The concentration of [ Hy³] = 4.861 *28⁻²³
The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.
Given,
Molarity of VoSo4 ,M = 0.02M
Vol of VoSo4 , V = 10 ml
Molarity of EDTA = 0.02 M
vol of EDTA = 9.10 ml = 0.0091 L
& 10 ml of buffer with pH =4
NOW,
no. of moles of EDTA = molarity * Volume (L)
= 0.02 M * 0.0091 L
= 182 * 10^-6 moles
= 1.82 * 10^-4 moles
Now,
∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]
[ Y^3-] = ∝ Y^3- * moles of EDTA
Given,
at pH = 4, ∝ Y^3- = 3*10^-9
∴ ∝ Y^3- = 3*10^-9
[ Y^3-] = 3*10^-9 * 1.82 * 10^-4
= 5.46 * 10^-13
Now, K f = [H2Y^2-]/[vo^2+][y3-]
[vo^2+] = 18.7
[H2Y2-] = K f * [ v o+][Y^2-]
[H2Y2] = 3.762 * 10^-13
[ HY^3-] = 4.8 * 10^-23
So, the concentration of the [ HY^3-] is 4.8 * 10^-23
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using the equation 40kj+ 2so3= 2so2+02, of so3=0.491, so2=0.17, 02=0.701, find Keq
The equilibrium constant, Keq for the reaction, given the data from the question is 0.084
What is equilibrium constant?The equilibrium constant, Keq for a reaction is the ratio of the concentration of the products raised to their coefficients to the ratio of the concentration of the reactants raised to their coefficients. For example, the equilibrium constant for the reaction nA + mB <=> eC can be obtained as follow
Keq = [C]^e / [A]^n × [B]^m
How to determine the equilibrium constant for the reaction Equation: 40 KJ + 2SO₃ <=> 2SO₂ + O₂[SO₃] = 0.491 M[SO₂] = 0.17 M[O₂] = 0.701 MEquilibrium constant (Keq) =?The equilibrium constant, Keq for the above reaction can be obtained as illustrated below:
Keq = [SO₂]^2 × [O₂] / [SO₃]^2
Keq = (0.17)^2 × (0.701) / (0.491)^2
Keq = 0.084
Thus, the equilibrium constant, Keq for the reaction is 0.084
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Consider these steps involved in bacterial reproduction.
X: Cell wall and membrane divide and separate.
Y: Genetic material is replicated.
Z: Two independent cells form.
Which list shows the correct order of steps of when a single cell reproduces?
X → Y → Z
Z → X → Y
Y → X → Z
Y → Z → X
The steps in which a bacterial cell reproduces is Y → X → Z Option C
What is reproduction?The term reproduction refers to the process by which new organisms appear. We know that reproduction must involve the fusion of male and female gametes to yield an offspring. The fusion of the male and female gametes can be described by genetics.
Now we know that bacteria are single cell organisms and that they tend to reproduce by cell division or as-exually. This implies that the fusion of gametes do not occur here.
Hence, the correct order for the steps that are involved in the reproduction of bacterial cells are;
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Answer:
C. Y X Z
Explanation:
Rapid breathing pays back the __________ debt by breaking down lactic acid. creatine glycogen oxygen glucose
Rapid breathing pays back the oxygen debt by breaking down lactic acid. creatine glycogen oxygen glucose.
Even after exercise must be finished, the "oxygen debt" could be paid when laborious breathing and an elevated heart rate were needed to eliminate lactic acid and replenish depleted energy stores.
The oxygen debt would be the quantity of oxygen needed to replenish the body's oxygen stores and remove the lactic acid. It can take anywhere between a few hours for little activity and several days after just a marathon when an individual has been exercising to start repaying an oxygen debt.
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The process where a substance goes directly from a solid state to a gaseous form is known as:____.
Answer:
sublimation because it's has changed from solid to gaseous
Two significance of melting point
The significance of melting points are
it gives us a idea about inter molecular force which binds the particles together.at melting point the solid and liquid states exist in equilibrium.What is melting point?The melting point is the temperature at which a given substance change its physical state from solid to liquid. At this point solids and liquids exist at equilibrium. Melting point of a substance depends on pressure. The melting point of ice increases when pressure decreases. Melting point of a substance decreases by the presence of impurities in it. so you increase or decrease the melting point on any substance by adding more impurities. Ionic bonds, shape and size of molecules are some other factors that affect the melting point.
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Two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas. Which of the following
equations correctly describes this reaction?
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
Select one:
O a. A
O b. B
OC. C
O d. D
Answer:
D
Explanation:
Mercury is Hg. Most of these reaction do not involve Hg. Only D correctly shows a balanced equation with mercury (Hg).
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?
The volume of 0. 250 mole sample of [tex]H_{2}[/tex] gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is 3.71 L.
Calculation,
According to ideal gas equation which is known as ideal gas law,
PV =n RT
P is the pressure of the hydrogen gas = 1.7 atmVis the volume of the hydrogen gas = ?n is the number of the hydrogen gas = 0.25 moleR is the universal gas constant = 0.082 atm L/mole KT is the temperature of the sample = 35°C = 35 + 273 = 308 KBy putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,
1.7 atm×V = 0.25 mole ×0.082 × 208 K
V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm
V = 3.71 L
So, volume of the sample of the hydrogen gas occupy is 3.71 L.
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What does summarizing involve?
A. Detailing every aspect of what was just read
B. Creating mental images of each idea in the text
C. Inferring the relationship between two characters in the text D. Stating the point of the text in a few brief statements
Answer:
The correct answer is D. Stating the point of the text in a few brief statements.
Explanation:
The whole idea of a summary is to effectively restate the text by only focusing on the main points.
Hope this helps:) Good luck!
Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure between the locations. Diffusion occurs until ___________
Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.
What is the gas exchange in bloodstream?The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.
The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.
In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.
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Which pair of aqueous solutions can create a buffer solution if present in the appropriate concentrations?.
HF and NaF - If the right concentrations of aqueous solutions are present, they can produce a buffer solution.
What are buffer solutions and how do they differ?The two main categories of buffers are acidic buffer solutions and alkaline buffer solutions. Acidic buffers are solutions that contain a weak acid and one of its salts and have a pH below 7. For instance, a buffer solution with a pH of roughly 4.75 is made of acetic acid and sodium acetate.Describe buffer solution via an example.When a weak acid or a weak base is applied in modest amounts, buffer solutions withstand the pH shift. A buffer made of a weak acid and its salt is an example. It is a solution of acetic acid and sodium acetate CH3COOH + CH3COONa.learn more about buffer solutions here
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Why is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear explicitly in any reaction because?
Succinate dehydrogenase is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear.
The respiratory complex II, also known as succinate dehydrogenase (SDH), succinate-coenzyme Q reductase (SQR), or SDH, is an enzyme complex that is present in the inner mitochondrial membrane of eukaryotic and numerous bacterial cells. SDH converts succinate to fumarate as part of the citric acid cycle. SDH shares structural similarities with fumarate reductase, an enzyme that catalyzes the reverse process during anaerobic respiration in bacteria. (1997, Hagerhall). Succinic semialdehyde dehydrogenase impairment is brought on by ALDH5A1 gene mutations. Instructions for creating the succinic semialdehyde dehydrogenase enzyme are found in the ALDH5A1 gene.
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How many fe(ii) ions are there in 20. 0 g of feso4 (molar mass=151. 9 g/mol) ? avogadro number=6. 0225x 1023
20 g of [tex]FeSO_4[/tex] contains [tex]7.94 \times 10^{22}[/tex] ions of [tex]Fe^2^+[/tex]
What is Mole?A mole is a unit to measure an amount of any substance which contains as many elementary particles as there in 12 g of Carbon 12.
A mole contains [tex]6.02214 \times 10^{23}[/tex] particles and this fixed number is called Avogadro’s number.
No. of moles is given by,
[tex]n =\frac{m}{M}[/tex]
where m = Given mass in grams
M = Molar mass
Here,
[tex]FeSO_4 \rightarrow Fe^2^+ + SO_4^2^-[/tex]
No. of moles of [tex]FeSO_4[/tex] = [tex]\frac{20g}{151.9gmol^-^1}[/tex] = 0.132 moles
No. of molecules of [tex]FeSO_4[/tex] = 0.132 x 6.022 x [tex]10^2^3[/tex] = 7.94 x [tex]10^2^2[/tex]
No. of molecules of [tex]FeSO_4[/tex] = no. of ions of [tex]Fe^2^+[/tex] = no of ions of [tex]SO_4^2^-[/tex]
Thus, no. of ions [tex]Fe^2^+[/tex] in 20 g of [tex]FeSO_4[/tex] is 7.94 x [tex]10^2^2[/tex]
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What volume of O2 is produced when 28. 5 g of hydrogen peroxide (H2O2) decomposes to form water and oxygen at 150°C and 2. 0 atm?
0.42 mol 7.3 L volume of O2 is produced when 28. 5 g of hydrogen peroxide (H2O2) decomposes to form water and oxygen at 150°C and 2. 0 atm
A moderate antiseptic used topically to treat minor burns, scrapes, and cuts is hydrogen peroxide. As a mouth rinse, it can be used to assist clear mucus or soothe minor oral irritation (caused, for example, by canker/cold sores, or gingivitis).
Stronger than chlorine, chlorine dioxide, and potassium permanganate, hydrogen peroxide is a potent oxidant.
Human blood is exposed to a hydrogen peroxide solution, which causes the peroxide to break down and release oxygen. Before transfusion, this process has been utilized to oxygenate banked blood.
When hydrogen peroxide comes into contact with skin, a chemical process takes place that causes hydrogen peroxide to turn white. When the solution oxidizes, oxygen bubbles that arise give the mixture a white, foamy appearance.
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1. Convert these from plus-minus notation to significant figures notation.
a. 65.316 mL + 0.05 mL.
b. 5.2 cm + 0.1 cm
c. 1.8642 km ± 0.22 km
d. 16.8°C ±1°C
Answer: a. 65.37 mL
b. 5.3 cm
c. 2.08 km (plus) or 1.64 km (minus)
d. 18°C (plus) or 16°C (minus)
Explanation:
The way significant figures work when you're adding or subtracting, is you go to the answer with the least amount of decimal places. Take a. for example; you have 65.316 (3 places after the decimal) and 0.05 (2 places after the decimal place). Based off of this, you would round your answer to two places after the decimal. And when you have a whole number, like in d. you round to the nearest whole number, since there aren't any decimal places to round your answer to.
When hydrochloric acid reacts with magnesium metal, hydro- gen gas and aqueous magnesium chloride are produced. what volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium?
The volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.
Chemical equation:Mg + 2HCl -----MgCl2 + H2
Given,
Molar mass of Mg = 24g/mol
Mole = Given mass/ Molar mass
Mole= 3/24
= 0.125 mol
From the given equation we get to know that
Mol ratio of Mg and HCl is 1:2.
Therefore,
mol of HCl = (2/1) × mol of Mg
=2× 0.125
= 0.25
Molarity = m× V
= M/m
= 5/0.25
= 20L
Thus, we find that the volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.
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What is the molality of a nh₄no₃ solution of 125 g of nh₄no₃ (80.0434 g/mol) in 275 g of water (18.0153 g/mol)?
The molality of the given solution is 5.67 mol/kg
You may calculate the molality of a solution to find out how many moles of solute you obtain per kilogram of solvent. Mol/kg is a typical molality measurement unit in chemistry. One molal is another way to refer to a solution with a concentration of 1 mol/kg. Molar mass must be represented in kg/mol rather than the more common g/mol or kg/kmol when using the unit mol/kg. The formula is as follows:
Molality = [tex]\frac{moles of solute}{kilogram of solvent}[/tex]
First we need to find moles of solute ;
moles of solutes = [tex]\frac{given mass}{molecular mass}[/tex]
moles = 125 / 80.0434
moles of solute = 1.56
Now, molality is ;
molality = 1.56 / 0.275
molality = 5.67 mol/kg
Therefore, The molality of the given solution is 5.67 mol/kg
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There are 4 gleeks in a glook, 7 glooks in a gluck, and 5 glucks in a glack. how many gleeks are in 4 glacks?
Answer:
9
Explanation:
because there are 4 gleeks and 5 Gluck's in a glack
If the concentration of red dye #40 in the original syrup is 4. 68 x 10-3 m, what is its concentration in dilution #3?.
Concentration difficulties can be caused by medical, cognitive, or psychological problems or may be related to sleep disorders or medications, Psychological conditions
What is Concentration?Concentration means focused attention, and it has many uses and benefits. It assists in studying, enables faster comprehension, improves memory, helps in focusing on a task, job, or goal, and enables you to ignore meaningless and irrelevant thoughts.Taking very small breaks by refocusing your attention elsewhere can dramatically improve mental concentration after that. The next time you are working on a project, take a break when you begin to feel stuck. Move around, talk to someone, or even switch to a different type of task.Concentration difficulties can be caused by medical, cognitive, or psychological problems or may be related to sleep disorders or medications, Psychological conditions that can interfere with concentration include anxiety, depression, bipolar disorder, emotional trauma, and stress.To learn more about Concentration, refer to:
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1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm. Half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The cylinder changes volume to maintain constant pressure. What is the volume in the final system?
The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
How to calculate volume?The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressureP2 = final pressureT1 = initial temperatureT2 = final temperatureV1 = initial volumeV2 = final volumeAccording to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.
However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:
2 × 12.3/300 = 2 × V2/900
0.082 = 2V2/900
73.8 = 2V2
V2 = 73.8 ÷ 2
V2 = 36.9L
Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
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Answer:
Explanation:
it's 18.45, my sister just got the guestion right! hope it helps :)
A mixture of reactants and products for the reaction shown below is at
equilibrium in a 2.0 L container. What would most likely happen to the
equilibrium if the volume of the container were increased to 4.0 L?
N₂(g) + 3H₂(g)—2NH₂(g)
A. More NH3 would be produced.
B. Less N₂, H₂, and NH3 would be produced.
C. More N₂, H₂, and NH3 would be produced.
D. More N₂ and H₂ would be produced.
If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)
What is chemical equilibrium?
This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.
Principle of chemical equilibriumA French scientist postulated a principle which helps us to understand a chemical system in equilibrium.
The principle states as follow:
If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.
How to determine what will happen if the volume of the container is increased from 2 L to 4 LFrom the principle given above, we can see that volume does not affect equilirium position.
However, from Boyle's law, we understood that pressure and volume are in invest relationship.
Thus, increasing volume simply means decreasing pressure.
A decrease in pressure will favors the side where there is an increase in volume.
Let us consider the equation from the question:
N₂(g) + 3H₂(g) <=> 2NH₃(g)
Volume of reactants = 1 + 3 = 4 LVolume of products = 2 LThus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.
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What volume of H2 gas will be produced if 60 L of ammonia, NH3, is decomposed into H2 and N2, assuming that all conditions are at STP?
a)
30 L
b)
90 L
c)
60 L
d)
120 L
e)
150 L
need answer ASAP!!
Answer:
I think the answer is c I'm not sure but probaly dont put c if your. ot sure try looking up the answers that helps me alot through my word
The volume of H₂ gas produced is approximately 90 L, Option (b) is correct.
To find the volume of H₂ gas produced when 60 L of ammonia (NH₃) is decomposed, we use the balanced chemical equation for the decomposition of ammonia:
2 NH₃(g) → 3 H₂(g) + N₂(g)
According to the equation, 2 moles of ammonia produce 3 moles of hydrogen gas (H₂). At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters.
First, calculate the moles of ammonia present in 60 L:
Moles of NH₃ = Volume / Molar Volume at STP = 60 L / 22.4 L/mol ≈ 2.68 moles
Using the stoichiometric ratio, 3 moles of H₂ are produced from 2 moles of NH₃. So, we can calculate the moles of H₂ produced:
Moles of H₂ = (3/2) * Moles of NH₃ ≈ (3/2) * 2.68 moles ≈ 4.02 moles
Now, find the volume of H₂ gas produced:
Volume of H₂ = Moles of H₂ * Molar Volume at STP = 4.02 moles * 22.4 L/mol ≈ 89.9 L
Rounded to one decimal place, the volume of H₂ gas produced is approximately 90 L, which corresponds to option b).
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What is the ph of a buffer made by combining 45. 0 ml of 0. 150 m nitrous acid and 20. 0 ml of 0. 175 m sodium nitrite? the ka of nitrous acid, hno2, is 4. 5×10^–4?
The pH of the buffer made by combining Nitrous acid and Sodium Nitrite will be 3.06.
pH can be defined as the medium of expressing the acidity or alkalinity of any solution. It is the potential of hydrogen atoms.
Buffers are the solutions that resist any change in the pH when an acid or base is added to them.
According to the question,
0.150 M nitrous acid (HNO₂) = 45 ml
0.175 M sodium nitrate (NO₂⁻)= 20 ml
Kₐ of nitrous acid (HNO₂) = 4.5 × 10⁻⁴
Total volume of buffer = 45 ml + 20 ml = 65 ml
Concentration of HNO₂ = (45) (0.150) / 65 = 0.103 M
Concentration of NO₂⁻ = (20) (0.175) / 65 = 0.054 M
HNO₂ ⇒ H⁺ + NO₂⁻
Initial : 0.103 0 0.054
Change: -x +x +x
Equilibrium: 0.103-x x 0.054+x
Kₐ = x(0.054+x) / 0.103-x = 0.054x / 0.103 = 0.524x
Also, Kₐ = 4.5 × 10⁻⁴
Therefore, 4.5 × 10⁻⁴ = 0.524x
x = 8.58 × 10⁻⁴ M
H⁺ = x = 8.58 × 10⁻⁴ M = 8.6 × 10⁻⁴ M
Therefore, pH = -log ( 8.6 × 10⁻⁴ M)
pH = 3.06
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Balance the equation for a half-reaction that occurs in acidic solution. use e− as the symbol for an electron. equation: p_{4} -> h_{3}po_{4} p4⟶h3po4
The balance the equation for a half-reaction that occurs in acidic solution is given as,
[tex]P_{4}+16H_{2} O+20e^{-}[/tex] → [tex]4H_{3}PO_{4}+20H^{+}[/tex]
The half-reaction method to balance redox reactions in acidic aqueous solutions follows rule.
Balance elements in the equation other than O and H.Balance the oxygen atoms by adding the appropriate number of water opposite side of the equation.Balance the hydrogen atoms by adding proton ions ( [tex]H^{+}[/tex] ion) to the opposite side of the equationAdd up charge on each side of the equation by adding enough number of electrons to more positive side.The [tex]e^{-}[/tex] on each side must be equal . Multiply by appropriate integers if they are nit equal.The half -equation are added together, by cancelling out the electrons to form one balanced equation.learn about half-reaction
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7. Which of the following is NOT part of the Kinetic Molecular Theory?
a. All matter came from the Big Bang.
b. Matter is made of small particles called atoms.
c. Atoms are in constant motion.
d. The energy of the atoms is called heat.
What concentration of nacl solute particles in water will provide an isotonic eyedrop solution?
The concentration of [tex]NaCl[/tex] solute particles in water will provide an isotonic eyedrop solution is 0.9% w/v
The isotonic solution is calculated by multiply the quantity of each drug in the prescription by its sodium chloride equivalent E , and subtract this value from the concentration of sodium chloride which is isotonic with body fluids . For a solution to be termed isotonic ( equal tone ) it must have the same osmotic pressure as a specific bodily fluid.
Example : The concentration of [tex]NaCl[/tex] solute particles in water will provide an isotonic eyedrop solution is 0.9% w/v
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The solubility KI is 50 g in 100 g of H2O at 20 °C. if 110 grams of ki are added to 200 grams of H2O ________
The solubility KI is 50 g in 100 g of H₂O at 20 °C. if 110 grams of ki are added to 200 grams of H₂O the solution will be saturated.
What is solubility?Solubility is a condition where the solute is fully dissolved in the solvent. When fully mixed with the solvent.
Given that 50 g of KI is added to 100 g of water at 20 °C it means 100 g of water can dissolve a maximum of 50 g of KCl.
1 g of water will dissolve an quantity of 0.5 g of KCl.
To assay for 200 g of water: 200 g of water can disintegrate a maximum of (0.5) x 200 g of KCl.
The maximum amount of KCl that will dissolve is 100 g
Actualised amount dissolved = 110 g
when Amount dissolved > Maximum solubility limit
110 g > 100 g
Thus, the solution is saturated.
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Calculate the frequency of light having a wavelength of 425nm. remember that 1nm=1×10−9m
The frequency of light having a wavelength of 425nm will be 70588 × [tex]10^{14} Hz[/tex].
The count of times an event takes place per unit of time is known as its frequency. The word frequency would be most frequently used to describe waves in physics including chemistry, including light, sound, including radio waves. The frequency refers to the number of times during one second that a point on a wave crosses a fixed reference point.
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places in the consecutive cycles.
Given data:
wavelength = 425nm = [tex]425 * 10^{-9} m[/tex]
Frequency can be calculated by using the formula;
Frequency = speed of light / wavelength
Frequency = 3 × [tex]10^{8} m/s[/tex] / 425 × [tex]10^{-9} m[/tex] = 7,0588 × [tex]10^{14} Hz[/tex].
Therefore, the frequency of light having a wavelength of 425nm will be 70588 × [tex]10^{14} Hz[/tex].
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A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
Answer:
[tex]\frac{1 kJ}{1,000 J}[/tex] · [tex]\frac{1,000 mmol}{1 mol}[/tex]
Explanation:
The final answer has a different set of units. In particular, millimoles (mmol) changes to moles (mol) and joules (J) changes to kilojoules (kJ). To make this change, you need to multiply the first value by proportions.
When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since J is located in the numerator, it must be located in the denominator of the conversion. Furthermore, since mmol is located in the denominator, it must be located in the numerator of the conversion.
Proportions:
1,000 J = 1 kJ
1,000 mmol = 1 mol
The full expression:
[tex]-1.3*10^4\frac{J}{mmol*^oC}[/tex] · [tex]\frac{1 kJ}{1,000 J}[/tex] · [tex]\frac{1,000 mmol}{1 mol}[/tex] = [tex]? \frac{kJ}{mol*^oC}[/tex]As you can see, the old units cancel out and you are left with kJ in the numerator and mol in the denominator.
Write the empirical formula for at least four ionic compounds that could be formed from the following ions
Answer:
NH₄CN, NH₄IO₃, Fe(CN)₃, Fe(IO₃)₃
Explanation:
Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.
1.) NH₄CN
-----> NH₄⁺ and CN⁻
-----> +1 + (-1) = 0
2.) NH₄IO₃
-----> NH₄⁺ and IO₃⁻
-----> +1 + (-1) = 0
3.) Fe(CN)₃
-----> Fe³⁺ and CN⁻
-----> +3 + (-1) + (-1) + (-1) = 0
4.) Fe(IO₃)₃
-----> Fe³⁺ and IO₃⁻
-----> +3 + (-1) + (-1) + (-1) = 0
Isotopes have question 2 options: a) a different number of neutrons in their nuclei. b) a different number of protons in their nuclei. c) a different number of electrons. d) different numbers of both protons and neutrons in their nuclei.
Answer:
A
Explanation:
Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.
Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.
