When [tex]n=1[/tex],
[tex]10^{2\cdot1 - 1} + 1 = 10^1 + 1 = 11[/tex]
which is of course divisible by 11.
Assume this holds for [tex]n=k[/tex], that
[tex]11 \mid 10^{2k - 1} + 1[/tex]
In other words,
[tex]10^{2k - 1} + 1 = 11\ell[/tex]
for some integer [tex]\ell[/tex].
Use this to show the claim is true for [tex]n=k+1[/tex].
[tex]10^{2(k+1) - 1} + 1 = 10^{2k + 1} + 1 \\\\ ~~~~~~~~~~~~~~~~~~~~ = 10^{2k+1} + \left(10^{2k-1} + 10^{2k-1}\right) + 1 \\\\ ~~~~~~~~~~~~~~~~~~~~ = \left(10^{2k+1} - 10^{2k-1}\right) + \left(10^{2k-1} + 1\right) \\\\ ~~~~~~~~~~~~~~~~~~~~ = 10^{2k-1} \left(10^2 - 1\right) + 11\ell \\\\ ~~~~~~~~~~~~~~~~~~~~ = 99\times10^{2k-1} + 11\ell \\\\ ~~~~~~~~~~~~~~~~~~~~ = 11\left(9\times10^{2k-1} + \ell\right)[/tex]
which is indeed divisible by 11. QED
On the off-chance you meant [tex]10^{2^n-1}+1[/tex], notice that [tex]2n-1[/tex] is odd for any integer [tex]n[/tex]. Similarly [tex]2^n-1[/tex] is odd for all [tex]n[/tex], so the above proof actually proves this automatically.
Identify the vertex of the parabola ?
Step-by-step explanation:
second one
explanation: trust me bro
Write an absolute value equation to satisfy the given solution set shown on a number line
(infinity -1/2]u [-1/2 -1/2] u [1/2 infinity)
question in pictures
The derivatives of the functions are listed below:
(a) [tex]f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}[/tex]
(b) [tex]f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }[/tex]
(c) f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²
(d) f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]
(e) f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶
(f) [tex]f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}][/tex]
(g) [tex]f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)[/tex]
(h) f'(x) = cot x + cos (㏑ x) · (1 / x)
How to find the first derivative of a group of functions
In this question we must obtain the first derivatives of each expression by applying differentiation rules:
(a) [tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}[/tex]
[tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}[/tex] Given[tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4\cdot x - \frac{x}{5} + 5 \cdot x^{-1} - \sqrt[11]{2022}[/tex] Definition of power[tex]f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}[/tex] Derivative of constant and power functions / Derivative of an addition of functions / Result(b) [tex]f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}[/tex]
[tex]f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}[/tex] Given[tex]f(x) = (x + 3)^{\frac{1}{3} }\cdot (x + 5)^{\frac{1}{3} }[/tex] Definition of power[tex]f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }[/tex] Derivative of a product of functions / Derivative of power function / Rule of chain / Result(c) f(x) = (sin x - cos x) / (x² - 1)
f(x) = (sin x - cos x) / (x² - 1) Givenf'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)² Derivative of cosine / Derivative of sine / Derivative of power function / Derivative of a constant / Derivative of a division of functions / Result(d) f(x) = 5ˣ · ㏒₅ x
f(x) = 5ˣ · ㏒₅ x Givenf'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)] Derivative of an exponential function / Derivative of a logarithmic function / Derivative of a product of functions / Result(e) f(x) = (x⁻⁵ + √3)⁻⁹
f(x) = (x⁻⁵ + √3)⁻⁹ Givenf'(x) = - 9 · (x⁻⁵ + √3)⁻⁸ · (- 5) · x⁻⁶ Rule of chain / Derivative of sum of functions / Derivative of power function / Derivative of constant functionf'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶ Associative and commutative properties / Definition of multiplication / Result(f) [tex]f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}[/tex]
[tex]f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}[/tex] Given[tex]f'(x) = 7^{x\cdot\ln x} \cdot \ln 7 \cdot (\ln x + 1) + 7\cdot (x\cdot \ln x)^{6}\cdot (\ln x + 1)[/tex] Rule of chain / Derivative of sum of functions / Derivative of multiplication of functions / Derivative of logarithmic functions / Derivative of potential functions [tex]f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}][/tex] Distributive property / Result(g) [tex]f(x) = \arccos^{2} x - \arctan (\sqrt{x})[/tex]
[tex]f(x) = \arccos^{2} x - \arctan (\sqrt{x})[/tex] Given[tex]f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)[/tex] Derivative of the subtraction of functions / Derivative of arccosine / Derivative of arctangent / Rule of chain / Derivative of power functions / Result(h) f(x) = ㏑ (sin x) + sin (㏑ x)
f(x) = ㏑ (sin x) + sin (㏑ x) Givenf'(x) = (1 / sin x) · cos x + cos (㏑ x) · (1 / x) Rule of chain / Derivative of sine / Derivative of natural logarithm /Derivative of addition of functions f'(x) = cot x + cos (㏑ x) · (1 / x) cot x = cos x / sin x / ResultTo learn more on derivatives: https://brainly.com/question/23847661
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Given that a function, g, has a domain of -20 < x < -5 < g(x) <45 and that g(0)= -2 and g(-9)= 6, select the statement that could be true for g.
The given statement that's true about the function is g(-13) = 20 is true for g.
How to illustrate the function?From the information given, the function, g, has a domain of -20 < x < -5 < g(x) <45 and that g(0)= -2 and g(-9)= 6.
Let's analyze the options that are given in the scenario. g(7) = -1. It should be noted that 7 isn't in our domain. Therefore, this isn't possible.
g(-13) = 29
x = 13 is in our domain and 20 is also is in our range. Therefore, this is true for g.
g(0) = 2.
This isn't true because it is given that g(0) = 2
In conclusion, the given statement that's true about the function is g(-13) = 20 is true for g.
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Kieron is using a quadratic function to find the length and width of a rectangle. He solves his function and finds that
w = −15 and w = 20
Explain how he can interpret his answers in the context of the problem.
Answer:
Step-by-step explanation:
The correct value of w is 20 as the width of a rectangle must be positive. A quadratic function always has 2 zeroes and in a case like this the negative one is ignored.
4x-12y=-20 substitution method
If we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.
Given two equations x-2y=5 and 4x+12y=-20.
We are required to find the value of x and y through substitution method.
Equation is like a relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. Equation can be a linear equation,quadratic equation, cubic equation or many more depending on the power of variable.
They can be solved as under:
x-2y=5---------------1
4x+12y=-20--------2
Finding value of variable x from equation 1.
x=5+2y--------------3
Use the value of variable x in equation 2.
4x+12y=-20
4(5+2y)+12y=-20
20+8y+12y=-20
20y=-20-20
20y=-40
y=-40/20
y=-2
Use the value of variable y in equation 3.
x=5+2y
x=5+2*(-2)
x=5-4
x=1
Hence if we solve the equations x-2y=5 and 4x+12y=-20 then we will get x=1 and y=-2.
Question is incomplete as it should include one more equation x-2y=5.
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2) Find the perimeter and area of the figures:
a)
P =
A =
8
8 ft.
b)
P =
A =
12
5m
Answer:
8+8+12+5= 33
Step-by-step explanation:
8+8+12+5=33
Hello please help asap!! i will mark brainliest and this is worth 20 points!!!!! tysm
The least number of colors you need to correct color in the sections of these pictures so that no two touching sections are the same color is 5 colors. This can be obtained by simply giving colors to the small shapes according to the criteria.
What is the least number of colors?From the question the figure, the number of colored sections with which are not colored with respect to a "touching" colored section, would not be half of the total colored sections since the sections are not alternating as they still meet at a common point.
After all, it notes no two touching sections, not adjacent sections.
There is no equation to calculate this requirement with respect to the total number of sections.
Taking one triangle or square as the starting we can give colors to each small units. This figure will be the start of sequence of other small figures.
If a square were to be this starting shape that have same color as that color of the square.
Now from the remaining given another color to the starting figure. We will get that shapes, that will have same color.
Like that the remaining figures are given colors.
Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure.
Hence the least number of colors you need to correct color in the sections of these pictures so that no two touching sections are the same color is 5 colors.
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Como derivar cos(2x)/tan(2x)
Use the quotient and chain rules. If
[tex]y = \dfrac{\cos(2x)}{\tan(2x)}[/tex]
then the derivative is
[tex]\dfrac{dy}{dx} = \dfrac{\tan(2x) \frac d{dx}\cos(2x) - \cos(2x) \frac d{dx}\tan(2x)}{\tan^2(2x)}[/tex]
[tex]\dfrac{dy}{dx} = \dfrac{\tan(2x) (-\sin(2x)) \frac d{dx}(2x) - \cos(2x)\sec^2(2x) \frac d{dx}(2x)}{\tan^2(2x)}[/tex]
[tex]\dfrac{dy}{dx} = \dfrac{-2\sin(2x)\tan(2x) - 2 \sec(2x) }{\tan^2(2x)}[/tex]
and we can rewrite this by
• multiplying by [tex]\frac{\cos^2(2x)}{\cos^2(2x)}[/tex],
[tex]\dfrac{dy}{dx} = \dfrac{-2\sin^2(2x)\cos(2x) - 2 \cos(2x) }{\sin^2(2x)}[/tex]
• factorizing,
[tex]\dfrac{dy}{dx} = -\dfrac{2\cos(2x) \left(\sin^2(2x) + 1\right)}{\sin^2(2x)}[/tex]
etc
Find the area of figure below,
Answer: 57 cm²
Step-by-step explanation:
We can split this figure into two shapes: the rectangle on the left and the triangle on the right. We can find the area of each separately and add them to get the total area.
RectangleThe area of a rectangle is [tex]lw[/tex], where l is the length and w is the width. We can just multiply 8 and 6 to get the area of the rectangle.
[tex]A=8*6\\A=48[/tex]
TriangleThe area of the triangle is [tex]\frac{1}{2}bh[/tex], where b is the base of the triangle and h is the height. Here' the base would be 6 cm as opposite sides of a rectangle have the same measure, and the height is 3.
[tex]A=\frac{1}{2}(6*3)\\A=\frac{1}{2}(18)\\A=9[/tex]
TotalThe total area would just be the sum of the two separate areas.
[tex]48+9=57[/tex]
Hence, the area of the figure is 57 cm².
Answer: 57 cm^2
Step-by-step explanation:
To find the entire area of the figure, we have to find the area of the rectangle and the triangle and sum it up
The area of the rectangle is 6 * 8 = 48 cm^2
The area of the triangle is 1/2 * 3 * 6(Opposite sides of a rectangle have equal lengths) = 9 cm^2
So the area of the figure is 48 + 9 = 57 cm^2
Perform the operation and
simplify.
3
x - 3
5
x + 2
-2x + 21
x² + [ ? ]x + [
Answer: -1
Step-by-step explanation:
Here, we are subtracting two fractions; therefore, we must make the denominators the same by finding the least common multiple. Since we have x - 3 for one denominator and x + 2 for the other, we don't have any common factors. Hence, the least common multiple would be their product.
[tex](x-3)(x+2)\\x(x-3)+2(x-3)\\x^2-3x+2x-6\\x^2-x-6[/tex]
The question is looking for the coefficient of the second term. Since there is just a negative sign in front of the x, the "?" can be filled with either a negative sign or a -1.
The formula for the perimeter of a rectangle is 2L + 2W = P (L = length, W = Width and P = Perimeter.) The perimeter of a rectangular garden is 400 feet. If the length of one side of the garden is 120 feet, what is the width of one side of the garden?
We conclude that the width of the rectangular garden is 80 feet.
How to get the dimensions of the garden?Let's define the variables:
L = length of the garden.W = width of the garden.The perimeter of a rectangle of length L and width W is given by the simple formula:
P = 2*(L + W)
The perimeter is equal to 400ft, then:
400ft = 2*(L + W)
And we know that the length is 120ft, then:
L = 120ft.
Replacing the length in the perimeter equation we get:
400ft = 2*(120ft + W)
Now we can solve this linear equation for W.
400ft/2 = 120ft + W
200ft = 120ft + W
200ft - 120ft = W
80ft = W
We conclude that the width of the rectangular garden is 80 feet.
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A "Shirley Temple" drink is made by a 5.
mixing 2 cups of 7-Up with 4 tablespoons
of grenadine syrup. Write a ratio of
grenadine syrup to 7-Up. (hint: 160 lstot of an
Tablespoons = 1 Cup)
The ratio of grenadine syrup to 7-Up will be 1:8.
How to find the ratio?From the information given, we are told that Shirley Temple" drink is made by a 5 mixing 2 cups of 7-Up with 4 tablespoons of grenadine syrup.
The ratio of grenadine syrup to 7-Up will be:
4 tablespoon : 2 cups
Note that 1 cup = 16 teaspoon
4 : (2 × 16)
= 4:32
= 1:8
Therefore, the ratio of grenadine syrup to 7-Up will be 1:8.
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A vector v has an initial (2,-3) point and terminal point (3,-4)
Write in component form.
The vector in component form is given by:
V = i - j.
How to find a vector?A vector is given by the terminal point subtracted by the initial point, hence:
(3,-4) - (2, -3) = (3 - 2, -4 - (-3)) = (1, -1)
How a vector is written in component form?A vector (a,b) in component form is:
V = a i + bj.
Hence, for vector (1,-1), we have that:
V = i - j.
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You inherit one million dollars. You invest it all in three accounts for one year. The first account pays 3% compounded annually, the second account pays 4% compounded annually, and the third account pays 2% compounded annually. After one year, you earn $34,000 in interest. If you invest four times the money into the account that pays 3% compared to 2%, how much did you invest in each account?
The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000
How to solve for the amount investedWe have x + y + z = 1000000
((1+0.03)x - x)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000
4z + x + z = 1000000
((1+0.03)4z - 4z)+ ((1+0.04)y - y) + ((1 + 0.02)z-z) = 34000
((1+0.03)4z - 1)+ ((1+0.04)y - 1) + ((1 + 0.02)z-1) = 34000
12/100z + 4/100y +2/100z = 34000
2y + 7z = 1700000
-2y - 10z = -2000000
2y + 7z = 1700000
Solve through the use of the simultaneous linear equation
z = 100000
y = 500000
x = 400000
The amount that was invested are at 3% = 400000, at 4% = 500000 and at 2% = 100000
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Which shapes have less than 3 lines of symmetry?
A) B and C
B) A and D
C) B and D
D) A and C
The shapes that have less than 3 lines of symmetry are Isosceles trapezoid and Isosceles triangle
How to determine the shapes that have less than 3 lines of symmetry?The shapes are given as:
Isosceles trapezoidSquareIsosceles triangleRegular PentagonThe lines of symmetry are the lines that, when the shape is rotated through this line, the shape remains the same
As a general rule:
An Isosceles trapezoid and an Isosceles triangle have two lines of symmetry
Hence, the shapes that have less than 3 lines of symmetry are Isosceles trapezoid and Isosceles triangle
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Which of the following represents
the graph of this equation?
y = 1/2|x|
The graph is shown in the attached image.
please help urgently
Answer:
2
Step-by-step explanation:
Substitute:
2(1)(3)+2 / 2(1)(3)-2 =
6 + 2 / 6 - 2 =
8 / 4 =
2.
Hey there!
2ab + 2 / 2ab - 2
= 2(1)(3) + 2 / 2(1)(3) - 2
= 2(3) + 2 / 2(3) - 2
= 6 + 2 / 6 - 2
= 8 / 4
= 2
Therefore, your answer should be: 2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
it took a 3D priner 10528 minutes to print 87 percent of a 3D print job. At this rate of speed how much time will take for the print to
reach 100 percent completion?
The time it would take for the print to reach 100 percent completion is 12,101 minutes 9 seconds.
What is time it would take to reach 100%?The mathematical operations that would be used to determine the required value are division and multiplication. Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Multiplication is the process of determining the product of two or more numbers. The sign used to denote multiplication is ÷.
Other mathematical operations that are used to solve problems include addition and subtraction.
Time it would take to reach 100% completion = (minutes it takes to print 87% of the words x 100%) / 87%
Time it would take to reach 100% completion = (10,528 x 1) / 0.87 =
10.528 / 0.87
= 12,101. 15
= 12,101+ (0.15 x 60)
= 12,101 minutes 9 seconds
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round 00.963.785 to the nearest. hundredth
he value of x?
ur answer in the box. need answer quickly! 35 points!
Answer:
x = 46 degrees
Step-by-step explanation:
180 - 134 = 46
Answer:
46°
Step-by-step explanation:
134 + x add to a straight line angle = 180
134+x = 180
x = 46
Solve the inequality
21≥t+10
The answer is t ≤ 11.
Subtract 10 from each side.21 - 10 ≥ t + 10 - 10t ≤ 11If Emery has $1,400 to invest at 5% per year compounded monthly, how long will it be before he has $2,400? If the compounding is
continuous, how long will it be? (Round your answers to three decimal places.)
Answer:
Step-by-step explanation:
(1400x14.5x5%) + 1400 =2415
Answer: 14.5 months
Caisse can download a maximum of 1000 mb of songs or movies to her smartphone each month. the file of each movie is 85mb, and the file of each song is 4mb. write an inequality that represents the number of movies(M) and songs(S) that Caisse downloads each month?
If Caisse can download a maximum of 1000 mb of songs or movies then the inequality that represents the number of movies and songs that Caisse downloads each month is 85x+4y<1000.
Given that Caisse can download a maximum of 1000 mb of songs or movies to her smartphone each month. the file of each movie is 85mb, and the file of each song is 4mb.
We are required to find the inequality that represents the number movies and songs that Caisse downloads each month.
Inequality is like an equation that shows the relationship between variables that are expressed in greater than, less than , greater than or equal to , less than or equal to sign.
let the number of movies be x and the number of songs be y.
According to question Caisse cannot download more than 1000 mb, so we will use less than towards equation.
It will be as under:
85x+4y<1000.
Hence if Caisse can download a maximum of 1000 mb of songs or movies then the inequality that represents the number of movies and songs that Caisse downloads each month is 85x+4y<1000.
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Solve for y.......
[tex]6 = 2(y + 2)[/tex]
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
y = 1[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
[tex] \qquad❖ \: \sf \:6 = 2(y + 2)[/tex]
[tex] \qquad❖ \: \sf \:(y + 2) = \cfrac{6}{2} [/tex]
[tex] \qquad❖ \: \sf \:y + 2 = 3[/tex]
[tex] \qquad❖ \: \sf \:y = 3 - 2[/tex]
[tex] \qquad❖ \: \sf \:y = 1[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
Value of y = 112. The base of a triangle with an area of 36 squared inches is 4.2 inches. What is the area of a similar
triangle whose base measures 5.6 inches?
The 4.2 inches base length and 36 in.² area of the given triangle and the 5.6 inches base length of the similar triangle gives the area of the similar triangle as 64 square inches
Which method can be used to find the area of the similar triangle given the dimensions?Area of a triangle = (Base length × Height)/2
Area of the given triangle = 36 in.²
Base length of the given triangle = 4.2 inches
Base length of the similar triangle = 5.6 inches
Therefore;
Area of the given triangle = (Base length × Height)/2
Which gives;
36 = (4.2 × h)/2
Where;
h = Height of the given triangle
36 × 2 = 4.2 × h
[tex]h = \mathbf{\frac{36 \times 2}{4.2}} = 17 \frac{1}{7} [/tex]
Height of the given triangle, h = 17+ 1/7
The ratio of corresponding sides of similar triangles are the same, which gives;
[tex] \frac{5.6}{4.2} = \frac{h'}{17 \frac{1}{7}} [/tex]
Where;
h' = The height of the similar triangle
Which gives;
[tex] h' = \frac{5.6}{4.2} \times 17 \frac{1}{7} = 22 \frac{6}{7} [/tex]
The area, A', of the similar triangle is therefore;
[tex] A' = \frac{1}{2} \times 5.6 \times 22 \frac{6}{7} = 64 [/tex]
The area of the similar triangle A' = 64 in.²The area can also be obtained using the scale factor of area as follows;
(4.2/5.6)² = 36/A'Which gives;
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Use the midpoint rule with the given value of n to approximate the integral. (Round your answer to four decimal places.)
16
0
sin
x
dx, n = 4
Split up [0, 16] into 4 equally-spaced subintervals of length [tex]\frac{16-0}4=4[/tex],
[0, 16] = [0, 4] U [4, 8] U [8, 12] U [12, 16]
with midpoints 2, 6, 10, and 14, respectively.
Then with the midpoint rule, we approximate the integral to be about
[tex]\displaystyle \int_0^{16} \sin(\sqrt x) \, dx \approx 4 \left(\sin(\sqrt2) + \sin(\sqrt6) + \sin(\sqrt{10}) + \sin(\sqrt{14})\right) \approx \boxed{4.1622}[/tex]
Miriam charges $5 per trip for deliveries plus $0.50 per mile, If x= the number of miles
Miriam drives for a trip and y = the total cost for a trip, which of these ordered pairs is a
solution to the equation that describes this situation? (1 Point)
(10, 10)
(2,7)
(12, 12)
(5, 6.5)
Answer:
(10,10)
Step-by-step explanation:
y = .5x + 5
If you put in 10 for x, we get 10 for y.
y = .5(10) + 5
y =5 + 5
y = 10
When x is 10, y is 10 (10,10)
Relate ratios in right triangles
Consider right triangle ADEF below. Which Expressions are equivalent to cos(E)?
Answer:
B
Step-by-step explanation:
Cos is the adjacent side over the hypotenuse. The adjacent side to <E is side ED. The hypotenuse is side EF. ED/EF. They do not go right out and give you this choice, but you see that B says the same thing.
Evaluate 3x² - 4xy + 2y² - 1 for x = - 3 and y = 5
Answer:
[tex]3x^{2} - 4xy + 2y { }^{2} - 1 \\ 3 \times ( - 3) { }^{2} - 4 \times ( - 3) \times 5 + 2 \times 5 {}^{2} - 1 \\ (3 \times 9) - ( - 60) + 50 - 1 \\ 27 + 60 + 50 - 1 \\ 165 [/tex]
Answer: 136
Substitute -3 for x and 5 for y.
[tex]3x^2 - 4xy + 2y^2 - 1[/tex]
[tex]3(-3)^2-4(-3)(5)+2(5)^2-1[/tex]
[tex]3(9)-4(-15)+2(25)-1[/tex]
[tex]27+60+50-1[/tex]
[tex]87+50-1[/tex]
[tex]137-1[/tex]
[tex]136[/tex]
hope this helped!
