(c) The perimeter of a rectangle with length 2r cm and width 5 m is 14 m.

Answer:

5.3 pounds

Step-by-step explanation:

1.2 plus 1.8 is 3 pounds

then you add 3 pounds plus 2.3 lbs and you get

5.3 pounds

Answer:

5.3

Step-by-step explanation:

If you add how much Mitchell bought (1.2) and how much his friends bought (2.3), (1.8) therefore the answer is 5.0 or rounded is just 5

Answer:

14 units is the answer

Step-by-step explanation:

^_^^_^^_^^_^^_^

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Answer:

[tex] a_n = 2n^2 + n + 1 [/tex]

Step-by-step explanation:

4, 11, 22, 37, 56

11 - 4 = 7

22 - 11 = 11

37 - 22 = 15

56 - 37 = 19

After the first difference, 11 - 4 = 7, each difference is 4 more than the previous difference.

Difference of differences:

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

Since we need the difference of differences to find a constant, this must be a second degree function.

[tex] a_1 = 4 = 2^2 + 1(0)[/tex]

[tex] a_2 = 11 = 3^2 + 2 = 3^2 + 2(1) [/tex]

[tex] a_3 = 22 = 4^2 + 6 = 4^2 + 3(2) [/tex]

[tex] a_4 = 37 = 5^2 + 12 = 5^2 + 4(3) [/tex]

[tex]a_5 = 56 = 6^2 + 20 = 6^2 + 5(4)[/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = n^2 + 2n + 1 + n^2 - n [/tex]

[tex] a_n = 2n^2 + n + 1 [/tex]

Answer:

Step-by-step explanation:

Well lets start with

(3*sqrt 2+ 1)(2*sqrt 3-4)

Lets multiply everything in the second parenthesis by 3*sqrt 2

2 sqrt 3 * 3 sqrt 2 =  6 sqrt 6

-4*3 sqrt 2 =  -12 sqrt 2

Now lets multiply everything by 1

1*2 sqrt 3 = 2 sqrt 3

1*-4 = -4

we have

-4  -12 [tex]\sqrt{2}[/tex]  +  6 [tex]\sqrt{6}[/tex]  + 2 [tex]\sqrt{3}[/tex]  as the awnser to problem A

Now lets do problem b

We can start by multiplying everything in the second parenthesis by 2

2*5=10

2*-1 *sqrt 3 = -2 sqrt 3

Now multiply everything in the second parenthesis by 2sqrt3

2sqrt 3 * 5 = 10 sqrt 3

2 sqrt 3 * -1* sqrt3 =  -6

Our final awnser is

10-6 +10 sqrt 3 -2 sqrt 3 ->  4+ 8 [tex]\sqrt{3}[/tex]

The awnser to question B is 4+ 8 [tex]\sqrt{3}[/tex]

pls give brainliest

Answer:

Step-by-step explanation:

The first line has slope of a/b and the second one has slope of m/n.

As an ≠ bm ⇒ a.b ≠ m/n, the slopes are different.

Since the slopes are different the lines are not parallel, hence they intersect at one point.

This means there is one solution only.

ax + by = c and mx + ny = d and an # bm then these simultaneous equations have Only one common solution.

[tex]\sf{ }[/tex] [tex]\sf{ }[/tex]

Answer:

AC is greater than BC

Step-by-step explanation:

First, we know that the angle of a straight line is 180°, so angle B as a whole is equal to 180 degrees. Therefore, angle YBC + angle ABC = 180 degrees. As angle YBC is a right angle, signified by the small square on the angle, it is 90 degrees. Therefore,

90 degrees + angle ABC = 180 degrees

subtract 90 degrees from both sides to isolate angle ABC

angle ABC = 90 degrees

Therefore, as angle ABC is equal to 90 degrees, and a right angle is 90 degrees, triangle ABC has a right angle, making it a right triangle.

In a right triangle, using the Pythagorean Theorem, the square of the side opposite the right angle is equal to the sum of the squares of the other side. Since side AC is opposite the right angle, we can say that

AC² = AB² + BC²

As the length of a side has to be greater than 0, we can say that

AC² = AB² + BC²

AB² > 0

AC² > BC²

square root both sides

AC > BC

Therefore, AC is greater than BC

Answer:

13

Step-by-step explanation:

i just know

Answer:

,

Step-by-step explanation:

,

Answer:

x = number of students tickets = 1,000

y = number of adults tickets = 250

Step-by-step explanation:

Let

x = number of students tickets

y = number of adults tickets

x + y = 1,250 (1)

2x + 3y = 2,750 (2)

Multiply (1) by 2

x + y = 1,250 (1) * 2

2x + 2y = 2,500 (3)

2x + 3y = 2,750 (2)

Subtract (3) from (2) to eliminate x

3y - 2y = 2,750 - 2,500

y = 250

Substitute y = 250 into (1)

x + y = 1,250

x + 250 = 1,250

x = 1,250 - 250

x = 1,000

x = number of students tickets = 1,000

y = number of adults tickets = 250

Answer:

2x-25<89

x<57

Step-by-step explanation:

2x-25<89

2x<89+25

2x<114

Divide by 2...

x<57

Hope this helped! Please mark brainliest :)

Answer:

Represent 1/2 by covering 50 squares.

Step-by-step explanation:

There are 100 squares in a 10-by-10 grid.

1/2 of 100 is 50, so you should cover 50 squares out of 100 squares.

Answer:

t = D/r

Step-by-step explanation:

you rearrange the equation so that is the subject. when you bring something over the equal sign, it reverses the function so D = r×t becomes t = D/r

Answer:

P [ X ≤  9.8 ]  = 0.1335

Step-by-step explanation:

P [ X ≤  9.8 ]  =  [ ( 9.8  - 10.2 )/1.8√25 ]

P [ X ≤  9.8 ]  =  - 0.4*5/1.8

P [ X ≤  9.8 ]  = - 2 / 1.8

P [ X ≤  9.8 ]  =  - 1.11

From z- table we get:  α  =  0.1335

P [ X ≤  9.8 ]  = 0.1335   or   P [ X ≤  9.8 ]  = 0.1335

Answer:

radical is sqrt we find 180 sqrt root

Step-by-step explanation:

first we write sqrt 180

sqrt 180 = ?

we can choose first two letters

18 are two letters

4^2 + 2 = 18

so first + third number choose

4 , 2 are number choose

4 + 2 sqrt (4+2-1)

6 sqrt 5

sqrt 180 = 6sqrt 5

Answer:

800 M &Ms

Step-by-step explanation:

First, we can operate on the estimate that the proportion of M&Ms of the sample is equal to the proportion of M&Ms in the giant bag.

Therefore,

number of orange M&Ms in sample / sample size = number of orange M&Ms in bag / bag size

3/50 = 48 / bag size

multiply both sides by 50 to remove a denominator

3  = 48 * 50 / bag size

multiply both sides by bag size to remove the other denominator

3 * bag size = 48 * 50

divide both sides by 3 to isolate bag size

bag size = 48 * 50 / 3

bag size  = 800 M &Ms

Answer:

9

Step-by-step explanation:

First you would need to subtract all the irrelevant students.

So, subtract 4 from 36, which is 34.

34 - (10 + 15) =

34 - 25 =

9

The answer is 9 pupils.

Step-by-step explanation:

went to a calculator

it said

Angle ∠A = 55.543°

Angle ∠B = 78.28°

Angle ∠C = 46.177

Answer:

[tex]\displaystyle x=\frac{-1}{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

x² + x + 1/4 = 0

↓ Compare to Standard Form

a = 1, b = 1, c = 1/4

Step 2: Solve for x

Answer:

The one with 6.4 ounces or multiple that are equivalent to that

Step-by-step explanation:

4/10 of a pound is equivalent to 2/5 of a pound. 2/5 of a pound is 6.4 ounces.

5 + (1 + 1)3 × 2

5 + (2) 3 x 2

5 + 6 x 2

5 + 12

17

Answer:

17

Step-by-step explanation:

5 + (1+1)3*2

1+1= 2

5+2*3*2

3*2= 6

6*2= 12

12+5=17

Answer:

(12/39) * (12/39) or 16/169

Step-by-step explanation:

Answer:

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{2.25}{\sqrt{12}} = 1.67[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 28 - 1.67 = 26.33 kg/d.

The upper end of the interval is the sample mean added to M. So it is 28 + 1.67 = 29.67 kg/d.

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

Answer:

8(X^2+1)

Step-by-step explanation:

(X²+3)²-(X²-1)

(X²+3)(X²+3)-(X²-1)(X²-1)

X⁴+3X²+3X²+9-(X⁴-X²-X²+1)

X⁴+6X²+9-(X⁴-2X²+1)

X⁴+6X²+9-X⁴+2X²-1

8X²+8

Answer:

[tex]{ \tt{sum = \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 = \frac{a(r {}^{2 - 1} )}{2 - 1} \\ { \bf{27 = ar - - - (i)}} \\ \\ 54 = \frac{a( {r}^{3 - 1} )}{3 - 1} \\ { \bf{108 = a {r}^{2} - - - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r = \frac{108}{27} \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term = \frac{27}{4} }}[/tex]

Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

16a + 4b = -1

Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

4a - 1 - a = -1/4

3a - 1 = -1/4

3a = 1 - 1/4

3a = 3/4

a = 1/4

b = -1 - 1/4

b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

the way to do these recurring decimals is by firstly separating the repeating part or recurring part and then multiply it by some power of 10 so we move it to the left, lemme show

[tex]3.5\overline{41}\implies \cfrac{35.\overline{41}}{10}\qquad \stackrel{\textit{say that the repe}\textit{ating part is }~\hfill }{x = \overline{0.41}\qquad \qquad \textit{so that }35.\overline{41}=35+\overline{0.41}=35+x}[/tex]

now, let's multiply that repeating part by some power of 10 that moves the 41 to the left, well, we have two repeating decimals, 4 and 1, so let's use two zeros, namely 100 or 10², thus

[tex]100\cdot x = 41.\overline{41}\implies 100x - 41+\overline{0.41}\implies 100x = 41+x\implies 99x=41 \\\\\\ \boxed{x =\cfrac{41}{99}}\qquad \qquad \textit{so then we can say that}~~\cfrac{35.\overline{41}}{10}\implies \cfrac{35+\frac{41}{99}}{10} \\\\\\ \cfrac{~~\frac{3506}{99}~~}{10}\implies \cfrac{~~\frac{3506}{99}~~}{\frac{10}{1}}\implies \cfrac{3506}{99}\cdot \cfrac{1}{10}\implies \cfrac{3506}{990}\implies \blacktriangleright \stackrel{\textit{which simplifies to}}{\cfrac{1753}{495}} \blacktriangleleft[/tex]

Answer:

a) ∠ADB is 55°

b) ∠ABD is 45°

Step-by-step explanation:

a) In the cyclic quadrilateral ABCD, we have;

Segment AB = Segment BC

∠ABC = 70°

Therefore, ∠ADC = 180° - 70° = 110° (Opposite angles are supplementary)

∠ADC + ∠CDP = 180° (Sum of angles on a straight line)

∴ ∠CDP = 180° - ∠ADC

∠CDP = 180° - 110° = 70°

∠DCP = 180° - 70° - 30° = 80°, (Angle sum property)

Similar to ∠DCP = ∠DAB = 80° (Exterior angle of a cyclic quadrilateral)

∠CAB = ∠ACB = (180° - 70°)/2 = 55° (Base angles of isosceles triangle ΔABC)

∠ADB = ∠ACB = 55° (Inscribed angle of a circle subtended by the same chord)

∠ADB = 55°

b) ∠ABD = 180° - ∠DAB - ∠ADB

∴ ∠ABD = 180° - 55° - 80° = 45°

∠ABD = 45°

Answer:

1/2

8

Step-by-step explanation:

When its talking about the result or output, look at the range, and then follow the line(s) back to the number(s) in the domain. Do the opposite when it's talking about the function of a certain number, e.g. f(4).