\frac{1}{2} \\ \text{replacing:} \\ A=68\cdot40\frac{1}{2}=2754 \end{gathered}[/tex]Now, they tell us it is 75% of the backyard therefore
[tex]2754\cdot0.75=2065.5[/tex]Now we calculate the amount in pounds knowing that for each square foot of area 1.5 pounds are needed
[tex]2065.5\cdot\frac{1.5}{1000}=3.1[/tex]The answer is 3.1 pounds
