The number of significant digits is 6.
What is significant figures?The crucial or important digits that accurately represent the meaning of a certain number are known as the significant figures of that number. 6.658, for instance, has four significant digits. These huge amounts give the numbers accuracy. Additionally, they are known as significant digits.
Given that: -3.22 x 5.1.
The product of -3.22 and 5.1 is 16.442.
In the number 16.442, there have 6 significant figures. Hence, The number of significant digits is 6.
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Lucy is cruising through space in her new spaceship. As she coasts along, a tiny spacebug drifts into her path and bounces off the window.
Consider several statements concerning this scenario. Evaluate each statement according to the law of momentum conservation and match it to the appropriate category.
TRUE: The total change in momentum for this interaction is zero.
FALSE: The change in the space bug's momentum is greater than the change in the spaceship's momentum.
UNDETERMINED: If the space bug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction.
ANALYSIS
1. Which has more kinetic energy:
a. A compact car going 70 mph or a tractor trailer going 15 mph?
b. An SUV going 30 mph or a pickup truck going 30 mph?
c. A school bus going 15 mph, an SUV going 35 mph, or a
compact car going 45 mph?
a) Tractor trailer will have more kinetic energy
b) kinetic energy of pickup truck will be more than a SUV
c) school bus will have the maximum kinetic energy
a) Tractor trailer will have more kinetic energy because its mass is way to heavy than that of compact car as kinetic energy is not only just dependent on velocity but also depend upon mass of that body .
b) since , speed of SUV and truck is same , but mass of the truck is more than SUV , hence kinetic energy of pickup truck will be more than a SUV .
C) Since , school bus carries number of passengers than SUV or compact car , hence school bus will have the maximum kinetic energy .
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URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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What is the total mechanical energy of a 3 kg object traveling at 7 m/s if its potential energy is 42 J? (1 point)
247.8 J
115.5 J
31.5 J
73.5 J
A 3 kilogram object traveling at 7 m/s and possessing a 42 J potential energy has a mechanical energy of 115.5 J.
How much mechanical energy does the thing possess?Performing a specific task results in the accumulation of mechanical energy. It is the total of an object's potential energy and kinetic energy. It is stated as;
Potential and kinetic energy are the components of mechanical energy.
Given the information in the query;
The object's mass is 3 kg.
The object's speed is 7 m/s.
Object's potential energy is 42 J.
Calculate the object's kinetic energy.
Kinetic energy = 1/2 × mass × ( velocity )²
Insert the specified values.
Kinetic energy is = 1/2 x 3 kg x 7 m/s2.
Kinetic energy = 0.5 x 3 kg x 49 m2/s2.
Kinetic energy = 73.5 kg/m2/s2.
Kinetic energy = 73.5 J.
Now, the object's mechanical energy will be;
Potential energy plus kinetic energy equals mechanical energy.
Put the values in.
Mechanical energy = 42J + 73.5J
Mechanical energy = 115.5 J.
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Why is it important for your measurements that the track is level for rolling motion in physics?
It is important for the measurements that the track is level for rolling motion in physics because the rolling objects only move on the tract that is leveled correctly.
What do you mean by rolling motion?The rolling motion is a fusion of translational motion and rotational motion. For a body, the motion of the center of mass is the adaptation motion of the body. During the rolling motion of a body, the exterior contact gets disfigured a little temporarily. A combination of translational and rotational motions happens during the rolling motion of an object. To define rolling motion, we must recognize the forces like angular momentum and torque. It is a merger of two types of motion i.e. translational and rotational motion. The translational motion of a body is the movement of the whole body from one place to another.
So we can conclude that Rolling motion is that usual combination of encircling and translational motion that we see everywhere and every day.
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A projectile is fired horizontally at 180 m/sec from an altitude of 734.7 m. What is the final vertical velocity of the projectile as it hits the ground?
A projectile is fired horizontally at 180 m/sec from an altitude of 734.7 m. The final vertical velocity of the projectile as it hits the ground will be 216.36 m/s
s = u*t + 1/2 * a * [tex]t^{2}[/tex]
734.7 = 180 * t + 1/2 * g * [tex]t^{2}[/tex]
734.7 = 180 * t + 1/2 * 9.8 * [tex]t^{2}[/tex]
= 4.9 [tex]t^{2}[/tex] + 180 t - 734.7
by solving the above quadratic equation , we get
t = 3.71 seconds
v = u + at
v = u + g*t
v = 180 + (9.8)(3.71)
= 216.36 m/s
The final vertical velocity of the projectile as it hits the ground will be 216.36 m/s
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Help on solving this single logarithm
log 8 + log 16 - log 2 = log64, In order to get another number, a number should be raised to a certain power, which is known as a logarithm.
The correct answer is A
Describe a logarithm.A number must be increased to a specific power, or logarithm, in order to obtain another number. For additional information on exponents, visit Figure 3.3 of this Math Review. As an example, the base 10 logarithm of the number ten raised to the power of two two is two, or log 100, which equals two.
What does a number's log mean?Exponentiation is a mathematical operation, and the logarithm, simply log, is its inverse. In other words, the log of a number is the value that a fixed base must be increased to in order to produce the value. Although technically any base can be used, the term "log" often suggests that base 10 is being used.
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A television uses a current of 1.5A at 120V. The television is used for 2 hours. Calculate
the power used in kW and the energy used in kWh.
Answer:
the power used is 0.18kW and the energy used is 0.36kWh
Explanation:
from power= current × voltage
power= 1.5A × 120V
power= 180W or 0.18kW
energy used = power × time
= 0.18kW ×2h
energy used = 0.36kWh
Astronauts in training are subjected to extreme acceleration forces by the centripental forces in againt centrifuge the radius of the centrifuge appriximately 5m calculate the approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s
The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN
ac = v² / r
v = 2 π r / T
ac = Centripetal acceleration
v = Linear / Tangential velocity
T = Time period
r = Radius
r = 5 m
T = 2 s
v = 2 * 3.14 * 5 / 2
v = 15.7 m / s
ac = 15.7 * 15.7 / 5
ac = 49.298 m / s²
Fc = m ac
m = Mass
m = 80 kg
Fc = 80 * 49.298
Fc = 3943.8 N
Fc = 3.94 KN
Therefore, the approximate centripetal force on the astronaut is 3.94 KN
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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s?
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
What is speed?
The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,
v = [tex]2\pi*r[/tex]/t
v = 2*3.14*1.8*108/2.2*104
v = 5.34 m/sec.
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
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A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?(1 point)
100 N
4000N
1600N
800N
Does anybody know how to solve something like this? I'm going through my notes and lesson by I can't find anything! I NEED THIS TODAY!!!
The force that is applied 100 N.
What is the force applied?We know that a lever is one of the kinds of simple machine that we have. The lever works by the fact that there is a load and an effort arm. We have been told that a lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters.
We can get the force that must be applied from the fact that;
Work = Force * distance
Force = Work/Distance
Force = 400/4
Force = 100 N
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Two small plastic spheres having positive electrical charges are given. When they are 60.00cm apart, the repulsive force between them has the magnitude 0.250N.calculate the charge on each sphere
Answer:
3.16 × 10‐⁶
Explanation:
through coulomb's law
the force of attraction or repulsion of charges is given by the relation
F = k.q1.q2/r²
where your k = 9 × 10⁹
Answer:
Charge 3.16 mkC microcoulomb
Explanation:
Given:
q₁ = q₂ = q - Electrical charges
r = 60.00 sm = 0.60 m - Distance between charges
F = 0.250 N - Repulsive force between charges
___________________
q - ?
F = k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²
Charge:
q = √ (F·r² / k )
q = r·√ (F / k )
q = 0.60· √ (0.250 / 9·10⁹) ≈ 3.16·10⁻⁶ C or:
q = 3.16 mkC (microcoulomb)
A 15 kg dog running at 4 m/s picks up a 1 kg stationary bone and continues to run what is the speed of the dog as it runs with its newfound treasure?
0
2.5
3.75
5.83
A bouncy ball has 30 J of kinetic energy before it collides with the floor. If the collision is perfectly elastic, what is the kinetic energy of the bouncy ball after it collides with the floor?
0
30
65
200
Answer: (1) C, (2) B
Explanation: I took the test, but to solve question 1 use the inelastic collision formula m1v1+m2v2 = (m1+m2)v2 to get the answer. Question 2 is b because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.
The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.
The kinetic energy of the bouncy ball after it collides with floor is 30 J.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
According to the given in question,
a.) Using inelastic collision formula
[tex]m_1v_1+m_2v_2 = (m_1+m_2)v_2[/tex]
[tex]v_2[/tex] = 60/16 m/sec = 3.75 m/sec
b.) Because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.
The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.
The kinetic energy of the bouncy ball after it collides with floor is 30 J.
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Two protons (charge q= 1.602·10-19 C) move at the same speed v= 1.4 ·106 m/s in opposite directions parallel to the x-axis. At the instant when they are at the same x-position, the proton moving in the negative direction is at distance r= 0.7 mm in the positive y-direction with respect to the one moving in the positive direction.
What is the magnitude of the magnetic field at the point of the proton moving in the negative direction?
B=
What is the magnetic force direction experienced by the proton moving in the negative direction?
FB=
(a) The magnitude of the magnetic field at the point of the proton moving in the negative direction is 2.1 x 10⁻⁹ T.
(b) The magnetic force direction experienced by the proton moving in the negative direction is 4.71 x 10⁻²² N.
What is the magnetic field due to the proton?
The magnitude of the magnetic field at the point of the proton moving in the negative direction is calculated as follows;
F = qvB = kq²/r²
qvB = kq²/r²
B = kq²/qvr²
B = kq/vr²
where;
k is coulomb's constantq is the magnitude of charge of the protonsr is the distance between the protonsv is the speed of the protonB = (9 x 10⁹ x 1.602 x 10⁻¹⁹) / (1.4 x 10⁶ x 0.7 x 10⁻³ x 0.7 x 10⁻³ )
B = 2.1 x 10⁻⁹ T
The magnetic force direction experienced by the proton moving in the negative direction is calculated as follows;
F = qvB
F = 1.602 x 10⁻¹⁹ x 1.4 x 10⁶ x 2.1 x 10⁻⁹
F = 4.71 x 10⁻²² N.
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4. A car is driving at 25 m/s (55 mph). The driver spots a deer jumping into the road. It takes
the driver 2 seconds to react and hit the brakes. Once the brakes are hit the car slows down at a
rate of 5 m/s/s. Calculate how long it takes to stop and how far the car travels during the
reaction time and stopping time.
1. The time taken for the car to stop is 5 s
2. The distance travelled during the reaction time is 50 m
3. The distance travelled during the stopping time is 62.5 m
1. How do I determine the time taken for the car to stop?
The time taken for the car to stop can be obtained as follow:
Initial velocity (u) =25 m/sDeceleration (a) = -5 m/s/s Final velocity (v) = 0 m/sTime taken to stop (t) =?a = (v - u) / t
-5 = (0 - 25) / t
-5 = -25 / t
Cross multiply
-5 × t = -25
Divide both sides by -5
t = -25 / -5
t = 5 s
Thus, the time taken to stop is 5 s
2. How do I determine the distance travelled during the reaction time?
The distance travelled during the reaction time can be obtained as follow:
Velocity = 25 m/sReaction time (t) = 2 secondsDistance travelled =?Distance travelled = velocity × reaction time
Distance travelled = 25 × 2
Distance travelled = 50 m
3. How do I determine the distance travelled during the stopping time?
Initial velocity (u) = 25 m/sDeceleration (a) = -5 m/s/s Final velocity (v) = 0 m/sStopping time (t) = 5 sDistance (s) =?s = ut + ½at²
s = (25 × 5) + (½ × -5 × 5²)
s = 125 - 62.5
s = 62.5 m
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Sleeping with an even a small amount of light can cause negative changes to peoples metabolism. for example, a studies shown that those who slept in dim light had more trouble _______ the next morning.
A) processing sugar
B) maintaining posture
C) slowing down their heart rate
D) avoiding devices like smart phones
PLS HELP 50 PO IN TS
Answer: A
Explanation: The research mentions both the insulin resistance and the increased heart rate. But one thin I noticed is that the increased heart rate happens at night while they sleep, but the question asks for the next morning, so A.
There’s really no exact citation found but this is as close as I can get you.
A body of mass 2kg falls freely from rest through a height 8m onto a hard floor bounces back to a height of 2m. calculate the change of momentum, if the bady is in contact with the floor for 0.1s, what is the force exerted on the body? (g=10ms^2)
The force exerted on the body is 12.66 N.
Linear momentum, translational momentum, or clearly momentum is the made of the mass and velocity of an item. it's miles a vector amount, possessing significance and a path. If m is an object's mass and v is its speed.
Given;
mass = 2 kg
height = 8m
bounce height = 2 m
let velocity just before striking the floor is initial velocity 12.65 m/s
the potential energy at 8 m = mgh
= 2 ×10× 8
= 160 J
same converted into kinetic energy 160 J = 1/2 mv²
V² = 320/2
v = 12.65 m/s
Final velocity
mgh = 1/2 mv²
2×10×2 = 1/2×2 × v²
v² = 6.32 m/s
Acceleration = change in velocity per unit of time
= - 6.32 - (-12.65) = 6.33 m/s² / 0.1
Force = mass × acceleration
= 2 × 6.33 m/s²
= 12.66 N
Momentum may be described as a mass in motion. All objects have mass; so if an object is transferring, then it has momentum - it has its mass in movement. the quantity of momentum that an item has depends upon variables: how an awful lot of stuff is moving and the way speedy the stuff is moving.
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Five gas molegules are choosen at random are found to have speed of 500,600,700, 800 and 900 m/s. Find the rms speed. Is it ghe same as average speed
Answer:
Explanation:
The rms speed:
Vrms = (500 + 600 + 700 + 800 + 900) / 5 = 700 m/s
3.2 Two ropes are tied to a fixed nail. The tension in the ropes is 10N and 20N respectively, while the angle between them is 120degrees. Calculate the magnitude and direction of the reaction to the nail.[8] 3.3. A person going for a walk follows the path shown in Fig.P3.59. The total trip consists of four straight-line paths. At the end of the walk, what is the person's resultant displacement measured from the starting point?
3.2) the magnitude and direction of the reaction to the nail is 26.5 N towards the wall.
3.3) the person's resultant displacement measured from the starting point is 239.99 m.
3.2)
The tension in the rope 1 = 10N
The tension in the rope 2 = 20N
the angle between them = 120degrees
We have;
R² = 10² + 20² - 2(10 x 20)Cos(120°)
R² = 100 + 400 - 400Cos(120°)
R² = 500 + 200
R² = 700
R = 26.5 N
towards the wall.
3.3)Let alone having the graph's x axis and the West-East axis in a Cartesian coordinate system coincide.
Let's split the vectors up using trigonometry.
Aₓ = 100.0 m
By = -300.0 m
angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
Cy = C sin 210° = -75.0 m
Cₓ = C cos 210° = -129.9 m
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
Dy = D sin 120 = 173.2 m
Dₓ = D cos 120 = -100.0 m
add the component Then we get :
x = Aₓ + Cₓ + Dₓ
x = 100 - 129.9 -100 = -129.9 m
y = By + Cy + Dy
Y = -300 - 75.0 + 173.2 = -201.8 m
Resulting vector calculated as :
[tex]R = \sqrt{x^2 + y^2}[/tex]
R = 239.99 m
3.2) the magnitude and direction of the reaction to the nail is 26.5 N towards the wall.
3.3) the person's resultant displacement measured from the starting point is 239.99 m.
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Q)What is the force between two small charged spheres having charges of 2 × 10^–7C and 3 × 10^–7 C placed 30 cm apart in the air?
The electrostatic force between the two charged spheres is determined as 6 x 10⁻³ N.
What is the electrostatic force between two charged objects?
The electrostatic force between two charged objects, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.
F = kq₁q₂/r²
where;
K is Coulomb's constantq₁ is the first chargeq₂ is the second charger is the distance between the chargesF = (9 x 10⁹ x 2 x 10⁻⁷ x 3 x 10⁻⁷) / (0.3²)
F = 6 x 10⁻³ N
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If a Mack truck and a Honda Civic have a head-on collision, which vehicle will experience the greater force of contact? The greater impulse? The greater change in momentum? The greater acceleration? Discuss how a failure to distinguish between these concepts leads to difficulties in understanding physics!
The Honda Civic is the car that would have greater impulse, momentum change and acceleration due to Collison.
What is the impact?The term impulse has to do with the product of force and time. The impact is literally the force that acts on an object for a short time. We know that the mass of the object is very important when we are discussing the impulse on the object.
When there is a head-on collision that occurs between the Mack truck and a Honda Civic, the Honda Civic would have the greater impulse and the greater change in momentum and thus the greater acceleration.
If we do not understand the concept of the effect of momentum and the acceleration of an object, we would not be able to understand the basic interaction that occur between objects using the principles of physics.
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A car is traveling 20m/s around a right hand curve. The passenger is at a radius of 5m and the driver is at radius of 6m. What is the centripetal acceleration felt by each?
The exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ is 80m/s² & 66.67m/s² respectively.
Mathematically , Centripetal acceleration ∝= v²/r
In the given question velocity will be same for passengers and driver because of common frame.
But the radius is different since distance from each points of frame to the Centre of road will vary. so their centripetal acceleration will differ.
∝= v²/r using this we can find out the exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ
∝ₙ= 20²/5= 80m/s²
∝ⁿ=20²/6= 66.67m/s²
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What are the causes of different falls in the air?
A, Highlight drop drop
B, The Wind Blows
C, of object
D, Air resistance
D. air resistance
Hope it helps
A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds? Given: g on moon = -1.63 meters/second2
[tex]66.015 \mathrm{~m}[/tex] will the feather have fallen if it reaches the surface in 9.00 seconds.
Given:
[tex]$$\begin{aligned}&t=9 \mathrm{~s} \\&a=1.63 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
The distance traveled by the feather onto the surface of the moon can be computed using the following equation:
[tex]d=\frac{1}{2} a t^2=(0.5)\left(1.63 \mathrm{~m} / \mathrm{s}^2\right)(9 \mathrm{~s})^2=66.015 \mathrm{~m}$$[/tex]
Kinematics in classical mechanics explains the motion of a specific item in a system. We're looking at the motion of a feather on the moon's surface.
Kinematics is the study of mechanical points, bodies, and systems in their motion without regard for their related physical qualities or the forces acting on them. The discipline is known as geometry of motion, and it mathematically describes these motions using algebra.
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Which of the following is not one of the rules that must be followed regarding animal research? A. Animal research must have a clear scientific purpose. B. Animal research can acquire its animals illegally. C. Animal research must provide humane care and housing. D. Animal research must ensure the least amount of suffering possible. Please select the best answer from the choices provided A B C D
On research on animals they must given proper care and housing. And the purpose of the research must have a scientific reason. Thus option B is correct.
What is animal research?Animal research includes various scientific investigation on animals such as testing various doses of some drugs, effect of various chemicals, level of toxicity of some compounds etc.
According to the research ethics, no animals can be used to conduct any unscientific works. There must be a scientific purpose which is very important to conduct any animal research.
If any animals irrespective of its nature,it must be provided proper care, food and housing. No harmful things must be there which make them more suffering. Hence, option B is correct.
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4. Ebo throws the ball again at an initial velocity of 18 m/s but this time at an angle of 53° to the ground. a) Work out the velocity in component vector form. b) Why will the ball spend a longer time in the air than it did before. c) Calculate the range of the ball.
16.52 m/s is the velocity and vcosθ is the velocity in component vector form.
velocity in vector form= vcosθ
vector form= vcosθ
vector form=18cos53
v=16.52 m/s
"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking quickly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not sufficient information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.
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A crowbar of 200 cm long is pivoted about to its other end to displace a load of 600 N. 0.5 m Calculate MA, VR and efficiency of the crowbar.
The mechanical advantage of the crow bar is 3 while the velocity ratio is 4. The efficiency of the machine is 75%.
What is the efficiency of the crow bar?We know that a machine is any device that can be used to make work a lot much easier. Thus, the machine is the object that could make less effort to be applied in making a greater work to be done as we can see in this case we have here.
From the question, the pieces of information that we can get are;
Distance moved by Effort = 200 cm
Distance moved by load = 0.5 m or 50 cm
Velocity ratio = Distance moved by Effort/Distance moved by load
= 200 cm /50 cm
= 4
Mechanical advantage is found to be; Load/Effort
= 600 N/200 N
= 3
Efficiency = Mechanical advantage/ Velocity ratio * 100/1
= 6/4 * 100/1
=3/4 * 100/1
= 75%
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For one length of wire the potential difference across the wire was 1.68 V The current in the wire was 0.70 A calculate the resistance of the of this length of wire  
For one length of wire the potential difference across the wire was 1.68 V . The current in the wire was 0.70 A . The resistance of the of this length of wire will be 2.4 ohm
using ohm's law
V = IR
I = current
R = resistance
R = V/I
= 1.68 / 0.70 = 2.4 ohm
The resistance of the of this length of wire will be 2.4 ohm
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A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?
0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s
ω=Δθ/Δt
Δθ= 90° = 1.571rad
Δt=13.45
ω=1.571/13.45
ω=0.116 rad/s
The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.
As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t
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how long (in seconds) would it take a Narwhal to accelerate from rest down a 30 meter long ravine with an acceleration of 2.2 m/s^2
The time (in seconds) it will take the Narwhal to accelerate from rest down a 30 meter long ravine is 5.2 s
How do I determine the time?We know from equations of motion that distance, acceleration and time are related according to the following formula:
s = ut + ½at²
Where
s is the distanceu is the initial velocitya is the accelerationt is the timeWith the above formula, we can obtain the time as follow:
Initial velocity (u) = 0 m/sDistance (s) = 30 mAcceleration(a) = 2.2 m/s²Time (t) = ?s = ut + 1/2at²
30 = (0 × t) + (½ × 2.2 × t²)
30 = 0 + (1.1 × t²)
30 = 1.1 × t²
Divide both side by 1.1
t² = 30 / 1.1
Take the square root of both side
t = √(30 / 1.1)
t = 5.2 s
Thus, the time taken is 5.2 s
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