What is the maximum number of pants per employee that can be washed each week? (2 points)

6. What is the maximum number of chef coats per employee that can be washed

each week? (2 points)

7. What is the maximum total number of items per employee that can be washed in a week? (2 points)

Answer:

12 m

Step-by-step explanation:

Well, imagine you got this nice room. How can it reach the other corner? It has to go along the 3 dimensions. So the shortest path would be: 5 + 4 + 3  12m

Answer:

3 + √(41) = 9.4 m (nearest tenth)

Step-by-step explanation:

The room can be modeled as a rectangular prism with:

If the ant is at the top of a corner of a room and crawls to the opposite bottom corner of the room, the shortest distance will be to travel down one vertical edge of the room then to travel the diagonal of the floor of the room (or to travel the diagonal of the ceiling and then one vertical edge).

Vertical edge = height of room = 3m

The diagonal of the floor (or ceiling) is the hypotenuse of a right triangle with legs of the width and length.  Therefore, to find the diagonal, use Pythagoras Theorem.

Pythagoras Theorem

[tex]a^2+b^2=c^2[/tex]

where:

Given:

Substitute the given values into the formula and solve for c:

[tex]\implies 4^2+5^2=c^2[/tex]

[tex]\implies c^2=41[/tex]

[tex]\implies c=\sqrt{41}[/tex]

Therefore, the shortest distance the ant can travel is:

⇒ 3 + √(41) = 9.4 m (nearest tenth)

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The principal amount that must be deposited as a lump sum amount is = $16,666.7

The simple interest amount = $20,000

The interest rate = 12%

The time that is given= 10 years

Therefore the principle amount =?

Using the simple interest formula;

SI= P×T×R/100

Make P the subject of formula,

P = SI ×100/T×R

P= 20,000×100/10×12

P= 2,000,000/120

P= $16,666.7

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Using the formula for a z-distribution confidence interval of proportions, he also needs to know the confidence level.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

Of these 3 itens, the problem states that he knows the sample size and the sample proportion, hence he needs to know z to determine the confidence interval. z depends on the confidence level, which is the remaining parameter.

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Answer:

A

Step-by-step explanation:

the side opposite of the angle is related to the size of this angle. Smaller angles have less space for the line to "spread out," so it will be shorter. Vice versa, bigger angles will have opposite sides longer because of more space.

I assume the given series is

[tex]\displaystyle 2 + \frac4{2^2} + \frac8{3^2} + \frac{16}{4^2} + \cdots = \frac{2^1}{1^2} + \frac{2^2}{2^2} + \frac{2^3}{3^2} + \frac{2^4}{4^2} + \cdots = \sum_{n=1}^\infty \frac{2^n}{n^2}[/tex]

By the ratio test, the series diverges, since

[tex]\displaystyle \lim_{n\to\infty} \left|\frac{2^{n+1}}{(n+1)^2} \cdot \frac{n^2}{2^n}\right| = 2 \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = 2 > 1[/tex]

Based on the information given about the temperature, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation.

From the information given, it van be seen that Daniela recorded the low temperatures during the school day last week and this week and her results are shown in the table.

Here, she didn't find the difference between the today and last week means. She just put the mean as a whole.

Therefore, Daniela made her error on step 3 because it says: "Find the ratio of the differences of the means compared to the mean absolute deviation. This was the error.

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The solution for the inequality given exists x > -11/10. The inequality contains an infinite number of solutions as long as it is greater than -11/10.

Given: 4(2 – x) > –2x – 3(4x + 1)

The inequality can be simplified to

8 - 4x > -14x - 3

subtract 8 from both sides of the equation, and we get

8 - 4x - 8 > -14x - 3 - 8

- 4x > -14x - 11

Add 14x from both sides

- 4x + 14x > -14x - 11 + 14x

10x > - 11

x > - 11/10

The solution for the inequality given exists x > -11/10. This means that any number greater than -11/10 exists as a solution to the inequality given. The inequality contains an infinite number of solutions as long as it is greater than -11/10.

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Answer:    C,E

Step-by-step explanation:

you did the work

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}[/tex]

❍ Arrange the given data in order either in ascending order or descending order.

2, 3, 4, 7, 9, 11

❍ Number of terms in data [n] = 6 which is even.

As we know,

[tex]\star \: \sf Median_{(when \: n \: is \: even)} = {\underline{\boxed{\sf{\purple{ \dfrac{ { \bigg (\dfrac{n}{2} \bigg)}^{th}term +{ \bigg( \dfrac{n}{2} + 1 \bigg)}^{th} term } {2} }}}}}[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ { \bigg (\dfrac{6}{2} \bigg)}^{th}term +{ \bigg( \dfrac{6}{2} + 1 \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \dfrac{6 + 2}{2} \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \cancel{ \dfrac{8}{2}} \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ 4}^{th} term } {2} }[/tex]

• Putting,

3rd term as 4 and the 4th term as 7.

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 4 + 7 } {2} }[/tex]

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 11} {2} }[/tex]

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} = \purple{5.5}[/tex]

[tex]\\[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\red{Solution:}}}}}[/tex]

❍ Arrange the given data in order either in ascending order or descending order.

1, 2, 3, 4, 5, 6, 7

❍ Number of terms in data [n] = 7 which is odd.

As we know,

[tex]\star \: \sf Median_{(when \: n \: is \: odd)} = {\underline{\boxed{\sf{\red{ { \bigg( \frac{n + 1}{2} \bigg)}^{th} term}}}}}[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} = {{ \bigg(\dfrac{ 7 + 1 } {2} \bigg) }}^{th} term[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} = { \bigg(\cancel{\dfrac{8}{2}} \bigg)}^{th} term[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} ={ 4}^{th} term[/tex]

• Putting,

4th term as 4.

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: odd)} = \red{ 4}[/tex]

[tex]\\[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\green{Solution:}}}}}[/tex]

The frequency distribution table for calculations of mean :

[tex]\begin{gathered}\begin{array}{|c|c|c|c|c|c|c|} \hline \rm x_{i} &\rm 3&\rm 1&\rm 7&\rm 4&\rm 6&\rm 2 \rm \\ \hline\rm f_{i} &\rm 4&\rm 6&\rm 2&\rm 2 & \rm 1&\rm 1 \\ \hline \rm f_{i}x_{i} &\rm 12&\rm 6&\rm 14&\rm 8&\rm 6&\rm \rm 2 \\ \hline \end{array} \\ \end{gathered} [/tex]

☆ Calculating the [tex]\sum f_{i}[/tex]

[tex] \implies 4 + 6 + 2 + 2 + 1 + 1[/tex]

[tex] \implies 16[/tex]

☆ Calculating the [tex]\sum f_{i}x_{i}[/tex]

[tex] \implies 12 + 6 + 14 + 8 + 6 + 2[/tex]

[tex]\implies 48[/tex]

As we know,

Mean by direct method :

[tex] \: \: \boxed{\green{{ { \overline{x} \: = \sf \dfrac{ \sum \: f_{i}x_{i}}{ \sum \: f_{i}}}}}}[/tex]

here,

• [tex]\sum f_{i}[/tex] = 16

• [tex]\sum f_{i}x_{i}[/tex] = 48

By putting the values we get,

[tex]\sf \longrightarrow \overline{x} \: = \: \dfrac{48}{16}[/tex]

[tex]\sf \longrightarrow \overline{x} \: = \green{3}[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Note\: :}}}}}}[/tex]

• Swipe to see the full answer.

[tex]\begin{gathered} {\underline{\rule{290pt}{3pt}}} \end{gathered}[/tex]

Answer:

12

Step-by-step explanation:

[tex]24=2^{3} \times 3 \\ \\ 36=2^{2} \times 3^{2} \\ \\ 96=2^{5} \times 3[/tex]

Hey there!

What is GCF (Greatest Common Factor)?

Basically, the GCF is the biggest number in a data set that all of your numbers share.

What are the factors of the numbers?

24:1, 2, 3, 4, 6, 8, 12, and 24

36: 1, 2, 3, 4, 6, 9, 12, 18, and 36

96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96

What are the like terms that the numbers share?

1, 2, 3, 4, 6, 8, and 12

What is the biggest number out of the like terms?

12

What is your number?

12

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

102 degrees

Step-by-step explanation:

Angles in a quadrilateral add to 360 degrees.

y = 360 - (120 + 85 + 53)

y = 360 - 258

y = 102 degrees

Using a quadratic regression equation, it is found that the prediction of volunteers in year 10 is of:

A. 47.

To find the equation, we need to insert the points (x,y) in the calculator.

In this problem, we have that the function initially increases, then it decreases, which means that it is a quadratic function. The points (x,y) to  be inserted into the calculator are given as follows:

(1, 20), (2,17), (3, 16), (4,16), (5,18), (6,21), (7,25), (8,31)

Inserting these points into the calculator, the prediction of y for a value of x is given as follows:

y = 0.702x^2 - 4.726x + 23.857

Hence, when x = 10, the prediction is:

y = 0.702 x 10² - 4.726 x 10 + 23.857

y = 47.

Hence option A is correct.

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The dollar gains depreciated relative to the pound when the price of pounds in dollars increases, for instance, from $1 = 1 pound to $2 = 1 pound.

Devaluation of a currency can take place in both absolute and relative terms. When the value of one currency declines in relation to the values of other currencies, this is referred to as a relative devaluation. For instance, the British pound sterling may be worth more today than it did yesterday in terms of US dollars.

A currency's value declines when compared to other currencies, which is known as currency depreciation. Political unrest, interest rate differences, weak economic fundamentals, and investor risk aversion are a few examples of the causes of currency devaluation.

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By using algebra properties and trigonometric formulas we find that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equivalent to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex].

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

[tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex]       Given.

[tex]\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}[/tex]      Subtraction between fractions with different denominator / (- 1) · a = - a.

[tex]\frac{2\cdot \sin x}{\cos^{2}x}[/tex]      Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

[tex]\frac{2\cdot \tan x}{\cos x}[/tex]      Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equal to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex]. Hence, the former expression is equivalent to the latter one.

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Answer:

30 degrees

Step-by-step explanation:

They are corresponding angles.

Answer: 30 degrees

Step-by-step explanation:

mangle8 and mangle 4 are corresponding angles meaning the angles are both the same.

Answer:

p(t) = 2950^3t

Step-by-step explanation:

I’m not sure if this is exactly what you wanted or not. Please let me know more info and I’ll write any more answers for this question in the comments. Have a great day!!

The region enclosed by the given curves are integrated with respect to x and the area is 4.2724 square units.

In this question,

The curves are y = 2/x, y = 2/x^2, x = 4

The diagram below shows the region enclosed by the given curves.

From the diagram, the limit of x is from 1 to 4.

The given curves are integrated with respect to x and the area is calculated as

[tex]A=\int\limits^4_1 {\frac{2}{x} } \, dx -\int\limits^4_1 {\frac{2}{x^{2} } } \, dx[/tex]

⇒ [tex]A=2[\int\limits^4_1 {\frac{1}{x} } \, dx -\int\limits^4_1 {\frac{1}{x^{2} } } \, dx][/tex]

⇒ [tex]A=2[\int\limits^4_1( {\frac{1}{x} } - {\frac{1}{x^{2} } } )\, dx][/tex]

⇒ [tex]A=2[lnx-\frac{1}{x} ] \limits^4_1[/tex]

⇒ [tex]A=2[(ln4-\frac{1}{4} )-(ln1-\frac{1}{1} )][/tex]

⇒ A = 2[(1.3862-0.25) - (0-1)]

⇒ A = 2[1.1362 + 1]

⇒ A = 2[2.1362]

⇒ A = 4.2724 square units.

Hence we can conclude that the region enclosed by the given curves are integrated with respect to x and the area is 4.2724 square units.

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Using the chord theorem, option C is the best solution since x = 5.

The four line segments that are created by two intersecting chords inside of a circle are explained by the chord theorem, sometimes referred to as the intersecting chords theorem, a statement in fundamental geometry. The products of the line segment lengths on each chord are equal, according to this assertion.

The value of x must be determined in order to answer the question.

We may determine the following using the chord property:

8*x = 4*10,

or, 8x = 40,

or, x = 40/8,

or x = 5.

Given that x = 5, option C is the best option according to the chord theorem.

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Answer: 5 games

Step-by-step explanation: A .500 record means that the soccer team won half of their games ( that's how I interpret it). Since they are going to play 30 games, they need to win half of 30 or 15 games to have that record. 15-10 = 5. So, they need to win 5 more games to have a .500 record.

The number of pieces of card stock which would result upon the process repetition is; 256 pieces.

According to the task content, it follows that since, there are 8 pieces of the 8 inches per side cards initially, the resulting number of cards after carrying out the process of cutting cards into half five, 5 times is;

No of cards = 8 (2)⁵

No. of cards = 256 pieces.

The size of each of the cards in discuss provided that all cuts will be made along and not across the longer edge is; 8 by 1/4 inches.

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Answer:

a. 1056 ft

b. 52.8 ft

Step-by-step explanation:

1 mile = 5280 feet

a.

[tex]\frac{1}{5} *5280 = 1056[/tex]

Therefore 1/5 of a mile is 1056 feet.

b.

[tex]\frac{1}{100} *5280=52.8[/tex]

Therefore 1/100 of a mile is 52.8 feet

Answer:

Step-by-step explanation: P(x 3), Q(7, -1) and PQ= 5 .

To Find :

The possible value of x.​

Solution :

We know, distance between two points in coordinate plane is given by :

Therefore, the possible value of x are 10 and 4.

Answer:

D.

Step-by-step explanation:

Answer: x^{3}(2x+9)

Step-by-step explanation:

Eliminate redundant parentheses:

(3x^{4}+3x^{3}+5x^{2})-1(x^{4}-6x^{3}+5x^{2})

3x^{4}+3x^{3}+5x^{2}-1(x^{4}-6x^{3}+5x^{2})

Distribute:

^{4}+3x^{3}+5x^{2}{-1(x^{4}-6x^{3}+5x^{2})}

3x^{4}+3x^{3}+5x^{2}

Combine like terms UNTIL YOU FIND ONE FACTOR

Answer:

Step-by-step explanation:

For missing hypotenuse: [tex]\sqrt({a^{2} + b^{2})[/tex]

Plug in the side lengths that are known to find the hypotenuse.

1. No, the angle is less than 18 degrees (closer to 15), so it is not safe

2. The length rounded to the nearest tenth is approximately 15.5 feet.

If for the first 150 miles of a trip, an car drives at v mph, for the next 200 miles, the car drives at (v+25) mph and the average speed of the whole trip is 35 mph, then the value of v will be 20mph (A).

Given Information:

Average speed = 35 mph

Total distance = 150 + 200 = 350 miles

For the first 150 miles of a trip, an car drives at v mph speed

⇒ Time, t1 = 150/v hrs

For the next 200 miles, the car drives at (v+25) mph speed

⇒ Time, t1 = 200 / (v+25) hrs

Now, the formula for average speed is given as,

Total distance / Total time

= [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex]

⇒ [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex] = 35 mph

[tex]\frac{350 v (v+25)}{150(v+25) + 200v}[/tex] = 35

[tex]\frac{350v^{2} + 8750v}{150v +3750 + 200v}[/tex] = 35

350v² + 8750v = 35 (350v + 3750)

v² + 25v = 35v + 375

v² - 10v = 375

v² - 10v - 375 = 0

Now, the above equation for speed can be written as,

v² - 20v + 15v - 375 = 0

v(v-20) + 15(v-20) = 0

(v-20) (v+15) = 0

v = 20

or v = -15

Since, speed is a scalar quantity, it can't be negative. Thus, v = 20 mph

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The expressions which demonstrates the identity property of multiplication is; 25(1) = 25 option B

Identity Property of Multiplication states that any number multiplied by 1 does not change, that is, it is constant or remains the same

Check all options

25(0) = 25

0 = 25

Not true

25(1) = 25

25 = 25

True (identity property of multiplication holds)

25 + 0 = 25

25 = 25

True (Not identity property of multiplication)

25 + 1 = 25

26 = 25

Not true

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Step-by-step explanation:

the mean value is the sum of all data points divided by the number of data points.

first we have 7 tests and their mean value :

(t1 + t2 + t3 + t4 + t5 + t6 + t7) / 7 = 54

that means

(t1 + t2 + t3 + t4 + t5 + t6 + t7) = 54 × 7 = 378

in order for the mean value to be at least 60% after 8 tests, we need to add a t8, so that

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) = 60 × 8 = 480

because only then we have

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) / 8 = 60

and the student passes.

so,

(t1 + t2 + t3 + t4 + t5 + t6 + t7) + t8 = 480

378 + t8 = 480

t8 = 480 - 378 = 102%

the student would have to achieve 102% on the 8th test.

which would be normally impossible, but maybe the tests involve some bonus points.

The volume of the cylinder is [tex]384\pi \sqrt{3cm }^{2}[/tex].

Body of the diagonal=24cm.

Assume the length of the side= a.

[tex]a^{2} +(a^{2} +a^{2} )=24^{2}[/tex]

                   [tex]a=\sqrt[8]{3} cm[/tex]

The area of the cylinder base=[tex]\pi R^{2}[/tex]

                                                =[tex]\pi (\frac{1}{2} \sqrt[8]{3} )^{2}[/tex]

                                                =[tex]48cm^{2}[/tex]

The high of the cylinder is[tex]\sqrt[8]{3}cm[/tex]

The volume of the cylinder:

=s*h

=[tex]48\pi *\sqrt[8]{3}[/tex]

=[tex]384\pi \sqrt{3} cm^{3}[/tex]

The volume of the cylinder is [tex]384\pi \sqrt{3cm }^{2}[/tex].

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The biggest possible volume of the cylinder will be [tex]2089.497\hspace{1mm}\text{cm}^3[/tex].

Now, given that the diagonal of the cube is [tex]24[/tex] cm. So, if the side length of the cube is [tex]x[/tex] cm, then we must have

[tex]x\sqrt{3}=24\\\Longrightarrow x=\frac{24}{\sqrt{3}}\\\Longrightarrow x=8\sqrt{3}[/tex]

Thus, the side length of the cube is [tex]8\sqrt{3}[/tex] cm.

So, the height of the cylinder with maximum volume will be [tex]h=8\sqrt{3}[/tex] cm and the diameter will be [tex]d=8\sqrt{3}[/tex]cm i.e. the radius will be [tex]r=\frac{d}{2}=\frac{8\sqrt{3}}{2}=4\sqrt{3}[/tex] cm.

So, using the above formula for the volume of a cylinder, we get

[tex]V=\pi r^{2}h=\pi\times (4\sqrt{3})^2\times 8\sqrt{3}=2089.497\hspace{1mm}\text{cm}^3[/tex].

Therefore, the biggest possible volume of the cylinder will be [tex]2089.497\hspace{1mm}\text{cm}^3[/tex].

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