Calculate the base length of the isosceles triangular pieces

The image of point a after reflection over the y axis followed by dilation with a scale factor of 3 centered at the origin is,

⇒ (6, 9)

A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.

Given that;

The coordinates of point a are,

⇒ a =  (-2,3)

Now, We can multiply by 3 in the point;

⇒ (- 2, 3) = (- 2 × 3, 3×3)

              = (- 6, 9)

Now, After reflection over the y axis,

Image of the point are,

⇒ (6, 9)

Thus, The image of point a after reflection over the y axis followed by dilation with a scale factor of 3 centered at the origin is,

⇒ (6, 9)

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It wiII cοst Jοnah $63.36 tο decοrate the 3-tiered circuIar wedding cake with fresh red rοses arοund the base οf each IeveI.

Tο caIcuIate the cοst οf decοrating the cake with rοses, we need tο first determine the circumference οf each tier, which wiII teII us hοw many rοses are needed fοr each tier.

The circumference οf a circIe can be caIcuIated using the fοrmuIa C = πd, where C is the circumference, π is the mathematicaI cοnstant pi (apprοximateIy 3.14), and d is the diameter.

Fοr the bοttοm tier with a diameter οf 14 inches, the circumference is C = πd = 3.14 x 14 = 43.96 inches.

Fοr the middIe tier with a diameter οf 10 inches, the circumference is C = πd = 3.14 x 10 = 31.4 inches.

Fοr the tοp tier with a diameter οf 6 inches, the circumference is C = πd = 3.14 x 6 = 18.84 inches.

Nοw, we need tο determine hοw many rοses are needed fοr each tier. Tο dο this, we need tο caIcuIate hοw many rοses wiII fit arοund the circumference οf each tier. We can dο this by dividing the circumference οf each tier by the width οf the rοses, which is 1.5 inches.

Fοr the bοttοm tier: 43.96 inches / 1.5 inches per rοse = 29.3, rοunded up tο 30 rοses.

Fοr the middIe tier: 31.4 inches / 1.5 inches per rοse = 20.9, rοunded up tο 21 rοses.

Fοr the tοp tier: 18.84 inches / 1.5 inches per rοse = 12.6, rοunded up tο 13 rοses.

Nοw that we knοw hοw many rοses are needed fοr each tier, we can caIcuIate the tοtaI cοst οf the rοses. Each rοse cοsts $0.99, sο the cοst οf the rοses fοr each tier is:

Bοttοm tier: 30 rοses x $0.99 per rοse = $29.70

MiddIe tier: 21 rοses x $0.99 per rοse = $20.79

Tοp tier: 13 rοses x $0.99 per rοse = $12.87

The tοtaI cοst οf decοrating the cake with rοses is the sum οf the cοsts fοr each tier:

$29.70 + $20.79 + $12.87 = $63.36

Therefοre, it wiII cοst Jοnah $63.36 tο decοrate the 3-tiered circuIar wedding cake with fresh red rοses arοund the base οf each IeveI.

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To prove that \[ A^{n}=\left[\begin{array}{ccc} a^{n} & n a^{n-1} & \frac{n(n-1)}{2}a^{n-2} \end{array}\right], we will use mathematical induction.

Base case: For \( n=1 \), \( A^{1}=A \). This is true since
\[ A=\left[\begin{array}{ccc} a & 1 & 0 \\ 0 & a & 1 \\ 0 & 0 & a \end{array}\right] \]
which matches the left side of our equation.

Inductive step: Assume that the statement is true for some \( n=k \), i.e.
\[ A^{k}=\left[\begin{array}{ccc} a^{k} & ka^{k-1} & \frac{k(k-1)}{2}a^{k-2} \end{array}\right] \]
We will now show that it is true for \( n=k+1 \).
\[ A^{k+1}=A^{k}\cdot A \]

We substitute the induction hypothesis into this equation and get:
\[ A^{k+1}=\left[\begin{array}{ccc} a^{k} & ka^{k-1} & \frac{k(k-1)}{2}a^{k-2} \end{array}\right]\cdot \left[\begin{array}{ccc} a & 1 & 0 \\ 0 & a & 1 \\ 0 & 0 & a \end{array}\right] \]

Calculating the matrix product yields:
\[ A^{k+1}=\left[\begin{array}{ccc} a^{k+1} & (k+1)a^{k} & \frac{(k+1)k}{2}a^{k-1} \end{array}\right] \]
which matches the left side of our equation, completing the proof.

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Using algebra we can conclude that Mrs. Ong brought a total of 12 fruits.

Algebra is a discipline of mathematics that studies symbols and the mathematical operations that can be applied to them.

These symbols are referred to as variables because they don't have predetermined values.

These symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations in order to ascertain the values.

Now, let the total fruits be x.

Oranges = 1/2 x - 3

Pears = [x - 1/2 (1/2x -3 ) ]- 2= x - 1/4x + 3/2 - 2 = 3x /4 - 1/2

Apples = x - 1/2 (3x /4 - 1/2) - 1

           = x - 3/8 x + 1/4 - 1 = 5x /8 - 3/4

Mangoes = 5

x - 5x/ 8 + 3/4 = 5

3x /8 + 3/4 = 5    

3x + 6 = 40

3x = 34

x = 11.333

Therefore, using algebra we can conclude that Mrs. Ong brought a total of 12 fruits.

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Complete question:

Mrs. Ong bought some fruits. 3 fewer than 1/2 of the fruits were oranges. 2 fewer than 1/2 of the remaining fruits were pears. 1 fewer than half of the remaining fruits were apples and the remaining 5 fruits were mangoes.

How many fruits did Mrs Ong buy altogether?

The triangle in this problem is classified as follows:

Scalene obtude triangle.

According to the largest angle measure, the triangle is classified as follows:

The largest angle measure in this problem is of 102º > 90º, hence the triangle is an obtuse triangle.

The triangle is also classified as scalene, isosceles or equilateral as follows:

The three angle measures for this problem are different, hence the triangle is scalene.

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Answer:

-17p+100

______

4

Step-by-step explanation: combine multiplied terms into a single fraction. distribute. combine multiplied terms into a single fraction. find a common denominator. combine fractions with a common denominator. multiply the numbers.Rearrange terms.Combine multiplied terms into a single fraction.Cancel terms that are in both the numerator and denominator.Find common denominator.Combine fractions with common denominator.Distribute.Add the numbers.Combine like terms

Answer: internal systolic blood pressure (100,110).

Step-by-step explanation:

Given the systolic blood pressure is normally distributed with a

mean G 105  and a standard leviation 5 .

to find : using empirical rule determines  the interval

dyslolie blood pressure that represent the middle 68% malen

solution 68% value  lie within 1 standard deviation the mean .

            { using empirical rule 2

we cab express this range as :

= (x -s , x +s)

= (105 -5, 105+5)

= (100 , 110)

The total surface area of the triangular pyramid is 107 * [tex]\sqrt(3)[/tex]square feet.

Take a triangle. This is a base. Now take 3 triangles such that each of them are connected to one-one side of the first triangle and when they're taken together, they form a closed object, called as a triangular pyramid.

We are given that;

The length of median from outer triangle to side of the inner triangle is 8 ft

Side of inner equilateral triangle is 12 ft

Now,

First, we can find the height of the outer equilateral triangle using the Pythagorean theorem:

a^2 + (m/2)^2 = b^2

where a is half the length of the side of the inner triangle (6 ft), m is the length of the median (8 ft), and b is the length of the side of the outer triangle (unknown).

b^2 = 6^2 + 8^2/4

b^2 = 36 + 4

b^2 = 40

b = sqrt(40)

b = 2 * sqrt(10)

So the height of the outer triangle is:

h = b * sqrt(3)/2

h = sqrt(30)

Now we can find the area of each equilateral triangle using the formula:

A = (sqrt(3)/4) * s^2

where A is the area and s is the length of the side.

For the inner triangle:

A_inner = (sqrt(3)/4) * 12^2

A_inner = 36 * sqrt(3)

For the outer triangle:

[tex]A_outer = (\sqrt(3)/4) * (2 * \sqrt(10))^2A_outer = 5 * \sqrt(3)[/tex]

Now we can find the area of the base, which is just the area of the inner equilateral triangle:

A_base = A_inner

A_base = 36 * [tex]\sqrt(3)[/tex]

Finally, we can find the surface area of the triangular pyramid by adding the areas of the four triangles and the base:

SA = A_inner + 3 * A_outer + A_base

[tex]SA = 36 * \sqrt(3) + 3 * 5 * \sqrt(3) + 36 * \sqrt(3)SA = 107 * \sqrt(3)[/tex]

Therefore, the surface area of the triangular pyramid will be 107 * [tex]\sqrt(3)[/tex]square feet.

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The trigonometric value of angle Cos Z would be = 77°

A trigonometric value is defined as those values that are based on three major trigonometric ratios such as the Sine, Cosine, and Tangent.

According to the rules of trigonometry the following is carried out:

Sine or sin θ = Side opposite to θ / Hypotenuse = XY / XZ

Cosines or cos θ = Adjacent side to θ / Hypotenuse = YZ / XY

Tangent or tan θ =Side opposite to θ / Adjacent side to θ = XY / YZ.

Therefore, the trigonometric value of cos Z = adj/hypo = 9/40 = 0.225

Z = Cos^-1 0.225.

Z = 76.9 = 77°

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△ABC is cοngruent tο bοth △ACD and △CBD.

Geοmetry depends οn shapes like squares, circles, rectangles, triangles, and οthers. Amοng all the fοrms we have here, triangles seem tο be the mοst intriguing and distinctive. The triangle's shape is created by the intersectiοn οf three lines and three angles.

△ABC is a right triangle, right angled at C.

CD is altitude drawn tο hypοthesis AB.

Tο prοve, △ACD ~ △CBD

In △ACD and △CBD.

∠ACB= ∠ADC=90°  

∠CAB=∠DAC (Cοmmοn angle)

By AA similarity we can say that, △ACD and △CBD.

Anοther side,

Need tο prοοf ∣AC∣²+∣BC∣²=∣A B∣²

If  is a right triangle at C with a prοjectiοn tο  as shοwn, then

BC²=BD*AB

AC²= AD*AB

A further beneficial cοnclusiοn can be demοnstrated by cοmbining the Pythagοrean and Euclidean theοrems. The Pythagοrean Theοrem prοvides us with

CD²= BC²-BD²

By putting the value οf BC²,

CD²= BD*AB-BD²

OR, CD²= BD*(AB-BD)

OR, CD²= BD*AD

AB²= (AD*AB)+(BD*AB)

Or, AB(AD+BD)=AB²

Or, AB²=AB²

Or, ∣AC∣²+∣BC∣²=∣A B∣² (prοved)

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The odds against the next car leaving the lot being black = option(A) is correct option.

The odds against getting three tails when you flip three coins = option(B) is the correct option.

What is probability?

The potential of any random event's result is referred to as probability. To determine the likelihood that any event will occur is the definition of this phrase.

There 34 cars out of which 20 are green, 8 are gold and 6 are black.

So, The odds against the next car leaving the lot being black

    = no. of black cars / no. of non black cars

    = 6/28

    =3/14 (A)

If three coins are flipped together,

the total number of outcomes will be = 2³ = 8

no. of outcomes getting three tails = 1

The odds against getting three tails when you flip three coins

= no. of outcomes getting three tails/ no. of outcomes not getting three tails

= 1/7 (option B)

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The area of triangle PTSQ with sides ST=4, TQ=20, PQ=25, PS=13 is calculated to be 260 square units.

To find the area of triangle PTSQ, we can use the formula for the area of a triangle:

Area = (1/2) × base × height

First, we need to find the height of the triangle. We can do this by drawing an altitude from point T to side PS. Let the foot of the altitude be point R. Then, triangle TRS is similar to triangle TQP by the AA similarity criterion, since angle TRS = angle TQP (both are right angles), and angle STR = angle PTQ (both are vertical angles).

Therefore, we can set up the following proportion:

TR / TS = TQ / TP

TR / 13 = 20 / (25 - TP)

Cross-multiplying, we get:

25TR - 13TQ = 260

Substituting the given values, we get:

25TR - 13(20) = 260

25TR = 520

TR = 20.8

Now, we can use the formula for the area of triangle PTSQ:

Area = (1/2) × PQ × TR

Substituting the given values, we get:

Area = (1/2) * 25 * 20.8 = 260 square units

Therefore, the area of triangle PTSQ is 260² units.

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Answer:

Step-by-step explanation:

1 hour = 60 minutes, so ratio is

20:60 = 1:3

∴ n = 1

The final simplified expression is: [tex]6x^(2) - 22x + 9[/tex]

To simplify the given expression, we need to combine like terms. This means that we need to add or subtract terms that have the same variable and exponent.

The given expression is: [tex]12x^(2)+9-8x-6x^(2)-14x[/tex]

First, let's combine the terms with the same variable and exponent:

[tex]12x^(2) - 6x^(2) = 6x^(2)[/tex]

[tex]-8x - 14x = -22x[/tex]

Now, let's substitute these simplified terms back into the expression:

[tex]6x^(2) + 9 - 22x[/tex]

This is the simplified expression. There are no more like terms to combine, so we cannot simplify it further.

The final simplified expression is: [tex]6x^(2) - 22x + 9[/tex]

Answer: [tex]6x^(2) - 22x + 9[/tex]

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The distance of the ladder from the side of the house can be found using the trigonometric function cosine.

Cosine relates the angle of elevation and the adjacent side (the distance from the side of the house) to the hypotenuse (the length of the ladder).

Cos(55 degrees) = adjacent/hypotenuse

Cos(55 degrees) = adjacent/16

Adjacent = 16 * cos(55 degrees)

Adjacent = 9.2 feet

Therefore, the distance of the ladder from the side of the house is 9.2 feet to the nearest tenth.

Note: To find the cosine of 55 degrees, you can use a calculator or a trigonometric table. The explicit multiplication used in the calculation is 16 * cos(55 degrees).

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a) The appropriate hypothesis test for this situation is an independent samples t-test. The test statistic is the t-value, which is 0.824 b) the above hypothesis test, compute and comment on The effect size is 0.074,

The null hypothesis is that there is no difference in stress level between full-time and part-time volunteers, and the alternative hypothesis is that there is a difference in stress level between full-time and part-time volunteers.

The test statistic is the t-value, which is 0.824. The degrees of freedom is 529, which is calculated by adding the sample sizes of the two groups (336 + 195) and subtracting 2. The p-value is 0.411, which is greater than the significance level of 0.05.

This means that we fail to reject the null hypothesis and conclude that there is no significant difference in stress level between full-time and part-time volunteers.

b) The effect size for this hypothesis test can be calculated using Cohen's d, which is the difference between the two group means divided by the pooled standard deviation.

The effect size is 0.074, which is considered a small effect. This means that the difference in stress level between full-time and part-time volunteers is small and may not be practically significant.

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83/17 = 4.88235294118

Answer:

4.88, and 4.9 rounded to the nearest 10th and 5 round to the nearest whole number.

Step-by-step explanation:

The Vdp for the plug permeability is given as 0.46, which indicates that the variability of permeability in the plug is lower than that of the porosity and permeability in the core samples.

From the plots of porosity and permeability vs depth given in Question 2, we can say that both porosity and permeability have a certain degree of variability as they change with depth. However, the variability of permeability appears to be greater than that of porosity as the values of permeability change more drastically with depth compared to the values of porosity.

To calculate the coefficient of variation for both porosity and permeability, we can use the formula:

Coefficient of Variation (CV) = (Standard Deviation / Mean) * 100

For porosity:

Mean = (10 + 15 + 25 + 30 + 20) / 5 = 20

Standard Deviation = √[(10 - 20)² + (15 - 20)² + (25 - 20)² + (30 - 20)² + (20 - 20)²] / 5 = 7.07

CV = (7.07 / 20) * 100 = 35.35%

For permeability

Mean = (0 + 600 + 100 + 200 + 300 + 400 + 500) / 7 = 300

Standard Deviation = √[(0 - 300)² + (600 - 300)² + (100 - 300)² + (200 - 300)² + (300 - 300)² + (400 - 300)² + (500 - 300)²] / 7 = 200

CV = (200 / 300) * 100 = 66.67%
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Therefore , the solution of the given problem of triangle comes out to be the HL Congruence Hypothesis cannot be used to demonstrate anything.

A triangular is a polygon because it has two or maybe more additional sections. It has a straightforward square form. Only the edges A, B, but also C distinguish a triangular from a parallelogram. When the sides are not exactly collinear, Euclidean geometry produces a singular plane instead of a cube. If a shape has three edges and three angles, it is said to be triangular.

Here,

According to the HL Congruence Theorem, a triangle is congruent if its hypotenuse and one of its legs are congruent with the hypotenuse and corresponding limb of another right triangle.

We must assess whether the two right triangles have the following information in order to decide whether the HL Congruence Theorem can be used to prove that the triangles are congruent:

Both of them are right circles.

Each triangle has a limb that is congruent.

Each triangle's hypotenuses are similar to one another.

The HL Congruence Theorem allows us to infer that the triangles are congruent if all three requirements are satisfied.

The HL Congruence Hypothesis cannot be used to demonstrate anything if any one of the prerequisites is not satisfied.

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The smallest possible area of a square which can be made from the three pieces is 11833.203125 cm².

To find the smallest possible area of a square, we need to make sure that we use the longest pieces to form the sides of the square. Therefore, we need to divide the 360 cm steel bar into equal parts first, then use the remaining parts to divide the other two steel bars.

Let's call the length of each part x.

The 360 cm steel bar can be divided into n parts of length x, where:

n = 360/x

Similarly, the 300 cm steel bar can be divided into m parts of length x, where:

m = 300/x

And the 210 cm steel bar can be divided into k parts of length x, where:

k = 210/x

To form a square, we need to use all the parts we cut from the steel bars. Therefore, the length of the sides of the square will be nx + mx + kx, which is equal to (n + m + k)x.

The area of the square will be (n + m + k)x²

To find the smallest possible area, we need to minimize (n + m + k)x². Since x can be any positive number, we can focus on minimizing n + m + k.

n + m + k = (360/x) + (300/x) + (210/x)

n + m + k = (870/x)

To minimize (n + m + k), we need to maximize x. However, x cannot be greater than the smallest steel bar, which is 210 cm long.

Therefore, x must be a factor of 210.

Let's try x = 1 cm. In this case, n + m + k = 870 cm, which means we can form a square with sides of length 870 cm/4 = 217.5 cm.

The area of this square is 217.5^2 = 47250.625 cm².

Let's try x = 2 cm. In this case, n + m + k = 435 cm, which means we can form a square with sides of length 435 cm/4 = 108.75 cm.

The area of this square is 108.75² = 11833.203125 cm².

Let's try x = 3 cm. In this case, n + m + k = 290 cm, which means we cannot form a square using all the parts we cut from the steel bars.

Therefore, the smallest possible area of a square which can be made from the three pieces is 11833.203125 cm², and this can be achieved by cutting the steel bars into parts of length 2 cm.

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To run 6 miles it takes 2880 seconds of time.

The speed formula can be defined as the rate at which an object covers some distance. Speed can be measured as the distance travelled by a body in a given period of time. The SI unit of speed is m/s.

Given that, a runner records his rate of speed along the first mile of a 6 mile path that winds through the park.

We know that, speed =Distance/Time

Here, Distance= 1/4 mile and time=120 seconds

Speed = 1/4 ÷120 =1/480 miles per seconds

Time taken to run 6 miles

We know that, Time =Distance/Speed

Time = 6 ÷ 1/480

= 6×480

= 2880 seconds

Therefore, to complete 6 miles it takes 2880 seconds.

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The value of ratio of lime juice to mint is 3/2.

And the amount of lime juice is 3/2 of the amount of mint leaves.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls)

The ratio of lime juice to mint is 3/4: 1/2. therefore the value of this ratio = 3/4 ÷ 1/2 = 3/2

therefore the amount of lime juice = 1/2 × 3/2 = 3/4

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In order for the system of equations to be consistent, k must not be equal to 31.6087.

In order for the system of equations to be consistent, the determinant of the coefficient matrix must not be equal to zero. The coefficient matrix is:

| -3  4  7 |
| -11 24 k |
| 2  -5 -8 |

The determinant of this matrix is:

(-3)(24)(-8) + (4)(k)(2) + (7)(-11)(-5) - (7)(24)(2) - (4)(-11)(-8) - (-3)(k)(-5)

Simplifying this expression gives:

576 + 8k + 385 - 336 - 352 + 15k = 0

Solving for k gives:

23k = 727

k = 727/23

k ≈ 31.6087

Therefore, in order for the system of equations to be consistent, k must not be equal to 31.6087.

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The following are the correct convertion for the units of mass:

8000 mg converted to gram is 8 g

80 g converted to kilogram is 0.08 kg

0.8 kg converted to g is 800 g.

Gram (g) is the base unit of mass in the metric system. The milligrams (mg) and kilograms (kg) are derived units.

1 gram = 1000 milligrams (mg)

1000 grams = 1 kilogram (kg)

8000 mg = (8000/1000) g

8000 mg = 8 g

80 g = (80/1000) kg

80 g = 0.08 kg

0.8 kg = (0.8 × 1000) g

0.8 kg = 800 g.

In conclusion, 8000 mg converted to gram is 8 g, 80 g converted to kilogram is 0.08 kg, and 0.8 kg converted to g is 800 g.

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The value of (g - f) (x) is -3x² + 2x - 4

The value of (f + g) (x) is 3x² + 6x - 6.

The value of (g / f) (x) is (4x - 5) / (3x² + 2x - 1).

The value of (fg) (x) is 12x³ - 7x² -14x + 5.

The solution has been obtained by using operations on functions.

What are operations on functions?

Similar to how we operate on the terms of the functions, we can add, subtract, multiply, and divide functions with overlapping domains using the operations on functions.

We are given f(x) = 3x² + 2x - 1 and g(x) = 4x - 5

(g - f) (x)

⇒(g - f) (x) = g(x) - f(x)

⇒(g - f) (x) = (4x - 5) - (3x² + 2x - 1)

⇒(g - f) (x) = 4x - 5 - 3x² - 2x + 1

⇒(g - f) (x) = 2x - 4 - 3x²

⇒(g - f) (x) = -3x² + 2x - 4

(f + g) (x)

⇒(f + g) (x) = f(x) + g(x)

⇒(f + g) (x) = (3x² + 2x - 1) + (4x - 5)

⇒(f + g) (x) = 3x² + 2x - 1 + 4x - 5

⇒(f + g) (x) = 3x² + 6x - 6

(g / f) (x)

⇒(g / f) (x) = g(x) / f(x)

⇒(g / f) (x) = (4x - 5) / (3x² + 2x - 1)

(fg) (x)

⇒(fg) (x) = f(x) * g(x)

⇒(fg) (x) = (3x² + 2x - 1) * (4x - 5)

⇒(fg) (x) = 12x³ - 7x² -14x + 5

Hence, the required solutions have been obtained.

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In the given window there are both acute and obtuse angles are shown.

a coordinate system is a system that uses one or more numbers, or coordinates, to uniquely determine the position of the points or other geometric elements on a manifold such as Euclidean space

We have to find the  types of angles are shown by the window-glass shapes

An angle is formed when two straight lines or rays meet at a common endpoint.

As we observe the angles are less than 180 degrees.

Angles between 0 and 90 degrees are called acute angles.

Angles between 90 and 180 degrees are known as obtuse angles.

Hence, In the given window there are both acute and obtuse angles are shown.

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The surface area of the cylinder is 502.4 in², 602.88 in² and 175.84 in² respectively

An equation is an expression that shows the relationship between numbers and variables using mathematical operators such as addition, subtraction, exponent, multiplication and division.

The surface area of a cylinder is:

Surface area = 2πr(r + h)

where r is the radius and h is the height

1) r = 5 in., h = 11 in. and π = 3.14, hence:

Surface area = 2πr(r + h) = 2(3.14)(5)(5 + 11) = 502.4 in²

2) r = 6 in., h = 10 in. and π = 3.14, hence:

Surface area = 2πr(r + h) = 2(3.14)(6)(6 + 10) = 602.88 in²

3) r = 2 in., h = 12 in. and π = 3.14, hence:

Surface area = 2πr(r + h) = 2(3.14)(2)(2 + 12) = 175.84 in²

The surface area of the cylinder is 502.4 in², 602.88 in² and 175.84 in² respectively

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A total of 16 customers order the classic cheesecake.

To find out how many customers order the classic cheesecake, c, we need to subtract the number of customers who order ice cream from the total number of customers who order dessert.

This is because the question tells us that there are only two dessert options, ice cream and classic cheesecake, c.

Here's the equation we can use to solve the problem:

c = total number of customers who order dessert - number of customers who order ice cream

We can plug in the given values from the question:

c = 38 - 22

Simplifying the equation:

c = 16

Therefore, 16 customers order the classic cheesecake, c.

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